Search Results

Search found 15563 results on 623 pages for 'django model'.

Page 18/623 | < Previous Page | 14 15 16 17 18 19 20 21 22 23 24 25  | Next Page >

  • customizing Django look and feel in Python

    - by user248237
    I am learning Django and got it to work with wsgi. I'm following the tutorial here: http://docs.djangoproject.com/en/1.1/intro/tutorial01/ My question is: how can I customize the look and feel of Django? Is there a repository of templates that "look good", kind of like there are for Wordpress, that I can start from? I find the tutorial counterintuitive in that it goes immediately toward customizing the admin page of Django, rather than the main pages visible to users of the site. Is there an example of a "typical" Django site, with a decent template, that I can look at and built on/modify? The polls application is again not very representative since it's so specialized. any references on this would be greatly appreciated. thanks.

    Read the article

  • Using an actor model versus a producer-consumer model?

    - by hewhocutsdown
    I'm doing some early-stage research towards architecting a new software application. Concurrency and multithreading will likely play a significant part, so I've been reading up on the various topics. The producer-consumer model, at least how it is expressed in Java, has some surface similarities but appears to be deeply dissimilar to the actor model in use with languages such as Erlang and Scala. I'm having trouble finding any good comparative data, or specific reasons to use or avoid the one or the other. Is the actor model even possible with Java or C#, or do you have do use one of the languages built for the purpose? Is there a third way?

    Read the article

  • Django anonymous user in model

    - by jack
    I have a model defined as below: class Example(models.Model): user = models.ForeignKey(User, null=True) other = models.CharField(max_length=100) The problem is Django refuses to assign django.contrib.auth.models.AnonymousUser directly to Example.user as null field so everytime I have to check if request.user.is_authenticated() ans assign Example.user = None manually. Is there a default value for AnonymousUser to use in a model field?

    Read the article

  • Can django's auth_user.username be varchar(75)? How could that be done?

    - by perrierism
    Is there anything wrong with running alter table on auth_user to make username be varchar(75) so it can fit an email? What does that break if anything? If you were to change auth_user.username to be varchar(75) where would you need to modify django? Is it simply a matter of changing 30 to 75 in the source code?: username = models.CharField(_('username'), max_length=30, unique=True, help_text=_("Required. 30 characters or fewer. Letters, numbers and @/./+/-/_ characters")) Or is there other validation on this field that would have to be changed or any other repercussions to doing so? See comment discussion with bartek below regarding the reason for doing it.

    Read the article

  • Adding links to full change forms for inline items in django admin?

    - by David Eyk
    I have a standard admin change form for an object, with the usual StackedInline forms for a ForeignKey relationship. I would like to be able to link each inline item to its corresponding full-sized change form, as the inline item has inlined items of its own, and I can't nest them. I've tried everything from custom widgets to custom templates, and can't make anything work. So far, the "solutions" I've seen in the form of snippets just plain don't seem to work for inlines. I'm getting ready to try some DOM hacking with jQuery just to get it working and move on. I hope I must be missing something very simple, as this seems like such a simple task! Using Django 1.2.

    Read the article

  • Doubt about django model API

    - by Clash
    Hello guys! So, here is what I want to do. I have a model Staff, that has a foreign key to the User model. I also have a model Match that has a foreign key to the User model. I want to select how much Matches every Staff has. I don't know how to do that, so far I only got it working for the User model. From Staff, it will not allow to annonate Match. This is what is working right now User.objects.annotate(ammount=Count("match")).filter(Q(ammount__gt=0)).order_by("ammount") And this is what I wanted to do Staff.objects.annotate(ammount=Count("match")).filter(Q(ammount__gt=0)).order_by("ammount") And by the way, is there any way to filter the matches? I want to filter the matches by a certain column. Thanks a lot in advance!

