Search Results

Search found 39440 results on 1578 pages for 'possible homework'.

Page 14/1578 | < Previous Page | 10 11 12 13 14 15 16 17 18 19 20 21  | Next Page >

  • Login via XDMCP not possible to 12.04 from Squeeze box

    - by Joysn
    Can anybody tell me whats wrong with my 12.04/lightdm/XDMCP setup? i activated X11 remote via tcp and XDMCP on lightdm and restarted lightdm: [SeatDefaults] user-session=ubuntu greeter-session=unity-greeter xserver-allow-tcp=true [XDMCPServer] enabled=true whenever i try to login to the remove lightdm via Xephyr Xephyr -query <remote ip> :10 i get the following trace: SELinux: Disabled on system, not enabling in X server [dix] Could not init font path element /usr/share/fonts/X11/cyrillic, removing from list! Ignoring device from udev. Ignoring device from udev. Ignoring device from udev. Ignoring device from udev. Ignoring device from udev. Ignoring device from udev. *** glibc detected *** Xephyr: free(): corrupted unsorted chunks: 0x08659088 *** ======= Backtrace: ========= /lib/i686/cmov/libc.so.6(+0x6af71)[0xb72b6f71] /lib/i686/cmov/libc.so.6(+0x6c7c8)[0xb72b87c8] /lib/i686/cmov/libc.so.6(cfree+0x6d)[0xb72bb8ad] Xephyr(Xfree+0x21)[0x81ddcd1] Xephyr(SrvXkbResizeKeyType+0x59e)[0x81ca01e] Xephyr[0x81ab8eb] Xephyr[0x81ac8c2] Xephyr[0x8088807] Xephyr[0x807c16a] /lib/i686/cmov/libc.so.6(__libc_start_main+0xe6)[0xb7262ca6] Xephyr[0x8061081] ======= Memory map: ======== 08048000-08204000 r-xp 00000000 fd:00 1148994 /usr/bin/Xephyr 08204000-08210000 rw-p 001bc000 fd:00 1148994 /usr/bin/Xephyr 08210000-08239000 rw-p 00000000 00:00 0 08496000-087ac000 rw-p 00000000 00:00 0 [heap] b5600000-b5621000 rw-p 00000000 00:00 0 b5621000-b5700000 ---p 00000000 00:00 0 b5762000-b588f000 rw-p 00000000 00:00 0 b588f000-b58b3000 r-xp 00000000 fd:00 50040 /usr/lib/libexpat.so.1.5.2 b58b3000-b58b5000 rw-p 00024000 fd:00 50040 /usr/lib/libexpat.so.1.5.2 b58d0000-b5ae4000 r-xp 00000000 fd:00 1212530 /usr/lib/dri/swrast_dri.so b5ae4000-b5ae9000 rw-p 00214000 fd:00 1212530 /usr/lib/dri/swrast_dri.so b5ae9000-b5af8000 rw-p 00000000 00:00 0 b5af8000-b5c24000 rw-s 00000000 00:04 1420132375 /SYSV00000000 (deleted) b5c24000-b5c28000 r-xp 00000000 fd:00 770089 /usr/lib/libXfixes.so.3.1.0 b5c28000-b5c29000 rw-p 00003000 fd:00 770089 /usr/lib/libXfixes.so.3.1.0 b5c29000-b5c31000 r-xp 00000000 fd:00 772923 /usr/lib/libXrender.so.1.3.0 b5c31000-b5c32000 rw-p 00007000 fd:00 772923 /usr/lib/libXrender.so.1.3.0 b5c32000-b5c3a000 r-xp 00000000 fd:00 49913 /usr/lib/libXcursor.so.1.0.2 b5c3a000-b5c3b000 rw-p 00007000 fd:00 49913 /usr/lib/libXcursor.so.1.0.2 b5c3b000-b5c58000 r-xp 00000000 09:02 466930 /lib/libgcc_s.so.1 b5c58000-b5c59000 rw-p 0001c000 09:02 466930 /lib/libgcc_s.so.1 b5c59000-b5c5b000 rw-p 00000000 00:00 0 b5c5b000-b7121000 r-xp 00000000 fd:00 49164 /usr/lib/libnvidia-glcore.so.256.53 b7121000-b7178000 rwxp 014c6000 fd:00 49164 /usr/lib/libnvidia-glcore.so.256.53 b7178000-b7188000 rwxp 00000000 00:00 0 b7188000-b7189000 r-xp 00000000 fd:00 49193 /usr/lib/tls/libnvidia-tls.so.256.53 b7189000-b718a000 rw-p 00000000 fd:00 49193 /usr/lib/tls/libnvidia-tls.so.256.53 b718a000-b718b000 rw-p 00000000 00:00 0 b718b000-b7190000 r-xp 00000000 fd:00 50172 /usr/lib/libfontenc.so.1.0.0 b7190000-b7191000 rw-p 00005000 fd:00 50172 /usr/lib/libfontenc.so.1.0.0 b7191000-b71a1000 r-xp 00000000 09:02 466849 /lib/libbz2.so.1.0.4 b71a1000-b71a2000 rw-p 00010000 09:02 466849 /lib/libbz2.so.1.0.4 b71a2000-b71b5000 r-xp 00000000 fd:00 52002 /usr/lib/libz.so.1.2.3.4 b71b5000-b71b6000 rw-p 00013000 fd:00 52002 /usr/lib/libz.so.1.2.3.4 b71b6000-b722a000 r-xp 00000000 fd:00 51162 /usr/lib/libfreetype.so.6.6.0 b722a000-b722e000 rw-p 00073000 fd:00 51162 /usr/lib/libfreetype.so.6.6.0 b722e000-b7246000 r-xp 00000000 fd:00 49652 /usr/lib/libxcb.so.1.1.0 b7246000-b7247000 rw-p 00017000 fd:00 49652 /usr/lib/libxcb.so.1.1.0 b7247000-b7248000 rw-p 00000000 00:00 0 b7248000-b724b000 r-xp 00000000 fd:00 54148 /usr/lib/libgpg-error.so.0.4.0 b724b000-b724c000 rw-p 00002000 fd:00 54148 /usr/lib/libgpg-error.so.0.4.0 b724c000-b738c000 r-xp 00000000 09:02 467095 /lib/i686/cmov/libc-2.11.3.so

    Read the article

  • Is it possible to only allow specific packages updates from a PPA

    - by Luis Alvarado
    Let us say I have added a PPA that has X package that I want but it also has Y package that I do not want to use or receive updates from. How can I, from the same PPA, receive updates for a specific package but deny updates from the same PPA for other packages. A step by step example would be good since this has happened to me in several PPAs that have a particular package I want but also add a whole bunch of others that I do not yet want to update.

