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  • python destructuring-bind dictionary contents

    - by Stephen
    Hi, I am trying to 'destructure' a dictionary and associate values with variables names after its keys. Something like params = {'a':1,'b':2} a,b = params.values() but since dictionaries are not ordered, there is no guarantee that params.values() will return values in the order of (a,b). Is there a nice way to do this? Thanks

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  • javascript-aware html parser for Python ~

    - by znetor
    <html> <head> <script type="text/javascript"> document.write('<a href="http://www.google.com">f*** js</a>'); document.write("f*** js!"); </script> </head> <body> <script type="text/javascript"> document.write('<a href="http://www.google.com">f*** js</a>'); document.write("f*** js!"); </script> <div><a href="http://www.google.com">f*** js</a></div> </body> </html> I want use xpath to catch all lable object in the html page above... In [1]: import lxml.html as H In [2]: f = open("test.html","r") In [3]: c = f.read() In [4]: doc = H.document_fromstring(c) In [5]: doc.xpath('//a') Out[5]: [<Element a at a01d17c>] In [6]: a = doc.xpath('//a')[0] In [7]: a.getparent() Out[7]: <Element div at a01d41c> I only get one don't generate by js~ but firefox xpath checker can find all lable!? http://i.imgur.com/0hSug.png how to do that??? thx~! <html> <head> </head> <body> <script language="javascript"> function over(){ a.innerHTML="mouse me" } function out(){ a.innerHTML="<a href='http://www.google.com'>google</a>" } </script> <body><li id="a"onmouseover="over()" onmouseout="out()">mouse me</li> </body> </html>

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  • Python method to remove iterability

    - by Debilski
    Suppose I have a function which can either take an iterable/iterator or a non-iterable as an argument. Iterability is checked with try: iter(arg). Depending whether the input is an iterable or not, the outcome of the method will be different. Not when I want to pass a non-iterable as iterable input, it is easy to do: I’ll just wrap it with a tuple. What do I do when I want to pass an iterable (a string for example) but want the function to take it as if it’s non-iterable? E.g. make that iter(str) fails.

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  • Python and sqlite3 - importing and exporting databases

    - by JPC
    I'm trying to write a script to import a database file. I wrote the script to export the file like so: import sqlite3 con = sqlite3.connect('../sqlite.db') with open('../dump.sql', 'w') as f: for line in con.iterdump(): f.write('%s\n' % line) Now I want to be able to import that database. I tried: import sqlite3 con = sqlite3.connect('../sqlite.db') f = open('../dump.sql','r') str = f.read() con.execute(str) but I'm not allowed to execute more than one statement. Is there a way to get it to run a .sql script directly?

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  • Unicode filename to python subprocess.call()

    - by otrov
    I'm trying to run subprocess.call() with unicode filename, and here is simplified problem: n = u'c:\\windows\\notepad.exe ' f = u'c:\\temp\\nèw.txt' subprocess.call(n + f) which raises famous error: UnicodeEncodeError: 'ascii' codec can't encode character u'\xe8' Encoding to utf-8 produces wrong filename, and mbcs passes filename as new.txt without accent I just can't read any more on this confusing subject and spin in circle. I found here lot of answers for many different problems in past so I thought to join and ask for help myself Thanks

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  • speed up calling lot of entities, and getting unique values, google app engine python

    - by user291071
    OK this is a 2 part question, I've seen and searched for several methods to get a list of unique values for a class and haven't been practically happy with any method so far. So anyone have a simple example code of getting unique values for instance for this code. Here is my super slow example. class LinkRating2(db.Model): user = db.StringProperty() link = db.StringProperty() rating2 = db.FloatProperty() def uniqueLinkGet(tabl): start = time.time() dic = {} query = tabl.all() for obj in query: dic[obj.link]=1 end = time.time() print end-start return dic My second question is calling for instance an iterator instead of fetch slower? Is there a faster method to do this code below? Especially if the number of elements called be larger than 1000? query = LinkRating2.all() link1 = 'some random string' a = query.filter('link = ', link1) adic ={} for itema in a: adic[itema.user]=itema.rating2

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  • building a pairwise matrix in scipy/numpy in Python from dictionaries