    Read the article

  • Quering distinct values throught related model

    - by matheus.emm
    Hi! I have a simple one-to-many (models.ForeignKey) relationship between two of my model classes: class TeacherAssignment(models.Model): # ... some fields year = models.CharField(max_length=4) class LessonPlan(models.Model): teacher_assignment = models.ForeignKey(TeacherAssignment) # ... other fields I'd like to query my database to get the set of distinct years of TeacherAssignments related to at least one LessonPlan. I'm able to get this set using Django query API if I ignore the relation to LessonPlan: class TeacherAssignment(models.Model): # ... model's fields def get_years(self): year_values = self.objects.all().values_list('year').distinct().order_by('-year') return [yv[0] for yv in year_values if len(yv[0]) == 4] Unfortunately I don't know how to express the condition that the TeacherAssignment must be related to at least one LessonPlan. Any ideas how I'd be able to write the query? Thanks in advance.

    Read the article

  • How to get a single widget to set 2 fields in Django?

    - by kender
    Hi, I got a model with 2 fields: latitude and longitude. Right now they're 2 CharFields, but I want to make a custom widget to set it in admin - was thinking about displaying Google Maps, then getting the coordinates of the marker. But can I have 1 widget (a single map) to set 2 different fields?

    Read the article

  • Django: Extending User Model - Inline User fields in UserProfile

    - by Jack Sparrow
    Is there a way to display User fields under a form that adds/edits a UserProfile model? I am extending default Django User model like this: class UserProfile(models.Model): user = models.OneToOneField(User, unique=True) about = models.TextField(blank=True) I know that it is possible to make a: class UserProfileInlineAdmin(admin.TabularInline): and then inline this in User ModelAdmin but I want to achieve the opposite effect, something like inverse inlining, displaying the fields of the model pointed by the OneToOne Relationship (User) in the page of the model defining the relationship (UserProfile). I don't care if it would be in the admin or in a custom view/template. I just need to know how to achieve this. I've been struggling with ModelForms and Formsets, I know the answer is somewhere there, but my little experience in Django doesn't allow me to come up with the solution yet. A little example would be really helpful!

    Read the article

  • Django model help

    - by dotty
    Does anyone have any clue why this doesn't work as expected. If i use the python shell and do team.game_set or team.games It returns an error AttributeError: 'Team' object has no attribute 'game' If i create a Game object and call game.home_team it returns the correct team object Heres my model class Team(models.Model): name = models.CharField(blank=True, max_length=100) class Game(models.Model): home_team = models.ForeignKey(Team, related_name="home_team")

    Read the article

  • Setting a preferred item of a many-to-one in Django

    - by Mike DeSimone
    I'm trying to create a Django model that handles the following: An Item can have several Names. One of the Names for an Item is its primary Name, i.e. the Name displayed given an Item. (The model names were changed to protect the innocent.) The models.py I've got looks like: class Item(models.Model): primaryName = models.OneToOneField("Name", verbose_name="Primary Name", related_name="_unused") def __unicode__(self): return self.primaryName.name class Name(models.Model): item = models.ForeignKey(Item) name = models.CharField(max_length=32, unique=True) def __unicode__(self): return self.name class Meta: ordering = [ 'name' ] The admin.py looks like: class NameInline(admin.TabularInline): model = Name class ItemAdmin(admin.ModelAdmin): inlines = [ NameInline ] admin.site.register(Item, ItemAdmin) It looks like the database schema is working fine, but I'm having trouble with the admin, so I'm not sure of anything at this point. My main questions are: How do I explain to the admin that primaryName needs to be one of the Names of the item being edited? Is there a way to automatically set primaryName to the first Name found, if primaryName is not set, since I'm using inline admin for the names?

    Read the article

  • Specifying default value for django hidden form field - bone DRY?

    - by jMyles
    So let's say at the last minute (in the view) I decide I want to specify a default for a field and make it hidden, like so: form.fields['coconut'] = forms.ModelChoiceField(label="", widget=forms.HiddenInput(), queryset=swallow.coconuts.all(), initial=some_particular_coconut) My question is this: Do I really need to specify queryset here? I mean, I already know, from initial, exactly which coconut I'm talking about. Why do I also need to specify that the universe of available coconuts is the set of coconuts which this particular swallow carried (by the husk)? Is there a way I can refrain from specifying queryset? Simply omitting causes django to raise TypeError. If indeed it is required, isn't this a bit damp?

