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  • Have optical drive connectors changed in the last year?

    - by Zippityboomba
    In early 2010 my motherboard freaked out, and I was able to drop in a new board and connect my two DVD drives that were initially bought in 2005. Tonight my new components arrived to build my next system, and I figured I'd just reuse the old DVD drives. Surprise, the long flat connector cable has no mate on the new motherboard. Reckon I'll just pick up a new DVD drive for $25, but what gives? Thanks!

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  • Like to Upgrade My PC (7 year old) - for animation and hardcore gaming ! - help me [closed]

    - by sri
    I like to buy a new computer for my studies and as well as gaming. My old pc has 1.5 GB RAM with 512MB Graphics card. And it is very old to run Adobe CS5 version and other high end animation software. My budget will be INR 20k-25k. I have 500GB hard disk, keyboard and mouse new. So apart from this, I like to buy : Intel or AMD is good ? My idea is : Corei5 or Corei7 = which is best and economy ? Which mother board. 4 GB RAM with upto 8 GB RAM slot for future upgrade. 1 GB or 2 GB Graphic card - which one ? If I am wrong - please suggest me

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  • Skype Mac API - Use AppleScript or 5 year old API?

    - by Andrew
    I have a x86_64 app that I would like to have optionally read Skype status messages. However, the 5 year old skype mac framework is 32-bit, and if there is a way to have that compile within a 64-bit app, I haven't found it. My question is, basically, how should I go about doing this? I really only need to get and set the USERSTATUS AWAY/ONLINE string. Using AppleScript, a "Should Skype allow this" dialog pops up... every time. This is highly inefficient and downright irritating. Advice? I'm considering writing a 32-bit CLI wrapper, but that seems like overkill.

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  • How do I check the validity of the Canadian Social Insurance Number in C#?

    - by user518307
    I've been given the assignment to write an algorithm in C# that checks the validity of a Canadian Social Insurance Number (SIN). Here are the steps to validate a SIN. Given an example Number: 123 456 782 Remove the check digit (the last digit): 123456782 Extract the even digits (2,4,6,8th digith): 12345678 Double them: 2 4 6 8 | | | | v v v v 4 8 12 16 Add the digits together: 4+8+1+2+1+6 = 22 Add the Odd placed digits: 1+3+5+7 = 16 Total : 38 Validity Algorithm If the total is a multiple of 10, the check digit should be zero. Otherwise, Subtract the Total from the next highest multiple of 10 (40 in this case) The check digit for this SIN must be equal to the difference of the number and the totals from earlier (in this case, 40-38 = 2; check digit is 2, so the number is valid) I'm lost on how to actually implement this in C#, how do I do this?

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  • What production software have you written in F# in the past year or so that you would previously hav

    - by Peter McGrattan
    Over the last few years F# has evolved into one of Microsoft's fully supported languages employing many ideas incubated in OCaml, ML and Haskell. Over the last several years C# has extended it's general purpose features by introducing more and more functional language features: LINQ (list comprehension), Lamdas, Closures, Anonymous Delegates and more... Given C#'s adoption of these functional features and F#'s taxonomy as an impure functional language (it allows YOU to access framework libraries or change shared state when a function is called if you want to) there is a strong similarity between the two languages although each has it's own polar opposite primary emphasis. I'm interested in any successful models employing these two languages in your production polyglot programs and also the areas within production software (web apps, client apps, server apps) you have written in F# in the past year or so that you would previously have written in C#.

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  • where to store information like gender and year of birth?

    - by fayer
    i have users and i need them to specify a gender (male, female) and year of birth (1930, 1931...1999, 2000). i wonder where i should store these values: in the database? in php file? if i store them in the database i have to manually create all entries first. but a good thing is that the user table will have constraints so the gender field will always be male or female, it cannot be something else. if i store them in the php file (eg. as html) then i can easily add/remove values. but a con is that i dont have the constraints in database, so another value could be stored as gender by mistake, even though i could add validation in php backend so even if someone hacked the html it is not stored unless it's either male or female. what is best practice to do this? thanks

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  • The script not working as expected files dump path

