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  • Access denied when starting SQL Server Express from command line

    - by Brettski
    Windows 7 computer running SQL Server Express 2008 (sp1). When I try to run net start mssql$sqlexpress I receive an error: System error 5 has occurred. Access is denied The SQL service is running under "Network Service" account The service starts fine if I use the services window. Could somebody help me figure out why I am receiving this error?

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  • Reduce number of points in line

    - by culebrón
    I'm searching for algorithms to reduce the LOD of polylines, lines (looped or not) of nodes. In simple words, I want to take hi-resolution coastline data and be able to reduce its LOD hundred- or thousandfold to render it in small-scale. I found polygon reduction algorithms (but they require triangles) and Laplacian smoothing, but that doesn't seem exactly what I need.

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  • I need a simple command line program to transform XML using XSLT

    - by fuzzy lollipop
    I am on OSX Snow Leopard (10.6.2) I can install anything I need to. I would preferably like a Python or Java solution. I have searched on Google and found lots of information on writing my own program to do this, but this is a just a quick and dirty experiment so I don't want to invest a lot of time on writing a bunch of code to do this, I am sure someone else has done this already.

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  • Help Repainting a Line

    - by serhio
    I am doing a custom control (inherited from VisualBasic.PowerPacks.LineShape), that should be painted like as standard one, but also having a Icon displayed near it. So, I just overrided OnPaint like this: protected override void OnPaint(System.Windows.Forms.PaintEventArgs e) { e.Graphics.DrawIcon(myIcon, StartPoint.X, StartPoint.Y); base.OnPaint(e); } Now, everything is OK, but when my control moves, the icon still remains drawn on the ancient place. Is there a way to paint it properly? The sample code for tests using Microsoft.VisualBasic.PowerPacks; using System.Windows.Forms; using System.Drawing; namespace LineShapeTest { /// /// Test Form /// public class Form1 : Form { IconLineShape myLine = new IconLineShape(); ShapeContainer shapeContainer1 = new ShapeContainer(); Panel panel1 = new Panel(); public Form1() { this.panel1.Dock = DockStyle.Fill; // load your back image here this.panel1.BackgroundImage = global::WindowsApplication22.Properties.Resources._13820t; this.panel1.Controls.Add(shapeContainer1); this.myLine.StartPoint = new Point(20, 30); this.myLine.EndPoint = new Point(80, 120); this.myLine.Parent = this.shapeContainer1; MouseEventHandler panelMouseMove = new MouseEventHandler(this.panel1_MouseMove); this.panel1.MouseMove += panelMouseMove; this.shapeContainer1.MouseMove += panelMouseMove; this.Controls.Add(panel1); } private void panel1_MouseMove(object sender, MouseEventArgs e) { if (e.Button == MouseButtons.Left) { myLine.StartPoint = e.Location; } } } /// /// Test LineShape /// public class IconLineShape : LineShape { Icon myIcon = SystemIcons.Exclamation; protected override void OnPaint(System.Windows.Forms.PaintEventArgs e) { e.Graphics.DrawIcon(myIcon, StartPoint.X, StartPoint.Y); base.OnPaint(e); } } } Nota Bene, for the lineShape: Parent = ShapeContainer Parent.Parent = Panel Update 1 TRACES In this variant of OnPaint, we have traces: protected override void OnPaint(System.Windows.Forms.PaintEventArgs e) { Graphics g = Parent.Parent.CreateGraphics(); g.DrawIcon(myIcon, StartPoint.X, StartPoint.Y); base.OnPaint(e); } Update 2 BLINKS In this variant of OnPaint, we have a blinking image: protected override void OnPaint(System.Windows.Forms.PaintEventArgs e) { Parent.Parent.Invalidate(this.Region, true); Graphics g = Parent.Parent.CreateGraphics(); g.DrawIcon(myIcon, StartPoint.X, StartPoint.Y); base.OnPaint(e); } Update 3: External Invalidation This variant works well, but... from exterior of IconLineShape class: private void panel1_MouseMove(object sender, MouseEventArgs e) { if (e.Button == MouseButtons.Left) { Region r = myLine.Region; myLine.StartPoint = e.Location; panel1.Invalidate(r); } } /// /// Test LineShape /// public class IconLineShape : LineShape { Icon myIcon = SystemIcons.Exclamation; Graphics parentGraphics; protected override void OnPaint(System.Windows.Forms.PaintEventArgs e) { parentGraphics.DrawIcon(myIcon, StartPoint.X, StartPoint.Y); base.OnPaint(e); } protected override void OnParentChanged(System.EventArgs e) { // Parent is a ShapeContainer // Parent.Parent is a Panel parentGraphics = Parent.Parent.CreateGraphics(); base.OnParentChanged(e); } } Even this resolves the problem of the test example, I need this control to be done inside the control, because I can't force the external "clients" of this control do not forget to save the old region and invalidate the parent each time changing a location...

