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  • Fun things you can do by mutating Java strings

    - by polygenelubricants
    So I've come around since I asked how to limit setAccessible to only “legitimate” uses and have come to embrace its power for fun. Enabled by its power, of course, is string mutation. import java.lang.reflect.Field; public class Mutator { static void mutate(Object obj, String field, Object newValue) { try { Field f = obj.getClass().getDeclaredField(field); f.setAccessible(true); f.set(obj, newValue); } catch (Exception e) { } } public static void mutate(String from, String to) { mutate(from, "value", to.toCharArray()); mutate(from, "count", to.length()); } public static void main(String args[]) { Mutator.mutate(System.getProperty("line.separator"), "<br/>\n"); System.out.println("Hello world!"); Mutator.mutate(Integer.toString(Integer.MIN_VALUE), "OMG!"); System.out.println(-2147483648); Mutator.mutate(String.valueOf((Object) null), "LOL!"); System.out.println(Arrays.toString(new int[3][])); Mutator.mutate(Arrays.toString(new int[0]), ":("); System.out.println(Arrays.toString(new byte[0])); } } Output (if no exception is thrown): Hello world!<br/> OMG!<br/> [LOL!, LOL!, LOL!]<br/> :(<br/> Let's see what other fun things we can come up with.

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  • Dymanic if statement evaluation problem with string comparison

    - by Mani
    I tried the example given in http://forums.sun.com/thread.jspa?threadID=780576&tstart=67605 to create if statement dynamically. But it is not working fine. Instead of using "age" variable as integer, i have used string in the below example. I am getting "fail" as answer instead of "success". Can anyone help me? / To change this template, choose Tools | Templates and open the template in the editor. / import java.lang.reflect.*; import bsh.Interpreter; public class Main { public static String d; public static void main(String args[]) { try { String age = "30"; String cond = "age==30"; Interpreter i = new Interpreter(); i.set("age", age); System.out.println(" sss" + i.get("age")); if((Boolean)i.eval(cond)) { System.out.println("success"); } else { System.out.println("fail"); } } catch (Throwable e) { System.err.println(e); } } } Thanks, Mani

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  • Backreferences syntax in replacement strings (why dollar sign?)

    - by polygenelubricants
    In Java, and it seems in a few other languages, backreferences in the pattern is preceded by a slash (e.g. \1, \2, \3, etc), but in a replacement string it's preceded by a dollar sign (e.g. $1, $2, $3, and also $0). Here's a snippet to illustrate: System.out.println( "left-right".replaceAll("(.*)-(.*)", "\\2-\\1") // WRONG!!! ); // prints "2-1" System.out.println( "left-right".replaceAll("(.*)-(.*)", "$2-$1") // CORRECT! ); // prints "right-left" System.out.println( "You want million dollar?!?".replaceAll("(\\w*) dollar", "US\\$ $1") ); // prints "You want US$ million?!?" System.out.println( "You want million dollar?!?".replaceAll("(\\w*) dollar", "US$ \\1") ); // throws IllegalArgumentException: Illegal group reference Questions: Is the use of $ for backreferences in replacement strings unique to Java? If not, what language started it? What flavors use it and what don't? Why is this a good idea? Why not stick to the same pattern syntax? Wouldn't that lead to a more cohesive and an easier to learn language? Wouldn't the syntax be more streamlined if statements 1 and 4 in the above were the "correct" ones instead of 2 and 3?

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  • Java Reflection, java.lang.IllegalAccessException Error

    - by rubby
    Hi all, My goal is : Third class will read the name of the class as String from console.Upon reading the name of the class, it will automatically and dynamically (!) generate that class and call its writeout method. If that class is not read from input, it will not be initialized. And I am taking java.lang.IllegalAccessException: Class deneme.class3 can not access a member of class java.lang.Object with modifiers "protected" error. And i don't know how i can fix it.. Can anyone help me? import java.io.*; import java.lang.reflect.*; class class3 { public void run() { try { BufferedReader reader= new BufferedReader(new InputStreamReader(System.in)); String line=reader.readLine(); Class c1 = Class.forName("java.lang.String"); Object obj = new Object(); Class c2 = obj.getClass(); Method writeout = null; for( Method mth : c2.getDeclaredMethods() ) { writeout = mth; break; } Object o = c2.newInstance(); writeout.invoke( o ); } catch(Exception ee) { System.out.println("ERROR! "+ee); } } public void writeout3() { System.out.println("class3"); } } class class4 { public void writeout4() { System.out.println("class4"); } } class ornek { public static void main(String[] args) { System.out.println("Please Enter Name of Class : "); class3 example = new class3(); example.run(); } }