    - by user3319390
    I have a script needs to be dump matching cname from my file contains and then matching scode to dump file to $cname/$year/$month/$day/ into files like access and error logs #!/bin/sh #base_dir="/home/vizion/Desktop" path="/home/vizion/Desktop/adn_DF9D_20140515_0005.log" name=$(basename "$path" ".log") for x in *.log; do year=${x:9:4}; month=${x:13:2}; day=${x:15:2}; done while read -r line do cname=$(echo ${line} | awk '{split($7,c,"/"); print c[3]}') scode=$(echo ${line} | awk -F"[ ]" '{print $9}') [[ ! -d "$cname/$year/$month/$day" ]] && mkdir -p "$cname/$year/$month/$day/" [[ ( ${scode} -ge 200 ) && ( ${scode} -le 399 ) ]] && { # [[ ! -d "$cname/$year/$month/$day" ]] && mkdir -p "$cname/$year/$month/$day/" echo ${line} >> /home/vizion/Desktop/$cname/$year/$month/$day/${cname}_${name}_access.log } [[ ( ${scode} -ge 400 ) && ( ${scode} -le 599 ) ]] && { [[ ! -d "$cname/$year/$month/$day" ]] && mkdir -p "$cname/$year/$month/$day" echo ${line} >> ${cname}_${name}_error.log } done < $path i am able to filter logs but not not dumping the exact location It's going other locations suggest to me correction in script

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  • Is your Credit Card Number valid?

    - by Rekha
    The credit card numbers may look like some random unique 16 digits number but those digits inform more than what we think it could be. The first digit of the card is the Major Industry Identifier: 1 and 2 -  Airlines 3  – Travel and Entertainment 4 and 5 -  Banking and Financial 6 – Merchandizing and Banking 7 – Petroleum 8 – Telecommunications 9 – National assignment The first 6 digits represent the Issuer Identification Number: Visa – 4xxxxx Master Card – 51xxxx & 55xxxx The 7th and following digits, excluding the last digit, are the person’s account number which leads to trillion possible combinations if the maximum of 12 digits is used. Many cards only use 9 digits. The final digit is the checksum or check digit. It is used to validate the card number using Luhn algorithm. How To Validate Credit Card Number? Take any credit card number, for example 5588 3201 2345 6789. Step 1: Double every other digit from the right: 5*2      8*2      3*2      0*2      2*2      4*2      6*2      8*2 ————————————————————————- 10        16        6          0          4          8      12        16 Step 2: Add these new digits to undoubled digits. All double digit numbers are added as a sum of their digits, so 16 becomes 1+6 = 7: Undoubled digits:       5          8          2          1          3          5          7          9 Doubled Digits:          10       16         6          0          4          8         12         16 Sum:  5+1+0+8+1+6+2+6+1+0+3+4+5+8+7+1+2+9+1+6 = 76 If the final sum is divisible by 10, then the Credit Card number is valid, if not, the number is invalid or fake!!! Hence the example is a fake number? via mint  cc and image credit This article titled,Is your Credit Card Number valid?, was originally published at Tech Dreams. Grab our rss feed or fan us on Facebook to get updates from us.

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  • Die glücklichen Gewinner der Oracle Partner Awards Germany 2012

