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  • Silverlight 4 Twitter Client &ndash; Part 6

    - by Max
    In this post, we are going to look into implementing lists into our twitter application and also about enhancing the data grid to display the status messages in a pleasing way with the profile images. Twitter lists are really cool feature that they recently added, I love them and I’ve quite a few lists setup one for DOTNET gurus, SQL Server gurus and one for a few celebrities. You can follow them here. Now let us move onto our tutorial. 1) Lists can be subscribed to in two ways, one can be user’s own lists, which he has created and another one is the lists that the user is following. Like for example, I’ve created 3 lists myself and I am following 1 other lists created by another user. Both of them cannot be fetched in the same api call, its a two step process. 2) In the TwitterCredentialsSubmit method we’ve in Home.xaml.cs, let us do the first api call to get the lists that the user has created. For this the call has to be made to https://twitter.com/<TwitterUsername>/lists.xml. The API reference is available here. myService1.AllowReadStreamBuffering = true; myService1.UseDefaultCredentials = false; myService1.Credentials = new NetworkCredential(GlobalVariable.getUserName(), GlobalVariable.getPassword()); myService1.DownloadStringCompleted += new DownloadStringCompletedEventHandler(ListsRequestCompleted); myService1.DownloadStringAsync(new Uri("https://twitter.com/" + GlobalVariable.getUserName() + "/lists.xml")); 3) Now let us look at implementing the event handler – ListRequestCompleted for this. public void ListsRequestCompleted(object sender, System.Net.DownloadStringCompletedEventArgs e) { if (e.Error != null) { StatusMessage.Text = "This application must be installed first."; parseXML(""); } else { //MessageBox.Show(e.Result.ToString()); parseXMLLists(e.Result.ToString()); } } 4) Now let us look at the parseXMLLists in detail xdoc = XDocument.Parse(text); var answer = (from status in xdoc.Descendants("list") select status.Element("name").Value); foreach (var p in answer) { Border bord = new Border(); bord.CornerRadius = new CornerRadius(10, 10, 10, 10); Button b = new Button(); b.MinWidth = 70; b.Background = new SolidColorBrush(Colors.Black); b.Foreground = new SolidColorBrush(Colors.Black); //b.Width = 70; b.Height = 25; b.Click += new RoutedEventHandler(b_Click); b.Content = p.ToString(); bord.Child = b; TwitterListStack.Children.Add(bord); } So here what am I doing, I am just dynamically creating a button for each of the lists and put them within a StackPanel and for each of these buttons, I am creating a event handler b_Click which will be fired on button click. We will look into this method in detail soon. For now let us get the buttons displayed. 5) Now the user might have some lists to which he has subscribed to. We need to create a button for these as well. In the end of TwitterCredentialsSubmit method, we need to make a call to http://api.twitter.com/1/<TwitterUsername>/lists/subscriptions.xml. Reference is available here. The code will look like this below. myService2.AllowReadStreamBuffering = true; myService2.UseDefaultCredentials = false; myService2.Credentials = new NetworkCredential(GlobalVariable.getUserName(), GlobalVariable.getPassword()); myService2.DownloadStringCompleted += new DownloadStringCompletedEventHandler(ListsSubsRequestCompleted); myService2.DownloadStringAsync(new Uri("http://api.twitter.com/1/" + GlobalVariable.getUserName() + "/lists/subscriptions.xml")); 6) In the event handler – ListsSubsRequestCompleted, we need to parse through the xml string and create a button for each of the lists subscribed, let us see how. I’ve taken only the “full_name”, you can choose what you want, refer the documentation here. Note the point that the full_name will have @<UserName>/<ListName> format – this will be useful very soon. xdoc = XDocument.Parse(text); var answer = (from status in xdoc.Descendants("list") select status.Element("full_name").Value); foreach (var p in answer) { Border bord = new Border(); bord.CornerRadius = new CornerRadius(10, 10, 10, 10); Button b = new Button(); b.Background = new SolidColorBrush(Colors.Black); b.Foreground = new SolidColorBrush(Colors.Black); //b.Width = 70; b.MinWidth = 70; b.Height = 25; b.Click += new RoutedEventHandler(b_Click); b.Content = p.ToString(); bord.Child = b; TwitterListStack.Children.Add(bord); } Please note, I am setting the button width to be auto based on the content and also giving it a midwidth value. I wanted to create a rounded corner buttons, but for some reason its not working. Also add this StackPanel – TwitterListStack of the Home.xaml <StackPanel HorizontalAlignment="Center" Orientation="Horizontal" Name="TwitterListStack"></StackPanel> After doing this, you would get a series of buttons in the