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  • parse error in php code

    - by user225269
    I just started php and I want to know how to make this parse error work. This is the error: Parse error: parse error in E:\wamp\www\PHP\create.php on line 22 And here is my code, by the way I'm making a database manipulating system. And I use wampserver and dreamweaver. <?php include 'E:\wamp\www\PHP\connection.php'; $IDNUMBER = $_POST['ID']; $LNAME = $_POST['Lname']; $FNAME = $_POST['Fname']; $MNAME = $_POST['Mname']; $GRADEYR = $_POST['GradeYr']; $ADDRESS = $_POST['Address']; if(!$_POST['submit']) { echo "please fill out the form"; header('Location: E:\wamp\www\PHP\main.php'); } else { mysql_query = "INSERT INTO students (`IDNUMBER`,`LNAME` ,`FNAME` ,`MNAME` ,`GRADEYR` ,`ADDRESS`) VALUES (NULL, '$IDNUMBER', '$LNAME', '$FNAME', '$MNAME', '$GRADEYR', '$ADDRESS')") or die(mysql_error()); echo "User has been added!"; header('E:\wamp\www\PHP\main.php'); } ?> Please help, I'm just a beginner in php.

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  • Garbled text when constructing emails with vmime

    - by Klaus Fiedler
    Hey, my Qt C++ program has a part where it needs to send the first 128 characters or so of the output of a bash command to an email address. The output from the tty is captured in a text box in my gui called textEdit_displayOutput and put into my message I built using the Message Builder ( the object m_vmMessage ) Here is the relevant code snippet: m_vmMessage.getTextPart()->setCharset( vmime::charsets::US_ASCII ); m_vmMessage.getTextPart()->setText( vmime::create < vmime::stringContentHandler > ( ui->textEdit_displayOutput->toPlainText().toStdString() ) ); vmime::ref < vmime::message > msg = m_vmMessage.construct(); vmime::utility::outputStreamAdapter out( std::cout ); msg->generate( out ); Giving bash 'ls /' and a newline makes vmime give terminal output like this: ls /=0Abin etc=09 initrd.img.old mnt=09 sbin=09 tmp=09 vmlinuz.o= ld=0Aboot farts=09 lib=09=09 opt=09 selinux usr=0Acdrom home=09 = lost+found=09 proc srv=09 var=0Adev initrd.img media=09 root = Whereas it should look more like this: ls / bin etc initrd.img.old mnt sbin tmp vmlinuz.old boot farts lib opt selinux usr cdrom home lost+found proc srv var dev initrd.img media root sys vmlinuz 18:22> How do I encode the email properly? Does vmime just display it like that on purpose and the actual content of the email is ok?

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  • Magic function `bash ` not found

    - by inspectorG4dget
    I have a bunch of simulations that I want to run on a high-performance cluster, on which I should make reservations to get computing time. Since the reservations are bounded by time, I am developing an automation script that I can scp into the cluster and run. This script will then download the relevant simulation files, run them, and upload the results. Part of this automation script is in bash (cp, scp, etc) and the rest is in python. In order to develop this automation, I am using an IPython notebook. So far, I've coded all the python automation stuff in my IPython notebook and am trying to write the bash part of it now. However, it seems that the magic %%bash doesn't work in my IPython notebook. I get the following error when I have this code in my cell: Cell %%bash echo hi Error File "<ipython-input-22-62ec98e35224>", line 3 echo hi ^ SyntaxError: invalid syntax On a whim, I tried this: Cell %%bash print "hi" Error hi ERROR: Magic function `bash` not found. So I tried this with %%system, %%! and %%shell. But none of those work; they all give me the same error. Why is this happening? How can I fix this? Metadata: IPython 0.13.dev Python 2.7.1 Mac OS X Lion

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  • fullcalendar events from REST-ful php server.

    - by biagidp
    I've written a very simple RESTful php server (my first experiment with REST, so feel free to make suggestions) to respond to the fullcalendar events callback. It produces exactly the same string output as the json-events.php file in the fullcalendar json example, but for some reason fullcalendar will not accept my server's output. I've tried messing with the headers because they're different from the ones produced by json-events.php, but I'm not really sure what's awry there, if anything. The code for the server is below: <?php class Listener{ function __construct() { $this->getResource(); $this->buildResponse(); } function getResource(){ $parts = explode('/', $_SERVER["REQUEST_URI"]); $script_name = end(explode('/', $_SERVER["SCRIPT_NAME"])); $this->resource = $parts[array_search($script_name, $parts) + 1]; $this->resource_id = $parts[array_search($script_name, $parts) + 2]; } function buildResponse(){ $method = strtolower($_SERVER["REQUEST_METHOD"]); $this->response_string = $method . ucwords($this->resource); } function getResponse(){ return $this->response_string; } } $listener = new Listener(); $thing = $listener->getResponse(); #$thing(); function getEvents(){ $year = date('Y'); $month = date('m'); echo json_encode(array( array( 'id' => 111, 'title' => "Event1", 'start' => "$year-$month-10", 'url' => "http://yahoo.com/" ), array( 'id' => 222, 'title' => "Event2", 'start' => "$year-$month-20", 'end' => "$year-$month-22", 'url' => "http://yahoo.com/" ) )); } ?> Any input, help or suggestions would be greatly appreciated! Thanks, David

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  • How to solve this simple PHP forloop issue?

