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  • Getting ActiveRecord (Rails) to_xml to use xsi:nil and xsi:type instead of nil and type

    - by nbeyer
    The default behavior of XML serialization (to_xml) for ActiveRecord objects will emit 'type' and 'nil' attributes that are similar to XML Schema Instance attributes, but aren't set in a XML Namespace. For example, a model might produce an output like this: <user> <username nil="true" /> <first-name type="string">Name</first-name> </user> Is there anyway to get to_xml to utilize the XML Schema Instance namespace and prefix the attributes and the values? Using the above example, I'd like to produce the following: <user xmlns:xsi="http://www.w3.org/1999/XMLSchema-instance" xmlns:xs="http://www.w3.org/1999/XMLSchema"> <username xsi:nil="true" /> <first-name xsi:type="xs:string">Name</first-name> </user>

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  • Type attribute for text_field

    - by Koning Baard XIV
    I have this code: <%= f.text_field :email, :type => "email", :placeholder => "[email protected]" %> So people can enter their email on an iPhone with the email keyboard instead of the ASCII keyboard. However, the output is: <input id="user_email" name="user[email]" placeholder="[email protected]" size="30" type="text" /> which should be: <input id="user_email" name="user[email]" placeholder="[email protected]" size="30" type="email" /> Is there a way to force Rails to use the email type instead of text, or must I use HTML directly? Thanks

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  • wpf: design time error while writing Nested type in xaml

    - by viky
    I have created a usercontrol which accept type of enum and assign the values of that enum to a ComboBox control in that usercontrol. Very Simple. I am using this user control in DataTemplates. Problem comes when there comes nested type. I assign that using this notation EnumType="{x:Type myNamespace:ParentType + NestedType}" It works fine at runtime. but at design time it throws error saying Could not create an instance of type 'TypeExtension' Why? Due to this I am not able to see my window at design time. Any help?

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  • Java class object from type variable

    - by Alexander Temerev
    Is there a way to get Class object from the type variable in Java generic class? Something like that: public class Bar extends Foo<T> { public Class getParameterClass() { return T.class; // doesn't compile } } This type information is available at compile time and therefore should not be affected by type erasure, so, theoretically, there should be a way to accomplish this. Does it exist?

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  • Unboxing to unknown type

    - by Robert
    I'm trying to figure out syntax that supports unboxing an integral type (short/int/long) to its intrinsic type, when the type itself is unknown. Here is a completely contrived example that demonstrates the concept: // Just a simple container that returns values as objects struct DataStruct { public short ShortVale; public int IntValue; public long LongValue; public object GetBoxedShortValue() { return LongValue; } public object GetBoxedIntValue() { return LongValue; } public object GetBoxedLongValue() { return LongValue; } } static void Main( string[] args ) { DataStruct data; // Initialize data - any value will do data.LongValue = data.IntValue = data.ShortVale = 42; DataStruct newData; // This works if you know the type you are expecting! newData.ShortVale = (short)data.GetBoxedShortValue(); newData.IntValue = (int)data.GetBoxedIntValue(); newData.LongValue = (long)data.GetBoxedLongValue(); // But what about when you don't know? newData.ShortVale = data.GetBoxedShortValue(); // error newData.IntValue = data.GetBoxedIntValue(); // error newData.LongValue = data.GetBoxedLongValue(); // error } In each case, the integral types are consistent, so there should be some form of syntax that says "the object contains a simple type of X, return that as X (even though I don't know what X is)". Because the objects ultimately come from the same source, there really can't be a mismatch (short != long). I apologize for the contrived example, it seemed like the best way to demonstrate the syntax. Thanks.

