Search Results

Search found 33468 results on 1339 pages for 'behaviour change'.

Page 14/1339 | < Previous Page | 10 11 12 13 14 15 16 17 18 19 20 21  | Next Page >

  • Strange behaviour on postback in ASP.NET

    - by C-King
    I'm working on a website with a login form. To log in, a postback is used to an OnClick handler in the codebehind. Somehow, the value returned from the Text-property of the username and password textboxes is ten times the value I entered, separated by commas. I checked my entire code for double ID's (which seems to be the most common problem causing this behaviour), but I found each ID defined only once. In the ASPX file I have this: <asp:Label ID="lblFeedback" ForeColor="Red" Font-Bold="true" runat="server" Visible="false" /><br /> <asp:Panel ID="pnlLogin" runat="server"> <table style="border-style: none;"> <tr> <td> <asp:Label ID="lblUsername" AssociatedControlID="txtUsername" runat="server" /> </td> <td> <asp:TextBox ID="txtUsername" runat="server" /><br /> </td> </tr> <tr> <td> <asp:Label ID="lblPassword" AssociatedControlID="txtPassword" runat="server" /> </td> <td> <asp:TextBox ID="txtPassword" runat="server" TextMode="password" /><br /> </td> </tr> <tr> <td> </td> <td> <asp:Button ID="btnLogin" OnClick="btnLogin_Click" runat="server" /> </td> </tr> </table> </asp:Panel> The OnClick handler in the Codebehind: protected void btnLogin_Click(object sender, EventArgs e) { string username = Util.Escape(txtUsername.Text); string password = Util.Escape(txtPassword.Text); WebsiteUser user = WebsiteUser.Create(username, password); if (user != null) { //Set some session variables and redirect to user profile } else { lblFeedback.Text = Localizer.Translate("INVALID_LOGIN"); lblFeedback.ForeColor = Color.Red; lblFeedback.Visible = true; pnlLogin.Visible = true; } } The website is running on ASP.NET 2.0 on ISS 5.1 (Win XP Pro)

    Read the article

  • Warning: comparison with string literals results in unspecified behaviour

    - by nunos
    So I starting the project of writing a simplified sheel for linux in c. I am not at all proficient with c nor with Linux that's exactly the reason I decided it would be a good idea. Starting with the parser, I have already encountered some problems. The code should be straightforward that's why I didn't include any comments. I am getting a warning with gcc: "comparison with string literals results in unspecified behaviour" at the lines commented with "WARNING HERE" (see code below). I have no idea why this causes an warning, but the real problem is that even though I am comparing an "<" to an "<" is doesn't get inside the if... I am looking for an answer for the problem explained, however if there's something that you see in the code that should be improved please say so. Just take in mind I am not that proficient and that this is still a work in progress (or better yet, a work in start). Thanks in advance. #include <stdio.h> #include <unistd.h> #include <string.h> typedef enum {false, true} bool; typedef struct { char **arg; char *infile; char *outfile; int background; } Command_Info; int parse_cmd(char *cmd_line, Command_Info *cmd_info) { char *arg; char *args[100]; int i = 0; arg = strtok(cmd_line, " \n"); while (arg != NULL) { args[i] = arg; arg = strtok(NULL, " \n"); i++; } int num_elems = i; cmd_info->infile = NULL; cmd_info->outfile = NULL; cmd_info->background = 0; int iarg = 0; for (i = 0; i < num_elems; i++) { if (args[i] == "&") //WARNING HERE return -1; else if (args[i] == "<") //WARNING HERE if (args[i+1] != NULL) cmd_info->infile = args[i+1]; else return -1; else if (args[i] == ">") //WARNING HERE if (args[i+1] != NULL) cmd_info->outfile = args[i+1]; else return -1; else cmd_info->arg[iarg++] = args[i]; } cmd_info->arg[iarg] = NULL; return 0; } void print_cmd(Command_Info *cmd_info) { int i; for (i = 0; cmd_info->arg[i] != NULL; i++) printf("arg[%d]=\"%s\"\n", i, cmd_info->arg[i]); printf("arg[%d]=\"%s\"\n", i, cmd_info->arg[i]); printf("infile=\"%s\"\n", cmd_info->infile); printf("outfile=\"%s\"\n", cmd_info->outfile); printf("background=\"%d\"\n", cmd_info->background); } int main(int argc, char* argv[]) { char cmd_line[100]; Command_Info cmd_info; printf(">>> "); fgets(cmd_line, 100, stdin); parse_cmd(cmd_line, &cmd_info); print_cmd(&cmd_info); return 0; }