top of the home page. 7) Now the button click event handler – b_Click, in this method, once the button is clicked, I call another method with the content string of the button which is clicked as the parameter. Button b = (Button)e.OriginalSource; getListStatuses(b.Content.ToString()); 8) Now the getListsStatuses method: toggleProgressBar(true); WebRequest.RegisterPrefix("http://", System.Net.Browser.WebRequestCreator.ClientHttp); WebClient myService = new WebClient(); myService.AllowReadStreamBuffering = true; myService.UseDefaultCredentials = false; myService.DownloadStringCompleted += new DownloadStringCompletedEventHandler(TimelineRequestCompleted); if (listName.IndexOf("@") > -1 && listName.IndexOf("/") > -1) { string[] arrays = null; arrays = listName.Split('/'); arrays[0] = arrays[0].Replace("@", " ").Trim(); //MessageBox.Show(arrays[0]); //MessageBox.Show(arrays[1]); string url = "http://api.twitter.com/1/" + arrays[0] + "/lists/" + arrays[1] + "/statuses.xml"; //MessageBox.Show(url); myService.DownloadStringAsync(new Uri(url)); } else myService.DownloadStringAsync(new Uri("http://api.twitter.com/1/" + GlobalVariable.getUserName() + "/lists/" + listName + "/statuses.xml")); Please note that the url to look at will be different based on the list clicked – if its user created, the url format will be http://api.twitter.com/1/<CurentUser>/lists/<ListName>/statuses.xml But if it is some lists subscribed, it will be http://api.twitter.com/1/<ListOwnerUserName>/lists/<ListName>/statuses.xml The first one is pretty straight forward to implement, but if its a list subscribed, we need to split the listName string to get the list owner and list name and user them to form the string. So that is what I’ve done in this method, if the listName has got “@” and “/” I build the url differently. 9) Until now, we’ve been using only a few nodes of the status message xml string, now we will look to fetch a new field - “profile_image_url”. Images in datagrid – COOL. So for that, we need to modify our Status.cs file to include two more fields one string another BitmapImage with get and set. public string profile_image_url { get; set; } public BitmapImage profileImage { get; set; } 10) Now let us change the generic parseXML method which is used for binding to the datagrid. public void parseXML(string text) { XDocument xdoc; xdoc = XDocument.Parse(text); statusList = new List<Status>(); statusList = (from status in xdoc.Descendants("status") select new Status { ID = status.Element("id").Value, Text = status.Element("text").Value, Source = status.Element("source").Value, UserID = status.Element("user").Element("id").Value, UserName = status.Element("user").Element("screen_name").Value, profile_image_url = status.Element("user").Element("profile_image_url").Value, profileImage = new BitmapImage(new Uri(status.Element("user").Element("profile_image_url").Value)) }).ToList(); DataGridStatus.ItemsSource = statusList; StatusMessage.Text = "Datagrid refreshed."; toggleProgressBar(false); } We are here creating a new bitmap image from the image url and creating a new Status object for every status and binding them to the data grid. Refer to the Twitter API documentation here. You can choose any column you want. 11) Until now, we’ve been using the auto generate columns for the data grid, but if you want it to be really cool, you need to define the columns with templates, etc… <data:DataGrid AutoGenerateColumns="False" Name="DataGridStatus" Height="Auto" MinWidth="400"> <data:DataGrid.Columns> <data:DataGridTemplateColumn Width="50" Header=""> <data:DataGridTemplateColumn.CellTemplate> <DataTemplate> <Image Source="{Binding profileImage}" Width="50" Height="50" Margin="1"/> </DataTemplate> </data:DataGridTemplateColumn.CellTemplate> </data:DataGridTemplateColumn> <data:DataGridTextColumn Width="Auto" Header="User Name" Binding="{Binding UserName}" /> <data:DataGridTemplateColumn MinWidth="300" Width="Auto" Header="Status"> <data:DataGridTemplateColumn.CellTemplate> <DataTemplate> <TextBlock TextWrapping="Wrap" Text="{Binding Text}"/> </DataTemplate> </data:DataGridTemplateColumn.CellTemplate> </data:DataGridTemplateColumn> </data:DataGrid.Columns> </data:DataGrid> I’ve used only three columns – Profile image, Username, Status text. Now our Datagrid will look super cool like this. Coincidentally,  Tim Heuer is on the screenshot , who is a Silverlight Guru and works on SL team in Microsoft. His blog is really super. Here is the zipped file for all the xaml, xaml.cs & class files pages. Ok let us stop here for now, will look into implementing few more features in the next few posts and then I am going to look into developing a ASP.NET MVC 2 application. Hope you all liked this post. If you have any queries / suggestions feel free to comment below or contact me. Cheers! Technorati Tags: Silverlight,LINQ,Twitter API,Twitter,Silverlight 4