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  • Access denied when starting sqlexpress from command line

    - by Brettski
    Windows 7 computer running SQL Server Express 2008 (sp1). When I try to run net start mssql$sqlexpress I receive an error: System error 5 has occurred. Access is denied The SQL service is running under "Network Service" account The service starts fine if I use the services window. Could somebody help me figure out why I am receiving this error?

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  • Initialization of an ArrayList in one line.

    - by Macarse
    I am willing to create a list of options to test something. I was doing: ArrayList<String> places = new ArrayList<String>(); places.add("Buenos Aires"); places.add("Córdoba"); places.add("La Plata"); I refactor the code doing: ArrayList<String> places = new ArrayList<String>(Arrays.asList("Buenos Aires", "Córdoba", "La Plata")); Is there a better way of doing this? Thanks for reading!

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  • WPF how to see last added text line in TexBox

    - by Janus
    I would like simmulate Console text output in my WPF app but when I add new lines in TextBox I should use scroll bar to see last added text but I want to see last added text but for firsts lines use scroll bar <TextBox TextWrapping="Wrap" AcceptsReturn="True" VerticalScrollBarVisibility="Auto" Text="{Binding Path=Data, Mode=TwoWay}" />`

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  • launching java test bycommand line

    - by lamisse
    I created runner.bat to launch one java test it contains : path to java,classpath org.junit.runner.JUnitCore package.class when I launch it : FAILURES Tests run: 1, Failures: 1 Exception in thread "Thread-0" java.lang.IllegalStateException: Shutdown in progress at java.lang.ApplicationShutdownHooks.add(Unknown Source) at java.lang.Runtime.addShutdownHook(Unknown Source) at com.sun.imageio.stream.StreamCloser$2.run(Unknown Source) at java.security.AccessController.doPrivileged(Native Method) at com.sun.imageio.stream.StreamCloser.addToQueue(Unknown Source) at javax.imageio.stream.FileCacheImageInputStream.<init>(Unknown Source) at com.sun.imageio.spi.InputStreamImageInputStreamSpi.createInputStreamInstance(Unknown Source) at javax.imageio.ImageIO.createImageInputStream(Unknown Source) at javax.imageio.ImageIO.read(Unknown Source) at com.polyspace.util.guicomponent.CompositePanel.setBufferedImage(Unknown Source) at com.polyspace.util.guicomponent.CompositePanel.<init>(Unknown Source)

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  • How do I use a command line tool to install .net 4 to IIS

    - by tehp
    I'm trying to deploy my WCF RIA services application to our in-house server for testing. I've been following the instructions and comments from this blog site: http://timheuer.com/blog/archive/2009/12/10/tips-to-deploy-ria-services-troubleshoot.aspx At the end someone points to this question: http://stackoverflow.com/questions/1528324/how-to-solve-a-http-error-404-3-not-found-error I've been trying to run that same tool with .net 4.0 but it keeps giving me an error: [Warning]The HTTP namespace reservation already exists. I am running the version of the exe that I found inside of C:\Windows\Microsoft.NET\Framework\v4.0.21006 There is also C:\Windows\Microsoft.NET\Framework\v3.0\Windows Communication Foundation that has (what I assume is) the same exe in it, and I can use it just fine. I've tried to un-install the 3.0 version before installing the 4.0 version, but I am still getting the same warning and failure. Has anyone successfully done this with .net 4.0?

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  • php - regex- preg_replace - space after line-break!

    - by aSeptik
    Hi all guys! still on regex! i want learn it but i'm still crashing the head into my keybord! ;-) ok very trivial for you, i'm sure! Assuming i have this sting, the \s is where the space actualy is... \n where linebreak is.. DESCRIPTION: The quick brown fox jum`\s\n` `\s`ps over the lazy dog now, what i need to do is remove All the space after the A-Z: that i have achieved by this regex: /\s+(?![A-Z:])/m that produce this result DESCRIPTION: The quick brown fox jum ps over the lazy dog as you can see it leave the space between jum and ps how to have a result like this? DESCRIPTION: The quick brown fox jumps over the lazy dog thank's for the time!

