Search Results

Search found 4490 results on 180 pages for 'binary trees'.

Page 16/180 | < Previous Page | 12 13 14 15 16 17 18 19 20 21 22 23  | Next Page >

  • Can a binary tree or tree be always represented in a Database as 1 table and self-referencing?

    - by Jian Lin
    I didn't feel this rule before, but it seems that a binary tree or any tree (each node can have many children but children cannot point back to any parent), then this data structure can be represented as 1 table in a database, with each row having an ID for itself and a parentID that points back to the parent node. That is in fact the classical Employee - Manager diagram: one boss can have many people under him... and each person can have n people under him, etc. This is a tree structure and is represented in database books as a common example as a single table Employee.

    Read the article

  • Can a binary tree or tree be always represented in a Database table as 1 table and self-referencing?

    - by Jian Lin
    I didn't feel this rule before, but it seems that a binary tree or any tree (each node can have many children but children cannot point back to any parent), then this data structure can be represented as 1 table in a database, with each row having an ID for itself and a parentID that points back to the parent node. That is in fact the classical Employee - Manager diagram: one boss can have many people under him... and each person under him can have n people under him, etc. This is a tree structure and is represented in database books as a common example as a single table Employee.

    Read the article

  • Implementation of a distance matrix of a binary tree that is given in the adjacency-list representation

    - by Denise Giubilei
    Given this problem I need an O(n²) implementation of this algorithm: "Let v be an arbitrary leaf in a binary tree T, and w be the only vertex connected to v. If we remove v, we are left with a smaller tree T'. The distance between v and any vertex u in T' is 1 plus the distance between w and u." This is a problem and solution of a Manber's exercise (Exercise 5.12 from U. Manber, Algorithms: A Creative Approach, Addison-Wesley (1989).). The thing is that I can't deal properly with the adjacency-list representation so that the implementation of this algorithm results in a real O(n²) complexity. Any ideas of how the implementation should be? Thanks.

    Read the article

  • Any efficient way to read datas from large binary file?

    - by limi
    Hi, I need to handle tens of Gigabytes data in one binary file. Each record in the data file is variable length. So the file is like: <len1><data1><len2><data2>..........<lenN><dataN> The data contains integer, pointer, double value and so on. I found python can not even handle this situation. There is no problem if I read the whole file in memory. It's fast. But it seems the struct package is not good at performance. It almost stuck on unpack the bytes. Any help is appreciated. Thanks.

    Read the article

  • Is there something special about the number 65535?

    - by Nick Rosencrantz
    2¹6-1 & 25 = 25 (or? obviously ?) A developer asked me today what is bitwise 65535 & 32 i.e. 2¹6-1 & 25 = ? I thought at first spontaneously 32 but it seemed to easy whereupon I thought for several minutes and then answered 32. 32 seems to have been the correct answer but how? 65535=2¹6-1=1111111111111111 (but it doesn't seem right since this binary number all ones should be -1(?)), 32 = 100000 but I could not convert that in my head whereupon I anyway answered 32 since I had to answer something. Is the answer 32 in fact trivial? Is in the same way 2¹6-1 & 25-1 =31? Why did the developer ask me about exactly 65535? Binary what I was asked to evaluate was 1111111111111111 & 100000 but I don't understand why 1111111111111111 is not -1. Shouldn't it be -1? Is 65535 a number that gives overflow and how do I know that?

