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• The Oracle Retail Week Awards - most exciting awards yet?

  - by sarah.taylor(at)oracle.com

  Last night's annual Oracle Retail Week Awards saw the UK's top retailers come together to celebrate the very best of our industry over the last year.  The Grosvenor House Hotel on Park Lane in London was the setting for an exciting ceremony which this year marked several significant milestones in British - and global - retail.  Check out our videos about the event at our Oracle Retail YouTube channel, and see if you were snapped by our photographer on our Oracle Retail Facebook page. There were some extremely hot contests for many of this year's awards - and all very deserving winners.  The entries have demonstrated beyond doubt that retailers have striven to push their standards up yet again in all areas over the past year.  The judging panel includes some of the most prestigious names in the retail industry - to impress the panel enough to win an award is a substantial achievement.  This year the panel included the likes of Andy Clarke - Chief Executive of ASDA Group; Mark Newton Jones - CEO of Shop Direct Group; Richard Pennycook - the finance director at Morrisons; Rob Templeman - Chief Executive of Debenhams; and Stephen Sunnucks - the president of Gap Europe.  These are retail veterans  who have each helped to shape the British High Street over the last decade.  It was great to chat with many of them in the Oracle VIP area last night.  For me, last night's highlight was honouring both Sir Stuart Rose and Sir Terry Leahy for their contributions to the retail industry.  Both have set the standards in retailing over the last twenty years and taken their respective businesses from strength to strength, demonstrating that there is always a need for innovation even in larger businesses, and that a business has to adapt quickly to new technology in order to stay competitive.  Sir Terry Leahy's retirement this year marks the end of an era of global expansion for the Tesco group and a milestone in the progression of British retail.  Sir Terry has helped steer Tesco through nearly 20 years of change, with 14 years as Chief Executive.  During this time he led the drive for international expansion and an aggressive campaign to increase market share.  He has led the way for High Street retailers in adapting to the rise of internet retailing and nurtured a very successful home delivery service.  More recently he has pioneered the notion of cross-channel retailing with the introduction of Tesco apps for the iPhone and Android mobile phones allowing customers to scan barcodes of items to add to a shopping list which they can then either refer to in store or order for delivery.  John Lewis Partnership was a very deserving winner of The Oracle Retailer of the Year award for their overall dedication to excellent retailing practices.  The business was also named the American Express Marketing/Advertising Campaign of the Year award for their memorable 'Never Knowingly Undersold' advert series, which included a very successful viral video and radio campaign with Fyfe Dangerfield's cover of Billy Joel's 'She's Always a Woman' used for the adverts.  Store Design of the Year was another exciting category with Topshop taking the accolade for its flagship Oxford Street store in London, which combines boutique concession-style stalls with high fashion displays and exclusive collections from leading designers.  The store even has its own hairdressers and food hall, making it a truly all-inclusive fashion retail experience and a global landmark for any self-respecting international fashion shopper. Over the next few weeks we'll be exploring some of the winning entries in more detail here on the blog, so keep an eye out for some unique insights into how the winning retailers have made such remarkable achievements. 

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• JAVA - Create variable names using a loop?

  - by SeerUK

  Hi, first time poster, long time reader so be gentle with me :) See the following code which works to generate me timestamps for the beginning and end of every month in a financial year. int year = 2010; // Financial year runs from Sept-Aug so earlyMonths are those where year = FY-1 and lateMonths are those where year = FY int[] earlyMonths = {8, 9, 10, 11}; // Sept to Dec int earlyYear = year -1; for (int i : earlyMonths) { month = i; Calendar cal = Calendar.getInstance(); cal.clear(); cal.set(earlyYear,month,1,0,0,0); Long start = cal.getTimeInMillis(); cal.clear(); cal.set(earlyYear,month,1); lastDayofMonth = cal.getActualMaximum(GregorianCalendar.DAY_OF_MONTH); cal.set(earlyYear,month,lastDayofMonth,23,59,59); Long end = cal.getTimeInMillis(); } int[] lateMonths = {0, 1, 2, 3, 4, 5, 6, 7}; // Jan to Aug for (int i : lateMonths) { month = i; Calendar cal = Calendar.getInstance(); cal.clear(); cal.set(year,month,1,0,0,0); Long start = cal.getTimeInMillis(); cal.clear(); cal.set(year,month,1); lastDayofMonth = cal.getActualMaximum(GregorianCalendar.DAY_OF_MONTH); cal.set(year,month,lastDayofMonth,23,59,59); Long end = cal.getTimeInMillis(); } So far so good, but in order to use these results I need these timestamps to be output to variables named by month (to be used in a prepared statement later in the code. e.g. SeptStart = sometimestamp, SeptEnd = some timestamp etc etc. I don't know if it is possible to declare new variables based on the results of each loop. Any ideas?

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• Create variable names using a loop in Java?