    - by A&C Redaktion
    Es war ein Höhepunkt des Oracle Partner Days: Die Award Ceremony, auf der deutsche Oracle Partner für ihr besonderes Engagement und herausragende Erfolge bei der Spezialisierung ausgezeichnet wurden. Jeder Preisträger erhielt neben dem Award eine Urkunde sowie einen Wertscheck in Höhe von 2.000 Euro für eine Demand Generation Kampagne. Wir gratulieren allen Gewinnern ganz herzlich und stellen sie Ihnen im Folgenden kurz vor:Database Partner of the Year Germany: inforsacom Informationssysteme GmbHDass der EMEA Database Partner of the Year inforsacom auch im bundesweiten Vergleich überzeugen würde, war keine große Überraschung, ist aber ein Riesenerfolg! Übrigens war inforsacom auch schon 2011 unter den Preisträgern des OPN Day Satellite (wir berichteten). Der Platinum Partner inforsacom Informationssysteme GmbH entwickelt und liefert seit 1997 integrierte IT-Lösungen im Data-Center. Als „trusted advisor“ ist es ein Schwerpunkt von Inforsacom, in der Beratung den größtmöglichen Kundennutzen aufzuzeigen. inforsacom setzt einen deutlichen Fokus auf Oracle Datenbanktechnologien sowie das Hardware und Engineered Systems Portfolio -  inklusive der damit verbundenen Spezialisierung und Ausbildung der Mitarbeiter. Middleware Partner of the Year Germany: People at Work Systems AGZum Middleware Partner of the Year wurde die People at Work Systems AG gekürt, ein Software- und Beratungsunternehmen aus München, das  Kunden individuelle Dienstleistungen und Lösungen für Customer Relationship Management (CRM) und  Business Process Management (BPM) auf der Basis von Oracle anbietet. Seit Jahren zeigt der Oracle Partner ein hohes Commitment zu Oracle, unter anderem durch sein umfassendes Engagement im Rahmen der Solution Partner Community SOA. Die große technologische und vertriebliche Kompetenz in Sachen BPM, SOA & Integration hat die People at Work GmbH in verschiedenen komplexen Fusion Middleware-Projekten erfolgreich unter Beweis gestellt. Applications Partner of the Year Germany: ifb AGDie ifb-group deckt als einer der wenigen Partner das komplette Hyperion, Oracle EPM und BI Portfolio ab. Dabei ist das Markenzeichen der ifb die enge Verbindung von Fachexpertise und Umsetzungsstärke, denn weltweit setzen über 800 Unternehmen seit vielen Jahren erfolgreich auf Lösungen der ifb. Der Award „Applications Partner of the Year“ würdigt die Spezialisierung der ifb auf EPM. Industry Partner of the Year Germany: PORTRIX LOGISTIC SOFTWARE GmbHÜber den Preis als bester Industry Partner freute sich die PORTRIX LOGISTIC SOFTWARE GmbH aus Hamburg, eine Tochter der portrix.net GmbH. Mit einer eigenen Software-Lösung bietet der ISV Speditionen eine Lösung an, die die Abrechnung und Transparenz von Vertragskonditionen über die ganze Transportkette hinweg vereinfacht. Die Unternehmensgruppe portrix.net ist mit mehr als vier Spezialisierungen mit sehr gutem Oracle Know-how ausgestattet und somit in der Lage, zu unterschiedlichsten Anforderungen von Endkunden und Oracle Partnern exzellent zu beraten. Oracle Accelerate Partner of the Year Germany: ICP Solution GmbHICP Solution unterstützt als "One-Stop-Shop" auf dem europäischen Markt Kunden in allen Fragen rund um PLM und Agile von Oracle. Das Leistungsspektrum reicht dabei von der Prozessoptimierung und PLM Einführung, über ERP Integration bis hin zum Wartungsvertrag und speziellen Schulungen.Server & Storage Systems Partner of the Year Germany: CCF AGDie CCF AG ist schon seit 19 Jahren ein überzeugter Sun/Oracle Partner, der ca. 90% seines Umsatzes mit Sun/Oracle Produkten macht. Als flexibles regionales Unternehmen mit angeschlossener Consulting Firma, die auf Solaris und Unix spezialisiert ist, ist die CCF einer der wenigen Oracle Partner mit eigenen Solaris Administratoren. Der Award würdigt auch die herausragenden Umsatzergebnisse von CCF im Hardware Segment.Oracle on Oracle Partner of the Year Germany: anykey GmbHAuch ankey ist bereits ein langjähriger Partner von Sun/Oracle und verfügt über hohes Consulting-Know-how. 2012 ist anykey richtig durchgestartet: Viele Zertifizierungen sowie Datenbankspezialisierung wurden erworben und der Platinum Partner hat sich damit den Bereich „Oracle on Oracle“ erschlossen. Durch die erfolgreiche Platzierung bei Kunden konnte anykey im letzten Fiskaljahr sogar den Umsatz verdoppeln.

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  • Die glücklichen Gewinner der Oracle Partner Awards Germany 2012