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  • using volatile keyword

    - by sap
    As i understand, if we declare a variable as volatile, then it will not be stored in the local cache. Whenever thread are updating the values, it is updated to the main memory. So, other threads can access the updated value. But in the following program both volatile and non-volatile variables are displaying same value. The volatile variable is not updated for the second thread. Can anybody plz explain this why testValue is not changed. class ExampleThread extends Thread { private int testValue1; private volatile int testValue; public ExampleThread(String str){ super(str); } public void run() { if (getName().equals("Thread 1 ")) { testValue = 10; testValue1= 10; System.out.println( "Thread 1 testValue1 : " + testValue1); System.out.println( "Thread 1 testValue : " + testValue); } if (getName().equals("Thread 2 ")) { System.out.println( "Thread 2 testValue1 : " + testValue1); System.out.println( "Thread 2 testValue : " + testValue); } } } public class VolatileExample { public static void main(String args[]) { new ExampleThread("Thread 1 ").start(); new ExampleThread("Thread 2 ").start(); } } output: Thread 1 testValue1 : 10 Thread 1 testValue : 10 Thread 2 testValue1 : 0 Thread 2 testValue : 0

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  • Regex help in java validations

    - by user1697113
    Hi i want to do some validations.I used to put regex in JS but im new to regex in java, so i tried to make up a code on similar lines in java. Here is what i did. 1)Check whether first character in string is alphanumeric. 2)Check whether the string atleast 1 number. so i wrote a code, but it is always returning false.I am not sure if i'm doing this correctly. private static boolean checkEmbeddedPassword(final String field) { boolean returnValue=true; String testpatternAlpha="/^[A-Za-z0-9].+$/"; String testNumber="/[0-9]/"; Pattern pattern=Pattern.compile(testpatternAlpha); Pattern pattern2=Pattern.compile(testNumber); Matcher matcher = pattern.matcher(field); Matcher matcher2 = pattern2.matcher(field); boolean firstChar=matcher.matches(); boolean numberFlag=matcher2.matches(); System.out.println("-----the value of pwd iss-----"+field); System.out.println("---------Regex---------Out--put-----"+firstChar); System.out.println("---------Regex---------Out- for numeral-put-----"+numberFlag); if(firstChar){ returnValue=false; } else if(field.contains(" ")) { System.out.println("-----------cannot have space------"); returnValue=false; } else if(numberFlag) { returnValue=false; } return returnValue; }

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  • Super class variables not printing through sub class

    - by Abhishek Singh
    Can u tell me why this code is not displaying any result on the console. class employee { protected String name; protected double salary; protected String dob; public employee(String name, double salary, String dob) { this.name = name; this.salary = salary; this.dob = dob; } public employee(String name, double salary) { this.name = name; this.salary = salary; } } public class Manage extends employee { String dept1; public Manage(String name, double salary, String dob, String dept1) { super(name, salary, dob); this.dept1 = dept1; } public Manage(String name, double salary, String dept1) { super(name, salary); this.dept1 = dept1; } public static void main(String args[]) { employee e = new employee("Vikas", 122345); employee e2 = new employee("Vikas", 122345, "12-2-1991"); Manage m = (Manage) new Manage("Vikas", 122345, "Sales"); Manage m2 = new Manage("Vikas", 122345, "12-2-1991", "sales"); m.display(); m2.display(); } public void display() { System.out.println("Name " + name); System.out.println("Salary " + salary); System.out.println("Birth " + dob); System.out.println("Department " + dept1); } }

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  • static block instance block java Order

    - by Rollerball
    Having read this question In what order are the different parts of a class initialized when a class is loaded in the JVM? and the related JLS. I would like to know in more detail why for example having class Animal (superclass) and class Dog (subclass) as following: class Animal { static{ System.out.println("This is Animal's static block speaking"): } { System.out.println("This is Animal's instance block speaking"); } class Dog{ static{ System.out.println("This is Dog's static block speaking"); } { System.out.println("This is Dog's instance block speaking"); } public static void main (String [] args) { Dog dog = new Dog(); } } Ok before instantiating a class its direct superclass needs to be initialized (therefore all the statics variables and block need to be executed). So basically the question is: Why after initializing the static variables and static blocks of the super class, control goes down to the subclass for static variables initialization rather then finishing off the initialization of also the instance member? The control goes like: superclass (Animal): static variables and static blocks subclass (Dog): static variables and static blocks superclass (Animal): instance variables and instance blocks sublcass (Dog):instance variables and instance blocks What is the reason why it is in this way rather than : superclass -> static members superclass -> instance members subclass -> static members sublcass-> instance members