    Read the article

  • Django forms: prepopulate form with request.user and url parameter

    - by Malyo
    I'm building simple Course Management App. I want Users to sign up for Course. Here's sign up model: class CourseMembers(models.Model): student = models.ForeignKey(Student) course = models.ForeignKey(Course) def __unicode__(self): return unicode(self.student) Student model is extended User model - I'd like to fill the form with request.user. In Course model most important is course_id, which i'm passing into view throught URL parameter (for example http://127.0.0.1:8000/courses/course/1/). What i want to achieve, is to generate 'invisible' (so user can't change the inserted data) form with just input, but containing request.user and course_id parameter.

    Read the article

  • 500 Internal Server Error when setting up Apache on Ubuntu+Django

    - by ApacheQ
    I tried with Apache on ubuntu 9.04 and get the same error: Internal Server Error The server encountered an internal error or misconfiguration and was unable to complete your request. Please contact the server administrator, webmaster@localhost and inform them of the time the error occurred, and anything you might have done that may have caused the error. More information about this error may be available in the server error log. And my apache/error.log is: [Sat Oct 06 09:32:04 2012] [error] [client 10.0.64.10] ServerName: 'sapint2' [Sat Oct 06 09:32:04 2012] [error] [client 10.0.64.10] DocumentRoot: '/etc/apache2/htdocs' [Sat Oct 06 09:32:04 2012] [error] [client 10.0.64.10] URI: '/' [Sat Oct 06 09:32:04 2012] [error] [client 10.0.64.10] Location: '/' [Sat Oct 06 09:32:04 2012] [error] [client 10.0.64.10] Directory: None [Sat Oct 06 09:32:04 2012] [error] [client 10.0.64.10] Filename: '/etc/apache2/htdocs' [Sat Oct 06 09:32:04 2012] [error] [client 10.0.64.10] PathInfo: '/' [Sat Oct 06 09:32:04 2012] [error] [client 10.0.64.10] Traceback (most recent call last): [Sat Oct 06 09:32:04 2012] [error] [client 10.0.64.10] File "/usr/lib/python2.7/dist-packages/mod_python/importer.py", line 1537, in HandlerDispatch\n default=default_handler, arg=req, silent=hlist.silent) [Sat Oct 06 09:32:04 2012] [error] [client 10.0.64.10] File "/usr/lib/python2.7/dist-packages/mod_python/importer.py", line 1229, in _process_target\n result = _execute_target(config, req, object, arg) [Sat Oct 06 09:32:04 2012] [error] [client 10.0.64.10] File "/usr/lib/python2.7/dist-packages/mod_python/importer.py", line 1128, in _execute_target\n result = object(arg) [Sat Oct 06 09:32:04 2012] [error] [client 10.0.64.10] File "/usr/local/lib/python2.7/dist-packages/django/core/handlers/modpython.py", line 180, in handler\n return ModPythonHandler()(req) [Sat Oct 06 09:32:04 2012] [error] [client 10.0.64.10] File "/usr/local/lib/python2.7/dist-packages/django/core/handlers/modpython.py", line 142, in call\n self.load_middleware() [Sat Oct 06 09:32:04 2012] [error] [client 10.0.64.10] File "/usr/local/lib/python2.7/dist-packages/django/core/handlers/base.py", line 45, in load_middleware\n mod = import_module(mw_module) [Sat Oct 06 09:32:04 2012] [error] [client 10.0.64.10] File "/usr/local/lib/python2.7/dist-packages/django/utils/importlib.py", line 35, in import_module\n import(name) [Sat Oct 06 09:32:04 2012] [error] [client 10.0.64.10] File "/usr/local/lib/python2.7/dist-packages/django/contrib/sessions/middleware.py", line 4, in \n from django.utils.cache import patch_vary_headers [Sat Oct 06 09:32:04 2012] [error] [client 10.0.64.10] File "/usr/local/lib/python2.7/dist-packages/django/utils/cache.py", line 25, in \n from django.core.cache import get_cache [Sat Oct 06 09:32:04 2012] [error] [client 10.0.64.10] File "/usr/local/lib/python2.7/dist-packages/django/core/cache/init.py", line 187, in \n cache = get_cache(DEFAULT_CACHE_ALIAS) [Sat Oct 06 09:32:04 2012] [error] [client 10.0.64.10] File "/usr/local/lib/python2.7/dist-packages/django/core/cache/init.py", line 179, in get_cache\n cache = backend_cls(location, params) [Sat Oct 06 09:32:04 2012] [error] [client 10.0.64.10] File "/usr/local/lib/python2.7/dist-packages/django/core/cache/backends/memcached.py", line 139, in init\n "Memcached cache backend requires either the 'memcache' or 'cmemcache' library" [Sat Oct 06 09:32:04 2012] [error] [client 10.0.64.10] InvalidCacheBackendError: Memcached cache backend requires either the 'memcache' or 'cmemcache' library [Sat Oct 06 09:51:30 2012] [notice] caught SIGTERM, shutting down [Sat Oct 06 09:51:31 2012] [notice] mod_python: Creating 8 session mutexes based on 150 max processes and 0 max threads. [Sat Oct 06 09:51:31 2012] [notice] mod_python: using mutex_directory /tmp [Sat Oct 06 09:51:31 2012] [notice] Apache/2.2.17 (Ubuntu) PHP/5.3.5-1ubuntu7.11 with Suhosin-Patch mod_python/3.3.1 Python/2.7.1+ mod_wsgi/3.3 configured -- resuming normal operations I need some help Thanks