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  • using in-line asm to write a for loop with 2 comparisons

    - by aCuria
    I want to convert the for loop in the following code into assembly but i am not sure how to start. An explanation of how to do it and why it works would be appreciated. I am using VS2010, C++, writing for the x86. The code is as follows: for (n = 0; norm2 < 4.0 && n < N; ++n) { __asm{ ///a*a - b*b + x fld a // a fmul st(0), st(0) // aa fld b // b aa fmul st(0), st(0) // bb aa fsub // (aa-bb) // st(0) - st(1) fld x // x (aa-bb) fadd // (aa-bb+x) /// 2.0*a*b + y; fld d // d (aa-bb+x) fld a // d a (aa-bb+x) fmul // ad (aa-bb+x) fld b // b ad (aa-bb+x) fmul // abd (aa-bb+x) fld y // y adb (aa-bb+x) fadd // b:(adb+y) a:(aa-bb+x) fld st(0) //b b:(adb+y) a:(aa-bb+x) fmul st(0), st(0) // bb b:(adb+y) a:(aa-bb+x) fld st(2) // a bb b:(adb+y) a:(aa-bb+x) fmul st(0), st(0) // aa bb b:(adb+y) a:(aa-bb+x) fadd // aa+bb b:(adb+y) a:(aa-bb+x) fstp norm2 // store aa+bb to norm2, st(0) is popped. fstp b fstp a } }

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  • php simplexmlelement get first element in one line

    - by Senica Gonzalez
    Just trying to figure a shorter way to do this: I'm using simpleXMLElement to parse an xml file and it's aggravating to have to call two lines to process an array when I know what node I want. Current code: $xml = new SimpleXMLElement($data); $r = $xml->xpath('///givexNumber'); $result["cardNum"] = $r[0]; What I would like to do would be something like I can do with DomX $result["cardNum"] = $xml->xpath('///givexNumber')->item(0)->nodeValue; Any ideas? I didn't really see that simplexmlelement can do this, but thought someone might know a trick or two.

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  • CSS line wrapping

    - by Mic
    Given a block container <div> this is a very long string which contains a bunch of characters that I want to break at container edges. </div> are there any css properties I can set to force it to break when it reaches the container width, regardless of the contents of the string, for example a break like: this is a ve ry long stri ng which ... is pretty much what I want. Right now, it seems to always prefer to break at whitespace characters or other special characters (such as /).

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  • Python beginner confused by a complex line of code

    - by Protean
    I understand the gist of the code, that it forms permutations; however, I was wondering if someone could explain exactly what is going on in the return statement. def perm(l): sz = len(l) print (l) if sz <= 1: print ('sz <= 1') return [l] return [p[:i]+[l[0]]+p[i:] for i in range(sz) for p in perm(l[1:])]

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  • Ruby - calling constructor without arguments & removal of new line characters

    - by Raj
    I am a newbie at Ruby, I have written down a sample program. I dont understand the following: Why constructor without any arguments are not called in Ruby? How do we access the class variable outside the class' definition? Why does it always append newline characters at the end of the string? How do we strip it? Code: class Employee attr_reader :empid attr_writer :empid attr_writer :name def name return @name.upcase end attr_accessor :salary @@employeeCount = 0 def initiaze() @@employeeCount += 1 puts ("Initialize called!") end def getCount return @@employeeCount end end anEmp = Employee.new print ("Enter new employee name: ") anEmp.name = gets() print ("Enter #{anEmp.name}'s employee ID: ") anEmp.empid = gets() print ("Enter salary for #{anEmp.name}: ") anEmp.salary = gets() theEmpName = anEmp.name.split.join("\n") theEmpID = anEmp.empid.split.join("\n") theEmpSalary = anEmp.salary.split.join("\n") anEmp = Employee.new() anEmp = Employee.new() theCount = anEmp.getCount puts ("New employee #{theEmpName} with employee ID #{theEmpID} has been enrolled, welcome to hell! You have been paid as low as $ #{theEmpSalary}") puts ("Total number of employees created = #{theCount}") Output: Enter new employee name: Lionel Messi Enter LIONEL MESSI 's employee ID: 10 Enter salary for LIONEL MESSI : 10000000 New employee LIONEL MESSI with employee ID 10 has been enrolled, welcome to hell! You have been paid as low as $ 10000000 Total number of employees created = 0 Thanks

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  • How to read line in CLIPS?

    - by daniels
    I need to read a string in CLIPS so i'm usign (readline) but it doesn't seem to work. It doesn't let me enter anything and it just returns "". Any ideea what's the issue? CLIPS> (readline) "" I'm using latest version of http://clipsrules.sourceforge.net/

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  • how to run line by line in text file - on windows mobile ?

