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  • How do I combine multiple changelog / commit entries in mercurial

    - by Kimvais
    I currently have a repository, where development work has been committed directly into the 'default' branch. I'd like to find a way to combine multiple small changesets into a single changeset, for merging the changes to child repositories. E.g in the default/main repo there are changesets something like: 12839: Fooed the bar 12838: Fixed blonking 12837: Trumped slamdunks ... 323: Started development for thingamajiks and I would like this to look like (in the child repos): 323: Added thingamajik functionality

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  • Mercurial/Intellij9 hg4idea Error: cannot update with applied MQ patches, please use rebase

    - by johnrock
    I am getting the following error when trying to update my project from Intellij 9 using hg4idea: Error: cannot update with applied MQ patches, please use rebase What does this mean? I have not created or applied any patches as far as I know. I can pull changes from my remote repository but cannot update the project from within Intellij. I can call hg update from the command line and that works fine. Thanks

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  • @ContextConfiguration in Spring 3.0 give me No default constructor found

    - by atomsfat
    I have already do the test using AbstractDependencyInjectionSpringContextTests and it works but in spring 3 it is deprecated, so I decided to try @ContextConfiguration but spring say that default constructor is not found, I check and the class doesn't have any constructor. If I use this test spring give the object. package atoms.portales.servicios.impl; import atoms.portales.model.Cliente; import atoms.portales.servicios.ClienteService; import java.util.List; import javax.persistence.EntityManager; import org.springframework.test.AbstractDependencyInjectionSpringContextTests; /** * * @author tsalazar */ public class ClienteServiceImplDeTest extends AbstractDependencyInjectionSpringContextTests{ private ClienteService clienteService; public ClienteService getClienteService() { return clienteService; } public void setClienteService(ClienteService clienteService) { this.clienteService = clienteService; } public ClienteServiceImplDeTest(String testName) { super(testName); } @Override protected String[] getConfigLocations() { return new String[]{"PersistenceAppCtx.xml", "ServicesAppCtx.xml"}; } /** * Test of buscaCliente method, of class ClienteServiceImplDeTest. */ public void testBuscaCliente() { System.out.println("======================================="); System.out.println("buscaCliente"); String nombre = ""; System.out.println(clienteService); System.out.println("======================================="); } } But if I use this, spring say that default constructor is not found. package atoms.config.portales.servicios.impl; import atoms.portales.model.Cliente; import atoms.portales.servicios.ClienteService; import org.junit.runner.RunWith; import org.junit.Test; import org.springframework.beans.factory.annotation.Autowired; import org.springframework.test.context.ContextConfiguration; import org.springframework.test.context.junit4.SpringJUnit4ClassRunner; import org.springframework.test.context.transaction.TransactionConfiguration; import org.springframework.transaction.annotation.Transactional; /** * * @author tsalazar */ @RunWith(SpringJUnit4ClassRunner.class) @ContextConfiguration(locations = {"/PersistenceAppCtx.xml", "/ServicesAppCtx.xml"}) @TransactionConfiguration(transactionManager = "transactionManager") @Transactional public class ClienteServiceImplTest { @Autowired private ClienteService clienteService; /** * Test of buscaCliente method, of class ClienteServiceImpl. */ @Test public void testBuscaCliente() { System.out.println("======================================="); System.out.println("buscaCliente"); System.out.println(clienteService); System.out.println("======================================="); } } This how I do the implementacion: package atoms.portales.servicios; import atoms.portales.model; /** * Una interface para obtener clientes, con sus surcursales, servicios, layouts * y contratos. Tambien soporta operaciones CRUD. * @author tsalazar */ public interface ClienteService { /** * Busca clientes a partir del nombre * @param nombre */ public Cliente buscaCliente(String nombre); } the implemetacion package atoms.portales..servicios.impl; import atoms.portales.model.Cliente; import atoms.portales.servicios.ClienteService; import javax.persistence.EntityManager; import javax.persistence.PersistenceContext; import org.springframework.stereotype.Repository; import org.springframework.stereotype.Service; import org.springframework.transaction.annotation.Transactional; /** * A JPA-based implementation.Delegates to a JPA entity manager to issue data access calls * against the backing repository. The EntityManager reference is provided by the managing container (Spring) * automatically. */ @Service("clienteSerivice") @Repository public class ClienteServiceImpl implements ClienteService { public ClienteServiceImpl() { } private EntityManager em; @PersistenceContext public void setEntityManager(EntityManager em) { this.em = em; } @Transactional(readOnly = true) public Cliente buscaCliente(String nombre) { Cliente cliente = em.getReference(Cliente.class, 1l); return cliente; } } spring configuration: <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:tx="http://www.springframework.org/schema/tx" xsi:schemaLocation=" http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-2.5.xsd"> <!-- Instructs Spring to perfrom declarative transaction management on annotated classes --> <tx:annotation-driven /> <!-- Drives transactions using local JPA APIs --> <bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager"> <property name="entityManagerFactory" ref="entityManagerFactory" /> </bean> <!-- Creates a EntityManagerFactory for use with the Hibernate JPA provider and a simple in-memory data source populated with test data --> <bean id="entityManagerFactory" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean"> <property name="dataSource" ref="dataSource" /> <property name="jpaVendorAdapter"> <bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter" /> </property> </bean> <!-- Deploys a in-memory "booking" datasource populated --> <bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource"> <property name="driverClassName" value="org.hsqldb.jdbcDriver" /> <property name="url" value="jdbc:hsqldb:hsql://localhost/test" /> <property name="username" value="sa" /> <property name="password" value="" /> </bean> <context:component-scan base-package="atoms.portales.servicios" /> </beans> This is the persistence.xml <?xml version="1.0" encoding="UTF-8"?> <persistence xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd" version="1.0"> <persistence-unit name="configuradorPortales" transaction-type="RESOURCE_LOCAL"> <provider>org.hibernate.ejb.HibernatePersistence</provider> <class>atoms.portales.model.Cliente</class> <properties> <property name="hibernate.dialect" value="org.hibernate.dialect.HSQLDialect"/> <property name="hibernate.hbm2ddl.auto" value="create-drop"/> <property name="hibernate.show_sql" value="true"/> <property name="hibernate.cache.provider_class" value="org.hibernate.cache.HashtableCacheProvider"/> </properties> </persistence-unit> </persistence> This is the error that give me:

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  • Creating a zip archive of the maven "target" directory

    - by Yaneeve
    Hi all, I am wish to create a zip archive of my "target" directory (${project.build.directory). using the maven-assembly-plugin seems to me like overkill for such a simple task (and a bit complicated - why must I use another file, the assembly descriptor, for such a task) I can't locate the seemingly more simple maven-zip-plugin in the http://repo1.maven.org/maven2 repository. Any input?

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  • Version control: delete branches after merging?

    - by Nathan Long
    When you branch some code, finish working with the branch, and merge it back to the trunk, what do you do with the branch? Delete it from the repository? Keep it for reference? It seems like you would keep it for reference, but I imagine the /branches directory could get pretty cluttered. (If this isn't something people generally agree on, please comment and I'll make it a community wiki.)

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  • ivy dependency on external JAR

    - by Misha Koshelev
    Dear All: I am battling with Ivy (I tried maven but had an event more difficult time setting up the JBoss repository for Hibernate). Quick question - I am using this wonderful package: http://ooweb.sourceforge.net/index.html Unfortunately, the JAR is only available through Sourceforge: http://sourceforge.net/projects/ooweb/files/ooweb/0.8.0/ooweb-0.8.0-bin.tar.gz/download Is there a way to get Ivy to download a specific JAR? For that matter, is it possible to do with Maven? Thank you! Misha

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  • Clean checkout from TFS 2008

    - by Luis Medel
    Hi all, I want to pass a project to a colleague without SCC bindings to avoid accidental changes in my repository. Is it possible to do a clean checkout from a TFS 2008 repo? I'm going crazy finding such an option in VS2008. Thanks in advance.

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  • Grabbing git log from other folder

    - by jmccartie
    I'm trying to output a git log from another folder on the server without having to cd into it first. git log /path/to/repo returns fatal: Not a git repository For the life of me, I can't find the switch to tell it to operate on/in a different path than . Thanks.

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  • How to install a downloaded Ruby gem file ?

    - by JCLL
    How does "gem install" works ? It is not intuitive... My gem is really here : [root@localhost Téléchargement]# ll *.gem -rw-rw-r-- 1 jean jean 16353818 mar 5 11:39 ruby-processing-1.0.9.gem But an idiomatic "gem install" does not see it... [root@localhost Téléchargement]# gem install ruby-processing-1.0.9.gem ERROR: could not find gem ruby-processing-1.0.9.gem locally or in a repository What's wrong with that ? Thx JC

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  • "Hiding" things in GIT

    - by bobobobo
    Git noob here. I know this is against the principal of "distributed source control" but I want to "password protect" certain development branches in my GIT repository. That is, I don't want that branch to be available via git branch -r, except to a certain group of developers who need access to that branch, via some sort of password. Possible?

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  • Adding Three20 in our project ?

    - by goeff27
    Hi How to find /Three20/src folder in downloaded source code ? or i have to create my own folder of that name ? and Clone the Three20 git repository: git clone git://github.com/facebook/three20.git is have to run on terminal or what ? Concept not clear ? any any body help me regarding all the steps clearly ? thanks

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  • ASP.NET MVC Stored Procedure

    - by Pinu
    I am using a ms sql stored procedure to get a set of records , when i am adding this stored procedure to my LinqToSql class and using it my repository it shows like it is returning a int value but it should be returning a set of rows. Is there some thing wrong with my stored procedure or some thing else???