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  • css problem with unordered lists (as usual with IE)

    - by Emin
    I am using un-ordered lists that nests some divs to show the desired output on screen. I am using css to style them and they seem to look perfect on chrome and firefox. But in IE(8) it looks there is a problem which I was unable to locate. I am using the below CSS <style type="text/css"> .ur_container {width:980px; padding: 0; margin: 0;} .ur_container ul.bx_grp {list-style-type: none; padding: 0px; margin: 0px; } .ur_container ul.bx_lnx {list-style-type: none; padding: 5px; margin: 0px; } .bx_grp {border:1px solid #c5c5c5; background-color: yellow; margin:0; padding:0;} .bx_grp_header {background-color: #d6d6d6; border-bottom:1px solid #acacac;} .bx_grp_title {float: left; font: bold 11px Arial; padding:5px;} .bx_grp_options {float: right; font: 10px Arial; padding: 5px;} .bx_grp_options a{color: #125B93; text-decoration: none; } .bx_lnx {padding:0px; background-color: red;} .bx_lnx_header {font:11px Arial; color:#333;} .bx_lnx_title {float: left;} .bx_lnx_refno {background-color:#333; color: fff; padding: 1px; margin-right: 5px; } .bx_lnx_options {float: right;} .bx_lnx_options a {color: #258CF4; text-decoration: none;} .bx_lnx_url {font: 9px Arial; color: #999; margin-top: 4px; } .bx_lnx_notes {} .bx_lnx_notes span {background-color: #FDFFCC; color: #666; font: 9px Arial; padding:2px;} .bx_lnx_tags {} .bx_lnx_tags span {background-color: #efefef; border-bottom: 1px solid #ccc; color: #666; font: 9px Arial; padding: 1px 2px 1px 2px; margin-right: 5px;} </style> Against the following HTML <div class="ur_container"> <ul class="bx_grp" id="grp_1"> <li> <div class="bx_grp_header"> <span class="bx_grp_title">Personal File</span> <span class="bx_grp_options"><a href="#">rename</a> &bull; <a href="#">make private</a> &bull; <a href="#">hide</a href="#"> &bull; <a href="#">delete</a></span> <div style="clear: both;"></div> </div> </li> <li> <ul class="bx_lnx" id="lnx_1"> <li> <div class="bx_lnx_header"> <span class="bx_linx_title"><span class="bx_lnx_refno">#3103</span>How to file personal files</span> <span class="bx_lnx_options"><a href="#">edit</a> &bull; <a href="#">move</a> &bull; <a href="#">delete</a></span> </div> </li> <li class="bx_lnx_url">http://www.google.com</li> <li class="bx_lnx_notes"><span>search google for this</span></li> <li class="bx_lnx_tags"><span>personal</span><span>file</span><span>google</span></li> </ul> </li> </ul> </div> Which produces this output in Chrome and Fireworks and the following in IE The yellow and red colors was used in order to show that is being going wrong. The yellow part is the undesired one. Can anyone point me in the right direction please ? Regards