    - by Londonbroil Wellington
    Here is the content of my flat file database: Jacob | Little | 22 | Male | Web Developer * Adam | Johnson | 45 | Male | President * Here is my php code: <?php $fopen = fopen('db.txt', 'r'); if (!$fopen) { echo 'File not found'; } $fread = fread($fopen, filesize('db.txt')); $records = explode('|', $fread); ?> <table border="1" width="100%"> <tr> <thead> <th>First Name</th> <th>Last Name</th> <th>Age</th> <th>Sex</th> <th>Occupation</th> </thead> </tr> <?php $rows = explode('*', $fread); for($i = 0; $i < count($rows) - 1; $i++) { echo '<tr>'; echo '<td>'.$records[0].'</td>'; echo '<td>'.$records[1].'</td>'; echo '<td>'.$records[2].'</td>'; echo '<td>'.$records[3].'</td>'; echo '<td>'.$records[4].'</td>'; echo '</tr>'; } fclose($fopen); ?> </table> Problem is I am getting the output of the first record repeated twice instead of 2 records one for Jacob and one for Adam. How to fix this?

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  • Algorithm for finding similar users through a join table

    - by Gdeglin
    I have an application where users can select a variety of interests from around 300 possible interests. Each selected interest is stored in a join table containing the columns user_id and interest_id. Typical users select around 50 interests out of the 300. I would like to build a system where users can find the top 20 users that have the most interests in common with them. Right now I am able to accomplish this using the following query: SELECT i2.user_id, count(i2.interest_id) AS count FROM interests_users as i1, interests_users as i2 WHERE i1.interest_id = i2.interest_id AND i1.user_id = 35 GROUP BY i2.user_id ORDER BY count DESC LIMIT 20; However, this query takes approximately 500 milliseconds to execute with 10,000 users and 500,000 rows in the join table. All indexes and database configuration settings have been tuned to the best of my ability. I have also tried avoiding the use of joins altogether using the following query: select user_id,count(interest_id) count from interests_users where interest_id in (13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60,61,62,63,64,65,66,68,69,70,71,72,73,74,75,76,77,78,79,80,81,82,83,84,85,86,87,88,89,90,91,92,93,94,95,96,97,98,508) group by user_id order by count desc limit 20; But this one is even slower (~800 milliseconds). How could I best lower the time that I can gather this kind of data to below 100 milliseconds? I have considered putting this data into a graph database like Neo4j, but I am not sure if that is the easiest solution or if it would even be faster than what I am currently doing.

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  • How can you connect to a password protected MS Access Database from a Spring JdbcTemplate?

    - by Tim Visher
    I need to connect to a password protected MS Access 2003 DB using the JDBC-ODBC bridge. I can't find out how to specify the password in the connect string, or even if that is the correct method of connecting. It would probably be relevant to mention that this is a Spring App which is accessing the database through a JdbcTemplate configured as a datasource bean in our application context file. Some relevant snippets: from application-context.xml <bean id="jdbcTemplate" class="org.springframework.jdbc.core.JdbcTemplate"> <property name="dataSource" ref="legacyDataSource" /> </bean> <bean id="jobsheetLocation" class="java.lang.String"> <constructor-arg value="${jobsheet.location}"/> </bean> <bean id="legacyDataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource"> <property name="driverClassName" value="${jdbc.legacy.driverClassName}" /> <property name="url" value="${jdbc.legacy.url}"/> <property name="password" value="-------------" /> </bean> from our build properties jdbc.legacy.driverClassName=sun.jdbc.odbc.JdbcOdbcDriver jdbc.legacy.url=jdbc:odbc:Driver\={Microsoft Access Driver (*.mdb)};Dbq\=@LegacyDbPath@;DriverID\=22;READONLY\=true Any thoughts?