    Read the article

  • Possible applications of algorithm devised for differentiating between structured vs random text

    - by rooznom
    I have written a program that can rapidly (within 5 sec on a 2GB RAM desktop, 2.33 Ghz CPU) differentiate between structured text (e.g english text) and random alphanumeric strings. It can also provide a probability score for the prediction. Are there any practical applications/uses of such a program. Note that the program is based on entropy models and does not have any dictionary comparisons in its workflow. Thanks in advance for your responses

    Read the article

  • Coherence on Exalogic: 6x Speeds on Half the Hardware is Possible

    - by jeckels
    Recently, Oracle Coherence released its 12c version, focused on scalability and real-time data delivery. As part of the launch, we showcased Coherence's tight coupling with Exalogic Elastic Cloud. By leveraging the Inifiniband Fabric in Exalogic, Coherence can now operate at up to 6x the speed on as little as half the hardware on an Exalogic box. This breakthrough is helping customers save money on their hardware costs while improving performance of their data grid. Here's a free resource available for you to explore this technology relationship further.For even more information on Coherence, attend our upcoming free virtual developer day on November 5th to see how developers can leverage Coherence in their everyday tasks.

    Read the article

  • IE 9 RC maybe possible to release on 10 February

    - by anirudha
    this is not a exclamatory we all know about that they always postponed their time for product release. I not know what is means of it. maybe it’s trick microsoft use to make their software popular. but sometime it’s give bad impression to user. On 2009 Microsoft put a widget [ countdown ] widget for launching Visual studio 2010. who used by many MSDN blogger. Somasagar are one of them who put the widget on their blog that show “How much time after Visual studio goes released”. but after post ponding the date I not know where widget was gone. site are down who provide the widget. they use same trick they postponed their  date 20 march to 12 April to release the Visual studio. well wait something more and next time never  believe that it’s really gone to release on certain date they show you on blog.

    Read the article

  • Tried every possible method but couldn't enable compiz?

    - by 9kkmin
    a newbie, installed ubuntu 10.10 about a month ago,over the month i fixed everything from dad playback,to webcam,but couldn't enable compiz anayway,my card is blacklisted, i tried the SKIP_CHECKS=yes,method and even tried ghex editing,but of no avail,now all i get when i run compiz in the terminal is "segmentation fault",the specs of my laptop is intel core i3 2330,and intel hd graphics 3000,has anyone has been able to run compiz on intel hd graphics 3000?

    Read the article

  • External hard drive failing, is backup recovery possible?

    - by backitup
    I have a Seagate Freeagent external hard drive. While I was backing it up on Windows XP my pc crashed and I received the horrifying "Delayed Write Error" when I rebooted citing "$MFT" and a few other files. I tried to unmount it, but to no avail. Now my pc just crashes when I try to access it via Windows. In Ubuntu I am able to view it through disk utility. SMART status is "DISK FAILURE IMMINENT". Fdisk doesn't work, and the SMART tests fail on "Reallocated Sector Count". Is there any way for me to rescue any of my data. I can still access the drive but as soon as I do that it crashes.

    Read the article

  • Linked lists in Java - Help with writing methods

    - by user368241
    Representation of a string in linked lists In every intersection in the list there will be 3 fields : The letter itself. The number of times it appears consecutively. A pointer to the next intersection in the list. The following class CharNode represents a intersection in the list : public class CharNode { private char _data; private int _value; private charNode _next; public CharNode (char c, int val, charNode n) { _data = c; _value = val; _next = n; } public charNode getNext() { return _next; } public void setNext (charNode node) { _next = node; } public int getValue() { return _value; } public void setValue (int v) { value = v; } public char getData() { return _data; } public void setData (char c) { _data = c; } } The class StringList represents the whole list : public class StringList { private charNode _head; public StringList() { _head = null; } public StringList (CharNode node) { _head = node; } } Add methods to the class StringList according to the details : (I will add methods gradually according to my specific questions) (Pay attention, these are methods from the class String and we want to fulfill them by the representation of a string by a list as explained above) Pay attention to all the possible error cases. Write what is the time complexity and space complexity of every method that you wrote. Make sure the methods you wrote are effective. It is NOT allowed to use ready classes of Java. It is NOT allowed to move to string and use string operations. 1) public int indexOf (int ch) - returns the index in the string it is operated on of the first appeareance of the char "ch". If the char "ch" doesn't appear in the string, returns -1. If the value of fromIndex isn't in the range, returns -1. Here is my try : public int indexOf (int ch) { int count = 0; charNode pos = _head; if (pos == null ) { return -1; } for (pos = _head; pos!=null && pos.getData()!=ch; pos = pos.getNext()) { count = count + pos.getValue(); } if (pos==null) return -1; return count; } Time complexity = O(N) Space complexity = O(1) EDIT : I have a problem. I tested it in BlueJ and if the char ch doesn't appear it returns -1 but if it does, it always returns 0 and I don't understand why... I am confused. How can the compiler know that the value is the number of times the letter appears consecutively? Can I assume this because its given on the question or what? If it's true and I can assume this, then my code should be correct right? Ok I just spoke with my instructor and she said it isn't required to write it in the exercise but in order for me to test that it indeed works, I need to open a new class and write a code for making a list so that the the value of every node is the number of times the letter appears consecutively. Can someone please assist me? So I will copy+paste to BlueJ and this way I will be able to test all the methods. Meanwhile I am moving on to the next methods. 2) public int indexOf (int ch, int fromIndex) - returns the index in the string it is operated on of the first appeareance of the char "ch", as the search begins in the index "fromIndex". If the char "ch" doesn't appear in the string, returns -1. If the value of fromIndex doesn't appear in the range, returns -1. Here is my try: public int indexOf (int ch, int fromIndex) { int count = 0, len=0, i; charNode pos = _head; CharNode cur = _head; for (pos = _head; pos!=null; pos = pos.getNext()) { len = len+1; } if (fromIndex<0 || fromIndex>=len) return -1; for (i=0; i<fromIndex; i++) { cur = cur.getNext(); } if (cur == null ) { return -1; } for (cur = _head; cur!=null && cur.getData()!=ch; cur = cur.getNext()) { count = count + cur.getValue(); } if (cur==null) return -1; return count; } Time complexity = O(N) ? Space complexity = O(1) 3) public StringList concat (String str) - returns a string that consists of the string that it is operated on and in its end the string "str" is concatenated. Here is my try : public StringList concat (String str) { String str = ""; charNode pos = _head; if (str == null) return -1; for (pos = _head; pos!=null; pos = pos.getNext()) { str = str + pos.getData(); } str = str + "str"; return str; } Time complexity = O(N) Space complexity = O(1)