  - by SeerUK

  Hi, first time poster, long time reader so be gentle with me :) See the following code which works to generate me timestamps for the beginning and end of every month in a financial year. int year = 2010; // Financial year runs from Sept-Aug so earlyMonths are those where year = FY-1 and lateMonths are those where year = FY int[] earlyMonths = {8, 9, 10, 11}; // Sept to Dec int earlyYear = year -1; for (int i : earlyMonths) { month = i; Calendar cal = Calendar.getInstance(); cal.clear(); cal.set(earlyYear,month,1,0,0,0); Long start = cal.getTimeInMillis(); cal.clear(); cal.set(earlyYear,month,1); lastDayofMonth = cal.getActualMaximum(GregorianCalendar.DAY_OF_MONTH); cal.set(earlyYear,month,lastDayofMonth,23,59,59); Long end = cal.getTimeInMillis(); } int[] lateMonths = {0, 1, 2, 3, 4, 5, 6, 7}; // Jan to Aug for (int i : lateMonths) { month = i; Calendar cal = Calendar.getInstance(); cal.clear(); cal.set(year,month,1,0,0,0); Long start = cal.getTimeInMillis(); cal.clear(); cal.set(year,month,1); lastDayofMonth = cal.getActualMaximum(GregorianCalendar.DAY_OF_MONTH); cal.set(year,month,lastDayofMonth,23,59,59); Long end = cal.getTimeInMillis(); } So far so good, but in order to use these results I need these timestamps to be output to variables named by month (to be used in a prepared statement later in the code. e.g. SeptStart = sometimestamp, SeptEnd = some timestamp etc etc. I don't know if it is possible to declare new variables based on the results of each loop. Any ideas?

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• How to set default date in date_select helper in Rails

  - by brad

  I'm trying to set up a date of birth helper in my Rails app (2.3.5). At present it is like so. <%= f.date_select :date_of_birth, :start_year => Time.now.year - 110, :end_year => Time.now.year %> This generates a perfectly functional set of date fields that work just fine but.... They default to today's date which is not ideal for a date of birth field (I'm not sure what is but unless you're running a neonatal unit today's date seems less than ideal). I want it to read Jan 1 2010 instead (or 2011 or whatever year it happens to be). Using the :default option has proven unsuccessful. I've tried many possibilities including; <%= f.date_select :date_of_birth, :default => {:year => Time.now.year, :month => 'Jan', :day => 1}, :start_year => Time.now.year - 110, :end_year => Time.now.year %> and <%= f.date_select :date_of_birth, :default => Time.local(2010,'Jan',1), :start_year => Time.now.year - 110, :end_year => Time.now.year %> None of this changes the behaviour of the first example. Does the default option actually work as described? It seems that this should be a fairly straightforward thing to do. Ta.

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• Optimal two variable linear regression SQL statement (censoring outliers)

  - by Dave Jarvis

  Problem Am looking to apply the y = mx + b equation (where m is SLOPE, b is INTERCEPT) to a data set, which is retrieved as shown in the SQL code. The values from the (MySQL) query are: SLOPE = 0.0276653965651912 INTERCEPT = -57.2338357550468 SQL Code SELECT ((sum(t.YEAR) * sum(t.AMOUNT)) - (count(1) * sum(t.YEAR * t.AMOUNT))) / (power(sum(t.YEAR), 2) - count(1) * sum(power(t.YEAR, 2))) as SLOPE, ((sum( t.YEAR ) * sum( t.YEAR * t.AMOUNT )) - (sum( t.AMOUNT ) * sum(power(t.YEAR, 2)))) / (power(sum(t.YEAR), 2) - count(1) * sum(power(t.YEAR, 2))) as INTERCEPT FROM (SELECT D.AMOUNT, Y.YEAR FROM CITY C, STATION S, YEAR_REF Y, MONTH_REF M, DAILY D WHERE -- For a specific city ... -- C.ID = 8590 AND -- Find all the stations within a 15 unit radius ... -- SQRT( POW( C.LATITUDE - S.LATITUDE, 2 ) + POW( C.LONGITUDE - S.LONGITUDE, 2 ) ) <15 AND -- Gather all known years for that station ... -- S.STATION_DISTRICT_ID = Y.STATION_DISTRICT_ID AND -- The data before 1900 is shaky; insufficient after 2009. -- Y.YEAR BETWEEN 1900 AND 2009 AND -- Filtered by all known months ... -- M.YEAR_REF_ID = Y.ID AND -- Whittled down by category ... -- M.CATEGORY_ID = '001' AND -- Into the valid daily climate data. -- M.ID = D.MONTH_REF_ID AND D.DAILY_FLAG_ID <> 'M' GROUP BY Y.YEAR ORDER BY Y.YEAR ) t Data The data is visualized here (with five outliers highlighted): Questions How do I return the y value against all rows without repeating the same query to collect and collate the data? That is, how do I "reuse" the list of t values? How would you change the query to eliminate outliers (at an 85% confidence interval)? The following results (to calculate the start and end points of the line) appear incorrect. Why are the results off by ~10 degrees (e.g., outliers skewing the data)? (1900 * 0.0276653965651912) + (-57.2338357550468) = -4.66958228 (2009 * 0.0276653965651912) + (-57.2338357550468) = -1.65405406 I would have expected the 1900 result to be around 10 (not -4.67) and the 2009 result to be around 11.50 (not -1.65). Thank you!

