Search Results

Search found 3804 results on 153 pages for 'regex'.

Page 113/153 | < Previous Page | 109 110 111 112 113 114 115 116 117 118 119 120  | Next Page >

  • classic asp comparison of comma seperated lists

    - by Reiwoldt
    Hello, I have two comma seperated lists:- 36,189,47,183,65,50 65, 50, 189, 47 the question is how to compare the two in classic ASP in order to identify and return any values that exist in list 1 but that don't exist in list 2 bearing in mind that associative arrays aren't available. e.g. in the above example I would need the return value to be 36,183 Thanks

    Read the article

  • regexp to match string with (comma-separated) number at start and to split into number and rest?

    - by mix
    Given a string such as: 23,234,456 first second third How can I split string this into two parts, where part 1 contains the number at the beginning and part 2 contains the rest---but only if the string STARTS with a number, and the number can be comma-separated or not? In other words, I want two results: 23,234,456 and first second third. If there's a number in that string that isn't part of the first number then it should be in the second result. My best stab at this so far, to grab the number at the beginning, is something like this: ^[0-9]+(,[0-9]{3})* Which seems to grab a comma-separated or non-comma-separated number that starts the line. However, when I run this in the Javascript console I get not only the full number, but also a match on just the last 3 digits with their preceeding ,. (e.g. 23,234,456 and ,456). As for getting the rest into another var I'm having trouble. I tried working with \b, etc., but I think I must be missing something fundamental about grabbing the rest of the line. I'm doing this in Javascript in case it matters. More examples of what to match and what not to match. 2 one two three should return 2 and one two three 2345 one two three should return 2345 and one two three 2 one 2 three should return 2 and one 2 three 2,234 one two 3,000 should return 2,234 and one two 3,000 The space between parts 1 and two could be included in the beginning of part 2.

    Read the article

  • How to using String.split in this case?

    - by hoang nguyen
    I want to write a fuction like that: - Input: "1" -> return : "1" - Input: "12" -> return : ["1","2"] If I use the function split(): String.valueOf("12").split("") -> ["","1","2"] But, I only want to get the result: ["1","2"]. What the best way to do this? Infact, I can do that: private List<String> decomposeQuantity(final int quantity) { LinkedList<String> list = new LinkedList<String>(); int parsedQuantity = quantity; while (parsedQuantity > 0) { list.push(String.valueOf(parsedQuantity % 10)); parsedQuantity = parsedQuantity / 10; } return list; } But, I want to use split() for having an affective code

    Read the article

  • PHP: extract email and name from data file

    - by pi-2r
    I need to extract the name and the e-mail from one data file. the file contains more than 500 lines and I want to extract this two informations almost all the data. I would like to use preg_match_all, but my function doesn't work ... $chaine = " ----------------- 11/21/12 16:06:54 tcp static-qvn-qvt-127041 MAIL [email protected] NAME tata1 ----------------- 11/21/12 16:06:54 tcp static-qvn-qvt-127041 MAIL [email protected] NAME tata2 * ----------------- 11/21/12 16:06:54 tcp static-qvn-qvt-127041 MAIL [email protected] NAME tata3 "; //$chaine =" #76:50#89:1#86:50#49:1#84:22"; $motif="/MAIL([a-z]{2,4}+)NAME([a-z]{2,4}+)/"; preg_match_all($motif,$chaine,$out); $nb=count($out[0]); for($i=0;$i<$nb;$i++) { echo $out[0][$i].'<br/>'; }

    Read the article

  • Split a string by comma, quote and full-stop.. with a few exceptions

    - by dunc
    I've got a lot of text, similar to the following paragraph, which I'd like to split into words without punctuation (', ", ,, ., newline etc).. with a few exceptions. Initially considered endemic to the Chalakudy River system in Kerala state, southern India, but now recognised to have a wider distribution in surrounding drainages including the Periyar, Manimala, and Pamba river though the Manimala data may be questionable given it seems to be the type locality of P. denisonii. In the Achankovil River basin it occurs sympatrically, and sometimes syntopically, with P. denisonii. Wild stocks may have dwindled by as much as 50% in the last 15 years or so with collection for the aquarium trade largely held responsible although habitats are also being degraded by pollution from agricultural and domestic sources, plus destructive fishing methods involving explosives or organic toxins. The text refers to P. denisonii which is a species of fish. It's an abbreviation of Genus species. I would like this reference to be one word. So, for instance, this is the kind of array I'd like to see: Array ( ... [44] given [45] it [46] seems [47] to [48] be [49] the [50] type [51] locality [52] of [53] P. denisonii [54] In [55] the ... ) The only things that distinguish these species references such as P. denisonii from a new sentence like end. New are: The P (for Puntius, as in the P. in the aforementioned example) is only ever one letter, always a capital the d (as in . denisonii) is always either a lower case letter or an apostrophe (') What regexp can I use with preg_split to give me such an array? I've tried a simple explode( " ", $array ) but it doesn't do the job at all. Thanks in advance,

