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  • Question about Linux Device Drivers.

    - by smwikipedia
    I have just installed the Xubuntu. My box runs quite slower than before when installed with a Win7. I am wondering if I am missing some device drivers. I can use gnome-device-manager to list my devices. In the device list view, I saw several blue question mark on the left side of devices. Based on my windows experience, the question mark should indicate the device is not properly configured. Is it the same with gnome-device-manager? And most importantly, how could I know for sure whether or not the corresponding device drivers have been installed? Many thanks.

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  • printing uid of a file on linux system

    - by neo730
    i am learning c programming. I am trying to make my own program similar to ls command but with less options.what i am doing is taking input directory/file name as argument and then gets all directory entry with dirent struct(if it is directory) . After it i use stat() to take all information of the file but here is my problem when i use write() to print these value its fine but when i want to print these with printf() i get warninng : format ‘%ld’ expects type ‘long int’, but argument 2 has type ‘__uid_t’. I don't know what should use at place of %ld and also for other special data types.

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  • Compiling Objective-C project on Linux (Ubuntu)

    - by Alex
    How to make an Objective-C project work on Ubuntu? My files are: Fraction.h #import <Foundation/NSObject.h> @interface Fraction: NSObject { int numerator; int denominator; } -(void) print; -(void) setNumerator: (int) n; -(void) setDenominator: (int) d; -(int) numerator; -(int) denominator; @end Fraction.m #import "Fraction.h" #import <stdio.h> @implementation Fraction -(void) print { printf( "%i/%i", numerator, denominator ); } -(void) setNumerator: (int) n { numerator = n; } -(void) setDenominator: (int) d { denominator = d; } -(int) denominator { return denominator; } -(int) numerator { return numerator; } @end main.m #import <stdio.h> #import "Fraction.h" int main( int argc, const char *argv[] ) { // create a new instance Fraction *frac = [[Fraction alloc] init]; // set the values [frac setNumerator: 1]; [frac setDenominator: 3]; // print it printf( "The fraction is: " ); [frac print]; printf( "\n" ); // free memory [frac release]; return 0; } I've tried two approaches to compile it: Pure gcc: $ sudo apt-get install gobjc gnustep gnustep-devel $ gcc `gnustep-config --objc-flags` -o main main.m -lobjc -lgnustep-base /tmp/ccIQKhfH.o:(.data.rel+0x0): undefined reference to `__objc_class_name_Fraction' I created a GNUmakefile Makefile: include ${GNUSTEP_MAKEFILES}/common.make TOOL_NAME = main main_OBJC_FILES = main.m include ${GNUSTEP_MAKEFILES}/tool.make ... and ran: $ source /usr/share/GNUstep/Makefiles/GNUstep.sh $ make Making all for tool main... Linking tool main ... ./obj/main.o:(.data.rel+0x0): undefined reference to `__objc_class_name_Fraction' So in both cases compiler gets stuck at undefined reference to `__objc_class_name_Fraction' Do you have and idea how to resolve this issue?

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  • Shipping GNU/Linux Firefox plugin with shared libraries (for installation with no root access)

    - by Vi
    The application is a Firefox plugin (loaded from $HOME/.mozilla/plugins), so wrapper script that sets LD_LIBRARY_PATH is not an easy option. RPATH, as far as I know, cannot refer to $HOME and can be only absolue path. Firefox tries to dlopen it's plugin from ~/.mozilla/plugins but fails (because it depends on shared libraries installed somewhere in the user home directory). Modifying Firefox menu item to provide a wrapper (with LD_LIBRARY_PATH) around Firefox is too hacky. What should installer script do (without root access) to make standard firefox load plug-ins that depends on out shared library? Should I just try to make embed everything into that .so to remove dependencies? Should I try to make installer script to finish linking or patch RPATH during the installation phase?

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  • Finding File WIth Fixed File Size (>0) in Unix/Linux

    - by neversaint
    I have a list of file that looks like this 4 -rw-r--r-- 1 neversaint hgc0746 53 May 1 10:37 SRX016372-SRR037477.est_count 4 -rw-r--r-- 1 neversaint hgc0746 53 May 1 10:34 SRX016372-SRR037478.est_count 4 -rw-r--r-- 1 neversaint hgc0746 53 May 1 10:41 SRX016372-SRR037479.est_count 0 -rw-r--r-- 1 neversaint hgc0746 0 Apr 27 11:16 SRX003838-SRR015096.est_count 0 -rw-r--r-- 1 neversaint hgc0746 0 Apr 27 11:32 SRX004765-SRR016565.est_count What I want to do is to find files that has exactly size 53. But why this command failed? $ find . -name "*.est_count" -size 53 -print It works well though if I just want to find file of size 0 with this command: $ find . -name "*.est_count" -size 0 -print

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  • Upgrading PHP 5.1 to 5.3 on Linux Server

    - by nicorellius
    I trying to find the best way to upgrade from PHP 5.1 to 5.3. The CRM software I am running on this server requires this upgrade or else I probably wouldn't even perform it, because it seems like it's going to be perhaps trickier than I hoped it would be. Being still new to the programming world, these routine upgrades are still worrisome to me. I am running apache 2.2.6 (Fedora), PHP 5.1.6 and MySQL 5.0.27 on this server.

