Search Results

Search found 4511 results on 181 pages for 'andrew min'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 13/181 | < Previous Page | 9 10 11 12 13 14 15 16 17 18 19 20  | Next Page >

  • Date & time query question (sql-server 2008)

    - by Gold
    hi i have table that contain date and time field. id|date|time ========= 1|01/01/2001|10:45 2|01/02/2002|11:45 3|01/03/2003|12:45 4|01/04/2004|12:55 i need to know the difference between the MAX(date) and the MIN(date) and the MAX(time) and the MIN(time) something like.... MAX(date)-MIN(date) ???..... thank's in advance

    Read the article

  • Setting minimum threads in thread pool

    - by expert
    I have an application with 4 worker threads from the thread pool. It was waking up every 0.5 second. as written in msdn the thread pool monitors every 0,5 second to create idle threads. I set the nuber of minimum threads to 4 and it solved the problem - no more background activity all the time. My question is - I have another applicatiopn which has the same number of threads threads-4, but here setting min thread to 4 doesn't help but when setting min thread to 5 then the background monitoring stops. What might be the difference between 2 application with the same number of threads from the thread pool- 4 threads.On one setting min threads to 4 helps and the other only setting min threads to 5 helps?

    Read the article

  • How to set up a functional macro with parameters in C++?

    - by user1728737
    is there a way that I can make this work? Or do I need to use separate files? #include <iostream> // Necessary using namespace std; long double primary, secondary, tertiary; #define long double mMaxOf2(long double min, long double max) { return ((max > min) ? (max) : (min)); } #define long double mMaxOf3(long double Min, long double Max, long double Mid) { long double Mid = (long double mMaxOf2(long double Min, long double Mid)); long double Max = (long double mMaxOf2(long double Mid, long double Max)); return (Max); } int main() { cout << "Please enter three numbers: "; cin << primary << secondary << tertiary; cout << "The maximum of " << primary << " " << secondary << " " << tertiary; cout << " using mMaxOf3 is " << long double mMaxOf3(primary, secondary, tertiary); return 0; } This is the error that I am getting. |20|error: expected unqualified-id before '{' token|

    Read the article

  • Point inside Oriented Bounding Box?

    - by Milo
    I have an OBB2D class based on SAT. This is my point in OBB method: public boolean pointInside(float x, float y) { float newy = (float) (Math.sin(angle) * (y - center.y) + Math.cos(angle) * (x - center.x)); float newx = (float) (Math.cos(angle) * (x - center.x) - Math.sin(angle) * (y - center.y)); return (newy > center.y - (getHeight() / 2)) && (newy < center.y + (getHeight() / 2)) && (newx > center.x - (getWidth() / 2)) && (newx < center.x + (getWidth() / 2)); } public boolean pointInside(Vector2D v) { return pointInside(v.x,v.y); } Here is the rest of the class; the parts that pertain: public class OBB2D { private Vector2D projVec = new Vector2D(); private static Vector2D projAVec = new Vector2D(); private static Vector2D projBVec = new Vector2D(); private static Vector2D tempNormal = new Vector2D(); private Vector2D deltaVec = new Vector2D(); private ArrayList<Vector2D> collisionPoints = new ArrayList<Vector2D>(); // Corners of the box, where 0 is the lower left. private Vector2D corner[] = new Vector2D[4]; private Vector2D center = new Vector2D(); private Vector2D extents = new Vector2D(); private RectF boundingRect = new RectF(); private float angle; //Two edges of the box extended away from corner[0]. private Vector2D axis[] = new Vector2D[2]; private double origin[] = new double[2]; public OBB2D(float centerx, float centery, float w, float h, float angle) { for(int i = 0; i < corner.length; ++i) { corner[i] = new Vector2D(); } for(int i = 0; i < axis.length; ++i) { axis[i] = new Vector2D(); } set(centerx,centery,w,h,angle); } public OBB2D(float left, float top, float width, float height) { for(int i = 0; i < corner.length; ++i) { corner[i] = new Vector2D(); } for(int i = 0; i < axis.length; ++i) { axis[i] = new Vector2D(); } set(left + (width / 2), top + (height / 2),width,height,0.0f); } public void set(float centerx,float centery,float w, float h,float angle) { float vxx = (float)Math.cos(angle); float vxy = (float)Math.sin(angle); float vyx = (float)-Math.sin(angle); float vyy = (float)Math.cos(angle); vxx *= w / 2; vxy *= (w / 2); vyx *= (h / 2); vyy *= (h / 2); corner[0].x = centerx - vxx - vyx; corner[0].y = centery - vxy - vyy; corner[1].x = centerx + vxx - vyx; corner[1].y = centery + vxy - vyy; corner[2].x = centerx + vxx + vyx; corner[2].y = centery + vxy + vyy; corner[3].x = centerx - vxx + vyx; corner[3].y = centery - vxy + vyy; this.center.x = centerx; this.center.y = centery; this.angle = angle; computeAxes(); extents.x = w / 2; extents.y = h / 2; computeBoundingRect(); } //Updates the axes after the corners move. Assumes the //corners actually form a rectangle. private void computeAxes() { axis[0].x = corner[1].x - corner[0].x; axis[0].y = corner[1].y - corner[0].y; axis[1].x = corner[3].x - corner[0].x; axis[1].y = corner[3].y - corner[0].y; // Make the length of each axis 1/edge length so we know any // dot product must be less than 1 to fall within the edge. for (int a = 0; a < axis.length; ++a) { float l = axis[a].length(); float ll = l * l; axis[a].x = axis[a].x / ll; axis[a].y = axis[a].y / ll; origin[a] = corner[0].dot(axis[a]); } } public void computeBoundingRect() { boundingRect.left = JMath.min(JMath.min(corner[0].x, corner[3].x), JMath.min(corner[1].x, corner[2].x)); boundingRect.top = JMath.min(JMath.min(corner[0].y, corner[1].y),JMath.min(corner[2].y, corner[3].y)); boundingRect.right = JMath.max(JMath.max(corner[1].x, corner[2].x), JMath.max(corner[0].x, corner[3].x)); boundingRect.bottom = JMath.max(JMath.max(corner[2].y, corner[3].y),JMath.max(corner[0].y, corner[1].y)); } public void set(RectF rect) { set(rect.centerX(),rect.centerY(),rect.width(),rect.height(),0.0f); } // Returns true if other overlaps one dimension of this. private boolean overlaps1Way(OBB2D other) { for (int a = 0; a < axis.length; ++a) { double t = other.corner[0].dot(axis[a]); // Find the extent of box 2 on axis a double tMin = t; double tMax = t; for (int c = 1; c < corner.length; ++c) { t = other.corner[c].dot(axis[a]); if (t < tMin) { tMin = t; } else if (t > tMax) { tMax = t; } } // We have to subtract off the origin // See if [tMin, tMax] intersects [0, 1] if ((tMin > 1 + origin[a]) || (tMax < origin[a])) { // There was no intersection along this dimension; // the boxes cannot possibly overlap. return false; } } // There was no dimension along which there is no intersection. // Therefore the boxes overlap. return true; } public void moveTo(float centerx, float centery) { float cx,cy; cx = center.x; cy = center.y; deltaVec.x = centerx - cx; deltaVec.y = centery - cy; for (int c = 0; c < 4; ++c) { corner[c].x += deltaVec.x; corner[c].y += deltaVec.y; } boundingRect.left += deltaVec.x; boundingRect.top += deltaVec.y; boundingRect.right += deltaVec.x; boundingRect.bottom += deltaVec.y; this.center.x = centerx; this.center.y = centery; computeAxes(); } // Returns true if the intersection of the boxes is non-empty. public boolean overlaps(OBB2D other) { if(right() < other.left()) { return false; } if(bottom() < other.top()) { return false; } if(left() > other.right()) { return false; } if(top() > other.bottom()) { return false; } if(other.getAngle() == 0.0f && getAngle() == 0.0f) { return true; } return overlaps1Way(other) && other.overlaps1Way(this); } public Vector2D getCenter() { return center; } public float getWidth() { return extents.x * 2; } public float getHeight() { return extents.y * 2; } public void setAngle(float angle) { set(center.x,center.y,getWidth(),getHeight(),angle); } public float getAngle() { return angle; } public void setSize(float w,float h) { set(center.x,center.y,w,h,angle); } public float left() { return boundingRect.left; } public float right() { return boundingRect.right; } public float bottom() { return boundingRect.bottom; } public float top() { return boundingRect.top; } public RectF getBoundingRect() { return boundingRect; } public boolean overlaps(float left, float top, float right, float bottom) { if(right() < left) { return false; } if(bottom() < top) { return false; } if(left() > right) { return false; } if(top() > bottom) { return false; } return true; } public static float distance(float ax, float ay,float bx, float by) { if (ax < bx) return bx - ay; else return ax - by; } public Vector2D project(float ax, float ay) { projVec.x = Float.MAX_VALUE; projVec.y = Float.MIN_VALUE; for (int i = 0; i < corner.length; ++i) { float dot = Vector2D.dot(corner[i].x,corner[i].y,ax,ay); projVec.x = JMath.min(dot, projVec.x); projVec.y = JMath.max(dot, projVec.y); } return projVec; } public Vector2D getCorner(int c) { return corner[c]; } public int getNumCorners() { return corner.length; } public boolean pointInside(float x, float y) { float newy = (float) (Math.sin(angle) * (y - center.y) + Math.cos(angle) * (x - center.x)); float newx = (float) (Math.cos(angle) * (x - center.x) - Math.sin(angle) * (y - center.y)); return (newy > center.y - (getHeight() / 2)) && (newy < center.y + (getHeight() / 2)) && (newx > center.x - (getWidth() / 2)) && (newx < center.x + (getWidth() / 2)); } public boolean pointInside(Vector2D v) { return pointInside(v.x,v.y); } public ArrayList<Vector2D> getCollsionPoints(OBB2D b) { collisionPoints.clear(); for(int i = 0; i < corner.length; ++i) { if(b.pointInside(corner[i])) { collisionPoints.add(corner[i]); } } for(int i = 0; i < b.corner.length; ++i) { if(pointInside(b.corner[i])) { collisionPoints.add(b.corner[i]); } } return collisionPoints; } }; What could be wrong? When I getCollisionPoints for 2 OBBs I know are penetrating, it returns no points. Thanks