    - by A&C Redaktion
    Es war ein Höhepunkt des Oracle Partner Days: Die Award Ceremony, auf der deutsche Oracle Partner für ihr besonderes Engagement und herausragende Erfolge bei der Spezialisierung ausgezeichnet wurden. Jeder Preisträger erhielt neben dem Award eine Urkunde sowie einen Wertscheck in Höhe von 2.000 Euro für eine Demand Generation Kampagne. Wir gratulieren allen Gewinnern ganz herzlich und stellen sie Ihnen im Folgenden kurz vor:Database Partner of the Year Germany: inforsacom Informationssysteme GmbHDass der EMEA Database Partner of the Year inforsacom auch im bundesweiten Vergleich überzeugen würde, war keine große Überraschung, ist aber ein Riesenerfolg! Übrigens war inforsacom auch schon 2011 unter den Preisträgern des OPN Day Satellite (wir berichteten). Der Platinum Partner inforsacom Informationssysteme GmbH entwickelt und liefert seit 1997 integrierte IT-Lösungen im Data-Center. Als „trusted advisor“ ist es ein Schwerpunkt von Inforsacom, in der Beratung den größtmöglichen Kundennutzen aufzuzeigen. inforsacom setzt einen deutlichen Fokus auf Oracle Datenbanktechnologien sowie das Hardware und Engineered Systems Portfolio -  inklusive der damit verbundenen Spezialisierung und Ausbildung der Mitarbeiter. Middleware Partner of the Year Germany: People at Work Systems AGZum Middleware Partner of the Year wurde die People at Work Systems AG gekürt, ein Software- und Beratungsunternehmen aus München, das  Kunden individuelle Dienstleistungen und Lösungen für Customer Relationship Management (CRM) und  Business Process Management (BPM) auf der Basis von Oracle anbietet. Seit Jahren zeigt der Oracle Partner ein hohes Commitment zu Oracle, unter anderem durch sein umfassendes Engagement im Rahmen der Solution Partner Community SOA. Die große technologische und vertriebliche Kompetenz in Sachen BPM, SOA & Integration hat die People at Work GmbH in verschiedenen komplexen Fusion Middleware-Projekten erfolgreich unter Beweis gestellt. Applications Partner of the Year Germany: ifb AGDie ifb-group deckt als einer der wenigen Partner das komplette Hyperion, Oracle EPM und BI Portfolio ab. Dabei ist das Markenzeichen der ifb die enge Verbindung von Fachexpertise und Umsetzungsstärke, denn weltweit setzen über 800 Unternehmen seit vielen Jahren erfolgreich auf Lösungen der ifb. Der Award „Applications Partner of the Year“ würdigt die Spezialisierung der ifb auf EPM. Industry Partner of the Year Germany: PORTRIX LOGISTIC SOFTWARE GmbHÜber den Preis als bester Industry Partner freute sich die PORTRIX LOGISTIC SOFTWARE GmbH aus Hamburg, eine Tochter der portrix.net GmbH. Mit einer eigenen Software-Lösung bietet der ISV Speditionen eine Lösung an, die die Abrechnung und Transparenz von Vertragskonditionen über die ganze Transportkette hinweg vereinfacht. Die Unternehmensgruppe portrix.net ist mit mehr als vier Spezialisierungen mit sehr gutem Oracle Know-how ausgestattet und somit in der Lage, zu unterschiedlichsten Anforderungen von Endkunden und Oracle Partnern exzellent zu beraten. Oracle Accelerate Partner of the Year Germany: ICP Solution GmbHICP Solution unterstützt als "One-Stop-Shop" auf dem europäischen Markt Kunden in allen Fragen rund um PLM und Agile von Oracle. Das Leistungsspektrum reicht dabei von der Prozessoptimierung und PLM Einführung, über ERP Integration bis hin zum Wartungsvertrag und speziellen Schulungen.Server & Storage Systems Partner of the Year Germany: CCF AGDie CCF AG ist schon seit 19 Jahren ein überzeugter Sun/Oracle Partner, der ca. 90% seines Umsatzes mit Sun/Oracle Produkten macht. Als flexibles regionales Unternehmen mit angeschlossener Consulting Firma, die auf Solaris und Unix spezialisiert ist, ist die CCF einer der wenigen Oracle Partner mit eigenen Solaris Administratoren. Der Award würdigt auch die herausragenden Umsatzergebnisse von CCF im Hardware Segment.Oracle on Oracle Partner of the Year Germany: anykey GmbHAuch ankey ist bereits ein langjähriger Partner von Sun/Oracle und verfügt über hohes Consulting-Know-how. 2012 ist anykey richtig durchgestartet: Viele Zertifizierungen sowie Datenbankspezialisierung wurden erworben und der Platinum Partner hat sich damit den Bereich „Oracle on Oracle“ erschlossen. Durch die erfolgreiche Platzierung bei Kunden konnte anykey im letzten Fiskaljahr sogar den Umsatz verdoppeln.