    - by Gold
    hi in WinForm on PC i use to run like this: FileStream FS = null; StreamWriter SW = null; FS = new FileStream(@"\Items.txt", FileMode.Create, FileAccess.ReadWrite, FileShare.ReadWrite); SW = new StreamWriter(FS, Encoding.Default); while (SW.Peek() != -1) { TEMP = (SW.ReadLine()); } but when i try this on Windows-mobile i get error: Error 1 'System.IO.StreamWriter' does not contain a definition for 'Peek' and no extension method 'Peek' accepting a first argument of type 'System.IO.StreamWriter' could be found (are you missing a using directive or an assembly reference?) Error 2 'System.IO.StreamWriter' does not contain a definition for 'ReadLine' and no extension method 'ReadLine' accepting a first argument of type 'System.IO.StreamWriter' could be found (are you missing a using directive or an assembly reference?) how to do it ? thanks

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  • Creating a simple command line interface (CLI) using a python server (TCP sock) and few scripts

    - by VN44CA
    I have a Linux box and I want to be able to telnet into it (port 77557) and run few required commands without having to access to the whole Linux box. So, I have a server listening on that port, and echos the entered command on the screen. (for now) Telnet 192.168.1.100 77557 Trying 192.168.1.100... Connected to 192.168.1.100. Escape character is '^]'. hello<br /> You typed: "hello"<br /> NOW: I want to create lot of commands that each take some args and have error codes. Anyone has done this before? It would be great if I can have the server upon initialization go through each directory and execute the init.py file and in turn, the init.py file of each command call into a main template lib API (e.g. RegisterMe()) and register themselves with the server as function call backs. At least this is how I would do it in C/C++. But I want the best Pythonic way of doing this. /cmd/ /cmd/myreboot/ /cmd/myreboot/ini.py (note underscore don't show for some reason) /cmd/mylist/ /cmd/mylist/init.py ... etc IN: /cmd/myreboot/_ini_.py: from myMainCommand import RegisterMe RegisterMe(name="reboot",args=Arglist, usage="Use this to reboot the box", desc="blabla") So, repeating this creates a list of commands and when you enter the command in the telnet session, then the server goes through the list, matches the command and passed the args to that command and the command does the job and print the success or failure to stdout. Thx

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  • Multi-line regex support in Vim

    - by Daniel
    I notice the standard regex syntax for matching across multiple lines is to use /s, like so: This is\nsome text /This.*text/s This works in Perl for instance but doesn't seem to be supported in Vim. Instead, I have to be much more specific: /This[^\r\n]*[\r\n]*text/ I can't find any reason for why this should be, so I'm thinking I probably just missed the relevant bits in the vim help. Can anyone confirm this behaviour one way or the other?

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  • Apply PHP regex replace on a multi-line repeted pattern

    - by Hussain
    Let's say I have this input: I can haz a listz0rs! # 42 # 126 I can haz another list plox? # Hello, world! # Welcome! I want to split it so that each set of hash-started lines becomes a list: I can haz a listz0rs! <ul> <li>42</li> <li>126</li> </ul> I can haz another list plox? <ul> <li>Hello, world!</li> <li>Welcome!</li> </ul> If I run the input against the regex "/(?:(?:(?<=^# )(.*)$)+)/m", I get the following result: Array ( [0] => Array ( [0] => 42 ) Array ( [0] => 126 ) Array ( [0] => Hello, world! ) Array ( [0] => Welcome! ) ) This is fine and dandy, but it doesn't distinguish between the two different lists. I need a way to either make the quantifier return a concatenated string of all the occurrences, or, ideally, an array of all the occurrences. Idealy, this should be my output: Array ( [0] = Array ( [0] = 42 [1] = 126 ) Array ( [0] = Hello, world! [1] = Welcome! ) ) Is there any way of achieving this, and if not, is there a close alternative? Thanks in advance!

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  • Writing a new line to file in PHP

    - by James P
    My code: $i = 0; $file = fopen('ids.txt', 'w'); foreach ($gemList as $gem) { fwrite($file, $gem->getAttribute('id') . '\n'); $gemIDs[$i] = $gem->getAttribute('id'); $i++; } fclose($file); For some reason, it's writing \n as a string, so the file looks like this: 40119\n40122\n40120\n42155\n36925\n45881\n42145\n45880 From Google'ing it tells me to use \r\n, but \r is a carriage return which doesn't seem to be what I want to do. I just want the file to look like this: 40119 40122 40120 42155 36925 45881 42145 45880 Thanks.

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