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  • Explain ML type inference to a C++ programmer

    - by Tsubasa Gomamoto
    How does ML perform the type inference in the following function definition: let add a b = a + b Is it like C++ templates where no type-checking is performed until the point of template instantiation after which if the type supports the necessary operations, the function works or else a compilation error is thrown ? i.e. for example, the following function template template <typename NumType> NumType add(NumType a, NumType b) { return a + b; } will work for add<int>(23, 11); but won't work for add<ostream>(cout, fout); Is what I am guessing is correct or ML type inference works differently? PS: Sorry for my poor English; it's not my native language.

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  • functional dependencies vs type families

    - by mhwombat
    I'm developing a framework for running experiments with artificial life, and I'm trying to use type families instead of functional dependencies. Type families seems to be the preferred approach among Haskellers, but I've run into a situation where functional dependencies seem like a better fit. Am I missing a trick? Here's the design using type families. (This code compiles OK.) {-# LANGUAGE TypeFamilies, FlexibleContexts #-} import Control.Monad.State (StateT) class Agent a where agentId :: a -> String liveALittle :: Universe u => a -> StateT u IO a -- plus other functions class Universe u where type MyAgent u :: * withAgent :: (MyAgent u -> StateT u IO (MyAgent u)) -> String -> StateT u IO () -- plus other functions data SimpleUniverse = SimpleUniverse { mainDir :: FilePath -- plus other fields } defaultWithAgent :: (MyAgent u -> StateT u IO (MyAgent u)) -> String -> StateT u IO () defaultWithAgent = undefined -- stub -- plus default implementations for other functions -- -- In order to use my framework, the user will need to create a typeclass -- that implements the Agent class... -- data Bug = Bug String deriving (Show, Eq) instance Agent Bug where agentId (Bug s) = s liveALittle bug = return bug -- stub -- -- .. and they'll also need to make SimpleUniverse an instance of Universe -- for their agent type. -- instance Universe SimpleUniverse where type MyAgent SimpleUniverse = Bug withAgent = defaultWithAgent -- boilerplate -- plus similar boilerplate for other functions Is there a way to avoid forcing my users to write those last two lines of boilerplate? Compare with the version using fundeps, below, which seems to make things simpler for my users. (The use of UndecideableInstances may be a red flag.) (This code also compiles OK.) {-# LANGUAGE MultiParamTypeClasses, FunctionalDependencies, FlexibleInstances, UndecidableInstances #-} import Control.Monad.State (StateT) class Agent a where agentId :: a -> String liveALittle :: Universe u a => a -> StateT u IO a -- plus other functions class Universe u a | u -> a where withAgent :: Agent a => (a -> StateT u IO a) -> String -> StateT u IO () -- plus other functions data SimpleUniverse = SimpleUniverse { mainDir :: FilePath -- plus other fields } instance Universe SimpleUniverse a where withAgent = undefined -- stub -- plus implementations for other functions -- -- In order to use my framework, the user will need to create a typeclass -- that implements the Agent class... -- data Bug = Bug String deriving (Show, Eq) instance Agent Bug where agentId (Bug s) = s liveALittle bug = return bug -- stub -- -- And now my users only have to write stuff like... -- u :: SimpleUniverse u = SimpleUniverse "mydir"

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  • Cannot initialize non-const reference from convertible type

    - by Julien L.
    Hi, I cannot initialize a non-const reference to type T1 from a convertible type T2. However, I can with a const reference. long l; const long long &const_ref = l; // fine long long &ref = l; // error: invalid initialization of reference of // type 'long long int&' from expression of type // 'long int' Most problems I encountered were related to r-values that cannot be assigned to a non-const reference. This is not the case here -- can someone explain? Thanks.