    Read the article

  • Design suggestion for expression tree evaluation with time-series data

    - by Lirik
    I have a (C#) genetic program that uses financial time-series data and it's currently working but I want to re-design the architecture to be more robust. My main goals are: sequentially present the time-series data to the expression trees. allow expression trees to access previous data rows when needed. to optimize performance of the data access while evaluating the expression trees. keep a common interface so various types of data can be used. Here are the possible approaches I've thought about: I can evaluate the expression tree by passing in a data row into the root node and let each child node use the same data row. I can evaluate the expression tree by passing in the data row index and letting each node get the data row from a shared DataSet (currently I'm passing the row index and going to multiple synchronized arrays to get the data). Hybrid: an immutable data set is accessible by all of the expression trees and each expression tree is evaluated by passing in a data row. The benefit of the first approach is that the data row is being passed into the expression tree and there is no further query done on the data set (which should increase performance in a multithreaded environment). The drawback is that the expression tree does not have access to the rest of the data (in case some of the functions need to do calculations using previous data rows). The benefit of the second approach is that the expression trees can access any data up to the latest data row, but unless I specify what that row is, I'll have to iterate through the rows and figure out which one is the last one. The benefit of the hybrid is that it should generally perform better and still provide access to the earlier data. It supports two basic "views" of data: the latest row and the previous rows. Do you guys know of any design patterns or do you have any tips that can help me build this type of system? Should I use a DataSet to hold and present the data, or are there more efficient ways to present rows of data while maintaining a simple interface? FYI: All of my code is written in C#.

    Read the article

  • How do I remove the leaves of a binary tree?

    - by flopex
    I'm trying to remove all of the leaves. I know that leaves have no children, this is what I have so far. public void removeLeaves(BinaryTree n){ if (n.left == null && n.right == null){ n = null; } if (n.left != null) removeLeaves(n.left); if (n.right != null) removeLeaves(n.right); }

    Read the article

  • Why is this attempt at a binary search crashing?

    - by Ian Campbell
    I am fairly new to the concept of a binary search, and am trying to write a program that does this in Java for personal practice. I understand the concept of this well, but my code is not working. There is a run-time exception happening in my code that just caused Eclipse, and then my computer, to crash... there are no compile-time errors here though. Here is what I have so far: public class BinarySearch { // instance variables int[] arr; int iterations; // constructor public BinarySearch(int[] arr) { this.arr = arr; iterations = 0; } // instance method public int findTarget(int targ, int[] sorted) { int firstIndex = 1; int lastIndex = sorted.length; int middleIndex = (firstIndex + lastIndex) / 2; int result = sorted[middleIndex - 1]; while(result != targ) { if(result > targ) { firstIndex = middleIndex + 1; middleIndex = (firstIndex + lastIndex) / 2; result = sorted[middleIndex - 1]; iterations++; } else { lastIndex = middleIndex + 1; middleIndex = (firstIndex + lastIndex) / 2; result = sorted[middleIndex - 1]; iterations++; } } return result; } // main method public static void main(String[] args) { int[] sortedArr = new int[] { 1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29 }; BinarySearch obj = new BinarySearch(sortedArr); int target = sortedArr[8]; int result = obj.findTarget(target, sortedArr); System.out.println("The original target was -- " + target + ".\n" + "The result found was -- " + result + ".\n" + "This took " + obj.iterations + " iterations to find."); } // end of main method } // end of class BinarySearch

    Read the article

  • adding virtual function to the end of the class declaration avoids binary incompatibility?

    - by bob
    Could someone explain to me why adding a virtual function to the end of a class declaration avoids binary incompatibility? If I have: class A { public: virtual ~A(); virtual void someFuncA() = 0; virtual void someFuncB() = 0; virtual void other1() = 0; private: int someVal; }; And later modify this function to: class A { public: virtual ~A(); virtual void someFuncA(); virtual void someFuncB(); virtual void someFuncC(); virtual void other1() = 0; private: int someVal; }; I get a coredump from another .so compiled against the previous declaration. But if I put someFuncC() at the end of the class declaration (after "int someVal"), I don't see coredump anymore. Could someone tell me why this is? And does this trick always work? PS. compiler is gcc, does this work with other compilers?

    Read the article

  • Save and Load Dictionary from encrypted or unreadable or binary format ?

    - by Prix
    I have a dictionary like the follow: public Dictionary<int, SpawnList> spawnEntities = new Dictionary<int, SpawnList>(); The class being used is as follow: public class SpawnList { public int NpcID { get; set; } public string Name { get; set; } public int Level { get; set; } public int TitleID { get; set; } public int StaticID { get; set; } public entityType Status { get; set; } public int TypeA { get; set; } public int TypeB { get; set; } public int TypeC { get; set; } public int ZoneID { get; set; } public int Heading { get; set; } public float PosX { get; set; } public float PosY { get; set; } public float PosZ { get; set; } } /// <summary>Entity type enum.</summary> public enum entityType { Ally, Enemy, SummonPet, NPC, Object, Monster, Gatherable, Unknown } How could I save this Dictionary to either a binary or encrypted format so I could later Load it again into my application ? My limitation is .Net 3.5 can't use anything higher.

