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  • How to convet to 16 bit binary

    - by ayush
    Hi i want to convert a long integer to binary but the problem is i want a fixed 16 bit binary result after conversion like if i convert 2 to 16 bit binary it should give me 0000000000000010 as ans can anyone help me ?

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  • read a file with both text and binary information in .Net

    - by Yin Zhu
    I need to read binary PGM image files. Its format: P5 # comments nrows ncolumns max-value binary values start at this line. (totally nrows*ncolumns bytes/unsigned char) I know how to do it in C or C++ using FILE handler by reading several lines first and read the binary block. But don't know how to do it in .Net.

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  • SQLServer Binary Data with ActiveRecord and JDBC

    - by John Duff
    I'm using the activerecord-jdbc-adapter with ActiveRecord to be able to access a SQLServer database for Rails Application running under jRuby and am having trouble inserting binary data. The Exception I am getting is below. Note I just have a blurb for the binary data from the fixtures that was working fine for MySQL. ActiveRecord::StatementInvalid: ActiveRecord::ActiveRecordError: Operand type clash: nvarchar is incompatible with image: INSERT INTO blobstorage_datachunks ([id], [datafile_id], [chunk_number], [data]) VALUES (369397133, 663419003, 0, N'GIF89a@') When I created the tables the migration had binary and SQLServer used Image instead. We're using Rails 2.3.5, SQLServer Express 2008. What I'm looking for is a way to get the binary data into SQLServer with ActiveRecord. Thanks in advance for the help.

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  • merge two binary images using Matlab

    - by Pier-alexandre Bouchard
    I need to create two different black binary rectangles using Matlab, to overlay a part of both and to extract the insertion. How can I overlay two binary images? -------|----------| | | 2 | | 1 |----|-----| | | |-----------| I created my two binary images using the false(X, Y) Matlab function. I dont find how to produce the merge the two images and to extract the insertion.

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  • Efficient Array Storage for Binary Tree

    - by Sundararajan S
    We have to write the nodes of a binary tree to a file. What is the most space efficient way of writing a binary tree . We can store it in array format with parent in position 'i' and its childs in 2i,2i+1. But this will waste lot of space in case of sparse binary trees.

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  • Where binary in SQL

    - by fire
    I have an SQL statement: SELECT * FROM customers WHERE BINARY login='xxx' AND password='yyyy' There are no blob/binary fields in the table, do I need the BINARY after the WHERE what else does it do?

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  • Best practices for handling binary data in Ruby?

    - by StackedCrooked
    What are the best practices for reading and writing binary data in Ruby? In the code sample below I needed to send a binary file using over HTTP (as POST data): f = File.new("resp.der", "r") # binary file begin while true out.syswrite(f.sysread(1)) # out is an output stream (type IO) end rescue EOFError => err puts "Sent response." end While this code seems to do a good job, it probably isn't very idiomatic. How can I improve it?

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  • Reading binary file with Octave

    - by Anthony Blake
    I'm trying to a binary file consisting of floats with Octave (on OS X), but I'm getting the following error: octave-3.2.3:2> load Input.dat R -binary error: load: failed to read matrix from file `Input.dat' The file was written like so: std::ofstream fout("Input.dat", std::ios::trunc | std::ios::binary); fout.write(reinterpret_cast<char*>(Buf), N*sizeof(double)); fout.close(); Any idea what could be going wrong here?

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  • how divide herader from binary data

    - by fixo2020
    Hi, I have this code: ofstream dest("test.txt",ios::binary); while (true){ size_t retval = recv (sd, buffer, sizeof(buffer), 0); dest.write(buffer,retval); if(retval <= 0) { delete[] buffer; break;} } Now, the recv() function return 4 bytes each loop right? and buffer contain it, this return all data so, pseudo-header and binary data (image), but I want know how capture only binary data, I know that the end of header are "\n\r" right? but what's are the solution better for make this? I make a function that detect when are "\n\r"? and after how capture binary data? Or, I put all data in memory, and after parse it? but how? I'm desperate :(

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  • Performance difference between compiled and binary linux distributions/packages

    - by jozko
    I was searching a lot on the internet and couldn't find an exact answer. There are distros like Gentoo (or FreeBSD) which does not come with binaries but only with source code for packages (ports). The majority of distros uses binary backages (debian, etc.). First question: How much speed increase can I expect from compiled package? How much speed increase can I get from real world packages like apache or mysql? i.e. queries per second? Second question: Does binary package means it does not use any CPU instructions that was introduced after first AMD 64bit CPU? With the 32bit packages does it mean that the package will run on 386 and basically does not use most of the modern CPU instructions? Additional info: - I am not talking about desktop, but server environment. - I dont care about compile time - I have more servers, so speed increase more than 15% is worth for using source code packages - Please no flamewars. Thank you very much

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  • Linux. Compare binary files

    - by frustratedCmpNoLongerUser
    I need to compare two binary files and get output in form for every different byte. So if file1.bin is 00 90 00 11 in binary form and file2.bin is 00 91 00 10 I want to get something like 00000001 90 91 00000003 11 10 what is the easiest way to accomplish the goal? Standard tool? Some 3rd party tool? inb4: cmp -l should be killed with fire,it uses decimal system for offsets and octal for bytes. "Consistency for losers" must be cmp's motto.