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  • Linked lists in Java - Help with writing methods

    - by user368241
    Representation of a string in linked lists In every intersection in the list there will be 3 fields : The letter itself. The number of times it appears consecutively. A pointer to the next intersection in the list. The following class CharNode represents a intersection in the list : public class CharNode { private char _data; private int _value; private charNode _next; public CharNode (char c, int val, charNode n) { _data = c; _value = val; _next = n; } public charNode getNext() { return _next; } public void setNext (charNode node) { _next = node; } public int getValue() { return _value; } public void setValue (int v) { value = v; } public char getData() { return _data; } public void setData (char c) { _data = c; } } The class StringList represents the whole list : public class StringList { private charNode _head; public StringList() { _head = null; } public StringList (CharNode node) { _head = node; } } Add methods to the class StringList according to the details : (I will add methods gradually according to my specific questions) (Pay attention, these are methods from the class String and we want to fulfill them by the representation of a string by a list as explained above) Pay attention to all the possible error cases. Write what is the time complexity and space complexity of every method that you wrote. Make sure the methods you wrote are effective. It is NOT allowed to use ready classes of Java. It is NOT allowed to move to string and use string operations. 1) public int indexOf (int ch) - returns the index in the string it is operated on of the first appeareance of the char "ch". If the char "ch" doesn't appear in the string, returns -1. If the value of fromIndex isn't in the range, returns -1. Here is my try : public int indexOf (int ch) { int count = 0; charNode pos = _head; if (pos == null ) { return -1; } for (pos = _head; pos!=null && pos.getData()!=ch; pos = pos.getNext()) { count = count + pos.getValue(); } if (pos==null) return -1; return count; } Time complexity = O(N) Space complexity = O(1) EDIT : I have a problem. I tested it in BlueJ and if the char ch doesn't appear it returns -1 but if it does, it always returns 0 and I don't understand why... I am confused. How can the compiler know that the value is the number of times the letter appears consecutively? Can I assume this because its given on the question or what? If it's true and I can assume this, then my code should be correct right? Ok I just spoke with my instructor and she said it isn't required to write it in the exercise but in order for me to test that it indeed works, I need to open a new class and write a code for making a list so that the the value of every node is the number of times the letter appears consecutively. Can someone please assist me? So I will copy+paste to BlueJ and this way I will be able to test all the methods. Meanwhile I am moving on to the next methods. 2) public int indexOf (int ch, int fromIndex) - returns the index in the string it is operated on of the first appeareance of the char "ch", as the search begins in the index "fromIndex". If the char "ch" doesn't appear in the string, returns -1. If the value of fromIndex doesn't appear in the range, returns -1. Here is my try: public int indexOf (int ch, int fromIndex) { int count = 0, len=0, i; charNode pos = _head; CharNode cur = _head; for (pos = _head; pos!=null; pos = pos.getNext()) { len = len+1; } if (fromIndex<0 || fromIndex>=len) return -1; for (i=0; i<fromIndex; i++) { cur = cur.getNext(); } if (cur == null ) { return -1; } for (cur = _head; cur!=null && cur.getData()!=ch; cur = cur.getNext()) { count = count + cur.getValue(); } if (cur==null) return -1; return count; } Time complexity = O(N) ? Space complexity = O(1) 3) public StringList concat (String str) - returns a string that consists of the string that it is operated on and in its end the string "str" is concatenated. Here is my try : public StringList concat (String str) { String str = ""; charNode pos = _head; if (str == null) return -1; for (pos = _head; pos!=null; pos = pos.getNext()) { str = str + pos.getData(); } str = str + "str"; return str; } Time complexity = O(N) Space complexity = O(1)

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  • CSS Hover on parent list Item only