    Read the article

  • asp.net regular expression not working as expected

    - by Zaps
    Hi, I have a textbox and a regular expression validator applied to it. I want to make sure that the only allowed string inputted into the textbox are "Anything Entered" or "Something Else" or "Another String" otherwise I want an error to be displayed. This is the regular expression I have so far: ValidationExpression="(^Anything Entered)$|(^Something Else)$ |(^Another String)$" However when I enter the supposed valid strings the error is displayed. I cant figure out whats wrong with the expression. Any help would be greatly appreciated. Thanks, Zaps

    Read the article

  • PHP preg_match Math Function

    - by Matt
    I'm writing a script that will allow a user to input a string that is a math statement, to then be evaluated. I however have hit a roadblock. I cannot figure out how, using preg_match, to dissallow statements that have variables in them. Using this, $calc = create_function("", "return (" . $string . ");" ); $calc();, allows users to input a string that will be evaluated, but it crashes whenever something like echo 'foo'; is put in place of the variable $string.

    Read the article

  • JavaScript Regex question

    - by Vincent
    All, I have following function to check for invalid symbols entered in a text box and return true or false. How can I modify this function to also check for occurrences like http:// and https:// and ftp:// return false if encountered ? function checkURL(textboxval) { return ! (/[<>()#'"]|""/.test(textboxval)); } Thanks

    Read the article

  • what is the regular expression for this

    - by bn
    I want to parse this (adv) much (thanks) I want to eliminate the words and the bracket (adv) but not (thanks) the condition is: inside bracket, and word length inside bracket is 1-5 characters I am using preg_match in PHP Thank You

    Read the article

  • mod_rewrite per-dir redirection returning a 400

    - by Eaterrust
    I moved my images directory to a different folder, and now I want to redirect all images requests from that folder to the new one. I do not have access to the main configuraion file, so I'm doing this in a .htaccess. I tried this, and it works:     RewriteCond %{REQUEST_URI} old_dir/.+.(jpg|png|gif)$     RewriteRule old_dir/(.+[^/]+..+)$ $1 [L,PT] But since they have permanently moved, I want to do a proper redirect, so I added the [R] flag, like this:      %{REQUEST_URI} old_dir/.+.(jpg|png|gif)$     RewriteRule old_dir/(.+[^/]+..+)$ $1 [L,PT,R] But the server gets confused, and returns a 400, so I looked at the log file, and this is what happens:     strip per-dir prefix: C:/wamp/www/natrazyle/old_dir/images/banner.jpg - old_dir/images/banner.jpg     applying pattern 'old_dir/(.+[^/]+..+)$' to uri 'old_dir/images/banner.jpg'     rewrite 'old_dir/images/banner.jpg' - 'images/banner.jpg'     add per-dir prefix: images/banner.jpg - C:/wamp/www/natrazyle/images/banner.jpg     explicitly forcing redirect with http://localhost/C:/wamp/www/natrazyle/images/banner.jpg As you can see, the full local path gets added after localhost I know I'm doing something wrong, I just can't figure it out myself. Any help would be greatly appreciated...

    Read the article

  • document.URL Matching in Javascript

    - by streetparade
    I have a url which looks like this https://test.high.com/people/11111111-name-firstname-_custa/deals/new Now i need to match document.URL if im on that Page if so i will alert a message. The important part is /deals/new How can i match that in Javascript?

    Read the article

  • Is it possible to use a back reference to specify the number of replications in a regular expression

    - by user307894
    Is it possible to use a back reference to specify the number of replications in a regular expression? foo= 'ADCKAL+2AG.+2AG.+2AG.+2AGGG+.+G+3AGGa4.' The substrings that start with '+[0-9]' followed by '[A-z]{n}.' need to be replaced with simply '+' where the variable n is the digit from earlier in the substring. Can that n be back referenced? For example (doesn't work) '+([0-9])[A-z]{/1}.' is the pattern I want replaced with "+" (that last dot can be any character and represents a quality score) so that foo should come out to ADCKAL++++G.G+. foo = 'ADCKAL+2AG.+2AG.+2AG.+2AGGG^+.+G+3AGGa4.' indelpatt = re.compile('\+([0-9])') while indelpatt.search(foo): indelsize=int(indelpatt.search(foo).group(1)) new_regex = '\+%s[ACGTNacgtn]{%s}.' % (indelsize,indelsize) newpatt=re.compile(new_regex) foo = newpatt.sub("+", foo) I'm probably missing an easier way to parse the string.