    Read the article

  • Translate a<b to IR Trees

    - by drozzy
    I have to translate the mini-java (java like language) statements into intermediate-representation trees. But for this question I have no idea what it is asking... a>b moves a 1 or 0 into some newly defined temporary, and whose right-hand side is a temporary Does the wording make sense to anyone? (I am using the Java compilers book, and it is question 7.2d) in ch7.)

    Read the article

  • Mercurial hook to disallow committing large binary files

    - by hekevintran
    I want to have a Mercurial hook that will run before committing a transaction that will abort the transaction if a binary file being committed is greater than 1 megabyte. I found the following code which works fine except for one problem. If my changeset involves removing a file, this hook will throw an exception. The hook (I'm using pretxncommit = python:checksize.newbinsize): from mercurial import context, util from mercurial.i18n import _ import mercurial.node as dpynode '''hooks to forbid adding binary file over a given size Ensure the PYTHONPATH is pointing where hg_checksize.py is and setup your repo .hg/hgrc like this: [hooks] pretxncommit = python:checksize.newbinsize pretxnchangegroup = python:checksize.newbinsize preoutgoing = python:checksize.nopull [limits] maxnewbinsize = 10240 ''' def newbinsize(ui, repo, node=None, **kwargs): '''forbid to add binary files over a given size''' forbid = False # default limit is 10 MB limit = int(ui.config('limits', 'maxnewbinsize', 10000000)) tip = context.changectx(repo, 'tip').rev() ctx = context.changectx(repo, node) for rev in range(ctx.rev(), tip+1): ctx = context.changectx(repo, rev) print ctx.files() for f in ctx.files(): fctx = ctx.filectx(f) filecontent = fctx.data() # check only for new files if not fctx.parents(): if len(filecontent) > limit and util.binary(filecontent): msg = 'new binary file %s of %s is too large: %ld > %ld\n' hname = dpynode.short(ctx.node()) ui.write(_(msg) % (f, hname, len(filecontent), limit)) forbid = True return forbid The exception: $ hg commit -m 'commit message' error: pretxncommit hook raised an exception: apps/helpers/templatetags/include_extends.py@bced6272d8f4: not found in manifest transaction abort! rollback completed abort: apps/helpers/templatetags/include_extends.py@bced6272d8f4: not found in manifest! I'm not familiar with writing Mercurial hooks, so I'm pretty confused about what's going on. Why does the hook care that a file was removed if hg already knows about it? Is there a way to fix this hook so that it works all the time? Update (solved): I modified the hook to filter out files that were removed in the changeset. def newbinsize(ui, repo, node=None, **kwargs): '''forbid to add binary files over a given size''' forbid = False # default limit is 10 MB limit = int(ui.config('limits', 'maxnewbinsize', 10000000)) ctx = repo[node] for rev in xrange(ctx.rev(), len(repo)): ctx = context.changectx(repo, rev) # do not check the size of files that have been removed # files that have been removed do not have filecontexts # to test for whether a file was removed, test for the existence of a filecontext filecontexts = list(ctx) def file_was_removed(f): """Returns True if the file was removed""" if f not in filecontexts: return True else: return False for f in itertools.ifilterfalse(file_was_removed, ctx.files()): fctx = ctx.filectx(f) filecontent = fctx.data() # check only for new files if not fctx.parents(): if len(filecontent) > limit and util.binary(filecontent): msg = 'new binary file %s of %s is too large: %ld > %ld\n' hname = dpynode.short(ctx.node()) ui.write(_(msg) % (f, hname, len(filecontent), limit)) forbid = True return forbid

    Read the article

  • javascript compare two DOM trees

    - by Paul
    I want to compare the change of a DOM node after a user event is fired on it; but I don't know on which element a user would fire, so my idea is to (1) save the DOM tree before an event and (2) compare the saved tree with the updated DOM tree when an event is fired. My question are (1) is there any better way? and (2) if there is no other way, what would be the fast algorithm to compare two DOM trees?