    Read the article

  • I need a very rapid game engine with as many presets as possible [closed]

    - by GLycan
    I have to make a game about the immune system (with as many grotesque simplifications as I want) in roughly two weeks. I'm thinking of something along the lines of bubble tanks, but I think I can roll with pretty much anything that fits the following: Working engine that handles mouvement, objects The fighting system can be done in any way that allows a bare minimum of configuration Scripting should be, preferably, Python Art should be customizable I'm hoping that there is some existing game that I could adapt. Any sggestions (aside from not leaving projects until later) ?

    Read the article

  • possible missing firmware

    - by pdd
    the other day i removed my linux-firmware package by mistake, i tried reinstalling it but i get this error: E: /var/cache/apt/archives/linux-firmware_1.60_all.deb: trying to overwrite '/lib/firmware/rt73.bin', which is also in package firmware-ralink 0.14+lenny2 the code from the terminal is: (Reading database ... 235747 files and directories currently installed.) Unpacking linux-firmware (from .../linux-firmware_1.60_all.deb) ... dpkg: error processing /var/cache/apt/archives/linux-firmware_1.60_all.deb (--unpack): trying to overwrite '/lib/firmware/rt73.bin', which is also in package firmware-ralink 0.14+lenny2 No apport report written because MaxReports is reached already dpkg-deb: error: subprocess paste was killed by signal (Broken pipe) Errors were encountered while processing: /var/cache/apt/archives/linux-firmware_1.60_all.deb E: Sub-process /usr/bin/dpkg returned an error code (1) A package failed to install. Trying to recover:

    Read the article

  • Classless tables possible with Datamapper?

    - by barerd
    I have an Item class with the following attributes: itemId,name,weight,volume,price,required_skills,required_items. Since the last two attributes are going to be multivalued, I removed them and create new schemes like: itemID,required_skill (itemID is foreign key, itemID and required_skill is primary key.) Now, I'm confused how to create/use this new table. Here are the options that came to my mind: 1) The relationship between Items and Required_skills is one-to-many, so I may create a RequiredSkill class, which belongs_to Item, which in turn has n RequiredSkills. Then I can do Item.get(1).requiredskills. This sounds most logical to me. 2) Since required_skills may well be thought of as constants (since they resemble rules), I may put them into a hash or gdbm database or another sql table and query from there, which I don't prefer. My question is: is there sth like a modelless table in datamapper, where datamapper is responsible from the creation and integrity of the table and allows me to query it in datamapper way, but does not require a class, like I may do it in sql?

    Read the article

  • Is the "impossible object" possible in computer graphics?

    - by CPP_Person
    This may be a silly question but I want to know the answer to it. I saw this thing called the "impossible object", while they're many different images of this online, it's suppost to be impossible geometry. Here is an example: Now as far as logic goes, I know you don't have to obey it in games, such as a flying cow, or an impossible object. So that's out of the way, but what stands in my way is whether or not there is a way to draw this onto a 3D scene. Like is there a way to represent it as a 3D object? Thanks!

    Read the article

  • Why is my Pre to Postfix code not working?