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  • GHC.Generics and Type Families

    - by jberryman
    This is a question related to my module here, and is simplified a bit. It's also related to this previous question, in which I oversimplified my problem and didn't get the answer I was looking for. I hope this isn't too specific, and please change the title if you can think if a better one. Background My module uses a concurrent chan, split into a read side and write side. I use a special class with an associated type synonym to support polymorphic channel "joins": {-# LANGUAGE TypeFamilies #-} class Sources s where type Joined s newJoinedChan :: IO (s, Messages (Joined s)) -- NOT EXPORTED --output and input sides of channel: data Messages a -- NOT EXPORTED data Mailbox a instance Sources (Mailbox a) where type Joined (Mailbox a) = a newJoinedChan = undefined instance (Sources a, Sources b)=> Sources (a,b) where type Joined (a,b) = (Joined a, Joined b) newJoinedChan = undefined -- and so on for tuples of 3,4,5... The code above allows us to do this kind of thing: example = do (mb , msgsA) <- newJoinedChan ((mb1, mb2), msgsB) <- newJoinedChan --say that: msgsA, msgsB :: Messages (Int,Int) --and: mb :: Mailbox (Int,Int) -- mb1,mb2 :: Mailbox Int We have a recursive action called a Behavior that we can run on the messages we pull out of the "read" end of the channel: newtype Behavior a = Behavior (a -> IO (Behavior a)) runBehaviorOn :: Behavior a -> Messages a -> IO () -- NOT EXPORTED This would allow us to run a Behavior (Int,Int) on either of msgsA or msgsB, where in the second case both Ints in the tuple it receives actually came through separate Mailboxes. This is all tied together for the user in the exposed spawn function spawn :: (Sources s) => Behavior (Joined s) -> IO s ...which calls newJoinedChan and runBehaviorOn, and returns the input Sources. What I'd like to do I'd like users to be able to create a Behavior of arbitrary product type (not just tuples) , so for instance we could run a Behavior (Pair Int Int) on the example Messages above. I'd like to do this with GHC.Generics while still having a polymorphic Sources, but can't manage to make it work. spawn :: (Sources s, Generic (Joined s), Rep (Joined s) ~ ??) => Behavior (Joined s) -> IO s The parts of the above example that are actually exposed in the API are the fst of the newJoinedChan action, and Behaviors, so an acceptable solution can modify one or all of runBehaviorOn or the snd of newJoinedChan. I'll also be extending the API above to support sums (not implemented yet) like Behavior (Either a b) so I hoped GHC.Generics would work for me. Questions Is there a way I can extend the API above to support arbitrary Generic a=> Behavior a? If not using GHC's Generics, are there other ways I can get the API I want with minimal end-user pain (i.e. they just have to add a deriving clause to their type)?

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  • Indirect load of type fails in PowerShell

    - by Dan
    When invoking [System.Configuration.ConfigurationManager]::GetSection("MySection") from within a PowerShell prompt, it throws an exception because the assembly containing the type represented by "MySection" in the app config is unable to be loaded. However, I have previously loaded the assembly containing that type, and I am even able to instantiate the type directly using 'new-object'. How is the ConfigurationManager resolving types such that the assemblies already loaded into the PowerShell app domain are not visible to it?

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  • C#: Determine Type for (De-)Serialization

    - by dbemerlin
    Hi, i have a little problem implementing some serialization/deserialization logic. I have several classes that each take a different type of Request object, all implementing a common interface and inheriting from a default implementation: This is how i think it should be: Requests interface IRequest { public String Action {get;set;} } class DefaultRequest : IRequest { public String Action {get;set;} } class LoginRequest : DefaultRequest { public String User {get;set;} public String Pass {get;set;} } Handlers interface IHandler<T> { public Type GetRequestType(); public IResponse HandleRequest(IModel model, T request); } class DefaultHandler<T> : IHandler<T> // Used as fallback if the handler cannot be determined { public Type GetRequestType() { return /* ....... how to get the Type of T? ((new T()).GetType()) ? .......... */ } public IResponse HandleRequest(IModel model, T request) { /* ... */ } } class LoginHandler : DefaultHandler<LoginRequest> { public IResponse HandleRequest(IModel mode, LoginRequest request) { } } Calling class Controller { public ProcessRequest(String action, String serializedRequest) { IHandler handler = GetHandlerForAction(action); IRequest request = serializer.Deserialize<handler.GetRequestType()>(serializedRequest); handler(this.Model, request); } } Is what i think of even possible? My current Solution is that each handler gets the serialized String and is itself responsible for deserialization. This is not a good solution as it contains duplicate code, the beginning of each HandleRequest method looks the same (FooRequest request = Deserialize(serializedRequest); + try/catch and other Error Handling on failed deserialization). Embedding type information into the serialized Data is not possible and not intended. Thanks for any Hints.