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• Optimal two variable linear regression SQL statement

  - by Dave Jarvis

  Problem Am looking to apply the y = mx + b equation (where m is SLOPE, b is INTERCEPT) to a data set, which is retrieved as shown in the SQL code. The values from the (MySQL) query are: SLOPE = 0.0276653965651912 INTERCEPT = -57.2338357550468 SQL Code SELECT ((sum(t.YEAR) * sum(t.AMOUNT)) - (count(1) * sum(t.YEAR * t.AMOUNT))) / (power(sum(t.YEAR), 2) - count(1) * sum(power(t.YEAR, 2))) as SLOPE, ((sum( t.YEAR ) * sum( t.YEAR * t.AMOUNT )) - (sum( t.AMOUNT ) * sum(power(t.YEAR, 2)))) / (power(sum(t.YEAR), 2) - count(1) * sum(power(t.YEAR, 2))) as INTERCEPT FROM (SELECT D.AMOUNT, Y.YEAR FROM CITY C, STATION S, YEAR_REF Y, MONTH_REF M, DAILY D WHERE -- For a specific city ... -- C.ID = 8590 AND -- Find all the stations within a 5 unit radius ... -- SQRT( POW( C.LATITUDE - S.LATITUDE, 2 ) + POW( C.LONGITUDE - S.LONGITUDE, 2 ) ) <15 AND -- Gather all known years for that station ... -- S.STATION_DISTRICT_ID = Y.STATION_DISTRICT_ID AND -- The data before 1900 is shaky; and insufficient after 2009. -- Y.YEAR BETWEEN 1900 AND 2009 AND -- Filtered by all known months ... -- M.YEAR_REF_ID = Y.ID AND -- Whittled down by category ... -- M.CATEGORY_ID = '001' AND -- Into the valid daily climate data. -- M.ID = D.MONTH_REF_ID AND D.DAILY_FLAG_ID <> 'M' GROUP BY Y.YEAR ORDER BY Y.YEAR ) t Data The data is visualized here: Questions How do I return the y value against all rows without repeating the same query to collect and collate the data? That is, how do I "reuse" the list of t values? How would you change the query to eliminate outliers (at an 85% confidence interval)? The following results (to calculate the start and end points of the line) appear incorrect. Why are the results off by ~10 degrees (e.g., outliers skewing the data)? (1900 * 0.0276653965651912) + (-57.2338357550468) = -4.66958228 (2009 * 0.0276653965651912) + (-57.2338357550468) = -1.65405406 I would have expected the 1900 result to be around 10 (not -4.67) and the 2009 result to be around 11.50 (not -1.65). Thank you!

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• Optimal two variable linear regression calculation

  - by Dave Jarvis

  Problem Am looking to apply the y = mx + b equation (where m is SLOPE, b is INTERCEPT) to a data set, which is retrieved as shown in the SQL code. The values from the (MySQL) query are: SLOPE = 0.0276653965651912 INTERCEPT = -57.2338357550468 SQL Code SELECT ((sum(t.YEAR) * sum(t.AMOUNT)) - (count(1) * sum(t.YEAR * t.AMOUNT))) / (power(sum(t.YEAR), 2) - count(1) * sum(power(t.YEAR, 2))) as SLOPE, ((sum( t.YEAR ) * sum( t.YEAR * t.AMOUNT )) - (sum( t.AMOUNT ) * sum(power(t.YEAR, 2)))) / (power(sum(t.YEAR), 2) - count(1) * sum(power(t.YEAR, 2))) as INTERCEPT, FROM (SELECT D.AMOUNT, Y.YEAR FROM CITY C, STATION S, YEAR_REF Y, MONTH_REF M, DAILY D WHERE -- For a specific city ... -- C.ID = 8590 AND -- Find all the stations within a 15 unit radius ... -- SQRT( POW( C.LATITUDE - S.LATITUDE, 2 ) + POW( C.LONGITUDE - S.LONGITUDE, 2 ) ) < 15 AND -- Gather all known years for that station ... -- S.STATION_DISTRICT_ID = Y.STATION_DISTRICT_ID AND -- The data before 1900 is shaky; insufficient after 2009. -- Y.YEAR BETWEEN 1900 AND 2009 AND -- Filtered by all known months ... -- M.YEAR_REF_ID = Y.ID AND -- Whittled down by category ... -- M.CATEGORY_ID = '001' AND -- Into the valid daily climate data. -- M.ID = D.MONTH_REF_ID AND D.DAILY_FLAG_ID <> 'M' GROUP BY Y.YEAR ORDER BY Y.YEAR ) t Data The data is visualized here: Question The following results (to calculate the start and end points of the line) appear incorrect. Why are the results off by ~10 degrees (e.g., outliers skewing the data)? (1900 * 0.0276653965651912) + (-57.2338357550468) = -4.66958228 (2009 * 0.0276653965651912) + (-57.2338357550468) = -1.65405406 I would have expected the 1900 result to be around 10 (not -4.67) and the 2009 result to be around 11.50 (not -1.65). Related Sites Least absolute deviations Robust regression Thank you!

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• Using bash to copy file to spec folders

  - by Franko

  I have a folder with a fair amount of subfolders. In some of the subfolders do I have a folder.jpg picture. What I try to do find that folder(s) and copy it to all other subfolders that got the same artist and album information then continue on to the next album etc. The structure of all the folders are "artist - year - album - [encoding information]". I have made a really simple one liner that find the folders that got the file but there am I stuck. ls -F | grep / | while read folders;do find "$folders" -name folder.jpg; done Anyone have any good tip or ideas how to solve this or pointers how to proceed? Edit: First of all, i´m real new to this (like you cant tell) so please have patience. Ok, let me break it down even more. I have a folder structure that looks like this: artist1 - year - album - [flac] artist1 - year - album - [mp3] artist1 - year - album - [AAC] artist2 - year - album - [flac] etc I like to loop over the set of folders that have the same artist and album information and look for a folder.jpg file. When I find that file do I like to copy it to all of the other folders in the same set. Ex if I find one folder.jpg in artist1 - year - album - [flac] folder do I like to have that folder.jpg copied to artist1 - year - album - [mp3] & artist1 - year - album - [AAC] but not to artist2 - year - album - [flac]. The continue the loop until all the sets been processed. I really hope that makes it a bit more easy to understand what I try to do :)