    Read the article

  • Change ListView background - strage behaviour

    - by Beasly
    Hi again, I have a problem with changing the background of a view in a ListView. What I need: Change the background image of a row onClick() What actually happens: The background gets changed (selected) after pressing e.g. the first entry. But after scrolling down the 8th entry is selected too. Scroll back to the top the first isn't selected anymore. The second entry is selected now. Continue scrolling and it continues jumping... What i'm dong in the Code: I have channels, and onClick() I toggle an attribute of channel boolean selected and then I change the background. I'm doing this only onClick() thats why I don't get why it's actuelly happening on other entries too. One thing I notices is: It seems to be only the "drawing"-part because the item which get selected "by it self" has still the selected value on false I think it seems to have something to do with the reuse of the views in the custom ListAdapters getView(...) Code of onClick() in ListActivity: @Override protected ViewHolder createHolder(View v) { // createHolder will be called only as long, as the ListView is not // filled TextView title = (TextView) v .findViewById(R.id.tv_title_channel_list_adapter); TextView content = (TextView) v .findViewById(R.id.tv_content_channel_list_adapter); ImageView icon = (ImageView) v .findViewById(R.id.icon_channel_list_adapter); if (title == null || content == null || icon == null) { Log.e("ERROR on findViewById", "Couldn't find Title, Content or Icon"); } ViewHolder mvh = new MyViewHolder(title, content, icon); // We make the views become clickable // so, it is not necessary to use the android:clickable attribute in // XML v.setOnClickListener(new ChannelListAdapter.OnClickListener(mvh) { public void onClick(View v, ViewHolder viewHolder) { // we toggle the enabled state and also switch the the // background MyViewHolder mvh = (MyViewHolder) viewHolder; Channel ch = (Channel) mvh.data; ch.setSelected(!ch.getSelected()); // toggle if (ch.getSelected()) { v.setBackgroundResource(R.drawable.row_blue_selected); } else { v.setBackgroundResource(R.drawable.row_blue); } // TESTING Log.d("onClick() Channel", "onClick() Channel: " + ch.getTitle() + " selected: " + ch.getSelected()); } }); return mvh; } Code of getView(...): @Override public View getView(int position, View view, ViewGroup parent) { ViewHolder holder; // When view is not null, we can reuse it directly, there is no need // to reinflate it. // We only inflate a new View when the view supplied by ListView is // null. if (view == null) { view = mInflater.inflate(mViewId, null); // call own implementation holder = createHolder(view); // TEST // we set the holder as tag view.setTag(holder); } else { // get holder back...much faster than inflate holder = (ViewHolder) view.getTag(); } // we must update the object's reference holder.data = getItem(position); // call the own implementation bindHolder(holder); return view; } I really would appreciate any idea how to solve this! :) If more information is needed please tell me. Thanks in advance!