    Read the article

  • Installing Django on Windows

    - by Pranav
    Ever needed to install Django in a Microsoft Windows environment, here is a quick start guide to make that happen: Read through the official Django installation documentation, it might just save you a world of hut down the road. Download Python for your version of Windows. Install Python, my preference here is to put it into the Program Files folder under a folder named Python<Version> Add your chosen Python installation path into your Windows path environment variable. This is an optional step, however it allows you to just type python in the command line and have it fire up the Python interpreter. An easy way of adding it is going into Control Panel, System and into the Environment Variables section. Download Django, you can either download a compressed file or if you’re comfortable with using version control – check it out from the Django Subversion repository. Create a folder named django under your <Python installation directory>\Lib\site-packages\ folder. Using my example above that would have been C:\Program Files\Python25\Lib\site-packages\. If you chose to download the compressed file, open it and extract the contents of the django folder into your newly created folder. If you’d prefer to check it out from Subversion, the normal check out points are http://code.djangoproject.com/svn/django/trunk/ for the latest development copy or a named release which you’ll find under http://code.djangoproject.com/svn/django/tags/releases/. Done, you now have a working Django installation on Windows. At this point, it’d be pertinent to confirm that everything is working properly, which you can do by following the first Django tutorial. The tutorial will make mention of django-admin.py, which is a utility which offers some basic functionality to get you off the ground. The file is located in the bin folder under your Django installation directory. When you need to use it, you can either type in the full path to it or simply add that file path into your environment variables as well. Hope this helps!

    Read the article

  • Django Error - AttributeError: 'Settings' object has no attribute 'LOCALE_PATHS'