    - by user248237
    I have a dictionary whose keys are strings and values are numpy arrays, e.g.: data = {'a': array([1,2,3]), 'b': array([4,5,6]), 'c': array([7,8,9])} I want to compute a statistic between all pairs of values in 'data' and build an n by x matrix that stores the result. Assume that I know the order of the keys, i.e. I have a list of "labels": labels = ['a', 'b', 'c'] What's the most efficient way to compute this matrix? I can compute the statistic for all pairs like this: result = [] for elt1, elt2 in itertools.product(labels, labels): result.append(compute_statistic(data[elt1], data[elt2])) But I want result to be a n by n matrix, corresponding to "labels" by "labels". How can I record the results as this matrix? thanks.

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  • Python for statement giving an Invalid Syntax error with list

    - by Cold Diamondz
    I have some code in which is throwing an error (I'm using repl.it) import random students = ['s1:0','s2:0','s3:0'] while True: print'\n'*50 print'Ticket Machine'.center(80) print'-'*80 print'1. Clear Student Ticket Values'.center(80) print'2. Draw Tickets'.center(80) menu = raw_input('-'*80+'\nChoose an Option: ') if menu == '1': print'\n'*50 print'CLEARED!' students = ['s1:0','s2:0','s3:0'] raw_input('Press enter to return to the main menu!') elif menu == '2': tickets = [] print'\n'*50 times = int(raw_input('How many tickets to draw? ') for a in students: for i in range(a.split(':')[1]): tickets.append(a.split(':')[0]) for b in range(1,times+1): print str(b) + '. ' + random.choice(tickets) else: print'\n'*50 print'That was not an option!' raw_input('Press enter to return to the main menu!') But it is throwing this error: File "<stdin>", line 19 for a in students: ^ SyntaxError: invalid syntax I am planning on using this in a class, but I can't use it until the bug is fixed, also, student names have been removed for privacy reasons.

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  • Join a list of lists together into 1 list in Python

    - by dotty
    Hay All. I have a list which consists of many lists, here is an example [ [Obj, Obj, Obj, Obj], [Obj], [Obj], [ [Obj,Obj], [Obj,Obj,Obj] ] ] Is there a way to join all these items together as 1 list, so the output will be something like [Obj,Obj,Obj,Obj,Obj,Obj,Obj,Obj,Obj,Obj,Obj] Thanks

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  • Easy Python input question

    - by Josh K
    I'd like to have something similar to the following pseudo code: while input is not None and timer < 5: input = getChar() timer = time.time() - start if timer >= 5: print "took too long" else: print input Anyway to do this without threading? I would like an input method that returns whatever has been entered since the last time it was called, or None (null) if nothing was entered.

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  • encapsulation in python list (want to use " instead of ')

    - by Codehai
    I have a list of users users["pirates"] and they're stored in the format ['pirate1','pirate2']. If I hand the list over to a def and query for it in MongoDB, it returns data based on the first index (e.g. pirate1) only. If I hand over a list in the format ["pirate1","pirate"], it returns data based on all the elements in the list. So I think there's something wrong with the encapsulation of the elements in the list. My question: can I change the encapsulation from ' to " without replacing every ' on every element with a loop manually? Short Example: aList = list() # get pirate Stuff # users["pirates"] is a list returned by a former query # so e.g. users["pirates"][0] may be peter without any quotes for pirate in users["pirates"]: aList.append(pirate) aVar = pirateDef(aList) print(aVar) the definition: def pirateDef(inputList = list()): # prepare query col = mongoConnect().MYCOL # query for pirates Arrrr pirates = col.find({ "_id" : {"$in" : inputList}} ).sort("_id",1).limit(50) # loop over users userList = list() for person in pirates: # do stuff that has nothing to do with the problem # append user to userlist userList.append(person) return userList If the given list has ' encapsulation it returns: 'pirates': [{'pirate': 'Arrr', '_id': 'blabla'}] If capsulated with " it returns: 'pirates' : [{'_id': 'blabla', 'pirate' : 'Arrr'}, {'_id': 'blabla2', 'pirate' : 'cheers'}] EDIT: I tried figuring out, that the problem has to be in the MongoDB query. The list is handed over to the Def correctly, but after querying pirates only consists of 1 element... Thanks for helping me Codehai

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  • python feedparser with yahoo weather rss

    - by mudder
    I'm trying to use feedparser to get some data from yahoos weather rss. It looks like feed parser strips out the yweather namespace data: http://weather.yahooapis.com/forecastrss?w=24260013&u=c <yweather:condition text="Fair" code="34" temp="23" date="Wed, 19 May 2010 5:55 pm EDT" /> looks like feedparser is completely ignoring that. is there away to get it?