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  • MySQL 1064 error, works in command line and phpMyAdmin; not in app

    - by hundleyj
    Here is my query: select * from (select *, 3956 * 2 * ASIN(SQRT(POWER(SIN(RADIANS(45.5200077 - lat)/ 2), 2) + COS(RADIANS(45.5200077)) * COS(RADIANS(lat)) * POWER(SIN(RADIANS(-122.6942014 - lng)/2),2))) AS distance from stops order by distance, route asc) as p group by route, dir order by distance asc limit 10 This works fine at the command line and in PHPMyAdmin. I'm using Dbslayer to connect to MySQL via my JavaScript backend, and the request is returning a 1064 error. Here is the encoded DBSlayer request string: http://localhost:9090/db?{%22SQL%22:%22select%20*%20from%20%28select%20*,%203956%20*%202%20*%20ASIN%28SQRT%28POWER%28SIN%28RADIANS%2845.5200077%20-%20lat%29/%202%29,%202%29%20+%20COS%28RADIANS%2845.5200077%29%29%20*%20COS%28RADIANS%28lat%29%29%20*%20POWER%28SIN%28RADIANS%28-122.6942014%20-%20lng%29/2%29,2%29%29%29%20AS%20distance%20from%20%60stops%60%20order%20by%20%60distance%60,%20%60route%60%20asc%29%20as%20p%20group%20by%20%60route%60,%20%60dir%60%20order%20by%20%60distance%60%20asc%20limit%2010%22} And the response: {"MYSQL_ERRNO" : 1064 , "MYSQL_ERROR" : "You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '(RADIANS(45.5200077)) * COS(RADIANS(lat)) * POWER(SIN(RADIANS(-122.6942014 - lng' at line 1" , "SERVER" : "trimet"} Thanks!

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  • SCJP Book, IO section: Is this a typo or is there a reason it would look like this?

    - by iamchuckb
    My question is about line 4, where the new PrintWriter is created with the constructor taking the FileWriter fw as a parameter. I don't understand the use of chaining the BufferedWriter bw to FileWriter if it isn't used later on in the actual writing. Can Java apply chaining in a way that bw still somehow affects the rest of the program? 16. try { 17. FileWriter fw = new FileWriter(test); 18. BufferedWriter bw = new BufferedWriter(fw, 1024); 19. PrintWriter out = new PrintWriter(fw); 20. out.println("<html><body><h1>"); 21. out.println(args[0]); 22. out.println("</h1></body></html>"); 23. out.close(); 24. bw.close(); 25. fw.close(); 26. }catch(IOException e) { 27. e.printStackTrace(); 28. } I think it is probably a typo and they meant to use bw as the parameter for PrintWriter out but like the title says, I'm new to this. Thanks to all in advance.

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  • Return value from Object match

    - by Hito_kun
    I'm, by no means, JS fluent, so forgive me if im asking for some really basic stuff, but I've not being able to find a proper answer to my question. Im writting my first Node.js (plus Extra Framework and Socket.io) app and Im having some fun setting up the server side of a FB-like messenger (surprise!!!). So, let's say I have this data structure to store online users(This is a JSON Array, but I'm not sure it is the best way to do it or should I go with Javascript Objects): [ { "site": 45, "users": [ { "idUser": 5, "idSocket": "qwe87r7w8qwe", "name": "Carlos Ray Norris" }, { "idUser": 6, "idSocket": "v8d9d0fgfs7d", "name": "John Connor" } ] }, { "site": 48, "users": [ { "idUser": 22, "idSocket": "qwe87r7w8qwe", "name": "David Bowie" }, { "idUser": 23, "idSocket": "v8d9d0fgfs7d", "name": "Barack H. Obama" } ] } ] What I want to do is to search in the array for x value given y. In this case, retrieving the idSocket knowing the idUser WITHOUT having to run through the array values. So I have basically 2 questions: first, what would be the proper way to store users online? and secondly, how to find values matching with the values I already know (find the idSocket that has a given idUser). I would like a pure JS approach(or using some of the tools given by Node, Socket.io or Express), but if that's not possible then I can look for some JQuery.

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  • postgresql help with php loop....

    - by KnockKnockWhosThere
    I keep getting an "Notice: Undefined index: did" error with this query, and I'm not understanding why... I'm much more used to mysql, so, maybe the syntax is wrong? This is the php query code: function get_demos() { global $session; $demo = array(); $result = pg_query("SELECT DISTINCT(did,vid,iid,value) FROM dv"); if(pg_num_rows($result) > 0) { while($r = pg_fetch_array($result)) { switch($r['did']) { case 1: $demo['a'][$r['vid']] = $r['value']; break; case 2: $demo['b'][$r['vid']] = $r['value']; break; case 3: $demo['c'][$r['vid']] = $r['value']; break; } } } else { $session->session_setMessage(2); } return $demo; } When I run that query at the pg prompt, I get results: "(1,1,1,"A")" "(1,2,2,"B")" "(1,3,3,"C")" "(1,4,4,"D")" "(1,5,5,"E")" "(1,6,6,"F")" "(1,7,7,"G")" "(1,8,8,"H")" "(1,9,9,"I")" "(1,10,A,"J")" "(1,11,B,"K")" "(1,12,C,"L")" "(1,13,D,"M")" "(2,14,1,"A")" "(2,15,2,"B")" "(2,16,0,"C")" "(3,17,1,"A")" "(3,18,2,"B")" "(3,19,3,"C")" "(3,20,4,"D")" "(3,21,5,"E")" "(3,22,6,"F")" "(3,23,7,"G")"