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  • General JDBC Setup

    - by AeroDroid
    So I have a MySQL database set up on a Debian server and it works fine from a phpMyAdmin client. I'm currently working on a project to write a Java server that would be able to use the MySQL database that is already on this server through a JDBC connection. I've looked at many tutorials and documentations but all of them seem to just explain how to do client-side code, but I have yet to figure out how to even successfully open a JDBC connection to the server. As far as I am concerned, I believe that program has the drivers properly set up because it's not crashing anymore (I simply direct the Java Build Path of my program to the Connector/J provided by MySQL). As far as my program goes, this is what it looks like... import java.sql.*; public class JDBCTest { public static void main(String[] args) { System.out.println("Started!"); try { DriverManager.registerDriver(new com.mysql.jdbc.Driver()); System.out.println("Driver registered. Connecting..."); Connection conn = DriverManager.getConnection("jdbc:mysql://localhost/", "root", "password"); System.out.println("Connected!"); conn.close(); } catch (SQLException e) { System.out.println("Error!"); e.printStackTrace(); } } } This is what's printed... Started! Driver registered. Connecting... It's as if the DriverManager.getConnection(String) just freezes there. I'm sure this is a problem with the server because when I intentionally misspell localhost, or an IP address, the program crashes within 20 seconds. This just hangs there forever. Sorry about this wall of text, but my final question is if anyone has any information what I should do or install on the server to get this to work? Thank you so much!

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  • Liferay Document Management System Workflow

    - by Rajkumar
    I am creating a DMS in Liferay. So far I could upload documents in Liferay in document library. And also i can see documents in document and media portlet. The problem is though status for the document is in pending state, the workflow is not started. Below is my code. Anyone please help. Very urgent. Folder folder = null; // getting folder try { folder = DLAppLocalServiceUtil.getFolder(10181, 0, folderName); System.out.println("getting folder"); } catch(NoSuchFolderException e) { // creating folder System.out.println("creating folder"); try { folder = DLAppLocalServiceUtil.addFolder(userId, 10181, 0, folderName, description, serviceContext); } catch (PortalException e3) { // TODO Auto-generated catch block e3.printStackTrace(); } catch (SystemException e3) { // TODO Auto-generated catch block e3.printStackTrace(); } } catch (PortalException e4) { // TODO Auto-generated catch block e4.printStackTrace(); } catch (SystemException e4) { // TODO Auto-generated catch block e4.printStackTrace(); } // adding file try { System.out.println("New File"); fileEntry = DLAppLocalServiceUtil.addFileEntry(userId, 10181, folder.getFolderId(), sourceFileName, mimeType, title, "testing description", "changeLog", sampleChapter, serviceContext); Map<String, Serializable> workflowContext = new HashMap<String, Serializable>(); workflowContext.put("event",DLSyncConstants.EVENT_CHECK_IN); DLFileEntryLocalServiceUtil.updateStatus(userId, fileEntry.getFileVersion().getFileVersionId(), WorkflowConstants.ACTION_PUBLISH, workflowContext, serviceContext); System.out.println("after entry"+ fileEntry.getFileEntryId()); } catch (DuplicateFileException e) { } catch (PortalException e1) { // TODO Auto-generated catch block e1.printStackTrace(); } catch (SystemException e1) { // TODO Auto-generated catch block e1.printStackTrace(); } } catch (PortalException e) { // TODO Auto-generated catch block e.printStackTrace(); } catch (SystemException e) { // TODO Auto-generated catch block e.printStackTrace(); } } return fileEntry.getFileEntryId(); } I have even used WorkflowHandlerRegistryUtil.startWorkflowInstance(companyId, userId, fileEntry.getClass().getName(), fileEntry.getClassPK, fileEntry, serviceContext); But still i have the same problem

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  • JAAS + authentification from database

