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• Read a file to multiple array byte[]

  - by hankol

  I have an encryption algorithm (AES) that accepts file converted to array byte and encrypt it. Since I am going to process a very big size files, the JVM may go out of memory. I am planing to read the files in multiple array byte. each containing some part of the file. Then I teratively feed the algorithm. Finally merge them to produce encrypted file. So my question is: there any way to read a file part by part to multiple array byte? I thought I can use the following to read the file to array byte: IOUtils.toByteArray(InputStream input). And then split the array into multiple bytes using: Arrays.copyOfRange(). But I am afraid that the first code that reads file to byte will make the JVM to go out of memory. any suggestion please ? thanks

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• Byte Size Tips: How to Disable the Useless Dashboard on Mac OS X

  - by The Geek

  After getting my new MacBook Air with the awesome battery life, I decided to give OS X a spin for a while to see how I liked it. About 34 seconds later, I encountered my first irritation: The stupid Dashboard feature is just completely useless. Here’s how to disable it. Note: overall, Mac OS X is a really great operating system. It’s just this one feature that makes no sense. Simply Remove Dashboard from Spaces     

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• Byte Size Tips: How to Change Your Computer Name on Mac OS X

  - by The Geek

  When you’re sharing stuff back and forth between your computers, the names of those computers actually start to matter — in my case, I upgraded to a new MacBook Air because my old one has a dead screen and is out of warranty, so I made it into a desktop with an external monitor. That’s when I got an error that my two Macs had the same name. Oops! Luckily it’s an extremely easy fix. Just open up System Preferences, go to Sharing, and change the computer name. Done! You can also change it from the Terminal using this command, though obviously it’s much simpler to just change it under Sharing.     

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• Demantra Performance Clustering Factor Out of Order Ratio TABLE_REORG CHECK_REORG (Doc ID 1594372.1)

  - by user702295

  Hello!   There is a new document available: Demantra Performance Clustering Factor Out of Order Ratio TABLE_REORG CHECK_REORG (Doc ID 1594372.1) Demantra Performance Clustering Factor Out of Order Ratio TABLE_REORG CHECK_REORG The table reorganization can be setup to automatically run in version 7.3.1.5.  In version 12.2.2 we run the TABLE_REORG.CHECK_REORG function at every appserver restart. If the function recommends a reorg then we strongly encourage to reorg the database object.  This is documented in the official docs. In versions 7.3.1.3 and 7.3.1.4, the TABLE_REORG module exists and can be used. It has two main functions that are documented in the Implementation Guide Supplement, Release 7.3, Part No. E26760-03, chapter 4. In short, if you are using version 7.3.1.3 or higher, you can check for the need to run a reorg by doing the following 2 steps: 1. Run TABLE_REORG.CHECK_REORG('T'); 2. Check the table LOG_TABLE_REORG for recommendations If you are on a version before 7.3.1.3, you will need to follow the instructions below to determine if you need to do a manual reorg. How to determine if a table reorg is needed 1. It is strongly encouraged by DEV that You gather statistics on the required table.  The prefered percentage for the gather is 100%. 2. Run the following SQL to evaluate how table reorg might affect Primary Key (PK) based access:   SELECT ui.index_name,trunc((ut.num_rows/ui.clustering_factor)/(ut.num_rows/ut.blocks),2) FROM user_indexes ui, user_tables ut, user_constraints uc WHERE ui.table_name=ut.table_name AND ut.table_name=uc.table_name AND ui.index_name=uc.index_name AND UC.CONSTRAINT_TYPE='P' AND ut.table_name=upper('&enter_table_name');   3. Based on the result: VALUE ABOVE 0.75 - DOES NOT REQUIRE REORG VALUE BETWEEN 0.5 AND 0.75 - REORG IS RECOMMENDED VALUE LOWER THAN 0.5 - IT IS HIGHLY RECOMMENDED TO REORG

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• Byte Size Tips: How to Stop OS X from Changing the Display Brightness Automatically

  - by The Geek

  After getting a new MacBook Air and deciding to try out OS X for a while, I started wondering why the battery would suddenly start dying really fast, but only when I was sitting at the kitchen table. That’s when I noticed the display brightness kept changing on its own… and realized the problem. OS X, just like your phone, and any modern device, tries to figure out the brightness of the room you’re in, and adjust the brightness of the screen. If you are over in Windows, it’s called “Adaptive” brightness, while your phone will just call it “Auto”. While this technology is great in theory, I don’t really need max brightness all the time, and I like to control it manually to make sure I’m getting the best battery life. Open up System Preferences, head to Displays. Then uncheck the Automatically adjust brightness setting.     

