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  • Regular Expression Fails

    - by Meander365
    Anyone help? When I run this I get " invalid quantifier ?<=href= " var aHrefMatch = new RegExp("(?<=href\=")[^]+?(?=")"); var matchedLink = mystring.match(aHrefMatch); But I know the regular expression is valid. Any ideas?

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  • Sed: regular expression match lines without <!--

    - by sixtyfootersdude
    I have a sed command to comment out xml commands sed 's/^\([ \t]*\)\(.*[0-9a-zA-Z<].*\)$/\1<!-- Security: \2 -->/' web.xml Takes: <a> <!-- Comment --> <b> bla </b> </a> Produces: <!-- Security: <a> --> <!-- Security: <!-- Comment --> --> // NOTE: there are two end comments. <!-- Security: <b> --> <!-- Security: bla --> <!-- Security: </b> --> <!-- Security: </a> --> Ideally I would like to not use my sed script to comment things that are already commented. Ie: <!-- Security: <a> --> <!-- Comment --> <!-- Security: <b> --> <!-- Security: bla --> <!-- Security: </b> --> <!-- Security: </a> --> I could do something like this: sed 's/^\([ \t]*\)\(.*[0-9a-zA-Z<].*\)$/\1<!-- Security: \2 -->/' web.xml sed 's/^[ \t]*<!-- Security: \(<!--.*-->\) -->/\1/' web.xml but I think a one liner is cleaner (?) This is pretty similar: http://stackoverflow.com/questions/436850/matching-a-line-that-doesnt-contain-specific-text-with-regular-expressions

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  • Split string on first two colons

    - by Mark Miller
    I would like to split a column of strings on the first two colons, but not on any subsequent colons: my.data <- read.table(text=' my.string some.data 12:34:56:78 -100 87:65:43:21 -200 a4:b6:c8888 -300 11:bb:ccccc -400 uu:vv:ww:xx -500', header = TRUE) desired.result <- read.table(text=' my.string1 my.string2 my.string3 some.data 12 34 56:78 -100 87 65 43:21 -200 a4 b6 c8888 -300 11 bb ccccc -400 uu vv ww:xx -500', header = TRUE) I have searched extensively and the following question is the closest to my current dilemma: Split on first comma in string Thank you for any suggestions. I prefer to use base R.

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  • JavaScript: add or subtract from number in string

    - by yoavf
    I have a string that looks like "(3) New stuff" where 3 can be any number. I would like to add or subtract to this number. I figured out the following way: var thenumber = string.match((/\d+/)); thenumber++; string = string.replace(/\(\d+\)/ ,'('+ thenumber +')'); Is there a more elegant way to do it?

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  • Converting time period strings to value/unit pair

    - by randomtoor
    I need to parse the contents of a string that represents a time period. The format of the string is value/unit, e.g.: 1s, 60min, 24h. I would separate the actual value (an int) and unit (a str) to separated variables. At the moment I do it like this: def validate_time(time): binsize = time.strip() unit = re.sub('[0-9]','',binsize) if unit not in ['s','m','min','h','l']: print "Error: unit {0} is not valid".format(unit) sys.exit(2) tmp = re.sub('[^0-9]','',binsize) try: value = int(tmp) except ValueError: print "Error: {0} is not valid".format(time) sys.exit(2) return value,unit However, it is not ideal as things like 1m0 are also (wrongly) validated (value=10,unit=m). What is the best way to validate/parse this input?

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  • Remove parameter from link

    - by goordis
    I have many links with parameter number - value is numbers between 1-1000 http://mysite.com?one=2&two=4&number=2 http://mysite.com?one=2&two=4&four=4&number=124 http://mysite.com?one=2&three=4&number=9 http://mysite.com?two=4&number=242 http://mysite.com?one=2&two=4&number=52 How can i remove from this parameter and value with PHP? I would like receive: http://mysite.com?one=2&two=4 http://mysite.com?one=2&two=4&four=4 http://mysite.com?one=2&three=4 http://mysite.com?two=4 http://mysite.com?one=2&two=4

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  • MySql Not Like Regexp?

    - by KnockKnockWhosThere
    I'm trying to find rows where the first character is not a digit. I have this: SELECT DISTINCT(action) FROM actions WHERE qkey = 140 AND action NOT REGEXP '^[:digit:]$'; But, I'm not sure how to make sure it checks just the first character...

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  • Using regular expressions with Dojo data.fetch?