    - by AhmedDrira
    i am traying to performe an authentification from data base using JAAS i v configured the login-config.xml like this <application-policy name="e-procurment_domaine"> <authentication> <login-module code="org.jboss.security.auth.spi.DatabaseServerLoginModule" flag="required"> <module-option name = "dsJndiName">BasepfeDS</module-option> <module-option name="securityDomain">java:/jaas/e-procurment_domaine</module-option> <module-option name="principalsQuery">SELECT pass FROM personne WHERE login=?</module-option> <module-option name="rolesQuery">SELECT disc FROM personne WHERE login=?</module-option> </login-module> </authentication> </application-policy> and I've written a test : this one @Test public void testFindALL() { System.out.println("Debut test de la méthode findALL"); // WebAuthentication wa=new WebAuthentication(); // wa.login("zahrat", "zahrat"); securityClient.setSimple("zahrat", "zahrat"); try { securityClient.login(); } catch (LoginException e) { // TODO Auto-generated catch block e.printStackTrace(); } Acheteur acheteur = new Acheteur(); System.out.println("" + acheteurRemote.findAll().size()); // } catch (EJBAccessException ex) { // System.out.println("Erreur attendue de type EJBAccessException: " // + ex.getMessage()); // } catch (Exception ex) { // ex.printStackTrace(); // fail("Exception pendant le test find ALL"); System.out.println("Fin test find ALL");} // } the test is fail i dont know why , but when i change the polycy with the methode of .property file it works .. i am using the annotation on the session BEAN classes @SecurityDomain("e-procurment_domaine") @DeclareRoles({"acheteur","vendeur","physique"}) @RolesAllowed({"acheteur","vendeur","physique"}) and the annotation on the session for the methode @RolesAllowed("physique") @Override public List<Acheteur> findAll() { log.debug("fetching all Acheteur"); return daoGenerique.findWithNamedQuery("Acheteur.findAll"); } i think that the test have an acess to my data base doe's it need mysql DRIVER or a special config on JBOSS?

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  • How to redirect page

    - by sharun
    Hi i created one java application in which i tried to open my company's standard login page and i planned to redirect the link to open my own design page. Standard login page is displayed, instead of going to my own design page as usual its going to mail page. After sign out the mail page i'm gettting my own design page. But my need is, when i sign in the standard login page it should diplay my own design page. Is it possible? Please Help me. And this is code that i followed import java.io.IOException; import javax.servlet.http.HttpServlet; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import com.google.appengine.api.users.UserService; import com.google.appengine.api.users.UserServiceFactory; import com.google.appengine.api.users.User; public class New extends HttpServlet { /** * */ private static final long serialVersionUID = 1L; public void doPost(HttpServletRequest req, HttpServletResponse resp) throws IOException { resp.setHeader("Cache-Control", "no-store, no-cache, must-revalidate"); resp.setContentType("text/html"); UserService userService = UserServiceFactory.getUserService(); User user = userService.getCurrentUser(); if (user != null) { if(user.getEmail().equals("[email protected]")) { resp.getWriter().println("done"); resp.sendRedirect("/login.jsp"); } else { resp.getWriter().println("Hello, " + user.getNickname()+"<br>"); resp.getWriter().println("Thanks for your interest. But this application is still not available to everybody."); resp.getWriter().println("<a href="+UserServiceFactory.getUserService().createLogoutURL(userService.createLoginURL(req.getRequestURI()))+">Log out</a>"); } } else { resp.sendRedirect(userService.createLoginURL("http://mail.yyy.edu.in")); } } } Thanks in advance Regards Sharun.

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  • How Does One Make Scala Control Abstraction in Repeat Until?

    - by peter_pilgrim
    Hi I am Peter Pilgrim. I watched Martin Odersky create a control abstraction in Scala. However I can not yet seem to repeat it inside IntelliJ IDEA 9. Is it the IDE? package demo class Control { def repeatLoop ( body: = Unit ) = new Until( body ) class Until( body: = Unit ) { def until( cond: = Boolean ) { body; val value: Boolean = cond; println("value="+value) if ( value ) repeatLoop(body).until(cond) // if (cond) until(cond) } } def doTest2(): Unit = { var y: Int = 1 println("testing ... repeatUntil() control structure") repeatLoop { println("found y="+y) y = y + 1 } { until ( y < 10 ) } } } The error message reads: Information:Compilation completed with 1 error and 0 warnings Information:1 error Information:0 warnings C:\Users\Peter\IdeaProjects\HelloWord\src\demo\Control.scala Error:Error:line (57)error: Control.this.repeatLoop({ scala.this.Predef.println("found y=".+(y)); y = y.+(1) }) of type Control.this.Until does not take parameters repeatLoop { In the curried function the body can be thought to return an expression (the value of y+1) however the declaration body parameter of repeatUntil clearly says this can be ignored or not? What does the error mean?