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  • linux + find word in file under directory but quickly

    - by yael
    I have the following command find /var -type f -exec grep "param1" {} \; -print With this command I can find the param1 string in any file under /var but the time that it take for this is very long. I need other possibility to find string in file but much more faster then my example THX yael

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  • Unescpaing huge single-line string on Linux

    - by Lajos Nagy
    I ended up with a huge, single line string literal (don't ask me how) where everything is escaped (mostly), including new lines and double quotes. Problem is, I want the original string. The string is huge so I'm not even sure how to begin. Here's what I have: "This\n is \"nice\",\nain\'t it?" This is what I want: This is "nice", ain't it? Again, the problem is that other shell sensitive stuff is not escaped (like $, or !), and that the string is couple of megabytes.

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  • Receving multiple multicast feeds on the same port - C, Linux

    - by Gigi
    I have an application that is receiving data from multiple multicast sources on the same port. I am able to receive the data. However, I am trying to account for statistics of each group (i.e. msgs received, bytes received) and all the data is getting mixed up. Does anyone know how to solved this problem? If I try to look at the sender's address, it is not the multicast address, but rather the IP of the sending machine. I am using the following socket options: struct ip_mreq mreq; mreq.imr_multiaddr.s_addr = inet_addr("224.1.2.3"); mreq.imr_interface.s_addr = INADDR_ANY; setsockopt(s, IPPROTO_IP, IP_ADD_MEMBERSHIP, &mreq, sizeof(mreq)); and also: setsockopt(s, SOL_SOCKET, SO_REUSEPORT, &reuse, sizeof(reuse)); I appreciate any help!!!

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  • linux piping ( convert -> pdf2ps -> lp)

    - by Bor
    Ok, so I can print a pdf doing: pdf2ps file.pdf - | lp -s But now I want to use convert to merge several pdf files, I can do this with: convert file1.pdf file2.pdf merged.pdf which merges file1.pdf and file2.pdf into merged.pdf, target can be replaced with '-'. Question How could I pipe convert into pdf2ps and then into lp though?

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  • How to detect pending system shutdown on Linux?

    - by Rajorshi
    Hi, I am working on an app where I need to detect system shutdown. However, I have not found any reliable way get a notification on this event. I know that on shutdown, my app will receive a SIGTERM signal followed by a SIGKILL. What I want to know is if there is someway to query if a SIGTERM is part of a shutdown sequence? Does any one know if there is a way to query that programmatically (C API)? As far as I know, the system does not provide any other method to query for an impending shutdowm. If it does, that would solve my problem as well. I have been trying out runlevels as well, but change in runlevels seem to be instantaneous and without any prior warnings.

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  • Eclipse And Linux: Keyboard unusable after gnome-screen-saver

    - by Martijn Courteaux
    Hi, I know this is not programming related. But I can't find any topics on Google or UbuntuForums. So the problem is: When gnome-screensaver starts on the moment Eclipse has the focus and I wake up again my laptop, Eclipse doesn't listen to keyboard-events. To solve this I have to change the focus to another program and then back to Eclipse. Than it works again. This isn't a real problem, but it would be nice if someone can solve it. Thanks

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  • Doubt regarding executable files in linux

    - by Chaitanya
    I have a program written in C, which is named computeWeight.c and to compile it i use the following code chaitu@ubuntu:~$ gcc -Wall -o computeWeight computeWeight.c //to execute it: chaitu@ubuntu:~$ ./computeWeight Do i have any mechansim where i can directly use as mentioned below, chaitu@ubuntu:~$ computeWeight Should i be changing any permissions on the executable to get this?

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  • What does the "build-essential" Terminal command mean & do in Linux based operating systems like Ubu

    - by Adam Siddhi
    Hi. I am researching how to install Ruby 1.9.1 in Xubuntu 10.04 and I came across the command build-essential multiple times. Sometimes it is followed by packages and sometimes it is both preceded and post-ceded by packages. The 2 examples I am looking at are: sudo apt-get install build-essential zlib1g zlib1g-dev zlibc libruby1.9 libxml2 libxml2-dev libxslt-dev and sudo apt-get install ruby irb ri rdoc ruby1.8-dev libzlib-ruby libyaml-ruby libreadline-ruby libncurses-ruby libcurses-ruby libruby libruby-extras libfcgi-ruby1.8 build-essential libopenssl-ruby libdbm-ruby libdbi-ruby libdbd-sqlite3-ruby sqlite3 libsqlite3-dev libsqlite3-ruby libxml-ruby libxml2-dev Thanks :adam

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  • escape from a linux cli for loop

    - by aidan
    I'm doing something like this: for f in `find -iname '*.html'`; do scp $f remoteserver:$f; done; I've got through about 3 of the 1000 files and I've decided I want to abort the operation. CTRL+C only escapes the SCP login prompt and takes me to the next one, rather than escaping the for loop. Is there a better way than hitting CTRL+C 9997 times? Thanks!