    Read the article

  • Point of contact of 2 OBBs?

    - by Milo
    I'm working on the physics for my GTA2-like game so I can learn more about game physics. The collision detection and resolution are working great. I'm now just unsure how to compute the point of contact when I hit a wall. Here is my OBB class: public class OBB2D { private Vector2D projVec = new Vector2D(); private static Vector2D projAVec = new Vector2D(); private static Vector2D projBVec = new Vector2D(); private static Vector2D tempNormal = new Vector2D(); private Vector2D deltaVec = new Vector2D(); // Corners of the box, where 0 is the lower left. private Vector2D corner[] = new Vector2D[4]; private Vector2D center = new Vector2D(); private Vector2D extents = new Vector2D(); private RectF boundingRect = new RectF(); private float angle; //Two edges of the box extended away from corner[0]. private Vector2D axis[] = new Vector2D[2]; private double origin[] = new double[2]; public OBB2D(float centerx, float centery, float w, float h, float angle) { for(int i = 0; i < corner.length; ++i) { corner[i] = new Vector2D(); } for(int i = 0; i < axis.length; ++i) { axis[i] = new Vector2D(); } set(centerx,centery,w,h,angle); } public OBB2D(float left, float top, float width, float height) { for(int i = 0; i < corner.length; ++i) { corner[i] = new Vector2D(); } for(int i = 0; i < axis.length; ++i) { axis[i] = new Vector2D(); } set(left + (width / 2), top + (height / 2),width,height,0.0f); } public void set(float centerx,float centery,float w, float h,float angle) { float vxx = (float)Math.cos(angle); float vxy = (float)Math.sin(angle); float vyx = (float)-Math.sin(angle); float vyy = (float)Math.cos(angle); vxx *= w / 2; vxy *= (w / 2); vyx *= (h / 2); vyy *= (h / 2); corner[0].x = centerx - vxx - vyx; corner[0].y = centery - vxy - vyy; corner[1].x = centerx + vxx - vyx; corner[1].y = centery + vxy - vyy; corner[2].x = centerx + vxx + vyx; corner[2].y = centery + vxy + vyy; corner[3].x = centerx - vxx + vyx; corner[3].y = centery - vxy + vyy; this.center.x = centerx; this.center.y = centery; this.angle = angle; computeAxes(); extents.x = w / 2; extents.y = h / 2; computeBoundingRect(); } //Updates the axes after the corners move. Assumes the //corners actually form a rectangle. private void computeAxes() { axis[0].x = corner[1].x - corner[0].x; axis[0].y = corner[1].y - corner[0].y; axis[1].x = corner[3].x - corner[0].x; axis[1].y = corner[3].y - corner[0].y; // Make the length of each axis 1/edge length so we know any // dot product must be less than 1 to fall within the edge. for (int a = 0; a < axis.length; ++a) { float l = axis[a].length(); float ll = l * l; axis[a].x = axis[a].x / ll; axis[a].y = axis[a].y / ll; origin[a] = corner[0].dot(axis[a]); } } public void computeBoundingRect() { boundingRect.left = JMath.min(JMath.min(corner[0].x, corner[3].x), JMath.min(corner[1].x, corner[2].x)); boundingRect.top = JMath.min(JMath.min(corner[0].y, corner[1].y),JMath.min(corner[2].y, corner[3].y)); boundingRect.right = JMath.max(JMath.max(corner[1].x, corner[2].x), JMath.max(corner[0].x, corner[3].x)); boundingRect.bottom = JMath.max(JMath.max(corner[2].y, corner[3].y),JMath.max(corner[0].y, corner[1].y)); } public void set(RectF rect) { set(rect.centerX(),rect.centerY(),rect.width(),rect.height(),0.0f); } // Returns true if other overlaps one dimension of this. private boolean overlaps1Way(OBB2D other) { for (int a = 0; a < axis.length; ++a) { double t = other.corner[0].dot(axis[a]); // Find the extent of box 2 on axis a double tMin = t; double tMax = t; for (int c = 1; c < corner.length; ++c) { t = other.corner[c].dot(axis[a]); if (t < tMin) { tMin = t; } else if (t > tMax) { tMax = t; } } // We have to subtract off the origin // See if [tMin, tMax] intersects [0, 1] if ((tMin > 1 + origin[a]) || (tMax < origin[a])) { // There was no intersection along this dimension; // the boxes cannot possibly overlap. return false; } } // There was no dimension along which there is no intersection. // Therefore the boxes overlap. return true; } public void moveTo(float centerx, float centery) { float cx,cy; cx = center.x; cy = center.y; deltaVec.x = centerx - cx; deltaVec.y = centery - cy; for (int c = 0; c < 4; ++c) { corner[c].x += deltaVec.x; corner[c].y += deltaVec.y; } boundingRect.left += deltaVec.x; boundingRect.top += deltaVec.y; boundingRect.right += deltaVec.x; boundingRect.bottom += deltaVec.y; this.center.x = centerx; this.center.y = centery; computeAxes(); } // Returns true if the intersection of the boxes is non-empty. public boolean overlaps(OBB2D other) { if(right() < other.left()) { return false; } if(bottom() < other.top()) { return false; } if(left() > other.right()) { return false; } if(top() > other.bottom()) { return false; } if(other.getAngle() == 0.0f && getAngle() == 0.0f) { return true; } return overlaps1Way(other) && other.overlaps1Way(this); } public Vector2D getCenter() { return center; } public float getWidth() { return extents.x * 2; } public float getHeight() { return extents.y * 2; } public void setAngle(float angle) { set(center.x,center.y,getWidth(),getHeight(),angle); } public float getAngle() { return angle; } public void setSize(float w,float h) { set(center.x,center.y,w,h,angle); } public float left() { return boundingRect.left; } public float right() { return boundingRect.right; } public float bottom() { return boundingRect.bottom; } public float top() { return boundingRect.top; } public RectF getBoundingRect() { return boundingRect; } public boolean overlaps(float left, float top, float right, float bottom) { if(right() < left) { return false; } if(bottom() < top) { return false; } if(left() > right) { return false; } if(top() > bottom) { return false; } return true; } public static float distance(float ax, float ay,float bx, float by) { if (ax < bx) return bx - ay; else return ax - by; } public Vector2D project(float ax, float ay) { projVec.x = Float.MAX_VALUE; projVec.y = Float.MIN_VALUE; for (int i = 0; i < corner.length; ++i) { float dot = Vector2D.dot(corner[i].x,corner[i].y,ax,ay); projVec.x = JMath.min(dot, projVec.x); projVec.y = JMath.max(dot, projVec.y); } return projVec; } public Vector2D getCorner(int c) { return corner[c]; } public int getNumCorners() { return corner.length; } public static float collisionResponse(OBB2D a, OBB2D b, Vector2D outNormal) { float depth = Float.MAX_VALUE; for (int i = 0; i < a.getNumCorners() + b.getNumCorners(); ++i) { Vector2D edgeA; Vector2D edgeB; if(i >= a.getNumCorners()) { edgeA = b.getCorner((i + b.getNumCorners() - 1) % b.getNumCorners()); edgeB = b.getCorner(i % b.getNumCorners()); } else { edgeA = a.getCorner((i + a.getNumCorners() - 1) % a.getNumCorners()); edgeB = a.getCorner(i % a.getNumCorners()); } tempNormal.x = edgeB.x -edgeA.x; tempNormal.y = edgeB.y - edgeA.y; tempNormal.normalize(); projAVec.equals(a.project(tempNormal.x,tempNormal.y)); projBVec.equals(b.project(tempNormal.x,tempNormal.y)); float distance = OBB2D.distance(projAVec.x, projAVec.y,projBVec.x,projBVec.y); if (distance > 0.0f) { return 0.0f; } else { float d = Math.abs(distance); if (d < depth) { depth = d; outNormal.equals(tempNormal); } } } float dx,dy; dx = b.getCenter().x - a.getCenter().x; dy = b.getCenter().y - a.getCenter().y; float dot = Vector2D.dot(dx,dy,outNormal.x,outNormal.y); if(dot > 0) { outNormal.x = -outNormal.x; outNormal.y = -outNormal.y; } return depth; } public Vector2D getMoveDeltaVec() { return deltaVec; } }; Thanks!