    - by Randy Simon
    I am trying to learn django by following along with this tutorial. I am using django version 1.1.1 I run django-admin.py startproject mysite and it creates the files it should. Then I try to start the server by running python manage.py runserver but here is where I get the following error. Traceback (most recent call last): File "manage.py", line 11, in <module> execute_manager(settings) File "/Library/Python/2.6/site-packages/django/core/management/__init__.py", line 362, in execute_manager utility.execute() File "/Library/Python/2.6/site-packages/django/core/management/__init__.py", line 303, in execute self.fetch_command(subcommand).run_from_argv(self.argv) File "/Library/Python/2.6/site-packages/django/core/management/base.py", line 195, in run_from_argv self.execute(*args, **options.__dict__) File "/Library/Python/2.6/site-packages/django/core/management/base.py", line 213, in execute translation.activate('en-us') File "/Library/Python/2.6/site-packages/django/utils/translation/__init__.py", line 73, in activate return real_activate(language) File "/Library/Python/2.6/site-packages/django/utils/translation/__init__.py", line 43, in delayed_loader return g['real_%s' % caller](*args, **kwargs) File "/Library/Python/2.6/site-packages/django/utils/translation/trans_real.py", line 205, in activate _active[currentThread()] = translation(language) File "/Library/Python/2.6/site-packages/django/utils/translation/trans_real.py", line 194, in translation default_translation = _fetch(settings.LANGUAGE_CODE) File "/Library/Python/2.6/site-packages/django/utils/translation/trans_real.py", line 172, in _fetch for localepath in settings.LOCALE_PATHS: File "/Library/Python/2.6/site-packages/django/utils/functional.py", line 273, in __getattr__ return getattr(self._wrapped, name) AttributeError: 'Settings' object has no attribute 'LOCALE_PATHS' Now, I can add a LOCAL_PATH atribute set to an empty string to my settings.py file but then it just complains about another setting and so on. What am I missing here?

    Read the article

  • Django + Apache wsgi = paths problem

    - by Shamanu4
    Hello. I have this view which generates interface language options menu def lang_menu(request,language): lang_choices = [] import os.path for lang in settings.LANGUAGES: if os.path.isfile("gui/%s.py" % lang) or os.path.isfile("gui/%s.pyc" % lang): langimport = "from gui.%s import menu" % lang try: exec(langimport) except ImportError: lang_choices.append({'error':'invalid language file'}) else: lang_choices.append(menu) else: lang_choices.append({'error':'lang file not found'}) t = loader.get_template('gui/blocks/lang_menu_options.html') data = '' for lang in lang_choices: if not 'error' in lang: data = "%s\n%s" % (data,t.render(Context(lang))) if not data: data = "Error! No languages configured or incorrect language files!" return Context({'content':data}) When I'am using development server (python manage.py runserver ...) it works fine. But when I ported my app to apache wsgi server I've got error "No languages configured or incorrect language files!" Here is my Apache config <VirtualHost *:9999> WSGIScriptAlias / "/usr/local/etc/django/terminal/django.wsgi" <Directory "/usr/local/etc/django/terminal"> Options +ExecCGI Allow From All </Directory> Alias /media/ "/usr/local/lib/python2.5/site-packages/django/contrib/admin/media/" <Location /media/> SetHandler None </Location> <Directory "/usr/local/lib/python2.5/site-packages/django/contrib/admin/media/> Allow from all </Directory> Alias /static/ "/usr/local/etc/django/terminal/media/" <Location /static/> SetHandler None </Location> ServerName ******* ServerAlias ******* ErrorLog /var/log/django.error.log TransferLog /var/log/django.access.log </VirtualHost> django.wsgi: import os, sys sys.path.append('/usr/local/etc/django') sys.path.append('/usr/local/etc/django/terminal') os.environ['DJANGO_SETTINGS_MODULE'] = 'terminal.settings' import django.core.handlers.wsgi application = django.core.handlers.wsgi.WSGIHandler() It's look like as problem with path configuration but I'm stuck here ...