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  • PASS Summit 2013 Review

    - by Ajarn Mark Caldwell
    As a long-standing member of PASS who lives in the greater Seattle area and has attended about nine of these Summits, let me start out by saying how GREAT it was to go to Charlotte, North Carolina this year.  Many of the new folks that I met at the Summit this year, upon hearing that I was from Seattle, commented that I must have been disappointed to have to travel to the Summit this year after 5 years in a row in Seattle.  Well, nothing could be further from the truth.  I cheered loudly when I first heard that the 2013 Summit would be outside Seattle.  I have many fond memories of trips to Orlando, Florida and Grapevine, Texas for past Summits (missed out on Denver, unfortunately).  And there is a funny dynamic that takes place when the conference is local.  If you do as I have done the last several years and saved my company money by not getting a hotel, but rather just commuting from home, then both family and coworkers tend to act like you’re just on a normal schedule.  For example, I have a young family, and my wife and kids really wanted to still see me come home “after work”, but there are a whole lot of after-hours activities, social events, and great food to be enjoyed at the Summit each year.  Even more so if you really capitalize on the opportunities to meet face-to-face with people you either met at previous summits or have spoken to or heard of, from Twitter, blogs, and forums.  Then there is also the lovely commuting in Seattle traffic from neighboring cities rather than the convenience of just walking across the street from your hotel.  So I’m just saying, there are really nice aspects of having the conference 2500 miles away. Beyond that, the training was fantastic as usual.  The SQL Server community has many outstanding presenters and experts with deep knowledge of the tools who are extremely willing to share all of that with anyone who wants to listen.  The opening video with PASS President Bill Graziano in a NASCAR race turned dream sequence was very well done, and the keynotes, as usual, were great.  This year I was particularly impressed with how well attended were the Professional Development sessions.  Not too many years ago, those were very sparsely attended, but this year, the two that I attended were standing-room only, and these were not tiny rooms.  I would say this is a testament to both the maturity of the attendees realizing how important these topics are to career success, as well as to the ever-increasing skills of the presenters and the program committee for selecting speakers and topics that resonated with people.  If, as is usually the case, you were not able to get to every session that you wanted to because there were just too darn many good ones, I encourage you to get the recordings. Overall, it was a great time as these events always are.  It was wonderful to see old friends and make new ones, and the people of Charlotte did an awesome job hosting the event and letting their hospitality shine (extra kudos to SQLSentry for all they did with the shuttle, maps, and other event sponsorships).  We’re back in Seattle next year (it is a release year, after all) but I would say that with the success of this year’s event, I strongly encourage the Board and PASS HQ to firmly reestablish the location rotation schedule.  I’ll even go so far as to suggest standardizing on an alternating Seattle – Charlotte schedule, or something like that. If you missed the Summit this year, start saving now, and register early, so you can join us!

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  • Query to find the data for every month of last year from the given date using mysql?

    - by Salil
    Hi All, I want data for the the last 1 year from the given date For ex:- I have date "2013-06-01" and i want data as follows also data i want is from three table using Group By or something else Month             Amount         Total_Data June 2013     100                5 May 2013       80                  4 -                     100                5 -                     100                5 July 2012       10                  2 I try following query but didn't workout SELECT DATE_FORMAT(rf.period, '%M %Y') as Month , sum(p.amount * ((100-q.amount)/100)) as Amount ,count(distinct q.label_id) as Total Data FROM table1 rf , table2 p , table3 q ,table4 a where rf.period BETWEEN '2013-06-01' AND '2013-06-01' and q.royalty_period BETWEEN '2013-06-01' AND '2013-06-01' and a.id = q.album_id and p.file_id = rf.id and p.upc = a.upc and p.local_revenue is not null GROUP BY Month Thanks in Advance, Salil Gaikwad

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  • SQL : where vs. on in join

    - by Erwin
    Perhaps a dumb question, but consider these 2 tables : T1 Store Year 01 2009 02 2009 03 2009 01 2010 02 2010 03 2010 T2 Store 02 Why is this INNER JOIN giving me the results I want (filtering the [year] in the ON clause) : select t1.* from t1 inner join t2 on t1.store = t2.store and t1.[year] = '2009' Store Year 02 2009 And why the LEFT OUTER JOIN include records of year 2010 ? select t1.* from t1 left outer join t2 on t1.store = t2.store and t1.year = '2009' where t2.store is null 01 2009 03 2009 01 2010 02 2010 03 2010 And I have to write the [year] filter in the 'WHERE' clause : select t1.* from t1 left outer join t2 on t1.store = t2.store where t2.store is null and t1.year = '2009' 01 2009 03 2009 Like I said, perhaps a dumb question, but it's bugging me !

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  • jQuery DatePicker - How to highlight certain days every month?