    Read the article

  • QuickBox2D poly behaviour vs box or circle

    - by Ben Kanizay
    Hi I've played a little with Box2D before and have just started using QuickBox2D which makes things heaps easier. I am however getting different behaviour with a specific poly shape than I am with a box. All other properties are the same. I've included 3 simple examples and their source below. What I really want to work is Example 1 with both objects as poly. As you can see, it seems like the 'paddle' poly is the one that's failing - the 'ball' (whether it's a poly or circle) just falls straight through it instead of bouncing off as it does with a box 'paddle' object. Would appreciate some help or insight. As I can only post one line at this stage, the swf previews of the 3 examples can be seen here Example 1 source: package { import com.actionsnippet.qbox.QuickBox2D; import com.actionsnippet.qbox.QuickObject; import flash.display.MovieClip; public class Eg1 extends MovieClip { private var sim:QuickBox2D; private var paddle:QuickObject; private var ball:QuickObject; public function Eg1() { this.sim = new QuickBox2D(this); this.paddle = this.sim.addPoly({ x:13, y:19, angle:0, density:0, draggable:false, isBullet:true, verts:[[-3.84,-0.67,-2.84,-1,-2.17,-0.33,2.17,-0.33,2.84,-1,3.84,-0.67,2.84,1,-2.51,1]] }); this.ball = this.sim.addPoly({ x:13, y:1, restitution:1, friction:1, draggable:false, isBullet:true, verts:[[-0.34,-1,0.34,-1,0.67,-0.33,0.67,0.33,0.34,1,-0.34,1,-0.67,0.33,-0.67,-0.33]] }); this.sim.start(); } }} Example 2 source: package { import com.actionsnippet.qbox.QuickBox2D; import com.actionsnippet.qbox.QuickObject; import flash.display.MovieClip; public class Eg2 extends MovieClip { private var sim:QuickBox2D; private var paddle:QuickObject; private var ball:QuickObject; public function Eg2() { this.sim = new QuickBox2D(this); this.paddle = this.sim.addBox({ x:13, y:19, angle:0, density:0, draggable:false, isBullet:true, width:8 }); this.ball = this.sim.addPoly({ x:13, y:1, restitution:1, friction:1, draggable:false, isBullet:true, verts:[[-0.34,-1,0.34,-1,0.67,-0.33,0.67,0.33,0.34,1,-0.34,1,-0.67,0.33,-0.67,-0.33]] }); this.sim.start(); } }} Example 3 source: package { import com.actionsnippet.qbox.QuickBox2D; import com.actionsnippet.qbox.QuickObject; import flash.display.MovieClip; public class Eg3 extends MovieClip { private var sim:QuickBox2D; private var paddle:QuickObject; private var ball:QuickObject; public function Eg3() { this.sim = new QuickBox2D(this); this.paddle = this.sim.addPoly({ x:13, y:19, angle:0, density:0, draggable:false, isBullet:true, verts:[[-3.84,-0.67,-2.84,-1,-2.17,-0.33,2.17,-0.33,2.84,-1,3.84,-0.67,2.84,1,-2.51,1]] }); this.ball = this.sim.addCircle({ x:13, y:1, restitution:1, friction:1, draggable:false, isBullet:true, radius:1 }); this.sim.start(); } }}

    Read the article

  • Odd C++ template behaviour with static member vars

    - by jon hanson
    This piece of code is supposed to calculate an approximation to e (i.e. the mathematical constant ~ 2.71828183) at compile-time, using the following approach; e1 = 2 / 1 e2 = (2 * 2 + 1) / (2 * 1) = 5 / 2 = 2.5 e3 = (3 * 5 + 1) / (3 * 2) = 16 / 6 ~ 2.67 e4 = (4 * 16 + 1) / (4 * 6) = 65 / 24 ~ 2.708 ... e(i) = (e(i-1).numer * i + 1) / (e(i-1).denom * i) The computation is returned via the result static member however, after 2 iterations it yields zero instead of the expected value. I've added a static member function f() to compute the same value and that doesn't exhibit the same problem. #include <iostream> #include <iomanip> // Recursive case. template<int ITERS, int NUMERATOR = 2, int DENOMINATOR = 1, int I = 2> struct CalcE { static const double result; static double f () {return CalcE<ITERS, NUMERATOR * I + 1, DENOMINATOR * I, I + 1>::f ();} }; template<int ITERS, int NUMERATOR, int DENOMINATOR, int I> const double CalcE<ITERS, NUMERATOR, DENOMINATOR, I>::result = CalcE<ITERS, NUMERATOR * I + 1, DENOMINATOR * I, I + 1>::result; // Base case. template<int ITERS, int NUMERATOR, int DENOMINATOR> struct CalcE<ITERS, NUMERATOR, DENOMINATOR, ITERS> { static const double result; static double f () {return result;} }; template<int ITERS, int NUMERATOR, int DENOMINATOR> const double CalcE<ITERS, NUMERATOR, DENOMINATOR, ITERS>::result = static_cast<double>(NUMERATOR) / DENOMINATOR; // Test it. int main (int argc, char* argv[]) { std::cout << std::setprecision (8); std::cout << "e2 ~ " << CalcE<2>::result << std::endl; std::cout << "e3 ~ " << CalcE<3>::result << std::endl; std::cout << "e4 ~ " << CalcE<4>::result << std::endl; std::cout << "e5 ~ " << CalcE<5>::result << std::endl; std::cout << std::endl; std::cout << "e2 ~ " << CalcE<2>::f () << std::endl; std::cout << "e3 ~ " << CalcE<3>::f () << std::endl; std::cout << "e4 ~ " << CalcE<4>::f () << std::endl; std::cout << "e5 ~ " << CalcE<5>::f () << std::endl; return 0; } I've tested this with VS 2008 and VS 2010, and get the same results in each case: e2 ~ 2 e3 ~ 2.5 e4 ~ 0 e5 ~ 0 e2 ~ 2 e3 ~ 2.5 e4 ~ 2.6666667 e5 ~ 2.7083333 Why does result not yield the expected values whereas f() does? According to Rotsor's comment below, this does work with GCC, so I guess the question is, am i relying on some type of undefined behaviour with regards to static initialisation order, or is this a bug with Visual Studio?