    - by Dfowj
    I'm trying to use the below code to fetch a regular expression like this /[computer]{3,8}/(what i think is any words containing the letters in computer ranging from 3 to 8 letters long) from a database (which i know is being loaded correctly). When i fetch, i get 10 results, all the same word... "Adenauer" var base = "computer"; var baseRE = '/[' + base + ']{' + this.minLength + ',' + base.length + '}/'; this.dict.fetch({query: {word:baseRE}, onComplete: onLoadWords, onError: function(err) { console.log(err); }}); Any ideas what im doing wrong?

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  • How can I test if an input field contains foreign characters?

    - by zeckdude
    I have an input field in a form. Upon pushing submit, I want to validate to make sure the user entered non-latin characters only, so any foreign language characters, like Chinese among many others. Or at the very least test to make sure it does not contain any latin characters. Could I use a regular expression for this? What would be the best approach for this? I am validating in both javaScript and in PHP. What solutions can I use to check for foreign characters in the input field in both programming languages?

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  • PHP: Is_numeric returns false on 0

    - by Industrial
    Hi everyone, Is_numeric() as well as is_int() returns false if the value is 0. What can i do instead to verify that a specific value is numbers only in PHP? Are we heading straight for the Regular Expressions camp, or are there some nice, handy feature for this out there already? Thanks!

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  • mine phrases (up to 3 words) from a given text

    - by DS_web_developer
    I asked before for a simple solution to my problem (using sphinx search service) but I got nowhere... someone has kindly provided me with this code <?php /** * $Project: GeoGraph $ * $Id$ * * GeoGraph geographic photo archive project * This file copyright (C) 2005 Barry Hunter ([email protected]) * * This program is free software; you can redistribute it and/or * modify it under the terms of the GNU General Public License * as published by the Free Software Foundation; either version 2 * of the License, or (at your option) any later version. * * This program is distributed in the hope that it will be useful, * but WITHOUT ANY WARRANTY; without even the implied warranty of * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the * GNU General Public License for more details. * * You should have received a copy of the GNU General Public License * along with this program; if not, write to the Free Software * Foundation, Inc., 59 Temple Place - Suite 330, Boston, MA 02111-1307, USA. */ /** * Provides the methods for updating the worknet tables * * @package Geograph * @author Barry Hunter <[email protected]> * @version $Revision$ */ function addTwoLetterPhrase($phrase) { global $w2; $w2[$phrase] = (isset($w2[$phrase]))?($w2[$phrase]+1):1; } function addThreeLetterPhrase($phrase) { global $w3; $w3[$phrase] = (isset($w3[$phrase]))?($w3[$phrase]+1):1; } function updateWordnet(&$db,$text,$field,$id) { global $w1,$w2,$w3; $alltext = strtolower(preg_replace('/\W+/',' ',str_replace("'",'',$text))); if (strlen($text)< 1) return; $words = preg_split('/ /',$alltext); $w1 = array(); $w2 = array(); $w3 = array(); //build a list of one word phrases foreach ($words as $word) { $w1[$word] = (isset($w1[$word]))?($w1[$word]+1):1; } //build a list of two word phrases $text = $alltext; $text = preg_replace('/(\w+) (\w+)/e','addTwoLetterPhrase("$1 $2")',$text); $text = $alltext; $text = preg_replace('/(\w+)/','',$text,1); $text = preg_replace('/(\w+) (\w+)/e','addTwoLetterPhrase("$1 $2")',$text); //build a list of three word phrases $text = $alltext; $text = preg_replace('/(\w+) (\w+) (\w+)/e','addThreeLetterPhrase("$1 $2 $3")',$text); $text = $alltext; $text = preg_replace('/(\w+)/','',$text,1); $text = preg_replace('/(\w+) (\w+) (\w+)/e','addThreeLetterPhrase("$1 $2 $3")',$text); $text = $alltext; $text = preg_replace('/(\w+) (\w+)/','',$text,1); $text = preg_replace('/(\w+) (\w+) (\w+)/e','addThreeLetterPhrase("$1 $2 $3")',$text); foreach ($w1 as $word=>$count) { $db->Execute("insert into wordnet1 set gid = $id,words = '$word',$field = $count");// ON DUPLICATE KEY UPDATE $field=$field+$count"); } foreach ($w2 as $word=>$count) { $db->Execute("insert into wordnet2 set gid = $id,words = '$word',$field = $count"); } foreach ($w3 as $word=>$count) { $db->Execute("insert into wordnet3 set gid = $id,words = '$word',$field = $count"); } } ?> It works fine and does almost exactly what I need....... except.... it is not utf8 friendly... I mean... it splits whole words into parts (on special chars) where it shouldn't! so my guess is I should use multibyte functions instead of regular preg_replace... I tried to replace preg_replace with mb_ereg_replace but it is not working as it should... at least not for 2 and 3 words phrases any ideas?