    Read the article

  • how to create binary of iphone application

    - by CodeWriter
    hello, On reading the iTunesConnect_DeveloperGuide.pdf, i came across the term binary. This is the paragraph found in the pdf: To submit your application through iTunes Connect and get it posted on the App Store successfully, make sure you have the following: Application binary (includes 57px icon), large 512px icon for use on the App Store, primary screenshot, contract information, export compliance information and applica- tion metadata It is also mentioned that the binary should be a zipped file. Can anyone please explain what is a binary and how to create one? Thanks

    Read the article

  • Linq Expression Trees in Compact Framework.

    - by Michal Drozdowicz
    The lack of expression trees in Compact Framework has bugged me for some time now, but I haven't really looked for a solution. Today, I've found a blog post about an alternative System.Linq.Expressions built on top of Mono System.Core and used e.g. by db4o (you can find it here). My question is - have you used this library and if so, what were your experiences with it (especially regarding performance)?

    Read the article

  • Languages for implementing decision trees

    - by Shailesh Tainwala
    What would be a good choice of programming language in which to implement a decision tree? The results of the implementation will be for personal use only, so no need to consider ability to publish etc. I have heard that Octave is a good option, can anyone explain why a matrix based language is recommended for implementing decision trees?

    Read the article

  • Moving Binary logs in Mysql to a different harddisk

    - by Darini
    This question is about Mysql Binary logging.We need to move the Binary logging to a different hard disk . What is the configuration change required in Mysql?.Currently Binary logs go into the same folder as the ibdata and there is a replication slave running which needs the binary logs

    Read the article

  • IIS7 Binary Stream Error

    - by WDuffy
    I'm struggling to understand the problem I'm seeing so please accept my apology if the question is vague. I'm running a classic asp app in IIS7 and everything seems to work fine except for one issue that has me stumped. Basically, files can be downloaded from the server which is done using the sendBinary method of Persits ASP Upload component. This component works fine for uploading etc it's just the downloading I have a problem. The strange thing is, I cannot have a pure asp page that serves the binary file. Everything works fine in II6, but in II7 there is a strange problem. For example this does not work. <% SET objUpload = server.createObject("Persits.Upload") objUpload.sendBinary "D:\sites\file.pdf", true, "application/octet-binary", true SET objUpload = NOTHING %> However, if I put anything in front of the asp code the file is served fine. serve this <% SET objUpload = server.createObject("Persits.Upload") objUpload.sendBinary "D:\sites\file.pdf", true, "application/octet-binary", true SET objUpload = NOTHING %> I can also write something to the response stream first and it works fine. <% Response.Write("server this") SET objUpload = server.createObject("Persits.Upload") objUpload.sendBinary "D:\sites\file.pdf", true, "application/octet-binary", true SET objUpload = NOTHING %> Does anyone have any ideas of what could be causing this or has anyone ran into a similar situation? I'm sure it has something to do with the setup in IIS 7.

    Read the article

  • Compiling vs using pre-built binaries performance?

    - by Nick Rosencrantz
    Will performance be better (quicker) if I manually compile the source for a software component for the actual machine that it will be used on, compared to if the source was compiled on another platform perhaps for many different architectures? I got some good results compiling source that I downloaded and I wonder whether this was due to compiling it instead of downloading a pre-compiled binary which is often the case with software updates.

    Read the article

  • Tournament bracket method to put distance between teammates

    - by Fred Thomsen
    I am using a proper binary tree to simulate a tournament bracket. It's preferred any competitors in the bracket that are teammates don't meet each other until the later rounds. What is an efficient method in which I can ensure that teammates in the bracket have as much distance as possible from each other? Are there any other data structures besides a tree that would be better for this purpose? EDIT: There can be more than 2 teams represented in a bracket.

    Read the article

  • How portable are Binaries compiled in Ubuntu?