    Read the article

  • Checkout multiple revision of one file in CVS repository

    - by Andrew
    Hi, To checkout I use the following command CVSROOT="/home/projects/stuff/" cvs co mywork with the mywork directory I have text files as well as pictures, i.e., looks something like this - paper.tex - pic1.jpg - pic2.jpg etc. In particular, I am interested in checking out all the version of paper.tex over time. Is there a way how I can check all revisions of this file out at once? Or which command can I use to see when revision have been made to this particular file? many thanks for your help, Andrew

    Read the article

  • Smallest executable for Windows

    - by Andrew Warren
    Hi I need to create a very simple GUI application for Windows(open a file, do some changes based on user input, upload the file to an intranet server). The client company has the latest release versions of Java SE, .NET and Adobe AIR installed on all their machines. And their #1 requirement is to have the smallest possible package for xcopy deployment. So which of the 3 listed platforms should I use? Another option of course is a native exe. Thanks, Andrew

    Read the article

  • Checkout multiple revision of one file in SVN repository

    - by Andrew
    Hi, To checkout I use the following command CVSROOT="/home/projects/stuff/" cvs co mywork with the mywork directory I have text files as well as pictures, i.e., looks something like this - paper.tex - pic1.jpg - pic2.jpg etc. In particular, I am interested in checking out all the version of paper.tex over time. Is there a way how I can check all revisions of this file out at once? Or which command can I use to see when revision have been made to this particular file? many thanks for your help, Andrew

    Read the article

  • Any good open source online RPG starter kit for development ?

    - by Andrew Sky
    Hi there, Does anyone know of a good open source toolkit that allows level designer and graphic designer or someone with basic programming experience to create multiplayer online Role Playing Game ? The game can be a simple 2D interface in a 2d virtual world. I know Microsoft have a starter kit something like the following : http://creators.xna.com/en-US/starterkit/roleplayinggame that allows developer to create RPG game running on XBox platform but i am looking more on multiplayer role playing game on the web platform where player can play directly with their browser. regards Andrew

    Read the article

  • jqgrid and django models

    - by Andrew Gee
    Hi, I have the following models class Employee(Person): job = model.Charfield(max_length=200) class Address(models.Model): street = models.CharField(max_length=200) city = models.CharField(max_length=200) class EmpAddress(Address): date_occupied = models.DateField() date_vacated = models.DateField() employee = models.ForeignKey() When I build a json data structure for an EmpAddress object using the django serialzer it does not include the inherited fields only the EmpAddress fields. I know the fields are available in the object in my view as I can print them but they are not built into the json structure. Does anyone know how to overcome this? Thanks Andrew

    Read the article

  • Changing default logical filename in SQL 2005

    - by Andrew
    I have a issue about creating databases in SQL 2005. I want to be able to change the default logical filename for the mdf file. At the moment the log logical filename ends in _log by default. I want the data logical filename to automatically end with _data for consistency. Is there a way i can set this? Andrew

    Read the article

  • Allow unregistered paypal users to make payments

    - by andrew
    Hi i am integrating paypal web payments standard into my shopping cart using the setup where you just send a form to paypal with all the values in hidden fields. I want to enable the option that allows people to make payments even if they are not a registered paypal user. I am sure i read somewhere in the paypal documentation but now i can't find it. Thanks a lot Andrew

    Read the article

  • DropdownList reset to to index 0 on load

    - by Andrew
    Hi, How would I reset my asp:DropDownList element (which has a runat="server") to index 0 every time the page is "reloaded" in firefox (F5 is pressed). If you suggest using javascript...please note that A: I am not using a form and B: I don't know how to access elements that have a runat="server" with javascript If this can be done using script on the .aspx page....please explain things you think an ASP newb would not know (ie. me, lol) thanks, Andrew :)

    Read the article

  • Does Apache ever give incorrect "out of threads" errors?