    Read the article

  • Django caching seems to be causing problems

    - by Issy
    Hey guys, i have just implemented the Django Cache Local Memory back end in some my code, however it seems to be causing a problem. I get the following error when trying to view the site (With Debug On): Traceback (most recent call last): File "/usr/lib/python2.6/dist-packages/django/core/servers/basehttp.py", line 279, in run self.result = application(self.environ, self.start_response) File "/usr/lib/python2.6/dist-packages/django/core/servers/basehttp.py", line 651, in __call__ return self.application(environ, start_response) File "/usr/lib/python2.6/dist-packages/django/core/handlers/wsgi.py", line 245, in __call__ response = middleware_method(request, response) File "/usr/lib/python2.6/dist-packages/django/middleware/cache.py", line 91, in process_response patch_response_headers(response, timeout) File "/usr/lib/python2.6/dist-packages/django/utils/cache.py", line 112, in patch_response_headers response['Expires'] = http_date(time.time() + cache_timeout) TypeError: unsupported operand type(s) for +: 'float' and 'str' I have checked my code, for caching everything seems to be ok. For example, i have the following in my middleware. MIDDLEWARE_CLASSES = ( 'django.contrib.sessions.middleware.SessionMiddleware', 'django.contrib.auth.middleware.AuthenticationMiddleware', 'django.middleware.cache.UpdateCacheMiddleware', 'django.middleware.common.CommonMiddleware', 'django.middleware.cache.FetchFromCacheMiddleware', 'django.contrib.flatpages.middleware.FlatpageFallbackMiddleware', ) My settings for Cache: CACHE_BACKEND = 'locmem://' CACHE_MIDDLEWARE_SECONDS = '3600' CACHE_MIDDLEWARE_KEY_PREFIX = 'za' CACHE_MIDDLEWARE_ANONYMOUS_ONLY = True And some of my code (template tag): def get_featured_images(): """ provides featured images """ cache_key = 'featured_images' images = cache.get(cache_key) if images is None: images = FeaturedImage.objects.all().filter(enabled=True)[:5] cache.set(cache_key, images) return {'images': images} Any idea what could be the problem, from the error message below it looks like there's an issue in django's cache.py?

    Read the article

  • django test client trouble

    - by Anton Koval'
    I've got a problem... we're writing project using django, and i'm trying to use django.test.client with nose test-framework for tests. Our code is like this: from simplejson import loads from urlparse import urljoin from django.test.client import Client TEST_URL = "http://smakly.localhost:9090/" def test_register(): cln = Client() ref_data = {"email": "[email protected]", "name": "???????", "website": "http://hot.bear.com", "xhr": "true"} print urljoin(TEST_URL, "/accounts/register/") response = loads(cln.post(urljoin(TEST_URL, "/accounts/register/"), ref_data)) print response["message"] and in nose output I catch: Traceback (most recent call last): File "/home/psih/work/svn/smakly/eggs/nose-0.11.1-py2.6.egg/nose/case.py", line 183, in runTest self.test(*self.arg) File "/home/psih/work/svn/smakly/src/smakly.tests/smakly/tests/frontend/test_profile.py", line 25, in test_register response = loads(cln.post(urljoin(TEST_URL, "/accounts/register/"), ref_data)) File "/home/psih/work/svn/smakly/parts/django/django/test/client.py", line 313, in post response = self.request(**r) File "/home/psih/work/svn/smakly/parts/django/django/test/client.py", line 225, in request response = self.handler(environ) File "/home/psih/work/svn/smakly/parts/django/django/test/client.py", line 69, in __call__ response = self.get_response(request) File "/home/psih/work/svn/smakly/parts/django/django/core/handlers/base.py", line 78, in get_response urlconf = getattr(request, "urlconf", settings.ROOT_URLCONF) File "/home/psih/work/svn/smakly/parts/django/django/utils/functional.py", line 273, in __getattr__ return getattr(self._wrapped, name) AttributeError: 'Settings' object has no attribute 'ROOT_URLCONF' My settings.py file does have this attribute. If I get the data from the server with standard urllib2.urllopen().read() it works in the proper way. Any ideas how I can solve this case?

    Read the article

  • Django's post_save signal behaves weirdly with models using multi-table inheritance