    Read the article

  • Security behaviour in Adobe Air

    - by t.stamm
    Hi everyone! I am trying to load external SWFs in my Adobe AIR App. The loaded SWF is trying to access an URL to retrieve some informations via XML. When starting the SWF by itself it works fine. When loading the SWF from the File.applicationStorageDirectory i will get an Security-Error because the loaded App is executed in a local-with-filesystem Sandbox appareantly. First Question: Is there a way to change this? That the loaded SWF is running in a network Sandbox? Since that first attempt didn't worked i've moved the SWF to the app:// directory. Now i'll get a Security-Error because there is no policy file on the Server available where the XML data should be retrieved. Second Question: Why is the policy file not necessary when running the SWF by itself, but is necessary when trying to load the data from the application Sandbox? What am i doing wrong? Thanks in advance!

    Read the article

  • JPA behaviour...

    - by Marcel
    Hi I have some trouble understanding a JPA behaviour. Mabye someone could give me a hint. Situation: Product entity: @Entity public class Product implements Serializable { ... @OneToMany(mappedBy="product", fetch=FetchType.EAGER) private List<ProductResource> productResources = new ArrayList<ProductResource>(); .... public List<ProductResource> getProductResources() { return productResources; } public boolean equals(Object obj) { if (obj == this) return true; if (obj == null) return false; if (!(obj instanceof Product)) return false; Product p = (Product) obj; return p.productId == productId; } } Resource entity: @Entity public class Resource implements Serializable { ... @OneToMany(mappedBy="resource", fetch=FetchType.EAGER) private List<ProductResource> productResources = new ArrayList<ProductResource>(); ... public void setProductResource(List<ProductResource> productResource) { this.productResources = productResource; } public List<ProductResource> getProductResources() { return productResources; } public boolean equals(Object obj) { if (obj == this) return true; if (obj == null) return false; if (!(obj instanceof Resource)) return false; Resource r = (Resource) obj; return (long)resourceId==(long)r.resourceId; } } ProductResource Entity: This is a JoinTable (association class) with additional properties (amount). It maps Product and Resources. @Entity public class ProductResource implements Serializable { ... @JoinColumn(nullable=false, updatable=false) @ManyToOne(fetch=FetchType.EAGER, cascade=CascadeType.PERSIST) private Product product; @JoinColumn(nullable=false, updatable=false) @ManyToOne(fetch=FetchType.EAGER, cascade=CascadeType.PERSIST) private Resource resource; private int amount; public void setProduct(Product product) { this.product = product; if(!product.getProductResources().contains((this))){ product.getProductResources().add(this); } } public Product getProduct() { return product; } public void setResource(Resource resource) { this.resource = resource; if(!resource.getProductResources().contains((this))){ resource.getProductResources().add(this); } } public Resource getResource() { return resource; } ... public boolean equals(Object obj) { if (obj == this) return true; if (obj == null) return false; if (!(obj instanceof ProductResource)) return false; ProductResource pr = (ProductResource) obj; return (long)pr.productResourceId == (long)productResourceId; } } This is the Session Bean (running on glassfish). @Stateless(mappedName="PersistenceManager") public class PersistenceManagerBean implements PersistenceManager { @PersistenceContext(unitName = "local_mysql") private EntityManager em; public Object create(Object entity) { em.persist(entity); return entity; } public void delete(Object entity) { em.remove(em.merge(entity)); } public Object retrieve(Class entityClass, Long id) { Object entity = em.find(entityClass, id); return entity; } public void update(Object entity) { em.merge(entity); } } I call the session Bean from a java client: public class Start { public static void main(String[] args) throws NamingException { PersistenceManager pm = (PersistenceManager) new InitialContext().lookup("java:global/BackITServer/PersistenceManagerBean"); ProductResource pr = new ProductResource(); Product p = new Product(); Resource r = new Resource(); pr.setProduct(p); pr.setResource(r); ProductResource pr_stored = (ProductResource) pm.create(pr); pm.delete(pr_stored); Product p_ret = (Product) pm.retrieve(Product.class, pr_stored.getProduct().getProductId()); // prints out true ???????????????????????????????????? System.out.println(p_ret.getProductResources().contains(pr_stored)); } } So here comes my problem. Why is the ProductResource entity still in the List productResources(see code above). The productResource tuple in the db is gone after the deletion and I do newly retrieve the Product entity. If I understood right every method call of the client happens in a new persistence context, but here i obviously get back the non-refreshed product object!? Any help is appreciated Thanks Marcel