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  • Help with python list-comprehension

    - by leChuck
    A simplified version of my problem: I have a list comprehension that i use to set bitflags on a two dimensional list so: s = FLAG1 | FLAG2 | FLAG3 [[c.set_state(s) for c in row] for row in self.__map] All set_state does is: self.state |= f This works fine but I have to have this function "set_state" in every cell in __map. Every cell in __map has a .state so what I'm trying to do is something like: [[c.state |= s for c in row] for row in self.map] or map(lambda c: c.state |= s, [c for c in row for row in self.__map]) Except that neither works (Syntax error). Perhaps I'm barking up the wrong tree with map/lamda but I would like to get rid on set_state. And perhaps know why assignment does not work in the list-comprehension

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  • Python: find <title>

    - by Peter
    I have this: response = urllib2.urlopen(url) html = response.read() begin = html.find('<title>') end = html.find('</title>',begin) title = html[begin+len('<title>'):end].strip() if the url = http://www.google.com then the title have no problem as "Google", but if the url = "http://www.britishcouncil.org/learning-english-gateway" then the title become "<!doctype html public "-//W3C//DTD HTML 4.0 Transitional//EN"> <HTML> <HEAD> <base href="http://www.britishcouncil.org/" /> <META http-equiv="Content-Type" Content="text/html;charset=utf-8"> <meta name="WT.sp" content="Learning;Home Page Smart View" /> <meta name="WT.cg_n" content="Learn English Gateway" /> <META NAME="DCS.dcsuri" CONTENT="/learning-english-gateway.htm">..." What is actually happening, why I couldn't return the "title"?

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  • Custom constructors for models in Google App Engine (python)

    - by Nikhil Chelliah
    I'm getting back to programming for Google App Engine and I've found, in old, unused code, instances in which I wrote constructors for models. It seems like a good idea, but there's no mention of it online and I can't test to see if it works. Here's a contrived example, with no error-checking, etc.: class Dog(db.Model): name = db.StringProperty(required=True) breeds = db.StringListProperty() age = db.IntegerProperty(default=0) def __init__(self, name, breed_list, **kwargs): db.Model.__init__(**kwargs) self.name = name self.breeds = breed_list.split() rufus = Dog('Rufus', 'spaniel terrier labrador') rufus.put() The **kwargs are passed on to the Model constructor in case the model is constructed with a specified parent or key_name, or in case other properties (like age) are specified. This constructor differs from the default in that it requires that a name and breed_list be specified (although it can't ensure that they're strings), and it parses breed_list in a way that the default constructor could not. Is this a legitimate form of instantiation, or should I just use functions or static/class methods? And if it works, why aren't custom constructors used more often?

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  • (Python) Converting a dictionary to a list?

    - by Daria Egelhoff
    So I have this dictionary: ScoreDict = {"Blue": {'R1': 89, 'R2': 80}, "Brown": {'R1': 61, 'R2': 77}, "Purple": {'R1': 60, 'R2': 98}, "Green": {'R1': 74, 'R2': 91}, "Red": {'R1': 87, 'Lon': 74}} Is there any way how I can convert this dictionary into a list like this: ScoreList = [['Blue', 89, 80], ['Brown', 61, 77], ['Purple', 60, 98], ['Green', 74, 91], ['Red', 87, 74]] I'm not too familiar with dictionaries, so I really need some help here. Thanks in advance!