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  • Using JRE 1.5, still maven says annotation not supported in -source 1.3

    - by Abhijeet
    Hi, I am using JRE 1.5. Still when I try to compile my code it fails by saying to use JRE 1.5 instead of 1.3 C:\temp\SpringExamplemvn -e clean install + Error stacktraces are turned on. [INFO] Scanning for projects... [INFO] ------------------------------------------------------------------------ [INFO] Building SpringExample [INFO] task-segment: [clean, install] [INFO] ------------------------------------------------------------------------ [INFO] [clean:clean {execution: default-clean}] [INFO] Deleting directory C:\temp\SpringExample\target [INFO] [resources:resources {execution: default-resources}] [WARNING] Using platform encoding (Cp1252 actually) to copy filtered resources, i.e. build is platform dependent! [INFO] Copying 6 resources [INFO] [compiler:compile {execution: default-compile}] [INFO] Compiling 6 source files to C:\temp\SpringExample\target\classes [INFO] ------------------------------------------------------------------------ [ERROR] BUILD FAILURE [INFO] ------------------------------------------------------------------------ [INFO] Compilation failure C:\temp\SpringExample\src\main\java\com\mkyong\stock\model\Stock.java:[45,9] annotations are not supported in -source 1.3 (try -source 1.5 to enable annotations) @Override [INFO] ------------------------------------------------------------------------ [INFO] Trace org.apache.maven.BuildFailureException: Compilation failure C:\temp\SpringExample\src\main\java\com\mkyong\stock\model\Stock.java:[45,9] annotations are not supported in -source 1.3 (try -source 1.5 to enable annotations) @Override at org.apache.maven.lifecycle.DefaultLifecycleExecutor.executeGoals(DefaultLifecycleExecutor.java:715) at org.apache.maven.lifecycle.DefaultLifecycleExecutor.executeGoalWithLifecycle(DefaultLifecycleExecutor.java:556) at org.apache.maven.lifecycle.DefaultLifecycleExecutor.executeGoal(DefaultLifecycleExecutor.java:535) at org.apache.maven.lifecycle.DefaultLifecycleExecutor.executeGoalAndHandleFailures(DefaultLifecycleExecutor.java:387) at org.apache.maven.lifecycle.DefaultLifecycleExecutor.executeTaskSegments(DefaultLifecycleExecutor.java:348) at org.apache.maven.lifecycle.DefaultLifecycleExecutor.execute(DefaultLifecycleExecutor.java:180) at org.apache.maven.DefaultMaven.doExecute(DefaultMaven.java:328) at org.apache.maven.DefaultMaven.execute(DefaultMaven.java:138) at org.apache.maven.cli.MavenCli.main(MavenCli.java:362) at org.apache.maven.cli.compat.CompatibleMain.main(CompatibleMain.java:60) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) at java.lang.reflect.Method.invoke(Method.java:585) at org.codehaus.classworlds.Launcher.launchEnhanced(Launcher.java:315) at org.codehaus.classworlds.Launcher.launch(Launcher.java:255) at org.codehaus.classworlds.Launcher.mainWithExitCode(Launcher.java:430) at org.codehaus.classworlds.Launcher.main(Launcher.java:375) Caused by: org.apache.maven.plugin.CompilationFailureException: Compilation failure C:\temp\SpringExample\src\main\java\com\mkyong\stock\model\Stock.java:[45,9] annotations are not supported in -source 1.3 (try -source 1.5 to enable annotations) @Override at org.apache.maven.plugin.AbstractCompilerMojo.execute(AbstractCompilerMojo.java:516) at org.apache.maven.plugin.CompilerMojo.execute(CompilerMojo.java:114) at org.apache.maven.plugin.DefaultPluginManager.executeMojo(DefaultPluginManager.java:490) at org.apache.maven.lifecycle.DefaultLifecycleExecutor.executeGoals(DefaultLifecycleExecutor.java:694) ... 17 more [INFO] ------------------------------------------------------------------------ [INFO] Total time: 2 seconds [INFO] Finished at: Wed Dec 22 10:04:53 IST 2010 [INFO] Final Memory: 9M/16M [INFO] ------------------------------------------------------------------------ C:\temp\SpringExamplejavac -version javac 1.5.0_08 javac: no source files

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  • Parsing a JSON feed from YQL using jQuery