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  • Obtain container type from (its) iterator type in C++ (STL)

    - by KRao
    It is easy given a container to get the associated iterators, example: std::vector<double>::iterator i; //An iterator to a std::vector<double> I was wondering if it is possible, given an iterator type, to deduce the type of the "corresponding container" (here I am assuming that for each container there is one and only one (non-const) iterator). More precisely, I would like a template metafunction that works with all STL containers (without having to specialize it manually for each single container) such that, for example: ContainerOf< std::vector<double>::iterator >::type evaluates to std::vector<double> Is it possible? If not, why? Thank you in advance for any help!

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  • Font for Wine that supports the entire character set of the Win32 Console?

    - by Brian Campbell
    I would like to be able to display in the Wine console all characters that the Win32 console can display. I've written a small test program to print out all 8-bit characters: #include <stdio.h> int main(int argc, char *argv[]) { int i, j; for (i = 0; i <= 0xF0; i+=0x10) { for (j = i; j <= i + 0x0F; ++j) printf("%2x:%c", j, (char)j); printf("\n"); } getchar(); return 0; } Under Wine, the best I can do so far is using Andale Mono: While this is what I see on Windows Server 2008: Is there anywhere I can legally download a font that will allow me to view all of those characters under Wine? edit I've found a set of DOS fonts that includes a CP437 font, which should cover the character set I'm interested in. However, even if I install this font, wineconsole doesn't seem to recognize it. Is there any way I can get wineconsole to use this font, or convert this font to a format that wineconsole can use? Or is there any way I can extract fonts from DOSEMU for use in Wine? Oh, and I should probably mention that I'm on Mac OS X 10.6.2, installing Wine via MacPorts, using the wine-devel package. more information I have tried installing some console fonts that should cover the full character set as Mac OS X fonts (such as the NewDOS font listed above, and a font I tried converting from the fonts supplied by DOSEMU). Wine does not seem to pick up on new fonts installed in Mac OS X. Is there a way to register new fonts I've installed with Wine? Would manually editing the system.reg file that seems to contain font mappings work, or is there something else I'd need to do? bump Bounty ends soon, I'm still looking for an answer for this. Does anyone use the Wine console for complex text user interfaces?

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  • Install lubuntu 12.04 on an old Dell c600 : Video issues