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  • remove apache tar binary package in centos

    - by user119720
    I need help in removing binary package that had been installed in my linux machine. The scenario that I am having are such as like this: I've already install latest apache that I get from its website(httpd.apache.org) through Unix binary package(tar.gz) After successfully install program,the apache server web perfectly without any issues. But then I having a thought,if there are another latest release version of apache in the future,then I need to make sure that i can upgrading current apache or reinstalling the new version apache. So my question is, how do I ensure that I have remove the old remove apache and all its dependencies so that it will not having conflict(probably) when installing the new apache. Right now the only thing that i can think of is to remove all the apache folder manually : rm -rf /apache2 Hope someone can shed some light about this.Thanks.

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  • "Launch Failed. Binary Not Found." Snow Leopard and Eclipse C/C++ IDE issue.

    - by Alex
    Not a question, I've just scoured the internet in search of a solution for this problem and thought I'd share it with the good folks of SO. I'll put it in plain terms so that it's accessible to newbs. :) (Apologies if this is the wrong place -- just trying to be helpful.) This issue occurs with almost any user OS X Snow Leopard who tries to use the Eclipse C/C++ IDE, but is particularly annoying for the people (like me) who were using the Eclipse C/C++ IDE in Leopard, and were unable to work with Eclipse anymore when they upgraded. The issue occurs When users go to build/compile/link their software. They get the following error: Launch Failed. Binary Not Found. Further, the "binaries" branch in the project window on the left is simply nonexistent. THE PROBLEM: is that GCC 4.2 (the GNU Compiler Collection) that comes with Snow Leopard compiles binaries in 64-bit by default. Unfortunately, the linker that Eclipse uses does not understand 64-bit binaries; it reads 32-bit binaries. There may be other issues here, but in short, they culminate in no binary being generated, at least not one that Eclipse can read, which translates into Eclipse not finding the binaries. Hence the error. One solution is to add an -arch i686 flag when making the file, but manually making the file every time is annoying. Luckily for us, Snow Leopard also comes with GCC 4.0, which compiles in 32 bits by default. So one solution is merely to link this as the default compiler. This is the way I did it. THE SOLUTION: The GCCs are in /usr/bin, which is normally a hidden folder, so you can't see it in the Finder unless you explicitly tell the system that you want to see hidden folders. Anyway, what you want to do is go to the /usr/bin folder and delete the path that links the GCC command with GCC 4.2 and add a path that links the GCC command with GCC 4.0. In other words, when you or Eclipse try to access GCC, we want the command to go to the compiler that builds in 32 bits by default, so that the linker can read the files; we do not want it to go to the compiler that compiles in 64 bits. The best way to do this is to go to Applications/Utilities, and select the app called Terminal. A text prompt should come up. It should say something like "(Computer Name):~ (Username)$ " (with a space for you user input at the end). The way to accomplish the tasks above is to enter the following commands, entering each one in sequence VERBATIM, and pressing enter after each individual line. cd /usr/bin rm cc gcc c++ g++ ln -s gcc-4.0 cc ln -s gcc-4.0 gcc ln -s c++-4.0 c++ ln -s g++-4.0 g++ Like me, you will probably get an error that tells you you don't have permission to access these files. If so, try the following commands instead: cd /usr/bin sudo rm cc gcc c++ g++ sudo ln -s gcc-4.0 cc sudo ln -s gcc-4.0 gcc sudo ln -s c++-4.0 c++ sudo ln -s g++-4.0 g++ Sudo may prompt you for a password. If you've never used sudo before, try just pressing enter. If that doesn't work, try the password for your main admin account. OTHER POSSIBLE SOLUTIONS You may be able to enter build variables into Eclipse. I tried this, but I don't know enough about it. If you want to feel it out, the flag you will probably need is -arch i686. In earnest, GCC-4.0 worked for me all this time, and I don't see any reason to switch now. There may be a way to alter the default for the compiler itself, but once again, I don't know enough about it. Hope this has been helpful and informative. Good coding!