    - by Anthony Glyadchenko
    For a class assignment, I have to use two stacks in C++ to make an equation to be converted to its left to right equivalent: 2+4*(3+4*8) -- 35*4+2 -- 142 Here is the main code: #include <iostream> #include <cstring> #include "ctStack.h" using namespace std; int main (int argc, char * const argv[]) { string expression = "2+4*2"; ctstack *output = new ctstack(expression.length()); ctstack *stack = new ctstack(expression.length()); bool previousIsANum = false; for(int i = 0; i < expression.length(); i++){ switch (expression[i]){ case '(': previousIsANum = false; stack->cmstackPush(expression[i]); break; case ')': previousIsANum = false; char x; while (x != '('){ stack->cmstackPop(x); output->cmstackPush(x); } break; case '0': case '1': case '2': case '3': case '4': case '5': case '6': case '7': case '8': case '9': cout << "A number" << endl; previousIsANum = true; output->cmstackPush(expression[i]); break; case '+': previousIsANum = false; cout << "+" << endl; break; case '-': previousIsANum = false; cout << "-" << endl; break; case '*': previousIsANum = false; cout << "*" << endl; break; case '/': previousIsANum = false; cout << "/" << endl; break; default: break; } } char i = ' '; while (stack->ltopOfStack > 0){ stack->cmstackPop(i); output->cmstackPush(i); cout << i << endl; } return 0; } Here is the stack code (watch out!): #include <cstdio> #include <assert.h> #include <new.h> #include <stdlib.h> #include <iostream> class ctstack { private: long* lpstack ; // the stack itself long ltrue ; // constructor sets to 1 long lfalse ; // constructor sets to 0 // offset to top of the stack long lmaxEleInStack ; // maximum possible elements of stack public: long ltopOfStack ; ctstack ( long lnbrOfEleToAllocInStack ) { // Constructor lfalse = 0 ; // set to zero ltrue = 1 ; // set to one assert ( lnbrOfEleToAllocInStack > 0 ) ; // assure positive argument ltopOfStack = -1 ; // ltopOfStack is really an index lmaxEleInStack = lnbrOfEleToAllocInStack ; // set lmaxEleInStack to max ele lpstack = new long [ lmaxEleInStack ] ; // allocate stack assert ( lpstack ) ; // assure new succeeded } ~ctstack ( ) { // Destructor delete [ ] lpstack ; // Delete the stack itself } ctstack& operator= ( const ctstack& ctoriginStack) { // Assignment if ( this == &ctoriginStack ) // verify x not assigned to x return *this ; if ( this -> lmaxEleInStack < ctoriginStack . lmaxEleInStack ) { // if destination stack is smaller than delete [ ] this -> lpstack ; // original stack, delete dest and alloc this -> lpstack = // sufficient memory new long [ ctoriginStack . lmaxEleInStack ] ; assert ( this -> lpstack ) ; // assure new succeeded // reset stack size attribute this -> lmaxEleInStack = ctoriginStack . lmaxEleInStack ; } // copy original to destination stack for ( long i = 0 ; i < ctoriginStack . lmaxEleInStack ; i ++ ) *( this -> lpstack + i ) = *( ctoriginStack . lpstack + i ) ; this -> ltopOfStack = ctoriginStack . ltopOfStack ; // reset stack position attribute return *this ; } long cmstackPush (char lplaceInStack ) { // Push Method if ( ltopOfStack == lmaxEleInStack - 1 ) // stack is full can't add element return lfalse ; ltopOfStack ++ ; // acquire free slot *(lpstack + ltopOfStack ) = lplaceInStack ; // add element return ltrue ; // any number other than zero is true } long cmstackPop (char& lretrievedStackEle ) { // Pop Method if ( ltopOfStack < 0 ) { // stack has no elements lretrievedStackEle = -1 ; // dummy element return lfalse ; } lretrievedStackEle = *( lpstack + ltopOfStack ) ; // stack has element -- return it ltopOfStack -- ; // stack is pop'd return ltrue ; // any number other than zero is true } long cmstackLookAtTop (char& lretrievedStackEle ) { // Pop Method if ( ltopOfStack < 0 ) { // stack has no elements lretrievedStackEle = -1 ; // dummy element return lfalse ; } lretrievedStackEle = *( lpstack + ltopOfStack ) ; // stack has element -- return it return ltrue ; // any number other than zero is true } long cmstackHasAnEle (char& lretrievedTopOfStack ) { // Has element method lretrievedTopOfStack = ltopOfStack ; return ltopOfStack < 0 ? lfalse : ltrue ; // 0 - false stack does not have any ele } // 1 - true stack has at least one element long cmstackMaxNbrOfEle (char& lretrievedMaxStackEle ) { // Maximum element method lretrievedMaxStackEle = lmaxEleInStack ; // return stack size in reference var return ltrue ; // Return Maximum Size of Stack } } ; Thanks, Anthony.