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  • Python - List and Loop in one def

    - by Dunwitch
    I'm trying to get the def wfsc_pod1 and wfsc_ip into the same def. I'm not quite sure how to approach the problem. I want wfsc_pod1 to display all the information for name, subnet and gateway. Then wfsc_ip shows the ip addresses below it. I also get a None value when I run it as it. Not sure why. Anything more pythonic is more appreciated. class OutageAddress: subnet = ["255.255.255.0", "255.255.255.1"] # Gateway order is matched with names gateway = ["192.168.1.1", "192.168.1.2", "192.168.1.3", "192.168.1.4", "192.168.1.5", "192.168.1.6", "192.168.1.7", "192.168.1.8", "192.168.1.9"] name = ["LOC1", "LOC2", "LOC3", "LOC4", "LOC5", "LOC6", "LOC7", "LOC8", "LOC9"] def wfsc_pod1(self): wfsc_1 = "%s\t %s\t %s\t" % (network.name[0],network.subnet[0],network.gateway[0]) return wfsc_1 def wfsc_ip(self): for ip in range(100,110): ip = "192.168.1."+str(ip) print ip network = OutageAddress() print network.wfsc_pod1() print network.wfsc_ip()

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  • Python: eliminating stack traces into library code?

    - by Mark Harrison
    When I get a runtime exception from the standard library, it's almost always a problem in my code and not in the library code. Is there a way to truncate the exception stack trace so that it doesn't show the guts of the library package? For example, I would like to get this: Traceback (most recent call last): File "./lmd3-mkhead.py", line 71, in <module> main() File "./lmd3-mkhead.py", line 66, in main create() File "./lmd3-mkhead.py", line 41, in create headver1[depotFile]=rev TypeError: Data values must be of type string or None. and not this: Traceback (most recent call last): File "./lmd3-mkhead.py", line 71, in <module> main() File "./lmd3-mkhead.py", line 66, in main create() File "./lmd3-mkhead.py", line 41, in create headver1[depotFile]=rev File "/usr/anim/modsquad/oses/fc11/lib/python2.6/bsddb/__init__.py", line 276, in __setitem__ _DeadlockWrap(wrapF) # self.db[key] = value File "/usr/anim/modsquad/oses/fc11/lib/python2.6/bsddb/dbutils.py", line 68, in DeadlockWrap return function(*_args, **_kwargs) File "/usr/anim/modsquad/oses/fc11/lib/python2.6/bsddb/__init__.py", line 275, in wrapF self.db[key] = value TypeError: Data values must be of type string or None.

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  • networking application and GUI in python

    - by pygabriel
    I'm writing an application that sends files over network, I want to develop a custom protocol to not limit myself in term on feature richness (http wouldn't be appropriate, the nearest thing is the bittorrent protocol maybe). I've tried with twisted, I've built a good app but there's a bug that makes my GUI blocking, so I've to switch to another framework/strategy. What do you suggest? Using raw sockets and using gtk mainloop (there are select-like functions in the toolkit) is too much difficult? It's viable running two mainloops in different threads? Asking for suggestions

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  • Python If Statement Defaults to an elif

    - by Brad Carvalho
    Not sure why my code is defaulting to this elif. But it's never getting to the else statement. Even going as far as throwing index out of bound errors in the last elif. Please disregard my non use of regex. It wasn't allowed for this homework assignment. The problem is the last elif before the else statement. Cheers, Brad if item == '': print ("%s\n" % item).rstrip('\n') elif item.startswith('MOVE') and not item.startswith('MOVEI'): print 'Found MOVE' elif item.startswith('MOVEI'): print 'Found MOVEI' elif item.startswith('BGT'): print 'Found BGT' elif item.startswith('ADD'): print 'Found ADD' elif item.startswith('INC'): print 'Found INC' elif item.startswith('SUB'): print 'Found SUB' elif item.startswith('DEC'): print 'Found DEC' elif item.startswith('MUL'): print 'Found MUL' elif item.startswith('DIV'): print 'Found DIV' elif item.startswith('BEQ'): print 'Found BEQ' elif item.startswith('BLT'): print 'Found BLT' elif item.startswith('BR'): print 'Found BR' elif item.startswith('END'): print 'Found END' elif item.find(':') and item[(item.find(':') -1)].isalpha(): print 'Mya have found a label' else: print 'Not sure what I found'

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