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  • Hashtable with int array as key in java

    - by Niels Hansen
    Hey! I'm trying to make a hashtable in java where the keys are int[], but it dosen't work. I have made a little test program to show my problem: public class test{ public static void main(String[] args){ int[] test0 = {1,1}; int[] test1 = {1,1}; Hashtable<int[], String> ht = new Hashtable<int[], String>(); String s0 = "foo"; ht.put(test0, s0); System.out.println("the result from ht.get(test1)"); System.out.println(ht.get(test1)); System.out.println("the result from ht.get(test0)"); System.out.println(ht.get(test0)); } } My intention is that both ht.get calles should return the same result, since the two arrays are equal, but they dont. Here is the result from running the code: the result from ht.get(test1) null the result from ht.get(test0) foo Am I missing something here or is it just impossible to use int[] as keys in a hastable?

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  • Java Socket Returns True

    - by ikurtz
    I hope you can help. Im fairly new to progamming and Im playing around with java Sockets. The problem is the code below. for some reason commSocket = new Socket(hostName, portNumber); is returning true even when it has not connected with the server (server not implemented yet!). Any ideas regarding this situation? For hostName Im passing my local machine IP and for port a manually selected port. public void networkConnect(String hostName, int portNumber){ try { networkConnected = false; netMessage = "Attempting Connection"; NetworkMessage networkMessage = new NetworkMessage(networkConnected, netMessage); commSocket = new Socket(hostName, portNumber); // this returns true!! System.out.println(commSocket.isConnected()); networkConnected = true; netMessage = "Connected: "; System.out.println("hellooo"); } catch (UnknownHostException e){ System.out.println(e.getMessage()); } catch (IOException e){ System.out.println(e.getMessage()); } } Many thanks. EDIT: new Socket(.., ..); is blocking isnt it? i thought in that case if that was processed without exceptions then we have a true connection?

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  • Wildcards vs. generic methods

    - by FredOverflow
    Is there any practical difference between the following approaches to print all elements in a range? public static void printA(Iterable<?> range) { for (Object o : range) { System.out.println(o); } } public static <T> void printB(Iterable<T> range) { for (T x : range) { System.out.println(x); } } Apparently, printB involves an additional checked cast to Object (see line 16), which seems rather stupid to me -- isn't everything an Object anyway? public static void printA(java.lang.Iterable); Code: 0: aload_0 1: invokeinterface #18, 1; //InterfaceMethod java/lang/Iterable.iterator:()Ljava/util/Iterator; 6: astore_2 7: goto 24 10: aload_2 11: invokeinterface #24, 1; //InterfaceMethod java/util/Iterator.next:()Ljava/lang/Object; 16: astore_1 17: getstatic #30; //Field java/lang/System.out:Ljava/io/PrintStream; 20: aload_1 21: invokevirtual #36; //Method java/io/PrintStream.println:(Ljava/lang/Object;)V 24: aload_2 25: invokeinterface #42, 1; //InterfaceMethod java/util/Iterator.hasNext:()Z 30: ifne 10 33: return public static void printB(java.lang.Iterable); Code: 0: aload_0 1: invokeinterface #18, 1; //InterfaceMethod java/lang/Iterable.iterator:()Ljava/util/Iterator; 6: astore_2 7: goto 27 10: aload_2 11: invokeinterface #24, 1; //InterfaceMethod java/util/Iterator.next:()Ljava/lang/Object; 16: checkcast #3; //class java/lang/Object 19: astore_1 20: getstatic #30; //Field java/lang/System.out:Ljava/io/PrintStream; 23: aload_1 24: invokevirtual #36; //Method java/io/PrintStream.println:(Ljava/lang/Object;)V 27: aload_2 28: invokeinterface #42, 1; //InterfaceMethod java/util/Iterator.hasNext:()Z 33: ifne 10 36: return

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  • tomcat resource missing, servlet not running