    - by hiobs
    The title says it all, actually. But allow me to specify the question: Assuming I were to compile an application that uses libffi, libGL, dlfcn, and SDL, would said binary run on other Linux distributions with same architecture, etc? The reason I ask is because of the directory /usr/lib/i386-linux-gnu - I might be wrong, but I assume this directory is something rather Ubuntu-specific, no? So, how portable are binaries compiled on Ubuntu really?

    Read the article

  • How to find the insertion point in an array using binary search?

    - by ????
    The basic idea of binary search in an array is simple, but it might return an "approximate" index if the search fails to find the exact item. (we might sometimes get back an index for which the value is larger or smaller than the searched value). For looking for the exact insertion point, it seems that after we got the approximate location, we might need to "scan" to left or right for the exact insertion location, so that, say, in Ruby, we can do arr.insert(exact_index, value) I have the following solution, but the handling for the part when begin_index >= end_index is a bit messy. I wonder if a more elegant solution can be used? (this solution doesn't care to scan for multiple matches if an exact match is found, so the index returned for an exact match may point to any index that correspond to the value... but I think if they are all integers, we can always search for a - 1 after we know an exact match is found, to find the left boundary, or search for a + 1 for the right boundary.) My solution: DEBUGGING = true def binary_search_helper(arr, a, begin_index, end_index) middle_index = (begin_index + end_index) / 2 puts "a = #{a}, arr[middle_index] = #{arr[middle_index]}, " + "begin_index = #{begin_index}, end_index = #{end_index}, " + "middle_index = #{middle_index}" if DEBUGGING if arr[middle_index] == a return middle_index elsif begin_index >= end_index index = [begin_index, end_index].min return index if a < arr[index] && index >= 0 #careful because -1 means end of array index = [begin_index, end_index].max return index if a < arr[index] && index >= 0 return index + 1 elsif a > arr[middle_index] return binary_search_helper(arr, a, middle_index + 1, end_index) else return binary_search_helper(arr, a, begin_index, middle_index - 1) end end # for [1,3,5,7,9], searching for 6 will return index for 7 for insertion # if exact match is found, then return that index def binary_search(arr, a) puts "\nSearching for #{a} in #{arr}" if DEBUGGING return 0 if arr.empty? result = binary_search_helper(arr, a, 0, arr.length - 1) puts "the result is #{result}, the index for value #{arr[result].inspect}" if DEBUGGING return result end arr = [1,3,5,7,9] b = 6 arr.insert(binary_search(arr, b), b) p arr arr = [1,3,5,7,9,11] b = 6 arr.insert(binary_search(arr, b), b) p arr arr = [1,3,5,7,9] b = 60 arr.insert(binary_search(arr, b), b) p arr arr = [1,3,5,7,9,11] b = 60 arr.insert(binary_search(arr, b), b) p arr arr = [1,3,5,7,9] b = -60 arr.insert(binary_search(arr, b), b) p arr arr = [1,3,5,7,9,11] b = -60 arr.insert(binary_search(arr, b), b) p arr arr = [1] b = -60 arr.insert(binary_search(arr, b), b) p arr arr = [1] b = 60 arr.insert(binary_search(arr, b), b) p arr arr = [] b = 60 arr.insert(binary_search(arr, b), b) p arr and result: Searching for 6 in [1, 3, 5, 7, 9] a = 6, arr[middle_index] = 5, begin_index = 0, end_index = 4, middle_index = 2 a = 6, arr[middle_index] = 7, begin_index = 3, end_index = 4, middle_index = 3 a = 6, arr[middle_index] = 5, begin_index = 3, end_index = 2, middle_index = 2 the result is 3, the index for value 7 [1, 3, 5, 6, 7, 9] Searching for 6 in [1, 3, 5, 7, 9, 11] a = 6, arr[middle_index] = 5, begin_index = 0, end_index = 5, middle_index = 2 a = 6, arr[middle_index] = 9, begin_index = 3, end_index = 5, middle_index = 4 a = 6, arr[middle_index] = 7, begin_index = 3, end_index = 3, middle_index = 3 the result is 3, the index for value 7 [1, 3, 5, 6, 7, 9, 11] Searching for 60 in [1, 3, 5, 7, 9] a = 60, arr[middle_index] = 5, begin_index = 0, end_index = 4, middle_index = 2 a = 60, arr[middle_index] = 7, begin_index = 3, end_index = 4, middle_index = 3 a = 60, arr[middle_index] = 9, begin_index = 4, end_index = 4, middle_index = 4 the result is 5, the index for value nil [1, 3, 5, 7, 9, 60] Searching for 60 in [1, 3, 5, 7, 9, 11] a = 60, arr[middle_index] = 5, begin_index = 0, end_index = 5, middle_index = 2 a = 60, arr[middle_index] = 9, begin_index = 3, end_index = 5, middle_index = 4 a = 60, arr[middle_index] = 11, begin_index = 5, end_index = 5, middle_index = 5 the result is 6, the index for value nil [1, 3, 5, 7, 9, 11, 60] Searching for -60 in [1, 3, 5, 7, 9] a = -60, arr[middle_index] = 5, begin_index = 0, end_index = 4, middle_index = 2 a = -60, arr[middle_index] = 1, begin_index = 0, end_index = 1, middle_index = 0 a = -60, arr[middle_index] = 9, begin_index = 0, end_index = -1, middle_index = -1 the result is 0, the index for value 1 [-60, 1, 3, 5, 7, 9] Searching for -60 in [1, 3, 5, 7, 9, 11] a = -60, arr[middle_index] = 5, begin_index = 0, end_index = 5, middle_index = 2 a = -60, arr[middle_index] = 1, begin_index = 0, end_index = 1, middle_index = 0 a = -60, arr[middle_index] = 11, begin_index = 0, end_index = -1, middle_index = -1 the result is 0, the index for value 1 [-60, 1, 3, 5, 7, 9, 11] Searching for -60 in [1] a = -60, arr[middle_index] = 1, begin_index = 0, end_index = 0, middle_index = 0 the result is 0, the index for value 1 [-60, 1] Searching for 60 in [1] a = 60, arr[middle_index] = 1, begin_index = 0, end_index = 0, middle_index = 0 the result is 1, the index for value nil [1, 60] Searching for 60 in [] [60]