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  • grunt server command not found in terminal

    - by user3413185
    In my project directory i installed grunt using the following command npm install grunt...after that i did grunt server in my project directory but it gives me command not found error.. providing my error below.. can you tell me how to fix it.. Raj$ grunt server -bash: grunt: command not found npm install grunt npm install grunt npm WARN package.json [email protected] No description npm WARN package.json [email protected] No repository field. npm WARN package.json [email protected] No README data

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  • How to embed a hgactivity graph in hgweb

    - by Ton
    I would like to embed an actity graph created by hgactivity inside my hgweb webinterface. What's the best method to do so. Here's a screenshot of a hgactivity graph: It shows the number of commits through time to a Mercurial repository.

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  • Rails auto_complete "undefined method `auto_complete_for'" problem

    - by Andrew Wize
    rails - 2.3.8 ruby - 1.8.7 After auto_complete plugin installstion i still have "undefined method `auto_complete_for'" problem! Andrey-Bezruks-MacBook-Pro:eyeonasia.stage wizeflux$ ruby script/plugin install http://github.com/rails/auto_complete.git --force svn: '/Users/wizeflux/Projects/ionasia/eyeonasia.stage/vendor/plugins' is not a working copy Initialized empty Git repository in /Users/wizeflux/Projects/ionasia/eyeonasia.stage/vendor/plugins/auto_complete/.git/ warning: Option "depth" is ignored for github.com/rails/auto_complete.git From github.com/rails/auto_complete * branch HEAD - FETCH_HEAD Andrey-Bezruks-MacBook-Pro:eyeonasia.stage wizeflux$ after restarting server i get an error on line " auto_complete_for :listings, :name " - undefined method `auto_complete_for' for #

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  • deployment public keys

    - by hyperboreean
    How do you guys deploy your code on your servers? I am using Fabric and Python and I would like a more automated way of pulling code from the repository through the use of public keys, but without any ops or manual intervention to set up the public keys. Are you storing them in the code as text or in a database and generate the pk file on the fly?

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  • How to tell Subversion to display binary files using an external program?

    - by lamcro
    I have some code which, like java, is stored in a binary format, and I have the applications to display and modify this code setup in the Subversion's config file. But when I run svn diff for these file, Subversion prevents me =================================================================== Cannot display: file marked as a binary type. svn:mime-type = application/octet-stream I can still view them, but only with the --force argument Since all the files in the repository are of this binary code, how can I permanently force subversion to open the files for diff or edit mode?

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  • Git init - .git: Permission Denied

    - by Gcoop
    Hi All, I am trying to initiate git on my remote server using ssh. When I run git init On the server in a folder I have write permissions to I get the following error. .git: Permission denied Do I need to assign any other permissions on that folder to be able to create the repository? Thanks

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  • ASP.NET MVC 2 AJAX dilemma: Lose Models concept or create unmanageable JavaScript

    - by Slightly Frustrated
    Hi, Ok, let's assume we are working with ASP.NET MVC 2 (latest and greatest preview) and we want to create AJAX user interface with jQuery. So what are our real options here? Option 1 - Pass Json from the Controller to the view, and then the view submits Json back to the controller. This means (in the order given): User opens some View (let's say - /Invoices/January) which has to visualize a list of data (e.g. <IEnumerable<X.Y.Z.Models.Invoice>>) Controller retrieves the Model from the repository (assuming we are using repository pattern). Controller creates a new instance of a class which we will serialize to Json. The reasaon we do this, is because the model may not be serializable (circular reference ftl) Controller populates the soon-to-be-serialized class with data Controller serializes the class to Json and passes it the view. User does some change and submits the 'form' The View submits back Json to the controller The Controller now must 'manually' validate the input, because the Json passed does not bind to a Model See, if our View is communicating to the controller via Json, we lose the Model validation, which IMHO is incredible disadvantage. In this case, forget about data annotations and stuff. Option 2 - Ok, the alternative of the first approach is to pass the Models to the Views, which is the default behavior in the template when you start a new project. We pass a strong typed model to the view The view renders the appropriate html and javascript, sticking to the model property names. This is important! The user submits the form. If we stick to the model names, when we .serialize() the form and submit it to the controller it will map to a model. There is no Json mapping. The submitted form directly binds to a strongly typed model, hence, we can use the model validation. E.g. we keep the business logic where it should be. Problem with this approach is, if we refactor some of the Models (change property names, types, etc), the javascript we wrote would become invalid. We will have to manually refactor the scripting and hope we don't miss something. There is no way you can test it either. Ok, the question is - how to write an AJAX front end, which keeps the business logic validation in the model (e.g. controller passes and receives a Model type), but in the same time doesn't screw up the javascript and html when we refactor the model?

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  • Where do you keep your code?

    - by skiphoppy
    Your code is of course checked into a repository somewhere, but where do you keep your working copy/copies? C:\Program Files isn't right, as it's for installed packages. My Documents somehow doesn't seem right, either—a My Code folder next to My Music and My Pictures? Dumping in C:\ is messy, but seems to be "working" for other people in my office.

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