    - by user2837260
    import javax.servlet.*; import java.io.*; public class MyServlet implements Servlet { public void init(ServletConfig con) {} public void service(ServletRequest req, ServletResponse res) throws IOException,ServletException { res.setContentType("text/html"); PrintWriter out=res.getWriter(); String s="blah"; String s1="blah"; out.println("<html><body>"); if((s.equals(req.getParameter("firstname")))&&(s1.equals(req.getParameter("pwd")))) out.println("passwords match"); else out.println("password and name combo does not match"); out.println("</body></html>"); } public void destroy() {} public ServletConfig getServletConfig() { return null;} public String getServletInfo() { return null;} } this is my java file with the servlet class.its saved with the name MyServlet.java and so is the class file. and here is the xml file: <web-app> <servlet> <servlet-name>demoo</servlet-name> <servlet-class>MyServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>demoo</servlet-name> <url-pattern>/demo</url-pattern> </servlet-mapping> </web-app> i have made the folder as WEB-INF and then classes... WEB-INF also contains the .xml file but when i try to run the servlet , it says resource not found ps- i am already looking for the servlet with the name :demo localhost:8081/s1/demo* s1 is the war file * a html file in the war file seems to run fine on the server though. *

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  • Read quicktime movie from servlet in a webpage?

    - by khue
    Hi, I have a servlet that construct response to a media file request by reading the file from server: File uploadFile = new File("C:\\TEMP\\movie.mov"); FileInputStream in = new FileInputStream(uploadFile); Then write that stream to the response stream. My question is how do I play the media file in the webpage using embed or object tag to read the media stream from the response? Here is my code in the servlet: public void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { request.getParameter("location"); uploadFile(response); } private void uploadFile(HttpServletResponse response) { File transferFile = new File("C:/TEMP/captured.mov"); FileInputStream in = null; try { in = new FileInputStream(transferFile); } catch (FileNotFoundException e) { System.out.println("File not found"); } try { System.out.println("in byes i s" + in.available()); } catch (IOException e) { } DataOutputStream responseStream = null; try { responseStream = new DataOutputStream(response.getOutputStream()); } catch (IOException e) { System.out.println("Io exception"); } try { Util.copyStream(in, responseStream); } catch (CopyStreamException e) { System.out.println("copy Stream exception"); } try { responseStream.flush(); } catch (IOException e) { } try { responseStream.close(); } catch (IOException e) { } } And here is html page as Ryan suggested: <embed SRC="http://localhost:7101/movies/transferservlet" WIDTH=100 HEIGHT=196 AUTOPLAY=true CONTROLLER=true LOOP=false PLUGINSPAGE="http://www.apple.com/quicktime/"> Any ideas?

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  • Java if statement strings and more

    - by user1820578
    I have decided to try and learn a little in java tonight and i have just been trying some stuff with things i have learned. My question is in an if statement how to i make two stings to be true. Here is what i have so far. if ("male".equals(gender)) && ("brendan".equals(name)) the problem i am pretty sure is the && but i am not sure. also my other question is with gender it should either be male or female. I want to have if statement with male and another for female. For this do i just do another if. For eg if ("male".equals(gender)) && ("brendan".equals(name)) { System.out.println("blah blah"); } else { System.out.println(" wrong wrong"); } if ("female".equals(gender)) { System.out.println("blah blah2"); } else { System.out.println(" wrong wrong 2"); } hope that makes sense. Any help would be great.

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  • Getting User input with Scanner

    - by Giannis
    I am trying to have a scanner take input in a loop. Once the user wants to finish he can exit this loop. I have tried many different ways to do it but there is always some problem. This is the code: Scanner sc = new Scanner(System.in); System.out.println("Continue?[Y/N]"); while (sc.hasNext()&& (sc.next().equals("Y"))) { System.out.println("Enter first name"); String name = sc.nextLine(); System.out.println("Enter surname"); String surname = sc.nextLine(); . . . System.out.println("Continue?[Y/N]"); } } The problem with the code above, which also happens on different methods I tried, is that when the user types Y, the scanner will skip the first input for first name,and jump to the surname. If the user types N the loop stops correctly. Someone can explain the reason this happens, and how to overcome using scanner class? p.s: Doing something like while(sc.nextLine().equals("Y")), will cause the loop to terminate before getting input from user after first run of the loop.