    - by maniat1k
    I am trying to install lubuntu on an old laptop. I use the 386 alternate instalation of it, because it has only 256mb ... All when ok so when I start up the lubuntu the screen splits between 1024x768 and 800x600... its very horrible to use =). Ok I do this: lspci and found an ATI Rage mobility M3. 01:00.0 VGA compatible controller: ATI Technologies Inc Rage Mobility M3 AGP 2x (rev 02) So I tryied the old xorg way to edit the missing resolution, but it does not work:... Section "Screen" Identifier "Default Screen" Device "ATI Technologies, Inc. Rage Mobility M3 (AGP)" Monitor "Generic Monitor" DefaultDepth 24 SubSection "Display" Depth 1 Modes "1024x768" EndSubSection SubSection "Display" Depth 4 Modes "1024x768" EndSubSection SubSection "Display" Depth 8 Modes "1024x768" EndSubSection SubSection "Display" Depth 15 Modes "1024x768" EndSubSection SubSection "Display" Depth 16 Modes "1024x768" EndSubSection SubSection "Display" Depth 24 Modes "1024x768" EndSubSection EndSection on an brand new xorg.conf... Do an init 6 to see if X take the changes, but nothing habbened: also tryed to do pkg-reconfigure -changedir /etc/X11 (where I created the new xorg.conf) and nothing.. removed the X conf from /tmp.. also do sudo apt-get update / upgrade... and no luck... UPDATE Updated to 12.04. This an edited xorg fr old dells like mine: # xorg.conf (X.Org X Window System server configuration file) # # This file was generated by dexconf, the Debian X Configuration tool, using # values from the debconf database. # # Edit this file with caution, and see the xorg.conf manual page. # (Type "man xorg.conf" at the shell prompt.) # # This file is automatically updated on xserver-xorg package upgrades *only* # if it has not been modified since the last upgrade of the xserver-xorg # package. # # If you have edited this file but would like it to be automatically updated # again, run the following command: # sudo dpkg-reconfigure -phigh xserver-xorg # xorg.conf for dell latitude c600 by A. Howlett and others Section "ServerLayout" Identifier "Default Server Layout" Screen 0 "Screen0" InputDevice "Keyboard0" "CoreKeyboard" InputDevice "Mouse0" "CorePointer" InputDevice "Generic Mouse" "AlwaysCore" EndSection Section "Files" RgbPath "/usr/X11R6/lib/X11/rgb" FontPath "/usr/share/fonts/local" FontPath "/usr/share/fonts/misc" FontPath "/usr/share/fonts/75dpi:unscaled" FontPath "/usr/share/fonts/100dpi:unscaled" FontPath "/usr/share/fonts/Type1" FontPath "/usr/share/fonts/CID" FontPath "/usr/share/fonts/Speedo" FontPath "/usr/share/fonts/cyrillic" FontPath "/usr/share/fonts/artwiz-aleczapka" FontPath "/usr/share/fonts/TTF" FontPath "/usr/share/fonts/util" FontPath "/usr/local/share/fonts" FontPath "/usr/share/fonts" FontPath "/usr/share/fonts" FontPath "/usr/share/fonts/aquafont" FontPath "/usr/share/fonts/artwiz" FontPath "/usr/share/fonts/artwiz-aleczapka-en" FontPath "/usr/share/fonts/corefonts" FontPath "/usr/share/fonts/freefont" EndSection Section "Module" Load "GLcore" Load "dbe" Load "dri" Load "extmod" Load "glx" Load "pex5" Load "record" Load "xie" Load "v4l" Load "freetype" EndSection Section "InputDevice" Identifier "Keyboard0" Driver "keyboard" Option "XkbModel" "pc104" Option "XkbLayout" "us" EndSection Section "InputDevice" Identifier "Mouse0" Driver "mouse" Option "CorePointer" Option "Device" "/dev/psaux" Option "Protocol" "PS/2" Option "Emulate3Buttons" "true" Option "ZAxisMapping" "4 5" EndSection Section "InputDevice" Identifier "Generic Mouse" Driver "mouse" Option "SendCoreEvents" "true" Option "Device" "/dev/input/mice" Option "Protocol" "ImPS/2" Option "Emulate3Buttons" "true" Option "ZAxisMapping" "4 5" EndSection Section "Monitor" Identifier "laptop LCD" VendorName "Dell" ModelName "Latitude C600" HorizSync 31.5-48.5 VertRefresh 40-70 EndSection Section "Device" Identifier "Video0" Driver "r128" VideoRam 8192 Option "EnablePageFlip" "true" Option "AGPFastWrite" "true" Option "AGPMode" "2" BusID "PCI:01:00:0" Screen 0 Option "Display" "FP" Option "MonitorLayout" "CRT, LFP" EndSection Section "Screen" Identifier "Screen0" Device "Video0" Monitor "laptop LCD" DefaultDepth 16 Subsection "Display" Depth 32 Modes "1280x1024" "1152x864" "1024x768" "800x600" "640x480" EndSubSection Subsection "Display" Depth 24 Modes "1280x1024" "1152x864" "1024x768" "800x600" "640x480" EndSubSection Subsection "Display" Depth 16 Modes "1280x1024" "1152x864" "1024x768" "800x600" "640x480" EndSubSection Subsection "Display" Depth 8 Modes "1280x1024" "1152x864" "1024x768" "800x600" "640x480" EndSubSection EndSection Section "DRI" Mode 0666 EndSection