    - by Sergio
    Hi I have a jquery datepicker which is renders the current date by default as a full calendar. Before this is rendered I get a list of days from the server via ajax of days that need to be highlighted for the current month. The code for this is as follows: $.get("Note/GetActionDates/?orgID=" + orgID + "&month=" + month +"&year=" + year, null, function(result) { RenderCalendar(result); }, "json"); function RenderCalendar(dates) { $("#actionCal").datepicker({ dateFormat: 'dd/mm/yy', beforeShowDay: function(thedate) { var theday = thedate.getDate(); if ($.inArray(theday, dates) == -1) { return [true, "", ""]; } else { return [true, "specialDate", "Actions Today"]; } } }); } This is all good, but I would like the highlighted dates to update when the user clicks to a different month. I can modify the jquery datepicker initialise code with the following code: onChangeMonthYear: function(year, month, inst) { //get new array of dates for that month $.get("Note/GetActionDates/?orgID=" + orgID + "&month=" + month + "&year=" + year, null, function(result) { RenderCalendar(result); }, "json"); } But this doesn't seem to work. Could anyone show me what I'm doing wrong? Thanks! :) UPDATE - Working Code Thanks for the help! I have tweaked the code from petersendidit as follows and it now works. Gonna add a little more code to remove duplicate dates from the dates array but aside from that its all good. $("#actionCal").datepicker({ dateFormat: 'dd/mm/yyyy', beforeShowDay: function(thedate) { var theday = thedate.getDate() + "/" + (thedate.getMonth() + 1) + "/" + thedate.getFullYear(); if ($.inArray(theday, actionCalDates) == -1) { return [true, "", ""]; } else { return [true, "specialDate", "Actions Today"]; } }, onChangeMonthYear: function(year, month, inst) { dateCount = 0; getDates(orgID, month, year); } }); function getDates(orgID, month, year) { dateCount += 1; if (dateCount < 4) { $.ajax({ url: "Note/GetActionDates/", data: { 'orgID': orgID, 'month': month, 'year': year }, type: "GET", dataType: "json", success: function(result) { actionCalDates = actionCalDates.concat(result); getDates(orgID, month + 1, year); getDates(orgID, month - 1, year); } }); } }

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  • Date problem in MYSQL Query

    - by davykiash
    Am looking for a query to sum values in a particular time duration say an year or a particular month in an year using MYSQL syntax.Note that my transaction_date column stores daily amount transacted. Am example of a query that returns total sales in an year query would look something like this SELECT SUM(transaction_amount) WHERE transaction_date = (YEAR) Am example of a query that returns total sales in an particular month and year would look something like this SELECT SUM(transaction_amount) WHERE transaction_date = (YEAR)(MONTH) How achievable is this?

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  • Most efficient way to check if a date falls between two dates?

    - by Dave Jarvis
    Given: Start Month & Start Day End Month & End Day Any Year What SQL statement results in TRUE if a date lands between the Start and End days? 1st example: Start Date = 11-22 End Date = 01-17 Year = 2009 Specific Date = 2010-01-14 TRUE 2nd example: Start Date = 11-22 End Date = 11-16 Year = 2009 Specific Date = 2010-11-20 FALSE 3rd example: Start Date = 02-25 End Date = 03-19 Year = 2004 Specific Date = 2004-02-29 TRUE I was thinking of using the MySQL functions datediff and sign plus a CASE condition to determine whether the year wraps, but it seems rather expensive. Am looking for a simple, efficient calculation. Update The problem is the end date cannot simply use the year. The year must be increased if the end month/day combination happens before the start date. The start date is easy: Start Date = date( concat_ws( '-', year, Start Month, Start Day ) The end date is not so simple. Thank you!

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  • Range partition skip check

    - by user289429
    We have large amount of data partitioned on year value using range partition in oracle. We have used range partition but each partition contains data only for one year. When we write a query targeting a specific year, oracle fetches the information from that partition but still checks if the year is what we have specified. Since this year column is not part of the index it fetches the year from table and compares it. We have seen that any time the query goes to fetch table data it is getting too slow. Can we somehow avoid oracle comparing the year values since we for sure know that the partition contains information for only one year.

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  • linq multiple order DESCENDING

    - by ile
    .OrderBy(y => y.Year).ThenBy(m => m.Month); How to set descending order? EDIT: I tried this: var result = (from dn in db.DealNotes where dn.DealID == dealID group dn by new { month = dn.Date.Month, year = dn.Date.Year } into date orderby date.Key.year descending orderby date.Key.month descending select new DealNoteDateListView { DisplayDate = date.Key.month + "-" + date.Key.year, Month = date.Key.month, Year = date.Key.year, Count = date.Count() }) //.OrderBy(y => y.Year).ThenBy(m => m.Month) ; And it seems working. Is it wrong to use orderby twice like I used it here?

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  • Stupid newbie c++ two-dimensional array problem.

    - by paulson scott
    I've no idea if this is too newbie or generic for stackoverlflow. Apologies if that's the case, I don't intend to waste time. I've just started working through C++ Primer Plus and I've hit a little stump. This is probably super laughable but: for (int year = 0; year < YEARS; year++) { cout << "Year " << year + 1 << ":"; for (int month = 0; month < MONTHS; month++) { absoluteTotal = (yearlyTotal[year][year] += sales[year][month]); } cout << yearlyTotal[year][year] << endl; } cout << "The total number of books sold over a period of " << YEARS << " years is: " << absoluteTotal << endl; I wish to display the total of all 3 years. The rest of the code works fine: input is fine, individual yearly output is fine but I just can't get 3 years added together for one final total. I did have the total working at one point but I didn't have the individual totals working. I messed with it and reversed the situation. I've been messing with it for God knows how long. Any idea guys? Sorry if this isn't the place!