    - by Daniel O'Connor
    Hey Everyone, So I have some nested lists (only one level deep) and I'm running into trouble with the CSS :hover feature. I only want the hover to apply to the parent class, but I can't figure that one out. Here's my CSS <style type="text/css" media="screen"> .listblock li img { visibility: hidden; } .listblock li:hover img { visibility: visible; } </style> And here is a sample of one of the lists. <ul> <li>One <a href="#"><img src="img/basket.png" height="16" width="16" alt="Buy" class="buy" onClick="pageTracker._trackEvent('Outbound Links', 'Amazon');"/></a></li> <li>Two <a href="#"><img src="img/basket.png" height="16" width="16" class="buy" /></a> <ul> <li>Uno<a href="#"><img src="img/basket.png" height="16" width="16" class="buy" /></a></li> <li>Dos <a href="#"><img src="img/basket.png" height="16" width="16" class="buy" /></a></li> </ul> </li> <li>Three <a href="#"><img src="img/basket.png" height="16" width="16" alt="Buy" class="buy" onClick="pageTracker._trackEvent('Outbound Links', 'Amazon');"/></a></li> </ul> The problem is that the image in the Uno and Dos list items also hovers. :( Help please! Thanks a lot

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  • Need help with copy constructor for very basic implementation of singly linked lists

    - by Jesus
    Last week, we created a program that manages sets of strings, using classes and vectors. I was able to complete this 100%. This week, we have to replace the vector we used to store strings in our class with simple singly linked lists. The function basically allows users to declare sets of strings that are empty, and sets with only one element. In the main file, there is a vector whose elements are a struct that contain setName and strSet (class). HERE IS MY PROBLEM: It deals with the copy constructor of the class. When I remove/comment out the copy constructor, I can declare as many empty or single sets as I want, and output their values without a problem. But I know I will obviously need the copy constructor for when I implement the rest of the program. When I leave the copy constructor in, I can declare one set, either single or empty, and output its value. But if I declare a 2nd set, and i try to output either of the first two sets, i get a Segmentation Fault. Moreover, if i try to declare more then 2 sets, I get a Segmentation Fault. Any help would be appreciated!! Here is my code for a very basic implementation of everything: Here is the setcalc.cpp: (main file) #include <iostream> #include <cctype> #include <cstring> #include <string> #include "help.h" #include "strset2.h" using namespace std; // Declares of structure to hold all the sets defined struct setsOfStr { string nameOfSet; strSet stringSet; }; // Checks if the set name inputted is unique bool isSetNameUnique( vector<setsOfStr> strSetArr, string setName) { for(unsigned int i = 0; i < strSetArr.size(); i++) { if( strSetArr[i].nameOfSet == setName ) { return false; } } return true; } int main(int argc, char *argv[]) { char commandChoice; // Declares a vector with our declared structure as the type vector<setsOfStr> strSetVec; string setName; string singleEle; // Sets a loop that will constantly ask for a command until 'q' is typed while (1) { // declaring a set to be empty if(commandChoice == 'd') { cin >> setName; // Check that the set name inputted is unique if (isSetNameUnique(strSetVec, setName) == true) { strSet emptyStrSet; setsOfStr set1; set1.nameOfSet = setName; set1.stringSet = emptyStrSet; strSetVec.push_back(set1); } else { cerr << "ERROR: Re-declaration of set '" << setName << "'\n"; } } // declaring a set to be a singleton else if(commandChoice == 's') { cin >> setName; cin >> singleEle; // Check that the set name inputted is unique if (isSetNameUnique(strSetVec, setName) == true) { strSet singleStrSet(singleEle); setsOfStr set2; set2.nameOfSet = setName; set2.stringSet = singleStrSet; strSetVec.push_back(set2); } else { cerr << "ERROR: Re-declaration of set '" << setName << "'\n"; } } // using the output function else if(commandChoice == 'o') { cin >> setName; if(isSetNameUnique(strSetVec, setName) == false) { // loop through until the set name is matched and call output on its strSet for(unsigned int k = 0; k < strSetVec.size(); k++) { if( strSetVec[k].nameOfSet == setName ) { (strSetVec[k].stringSet).output(); } } } else { cerr << "ERROR: No such set '" << setName << "'\n"; } } // quitting else if(commandChoice == 'q') { break; } else { cerr << "ERROR: Ignoring bad command: '" << commandChoice << "'\n"; } } return 0; } Here is the strSet2.h: #ifndef _STRSET_ #define _STRSET_ #include <iostream> #include <vector> #include <string> struct node { std::string s1; node * next; }; class strSet { private: node * first; public: strSet (); // Create empty set strSet (std::string s); // Create singleton set strSet (const strSet &copy); // Copy constructor // will implement destructor later void output() const; strSet& operator = (const strSet& rtSide); // Assignment }; // End of strSet class #endif // _STRSET_ And here is the strSet2.cpp (implementation of class) #include <iostream> #include <vector> #include <string> #include "strset2.h" using namespace std; strSet::strSet() { first = NULL; } strSet::strSet(string s) { node *temp; temp = new node; temp->s1 = s; temp->next = NULL; first = temp; } strSet::strSet(const strSet& copy) { cout << "copy-cst\n"; node *n = copy.first; node *prev = NULL; while (n) { node *newNode = new node; newNode->s1 = n->s1; newNode->next = NULL; if (prev) { prev->next = newNode; } else { first = newNode; } prev = newNode; n = n->next; } } void strSet::output() const { if(first == NULL) { cout << "Empty set\n"; } else { node *temp; temp = first; while(1) { cout << temp->s1 << endl; if(temp->next == NULL) break; temp = temp->next; } } } strSet& strSet::operator = (const strSet& rtSide) { first = rtSide.first; return *this; }