    - by Keith
    I am using YQL's query.multi to grab multiple feeds so I can parse a single JSON feed with jQuery and reduce the number of connections I'm making. In order to parse a single feed, I need to be able to check the type of result (photo, item, entry, etc) so I can pull out items in specific ways. Because of the way the items are nested within the JSON feed, I'm not sure the best way to loop through the results and check the type and then loop through the items to display them. Here is a YQL (http://developer.yahoo.com/yql/console/) query.multi example and you can see three different result types (entry, photo, and item) and then the items nested within them: select * from query.multi where queries= "select * from twitter.user.timeline where id='twitter'; select * from flickr.photos.search where has_geo='true' and text='san francisco'; select * from delicious.feeds.popular" or here is the JSON feed itself: http://query.yahooapis.com/v1/public/yql?q=select%20*%20from%20query.multi%20where%20queries%3D%22select%20*%20from%20flickr.photos.search%20where%20user_id%3D'23433895%40N00'%3Bselect%20*%20from%20delicious.feeds%20where%20username%3D'keith.muth'%3Bselect%20*%20from%20twitter.user.timeline%20where%20id%3D'keithmuth'%22&format=json&env=store%3A%2F%2Fdatatables.org%2Falltableswithkeys&callback=

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  • Newb Question: scanf() in C

    - by riemannliness
    So I started learning C today, and as an exercise i was told to write a program that asks the user for numbers until they type a 0, then adds the even ones and the odd ones together. Here is is (don't laugh at my bad style): #include <stdio.h>; int main() { int esum = 0, osum = 0; int n, mod; puts("Please enter some numbers, 0 to terminate:"); scanf("%d", &n); while (n != 0) { mod = n % 2; switch(mod) { case 0: esum += n; break; case 1: osum += n; } scanf("%d", &n); } printf("The sum of evens:%d,\t The sum of odds:%d", esum, osum); return 0; } My question concerns the mechanics of the scanf() function. It seems that when you enter several numbers at once separated by spaces (eg. 1 22 34 2 8), the scanf() function somehow remembers each distinct numbers in the line, and steps through the while loop for each one respectively. Why/how does this happen? Example interaction within command prompt: - Please enter some numbers, 0 to terminate: 42 8 77 23 11 (enter) 0 (enter) - The sum of evens:50, The sum of odds:111 I'm running the program through the command prompt, it's compiled for win32 platforms with visual studio.

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  • How can I define a verb in J that applies a different verb alternately to each atom in a list?

    - by Gregory Higley
    Imagine I've defined the following name in J: m =: >: i. 2 4 5 This looks like the following: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 I want to create a monadic verb of rank 1 that applies to each list in this list of lists. It will double (+:) or add 1 (>:) to each alternate item in the list. If we were to apply this verb to the first row, we'd get 2 3 6 5 10. It's fairly easy to get a list of booleans which alternate with each item, e.g., 0 1 $~{:$ m gives us 0 1 0 1 0. I thought, aha! I'll use something like +:`>: @. followed by some expression, but I could never quite get it to work. Any suggestions? UPDATE The following appears to work, but perhaps it can be refactored into something more elegant by a J pro. poop =: monad define (($ y) $ 0 1 $~{:$ y) ((]+:)`(]:) @. [)"0 y )

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  • How to make placeholder varablies in jquery validate 1.7?

    - by chobo2
    Hi I am using jquery 1.4.2 and jquery validate 1.7(http://bassistance.de/jquery-plugins/jquery-plugin-validation/) Say I have this example that I just grabbed off some random site(http://www.webreference.com/programming/javascript/jquery/form_validation/) 8 <script type="text/javascript"> 9 $(document).ready(function() { 10 $("#form1").validate({ 11 rules: { 12 name: "required",// simple rule, converted to {required:true} 13 email: {// compound rule 14 required: true, 15 email: true 16 }, 17 url: { 18 url: true 19 }, 20 comment: { 21 required: true 22 } 23 }, 24 messages: { 25 comment: "Please enter a comment." 26 } 27 }); 28 }); 29 </script> now is it possible to do something like this 10 $("#form1").validate({ var NameHolder = "name" 11 rules: { 12 NameHolder: "required",// simple rule, converted to {required:true} 13 email: {// compound rule 14 required: true, 15 email: true So basically I want to make sort of a global variable to hold theses rule names( what correspond to the names on that html control). My concern is the names of html controls can change and it kinda sucks that I will have to go around and change it in many places of my code to make it work again. So basically I am wondering is there away to make a global variable to store this name. So if I need to change the name I only have to change it in one spot in my javascript file sort of the way stopping magic numbers ?