    - by hekevintran
    Django's post_save signal behaves weirdly with models using multi-table inheritance I am noticing an odd behavior in the way Django's post_save signal works when using a model that has multi-table inheritance. I have these two models: class Animal(models.Model): category = models.CharField(max_length=20) class Dog(Animal): color = models.CharField(max_length=10) I have a post save callback called echo_category: def echo_category(sender, **kwargs): print "category: '%s'" % kwargs['instance'].category post_save.connect(echo_category, sender=Dog) I have this fixture: [ { "pk": 1, "model": "animal.animal", "fields": { "category": "omnivore" } }, { "pk": 1, "model": "animal.dog", "fields": { "color": "brown" } } ] In every part of the program except for in the post_save callback the following is true: from animal.models import Dog Dog.objects.get(pk=1).category == u'omnivore' # True When I run syncdb and the fixture is installed, the echo_category function is run. The output from syncdb is: $ python manage.py syncdb --noinput Installing json fixture 'initial_data' from '~/my_proj/animal/fixtures'. category: '' Installed 2 object(s) from 1 fixture(s) The weird thing here is that the dog object's category attribute is an empty string. Why is it not 'omnivore' like it is everywhere else? As a temporary (hopefully) workaround I reload the object from the database in the post_save callback: def echo_category(sender, **kwargs): instance = kwargs['instance'] instance = sender.objects.get(pk=instance.pk) print "category: '%s'" % instance.category post_save.connect(echo_category, sender=Dog) This works but it is not something I like because I must remember to do it when the model inherits from another model and it must hit the database again. The other weird thing is that I must do instance.pk to get the primary key. The normal 'id' attribute does not work (I cannot use instance.id). I do not know why this is. Maybe this is related to the reason why the category attribute is not doing the right thing?

    Read the article

  • Django filters - Using an AllValuesFilter (with a LinkWidget) on a ManyToManyField

    - by magnetix
    This is my first Stack Overflow question, so please let me know if I do anything wrong. I wish to create an AllValues filter on a ManyToMany field using the wonderful django-filters application. Basically, I want to create a filter that looks like it does in the Admin, so I also want to use the LinkWidget too. Unfortunately, I get an error (Invalid field name: 'operator') if I try this the standard way: # Models class Organisation(models.Model): name = models.CharField() ... class Sign(models.Model): name = models.CharField() operator = models.ManyToManyField('Organisation', blank=True) ... # Filter class SignFilter(LinkOrderFilterSet): operator = django_filters.AllValuesFilter(widget=django_filters.widgets.LinkWidget) class Meta: model = Sign fields = ['operator'] I got around this by creating my own filter with the many to many relationship hard coded: # Models class Organisation(models.Model): name = models.CharField() ... class Sign(models.Model): name = models.CharField() operator = models.ManyToManyField('Organisation', blank=True) ... # Filter class MyFilter(django_filters.ChoiceFilter): @property def field(self): cd = {} for row in self.model.objects.all(): orgs = row.operator.select_related().values() for org in orgs: cd[org['id']] = org['name'] choices = zip(cd.keys(), cd.values()) list.sort(choices, key=lambda x:(x[1], x[0])) self.extra['choices'] = choices return super(AllValuesFilter, self).field class SignFilter(LinkOrderFilterSet): operator = MyFilter(widget=django_filters.widgets.LinkWidget) I am new to Python and Django. Can someone think of a more generic/elegant way of doing this?

    Read the article

  • How to filter queryset in changelist_view in django admin?

    - by minder
    Let's say I have a site where Users can add Entries through admin panel. Each User has his own Category he is responsible for (each Category has an Editor assigned through ForeingKey/ManyToManyField). When User adds Entry, I limit the choices by using EntryAdmin like this: class EntryAdmin(admin.ModelAdmin): (...) def formfield_for_foreignkey(self, db_field, request, **kwargs): if db_field.name == 'category': if request.user.is_superuser: kwargs['queryset'] = Category.objects.all() else: kwargs['queryset'] = Category.objects.filter(editors=request.user) return db_field.formfield(**kwargs) return super(EntryAdmin, self).formfield_for_foreignkey(db_field, request, **kwargs) This way I can limit the categories to which a User can add Entry and it works perfect. Now the tricky part: On the Entry changelist/action page I want to show only those Entries which belong to current User's Category. I tried to do this using this method: def changelist_view(self, request, extra_context=None): if not request.user.is_superuser: self.queryset = self.queryset.filter(editors=request.user) But I get this error: AttributeError: 'function' object has no attribute 'filter' This is strange, because I thought it should be a typical QuerySet. Basically such methods are not well documented and digging through tons of Django code is not my favourite sport. Any ideas how can I achieve my goal?