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  • Regular Expressions, avoiding HTML tags in PHP

    - by Jason Axelrod
    I have actually seen this question quite a bit here, but none of them are exactly what I want... Lets say I have the following phrase: Line 1 - This is a TEST phrase. Line 2 - This is a <img src="TEST" /> image. Line 3 - This is a <a href="somelink/TEST">TEST</a> link. Okay, simple right? I am trying the following code: $linkPin = '#(\b)TEST(\b)(?![^<]*>)#i'; $linkRpl = '$1<a href="newurl">TEST</a>$2'; $html = preg_replace($linkPin, $linkRpl, $html); As you can see, it takes the word TEST, and replaces it with a link to test. The regular expression I am using right now works good to avoid replacing the TEST in line 2, it also avoids replacing the TEST in the href of line 3. However, it still replaces the text encapsulated within the tag on line 3 and I end up with: Line 1 - This is a <a href="newurl">TEST</a> phrase. Line 2 - This is a <img src="TEST" /> image. Line 3 - This is a <a href="somelink/TEST"><a href="newurl">TEST</a></a> link. This I do not want as it creates bad code in line 3. I want to not only ignore matches inside of a tag, but also encapsulated by them. (remember to keep note of the / in line 2)

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  • How can I improve this regular expression?

    - by Michael Haren
    I want a regular expression to match valid input into a Tags input field with the following properties: 1-5 tags Each tag is 1-30 characters long Valid tag characters are [a-zA-Z0-9-] input and tags can be separated by any amount of whitespace Here's what I have so far--it seems to work but I'm interested how it could be simplified or if it has any major flaws: \s*[a-zA-Z0-9-]{1,30}(\s+[a-zA-Z0-9-]{1,30}){0,4}\s* // that is: \s* // match all beginning whitespace [a-zA-Z0-9-]{1,30} // match the first tag (\s+[a-zA-Z0-9-]{1,30}){0,4} // match all subsequent tags \s* // match all ending whitespace Preprocessing the input to make the whitespace issue easier isn't an option (e.g. trimming or adding a space). If it matters, this will be used in javascript. Any suggestions would be appreciated, thanks!

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  • Perl Matching ,Extracting , and printing emails

    - by user3448790
    How do I match an email using the The Official Standard: RFC 5322 in a html source code, after that i will extract the strings that are matched ONLY, and print out inly the emails, and not the whole source code? Is there any examples and output to illustrate this? Thnaks! elsif ($_ eq '-dDATA' or $_ eq '-ft') { opendir(DIR,'DATA'); my(@dir) = grep /\.htm/, readdir (DIR); closedir(DIR); my $value = join(@dir); print "$value\n"; foreach my $movies (@dir) { open (my $FHD, "<", "DATA/$movies") || die $!; print <$FHD>; } } }

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  • Regular Expression

    - by Blanca
    Hi! i would like to avoid texts like this one: height="49" with a regular expresion. I tought in .replaceAll("\s*="*"",""); (replaceAll is used as a method in a java class), but eclipse don't allowed me to do that. Any other suggestion?? tx!

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  • In Vim, how to swap 2 non adjacent patterns?

    - by ThG
    I have lines of text, all with the same structure, and would like to make a permutation of 2 elements on all lines: 1257654 some text (which may be long) #Foo 1543098 some other text #Barbar 1238769 whatever #Baz 2456874 something else #Quux I want to obtain : #Foo some text (which may be long) 1257654 #Barbar some other text 1543098 #Baz whatever 1238769 #Quux something else 2456874 This is where I am stuck : :%s/\(\d\{7\}\)\(#.\{-}\)/\2\1/ Where did I go wrong ?

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  • mod_rewrite rule for all urls except ones with some words

    - by zlog
    How do I write a mod_rewrite regulare expression rule that is the opposite of this: ^(.+)/path/(page1|page2)+$ ie, I want all pages except blah/path/page1 and blah/path/page2 to redirect to another path, where the x in blah/path/x is used in the new path. For example, I'd like write a rewrite rule like: RewriteRule some_regex /index.php?path/show/$1 [L] where some_regex would pull out the last component of a url in the format: /something/path/some_param to redirect to /index.php/path/show/some_param I'm trying to use ! and [^] syntax, but I don't quite understand how these work, especially when they involve words not single characters.

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