    Read the article

  • Need some help on how to replay the last game of a java maze game

    - by Marty
    Hello, I am working on creating a Java maze game for a project. The maze is displayed on the console as standard output not in an applet. I have created most of hte code I need, however I am stuck at one problem and that is I need a user to be able to replay the last game i.e redraw the maze with the users moves but without any input from the user. I am not sure on what course of action to take, i was thinking about copying each users move or the position of each move into another array, as you can see i have 2 variables which hold the position of the player, plyrX and plyrY do you think copying these values into a new array after each move would solve my problem and how would i go about this? I have updated my code, apologies about the textIO.java class not being present, not sure how to resolve that exept post a link to TextIO.java [TextIO.java][1] My code below is updated with a new array of type char to hold values from the original maze (read in from text file and displayed using unicode characters) and also to new variables c_plyrX and c_plyrY which I am thinking should hold the values of plyrX and plyrY and copy them into the new array. When I try to call the replayGame(); method from the menu the maze loads for a second then the console exits so im not sure what I am doing wrong Thanks public class MazeGame { //unicode characters that will define the maze walls, //pathways, and in game characters. final static char WALL = '\u2588'; //wall final static char PATH = '\u2591'; //pathway final static char PLAYER = '\u25EF'; //player final static char ENTRANCE = 'E'; //entrance final static char EXIT = '\u2716'; //exit //declaring member variables which will hold the maze co-ordinates //X = rows, Y = columns static int entX = 0; //entrance X co-ordinate static int entY = 1; //entrance y co-ordinate static int plyrX = 0; static int plyrY = 1; static int exitX = 24; //exit X co-ordinate static int exitY = 37; //exit Y co-ordinate //static member variables which hold maze values //used so values can be accessed from different methods static int rows; //rows variable static int cols; //columns variable static char[][] maze; //defines 2 dimensional array to hold the maze //variables that hold player movement values static char dir; //direction static int spaces; //amount of spaces user can travel //variable to hold amount of moves the user has taken; static int movesTaken = 0; //new array to hold player moves for replaying game static char[][] mazeCopy; static int c_plyrX; static int c_plyrY; /** userMenu method for displaying the user menu which will provide various options for * the user to choose such as play a maze game, get instructions, etc. */ public static void userMenu(){ TextIO.putln("Maze Game"); TextIO.putln("*********"); TextIO.putln("Choose an option."); TextIO.putln(""); TextIO.putln("1. Play the Maze Game."); TextIO.putln("2. View Instructions."); TextIO.putln("3. Replay the last game."); TextIO.putln("4. Exit the Maze Game."); TextIO.putln(""); int option; //variable for holding users option TextIO.put("Type your choice: "); option = TextIO.getlnInt(); //gets users option //switch statement for processing menu options switch(option){ case 1: playMazeGame(); case 2: instructions(); case 3: if (c_plyrX == plyrX && c_plyrY == plyrY)replayGame(); else { TextIO.putln("Option not available yet, you need to play a game first."); TextIO.putln(); userMenu(); } case 4: System.exit(0); //exits the user out of the console default: TextIO.put("Option must be 1, 2, 3 or 4"); } } //end of userMenu /**main method, will call the userMenu and get the users choice and call * the relevant method to execute the users choice. */ public static void main(String[]args){ userMenu(); //calls the userMenu method } //end of main method /**instructions method, displays instructions on how to play * the game to the user/ */ public static void instructions(){ TextIO.putln("To beat the Maze Game you have to move your character"); TextIO.putln("through the maze and reach the exit in as few moves as possible."); TextIO.putln(""); TextIO.putln("Your characer is displayed as a " + PLAYER); TextIO.putln("The maze exit is displayed as a " + EXIT); TextIO.putln("Reach the exit and you have won escaped the maze."); TextIO.putln("To control your character type the direction you want to go"); TextIO.putln("and how many spaces you want to move"); TextIO.putln("for example 'D3' will move your character"); TextIO.putln("down 3 spaces."); TextIO.putln("Remember you can't walk through walls!"); boolean insOption; //boolean variable TextIO.putln(""); TextIO.put("Do you want to play the Maze Game now? (Y or N) "); insOption = TextIO.getlnBoolean(); if (insOption == true)playMazeGame(); else userMenu(); } //end of instructions method /**playMazeGame method, calls the loadMaze method and the charMove method * to start playing the Maze Game. */ public static void playMazeGame(){ loadMaze(); plyrMoves(); } //end of playMazeGame method /**loadMaze method, loads the 39x25 maze from the MazeGame.txt text file * and inserts values from the text file into the maze array and * displays the maze on screen using the unicode block characters. * plyrX and plyrY variables are set at their staring co ordinates so that when * a game is completed and the user selects to play a new game * the player character will always be at position 01. */ public static void loadMaze(){ plyrX = 0; plyrY = 1; TextIO.readFile("MazeGame.txt"); //now reads from the external MazeGame.txt file rows = TextIO.getInt(); //gets the number of rows from text file to create X dimensions cols = TextIO.getlnInt(); //gets number of columns from text file to create Y dimensions maze = new char[rows][cols]; //creates maze array of base type char with specified dimnensions //loop to process the array and read in values from the text file. for (int i = 0; i<rows; i++){ for (int j = 0; j<cols; j++){ maze[i][j] = TextIO.getChar(); } TextIO.getln(); } //end for loop TextIO.readStandardInput(); //closes MazeGame.txt file and reads from //standard input. //loop to process the array values and display as unicode characters for (int i = 0; i<rows; i++){ for (int j = 0; j<cols; j++){ if (i == plyrX && j == plyrY){ plyrX = i; plyrY = j; TextIO.put(PLAYER); //puts the player character at player co-ords } else{ if (maze[i][j] == '0') TextIO.putf("%c",WALL); //puts wall block if (maze[i][j] == '1') TextIO.putf("%c",PATH); //puts path block if (maze[i][j] == '2') { entX = i; entY = j; TextIO.putf("%c",ENTRANCE); //puts entrance character } if (maze[i][j] == '3') { exitX = i; //holds value of exit exitY = j; //co-ordinates TextIO.putf("%c",EXIT); //puts exit character } } } TextIO.putln(); } //end for loop } //end of loadMaze method /**redrawMaze method, method for redrawing the maze after each move. * */ public static void redrawMaze(){ TextIO.readFile("MazeGame.txt"); //now reads from the external MazeGame.txt file rows = TextIO.getInt(); //gets the number of rows from text file to create X dimensions cols = TextIO.getlnInt(); //gets number of columns from text file to create Y dimensions maze = new char[rows][cols]; //creates maze array of base type char with specified dimnensions //loop to process the array and read in values from the text file. for (int i = 0; i<rows; i++){ for (int j = 0; j<cols; j++){ maze[i][j] = TextIO.getChar(); } TextIO.getln(); } //end for loop TextIO.readStandardInput(); //closes MazeGame.txt file and reads from //standard input. //loop to process the array values and display as unicode characters for (int i = 0; i<rows; i++){ for (int j = 0; j<cols; j++){ if (i == plyrX && j == plyrY){ plyrX = i; plyrY = j; TextIO.put(PLAYER); //puts the player character at player co-ords } else{ if (maze[i][j] == '0') TextIO.putf("%c",WALL); //puts wall block if (maze[i][j] == '1') TextIO.putf("%c",PATH); //puts path block if (maze[i][j] == '2') { entX = i; entY = j; TextIO.putf("%c",ENTRANCE); //puts entrance character } if (maze[i][j] == '3') { exitX = i; //holds value of exit exitY = j; //co-ordinates TextIO.putf("%c",EXIT); //puts exit character } } } TextIO.putln(); } //end for loop } //end redrawMaze method /**replay game method * */ public static void replayGame(){ c_plyrX = plyrX; c_plyrY = plyrY; TextIO.readFile("MazeGame.txt"); //now reads from the external MazeGame.txt file rows = TextIO.getInt(); //gets the number of rows from text file to create X dimensions cols = TextIO.getlnInt(); //gets number of columns from text file to create Y dimensions mazeCopy = new char[rows][cols]; //creates maze array of base type char with specified dimnensions //loop to process the array and read in values from the text file. for (int i = 0; i<rows; i++){ for (int j = 0; j<cols; j++){ mazeCopy[i][j] = TextIO.getChar(); } TextIO.getln(); } //end for loop TextIO.readStandardInput(); //closes MazeGame.txt file and reads from //standard input. //loop to process the array values and display as unicode characters for (int i = 0; i<rows; i++){ for (int j = 0; j<cols; j++){ if (i == c_plyrX && j == c_plyrY){ c_plyrX = i; c_plyrY = j; TextIO.put(PLAYER); //puts the player character at player co-ords } else{ if (mazeCopy[i][j] == '0') TextIO.putf("%c",WALL); //puts wall block if (mazeCopy[i][j] == '1') TextIO.putf("%c",PATH); //puts path block if (mazeCopy[i][j] == '2') { entX = i; entY = j; TextIO.putf("%c",ENTRANCE); //puts entrance character } if (mazeCopy[i][j] == '3') { exitX = i; //holds value of exit exitY = j; //co-ordinates TextIO.putf("%c",EXIT); //puts exit character } } } TextIO.putln(); } //end for loop } //end replayGame method /**plyrMoves method, method for moving the players character * around the maze. */ public static void plyrMoves(){ int nplyrX = plyrX; int nplyrY = plyrY; int pMoves; direction(); //UP if (dir == 'U' || dir == 'u'){ nplyrX = plyrX; nplyrY = plyrY; for(pMoves = 0; pMoves <= spaces; pMoves++){ if (maze[nplyrX][nplyrY] == '0'){ TextIO.putln("Invalid move, try again."); } else if (pMoves != spaces){ nplyrX =plyrX + 1; } else { plyrX = plyrX-spaces; c_plyrX = plyrX; movesTaken++; } } }//end UP if //DOWN if (dir == 'D' || dir == 'd'){ nplyrX = plyrX; nplyrY = plyrY; for (pMoves = 0; pMoves <= spaces; pMoves ++){ if (maze[nplyrX][nplyrY] == '0'){ TextIO.putln("Invalid move, try again"); } else if (pMoves != spaces){ nplyrX = plyrX+1; } else{ plyrX = plyrX+spaces; c_plyrX = plyrX; movesTaken++; } } } //end DOWN if //LEFT if (dir == 'L' || dir =='l'){ nplyrX = plyrX; nplyrY = plyrY; for (pMoves = 0; pMoves <= spaces; pMoves++){ if (maze[nplyrX][nplyrY] == '0'){ TextIO.putln("Invalid move, try again"); } else if (pMoves != spaces){ nplyrY = plyrY + 1; } else{ plyrY = plyrY-spaces; c_plyrY = plyrY; movesTaken++; } } } //end LEFT if //RIGHT if (dir == 'R' || dir == 'r'){ nplyrX = plyrX; nplyrY = plyrY; for (pMoves = 0; pMoves <= spaces; pMoves++){ if (maze[nplyrX][nplyrY] == '0'){ TextIO.putln("Invalid move, try again."); } else if (pMoves != spaces){ nplyrY += 1; } else{ plyrY = plyrY+spaces; c_plyrY = plyrY; movesTaken++; } } } //end RIGHT if //prints message if player escapes from the maze. if (maze[plyrX][plyrY] == '3'){ TextIO.putln("****Congratulations****"); TextIO.putln(); TextIO.putln("You have escaped from the maze."); TextIO.putln(); userMenu(); } else{ movesTaken++; redrawMaze(); plyrMoves(); } } //end of plyrMoves method /**direction, method * */ public static char direction(){ TextIO.putln("Enter the direction you wish to move in and the distance"); TextIO.putln("i.e D3 = move down 3 spaces"); TextIO.putln("U - Up, D - Down, L - Left, R - Right: "); dir = TextIO.getChar(); if (dir =='U' || dir == 'D' || dir == 'L' || dir == 'R' || dir == 'u' || dir == 'd' || dir == 'l' || dir == 'r'){ spacesMoved(); } else{ loadMaze(); TextIO.putln("Invalid direction!"); TextIO.put("Direction must be one of U, D, L or R"); direction(); } return dir; //returns the value of dir (direction) } //end direction method /**spaces method, gets the amount of spaces the user wants to move * */ public static int spacesMoved(){ TextIO.putln(" "); spaces = TextIO.getlnInt(); if (spaces <= 0){ loadMaze(); TextIO.put("Invalid amount of spaces, try again"); spacesMoved(); } return spaces; } //end spacesMoved method } //end of MazeGame class