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• Exclude children based on content in XML with PHP (simplexml)

  - by Hakan

  Another question about PHP and XML... Is it posible to exclude children based on there childrens content. See the example below: If "title" contains the word "XTRA:" I don't want this "movie" to be listed. This is my PHP code: <? $xml = simplexml_load_file("movies.xml"); foreach ($xml->movie as $movie){ ?> <h2><? echo $movie->title ?></h2> <p>Year: <? echo $movie->year ?></p> <? } ?> This is mys XML file: <?xml version="1.0" encoding="UTF-8"?> <movies> <movie> <title>Little Fockers</title> <year>2010</year> </movie> <movie> <title>Little Fockers XTRA: teaser 3</title> <year>2010</year> </movie> </movies> The outcome of the code above is: <h2>Little Fockers</h2> <p>Year: 2010</p> <h2>Little Fockers XTRA: teaser 3</h2> <p>Year: 2010</p> I want it to be only: <h2>Little Fockers</h2> <p>Year: 2010</p>

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• Sampling Duplicates

  - by user3640982

  I have a dataset from which I need to sample. It is set up with an ID field and a year field. I want every record from the most current year and then I want the most current ID's but sampled from every 3rd year going back. The data is ordered by year. For example ID<-rep(1:3, 5) Year<-rep(c(1,2,3,4,5),each=3) df<-data.frame(ID,Year) ID Year 1 1 1 2 2 1 3 3 1 4 1 2 5 2 2 6 3 2 7 1 3 8 2 3 9 3 3 10 1 4 11 2 4 12 3 4 13 1 5 14 2 5 15 3 5 So from this example, I would want to return ID Year 1 1 1 2 2 1 3 3 1 4 1 4 5 2 4 6 3 4 I'm thinking that some combination of duplicated() and which() should get what I want, but the problem is duplicated() just tells if it has been repeated; it doesn't say which record is being repeated. which(duplicated(df$ID)) [1] 4 5 6 7 8 9 10 11 12 13 14 15 This a problem since not every ID exists in every year. Any help would be appreciated. Thanks, Eric

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• Mysql query, need suggestion or solution

  - by Xi Kam

  Can anyone help me, i have two tables and i need records from both the table //////////////////////////////++ Query 1 ++//////////////////////////////////// SELECT SUM(rec_issued) AS issed, regen_id, YEAR(issue_date) AS iYear, MONTH(issue_date) AS iMonth FROM `view_rec_issued` WHERE `regen_id` = 2 GROUP BY YEAR(issue_date) DESC, MONTH(issue_date) DESC ORDER BY issue_date ASC issed regen_id iYear iMonth 424 2 2011 3 4340 2 2011 4 4235 2 2011 5 10570 2 2012 2 4761 2 2012 3 5000 2 2012 4 3700 2 2012 5 3414 2 2012 6 3700 2 2012 7 2992 2 2012 8 995 2 2012 10 ![Result from Query 1][1] //////////////////////////////++ Query 2 ++//////////////////////////////////// SELECT SUM(total_redem) AS redemed, regen_id, YEAR(redemption_date) AS rYear, MONTH(redemption_date) AS rMonth FROM `recredem_month_wise` WHERE `regen_id` = 2 GROUP BY YEAR(redemption_date) DESC, MONTH(redemption_date) DESC order by redemption_date ASC redemed regen_id rYear rMonth 424 2 2011 3 260 2 2011 4 6523 2 2011 5 1070 2 2011 6 200 2 2011 10 500 2 2011 11 9750 2 2012 2 5000 2 2012 3 5500 2 2012 4 3803 2 2012 5 3700 2 2012 7 3000 2 2012 8 ![Result from Query 2][2] But i want it as - issed regen_id iYear iMonth redemed regen_id rYear rMonth 424 2 2011 3 424 2 2011 3 4340 2 2011 4 260 2 2011 4 4235 2 2011 5 6523 2 2011 5 NULL NULL NULL NULL 1070 2 2011 6 NULL NULL NULL NULL 200 2 2011 10 NULL NULL NULL NULL 500 2 2011 11 10570 2 2012 2 9750 2 2012 2 4761 2 2012 3 5000 2 2012 3 5000 2 2012 4 5500 2 2012 4 3700 2 2012 5 3803 2 2012 5 3414 2 2012 6 NULL NULL NULL NULL 3700 2 2012 7 3700 2 2012 7 2992 2 2012 8 3000 2 2012 8 995 2 2012 10 NULL NULL NULL NULL ![I want this output][3] In these table regen_id is unique and i need data as YEAR and MONTH, if in any table not have the records in perticular month and year it should retrieve zero or null. But in every record year and month should equal like this - iYear = rYear and iMonth = rMonth So we can merge both the fields - No need to show year and month twice iYear and rYear = year iMonth and rMonth = month Thank You Please look at this problem.

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• How to calculate checksum?