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  • User cannot Add or Remove people from a distribution list using outlook.

    - by Matt
    Recently we moved across a user and a distribution list from Exchange 2003 to 2010. The user used to be able to add and remove from a distribution list within Outlook. I have added them to the Managed by list in Exchange in the distribution list, but to no avail. They are getting an error message saying You do not have the sufficient permissions to perform this operation on this object. I cannot seem to find the setting to allow the user permissions.

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  • What system of administrative e-mail addresses does your organization use?

    - by Draco Flangetastic
    I'm getting ready to request a new batch of administrative e-mail addresses to replace an outdated hierarchy within my organization. I have the opportunity of choosing new aliases for 24/7 alert recipients, monitoring recipients, all team members, etc. What does your org use for these purposes? Groups in my org use things like: org-dept@, org-dept-all@, org-dept-alert@, org-dept-monitoring@, org-dept-status@. TIA!!!!!111

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  • creating iTunes listing INCLUDING "Where" information

    - by Hugh
    Although iTunes produces a very good comprehensive listing of all music which can be copied and pasted into excel to give a database of music, unfortunately it does not include"where" information as shown on the "Get Info" summary. As, in my own case, music files are in a number of different locations(drives and folders) I would like to be able to identify, quickly and simply,duplicate tracks as the last column in the excel listing. Is there a way to do this?

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  • How do I make a LDAP query-based dynamic distribution group in Exchange 2010

    - by blsub6
    I see that there were ways in Exchange 2003 and Exchange 2007 to just put in an LDAP query and it would populate the group for you. Is there any way to do that in Exchange 2010? I know there's dynamic distribution groups but I don't want to create the group based on one of their pre-set queries and I don't want to mess around with "custom attributes". I just want to put an LDAP query in there and make it run it to populate the distribution group.

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  • How to create custom rss feed generator (sharepoint 2010)?

    - by user362194
    I need to create RSS, that include all sharepoint lists and pages. Sharepoint gives "http://localhost/_layouts/listfeed.aspx?List={0251B48D-9D09-4C94-8D33-8A4589C57EC8}&Source=http%3A%2F%2Flocalhost%2FPages%2FForms%2FAllItems.aspx" "http://localhost/_layouts/feed.aspx?xsl=1&web=%2F&page=122705e9-4542-4e65-b001-81ea8699c5bd&wp=922036c8-5d01-4a89-8cd6-65b308095451&pageurl=SitePages%2FTempPage.aspx" How to produce one rss for all site content?