    - by Eli Courtwright
    Lately our Apache web server has been giving us this error multiple times per day: [Tue Apr 06 01:07:10 2010] [error] Server ran out of threads to serve requests. Consider raising the ThreadsPerChild setting We raised our ThreadsPerChild setting from 50 to 100, but we still get the error. Our access logs indicate that these errors never even happen at periods of high load. For example, here's an excerpt from our access log (ip addresses and some urls are edited for privacy). As you can see, the above error happened at 1:07 and only a small handful of requests occurred in the several minutes leading up to the error: 99.88.77.66 - - [06/Apr/2010:00:59:33 -0400] "GET /WebRepository/jquery/jquery-ui-1.7.1.custom/css/smoothness/images/ui-icons_222222_256x240.png HTTP/1.1" 304 - 99.88.77.66 - - [06/Apr/2010:00:59:34 -0400] "GET /WebRepository/jquery/jquery-ui-1.7.1.custom/css/smoothness/images/ui-bg_glass_75_dadada_1x400.png HTTP/1.1" 200 111 99.88.77.66 - - [06/Apr/2010:00:59:34 -0400] "GET /WebRepository/jquery/jquery-ui-1.7.1.custom/css/smoothness/images/ui-bg_glass_75_dadada_1x400.png HTTP/1.1" 200 111 99.88.77.66 - mpeu [06/Apr/2010:00:59:40 -0400] "GET /some/dynamic/content HTTP/1.1" 200 145049 55.44.33.22 - mpeu [06/Apr/2010:01:06:56 -0400] "GET /other/dynamic/content HTTP/1.1" 200 12311 55.44.33.22 - - [06/Apr/2010:01:06:56 -0400] "GET /WebRepository/jquery/jquery-ui-1.7.1.custom/css/smoothness/jquery-ui-1.7.1.custom.css HTTP/1.1" 304 - 55.44.33.22 - - [06/Apr/2010:01:06:56 -0400] "GET /WebRepository/jquery/jquery-ui-1.7.1.custom/js/jquery-1.3.2.min.js HTTP/1.1" 304 - 55.44.33.22 - - [06/Apr/2010:01:06:56 -0400] "GET /WebRepository/jquery/jquery-ui-1.7.1.custom/js/jquery-ui-1.7.1.custom.min.js HTTP/1.1" 304 - 55.44.33.22 - - [06/Apr/2010:01:06:56 -0400] "GET /WebRepository/jquery.tablesorter.min.js HTTP/1.1" 304 - 55.44.33.22 - - [06/Apr/2010:01:06:56 -0400] "GET /WebRepository/date.js HTTP/1.1" 304 - 55.44.33.22 - - [06/Apr/2010:01:06:56 -0400] "GET /WebRepository/pdfs/image1.gif HTTP/1.1" 304 - 55.44.33.22 - - [06/Apr/2010:01:06:56 -0400] "GET /WebRepository/pdfs/image2.png HTTP/1.1" 304 - 55.44.33.22 - - [06/Apr/2010:01:06:56 -0400] "GET /WebRepository/pdfs/image3.png HTTP/1.1" 304 - 55.44.33.22 - - [06/Apr/2010:01:06:56 -0400] "GET /WebRepository/pdfs/image4.png HTTP/1.1" 304 - 55.44.33.22 - - [06/Apr/2010:01:06:56 -0400] "GET /WebRepository/pdfs/image5.png HTTP/1.1" 304 - 55.44.33.22 - - [06/Apr/2010:01:06:56 -0400] "GET /WebRepository/pdfs/image6.png HTTP/1.1" 304 - 55.44.33.22 - - [06/Apr/2010:01:06:56 -0400] "GET /WebRepository/pdfs/image7.png HTTP/1.1" 304 - 55.44.33.22 - - [06/Apr/2010:01:06:57 -0400] "GET /WebRepository/pdfs/image8.png HTTP/1.1" 304 - 55.44.33.22 - - [06/Apr/2010:01:06:57 -0400] "GET /WebRepository/pdfs/image9.png HTTP/1.1" 304 - 55.44.33.22 - - [06/Apr/2010:01:06:57 -0400] "GET /WebRepository/pdfs/imageA.png HTTP/1.1" 304 - 55.44.33.22 - - [06/Apr/2010:01:06:57 -0400] "GET /WebRepository/jquery/jquery-ui-1.7.1.custom/css/smoothness/images/ui-bg_flat_75_ffffff_40x100.png HTTP/1.1" 304 - 55.44.33.22 - - [06/Apr/2010:01:06:59 -0400] "GET /WebRepository/jquery/jquery-ui-1.7.1.custom/css/smoothness/images/ui-bg_highlight-soft_75_cccccc_1x100.png HTTP/1.1" 304 - 55.44.33.22 - - [06/Apr/2010:01:06:59 -0400] "GET /WebRepository/jquery/jquery-ui-1.7.1.custom/css/smoothness/images/ui-bg_glass_75_e6e6e6_1x400.png HTTP/1.1" 200 110 55.44.33.22 - - [06/Apr/2010:01:06:59 -0400] "GET /WebRepository/jquery/jquery-ui-1.7.1.custom/css/smoothness/images/ui-bg_glass_75_e6e6e6_1x400.png HTTP/1.1" 200 110 11.22.33.44 - mpeu [06/Apr/2010:01:18:03 -0400] "GET /other/dynamic/content HTTP/1.1" 200 12311 11.22.33.44 - - [06/Apr/2010:01:18:03 -0400] "GET /WebRepository/jquery/jquery-ui-1.7.1.custom/js/jquery-1.3.2.min.js HTTP/1.1" 304 - 11.22.33.44 - - [06/Apr/2010:01:18:04 -0400] "GET /WebRepository/jquery/jquery-ui-1.7.1.custom/css/smoothness/jquery-ui-1.7.1.custom.css HTTP/1.1" 200 27374 11.22.33.44 - - [06/Apr/2010:01:18:04 -0400] "GET /WebRepository/jquery/jquery-ui-1.7.1.custom/js/jquery-ui-1.7.1.custom.min.js HTTP/1.1" 304 - 11.22.33.44 - - [06/Apr/2010:01:18:04 -0400] "GET /WebRepository/jquery.tablesorter.min.js HTTP/1.1" 200 12795 11.22.33.44 - - [06/Apr/2010:01:18:04 -0400] "GET /WebRepository/date.js HTTP/1.1" 200 25809 For what it's worth, we're running the version of Apache that ships with Oracle 10g (some 2.0 version), and we're using mod_plsql to generate our dynamic content. Since the Apache server runs as a separate process and the database doesn't record any problems when this error occurs, I'm doubtful that Oracle is the problem. Unfortunately, the errors are freaking out our sysadmins, who are inclined to blame any and all problems which occur with the server on this error. Is this a known bug in Apache that I simply haven't been able to find any reference to through Google?