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• isometric drawing order with larger than single tile images - drawing order algorithm?

  - by Roger Smith

  I have an isometric map over which I place various images. Most images will fit over a single tile, but some images are slightly larger. For example, I have a bed of size 2x3 tiles. This creates a problem when drawing my objects to the screen as I get some tiles erroneously overlapping other tiles. The two solutions that I know of are either splitting the image into 1x1 tile segments or implementing my own draw order algorithm, for example by assigning each image a number. The image with number 1 is drawn first, then 2, 3 etc. Does anyone have advice on what I should do? It seems to me like splitting an isometric image is very non obvious. How do you decide which parts of the image are 'in' a particular tile? I can't afford to split up all of my images manually either. The draw order algorithm seems like a nicer choice but I am not sure if it's going to be easy to implement. I can't solve, in my head, how to deal with situations whereby you change the index of one image, which causes a knock on effect to many other images. If anyone has an resources/tutorials on this I would be most grateful.

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• Z-order with Alpha blending in a 3D world

  - by user41765

  I'm working on a game in a 3D world with 2D sprites only (like Don't Starve game). (OpenGL ES2 with C++) Currently, I'm ordering elements back to front before drawing them without batch (so 1 element = 1 drawcall). I would like to implement batching in my framework to decrease draw calls. Here is what I've got for the moment: Order all elements of my scene back to front. Send order list of elements to the Renderer. Renderer look in his batch manager if a batch exist for the given element with his Material. Batch didn't exist: create a new one. Batch exist for element with this Material: Add sprite to the batch. Compute big mesh with all sprite for each batch (1 material type = 1 batch). When all batches are ok, the batch manager compute draw commands for the renderer. Renderer process draw commands (bind shader, bind textures, bind buffers, draw element) Image with my problem here: Explication here But I've got some problems because objects can be behind another objects inside another batch. How can I do something like that? Thanks!

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• Order in which passphrase is asked for encrypted volumes

  - by Lars Kotthoff

  I have installed 12.10 on a machine with two disks. The root partition is on one disk, the swap partition on the other. Both disks are encrypted and I have added the corresponding entries to /etc/crypttab. During boot, it asks for the passphrase for the disk with the root filesystem. Then it continues booting and gets to the login screen before I get a chance to enter the passphrase for the other disk. After logging in, I verified that it was actually waiting for me to enter the passphrase for that second partition (askpass process is running). But at that point, I have no way of entering the passphrase anymore. The manpage for crypttab suggests that the order in which the volumes are specified matters, so I changed it to have the swap disk first. I updated the initramfs and grub afterwards, but it didn't make any difference. How can I specify the order in which the encrypted partitions are unlocked? I'm looking for a solution that either asks for the swap passphrase first or tells the system to wait until all encrypted partitions are unlocked before displaying the login screen.

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• Byte Size Tips: How to Show Google / Gmail Contacts in the OS X Contacts App

  - by The Geek

  The Contacts app on OS X isn’t very interesting, but if you can use it to display your Gmail contacts, it’ll get a little bit better. Luckily it’s pretty easy to add your Google / Gmail contacts, but you’ll have to click the mouse a few times and maybe poke at the old keyboard once or twice to type in your email address and password. It’s worth noting that if you set up Gmail in the Mail app you shouldn’t have to do this. Since we prefer Gmail in a browser, that’s why we’re writing this. Or just because we’re procrastinating the book editing that we’re supposed to be doing. Don’t judge. Start by opening the Preferences for the Contacts app by heading up to the Menu bar. Go to Accounts and then click the + sign to add a new one. Choose CardDAV for the account type, use your Gmail username and password, and put google.com as the server address. If you are using two-factor authentication, you’ll need to create a specific password for this account.    

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• Byte Size Tips: How to Insert a YouTube Video Into a PowerPoint Presentation in Office 2013

  - by Taylor Gibb

  How many times have you needed to show a video during a presentation? Using YouTube and PowerPoint, it is now possible. Insert a YouTube Video Into a PowerPoint Presentation in Office 2013 Go ahead and open PowerPoint and switch over to the Insert tab. Then click on Video, and then Online Video… If this is your first time inserting a video from YouTube, you will need to add it as a provider from the bottom left hand side of the dialog. Once added, you will be able to enter a search term. You can then simply select a video and hit the insert button. That’s all there is to it. Remember Videos come with their own set of editing options, so be sure to take a look around.     