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  • Timer takes 10 ms more then interval

    - by Praveen
    Hi All, I am using a timer with interval 50 miliseconds. But in the timer's tick event when I print the time it's always 62 or 65 ms. I don't understand why it's taking 10 ms more. Please can some one have look into this. Here is the code I am using. static int _counter; System.Timers.Timer _timer = new System.Timers.Timer(1000); public Form1() { InitializeComponent(); _timer.Elapsed += new ElapsedEventHandler(_timer_Elapsed); _timer.Start(); } void _timer_Elapsed(object sender, ElapsedEventArgs e) { Console.WriteLine(DateTime.Now.ToString("{hh:mm:ss.fff}")); _counter++; if (_counter == 20) _timer.Stop(); } And this the output: {01:59:08.381} {01:59:09.393} {01:59:10.407} {01:59:11.421} {01:59:12.435} {01:59:13.449} {01:59:14.463} {01:59:15.477} {01:59:16.491} {01:59:17.505} {01:59:18.519} {01:59:19.533} {01:59:20.547} {01:59:21.561} {01:59:22.575} {01:59:23.589} {01:59:24.603} {01:59:25.615} {01:59:26.629} {01:59:27.643}

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  • Error when passing quotes to webservice by AJAX

    - by Radu
    I'm passing data using .ajax and here are my data and contentType attributes: data: '{ "UserInput" : "' + $('#txtInput').val() + '","Options" : { "Foo1":' + bar1 + ', "Foo2":' + Bar2 + ', "Flags":"' + flags + '", "Immunity":' + immunity + '}}', contentType: 'application/json; charset=utf-8', Server side my code looks like this: <WebMethod()> _ Public Shared Function ParseData(ByVal UserInput As String, ByVal Options As Options) As String The userinput is obvious but the Options structure is like the following: Public Structure Options Dim Foo1 As Boolean Dim Foo2 As Boolean Dim Flags As String Dim Immunity As Integer End Structure Everything works fine when $('#txtInput') contains no double-quotes but if they are present I get an error (for an input of asd"): {"Message":"Invalid object passed in, \u0027:\u0027 or \u0027}\u0027 expected. (22): { \"UserInput\" : \"asd\"\",\"Options\" : { \"Foo1\":false, \"Foo2\":false, \"Flags\":\"\", \"Immunity\":0}}","StackTrace":" at System.Web.Script.Serialization.JavaScriptObjectDeserializer.DeserializeDictionary(Int32 depth)\r\n at System.Web.Script.Serialization.JavaScriptObjectDeserializer.DeserializeInternal(Int32 depth)\r\n at System.Web.Script.Serialization.JavaScriptObjectDeserializer.BasicDeserialize(String input, Int32 depthLimit, JavaScriptSerializer serializer)\r\n at System.Web.Script.Serialization.JavaScriptSerializer.Deserialize[T](String input)\r\n at System.Web.Script.Services.RestHandler.ExecuteWebServiceCall(HttpContext context, WebServiceMethodData methodData)","ExceptionType":"System.ArgumentException"} Any idea how I can avoid this error? Also, when I pass the same input with quotes directly it works fine.

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  • charsets in MySQL replication

    - by niklassaers
    Hi guys, What can I do to ensure that replication will use latin1 instead of utf-8? I'm migrating between an MySQL 5.1.22 server (master) on a Linux system and a MySQL 5.1.42 server (slave) on a FreeBSD system. My replication works well, but when non-ascii characters are in my varchars, they turn "weird". The Linux/MySQL-5.1.22 shows the following character set variables: character_set_client=latin1 character_set_connection=latin1 character_set_database=latin1 character_set_filesystem=binary character_set_results=latin1 character_set_server=latin1 character_set_system=utf8 character_sets_dir=/usr/share/mysql/charsets/ collation_connection=latin1_swedish_ci collation_database=latin1_swedish_ci collation_server=latin1_swedish_ci While the FreeBSD shows character_set_client=utf8 character_set_connection=utf8 character_set_database=utf8 character_set_filesystem=binary character_set_results=utf8 character_set_server=utf8 character_set_system=utf8 character_sets_dir=/usr/local/share/mysql/charsets/ collation_connection=utf8_general_ci collation_database=utf8_general_ci collation_server=utf8_general_ci Setting any of these variables from the MySQL CLI has no effect, and setting them in my.cnf or at the command line makes the server not start. Of course, both servers have the tables in question created the same way, in this case with DEFAULT CHARSET=latin1. Let me give you an example: CREATE TABLE `test` ( `test` varchar(5) DEFAULT NULL ) ENGINE=MyISAM DEFAULT CHARSET=latin1 When I on the master do, in a Latin1 terminal, "INSERT INTO test VALUES ('æøå')", this becomes on the slave, when I select it from a Latin1 based terminal +--------+ | test | +--------+ | æøå | +--------+ On a UTF-8 based terminal on the replication slave, test contains: +--------+ | test | +--------+ | æøå | +--------+ So my conclusion is that it is converted to utf8, even though the table definition is latin1. Is this a correct conclusion? Of course, on the master, in a latin1 terminal, it still says: +------+ | test | +------+ | æøå | +------+ Since both system character sets are utf-8, if I set both terminals to utf-8 and do again "INSERT INTO test VALUES ('æøå')" on the master with a utf-8 terminal, on the slave with utf-8 I get: +------------+ | test | +------------+ | æøà | +------------+ If my conclusion is correct, all my replicated data is converted to utf8 (if it is utf8, it is treated as latin1 and converted to utf8), while all the old data in the table is, as the CREATE TABLE suggests, latin1. I'd love to convert it all to utf-8 if it weren't for the fact that legacy applications rely on it being latin1, so I need to keep it in latin1 while they still exist. What can I do to ensure that the replication reads latin1, treats it as latin1 and writes it on the slave as latin1? Cheers Nik