    Read the article

  • Parallelism in .NET – Part 10, Cancellation in PLINQ and the Parallel class

    - by Reed
    Many routines are parallelized because they are long running processes.  When writing an algorithm that will run for a long period of time, its typically a good practice to allow that routine to be cancelled.  I previously discussed terminating a parallel loop from within, but have not demonstrated how a routine can be cancelled from the caller’s perspective.  Cancellation in PLINQ and the Task Parallel Library is handled through a new, unified cooperative cancellation model introduced with .NET 4.0. Cancellation in .NET 4 is based around a new, lightweight struct called CancellationToken.  A CancellationToken is a small, thread-safe value type which is generated via a CancellationTokenSource.  There are many goals which led to this design.  For our purposes, we will focus on a couple of specific design decisions: Cancellation is cooperative.  A calling method can request a cancellation, but it’s up to the processing routine to terminate – it is not forced. Cancellation is consistent.  A single method call requests a cancellation on every copied CancellationToken in the routine. Let’s begin by looking at how we can cancel a PLINQ query.  Supposed we wanted to provide the option to cancel our query from Part 6: double min = collection .AsParallel() .Min(item => item.PerformComputation()); .csharpcode, .csharpcode pre { font-size: small; color: black; font-family: consolas, "Courier New", courier, monospace; background-color: #ffffff; /*white-space: pre;*/ } .csharpcode pre { margin: 0em; } .csharpcode .rem { color: #008000; } .csharpcode .kwrd { color: #0000ff; } .csharpcode .str { color: #006080; } .csharpcode .op { color: #0000c0; } .csharpcode .preproc { color: #cc6633; } .csharpcode .asp { background-color: #ffff00; } .csharpcode .html { color: #800000; } .csharpcode .attr { color: #ff0000; } .csharpcode .alt { background-color: #f4f4f4; width: 100%; margin: 0em; } .csharpcode .lnum { color: #606060; } We would rewrite this to allow for cancellation by adding a call to ParallelEnumerable.WithCancellation as follows: var cts = new CancellationTokenSource(); // Pass cts here to a routine that could, // in parallel, request a cancellation try { double min = collection .AsParallel() .WithCancellation(cts.Token) .Min(item => item.PerformComputation()); } catch (OperationCanceledException e) { // Query was cancelled before it finished } .csharpcode, .csharpcode pre { font-size: small; color: black; font-family: consolas, "Courier New", courier, monospace; background-color: #ffffff; /*white-space: pre;*/ } .csharpcode pre { margin: 0em; } .csharpcode .rem { color: #008000; } .csharpcode .kwrd { color: #0000ff; } .csharpcode .str { color: #006080; } .csharpcode .op { color: #0000c0; } .csharpcode .preproc { color: #cc6633; } .csharpcode .asp { background-color: #ffff00; } .csharpcode .html { color: #800000; } .csharpcode .attr { color: #ff0000; } .csharpcode .alt { background-color: #f4f4f4; width: 100%; margin: 0em; } .csharpcode .lnum { color: #606060; } Here, if the user calls cts.Cancel() before the PLINQ query completes, the query will stop processing, and an OperationCanceledException will be raised.  Be aware, however, that cancellation will not be instantaneous.  When cts.Cancel() is called, the query will only stop after the current item.PerformComputation() elements all finish processing.  cts.Cancel() will prevent PLINQ from scheduling a new task for a new element, but will not stop items which are currently being processed.  This goes back to the first goal I mentioned – Cancellation is cooperative.  Here, we’re requesting the cancellation, but it’s up to PLINQ to terminate. If we wanted to allow cancellation to occur within our routine, we would need to change our routine to accept a CancellationToken, and modify it to handle this specific case: public void PerformComputation(CancellationToken token) { for (int i=0; i<this.iterations; ++i) { // Add a check to see if we've been canceled // If a cancel was requested, we'll throw here token.ThrowIfCancellationRequested(); // Do our processing now this.RunIteration(i); } } With this overload of PerformComputation, each internal iteration checks to see if a cancellation request was made, and will throw an OperationCanceledException at that point, instead of waiting until the method returns.  This is good, since it allows us, as developers, to plan for cancellation, and terminate our routine in a clean, safe state. This is handled by changing our PLINQ query to: try { double min = collection .AsParallel() .WithCancellation(cts.Token) .Min(item => item.PerformComputation(cts.Token)); } catch (OperationCanceledException e) { // Query was cancelled before it finished } PLINQ is very good about handling this exception, as well.  There is a very good chance that multiple items will raise this exception, since the entire purpose of PLINQ is to have multiple items be processed concurrently.  PLINQ will take all of the OperationCanceledException instances raised within these methods, and merge them into a single OperationCanceledException in the call stack.  This is done internally because we added the call to ParallelEnumerable.WithCancellation. If, however, a different exception is raised by any of the elements, the OperationCanceledException as well as the other Exception will be merged into a single AggregateException. The Task Parallel Library uses the same cancellation model, as well.  Here, we supply our CancellationToken as part of the configuration.  The ParallelOptions class contains a property for the CancellationToken.  This allows us to cancel a Parallel.For or Parallel.ForEach routine in a very similar manner to our PLINQ query.  As an example, we could rewrite our Parallel.ForEach loop from Part 2 to support cancellation by changing it to: try { var cts = new CancellationTokenSource(); var options = new ParallelOptions() { CancellationToken = cts.Token }; Parallel.ForEach(customers, options, customer => { // Run some process that takes some time... DateTime lastContact = theStore.GetLastContact(customer); TimeSpan timeSinceContact = DateTime.Now - lastContact; // Check for cancellation here options.CancellationToken.ThrowIfCancellationRequested(); // If it's been more than two weeks, send an email, and update... if (timeSinceContact.Days > 14) { theStore.EmailCustomer(customer); customer.LastEmailContact = DateTime.Now; } }); } catch (OperationCanceledException e) { // The loop was cancelled } Notice that here we use the same approach taken in PLINQ.  The Task Parallel Library will automatically handle our cancellation in the same manner as PLINQ, providing a clean, unified model for cancellation of any parallel routine.  The TPL performs the same aggregation of the cancellation exceptions as PLINQ, as well, which is why a single exception handler for OperationCanceledException will cleanly handle this scenario.  This works because we’re using the same CancellationToken provided in the ParallelOptions.  If a different exception was thrown by one thread, or a CancellationToken from a different CancellationTokenSource was used to raise our exception, we would instead receive all of our individual exceptions merged into one AggregateException.

    Read the article

  • HTC to launch Windows 7 phone in India

    - by samsudeen
    It is a good news for the Indian smart phone users as the wait is finally over for Windows 7 mobile.The Taiwanese  mobile giant HTC is all set to release its Windows 7 based Smartphone series in India from January. HTC HD7 & HTC Mozart , the two smart phones running on Windows 7 OS started appearing on the HTC Indian website (HTC India) from last week.Though Flip kart (Indian online e-commerce website)  has started getting pre -orders for HTC HD7 a month ago , the buzz has started from last week after the introduction of “HTC Mozart”. The complete feature comparison between both the smart phones is given below. Feature Comparison HTC Mozart HTC HD 7 Microsoft Windows 7 Microsoft Windows 7 Qualcomm Snapdragon Processor QSD 8250 1 GHz CPU Qualcomm Snapdragon Processor QSD 8250 1 GHz CPU 8MegaPixel camera with Xenon Flash 5 MP, 2592?1944 pixels, autofocus, dual-LED flash, 480 x 800 pixels, 3.7 inches 480 x 800 pixels, 4.3 inches 11.9mm thick and Weighs 130g 11.2 mm thick and Weighs 162 g Bluetooth 2.1 Bluetooth 2.1 8 GB of internal storage memory 8 GB of internal storage memory 512MB of ROM and 576 of RAM 512MB of ROM and 576 of RAM 3G HSDPA 7.2 Mbps and HSUPA 2 Mbps 3G HSDPA 7.2 Mbps; HSUPA 2 Mbps Wi-Fi 802.11 b/g/n Wi-Fi 802.11 b/g/n Micro-USB interconnector Micro-USB interconnector 3.5mm audio jack 3.5mm audio jack GPS antenna GPS antenna Standard battery Li-Po 1300 MA Standard battery, Li-Ion 1230 MA Standby 360 h (2G) up to 435 h (3G) Up to 310 h (2G) / Up to 320 h (3G) Talk time Up to 6 h 40 min (2G) and 5 h 30 min (3G) Up to 6 h 20 min (2G) / Up to 5 h 20 min (3G) Estimated Price “HTC HD 7″ is priced between  INR 27855 to 32000. though the price of “HDT Mozart” is officially not announced it is estimated to be around INR 30000. Where to Buy The Windows 7 phone is not yet available in stores directly, but most of the leading mobile stores are getting pre -orders. I have given some of the online store links below. Flip kart UniverCell This article titled,HTC to launch Windows 7 phone in India, was originally published at Tech Dreams. Grab our rss feed or fan us on Facebook to get updates from us.