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• Internet Explorer menu z-order problem [migrated]

  - by robgt

  I have what appears to be a z-order problem with Internet Explorer 9. It might be in other IE versions also, but not tested. I have to assume so. This page: http://www.modelhelicopters.co.uk/partsfinder/trex500esp/frames If you hover over the "All pages for this model" menu item on the parts finder menu bar (below the currency selector) - it should drop down a list of all the parts finder pages for the selected model helicopter. If you view the same page in IE or Chrome etc, you will see how it should appear. In IE9, the menu gets cut off at the top of the main exploded view image - suggesting the z-order is wrong. I have tried amending this with a jquery snippet but it didn't fix IE9. I know the code was inserted by jquery as shown by firebug in firefox. $j('div.std img[src*="/partsfinder/img"]').attr("style","position:relative;z-index:-100;"); I really do not know why this is not working.

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• Requiring a specific order of compilaiton

  - by Aber Kled

  When designing a compiled programming language, is it a bad idea to require a specific order of compilation of separate units, according to their dependencies? To illustrate what I mean, consider C. C is the opposite of what I'm suggesting. There are multiple .c files, that can all depend on each other, but all of these separate units can be compiled on their own, in no particular order - only to be linked together into a final executable later. This is mostly due to header files. They enable separate units to share information with each other, and thus the units are able to be compiled independently. If a language were to dispose of header files, and only keep source and object files, then the only option would be to actually include the unit's meta-information in the unit's object file. However, this would mean that if the unit A depends on the unit B, then the unit B would need to be compiled before unit A, so unit A could "import" the unit B's object file, thus obtaining the information required for its compilation. Am I missing something here? Is this really the only way to go about removing header files in compiled languages?

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• Marshalling a big-endian byte collection into a struct in order to pull out values

  - by Pat

  There is an insightful question about reading a C/C++ data structure in C# from a byte array, but I cannot get the code to work for my collection of big-endian (network byte order) bytes. (EDIT: Note that my real struct has more than just one field.) Is there a way to marshal the bytes into a big-endian version of the structure and then pull out the values in the endianness of the framework (that of the host, which is usually little-endian)? This should summarize what I'm looking for (LE=LittleEndian, BE=BigEndian): void Main() { var leBytes = new byte[] {1, 0}; var beBytes = new byte[] {0, 1}; Foo fooLe = ByteArrayToStructure<Foo>(leBytes); Foo fooBe = ByteArrayToStructureBigEndian<Foo>(beBytes); Assert.AreEqual(fooLe, fooBe); } [StructLayout(LayoutKind.Explicit, Size=2)] public struct Foo { [FieldOffset(0)] public ushort firstUshort; } T ByteArrayToStructure<T>(byte[] bytes) where T: struct { GCHandle handle = GCHandle.Alloc(bytes, GCHandleType.Pinned); T stuff = (T)Marshal.PtrToStructure(handle.AddrOfPinnedObject(),typeof(T)); handle.Free(); return stuff; } T ByteArrayToStructureBigEndian<T>(byte[] bytes) where T: struct { ??? }

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• Byte-Pairing for data compression

  - by user1669533

  Question about Byte-Pairing for data compression. If byte pairing converts two byte values to a single byte value, splitting the file in half, then taking a gig file and recusing it 16 times shrinks it to 62,500,000. My question is, is byte-pairing really efficient? Is the creation of a 5,000,000 iteration loop, to be conservative, efficient? I would like some feed back on and some incisive opinions please. Dave, what I read was: "The US patent office no longer grants patents on perpetual motion machines, but has recently granted at least two patents on a mathematically impossible process: compression of truly random data." I was not inferring the Patent Office was actually considering what I am inquiring about. I was merely commenting on the notion of a "mathematically impossible process." If someone has, in some way created a method of having a "single" data byte as a placeholder of 8 individual bytes of data, that would be a consideration for a patent. Now, about the mathematically impossibility of an 8 to 1 compression method, it is not so much a mathematically impossibility, but a series of rules and conditions that can be created. As long as there is the rule of 8 or 16 bit representation of storing data on a medium, there are ways to manipulate data that mirrors current methods, or creation by a new way of thinking.