    Read the article

  • How to compile scheme into native binary files ?

    - by Joe
    I am very new to scheme. And now I am trying to compile some scheme code into binary file which will be loaded faster into interpreter. (The interpreter is a hybrid interpreter)Some one told me that I can compile the code into native binary file and then load it into interperter. And my question is: 1. What is the native binary file? 2. How can I compile the scheme code into a native binary file? 3. How can I load native bianry file into scheme interpreter? Thanks in advance. Joe Suggested that I want to compile below code into native binary file: (define test (lambda() (display "this is a test")) And then load the bianry file into interpreter and call the function "test".

    Read the article

  • C++ : Lack of Standardization at the Binary Level

    - by Nawaz
    Why ISO/ANSI didn't standardize C++ at the binary level? There are many portability issues with C++, which is only because of lack of it's standardization at the binary level. Don Box writes, (quoting from his book Essential COM, chapter COM As A Better C++) C++ and Portability Once the decision is made to distribute a C++ class as a DLL, one is faced with one of the fundamental weaknesses of C++, that is, lack of standardization at the binary level. Although the ISO/ANSI C++ Draft Working Paper attempts to codify which programs will compile and what the semantic effects of running them will be, it makes no attempt to standardize the binary runtime model of C++. The first time this problem will become evident is when a client tries to link against the FastString DLL's import library from a C++ developement environment other than the one used to build the FastString DLL. Are there more benefits Or loss of this lack of binary standardization?

    Read the article

  • String or binary data would be truncated.

    - by Derek Dieter
    This error message is relatively straight forward. The way it normally happens is when you are trying to insert data from a table that contains values that have larger data lengths than the table you are trying to insert into. An example of this would be trying to insert data from a permanent table, into [...]

    Read the article

< Previous Page | 12 13 14 15 16 17 18 19 20 21 22 23  | Next Page >