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  • data validation on wpf passwordbox:type password, re-type password

    - by black sensei
    Hello Experts !! I've built a wpf windows application in with there is a registration form. Using IDataErrorInfo i could successfully bind the field to a class property and with the help of styles display meaningful information about the error to users.About the submit button i use the MultiDataTrigger with conditions (Based on a post here on stackoverflow).All went well. Now i need to do the same for the passwordbox and apparently it's not as straight forward.I found on wpftutorial an article and gave it a try but for some reason it wasn't working. i've tried another one from functionalfun. And in this Functionalfun case the properties(databind,databound) are not recognized as dependencyproperty even after i've changed their name as suggested somewhere in the comments plus i don't have an idea whether it will work for a windows application, since it's designed for web. to give you an idea here is some code on textboxes <Window.Resources> <data:General x:Key="recharge" /> <Style x:Key="validButton" TargetType="{x:Type Button}" BasedOn="{StaticResource {x:Type Button}}" > <Setter Property="IsEnabled" Value="False"/> <Style.Triggers> <MultiDataTrigger> <MultiDataTrigger.Conditions> <Condition Binding="{Binding ElementName=txtRecharge, Path=(Validation.HasError)}" Value="false" /> </MultiDataTrigger.Conditions> <Setter Property="IsEnabled" Value="True" /> </MultiDataTrigger> </Style.Triggers> </Style> <Style x:Key="txtboxerrors" TargetType="{x:Type TextBox}" BasedOn="{StaticResource {x:Type TextBox}}"> <Style.Triggers> <Trigger Property="Validation.HasError" Value="true"> <Setter Property="ToolTip" Value="{Binding RelativeSource={RelativeSource Self}, Path=(Validation.Errors)[0].ErrorContent}"/> <Setter Property="Validation.ErrorTemplate"> <Setter.Value> <ControlTemplate> <DockPanel LastChildFill="True"> <TextBlock DockPanel.Dock="Bottom" FontSize="8" FontWeight="ExtraBold" Foreground="red" Padding="5 0 0 0" Text="{Binding ElementName=showerror, Path=AdornedElement.(Validation.Errors)[0].ErrorContent}"></TextBlock> <Border BorderBrush="Red" BorderThickness="2"> <AdornedElementPlaceholder Name="showerror" /> </Border> </DockPanel> </ControlTemplate> </Setter.Value> </Setter> </Trigger> </Style.Triggers> </Style> </Window.Resources> <TextBox Margin="12,69,12,70" Name="txtRecharge" Style="{StaticResource txtboxerrors}"> <TextBox.Text> <Binding Path="Field" Source="{StaticResource recharge}" ValidatesOnDataErrors="True" UpdateSourceTrigger="PropertyChanged"> <Binding.ValidationRules> <ExceptionValidationRule /> </Binding.ValidationRules> </Binding> </TextBox.Text> </TextBox> <Button Height="23" Margin="98,0,0,12" Name="btnRecharge" VerticalAlignment="Bottom" Click="btnRecharge_Click" HorizontalAlignment="Left" Width="75" Style="{StaticResource validButton}">Recharge</Button> some C# : class General : IDataErrorInfo { private string _field; public string this[string columnName] { get { string result = null; if(columnName == "Field") { if(Util.NullOrEmtpyCheck(this._field)) { result = "Field cannot be Empty"; } } return result; } } public string Error { get { return null; } } public string Field { get { return _field; } set { _field = value; } } } So what are suggestion you guys have for me? I mean how would you go about this? how do you do this since the databinding first purpose here is not to load data onto the fields they are just (for now) for data validation. thanks for reading this.