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• Scale an image which is stored as a byte[] in Java

  - by Sergio del Amo

  I upload a file with a struts form. I have the image as a byte[] and I would like to scale it. FormFile file = (FormFile) dynaform.get("file"); byte[] fileData = file.getFileData(); fileData = scale(fileData,200,200); public byte[] scale(byte[] fileData, int width, int height) { // TODO } Anyone knows an easy function to do this? public byte[] scale(byte[] fileData, int width, int height) { ByteArrayInputStream in = new ByteArrayInputStream(fileData); try { BufferedImage img = ImageIO.read(in); if(height == 0) { height = (width * img.getHeight())/ img.getWidth(); } if(width == 0) { width = (height * img.getWidth())/ img.getHeight(); } Image scaledImage = img.getScaledInstance(width, height, Image.SCALE_SMOOTH); BufferedImage imageBuff = new BufferedImage(width, height, BufferedImage.TYPE_INT_RGB); imageBuff.getGraphics().drawImage(scaledImage, 0, 0, new Color(0,0,0), null); ByteArrayOutputStream buffer = new ByteArrayOutputStream(); ImageIO.write(imageBuff, "jpg", buffer); return buffer.toByteArray(); } catch (IOException e) { throw new ApplicationException("IOException in scale"); } } If you run out of Java Heap Space in tomcat as I did, increase the heap space which is used by tomcat. In case you use the tomcat plugin for Eclipse, next should apply: In Eclipse, choose Window Preferences Tomcat JVM Settings Add the following to the JVM Parameters section -Xms256m -Xmx512m

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• how to send image to remote server using webservices in android only save to byte array

  - by satyamurthy

  get image from sdcard and store that image to remote server. i am getting the image from sdcard and i converterd that image to bytearray by using bitmap .but what's the problem if i oberver byte array it is showing some different values it is not matching with .net image byte array conversion. can u pl help if you have any solution it is very urgent to me following is the code i am using can u pl suggest me FileInputStream fin = new FileInputStream(new File("/sdcard/pictures/1.jpg")); BufferedInputStream bis = new BufferedInputStream(fin,3000); byte[] data = new byte[bis.available()]; bis.read(data, 0, data.length); byte[] data1=new byte[data.length]; for (int i = 0; i < data.length; i++) { System.out.print(data[i]); data1[i]=data[i]; } System.out.println("5..................."+data1); Bitmap bitmap = BitmapFactory.decodeByteArray(data1,0,data1.length); System.out.println("6..................."+data1.length); Log.v("hgfjohfjghjdfhgj",""+bitmap); if(bitmap!=null) image.setImageBitmap(bitmap); else Log.e("Bitmap "," Not Created");

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• java packets byte

  - by user303289

  Guys, I am implementing a protocol in one of the wireless project. I am stucked at one point. In of the java file i am suppose to receive a packet and that packet is 12 byte packet and I have to write different functions for reading different parts of packets and convert it to diferent type. Like I want first four byte in one of the function and convert it to int, next two bytes in string. and again next two in string, last two hop in string and followed by last two int. I want follwing function to implement: // here is the interface /* FloodingData should use methods defined in this class. */ class FloodingPacket{ public static void main(String arg[]){ byte FloodingPack[]; // just for example to test in code FloodingPack=new byte[12]; interface IFloodingPacket { // Returns the unique sequence number for the packet int getSequenceNumber() ; // Returns the source address for the packet String getSourceAddress(); // Returns the destination address for the packet String getDestinationAddress(); // Returns the last hop address for the packet String getLastHopAddress(); // Sets the last hop address to the address of the node // which the packet was received from void updateLastHopAddress(); // Returns the entire packet in bytes (for sending) byte[] getBytes(); // Sets the bytes of the packet (for receiving) void setBytes(byte[] packet); }

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• Configure startup order of websphere application withing EAR

  - by Lukasz L.

  Is it possible to define startup order of the WebSphere enterprise application within EAR (some of descriptor/binding files, META-INF or anywhere else)? The procedure described in IBM InfoCenter requires using AdminConsole, but I would prefer to set fixed order in the EAR to assert that our 2 EAR's will start in fixed order (one is requiring the other to start before). Unfortunatelly, I haven't found in Internet any way for setting startup order other then AdminConsole/wsadmin. I don't want to go into AdminConsole each time I redeploy the EAR.

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• Order of learning sort algorithms

  - by user619818

  I have already studied bubblesort, insertion sort and selection sort and can implement them in C pretty much from knowledge of the algorithm. I want to go on to learn shellsort, merge sort, heapsort and quicksort, which I guess are a lot harder to understand. What order should I take these other sort algos? I am assuming a simpler sort algo helps learn a more complex one. Don't mind taking on some others if it helps the learning process.