    Read the article

  • IntelliJ IDEA non standard caret behaviour

    - by Vaat666
    I have an issue with IntelliJ IDEA when selecting a big amount of text, and I cannot find the parameter to set to change that. Here is an example of the situation: My caret is on line 3 I scroll with the mouse wheel towards line 300 I press ctrl + shift I press the left button of the mouse Such an action would result in the text from line 3 to 300 being selected in all common editors (even in MS-Word I think), but not in IntelliJ. Do you know how to set this right? Thanks!

    Read the article

  • GCC, functions, and pointer arguments, warning behaviour

    - by James Morris
    I've recently updated to a testing distribution, which is now using GCC 4.4.3. Now I've set everything up, I've returned to coding and have built my project and I get one of these horrible messages: *** glibc detected *** ./boxyseq: free(): invalid pointer: 0x0000000001d873e8 *** I absolutely know what is wrong here, but was rather confused as to when I saw my C code where I call a function which frees a dynamically allocated data structure - I had passed it an incompatible pointer type - a pointer to a completely different data structure. warning: passing argument 1 of 'data_A_free' from incompatible pointer type note: expected 'struct data_A *' but argument is of type 'struct data_B *' I'm confused because I'm sure this would have been an error before and compilation would never have completed. Is this not just going to make life more difficult for C programmers? Can I change it back to an error without making a whole bunch of other warnings errors too? Or am I loosing the plot and it's always been a warning?

    Read the article

  • Very strange form behaviour

    - by musoNic80
    I can't work this out. One minute it was working fine and now it's not and I can't see what's changed!! My problem is simply submitting a username and password for a login function. The form method is set to "post" but for some reason no data is getting through. If I dump $_REQUEST or $_POST they return empty. I know the form is submitting because if I change the method to "get" I receive the data as expected. Can anyone think of any reason why "get" would work when "post" isn't?!?!? If it's relevant, I'm using the codeigniter framework.

    Read the article

  • Oracle Date format - Strange behaviour

    - by Sauron
    I am writing a SQL query to retrive data from a table between two dates. I give two inputs as shown. I convert the Date TO_CHAR(DD/MON/YYYY). 1. StartDate > 01/SEP/2009 EndDate < 01/OCT/2009 2. StartDate > 01/SEP/2009 EndDate < 1/OCT/2009 I dont get any result for the first input. When I change it to second one i get the result. What is the difference between 01/OCT/2009 1/OCT/2009

    Read the article

  • JQuery animate behaviour with inline-block elements

    - by IlludiumPu36
    I'm using JQuery to animate two divs, one on top of the other, inside a another div. The effect is like a button with the top and bottom halves opening up and down to reveal some contents. The idea is to have a number of these 'buttons' in line using float:left When a button is clicked, the script checks if another button is open, if so, closes that button and opens the clicked button. This works fine, except I want to change float:left to display:inline-block on the container div class (to prevent wrapping of a number of buttons if the browser is resized). The problem is the layout of buttons breaks as JQuery animate seems to be changing the vertical position of the button containers while animating. See fiddle