    Read the article

  • Move penetrating OBB out of another OBB to resolve collision

    - by Milo
    I'm working on collision resolution for my game. I just need a good way to get an object out of another object if it gets stuck. In this case a car. Here is a typical scenario. The red car is in the green object. How do I correctly get it out so the car can slide along the edge of the object as it should. I tried: if(buildings.size() > 0) { Entity e = buildings.get(0); Vector2D vel = new Vector2D(); vel.x = vehicle.getVelocity().x; vel.y = vehicle.getVelocity().y; vel.normalize(); while(vehicle.getRect().overlaps(e.getRect())) { vehicle.setCenter(vehicle.getCenterX() - vel.x * 0.1f, vehicle.getCenterY() - vel.y * 0.1f); } colided = true; } But that does not work too well. Is there some sort of vector I could calculate to use as the vector to move the car away from the object? Thanks Here is my OBB2D class: public class OBB2D { // Corners of the box, where 0 is the lower left. private Vector2D corner[] = new Vector2D[4]; private Vector2D center = new Vector2D(); private Vector2D extents = new Vector2D(); private RectF boundingRect = new RectF(); private float angle; //Two edges of the box extended away from corner[0]. private Vector2D axis[] = new Vector2D[2]; private double origin[] = new double[2]; public OBB2D(Vector2D center, float w, float h, float angle) { set(center,w,h,angle); } public OBB2D(float left, float top, float width, float height) { set(new Vector2D(left + (width / 2), top + (height / 2)),width,height,0.0f); } public void set(Vector2D center,float w, float h,float angle) { Vector2D X = new Vector2D( (float)Math.cos(angle), (float)Math.sin(angle)); Vector2D Y = new Vector2D((float)-Math.sin(angle), (float)Math.cos(angle)); X = X.multiply( w / 2); Y = Y.multiply( h / 2); corner[0] = center.subtract(X).subtract(Y); corner[1] = center.add(X).subtract(Y); corner[2] = center.add(X).add(Y); corner[3] = center.subtract(X).add(Y); computeAxes(); extents.x = w / 2; extents.y = h / 2; computeDimensions(center,angle); } private void computeDimensions(Vector2D center,float angle) { this.center.x = center.x; this.center.y = center.y; this.angle = angle; boundingRect.left = Math.min(Math.min(corner[0].x, corner[3].x), Math.min(corner[1].x, corner[2].x)); boundingRect.top = Math.min(Math.min(corner[0].y, corner[1].y),Math.min(corner[2].y, corner[3].y)); boundingRect.right = Math.max(Math.max(corner[1].x, corner[2].x), Math.max(corner[0].x, corner[3].x)); boundingRect.bottom = Math.max(Math.max(corner[2].y, corner[3].y),Math.max(corner[0].y, corner[1].y)); } public void set(RectF rect) { set(new Vector2D(rect.centerX(),rect.centerY()),rect.width(),rect.height(),0.0f); } // Returns true if other overlaps one dimension of this. private boolean overlaps1Way(OBB2D other) { for (int a = 0; a < axis.length; ++a) { double t = other.corner[0].dot(axis[a]); // Find the extent of box 2 on axis a double tMin = t; double tMax = t; for (int c = 1; c < corner.length; ++c) { t = other.corner[c].dot(axis[a]); if (t < tMin) { tMin = t; } else if (t > tMax) { tMax = t; } } // We have to subtract off the origin // See if [tMin, tMax] intersects [0, 1] if ((tMin > 1 + origin[a]) || (tMax < origin[a])) { // There was no intersection along this dimension; // the boxes cannot possibly overlap. return false; } } // There was no dimension along which there is no intersection. // Therefore the boxes overlap. return true; } //Updates the axes after the corners move. Assumes the //corners actually form a rectangle. private void computeAxes() { axis[0] = corner[1].subtract(corner[0]); axis[1] = corner[3].subtract(corner[0]); // Make the length of each axis 1/edge length so we know any // dot product must be less than 1 to fall within the edge. for (int a = 0; a < axis.length; ++a) { axis[a] = axis[a].divide((axis[a].length() * axis[a].length())); origin[a] = corner[0].dot(axis[a]); } } public void moveTo(Vector2D center) { Vector2D centroid = (corner[0].add(corner[1]).add(corner[2]).add(corner[3])).divide(4.0f); Vector2D translation = center.subtract(centroid); for (int c = 0; c < 4; ++c) { corner[c] = corner[c].add(translation); } computeAxes(); computeDimensions(center,angle); } // Returns true if the intersection of the boxes is non-empty. public boolean overlaps(OBB2D other) { if(right() < other.left()) { return false; } if(bottom() < other.top()) { return false; } if(left() > other.right()) { return false; } if(top() > other.bottom()) { return false; } if(other.getAngle() == 0.0f && getAngle() == 0.0f) { return true; } return overlaps1Way(other) && other.overlaps1Way(this); } public Vector2D getCenter() { return center; } public float getWidth() { return extents.x * 2; } public float getHeight() { return extents.y * 2; } public void setAngle(float angle) { set(center,getWidth(),getHeight(),angle); } public float getAngle() { return angle; } public void setSize(float w,float h) { set(center,w,h,angle); } public float left() { return boundingRect.left; } public float right() { return boundingRect.right; } public float bottom() { return boundingRect.bottom; } public float top() { return boundingRect.top; } public RectF getBoundingRect() { return boundingRect; } public boolean overlaps(float left, float top, float right, float bottom) { if(right() < left) { return false; } if(bottom() < top) { return false; } if(left() > right) { return false; } if(top() > bottom) { return false; } return true; } };

    Read the article

  • Finding the normal of OBB face with an OBB penetrating

    - by Milo
    Below is an illustration: I have an OBB in an OBB (see below for OBB2D code if needed). What I need to determine is, what face it is in, and what direction do I point the normal? The goal is to get the OBB out of the OBB so the normal needs to face outward of the OBB. How could I go about: Finding what face the line is penetrating given the 4 corners of the OBB and the class below: if we define dx=x2-x1 and dy=y2-y1, then the normals are (-dy, dx) and (dy, -dx). Which normal points outward of the OBB? Thanks public class OBB2D { // Corners of the box, where 0 is the lower left. private Vector2D corner[] = new Vector2D[4]; private Vector2D center = new Vector2D(); private Vector2D extents = new Vector2D(); private RectF boundingRect = new RectF(); private float angle; //Two edges of the box extended away from corner[0]. private Vector2D axis[] = new Vector2D[2]; private double origin[] = new double[2]; public OBB2D(Vector2D center, float w, float h, float angle) { set(center,w,h,angle); } public OBB2D(float left, float top, float width, float height) { set(new Vector2D(left + (width / 2), top + (height / 2)),width,height,0.0f); } public void set(Vector2D center,float w, float h,float angle) { Vector2D X = new Vector2D( (float)Math.cos(angle), (float)Math.sin(angle)); Vector2D Y = new Vector2D((float)-Math.sin(angle), (float)Math.cos(angle)); X = X.multiply( w / 2); Y = Y.multiply( h / 2); corner[0] = center.subtract(X).subtract(Y); corner[1] = center.add(X).subtract(Y); corner[2] = center.add(X).add(Y); corner[3] = center.subtract(X).add(Y); computeAxes(); extents.x = w / 2; extents.y = h / 2; computeDimensions(center,angle); } private void computeDimensions(Vector2D center,float angle) { this.center.x = center.x; this.center.y = center.y; this.angle = angle; boundingRect.left = Math.min(Math.min(corner[0].x, corner[3].x), Math.min(corner[1].x, corner[2].x)); boundingRect.top = Math.min(Math.min(corner[0].y, corner[1].y),Math.min(corner[2].y, corner[3].y)); boundingRect.right = Math.max(Math.max(corner[1].x, corner[2].x), Math.max(corner[0].x, corner[3].x)); boundingRect.bottom = Math.max(Math.max(corner[2].y, corner[3].y),Math.max(corner[0].y, corner[1].y)); } public void set(RectF rect) { set(new Vector2D(rect.centerX(),rect.centerY()),rect.width(),rect.height(),0.0f); } // Returns true if other overlaps one dimension of this. private boolean overlaps1Way(OBB2D other) { for (int a = 0; a < axis.length; ++a) { double t = other.corner[0].dot(axis[a]); // Find the extent of box 2 on axis a double tMin = t; double tMax = t; for (int c = 1; c < corner.length; ++c) { t = other.corner[c].dot(axis[a]); if (t < tMin) { tMin = t; } else if (t > tMax) { tMax = t; } } // We have to subtract off the origin // See if [tMin, tMax] intersects [0, 1] if ((tMin > 1 + origin[a]) || (tMax < origin[a])) { // There was no intersection along this dimension; // the boxes cannot possibly overlap. return false; } } // There was no dimension along which there is no intersection. // Therefore the boxes overlap. return true; } //Updates the axes after the corners move. Assumes the //corners actually form a rectangle. private void computeAxes() { axis[0] = corner[1].subtract(corner[0]); axis[1] = corner[3].subtract(corner[0]); // Make the length of each axis 1/edge length so we know any // dot product must be less than 1 to fall within the edge. for (int a = 0; a < axis.length; ++a) { axis[a] = axis[a].divide((axis[a].length() * axis[a].length())); origin[a] = corner[0].dot(axis[a]); } } public void moveTo(Vector2D center) { Vector2D centroid = (corner[0].add(corner[1]).add(corner[2]).add(corner[3])).divide(4.0f); Vector2D translation = center.subtract(centroid); for (int c = 0; c < 4; ++c) { corner[c] = corner[c].add(translation); } computeAxes(); computeDimensions(center,angle); } // Returns true if the intersection of the boxes is non-empty. public boolean overlaps(OBB2D other) { if(right() < other.left()) { return false; } if(bottom() < other.top()) { return false; } if(left() > other.right()) { return false; } if(top() > other.bottom()) { return false; } if(other.getAngle() == 0.0f && getAngle() == 0.0f) { return true; } return overlaps1Way(other) && other.overlaps1Way(this); } public Vector2D getCenter() { return center; } public float getWidth() { return extents.x * 2; } public float getHeight() { return extents.y * 2; } public void setAngle(float angle) { set(center,getWidth(),getHeight(),angle); } public float getAngle() { return angle; } public void setSize(float w,float h) { set(center,w,h,angle); } public float left() { return boundingRect.left; } public float right() { return boundingRect.right; } public float bottom() { return boundingRect.bottom; } public float top() { return boundingRect.top; } public RectF getBoundingRect() { return boundingRect; } public boolean overlaps(float left, float top, float right, float bottom) { if(right() < left) { return false; } if(bottom() < top) { return false; } if(left() > right) { return false; } if(top() > bottom) { return false; } return true; } };