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  • My iPhone app ran fine in simulator but crashed on device (iPod touch 3.1.2) test, I got the followi

    - by Mickey Shine
    I was running myapp on an iPod touch and I noticed it missed some libraries. Is that the reason? [Session started at 2010-03-19 15:57:04 +0800.] GNU gdb 6.3.50-20050815 (Apple version gdb-1128) (Fri Dec 18 10:08:53 UTC 2009) Copyright 2004 Free Software Foundation, Inc. GDB is free software, covered by the GNU General Public License, and you are welcome to change it and/or distribute copies of it under certain conditions. Type "show copying" to see the conditions. There is absolutely no warranty for GDB. Type "show warranty" for details. This GDB was configured as "--host=i386-apple-darwin --target=arm-apple-darwin".tty /dev/ttys007 Loading program into debugger… Program loaded. target remote-mobile /tmp/.XcodeGDBRemote-237-78 Switching to remote-macosx protocol mem 0x1000 0x3fffffff cache mem 0x40000000 0xffffffff none mem 0x00000000 0x0fff none run Running… [Switching to thread 11779] [Switching to thread 11779] sharedlibrary apply-load-rules all (gdb) continue warning: Unable to read symbols for "/Library/MobileSubstrate/MobileSubstrate.dylib" (file not found). 2010-03-19 15:57:18.892 myapp[2338:207] MS:Notice: Installing: com.yourcompany.myapp [myapp] (478.52) 2010-03-19 15:57:19.145 myapp[2338:207] MS:Notice: Loading: /Library/MobileSubstrate/DynamicLibraries/Backgrounder.dylib warning: Unable to read symbols for "/Library/MobileSubstrate/DynamicLibraries/Backgrounder.dylib" (file not found). warning: Unable to read symbols for "/Developer/Platforms/iPhoneOS.platform/Developer/SDKs/iPhoneOS3.1.2.sdk/usr/lib/libsubstrate.dylib" (file not found). MS:Warning: message not found [myappAppDelegate applicationWillResignActive:] MS:Warning: message not found [myappAppDelegate applicationDidBecomeActive:] 2010-03-19 15:57:19.550 myapp[2338:207] in FirstViewController 2010-03-19 15:57:20.344 myapp[2338:207] in load table view 2010-03-19 15:57:20.478 myapp[2338:207] in loading splash view 2010-03-19 15:57:22.793 myapp[2338:207] in set interface Program received signal: “0”. warning: check_safe_call: could not restore current frame

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  • Developing Job References

    - by Joe Smith
    How do you develop references for jobs? I have 6 years of programming experience spanning two jobs, but sadly I don't have a lot of people I can draw on as references. It's been several years since I left my last job, which was at a small company, and I've lost touch with the few people I knew there. I now work at another small company. I think I've gone as far as I can in my current position, and would like to look for greener pastures, but I can't exactly use my current boss as a reference, even though I have a very good repore with him. I'm sure he'd make a great reference down the road, but I'm afraid I'd insult him or jeopardize my current job by mentioning that I'm thinking of leaving and would like him to help me. I've applied to some jobs, and I have gotten several replies like, "Oh, you're exactly what we're looking for. Send us a couple references and we'll schedule an interview. Oh, no references? You must be a psychopath, nevermind." I've tried doing some small freelance work on the side, just so I can have a contact who can vouch for my work, but the competition for even small projects is pretty fierce and I can rarely devote adequate time to freelancing while holding a full time job. In addition, I often encounter a Catch-22 where a lot of freelancing jobs also require references. So how do programmers maintain existing references and develop new ones, especially while holding a full time job?