    Read the article

  • My new DNS change works from America but not Sweden

    - by Dougie
    Several hours ago i changed nameserver and DNS info on one of my domains at my domainregistar. When i access the domain from my home computers and when my friends access the domain they get to the old ip-adress hosting the dead site(We all live in Sweden). But when i access the website from my mobile phone or through google.com/translate or North American proxies the website is shown like it should. Why is this?, does it take time for change to take effect for diffrent locations/countries? I find it very strange and would like to start using my site now. Do you think it will change or could i've been doing something wrong?

    Read the article

  • Change the User Interface Language in Vista or Windows 7

    - by Matthew Guay
    Would you like to change the user interface language in any edition of Windows 7 or Vista on your computer?  Here’s a free app that can help you do this quickly and easily. If your native language is not the one most spoken in your area, you’ve likely purchased a PC with Windows preinstalled with a language that is difficult or impossible for you to use.  Windows 7 and Vista Ultimate include the ability to install multiple user interface languages and switch between them. However, all other editions are stuck with the language they shipped with.  With the free Vistalizator app, you can add several different interface languages to any edition of Vista or Windows 7 and easily switch between them. Note:  In this test, we used an US English copy of both Windows 7 Home Premium and Windows Vista Home Premium, and it works the same on any edition. The built-in language switching in the Ultimate Editions lets you set a user interface language for each user account, but this will only switch it for all users.  Add a User Interface Language to Windows To add an interface language to any edition of Windows 7 and Vista, first download Vistalizator (link below).  Then, from the same page, download the language pack of your choice.  The language packs are specific for each service pack of Windows, so make sure to choose the correct version and service pack you have installed. Once the downloads are finished, launch the Vistalizator program. You do not need to install it; simply run it and you’re ready to go.  Click the Add languages button to add a language to Windows. Select the user interface language pack you downloaded, and click Open. Depending on the language you selected, it may not automatically update with Windows Update when a service pack is released.  If so, you will have to remove the language pack and reinstall the new one for that service pack at that time.  Click Ok to continue. Make sure you’ve selected the correct language, and click Install language. Vistalizator will extract and install the language pack.  This took around 5 to 10 minutes in our test. Once the language pack is installed, click Yes to make it the default display language. Now, you have two languages installed in Windows.  You may be prompted to check for updates to the language pack; if so, click Update languages and Vistalizator will automatically check for and install any updates. When finished, exit Vistalizator to finish switching the language.  Click Yes to automatically reboot and apply the changes. When you computer reboots, it will show your new language, which in our test is Thai.  Here’s our Windows 7 Home Premium machine with the Thai language pack installed and running. You can even add a right to left language, such as Arabic, to Windows.  Simply repeat the steps to add another language pack.    Vistalizator was originally designed for Windows Vista, and works great with Windows 7 too.  The language packs for Vista are larger downloads than their Windows 7 counterparts.  Here’s our Vista Home Premium in English… And here’s how it looks after installing the Simplified Chinese language pack with Vistalizator. Revert to Your Original Language If you wish to return to the language that your computer shipped with, or want to switch to another language you’ve installed, run Vistalizator again.  Select the language you wish to use, and click Change language.   When you close Vistalizator, you will again be asked to reboot.  Once you’ve rebooted, you’ll see your new (or original) language ready to use.  Here’s our Windows 7 Home Premium desktop, back in it’s original English interface. Conclusion This is a great way to change your computer’s language into your own native language, and is especially useful for expatriates around the world.  Also, if you’d like to simply change or add an input language instead of changing the language throughout your computer, check out our tutorial on How to Add Keyboard Languages to XP, Vista, and Windows 7. Download Vistalizator Similar Articles Productive Geek Tips Enable Military Time in Windows 7 or VistaWhy Does My Password Expire in Windows?Use Windows Vista Aero through Remote Desktop ConnectionDisable User Account Control (UAC) the Easy Way on Win 7 or VistaAdd keyboard languages to XP, Vista, and Windows 7 TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips DVDFab 6 Revo Uninstaller Pro Registry Mechanic 9 for Windows PC Tools Internet Security Suite 2010 Home Networks – How do they look like & the problems they cause Check Your IMAP Mail Offline In Thunderbird Follow Finder Finds You Twitter Users To Follow Combine MP3 Files Easily QuicklyCode Provides Cheatsheets & Other Programming Stuff Download Free MP3s from Amazon