    Read the article

  • VHDL - Problem with std_logic_vector

    - by wretrOvian
    Hi, i'm coding a 4-bit binary adder with accumulator: library ieee; use ieee.std_logic_1164.all; entity binadder is port(n,clk,sh:in bit; x,y:inout std_logic_vector(3 downto 0); co:inout bit; done:out bit); end binadder; architecture binadder of binadder is signal state: integer range 0 to 3; signal sum,cin:bit; begin sum<= (x(0) xor y(0)) xor cin; co<= (x(0) and y(0)) or (y(0) and cin) or (x(0) and cin); process begin wait until clk='0'; case state is when 0=> if(n='1') then state<=1; end if; when 1|2|3=> if(sh='1') then x<= sum & x(3 downto 1); y<= y(0) & y(3 downto 1); cin<=co; end if; if(state=3) then state<=0; end if; end case; end process; done<='1' when state=3 else '0'; end binadder; The output : -- Compiling architecture binadder of binadder ** Error: C:/Modeltech_pe_edu_6.5a/examples/binadder.vhdl(15): No feasible entries for infix operator "xor". ** Error: C:/Modeltech_pe_edu_6.5a/examples/binadder.vhdl(15): Type error resolving infix expression "xor" as type std.standard.bit. ** Error: C:/Modeltech_pe_edu_6.5a/examples/binadder.vhdl(16): No feasible entries for infix operator "and". ** Error: C:/Modeltech_pe_edu_6.5a/examples/binadder.vhdl(16): Bad expression in right operand of infix expression "or". ** Error: C:/Modeltech_pe_edu_6.5a/examples/binadder.vhdl(16): No feasible entries for infix operator "and". ** Error: C:/Modeltech_pe_edu_6.5a/examples/binadder.vhdl(16): Bad expression in left operand of infix expression "or". ** Error: C:/Modeltech_pe_edu_6.5a/examples/binadder.vhdl(16): Bad expression in right operand of infix expression "or". ** Error: C:/Modeltech_pe_edu_6.5a/examples/binadder.vhdl(16): Type error resolving infix expression "or" as type std.standard.bit. ** Error: C:/Modeltech_pe_edu_6.5a/examples/binadder.vhdl(28): No feasible entries for infix operator "&". ** Error: C:/Modeltech_pe_edu_6.5a/examples/binadder.vhdl(28): Type error resolving infix expression "&" as type ieee.std_logic_1164.std_logic_vector. ** Error: C:/Modeltech_pe_edu_6.5a/examples/binadder.vhdl(39): VHDL Compiler exiting I believe i'm not handling std_logic_vector's correctly. Please tell me how? :(

    Read the article

  • These are few objective type questions which i was not able to find the solution [closed]