  - by Patel Rikin

  I m developing instrument driver and i want to know how to calculate checksum of frame. Explanation: Expressed by characters [0-9] and [A-F]. Characters beginning from the character after [STX] and until [ETB] or [ETX] (including [ETB] or [ETX]) are added in binary. The 2-digit numbers, which represent the least significant 8 bits in hexadecimal code, are converted to ASCII characters [0-9] and [A-F]. The most significant digit is stored in CHK1 and the least significant digit in CHK2. This is sample frame : <STX>2Q|1|2^1||||20011001153000<CR><ETX><CHK1><CHK2><CR><LF> and i want to know what is value of chk1 and chk2 and i am new in this so i m totally blank about how to calculate checksum i am not getting above 3rd and 4th point. can any one provide sample code for c#. Please help me.

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• Going to the Score Cards - Exceptional DBA Awards 2011

  - by Rodney

  This year marks my 4th year as a judge for the Exceptional DBA Awards, founded by Red Gate in 2008 to "recognize the essential but often overlooked contributions of DBAs, the unsung heroes of the IT community." As a professional DBA myself I have been honored to participate as a judge. It is not an easy job because there is a voluminous amount of nominees from all over the world. Each judge has to read through every word of the nominee's answers, deciding what makes each person special and stand out amongst their peers. What drives them? What single element of their submission will shine above all others? It is my hope that what I am about to divulge to you as a judge will prompt you to think about yourself or someone you know and decide that you may be the exceptional DBA who can take home the gold at this year's award ceremony in Seattle. We are more than a few weeks into the nomination process and there are quite a number of submissions already. I can not tell you how many as that would not be fair. I can say it is not 1 million or more. I can also say that it is not 100,000. But that is all I can say about that. However, I can tell you that it is enough this year that we are breaking records on the number of people who have been influenced, inspired or intrigued by the awards in the past. I remember them all like it were yesterday. fuzzy thought cloud here. It was a rainy day in Seattle (all memories for each award ceremony will start thusly) and I was in the hotel going over my notes on what I wanted to say about the winner of the 2008 Red Gate Exceptional DBA Award. The notes were on index cards that I had either bought or stolen from my wife, I do not recall, but I was nervous which was unlike me. This was, after all, a big night for the winner. Of course, we, the judges and the SQL community, had already decided the winner and now all that remained was to present the award. The room was packed. It was Casino night, sponsored by sqlservercentral.com. Money (fake), drinks (not fake) and camaraderie flowed through the room. Dan McClain won the award that year. He worked for Anheuser-Busch at the time. I promise that did not influence my decision. We presented Dan with the award. He was very proud of this achievement, rightfully so, as was the SQL community for him. I spoke with Dan throughout the conference and realized how huge this award was for him, not just personally but professionally. It was a rainy day in Seattle in 2009 and I was nervous. I was asked to speak to a group of people again as a judge for the Exceptional DBA Awards. This year, Josef Richberg would be the recipient of the award, but he would not be able to attend. We all prayed for him as he fought through an illness and congratulated him for his accomplishments as a DBA for his company. He got better and sallied forth and continued to give back to the SQL community that he saw as one big family. In 2010, and I am getting ahead of myself, he was asked to be a judge himself for the very award he had just received the year before. It was a sunny day in Seattle and I missed it, because it was in July and I was not there. It was a rainy day in Seattle and it is 2010 and Tracy Hamlin enters a submission that blows this judge away. She is managing a 50 Terabyte distributed database ("50 Gigabytes! Are you kidding me!!!", Rodney jokes.)  and loves her daily job as a DBA working with developers, mentoring them and teaching them best practices with kindness and patience. She is a people person who just happens to have 10+ years experience with RDBMS'. She wins the award and goes on to be recognized as famous at PASS. It will be a rainy day in Seattle this year when I sit amongst my old constituent judges and friends, Brad McGehee, http://www.simple-talk.com/books/sql-books/how-to-become-an-exceptional-dba,-2nd-edition/, Steve Jones, whom we all know and love at http://www.sqlservercentral.com and a young upstart to the SQL Community, this cat named Brent Ozar to announce the 2011 winner. I personally have not heard of Brent but I am told I have interviewed him for a DBA position several years ago and turned him down, http://www.brentozar.com/archive/2011/05/exceptional-dba-contest/ . I hope that did not jeopardize his future in the SQL world. I am a big hearted oaf and would feel horrible. Hopefully I will meet him at PASS and we can work this all out and I can help him get a DBA job. The rain has stopped and a new year is upon us. The stakes are high...the competition is fierce...the rewards are incredible. The entry form awaits you. http://www.exceptionaldba.com/ I very much look forward to meeting you and presenting the award to you in front of hundreds of your envious but proud peers as the new Exceptional DBA for 2011 at the PASS Summit. Here is what you could win: The Exceptional DBA of the Year receives full conference registration for the 2011 PSS Summit in Seattle, where the awards ceremony will take place, four nights' hotel accommodation, and $300 towards travel expenses. They will also be featured on Simple-Talk. Are you ready? Are you nervous?