    Read the article

  • How to Change and Manually Start and Stop Automatic Maintenance in Windows 8

    - by Lori Kaufman
    Windows 8 has a new feature that allows you to automatically run scheduled daily maintenance on your computer. These maintenance tasks run in the background and include security updating and scanning, Windows software updates, disk defragmentation, system diagnostics, among other tasks. We’ve previously shown you how to automate maintenance in Windows 7, Vista, and XP. Windows 8 maintenance is automatic by default and the performance and energy efficiency has been improved over Windows 7. The program for Windows 8 automatic maintenance is called MSchedExe.exe and it is located in the C:\Windows\System32 directory. We will show you how you can change the automatic maintenance settings in Windows 8 and how you can start and stop the maintenance manually. NOTE: It seems that you cannot turn off the automatic maintenance in Windows 8. You can only change the settings and start and stop it manually. Can Dust Actually Damage My Computer? What To Do If You Get a Virus on Your Computer Why Enabling “Do Not Track” Doesn’t Stop You From Being Tracked

    Read the article

  • Change default language settings in Visual Studio 2012

    - by sreejukg
    The first thing you need to do after the installation of Visual Studio 2012 is to choose the IDE preferences. Once you select your preferred collection of settings, the IDE will always choose dialogs and other options according to your selection. Nowadays developer’s needs to work with different programming environments and due to this, developers might need to reset the default settings. In this article, I am going to demonstrate how you can change the default settings in Visual Studio 2012. For the purpose of this demonstration, I have installed Visual Studio 2012 and selected C++ as my default environment settings. So now when I go to file -> new project, it will give me C++ templates by default as follows. If you want to select another language, you need to expand Other Languages section and select C# or VB. Now I am going to change these default settings. I am going to change the default language preference to C#. In Visual Studio 2012, go to tools menu and select Import and Export Settings. Here you have 3 options; one is to export the current settings so that the settings are saved for future use. Also you can import previously saved settings. The last option available is to reset it to default. It is a good Idea to export your settings and import it as you need in later stages. To reset the settings to default select the Reset option and click next. Now Visual Studio will ask you to whether you would like to save the settings, which can be used in future to restore. Select any one option and click next. For the purpose of this demo, I have selected not to save the settings. Click Next button to continue. Now Visual Studio will bring you the similar dialog that appears just after installation to select your IDE settings. Select the required settings from the available list and click Finish button. Click Finish once you are done. If everything OK, you will see the success message as below. Now go to file -> new Project, you will see the selected language appear by default. I selected C# in the previous step and the new project dialog appears as follows. Changing IDE settings in Visual Studio 2012 is very easy and straight forward.

    Read the article

  • Help me with CDMA usb modem (How to change storage mode to modem mode)

    - by user98698
    My modem isn't in the device list of usb_modeswitch.... so I cannot automatically use the modem on the ubuntu.... I found the way to change the modem from usb storage mode to modem mode and I can use my modem. But I forgot the instructions. I don't know the modem's name. It's chinese modem. But here is vendor/product id ....05 Qualcomm, Inc. Mass Storage Device and I think the target vendor/product id is ..... 05. So help me to change. I don't want to replace modem. pls. Sorry for my english....

    Read the article

  • How to change grub-bios to grub-efi

    - by user92325
    So a while ago i installed Ubuntu on my Macbook. I had to reinstall it because something in the update manager messed up. Not to concerded about that but for some reason after the installation Ubuntu wont boot. I found out later that Apple hardware uses EFI as the BIOS. Every time i try to install it i make a swap space and the root file to make the installation. I noticed that when i make the boot file its in grub-bios. I need to change this to grub-efi i found out but theres no option to change this. It still wont boot though. When i install it i dont get any errors but doing a little bit of reasearch i find that the boot file may be the problem im not entirely sure how to fix this but if anyone could give me some insight on this subject id very much appreciate it

    Read the article

  • Will domain change affect my pagerank?