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  • Java library for trees similar to JGraphT for graphs?

    - by lexicore
    I'm a big fan of JGraphT, a Java library for graphs. Could anyone recommend a similar Java library for trees? Preferrably FOSS. What I need is a good API, preferrably typesafe with generics which allows modelling different kinds of trees (with some user data attached to verticies/edges) and run different algorithms and operations on these trees. For instance, traverse or balance. At the moment I'm not interested in visualization of trees.

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  • Using custom DataContractResolver in WCF, to transport inheritance trees involving generics

    - by Benson
    I've got a WCF service, in which there are operations which accept a non-generic base class as parameter. [DataContract] class Foo { ... } This base class is in turn inherited, by such generics classes as [DataContract] class Bar : Foo { ... } To get this to work, I'd previously have to register KnownTypes for the Foo class, and have these include all possible variations of Bar (such as Bar, Bar and even Bar). With the DataContractResolver in .NET 4, however, I should be able to build a resolver which properly stores (and restores) the classes. My questions: Are DataContractResolvers typically only used on the service side, and not by the client? If so, how would that be useful in this scenario? Am I wrong to write a DataContractResolver which serializes the fully qualified type name of a generic type, such as Bar1[List1[string, mscorlib], mscorlib] ? Couldn't the same DataContractResolver on the client side restore these types?

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  • Dynamically loading sub-trees into YUI Treeview

    - by user319399
    When you create a YUI TreeView instance, you can pass in an object that represents an entire tree, and it will automatically build up the TextNodes for you. I'd like to send in a partial tree, such that the tree only goes, say, 2 levels deep, and anything deeper than that will invoke dynamic loading. I've got that much working. Now for the interesting part. In the dynamic loading callback I give to my tree instance, I want to again be able to just give YUI a big object representing more of the tree. I want to do something like this: // data is a array of objects organized into a tree, with some nodes requiring dynamic loading when they are navigated to tree = new YAHOO.widget.TreeView("treeDiv1", data); tree.setDynamicLoad(loadDataForNode); function loadDataForNode(node, onCompleteCallback) { if(node.children.length==0) { var subTree = { "label":"Cars", isLeaf:false, children:[ { "label":"Chevy", isLeaf:true }, { "label":"Ford", isLeaf:true }, ] }; // doesn't work, even though it has the required "label" field var tempNode = new YAHOO.widget.TextNode(subTree, node, true); } onCompleteCallback(); } Is this possible? Or do I have to iterate over all the nodes in my subtree and construct individual TextNodes for each one? Thanks much...

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  • Linux Kernel - Red/Black Trees

    - by CodeRanger
    I'm trying to implement a red/black tree in Linux per task_struct using code from linux/rbtree.h. I can get a red/black tree inserting properly in a standalone space in the kernel such as a module but when I try to get the same code to function with the rb_root declared in either task_struct or task_struct-files_struct, I get a SEGFAULT everytime I try an insert. Here's some code: In task_struct I create a rb_root struct for my tree (not a pointer). In init_task.h, macro INIT_TASK(tsk), I set this equal to RB_ROOT. To do an insert, I use this code: rb_insert(&(current-fd_tree), &rbnode); This is where the issue occurs. My insert command is the standard insert that is documented in all RBTree documentation for the kernel: int my_insert(struct rb_root *root, struct mytype *data) { struct rb_node **new = &(root->rb_node), *parent = NULL; /* Figure out where to put new node */ while (*new) { struct mytype *this = container_of(*new, struct mytype, node); int result = strcmp(data->keystring, this->keystring); parent = *new; if (result < 0) new = &((*new)->rb_left); else if (result > 0) new = &((*new)->rb_right); else return FALSE; } /* Add new node and rebalance tree. */ rb_link_node(&data->node, parent, new); rb_insert_color(&data->node, root); return TRUE; } Is there something I'm missing? Some reason this would work fine if I made a tree root outside of task_struct? If I make rb_root inside of a module this insert works fine. But once I put the actual tree root in the task_struct or even in the task_struct-files_struct, I get a SEGFAULT. Can a root node not be added in these structs? Any tips are greatly appreciated. I've tried nearly everything I can think of.

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  • Red-Black trees - Erasing a node with two non-leaf children

    - by SalamiArmi
    Hi all, I've been implementing my own version of a red-black tree, mostly basing my algorithms from Wikipedia (http://en.wikipedia.org/wiki/Red-black_tree). Its fairly concise for the most part, but there's one part that I would like clarification on. When erasing a node from the tree that has 2 non-leaf (non-NULL) children, it says to move either side's children into the deletable node, and remove that child. I'm a little confused as to which side to remove from, based on that. Do I pick the side randomly, do I alternate betweek sides, or do I stick to the same side for every future deletion?