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• PASS Summit 2010 Recap

  - by AjarnMark

  Last week I attended my eighth PASS Summit in nine years, and every year it is a fantastic event!  I was fortunate my first year to have a contact (Bill Graziano (blog | Twitter) from SQLTeam) that I was expecting to meet, and who got me started on a good track of making new contacts.  Each year I have made a few more, and renewed friendships from years past.  Many of the attendees agree that the pure networking opportunities are one of the best benefits of attending the Summit.  And there’s a lot of great technical stuff, too, some of the things that stick out for me this year include… Pre-Con Monday: PowerShell with Allen White (blog | Twitter).  This was the first time that I attended a pre-con.  For those not familiar with the concept, the regular sessions for the conference are 75-90 minutes long.  For an extra fee, you can attend a full-day session on a single topic during a pre- or post-conference training day.  I had been meaning for several months to dive in and learn PowerShell, but just never seemed to find (or make) the time for it, so when I saw this was one of the all-day sessions, and I was planning to be there on Monday anyway, I decided to go for it.  And it was well worth it!  I definitely came out of there with a good foundation to build my own PowerShell scripts, plus several sample scripts that he showed which already cover the first four or five things I was planning to do with PowerShell anyway.  This looks like the right tool for me to build an automated version of our software deployment process, which right now contains many repeated steps.  Thanks Allen! Service Broker with Denny Cherry (blog | Twitter).  I remembered reading Denny’s blog post on Using Service Broker instead of Replication, and ever since then I have been thinking about using this to populate a new reporting-focused Data Repository that we will be building in the near future.  When I saw he was doing this session, I thought it would be great to get more information and be able to ask the author questions.  When I brought this idea back to my boss, he really liked it, as we had previously been discussing doing nightly data loads, with an option to manually trigger a mid-day load if up-to-the-minute data was needed for something.  If we go the Service Broker route, we can keep the Repository current in near real-time.  Hooray! DBA Mythbusters with Paul Randal (blog | Twitter).  Even though I read every one of the posts in Paul’s blog series of the same name, I had to go see the legend in person.  It was great, and I still learned something new! How to Conduct Effective Meetings with Joe Webb (blog | Twitter).  I always like to sit in on a session that Joe does.  I met Joe several years ago when both he and Bill Graziano were on the PASS Board of Directors together, and we have kept in touch.  Joe is very well-spoken and has great experience with both SQL Server and business.  And we could certainly use some pointers at my work (probably yours, too) on making our meetings more effective and to run on-time.  Of course, now that I’m the Chapter Leader for the Professional Development virtual chapter, I also had to sit in on this ProfDev session and recruit Joe to do a presentation or two for the chapter next year. Query Optimization with David DeWitt.  Anyone who has seen Dr. David DeWitt present the 3rd keynote at a PASS Summit over the last three years knows what a great time it is to sit and listen to him make some really complicated and advanced topic easy to understand (although it still makes your head hurt).  It still amazes me that the simple two-table join query from pubs that he used in his example can possibly have 22 million possible physical query plans.  Ouch! Exhibit Hall:  This year I spent more serious time in the exhibit hall than any year past.  I have talked my boss into making a significant (for us) investment in monitoring tools next year, and this was a great opportunity to talk with all the big-hitters.  Readers of mine may recall that I fell in love with the SQL Sentry Power Suite several months ago and wrote a blog entry about it just from the trial version.  Well as things turned out, short-term budget priorities shifted, and we weren’t able to make the purchase then.  I have it in the budget for next year, but since I was going to the Summit, my boss wanted me to look at the other options to see if this was really the one that we wanted.  I spent a couple of hours talking with representatives from Red-Gate, Idera, Confio, and Quest about their offerings, and giving them each the same 3 scenarios that I wanted to be able to accomplish based on the questions and issues that arise in our company.  It was interesting to discover the different approaches or “world view” that each vendor takes to the subject of performance monitoring and troubleshooting.  I may write a separate article that goes into this in more depth, but the product that best aligned with our point of view, and met the current needs we have is still the SQL Sentry Power Suite.  I’m not saying that the others are bad or wrong or anything like that, just that the way they tackled the issue did not align as well with our particular needs as does SQL Sentry’s product.  And that was something I learned too, when you go shopping for these products, you really need to know what you want to get from them.  It’s best if you have a few example scenarios from work that you can use to test out how well each tool fits your particular needs. Overall, another GREAT event.  I can’t wait to get the DVDs so I can sit in on a bunch of other sessions that I couldn’t get to because I was in one of the ones above.  And I can hardly wait until next year!

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• JCP Party Tonight...10th Annual JCP Award Unveiling

  - by heathervc

  Tonight is the night-attend the Presentation of the 10th Annual JCP Awards! This year's JCP Award nominee list has been finalized, and the winners will be announced tonight during the JCP party at the Infusion Lounge.  We will open the doors at 6:30 PM; awards presentation at 7:00 PM.  This year's three award categories are Member of the Year, Outstanding Spec Lead, and Most Significant JSR. The JCP Member/Participant of the Year shines the light on who has shown the leadership and commitment that led to the most positive impact on the community. The Outstanding Spec Lead highlights the individual who led a specific JSR with exceptional efficiency and execution. The Most Significant JSR recognizes the most significant JSR for the Java community in the past year. Read the final list of the nominees and their profiles now.  Hope to see you there!