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• Finding the lowest average Hamming distance when the order of the strings matter

  - by user1049697

  I have a sequence of binary strings that I want to find a match for among a set of longer sequences of binary strings. A match means that the compared sequence gives the lowest average Hamming distance when all elements in the shorter sequence have been matched against a sequence in one of the longer sets. Let me try to explain with an example. I have a set of video frames that have been hashed using a perceptual hashing algorithm so that the video frames that look the same has roughly the same hash. I want to match a short video clip against a set of longer videos, to see if the clip is contained in one of these. This means that I need to find out where the sequence of the hashed frames in the short video has the lowest average Hamming distance when compared with the long videos. The short video is the sub strings Sub1, Sub2 and Sub3, and I want to match them against the hashes of the long videos in Src. The clue here is that the strings need to match in the specific order that they are given in, e.g. that Sub1 always has to match the element before Sub2, and Sub2 always has to match the element before Sub3. In this example it would map thusly: Sub1-Src3, Sub2-Src4 and Sub3-Src5. So the question is this: is there an algorithm for finding the lowest average Hamming distance when the order of the elements compared matter? The naïve approach to compare the substring sequence to every source string won't cut it of course, so I need something that preferably can match a (much) shorter sub string to a set of million of elements. I have looked at MVP-trees, BK-trees and similar, but everything seems to only take into account one binary string and not a sequence of them. Sub1: 100111011111011101 Sub2: 110111000010010100 Sub3: 111111010110101101 Src1: 001011010001010110 Src2: 010111101000111001 Src3: 101111001110011101 Src4: 010111100011010101 Src5: 001111010110111101 Src6: 101011111111010101 I have added a calculation of the examples below. (The Hamming distances aren't correct, but it doesn't matter) **Run 1.** dist(Sub1, Src1) = 8 dist(Sub2, Src2) = 10 dist(Sub3, Src3) = 12 average = 10 **Run 2.** dist(Sub1, Src2) = 10 dist(Sub2, Src3) = 12 dist(Sub3, Src4) = 10 average = 11 **Run 3.** dist(Sub1, Src3) = 7 dist(Sub2, Src4) = 6 dist(Sub3, Src5) = 10 average = 8 **Run 4.** dist(Sub1, Src3) = 10 dist(Sub2, Src4) = 4 dist(Sub3, Src5) = 2 average = 5 So the winner here is sequence 4 with an average distance of 5.

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• Order of partitions for root, home and swap with respect to Windows partitions

  - by Tim

  I am installing Ubuntu on the same hard drive as Windows 7. The partitions of Windows 7 have already occupied the left part of the hard drive. I was wondering how to arrange the order of partitions of root, home and swap, i.e. which is on the left just besides one Windows partition, which is in the middle and which is on the far right? Is there some consideration regarding about this arrangement? Thanks and regards!

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• Finding the order of a set's elements

  - by Maciej Stachowski

  A little rephrased, in the form of a game, real-life problem: Suppose there is a set of elements {1, 2, ..., n}. Player A has chosen a single permutation of this set. Player B wants to find out the order of the elements by asking questions of form "Is X earlier in the permutation than Y?", where X and Y are elements of the set. Assuming B wants to minimize the amount of questions, how many times would he have to ask, and what would be the algorithm?

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• How do I change the grub boot order?

  - by chrisjlee

  I've got windows 7 and ubuntu installed on a shared machine. A lot of the non-developers use windows. Currently the order of boot looks like the following (but not word for word) Ubuntu 11.10 kernelgeneric *86 Ubuntu 11.10 kernelgeneric *86 (safe boot) Memory test Memory test Windows 7 on /sda/blah blah How do i change it to default as windows 7 at the top of the list? Windows 7 on /sda/blah blah Ubuntu 11.10 kernelgeneric *86 Ubuntu 11.10 kernelgeneric *86 (safe boot) Memory test Memory test

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• Spring AOP advice order

  - by Chetter Hummin

  In Spring AOP, I can add an aspect at the following locations before a method executes (using MethodBeforeAdvice) after a method executes (using AfterReturningAdvice) around a method (both before and after a method executes) (using MethodInterceptor) If I have all three types of advice, is the order of execution always as follows? Around (before part) Before Method itself After Around (after part)

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• Website Mistake #17 - Order Buttons

  We see this mistake quite a bit or maybe we don't! So many times we see order buttons and form submit buttons that don't appear to be buttons.

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