    Read the article

  • JQuery if/else statement matching a wildcard css name

    - by Neokoenig
    Hi All, I'm trying to write an if/else statement in jQuery which can change an elements class by matching 'IN' or 'OUT' (in this case). I.e, I have several Divs with class='IN-something' OR class='OUT-something'. The below would work if I new the exact CSS class, but all I'll know is whether it contains 'IN' or 'OUT'. So like this, but works: if ($(jRow).hasClass('IN-*')) {jRow.attr( "class", "OUT-foo" );} else {jRow.attr( "class", "IN-foo");} Ideas? Thanks!

    Read the article

  • Regular Expression to capture the first <p> of HTML

    - by Program.X
    I have the following regular expression: (?:<(?<tag>\w*)>(?<text>.*)</\k<tag>>) I want it t grab the text within the first HTML element. eg. <p>This should capture</p>This shouldn't Works, but ... <p>This should capture</p><p>This shouldn't</p> Doesn't work. As you'd expect, it returns: This should capture</p><p>This shouldn't I'm racking my brains here. How can I just have it select the FIRST inner text? (I'm trying to be tag-agnostic, so <strong>This should match</strong> is equally appropriate, etc.)

    Read the article

  • Replace String pattern in Java

    - by Hirantha
    I have the following string "value=\"\\d{4}((((0[1-9])|(1[0-2]))((0[1-9])|([12]\\d)|(3[01]))?)?|(\\-(((0[1-9])|(1[0-2]))(\\-((0[1-9])|([12]\\d)|(3[01])))?)?)?)d{4}" There I want to replace all the occurrences of "{" with NCHAR(0x7B) "}" with NCHAR(0x7D). An the content in-between "{ }" should remain unchanged: Ex: \\d{4} after replacing -> NCHAR(0x7B) 4 NCHAR(0x7D). Is there a way to do this using Regular Expressions in Java?. Anyway, this can be done processing the whole string using string operations.

    Read the article

  • How to strip everything between a key phrase and an ending tag?

    - by user3620142
    I am trying to strip everything between a key phrase and ending tag but for some reason it is not working. I always get blank data. I've tried many different ways but no luck. Basically I have a script that connect to IMAP and store emails into MySQL as service tickets. It works great but I am trying to strip off everything except for user reply because currently if a user reply to an email it re-inserts the entire email into MySQL. I added a key phrase at the top of all outgoing emails . Structure is as below: --Reply below this line to respond-- ------------------------------------------------------------------------------------ Email body message... When replying to the message, it becomes: New Message reply...... --Reply below this line to respond-- old message body. I would only like to insert the new reply message only. This is what I've got so far: $message = strip_tags($message, "<br><div><p><u><hr></section>"); $message=preg_replace("</p>", "br /", $message); $message=preg_replace('#--REPLY above this line to respond--(.*?)</section>)#s', ' ', $message); $message=clean("<br/><hr><u>Received On $rep_date / $from_email</u><br><br/>$message"); It inserts the Received On date and From but $message is blank. If I remove $message=preg_replace('#--REPLY above this line to respond--(.*?)</section>)#s', ' ', $message); it inserts the entire email. Any suggestion on what i am doing wrong?

    Read the article

  • regular expression for bit strings with even number of 1s

    - by equilibrium
    Let L= { w in (0+1)* | w has even number of 1s}, i.e. L is the set of all bit strings with even number of 1s. Which one of the regular expressions below represents L? A) (0*10*1)* B) 0*(10*10*)* C) 0*(10*1)* 0* D) 0*1(10*1)* 10* According to me option D is never correct because it does not represent the bit string with zero 1s. But what about the other options? We are concerned about the number of 1s(even or not) not the number of zeros doesn't matter. Then which is the correct option and why?

    Read the article

  • Validate a string

    - by Activist
    I'm not that good with regular expressions... I need a JavaScript regular expression that will do the following: The string can contain letters (upper and lower case), but not punctuations such as éàïç... The string can contain numbers (0..9) anywhere in the string, except on the first position. The string can contain underscores (_). Valid strings: foo foo1 foo_bar fooBar Invalid strings: 1foo -- number as first character foo bar -- space föo -- punctuation ö Many thanks!

    Read the article

< Previous Page | 109 110 111 112 113 114 115 116 117 118 119 120  | Next Page >