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  • Repeated Scene Trees (Java3d / OpenGL)

    - by Jim
    Hello, I want to make a 3d scene that loops around on its self. That is to say, if you keep going in any direction, you will loop back to the other side. My current implementation is so bad, it's embarrassing to admit to it. I redraw the each change twenty-seven times, to make a 3x3x3 scene cube. When the user reaches the end of the middle cube, I jump them over to the other side. Maintaining consistency (let alone performance) is a nightmare. Total Disaster. This doesn't seem like it would be an unusual request, so I'm wondering if anyone knows of a more legit solution. Thanks!

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  • Insertions into Zipper trees on XML files in Clojure

    - by ivar
    I'm confused as how to idiomatically change a xml tree accessed through clojure.contrib's zip-filter.xml. Should be trying to do this at all, or is there a better way? Say that I have some dummy xml file "itemdb.xml" like this: <itemlist> <item id="1"> <name>John</name> <desc>Works near here.</desc> </item> <item id="2"> <name>Sally</name> <desc>Owner of pet store.</desc> </item> </itemlist> And I have some code: (require '[clojure.zip :as zip] '[clojure.contrib.duck-streams :as ds] '[clojure.contrib.lazy-xml :as lxml] '[clojure.contrib.zip-filter.xml :as zf]) (def db (ref (zip/xml-zip (lxml/parse-trim (java.io.File. "itemdb.xml"))))) ;; Test that we can traverse and parse. (doall (map #(print (format "%10s: %s\n" (apply str (zf/xml-> % :name zf/text)) (apply str (zf/xml-> % :desc zf/text)))) (zf/xml-> @db :item))) ;; I assume something like this is needed to make the xml tags (defn create-item [name desc] {:tag :item :attrs {:id "3"} :contents (list {:tag :name :attrs {} :contents (list name)} {:tag :desc :attrs {} :contents (list desc)})}) (def fred-item (create-item "Fred" "Green-haired astrophysicist.")) ;; This disturbs the structure somehow (defn append-item [xmldb item] (zip/insert-right (-> xmldb zip/down zip/rightmost) item)) ;; I want to do something more like this (defn append-item2 [xmldb item] (zip/insert-right (zip/rightmost (zf/xml-> xmldb :item)) item)) (dosync (alter db append-item2 fred-item)) ;; Save this simple xml file with some added stuff. (ds/spit "appended-itemdb.xml" (with-out-str (lxml/emit (zip/root @db) :pad true))) I am unclear about how to use the clojure.zip functions appropriately in this case, and how that interacts with zip-filter. If you spot anything particularly weird in this small example, please point it out.

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  • B-trees that use redistribution on insertion

    - by Phenom
    If I insert the following keys into a B-tree of order 4 (meaning 4 pointers and 3 elements in each node), I get the following B-tree. G / \ A IY Would it look any different if redistribution on insertion were used? How does redistribution on insertion work?

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  • Deeply nested subqueries for traversing trees in MySQL

    - by nickf
    I have a table in my database where I store a tree structure using the hybrid Nested Set (MPTT) model (the one which has lft and rght values) and the Adjacency List model (storing parent_id on each node). my_table (id, parent_id, lft, rght, alias) This question doesn't relate to any of the MPTT aspects of the tree but I thought I'd leave it in in case anyone had a good idea about how to leverage that. I want to convert a path of aliases to a specific node. For example: "users.admins.nickf" would find the node with alias "nickf" which is a child of one with alias "admins" which is a child of "users" which is at the root. There is a unique index on (parent_id, alias). I started out by writing the function so it would split the path to its parts, then query the database one by one: SELECT `id` FROM `my_table` WHERE `parent_id` IS NULL AND `alias` = 'users';-- 1 SELECT `id` FROM `my_table` WHERE `parent_id` = 1 AND `alias` = 'admins'; -- 8 SELECT `id` FROM `my_table` WHERE `parent_id` = 8 AND `alias` = 'nickf'; -- 37 But then I realised I could do it with a single query, using a variable amount of nesting: SELECT `id` FROM `my_table` WHERE `parent_id` = ( SELECT `id` FROM `my_table` WHERE `parent_id` = ( SELECT `id` FROM `my_table` WHERE `parent_id` IS NULL AND `alias` = 'users' ) AND `alias` = 'admins' ) AND `alias` = 'nickf'; Since the number of sub-queries is dependent on the number of steps in the path, am I going to run into issues with having too many subqueries? (If there even is such a thing) Are there any better/smarter ways to perform this query?

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