    - by Tarun
    1. Which of the following advantages does System.Collections.IDictionaryEnumerator provide over System.Collections.IEnumerator? a. It adds properties for direct access to both the Key and the Value b. It is optimized to handle the structure of a Dictionary. c. It provides properties to determine if the Dictionary is enumerated in Key or Value order d. It provides reverse lookup methods to distinguish a Key from a specific Value 2. When Implementing System.EnterpriseServices.ServicedComponent derived classes, which of the following statements are true? a. Enabling object pooling requires an attribute on the class and the enabling of pooling in the COM+ catalog. b. Methods can be configured to automatically mark a transaction as complete by the use of attributes. c. You can configure authentication using the AuthenticationOption when the ActivationMode is set to Library. d. You can control the lifecycle policy of an individual instance using the SetLifetimeService method. 3. Which of the following are true regarding event declaration in the code below? class Sample { event MyEventHandlerType MyEvent; } a. MyEventHandlerType must be derived from System.EventHandler or System.EventHandler<TEventArgs> b. MyEventHandlerType must take two parameters, the first of the type Object, and the second of a class derived from System.EventArgs c. MyEventHandlerType may have a non-void return type d. If MyEventHandlerType is a generic type, event declaration must use a specialization of that type. e. MyEventHandlerType cannot be declared static 4. Which of the following statements apply to developing .NET code, using .NET utilities that are available with the SDK or Visual Studio? a. Developers can create assemblies directly from the MSIL Source Code. b. Developers can examine PE header information in an assembly. c. Developers can generate XML Schemas from class definitions contained within an assembly. d. Developers can strip all meta-data from managed assemblies. e. Developers can split an assembly into multiple assemblies. 5. Which of the following characteristics do classes in the System.Drawing namespace such as Brush,Font,Pen, and Icon share? a. They encapsulate native resource and must be properly Disposed to prevent potential exhausting of resources. b. They are all MarshalByRef derived classes, but functionality across AppDomains has specific limitations. c. You can inherit from these classes to provide enhanced or customized functionality 6. Which of the following are required to be true by objects which are going to be used as keys in a System.Collections.HashTable? a. They must handle case-sensitivity identically in both the GetHashCode() and Equals() methods. b. Key objects must be immutable for the duration they are used within a HashTable. c. Get HashCode() must be overridden to provide the same result, given the same parameters, regardless of reference equalityl unless the HashTable constructor is provided with an IEqualityComparer parameter. d. Each Element in a HashTable is stored as a Key/Value pair of the type System.Collections.DictionaryElement e. All of the above 7. Which of the following are true about Nullable types? a. A Nullable type is a reference type. b. A Nullable type is a structure. c. An implicit conversion exists from any non-nullable value type to a nullable form of that type. d. An implicit conversion exists from any nullable value type to a non-nullable form of that type. e. A predefined conversion from the nullable type S? to the nullable type T? exists if there is a predefined conversion from the non-nullable type S to the non-nullable type T 8. When using an automatic property, which of the following statements is true? a. The compiler generates a backing field that is completely inaccessible from the application code. b. The compiler generates a backing field that is a private instance member with a leading underscore that can be programmatically referenced. c. The compiler generates a backing field that is accessible via reflection d. The compiler generates a code that will store the information separately from the instance to ensure its security. 9. Which of the following does using Initializer Syntax with a collection as shown below require? CollectionClass numbers = new CollectionClass { 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 }; a. The Collection Class must implement System.Collections.Generic.ICollection<T> b. The Collection Class must implement System.Collections.Generic.IList<T> c. Each of the Items in the Initializer List will be passed to the Add<T>(T item) method d. The items in the initializer will be treated as an IEnumerable<T> and passed to the collection constructor+K110 10. What impact will using implicitly typed local variables as in the following example have? var sample = "Hello World"; a. The actual type is determined at compilation time, and has no impact on the runtime b. The actual type is determined at runtime, and late binding takes effect c. The actual type is based on the native VARIANT concept, and no binding to a specific type takes place. d. "var" itself is a specific type defined by the framework, and no special binding takes place 11. Which of the following is not supported by remoting object types? a. well-known singleton b. well-known single call c. client activated d. context-agile 12. In which of the following ways do structs differ from classes? a. Structs can not implement interfaces b. Structs cannot inherit from a base struct c. Structs cannot have events interfaces d. Structs cannot have virtual methods 13. Which of the following is not an unboxing conversion? a. void Sample1(object o) { int i = (int)o; } b. void Sample1(ValueType vt) { int i = (int)vt; } c. enum E { Hello, World} void Sample1(System.Enum et) { E e = (E) et; } d. interface I { int Value { get; set; } } void Sample1(I vt) { int i = vt.Value; } e. class C { public int Value { get; set; } } void Sample1(C vt) { int i = vt.Value; } 14. Which of the following are characteristics of the System.Threading.Timer class? a. The method provided by the TimerCallback delegate will always be invoked on the thread which created the timer. b. The thread which creates the timer must have a message processing loop (i.e. be considered a UI thread) c. The class contains protection to prevent reentrancy to the method provided by the TimerCallback delegate d. You can receive notification of an instance being Disposed by calling an overload of the Dispose method. 15. What is the proper declaration of a method which will handle the following event? Class MyClass { public event EventHandler MyEvent; } a. public void A_MyEvent(object sender, MyArgs e) { } b. public void A_MyEvent(object sender, EventArgs e) { } c. public void A_MyEvent(MyArgs e) { } d. public void A_MyEvent(MyClass sender,EventArgs e) { } 16. Which of the following scenarios are applicable to Window Workflow Foundation? a. Document-centric workflows b. Human workflows c. User-interface page flows d. Builtin support for communications across multiple applications and/or platforms e. All of the above 17. When using an automatic property, which of the following statements is true? a. The compiler generates a backing field that is completely inaccessible from the application code. b. The compiler generates a backing field that is a private instance member with a leading underscore that can be programmatically referenced. c. The compiler generates a backing field that is accessible via reflection d. The compiler generates a code that will store the information separately from the instance to ensure its security. 18 While using the capabilities supplied by the System.Messaging classes, which of the following are true? a. Information must be explicitly converted to/from a byte stream before it uses the MessageQueue class b. Invoking the MessageQueue.Send member defaults to using the System.Messaging.XmlMessageFormatter to serialize the object. c. Objects must be XMLSerializable in order to be transferred over a MessageQueue instance. d. The first entry in a MessageQueue must be removed from the queue before the next entry can be accessed e. Entries removed from a MessageQueue within the scope of a transaction, will be pushed back into the front of the queue if the transaction fails. 19. Which of the following are true about declarative attributes? a. They must be inherited from the System.Attribute. b. Attributes are instantiated at the same time as instances of the class to which they are applied. c. Attribute classes may be restricted to be applied only to application element types. d. By default, a given attribute may be applied multiple times to the same application element. 20. When using version 3.5 of the framework in applications which emit a dynamic code, which of the following are true? a. A Partial trust code can not emit and execute a code b. A Partial trust application must have the SecurityCriticalAttribute attribute have called Assert ReflectionEmit permission c. The generated code no more permissions than the assembly which emitted it. d. It can be executed by calling System.Reflection.Emit.DynamicMethod( string name, Type returnType, Type[] parameterTypes ) without any special permissions Within Windows Workflow Foundation, Compensating Actions are used for: a. provide a means to rollback a failed transaction b. provide a means to undo a successfully committed transaction later c. provide a means to terminate an in process transaction d. achieve load balancing by adapting to the current activity 21. What is the proper declaration of a method which will handle the following event? Class MyClass { public event EventHandler MyEvent; } a. public void A_MyEvent(object sender, MyArgs e) { } b. public void A_MyEvent(object sender, EventArgs e) { } c. public void A_MyEvent(MyArgs e) { } d. public void A_MyEvent(MyClass sender,EventArgs e) { } 22. Which of the following controls allows the use of XSL to transform XML content into formatted content? a. System.Web.UI.WebControls.Xml b. System.Web.UI.WebControls.Xslt c. System.Web.UI.WebControls.Substitution d. System.Web.UI.WebControls.Transform 23. To which of the following do automatic properties refer? a. You declare (explicitly or implicitly) the accessibility of the property and get and set accessors, but do not provide any implementation or backing field b. You attribute a member field so that the compiler will generate get and set accessors c. The compiler creates properties for your class based on class level attributes d. They are properties which are automatically invoked as part of the object construction process 24. Which of the following are true about Nullable types? a. A Nullable type is a reference type. b. An implicit conversion exists from any non-nullable value type to a nullable form of that type. c. A predefined conversion from the nullable type S? to the nullable type T? exists if there is a predefined conversion from the non-nullable type S to the non-nullable type T 25. When using an automatic property, which of the following statements is true? a. The compiler generates a backing field that is completely inaccessible from the application code. b. The compiler generates a backing field that is accessible via reflection. c. The compiler generates a code that will store the information separately from the instance to ensure its security. 26. When using an implicitly typed array, which of the following is most appropriate? a. All elements in the initializer list must be of the same type. b. All elements in the initializer list must be implicitly convertible to a known type which is the actual type of at least one member in the initializer list c. All elements in the initializer list must be implicitly convertible to common type which is a base type of the items actually in the list 27. Which of the following is false about anonymous types? a. They can be derived from any reference type. b. Two anonymous types with the same named parameters in the same order declared in different classes have the same type. c. All properties of an anonymous type are read/write. 28. Which of the following are true about Extension methods. a. They can be declared either static or instance members b. They must be declared in the same assembly (but may be in different source files) c. Extension methods can be used to override existing instance methods d. Extension methods with the same signature for the same class may be declared in multiple namespaces without causing compilation errors