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  • What is the minimum interface that has the Count property in .Net

    - by SoMoS
    Hello, I need to change a method that has one parameter that takes a serie of objects. I need to find the lowest Interface (in inheritance tree) that has the Count property. Until now I was using the IEnumerable but as this has not Count I need to change it to the wider interface possible so the method can work with the biggest number of types of series (collections, lists, arrays, etc). Thanks in advance.

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  • HTML: Menus as UL instead of DIVs?

    - by JamesBrownIsDead
    I recently created a menu for a web page where buttons are DIV elements. I've been Googling around and see that many people create UL lists and each button is a LI element. What benefit is using an UL and LIs instead of just DIVs? Is it somehow better for SEO? Does this have to do with "semantic" markup? Any compelling reason to rewrite my menu as a UL?

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  • How do I get user input to refer to a variable in Python?

    - by somefreakingguy
    I would like to get user input to refer to some list in my code. I think it's called namespace? So, what would I have to do to this code for me to print whatever the user inputs, supposing they input 'list1' or 'list2'? list1 = ['cat', 'dog', 'juice'] list2 = ['skunk', 'bats', 'pogo stick'] x = raw_input('which list would you like me to print?') I plan to have many such lists, so a series of if...then statements seems unruly.

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  • LinkedList parameters in Java

    - by Walt
    Hi there, I created a program that contains linked lists that are passed various methods. While this works just fine in Java... a style checker program we have to use doesn't like it It says: Declaring variables, return values or parameters of type 'LinkedList' is not allowed. If I declare them as simply List then I don't have access to the methods I want. What should I do?

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  • How should I write this string-prefix check so that it's idiomatic Python?

    - by Kevin Stargel
    I have a couple of lists of items: specials = ['apple', 'banana', 'cherry', ...] smoothies = ['banana-apple', 'mocha mango', ...] I want to make a new list, special_smoothies, consisting of elements in smoothies that start with the elements in specials. However, if specials is blank, special_smoothies should be identical to smoothies. What's the most Pythonic way to do this? Is there a way to do this without a separate conditional check on whether specials is blank?

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  • Splitting a list in python

    - by blob8108
    Hi, I'm writing a parser in Python. I've converted an input string into a list of tokens, such as: ['(', '2', '.', 'x', '.', '(', '3', '-', '1', ')', '+', '4', ')', '/', '3', '.', 'x', '^', '2'] I want to be able to split the list into multiple lists, like the str.split('+') function. But there doesn't seem to be a way to do my_list.split('+'). Any ideas? Thanks!

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  • jQuery UI Drag/Drop does not work in FF

    - by nolabel
    I've been looking all over the place, but I haven't landed an answer yet. Is the current jQuery UI 1.8-1.8.2 supports Firefox 3+? I have 3.6.3 installed, but the example on their websites works for my IE7, IE8, Chrome, but not Firefox. http://jqueryui.com/demos/sortable/#connect-lists

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  • python: list manipulation

    - by Jason S
    I have a list L of objects (for what it's worth this is in scons). I would like to create two lists L1 and L2 where L1 is L with an item I1 appended, and L2 is L with an item I2 appended. I would use append but that modifies the original list. How can I do this in Python? (sorry for the beginner question, I don't use the language much, just for scons)

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  • Start a list from a certain number

    - by Colin
    What's the best way to get a ul to start from 'x'? The start tag is depricated and everything I have found on Google has used the :before pseudo class which doesn't work in IE6 or 7. Didn't have much luck when searching stack either. Only thing I can think of is manually go through and number the lists myself and style accordingly? Any help appreciated.

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  • JPQL IN clause: Java-Arrays (or Lists, Sets...)?

    - by Bernd Haug
    I would like to load all objects that have a textual tag set to any of a small but arbitrary number of values from our database. The logical way to go about this in SQL would be to build an "IN" clause. JPQL allows for IN, but it seems to require me to specify every single parameter to IN directly (as in, "in (:in1, :in2, :in3)"). Is there some way to specify an array, or a list (or some other container) that should be unrolled to the values of an IN clause?

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