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  • find command in Linux

    - by Martin
    My goal is to find all pdf files on a remote machine, so I resort to the useless command find. So I type find . *.pdf or find ~ .pdf or find ~ ".pdf" and I get nothing. I do the same on my machine and I get nothing. I do a regular search from the menu on my machine and I find quite a few pdf files. Would somebody please tell me what am I doing wrong?

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  • Linux issues on setting a timer function

    - by laura
    I am creating a process with 2 children, 1 of the children is responsible to read questions (line by line from a file), output every question and reading the answer, and the other one is responsable to measure the time elapsed and notify the user at each past 1 minute about the remaining time. My problem is that i couldn't find any useful example of how i can make this set time function to work. Here is what i have tried so far. The problem is that it outputs the same elapsed time every time and never gets out from the loop. #include<time.h> #define T 600000 int main(){ clock_t start, end; double elapsed; start = clock(); end = start + T; while(clock() < end){ elapsed = (double) (end - clock()) / CLOCKS_PER_SEC; printf("you have %f seconds left\n", elapsed); sleep(60); } return 0; }

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  • one two-directed tcp socket OR two one-directed? (linux, high volume, low latency)

    - by osgx
    Hello I need to send (interchange) a high volume of data periodically with the lowest possible latency between 2 machines. The network is rather fast (e.g. 1Gbit or even 2G+). Os is linux. Is it be faster with using 1 tcp socket (for send and recv) or with using 2 uni-directed tcp sockets? The test for this task is very like NetPIPE network benchmark - measure latency and bandwidth for sizes from 2^1 up to 2^13 bytes, each size sent and received 3 times at least (in teal task the number of sends is greater. both processes will be sending and receiving, like ping-pong maybe). The benefit of 2 uni-directed connections come from linux: http://lxr.linux.no/linux+v2.6.18/net/ipv4/tcp_input.c#L3847 3847/* 3848 * TCP receive function for the ESTABLISHED state. 3849 * 3850 * It is split into a fast path and a slow path. The fast path is 3851 * disabled when: ... 3859 * - Data is sent in both directions. Fast path only supports pure senders 3860 * or pure receivers (this means either the sequence number or the ack 3861 * value must stay constant) ... 3863 * 3864 * When these conditions are not satisfied it drops into a standard 3865 * receive procedure patterned after RFC793 to handle all cases. 3866 * The first three cases are guaranteed by proper pred_flags setting, 3867 * the rest is checked inline. Fast processing is turned on in 3868 * tcp_data_queue when everything is OK. All other conditions for disabling fast path is false. And only not-unidirected socket stops kernel from fastpath in receive

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  • one two-directed tcp socket of two one-directed? (linux, high volume, low latency)

    - by osgx
    Hello I need to send (interchange) a high volume of data periodically with the lowest possible latency between 2 machines. The network is rather fast (e.g. 1Gbit or even 2G+). Os is linux. Is it be faster with using 1 tcp socket (for send and recv) or with using 2 uni-directed tcp sockets? The test for this task is very like NetPIPE network benchmark - measure latency and bandwidth for sizes from 2^1 up to 2^13 bytes, each size sent and received 3 times at least (in teal task the number of sends is greater. both processes will be sending and receiving, like ping-pong maybe). The benefit of 2 uni-directed connections come from linux: http://lxr.linux.no/linux+v2.6.18/net/ipv4/tcp_input.c#L3847 3847/* 3848 * TCP receive function for the ESTABLISHED state. 3849 * 3850 * It is split into a fast path and a slow path. The fast path is 3851 * disabled when: ... 3859 * - Data is sent in both directions. Fast path only supports pure senders 3860 * or pure receivers (this means either the sequence number or the ack 3861 * value must stay constant) ... 3863 * 3864 * When these conditions are not satisfied it drops into a standard 3865 * receive procedure patterned after RFC793 to handle all cases. 3866 * The first three cases are guaranteed by proper pred_flags setting, 3867 * the rest is checked inline. Fast processing is turned on in 3868 * tcp_data_queue when everything is OK. All other conditions for disabling fast path is false. And only not-unidirected socket stops kernel from fastpath in receive

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  • How to get total cpu usage in Linux (c++)

    - by cz-david
    I am trying to get total cpu usage in %. First I should start by saying that "top" will simply not do, as there is a delay between cpu dumps, it requires 2 dumps and several seconds, which hangs my program (I do not want to give it its own thread) next thing what I tried is "ps" which is instant but always gives very high number in total (20+) and when I actually got my cpu to do something it stayed at about 20... Is there any other way that I could get total cpu usage? It does not matter if it is over one second or longer periods of time... Longer periods would be more useful, though.

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