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  • bubble sort on array of c structures not sorting properly

    - by xmpirate
    I have the following program for books record and I want to sort the records on name of book. the code isn't showing any error but it's not sorting all the records. #include "stdio.h" #include "string.h" #define SIZE 5 struct books{ //define struct char name[100],author[100]; int year,copies; }; struct books book1[SIZE],book2[SIZE],*pointer; //define struct vars void sort(struct books *,int); //define sort func main() { int i; char c; for(i=0;i<SIZE;i++) //scanning values { gets(book1[i].name); gets(book1[i].author); scanf("%d%d",&book1[i].year,&book1[i].copies); while((c = getchar()) != '\n' && c != EOF); } pointer=book1; sort(pointer,SIZE); //sort call i=0; //printing values while(i<SIZE) { printf("##########################################################################\n"); printf("Book: %s\nAuthor: %s\nYear of Publication: %d\nNo of Copies: %d\n",book1[i].name,book1[i].author,book1[i].year,book1[i].copies); printf("##########################################################################\n"); i++; } } void sort(struct books *pointer,int n) { int i,j,sorted=0; struct books temp; for(i=0;(i<n-1)&&(sorted==0);i++) //bubble sort on the book name { sorted=1; for(j=0;j<n-i-1;j++) { if(strcmp((*pointer).name,(*(pointer+1)).name)>0) { //copy to temp val strcpy(temp.name,(*pointer).name); strcpy(temp.author,(*pointer).author); temp.year=(*pointer).year; temp.copies=(*pointer).copies; //copy next val strcpy((*pointer).name,(*(pointer+1)).name); strcpy((*pointer).author,(*(pointer+1)).author); (*pointer).year=(*(pointer+1)).year; (*pointer).copies=(*(pointer+1)).copies; //copy back temp val strcpy((*(pointer+1)).name,temp.name); strcpy((*(pointer+1)).author,temp.author); (*(pointer+1)).year=temp.year; (*(pointer+1)).copies=temp.copies; sorted=0; } *pointer++; } } } My Imput The C Programming Language X Y Z 1934 56 Inferno Dan Brown 1993 453 harry Potter and the soccers stone J K Rowling 2012 150 Ruby On Rails jim aurther nil 2004 130 Learn Python Easy Way gmaps4rails 1967 100 And the output ########################################################################## Book: Inferno Author: Dan Brown Year of Publication: 1993 No of Copies: 453 ########################################################################## ########################################################################## Book: The C Programming Language Author: X Y Z Year of Publication: 1934 No of Copies: 56 ########################################################################## ########################################################################## Book: Ruby On Rails Author: jim aurther nil Year of Publication: 2004 No of Copies: 130 ########################################################################## ########################################################################## Book: Learn Python Easy Way Author: gmaps4rails Year of Publication: 1967 No of Copies: 100 ########################################################################## ########################################################################## Book: Author: Year of Publication: 0 No of Copies: 0 ########################################################################## We can see the above sorting is wrong? What I'm I doing wrong?

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  • Rotate a linked list

    - by user408041
    I want to rotate a linked list that contains a number. 123 should be rotated to 231. The function created 23 but the last character stays empty, why? typedef struct node node; struct node{ char digit; node* p; }; void rotate(node** head){ node* walk= (*head); node* prev= (*head); char temp= walk->digit; while(walk->p!=NULL){ walk->digit=walk->p->digit; walk= walk->p; } walk->digit=temp; } How I create the list: node* convert_to_list(int num){ node * curr, * head; int i=0,length=0; char *arr=NULL; head = NULL; length =(int) log10(((double) num))+1; arr =(char*) malloc((length)*sizeof(char)); //allocate memory sprintf (arr, "%d" ,num); //(num, buf, 10); for(i=length;i>=0;i--) { curr = (node *)malloc(sizeof(node)); (curr)->digit = arr[i]; (curr)->p = head; head = curr; } curr = head; return curr; }

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  • Announcing Fusion Middleware Innovation Awards