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  • ActionScript Custom Class With Return Type?

    - by TheDarkIn1978
    i just know this is a dumb question, so excuse me in advance. i want to essentially classify a simple function in it's own .as file. the function compares integers. but i don't know how to call the class and receive a boolean return. here's my class package { public class CompareInts { public function CompareInts(small:int, big:int) { compare(small, big); } private function compare(small:int, big:int):Boolean { if (small < big) return true; else return false; } } } so now i'd like to write something like this: if (CompareInts(1, 5) == true). or output 'true' by writing trace(CompareInts(1, 5));

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  • Very different font sizes across browsers

    - by Yang
    Chrome/WebKit and Firefox have different rendering engines which render fonts differently, in particular with differing dimensions. This isn't too surprising, but what's surprising is the magnitude of some of the differences. I can always tweak individual elements on a page to be more similar, but that's tedious, to say the least. I've been searching for more systematic solutions, but many resources (e.g. SO answers) simply say "use a reset package." While I'm sure this fixes a bunch of other things like padding and spacing, it doesn't seem to make any difference for font dimensions. For instance, if I take the reset package from http://html5reset.org/, I can show pretty big differences (note the layout dimensions shown in the inspectors). [The images below are actually higher res than shown/resized in this answer.] <h1 style="font-size:64px; background-color: #eee;">Article Header</h1> With Helvetica, Chrome is has the shorter height instead. <h1 style="font-size:64px; background-color: #eee; font-family: Helvetica">Article Header</h1> Using a different font, Chrome again renders a much taller font, but additionally the letter spacing goes haywire (probably due to the boldification of the font): <style> @font-face { font-family: "MyriadProRegular"; src: url("fonts/myriadpro-regular-webfont.eot"); src: local("?"), url("fonts/myriadpro-regular-webfont.woff") format("woff"), url("fonts/myriadpro-regular-webfont.ttf") format("truetype"), url("fonts/myriadpro-regular-webfont.svg#webfonteknRmz0m") format("svg"); font-weight: normal; font-style: normal; } @font-face { font-family: "MyriadProLight"; src: url("fonts/myriadpro-light-webfont.eot"); src: local("?"), url("fonts/myriadpro-light-webfont.woff") format("woff"), url("fonts/myriadpro-light-webfont.ttf") format("truetype"), url("fonts/myriadpro-light-webfont.svg#webfont2SBUkD9p") format("svg"); font-weight: normal; font-style: normal; } @font-face { font-family: "MyriadProSemibold"; src: url("fonts/myriadpro-semibold-webfont.eot"); src: local("?"), url("fonts/myriadpro-semibold-webfont.woff") format("woff"), url("fonts/myriadpro-semibold-webfont.ttf") format("truetype"), url("fonts/myriadpro-semibold-webfont.svg#webfontM3ufnW4Z") format("svg"); font-weight: normal; font-style: normal; } </style> ... <h1 style="font-size:64px; background-color: #eee; font-family: Helvetica">Article Header</h1> I've tried a few resets/normalize packages to no avail. I just wanted to confirm here that this is indeed a fact of life (even omitting the more glaring offenders like IE and mobile) and I'm not missing some super-awesome solution to this mess.