    Read the article

  • Django: TypeError: 'str' object is not callable, referer: http://xxx

    - by user705415
    I've been wondering why when I set the settings.py of my django project 'arvindemo' debug = Flase and deploy it on Apache with mod_wsgi, I got the 500 Internal Server Error. Env: Django 1.4.0 Python 2.7.2 mod_wsgi 2.8 OS centOS Here is the recap: Visit the homepage, go to sub page A/B/C/D, and fill some forms, then submit it to the Apache server. Once click 'submit' button, I will get the '500 Internal Server Error', and the error_log listed below(Traceback): [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] Traceback (most recent call last): [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] File "/opt/python2.7/lib/python2.7/site-packages/django/core/handlers/wsgi.py", line 241, in __call__ [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] response = self.get_response(request) [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] File "/opt/python2.7/lib/python2.7/site-packages/django/core/handlers/base.py", line 179, in get_response [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] response = self.handle_uncaught_exception(request, resolver, sys.exc_info()) [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] File "/opt/python2.7/lib/python2.7/site-packages/django/core/handlers/base.py", line 224, in handle_uncaught_exception [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] if resolver.urlconf_module is None: [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] File "/opt/python2.7/lib/python2.7/site-packages/django/core/urlresolvers.py", line 323, in urlconf_module [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] self._urlconf_module = import_module(self.urlconf_name) [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] File "/opt/python2.7/lib/python2.7/site-packages/django/utils/importlib.py", line 35, in import_module [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] __import__(name) [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] File "/opt/web/django/arvindemo/arvindemo/../arvindemo/urls.py", line 23, in <module> [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] url(r'^submitPage$', name=submitPage), [Tue Apr 10 10:07:20 2012] [error] [client 122.198.133.250] TypeError: url() takes at least 2 arguments (2 given) When using django runserver, I set arvindemo.settings debug = True, everything is OK. But things changed once I set debug = Flase. Here is my views.py from django.http import HttpResponseRedirect from django.http import HttpResponse, HttpResponseServerError from django.shortcuts import render_to_response import datetime, string from user_info.models import * from django.template import Context, loader, RequestContext import settings def hello(request): return HttpResponse("hello girl") def helpPage(request): return render_to_response('kktHelp.html') def server_error(request, template_name='500.html'): return render_to_response(template_name, context_instance = RequestContext(request) ) def page404(request): return render_to_response('404.html') def submitPage(request): post = request.POST Mall = 'goodsName' Contest = 'ojs' Presentation = 'addr' WeatherReport = 'city' Habit = 'task' if Mall in post: return submitMall(request) elif Contest in post: return submitContest(request) elif Presentation in post: return submitPresentation(request) elif Habit in post: return submitHabit(request) elif WeatherReport in post: return submitWeather(request) else: return HttpResponse(request.POST) return HttpResponseRedirect('404') def submitXXX(): ..... def xxxx(): .... Here comes the urls.py from django.conf.urls import patterns, include, url from views import * from django.conf import settings handler500 = 'server_error' urlpatterns = patterns('', url(r'^hello/$', hello), # hello world url(r'^$', homePage), url(r'^time/$', getTime), url(r'^time/plus/(\d{1,2})/$', hoursAhead), url(r'^Ttime/$', templateGetTime), url(r'^Mall$', templateMall), url(r'^Contest$', templateContest), url(r'^Presentation$', templatePresentation), url(r'^Habit$', templateHabit), url(r'^Weather$', templateWeather), url(r'^Help$', helpPage), url(r'^404$', page404), url(r'^500$', server_error), url(r'^submitPage$', submitPage), url(r'^submitMall$', submitMall), url(r'^submitContest$', submitContest), url(r'^submitPresentation$', submitPresentation), url(r'^submitHabit$', submitHabit), url(r'^submitWeather$', submitWeather), url(r'^terms$', terms), url(r'^privacy$', privacy), url(r'^thanks$', thanks), url(r'^about$', about), url(r'^static/(?P<path>.*)$','django.views.static.serve',{'document_root':settings.STATICFILES_DIRS}), ) I'm sure there is no syntax error in my django project,cause when I use django runserver, everything is fine. Anyone can help ? Best regards

    Read the article

< Previous Page | 14 15 16 17 18 19 20 21 22 23 24 25  | Next Page >