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• Project Euler 4: (Iron)Python

  - by Ben Griswold

  In my attempt to learn (Iron)Python out in the open, here’s my solution for Project Euler Problem 4.  As always, any feedback is welcome. # Euler 4 # http://projecteuler.net/index.php?section=problems&id=4 # Find the largest palindrome made from the product of # two 3-digit numbers. A palindromic number reads the # same both ways. The largest palindrome made from the # product of two 2-digit numbers is 9009 = 91 x 99. # Find the largest palindrome made from the product of # two 3-digit numbers. import time start = time.time() def isPalindrome(s): return s == s[::-1] max = 0 for i in xrange(100, 999): for j in xrange(i, 999): n = i * j; if (isPalindrome(str(n))): if (n > max): max = n print max print "Elapsed Time:", (time.time() - start) * 1000, "millisecs" a=raw_input('Press return to continue')

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• How much do they study in the best universities, relative to the other universities?

  - by Velizar Hristov

  In my university, our total required weekly attendance (for lectures and tutorials/similar) is about 12 hours. It was like that in the first year, and then everything required extremely little effort - I believe that if I invested as much efforts as someone who is studying for medicine or law, I could have learnt everything for 1-2 months - if not less! Now I'm second year and it doesn't look like it's going to be too different. This concerns me about the people who study in Oxford, Cambridge or Imperial College. It would be weird if they study that little, and it would be very concerning if they do study very hard, because this would mean that by the end of the year, their first year students will be better than our average third year student. Which is bad news for me, given that I share the market with them. I know the question can't have an absolutely accurate answer, but it can still be answered quite definitely, and it's relevant to many people.

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• 3rd Annual South Florida SQL Saturday - August 13th!

  - by ScottKlein

  The 3rd annual South Florida SQL Saturday event will be help August 13th, 2011 at Nova Southeastern University in Davie, FL. This is a change in venue from last year as DeVry is in the middle of a major remodling project. We has almost 450 last year, and we expect to have over 500 this year with great speakers such as Andy Warren, Herve Roggero, and more! As always, we our goal is to feed you well, so we are shooting for some hot lunch food this year. We are working on that now and will update you as soon as we firm it up. One of the things we will be trying this year is 90-100 minute sessions on a couple of tracks. We strongly feel that several topics are just getting warmed up in 45 minutes, so we are going to experiment with 90-100 minute sessions on some of the BI topics. We would love to see you there!

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• Years experience over unfinished degree?

  - by Daniel Lewis

  I'm currently in my placement year and working for a great software development company. It was always my intention of getting to this stage through university, getting enough academic experience as well as the year’s placement and then try to get a full time programming job without the need to finish my degree. I decided this from an early stage as I have never really liked the whole university environment. I was so unhappy at university and I’m so happy now I’m on my placement year, I really don’t know if I can go back. My question is, do you think companies will take me on if I apply for other jobs after my placement year and not penalize me for not finishing my degree? I guess at the end of the day I don't want to look back on my life and think "god, why didn't I just spend one more year being unhappy to have a job I love" but I know that even if I get a degree I could still end up without a programming job and this worries me more than anything.

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• T-SQL Tuesday #014:I Hereby Resolve

  - by AllenMWhite

  It's another T-SQL Tuesday! Like many others, I really don't make New Year's Resolutions. They're too easy to forget about and it's too easy to "justify" why it just wasn't practical (and sometimes it's true.) That said, there are some things I'm working on changing for this year. Last year was the first full year for my new business venture, and it has been successful so far. I'm confident it's going to continue on this path, and we'll be doing even better this time next year. With that success...(read more)

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• .htaccess and browser caching

  - by Tim

  I ran across these suggested htaccess edits. Is this a good practice? Is this something I should implement on my wordpress site?: <IfModule mod_expires.c> ExpiresActive On ExpiresByType image/jpg "access plus 1 year" ExpiresByType image/jpeg "access plus 1 year" ExpiresByType image/gif "access plus 1 year" ExpiresByType image/png "access plus 1 year" ExpiresByType text/css "access plus 1 month" ExpiresByType application/pdf "access plus 1 month" ExpiresByType text/x-javascript "access plus 1 month" ExpiresByType application/x-shockwave-flash "access plus 1 month" ExpiresByType image/x-icon "access plus 1 year" ExpiresDefault "access plus 2 days" </IfModule>

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• problem with routing/T4MVC Url.Action()

  - by VinnyG

  I have these 2 routes : routes.MapRoute("Agenda", ConfigurationManager.AppSettings["eventsUrl"] + "/{year}/{month}", MVC.Events.Index(), new { year = DateTime.Now.Year, month = DateTime.Now.Month }); routes.MapRoute("AgendaDetail", ConfigurationManager.AppSettings["eventsUrl"] + "/{year}/{month}/{day}", MVC.Events.Detail(), new { year = DateTime.Now.Year, month = DateTime.Now.Month, day = DateTime.Now.Day }); And it work perfectly with this code : <a href="<%= Url.Action(MVC.Events.Detail(Model.EventsModel.PreviousDay.Year, Model.EventsModel.PreviousDay.Month, Model.EventsModel.PreviousDay.Day))%>" title="<%= Model.EventsModel.PreviousDay.ToShortDateString() %>"><img src="<%= Links.Content.images.contenu.calendrier.grand.mois_precedent_png %>" alt="événement précédent" /></a> Except when I get to do the link to today, if it's today, il will point only to www.myurl.com/agenda, witch is the value of CnfigurationManager.AppSettings["eventsUrl"]. What am I doing wrong? It's like if it's today, it point bak to the default agenda... Thanks for the help!