    - by Michelle Kimihira
    Author: Neela Chaudhari Every year at OpenWorld, Oracle announces the winners to its most prestigious awards in Middleware, the Fusion Middleware Innovation Awards. This year, we’ll be announcing the winners and highlighting a few of their original implementations during this key session in the Middleware stream: 11:45 AM on Tuesday, October 2nd, CON9162 Oracle Fusion Middleware: Meet This Year's Most Impressive Customer Projects in Moscone West, 3001. In addition, we’ll give a sneak peak of a few winners during GEN9394: Fusion Middleware General Session with Hasan Rizvi at 10:15 AM on Tuesday, October 2nd in Moscone West, Hall D! What kinds of customers win the Fusion Middleware Innovation Awards? Winners are selected based on the uniqueness of their business case, business benefits, level of impact relative to the size of the organization, complexity and magnitude of implementation, and the originality of architecture. The winners are selected by a panel of judges that score each entry across multiple different scoring categories. This year, the following categories included: Oracle Exalogic Cloud Application Foundation Service Integration (SOA) and BPM WebCenter Identity Management Data Integration Application Development Framework and Fusion Development Business Analytics (BI, EPM and Exalytics) Last year at OpenWorld 2011 we had standing room only in our session, so come early!  We had over 30 innovative customers that won the award, including companies like BT, Choice Hotels, Electronic Arts, Clorox Company, ING, Dunkin Brands, Telenor, Haier, AT&T, Manpower, Herbal Life and many others. Did you miss your chance this year to nominate your company? Come join with us in the awards session to get an edge in your next year’s submission and watch for the next opportunity for 2013 on this blog. There’s other awards as part of Oracle’s Excellence awards program or subscribe to our regular Fusion Middleware newsletter to get the latest reminders.

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  • Top Partners 2010 Specialization Awards

    - by Paulo Folgado
    Portugal Top Partners 2010 Specialization Awards Be Recognized Caro Parceiro, Vão ter lugar mais uma vez os prémios Top Partners, que anualmente visam reconhecer as realizações dos parceiros Oracle em termos de negócio. Este ano, sob o signo de Partner Specialization Awards, pretendemos, a par com os resultados de negócio, premiar igualmente o esforço dos nossos parceiros em termos de especialização e de desenvolvimento da sua auto-suficiência. Outras das inovações deste ano é o processo ser baseado numa entrega de candidaturas dos parceiros, e de estas serem avaliadas, com base em critérios definidos, por um júri incluindo entidades externas. Categorias dos Prémios: ·       Database Partner of the Year ·       Middleware Partner of the Year ·       Applications Partner of the Year ·       ISV Partner of the Year ·       Midsize Partner of the Year ·       Industry Partner of the Year ·       Accelerate Partner of the Year   Um dos objectivos dos Top Partners 2010 Specialization Awards é destacar e incentivar a cooperação entre a Oracle e os seus parceiros. Por esta razão, para além dos vários critérios específicos, os parceiros têm de cumprir um conjunto de critérios gerais: ·       Cooperação com a Oracle ·       Investimento no desenvolvimento dos conhecimentos em Oracle ·       Aproximação conjunta ao mercado ·       Utilização activa dos recursos e ferramentas do Oracle PartnerNetwork através do Portal OPN   Os Top Partners 2010 Specialization Awards estão abertos a todos os parceiros em Portugal que estejam registados no OPN Specialized em uma ou mais especializações. As candidaturas podem ser enviadas até 31 de Maio de 2010. Be recognized! Para mais informação clique aqui

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  • 25 Favorite JCP Award Memories

    - by heathervc
    As we celebrated the 10th Annual JCP Awards and Party at JavaOne last week, we asked attendees to share their favorite memories.  Add yours to the retrospective list below... The 10th Award party will be the best :-) I won a DSLR camera at the 2011 JCP party and have taken many awesome photos of my family with it ever since!  Thanks JCP! Remembering the password to get in! It was very fascinating talking to all those JUG Members of last years' (2011) party and hearing about their hopes & expectations.  Especially from members of SouJava and LJC. Hanging out with my friends Best food and one of my colleagues won the raffle prize. My friend Brian won a jacket 3 years ago and my friend Craig won a camera last year. 2010 when I took home 2 awards on behalf of JSRs I'm on. When Patrick & Scott sang 'Light My Fire'! Catch up with friends! Being able to attend my first JCP party and and joining JCP community. Of course it's when some people won the award (SouJava and LJC)!   Meeting Crazy Bob! This is my first. Mike  to be JCP Member of the Year in 2011. When SouJava and London Java Community won Member of the Year award! JBoss making CDI Everything! When SouJava won the JCP Member of the Year award. I love feeling like it is the Oscars! First Party! Winning JCP Member of the Year last year. The year I was running for it (JCP Award). 2009 music and hostess. Obscured on legal advice.

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