    - by Chankey Pathak
    I have two blogger's blog. (http://chankeypathak.blogspot.com and http://javaenthusiastic.blogspot.com) One blog has PR 3 and the other blog has PR 2. I want to buy the domain for both blogs so that they will become http://chankeypathak.com/ and http://javaenthusiastic.com/ I will follow all the procedures that Blogger suggests so that all the visitors to http://chankeypathak.blogspot.com will be redirected to http://chankeypathak.com/ and same for the java's blog. I just want to know that whether this will affect my pagerank or not? I want my PR to remain same and not to be change because of domain change. Let me know. Thank you. PS: I don't know whether one person is allowed to post his site's URL in questions or not. If it is not allowed then you may edit the question.

    Read the article

  • How to change eclipse font sizes

    - by David M. Karr
    I'm trying to reduce the font sizes used in Eclipse. I've read several notes talking about how to do this, but none of them have made a difference. Obviously, changing it in Eclipse preferences doesn't do it. The common answers about using "Appearance-Fonts" doesn't work, because there is no "Fonts" tab. I believe I saw one person say that the "Fonts" tab isn't supposed to be there anymore. The next suggestion is to install MyUnity and change the font settings there. That appeared to change the fonts used in other apps, like gnome-terminal and window headers, but it still has had no effect on Eclipse.

    Read the article

  • How to change the default editor of a specific file type in JDeveloper

    - by [email protected]
    When you open a file in JDeveloper, the mode that is used as the default might not be what you as a developer want.  If, for example, every time you open a .jsp(x) file you click on the source tab at the bottom of the window so that you can edit the jsp(x) file in source code mode, you may want to consider changing the default editor for that file type.  This is easy to do in the JDeveloper tool preferences and can be a time saver in the long run, since some editors can take a while to start up and if you don't need them often, this would just be lost time.  Here are the steps:  From the JDeveloper menu, select Tools->Preferences...Select "File Types" in the tree component on the left side of the preferences dialog.Click on the "Default Editors" tab.Scroll to the file type you want to change.In the details section at the bottom of the dialog, use the "Default Editor" select list to change the default to your liking.

    Read the article

  • How to change speed without changing path travelled?

    - by Ben Williams
    I have a ball which is being thrown from one side of a 2D space to the other. The formula I am using for calculating the ball's position at any one point in time is: x = x0 + vx0*t y = y0 + vy0*t - 0.5*g*t*t where g is gravity, t is time, x0 is the initial x position, vx0 is the initial x velocity. What I would like to do is change the speed of this ball, without changing how far it travels. Let's say the ball starts in the lower left corner, moves upwards and rightwards in an arc, and finishes in the lower right corner, and this takes 5s. What I would like to be able to do is change this so it takes 10s or 20s, but the ball still follows the same curve and finishes in the same position. How can I achieve this? All I can think of is manipulating t but I don't think that's a good idea. I'm sure it's something simple, but my maths is pretty shaky.

    Read the article

  • The rights needed to change a AD LDAP password

    - by Luuky19
    What are the bare minimum rights you need to change an other persons LDAP password?. I'm working on a tool that allows a user to change his password. as the tool needs to be written in PHP the only problem is that you can't use a user account to change the password. to work around this we want to use an manger/admin account that can only change the passwords of all the other users. now the problem. we could not find the right rights to set so that the account was allowed to change the passwords. the only way it worked for us was if we made him domain-admin and that is something we don't want. So what are the minimum rights that some one needs to change a other person password with PHP? EDIT: Changed the title to fit the question better.

    Read the article

  • Move website from host a to host b without down time dns change

    - by grigione
    I would like to move my website from host A to host B I have uploaded a copy of my site to the new host, while keeping the old copy in place with the old host I will need to update the nameservers to point to the new nameservers. I'll want to change the DNS settings of domain name to point to new host b To avoid down time for the DNS change to propagate through the net, can I add the old nameservers and new nameservers together without causing problems, or must I delete the old nameservers first? What happens to my website when it points to two different nameservers?

    Read the article

< Previous Page | 10 11 12 13 14 15 16 17 18 19 20 21  | Next Page >