    Read the article

  • Responsive Inline Elements with Twitter Bootstrap

    - by MightyZot
    Originally posted on: http://geekswithblogs.net/MightyZot/archive/2013/11/12/responsive-inline-elements-with-twitter-bootstrap.aspxTwitter Boostrap is a responsive css platform created by some dudes affiliated with Twitter and since supported and maintained by an open source following. I absolutely love the new version of this css toolkit. They rebuilt it with a mobile first strategy and it’s very easy to layout pages once you get the hang of it. Using a css / javascript framework like bootstrap is certainly much easier than coding your layout by hand. And, you get a “leg up” when it comes to adding responsive features to your site. Bootstrap includes column layout classes that let you specify size and placement based upon the viewport width. In addition, there are a handful of responsive helpers to hide and show content based upon the user’s device size. Most notably, the visible-xs, visible-sm, visible-md, and visible-lg classes let you show content for devices corresponding to those sizes (they are listed in the bootstrap docs.) hidden-xs, hidden-sm, hidden-md, and hidden-lg let you hide content for devices with those respective sizes. These helpers work great for showing and hiding block elements. Unfortunately, there isn’t a provision yet in Twitter Bootstrap (as of the time of this writing) for inline elements. We are using the navbar classes to create a navigation bar at the top of our website, www.crowdit.com. When you shrink the width of the screen to tablet or phone size, the tools in the navbar are turned into a drop down menu, and a button appears on the right side of the navbar. This is great! But, we wanted different content to display based upon whether the items were on the navbar versus when they were in the dropdown menu. The visible-?? and hidden-?? classes make this easy for images and block elements. In our case, we wanted our anchors to show different text depending upon whether they’re in the navbar, or in the dropdown. span is inherently inline and it can be a block element. My first approach was to create two anchors for each options, one set visible when the navbar is on a desktop or laptop with a wide display and another set visible when the elements converted to a dropdown menu. That works fine with the visible-?? and hidden-?? classes, but it just doesn’t seem that clean to me. I put up with that for about a week…last night I created the following classes to augment the block-based classes provided by bootstrap. .cdt-hidden-xs, .cdt-hidden-sm, .cdt-hidden-md, .cdt-hidden-lg {     display: inline !important; } @media (max-width:767px) {     .cdt-hidden-xs, .cdt-hidden-sm.cdt-hidden-xs, .cdt-hidden-md.cdt-hidden-xs, .cdt-hidden-lg.cdt-hidden-xs {         display: none !important;     } } @media (min-width:768px) and (max-width:991px) {     .cdt-hidden-xs.cdt-hidden-sm, .cdt-hidden-sm, .cdt-hidden-md.cdt-hidden-sm, .cdt-hidden-lg.cdt-hidden-sm {         display: none !important;     } } @media (min-width:992px) and (max-width:1199px) {     .cdt-hidden-xs.cdt-hidden-md, .cdt-hidden-sm.cdt-hidden-md, .cdt-hidden-md, .cdt-hidden-lg.cdt-hidden-md {         display: none !important;     } } @media (min-width:1200px) {     .cdt-hidden-xs.cdt-hidden-lg, .cdt-hidden-sm.cdt-hidden-lg, .cdt-hidden-md.cdt-hidden-lg, .cdt-hidden-lg {         display: none !important;     } } .cdt-visible-xs, .cdt-visible-sm, .cdt-visible-md, .cdt-visible-lg {     display: none !important; } @media (max-width:767px) {     .cdt-visible-xs, .cdt-visible-sm.cdt-visible-xs, .cdt-visible-md.cdt-visible-xs, .cdt-visible-lg.cdt-visible-xs {         display: inline !important;     } } @media (min-width:768px) and (max-width:991px) {     .cdt-visible-xs.cdt-visible-sm, .cdt-visible-sm, .cdt-visible-md.cdt-visible-sm, .cdt-visible-lg.cdt-visible-sm {         display: inline !important;     } } @media (min-width:992px) and (max-width:1199px) {     .cdt-visible-xs.cdt-visible-md, .cdt-visible-sm.cdt-visible-md, .cdt-visible-md, .cdt-visible-lg.cdt-visible-md {         display: inline !important;     } } @media (min-width:1200px) {     .cdt-visible-xs.cdt-visible-lg, .cdt-visible-sm.cdt-visible-lg, .cdt-visible-md.cdt-visible-lg, .cdt-visible-lg {         display: inline !important;     } } I created these by looking at the example provided by bootstrap and consolidating the styles. “cdt” is just a prefix that I’m using to distinguish these classes from the block-based classes in bootstrap. You are welcome to change the prefix to whatever feels right for you. These classes can be applied to spans in textual content to hide and show text based upon the browser width. Applying the styles is simple… <span class=”cdt-visible-xs”>This text is visible in extra small</span> <span class=”cdt-visible-sm”>This text is visible in small</span> Why would you want to do this? Here are a couple of examples, shown in screen shots. This is the CrowdIt navbar on larger displays. Notice how the text is two line and certain words are capitalized? Now, check this out! Here is a screen shot showing the dropdown menu that’s displayed when the browser window is tablet or phone sized. The markup to make this happen is quite simple…take a look. <li>     <a href="@Url.Action("what-is-crowdit","home")" title="Learn about what CrowdIt can do for your Small Business">         <span class="cdt-hidden-xs">WHAT<br /><small>is CrowdIt?</small></span>         <span class="cdt-visible-xs">What is CrowdIt?</span>     </a> </li> There is a single anchor tag in this example and only the spans change visibility based on browser width. I left them separate for readability and because I wanted to use the small tag; however, you could just as easily hide the “WHAT” and the br tag on small displays and replace them with “What “, consolidating this even further to text containing a single span. <span class=”cdt-hidden-xs”>WHAT<br /></span><span class=”cdt-visible-xs”>What </span>is CrowdIt? You might be a master of css and have a better method of handling this problem. If so, I’d love to hear about your solution…leave me some feedback! You’ll be entered into a drawing for a chance to win an autographed picture of ME! Yay!

    Read the article

  • writing programs without compiler?