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  • How to Customize Fonts and Colors for Gnome Panels in Ubuntu Linux

    - by The Geek
    Earlier this week we showed you how to make the Gnome Panels totally transparent, but you really need some customized fonts and colors to make the effect work better. Here’s how to do it. This article is the first part of a multi-part series on how to customize the Ubuntu desktop, written by How-To Geek reader and ubergeek, Omar Hafiz. Changing the Gnome Colors the Easy Way You’ll first need to install Gnome Color Chooser which is available in the default repositories (the package name is gnome-color-chooser). Then go to System > Preferences > Gnome Color Chooser to launch the program. When you see all these tabs you immediately know that Gnome Color Chooser does not only change the font color of the panel, but also the color of the fonts all over Ubuntu, desktop icons, and many other things as well. Now switch to the panel tab, here you can control every thing about your panels. You can change font, font color, background and background color of the panels and start menus. Tick the “Normal” option and choose the color you want for the panel font. If you want you can change the hover color of the buttons on the panel by too. A little below the color option is the font options, this includes the font, font size, and the X and Y positioning of the font. The first two options are pretty straight forward, they change the typeface and the size. The X-Padding and Y-Padding may confuse you but they are interesting, they may give a nice look for your panels by increasing the space between items on your panel like this: X-Padding:   Y-Padding:   The bottom half of the window controls the look of your start menus which is the Applications, Places, and Systems menus. You can customize them just the way you did with the panel.   Alright, this was the easy way to change the font of your panels. Changing the Gnome Theme Colors the Command-Line Way The other hard (not so hard really) way will be changing the configuration files that tell your panel how it should look like. In your Home Folder, press Ctrl+H to show the hidden files, now find the file “.gtkrc-2.0”, open it and insert this line in it. If there are any other lines in the file leave them intact. include “/home/<username>/.gnome2/panel-fontrc” Don’t forget to replace the <user_name> with you user account name. When done close and save the file. Now navigate the folder “.gnome2” from your Home Folder and create a new file and name it “panel-fontrc”. Open the file you just created with a text editor and paste the following in it: style “my_color”{fg[NORMAL] = “#FF0000”}widget “*PanelWidget*” style “my_color”widget “*PanelApplet*” style “my_color” This text will make the font red. If you want other colors you’ll need to replace the Hex value/HTML Notation (in this case #FF0000) with the value of the color you want. To get the hex value you can use GIMP, Gcolor2 witch is available in the default repositories or you can right-click on your panel > Properties > Background tab then click to choose the color you want and copy the Hex value. Don’t change any other thing in the text. When done, save and close. Now press Alt+F2 and enter “killall gnome-panel” to force it to restart or you can log out and login again. Most of you will prefer the first way of changing the font and color for it’s ease of applying and because it gives you much more options but, some may not have the ability/will to download and install a new program on their machine or have reasons of their own for not to using it, that’s why we provided the two way. Latest Features How-To Geek ETC How to Enable User-Specific Wireless Networks in Windows 7 How to Use Google Chrome as Your Default PDF Reader (the Easy Way) How To Remove People and Objects From Photographs In Photoshop Ask How-To Geek: How Can I Monitor My Bandwidth Usage? Internet Explorer 9 RC Now Available: Here’s the Most Interesting New Stuff Here’s a Super Simple Trick to Defeating Fake Anti-Virus Malware The Splendiferous Array of Culinary Tools [Infographic] Add a Real-Time Earth Wallpaper App to Ubuntu with xplanetFX The Citroen GT – An Awesome Video Game Car Brought to Life [Video] Final Man vs. Machine Round of Jeopardy Unfolds; Watson Dominates Give Chromium-Based Browser Desktop Notifications a Native System Look in Ubuntu Chrome Time Track Is a Simple Task Time Tracker

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  • Dynamically loading type in Silverlight with Type.GetType()

    - by ondesertverge
    Trying to specify the assembly name like this: Type.GetType(string.Format("{0}.{1}, {0}", widget.Assembly, widget.Class)); Throws this: The requested assembly version conflicts with what is already bound in the app domain or specified in the manifest Trying it without the the assembly: Type.GetType(string.Format("{0}.{1}", widget.Assembly, widget.Class)); Returns null. I am looking for a way to instantiate a class using it's fully qualified name in Silverlight 4.0. Thanks.

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