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  • SQL Duplicates Issue SQL SERVER 2000

    - by jeff
    I have two tables : Product and ProductRateDetail. The parent table is Product. I have duplicate records in the product table which need to be unique. There are entries in the ProductRateDetail table which correspond to duplicate records in the product table. Somehow I need to update the ProductRateDetail table to match the original (older) ID from the Product table and then remove the duplicates from the product table. I would do this manually but there are 100's of records. i.e. something like UPDATE tbl_productRateDetail SET productID = (originalID from tbl_product) then something like DELETE from tbl_product WHERE duplicate ID and only delete the recently added ID data example: (sorry can't work out this formatting thing) tbl_Product select * from dbo.Product where ProductCode = '10003' ProductID ProductTypeID ProductDescription ProductCode ProductSize 365 1 BEND DOUBLE FLANGED 10003 80mmX90deg 1354 1 BEND DOUBLE FLANGED 10003 80mmX90deg tbl_ProductRateDetail SELECT * FROM [MSTS2].[dbo].[ProductRateDetail] WHERE ProductID in (365,1354) ProductRateDetailID ProductRateID ProductID UnitRate 365 1 365 16.87 1032 5 365 16.87 2187 10 365 16.87 2689 11 365 16.87 3191 12 365 16.87 7354 21 1354 21.30 7917 22 1354 21.30 8480 23 1354 21.30 9328 25 1354 21.30 9890 26 1354 21.30 10452 27 1354 21.30 Please help!

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  • How to (kindly) ask your users to upgrade from IE6?

    - by nickf
    It's no secret at all that IE6 has been a major roadblock to the advancement of the web over the last few years. I couldn't count the number of hours I've spent bashing my head against a wall trying to fix or debug IE6 issues. The way I see it, there are two types of IE6 user. a) the poor corporate schmoe whose IT department doesn't want to upgrade in case something breaks, and b) the mums and dads of the world who think the internet is the blue E on their desktop (and I don't mean that in a nasty way). There's probably a couple of people who know about all the other browsers, but still choose to run IE6. They get what they deserve, IMO. Anyway, getting to the point, I'd say that 90% of my IE6-using visitors are in the the mums and dads category - they're not stupid, they just don't know WHY they should upgrade to IE7 or Firefox or whatever. How do I educate these people without pissing them off? Is there a nice and friendly website I can direct these people to, which explains the reasons for upgrading in plain language? Any mention of "security" or "web standards" I think would just come across as scary. I've just seen http://www.whatbrowser.org which seems to fit the bill nicely. It explains in very basic terms: what a web browser is why you'd want to upgrade it how old your current browser is (subtle hint to those with a 9 year old browser) ..aaaand it's in 22 languages. It's from Google but displays no bias (it links to Firefox, Chrome, Opera, Safari, Internet Explorer displayed in a random order).

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  • Getting random record from database with group by

    - by Saif Bechan
    Hello i have a question on picking random entries from a database. I have 4 tables, products, bids and autobids, and users. Products ------- id 20,21,22,23,24(prime_key) price........... etc........... users ------- id(prim_key) name user1,user2,user3 etc bids ------- product_id user_id created autobids -------- user_id product_id Now a multiple users can have an autobid on an product. So for the next bidder I want to select a random user from the autobid table example of the query in language: for each product in the autobid table I want a random user, which is not the last bidder. On product 20 has user1,user2,user3 an autobidding. On product 21 has user1,user2,user3 an autobidding Then I want a resultset that looks for example like this 20 – user2 21 – user3 Just a random user. I tried miximg the GOUP BY (product_id) and making it RAND(), but I just can't get the right values from it. Now I am getting a random user, but all the values that go with it don't match. Can someone please help me construct this query, I am using php and mysql

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  • Attempted to render a circle in opengl es 1.1, renders as oval

    - by eipxen
    Hi all, I attempted to render a circle in opengl es 1.1 as a test before building a larger program, but it renders as an oval. Here is the code I use to generate and render my vertices: static const int numVerts = 40; static GLfloat myFirstCircle[82]; myFirstCircle[0] = 0.0f; myFirstCircle[1] = 0.0f; for (int i = 2; i < (numVerts+1)*2; i+=2) { myFirstCircle[i] = .5 * cosf(i*2*3.14159/numVerts); myFirstCircle[i+1] = .5 * sinf(i*2*3.14159/numVerts); } glVertexPointer(2, GL_FLOAT, 0, myFirstCircle); glEnableClientState(GL_VERTEX_ARRAY); glDrawArrays(GL_TRIANGLE_FAN, 0, 22); I'm still somewhat new to this system, so I may have a silly error that I do not see, but it seems to me like this should generate 40 vertices on a circle of radius .5. When it renders, the shape on screen appears to be an oval, significantly taller than it is wide. My question is thus: why is my circle rendering this way, and what could I do to fix it? This is the first question on stackoverflow, so I'm not sure how to share an image of my output.

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