    Read the article

  • What are the advantages and disadvantages of Dojo, jQuery and Ext JS

    - by easoncyh
    This is a question asked in one of my lectures as a bonus. That means student giving the most appropriate answer will get extra credit. I have used jQuery before for a try and I have found jQuery to be extremely useful! However, I have not never used neither Dojo and Ext JS, can anyone please tell me the advantages and disadvantages of them? Thank you in advance!

    Read the article

  • Dijkstra's Bankers Algorithm

    - by idea_
    Could somebody please provide a step-through approach to solving the following problem using the Banker's Algorithm? How do I determine whether a "safe-state" exists? What is meant when a process can "run to completion"? In this example, I have four processes and 10 instances of the same resource. Resources Allocated | Resources Needed Process A 1 6 Process B 1 5 Process C 2 4 Process D 4 7

    Read the article

  • Card Shuffling in C#

    - by Jeff
    I am trying to write a code for a project that lists the contents of a deck of cards, asks how much times the person wants to shuffle the deck, and then shuffles them. It has to use a method to create two random integers using the System.Random class. These are my classes: Program.cs: using System; using System.Collections.Generic; using System.Linq; using System.Text; namespace ConsoleApplication3 { class Program { static void Main(string[] args) { Deck mydeck = new Deck(); foreach (Card c in mydeck.Cards) { Console.WriteLine(c); } Console.WriteLine("How Many Times Do You Want To Shuffle?"); } } } Deck.cs: using System; using System.Collections.Generic; using System.Linq; using System.Text; namespace ConsoleApplication3 { class Deck { Card[] cards = new Card[52]; string[] numbers = new string[] { "2", "3", "4", "5", "6", "7", "8", "9", "J", "Q", "K" }; public Deck() { int i = 0; foreach(string s in numbers) { cards[i] = new Card(Suits.Clubs, s); i++; } foreach (string s in numbers) { cards[i] = new Card(Suits.Spades, s); i++; } foreach (string s in numbers) { cards[i] = new Card(Suits.Hearts, s); i++; } foreach (string s in numbers) { cards[i] = new Card(Suits.Diamonds, s); i++; } } public Card[] Cards { get { return cards; } } } } classes.cs: using System; using System.Collections.Generic; using System.Linq; using System.Text; namespace ConsoleApplication3 { enum Suits { Hearts, Diamonds, Spades, Clubs } } Card.cs: using System; using System.Collections.Generic; using System.Linq; using System.Text; namespace ConsoleApplication3 { class Card { protected Suits suit; protected string cardvalue; public Card() { } public Card(Suits suit2, string cardvalue2) { suit = suit2; cardvalue = cardvalue2; } public override string ToString() { return string.Format("{0} of {1}", cardvalue, suit); } } } Please tell me how to make the cards shuffle as much as the person wants and then list the shuffled cards. Sorry about the formatting im new to this site.

    Read the article

  • OO design - car rental

    - by gkid123
    AnHow would you implement the following car hierarchy along with the accessor functions and a CarRental class which contains the container to store them? A car rental company wants to keep track of its cars. Each vehicle has a license plate and a brand. Currently the company has SUV and Sedans. SUV have an optional third row seat, sedan’s have an optional sport package. Each car can be queried to inquire the number of passengers it can carry.

    Read the article

< Previous Page | 10 11 12 13 14 15 16 17 18 19 20 21  | Next Page >