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• Create date efficiently

  - by Dave Jarvis

  On Pavel's page is the following function: CREATE OR REPLACE FUNCTION makedate(year int, dayofyear int) RETURNS date AS $$ SELECT (date '0001-01-01' + ($1 - 1) * interval '1 year' + ($2 - 1) * interval '1 day'):: date $$ LANGUAGE sql; I have the following code: makedate(y.year,1) What is the fastest way in PostgreSQL to create a date for January 1st of a given year? Pavel's function would lead me to believe it is: date '0001-01-01' + y.year * interval '1 year' + interval '1 day'; My thought would be more like: to_date( y.year||'-1-1', 'YYYY-MM-DD'); Am looking for the fastest way using PostgreSQL 8.4. (The query that uses the date function can select between 100,000 and 1 million records, so it needs speed.) Thank you!

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• Django Grouping Query

  - by Matt

  I have the following (simplified) models: class Donation(models.Model): entry_date = models.DateTimeField() class Category(models.Model): name = models.CharField() class Item(models.Model): donation = models.ForeignKey(Donation) category = models.ForeignKey(Category) I'm trying to display the total number of items, per category, grouped by the donation year. I've tried this: Donation.objects.extra(select={'year': "django_date_trunc('year', %s.entry_date)" % Donation._meta.db_table}).values('year', 'item__category__name').annotate(items=Sum('item__quantity')) But I get a Field Error on item__category__name. I've also tried: Item.objects.extra(select={"year": "django_date_trunc('year', entry_date)"}, tables=["donations_donation"]).values("year", "category__name").annotate(items=Sum("quantity")).order_by() Which generally gets me what I want, but the item quantity count is multiplied by the number of donation records. Any ideas? Basically I want to display this: 2010 - Category 1: 10 items - Category 2: 17 items 2009 - Category 1: 5 items - Category 3: 8 items

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• PERL XPath Parser Help

  - by cognvision

  I want to pull in data using a XML::XPath parser from a XML DB file from the Worldbank site. The problem is that I'm not seeing any results in the output. I must be missing something in the code. Ideally, I would like to extract just the death rate statistics from each country XML DB (year and value). I'm using this as part of my input: http://data.worldbank.org/sites/default/files/countries/en/afghanistan_en.xml use strict; use LWP 5.64; use HTML::ContentExtractor; use XML::XPath; my $agent1 = LWP::UserAgent->new; my $extractor = HTML::ContentExtractor->new(); #Retrieve main Worldbank country site my $mainlink = "http://data.worldbank.org/country/"; my $page = $agent1->get("$mainlink"); my $fulltext = $page->decoded_content(); #Match to just all available countries in Worldbank my $country = ""; my @countryList; if (@countryList = $fulltext =~ m/(http:\/\/data\.worldbank\.org\/country\/.*?")/gi){ foreach $country(@countryList){ #Remove " at the end of link $country=~s/\"//gi; print "\n" . $country; #Retrieve each country profile's XML DB file my $page = $agent1->get("$country"); my $fulltext = $page->decoded_content(); my $XML_DB = ""; my @countryXMLDBList; if (@countryXMLDBList = $fulltext =~ m/(http:\/\/data\.worldbank\.org\/sites\/default\/files\/countries\/en\/.*?\.xml)/gi){ foreach $XML_DB(@countryXMLDBList){ my $page = $agent1->get("$XML_DB"); my $fulltext = $page->decoded_content(); #print $fulltext; #Use XML XPath parser to find elements related to death rate my $xp = XML::XPath->new($fulltext); #my $xp = XML::XPath->new("afghanistan_en.xml"); my $nodeSet = $xp->find("//*"); if (!$nodeSet->isa('XML::XPath::NodeSet') || $nodeSet->size() == 0) { #No match found print "\nMatch not found!"; exit; } else { foreach my $node ($nodeSet->get_nodelist){ print "\n" . $node->find('country')->string_value; print "\n" . $node->find('indicator')->string_value; print "\n" . $node->find('year')->string_value; print "\n" . $node->find('value')->string_value; exit; } } } #Build line graph based on death rate statistics and output some image file format } } } I am also looking into using the xpath expression "following-sibling", but not sure how to use it correctly. For example, I have the following set of XML data where I am only interested in pulling siblings directly after the indicator for just death rate data. <data> <country id="AFG">Afghanistan</country> <indicator id="SP.DYN.CDRT.IN">Death rate, crude (per 1,000 people)</indicator> <year>2006</year> <value>20.3410000</value> </data> - <data> <country id="AFG">Afghanistan</country> <indicator id="SP.DYN.CDRT.IN">Death rate, crude (per 1,000 people)</indicator> <year>2007</year> <value>19.9480000</value> </data> - <data> <country id="AFG">Afghanistan</country> <indicator id="SP.DYN.CDRT.IN">Death rate, crude (per 1,000 people)</indicator> <year>2008</year> <value>19.5720000</value> </data> - <data> <country id="AFG">Afghanistan</country> <indicator id="IC.EXP.DOCS">Documents to export (number)</indicator> <year>2005</year> <value>7.0000000</value> </data> - <data> <country id="AFG">Afghanistan</country> <indicator id="IC.EXP.DOCS">Documents to export (number)</indicator> <year>2006</year> <value>12.0000000</value> </data> - <data> <country id="AFG">Afghanistan</country> <indicator id="IC.EXP.DOCS">Documents to export (number)</indicator> <year>2007</year> <value>12.0000000</value> </data> Any help would be much appreciated!!!

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