    - by Matt
    I am not sure if this is even possible but I have watched a few videos with programming examples where it seems like the program is being written in some kind of command prompt rather than a nice graphical compiler. Im just curious as to what might be going on in these videos. Is it possible to write a program without a compiler? heres two examples: http://www.youtube.com/watch?v=hFSY9cWjO8o( @ 6 min) http://www.youtube.com/watch?v=tKTZoB2Vjuk (@ 5 min) Could anyone explain how this is done?

    Read the article

  • Is there a CDN for backbone.marionette?

    - by Thunder Rabbit
    Getting started with Backbone and Marionette, I was about to copy the file at https://github.com/marionettejs/backbone.marionette/blob/master/lib/backbone.marionette.js to my local server, but wondered if there was a CDN version of it. For Underscore and Backbone dev, I'm including these two files, respectively: http://documentcloud.github.com/underscore/underscore-min.js http://documentcloud.github.com/backbone/backbone-min.js Is there a similar URL for backbone.marrionette.js?

    Read the article

  • Writing programs without graphical IDE

    - by Matt
    I am not sure if this is even possible but I have watched a few videos with programming examples where it seems like the program is being written in some kind of command prompt rather than a nice graphical IDE. Im just curious as to what might be going on in these videos. Is it possible to write a program without an IDE? heres two examples: http://www.youtube.com/watch?v=hFSY9cWjO8o( @ 6 min) http://www.youtube.com/watch?v=tKTZoB2Vjuk (@ 5 min) Could anyone explain how this is done?

    Read the article

  • Getting Started with jqChart for ASP.NET Web Forms

    - by jqChart
    Official Site | Samples | Download | Documentation | Forum | Twitter Introduction jqChart takes advantages of HTML5 Canvas to deliver high performance client-side charts and graphs across browsers (IE 6+, Firefox, Chrome, Opera, Safari) and devices, including iOS and Android mobile devices. Some of the key features are: High performance rendering. Animaitons. Scrolling/Zoooming. Support for unlimited number of data series and data points. Support for unlimited number of chart axes. True DateTime Axis. Logarithmic and Reversed axis scale. Large set of chart types - Bar, Column, Pie, Line, Spline, Area, Scatter, Bubble, Radar, Polar. Financial Charts - Stock Chart and Candlestick Chart. The different chart types can be easily combined.  System Requirements Browser Support jqChart supports all major browsers: Internet Explorer - 6+ Firefox Google Chrome Opera Safari jQuery version support jQuery JavaScript framework is required. We recommend using the latest official stable version of the jQuery library. Visual Studio Support jqChart for ASP.NET does not require using Visual Studio. You can use your favourite code editor. Still, the product has been tested with several versions of Visual Studio .NET and you can find the list of supported versions below: Visual Studio 2008 Visual Studio 2010 Visual Studio 2012 ASP.NET Web Forms support Supported version - ASP.NET Web Forms 3.5, 4.0 and 4.5 Installation Download and unzip the contents of the archive to any convenient location. The package contains the following folders: [bin] - Contains the assembly DLLs of the product (JQChart.Web.dll) for WebForms 3.5, 4.0 and 4.5. This is the assembly that you can reference directly in your web project (or better yet, add it to your ToolBox and then drag & drop it from there). [js] - The javascript files of jqChart and jqRangeSlider (and the needed libraries). You need to include them in your ASPX page, in order to gain the client side functionality of the chart. The first file is "jquery-1.5.1.min.js" - this is the official jQuery library. jqChart is built upon jQuery library version 1.4.3. The second file you need is the "excanvas.js" javascript file. It is used from the versions of IE, which dosn't support canvas graphics. The third is the jqChart javascript code itself, located in "jquery.jqChart.min.js". The last one is the jqRangeSlider javascript, located in "jquery.jqRangeSlider.min.js". It is used when the chart zooming is enabled. [css] - Contains the Css files that the jqChart and the jqRangeSlider need. [samples] - Contains some examples that use the jqChart. For full list of samples plese visit - jqChart for ASP.NET Samples. [themes] - Contains the themes shipped with the products. It is used from the jqRangeSlider. Since jqRangeSlider supports jQuery UI Themeroller, any theme compatible with jQuery UI ThemeRoller will work for jqRangeSlider as well. You can download any additional themes directly from jQuery UI's ThemeRoller site available here: http://jqueryui.com/themeroller/ or reference them from Microsoft's / Google's CDN. <link rel="stylesheet" type="text/css" media="screen" href="http://ajax.aspnetcdn.com/ajax/jquery.ui/1.8.21/themes/smoothness/jquery-ui.css" /> The final result you will have in an ASPX page containing jqChart would be something similar to that (assuming you have copied the [js] to the Script folder and [css] to Content folder of your ASP.NET site respectively). <%@ Page Language="C#" AutoEventWireup="true" CodeBehind="Default.aspx.cs" Inherits="samples_cs.Default" %> <%@ Register Assembly="JQChart.Web" Namespace="JQChart.Web.UI.WebControls" TagPrefix="jqChart" %> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html > <head runat="server"> <title>jqChart ASP.NET Sample</title> <link rel="stylesheet" type="text/css" href="~/Content/jquery.jqChart.css" /> <link rel="stylesheet" type="text/css" href="~/Content/jquery.jqRangeSlider.css" /> <link rel="stylesheet" type="text/css" href="~/Content/themes/smoothness/jquery-ui-1.8.21.css" /> <script src="<% = ResolveUrl("~/Scripts/jquery-1.5.1.min.js") %>" type="text/javascript"></script> <script src="<% = ResolveUrl("~/Scripts/jquery.jqRangeSlider.min.js") %>" type="text/javascript"></script> <script src="<% = ResolveUrl("~/Scripts/jquery.jqChart.min.js") %>" type="text/javascript"></script> <!--[if IE]><script lang="javascript" type="text/javascript" src="<% = ResolveUrl("~/Scripts/excanvas.js") %>"></script><![endif]--> </head> <body> <form id="form1" runat="server"> <asp:ObjectDataSource ID="ObjectDataSource1" runat="server" SelectMethod="GetData" TypeName="SamplesBrowser.Models.ChartData"></asp:ObjectDataSource> <jqChart:Chart ID="Chart1" Width="500px" Height="300px" runat="server" DataSourceID="ObjectDataSource1"> <Title Text="Chart Title"></Title> <Animation Enabled="True" Duration="00:00:01" /> <Axes> <jqChart:CategoryAxis Location="Bottom" ZoomEnabled="true"> </jqChart:CategoryAxis> </Axes> <Series> <jqChart:ColumnSeries XValuesField="Label" YValuesField="Value1" Title="Column"> </jqChart:ColumnSeries> <jqChart:LineSeries XValuesField="Label" YValuesField="Value2" Title="Line"> </jqChart:LineSeries> </Series> </jqChart:Chart> </form> </body> </html>   Official Site | Samples | Download | Documentation | Forum | Twitter

    Read the article

  • How to code Microsoft Excel "Shift Cells Up" feature in SQL

    - by user293249
    Take a simple table like below: Column Headings: || Agent's Name || Time Logged In || Center || Row 1: Andrew || 12:30 PM || Home Base Row 2: Jeff || 7:00 AM || Virtual Base Row 3: Ryan || 6:30 PM || Test Base Now lets say that a single cell is deleted so the table now looks like this: Column Headings: || Agent's Name || Time Logged In || Center || Row 1: Andrew || 12:30 PM || Row 2: Jeff || 7:00 AM || Virtual Base Row 3: Ryan || 6:30 PM || Test Base Notice that "Home Base" is missing. Now in excel you can delete the cell and shift the rest so the finished product looks like below: Column Headings: || Agent's Name || Time Logged In || Center || Row 1: Andrew || 12:30 PM || Virtual Base Row 2: Jeff || 7:00 AM || Test Base Row 3: Ryan || 6:30 PM || And you can see we are left with a blank cell last row. How do I code this procedure of shifting the cells up in SQL? I've been struggling on this problem for weeks! Thank you!

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 9 10 11 12 13 14 15 16 17 18 19 20  | Next Page >