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  • JAVA MySql multiple word search

    - by user1703849
    i have a database in MySql that has a name column in it which contains several words(description). I am connected to database with java through eclipse. I have a search, that returns results if only name field contains one word. id: name: info: type: 1 balloon big red balloon big 2 house expensive beautiful luxury 3 chicken wings deep fried wings tasty these are just random words but as an example my search can only see ex. balloon and then show info, but if i type chicken wings, it does nothing. so it possible somehow to search from columns with multiple words? this is my search code below import java.io.*; import java.sql.*; import java.util.*; class Search { public static void main(String[] args) { Scanner inp``ut = new Scanner(System.in); try { Connection con = DriverManager.getConnection( "jdbc:mysql://example/mydb", "user", "password"); Statement stmt = (Statement) con.createStatement(); System.out.print("enter search: "); String name = input.next(); String SQL = "SELECT * FROM menu where name LIKE '" + name + "'"; ResultSet rs = stmt.executeQuery(SQL); while (rs.next()) { System.out.println("Name: " +rs.getString("name")); System.out.println("Description: " + rs.getString("info") ); System.out.println("Price: " + rs.getString("Price")); } } catch (Exception e) { System.out.println("ERROR: " + e.getMessage()); } } }

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  • Groovy htmlunit getFirstByXPath returning null

    - by StartingGroovy
    I have had a few issues with HtmlUnit returning nulls lately and am looking for guidance. each of my results for grabbing the first row of a website have returned null. I am wondering if someone can A) explain why they might be returning null B) explain better ways (if there are some) to go about getting the information Here is my current code (URL is in the source): client = new WebClient(BrowserVersion.FIREFOX_3) client.javaScriptEnabled = false def url = "http://www.hidemyass.com/proxy-list/" page = client.getPage(url) IpAddress = page.getFirstByXPath("//html/body/div/div/form/table/tbody/tr/td[2]").getValue() println "IP Address is: $data" //returns null //Port_Number is an Image Country = page.getFirstByXPath("//html/body/div/div/form/table/tbody/tr/td[4][@class='country']/@rel").getValue() println "Country abbreviation is: $Country" //differentiate speed and connection by name of gif? Type = page.getFirstByXPath("//html/body/div/div/form/table/tbody/tr/td[7]").getValue() println "Proxy type is: $Type" Anonymity = page.getFirstByXPath("//html/body/div/div/form/table/tbody/tr/td[8]").getValue() println "Anonymity Level is: $Anonymity" client.closeAllWindows() Right now all of my XPaths return null and .getValue() obviously doesn't work on null. I also have questions as to what I should do about the PORT since it is an image? Is there a better alternative than downloading it and attempting to solve it by OCR? Side Note There is no significance in this site, I was just looking for a site that I could practice scraping on (the last one I ran into issues of fragment identities and couldn't get an answer to: HtmlUnit getByXpath returns null and HtmlUnit and Fragment Identities )

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  • java programming

    - by Baiba
    ok i have version of t code, please tell me what i need to do when i need to get out of program The INDEX NUMBER OF COLUMN IN WHICH ARE LEAST ZEROS? class Uzd{ public static void main(String args[]){ int mas[][]= {{3,4,7,5,0}, {4,5,3,0,1}, {8,2,4,0,3}, {7,0,2,0,1}, {0,0,1,3,0}}; int nul_mas[] = new int[5]; int nul=0; for(int j=0;j<5;j++){// nul=0; for(int i=0;i<5;i++){ if(mas[i][j]==0){ nul++; } } nul_mas[j]=nul; } for(int i=0;i<5;i++){ for(int j=0;j<5;j++){ System.out.print(mas[i][j]); } System.out.println(); } System.out.println();// atstarpe System.out.println("///zeros in each column///"); for(int i=0;i<5;i++){System.out.print(nul_mas[i]);} System.out.println(); }} and after running it shows: 34750 45301 82403 70201 00130 ///zeros in each column/// But i need not in each column but i need to get out index of column in which zeros are least! in this situation it is column nubmer 2!! 12032

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  • Load Testing Java Web Application - find TPS / Avg transaction response time

    - by Steve
    I would like to build my own load testing tool in Java with the goal of being able to load test a web application I am building throughout the development cycle. The web application will be receiving server to server HTTP Post requests and I would like to find its starting transaction per second (TPS) capacity along with the avgerage response time. The Post request and response messages will be in XML (I dont' think that's really applicable though :) ). I have written a very simple Java app to send transactions and count how many transactions it was able to send in one second (1000 ms) however I don't think this is the best way to load test. Really what I want is to send any number of transactions at exactly the same time - i.e. 10, 50, 100 etc. Any help would be appreciated! Oh and here is my current test app code: Thread[] t = new Thread[1]; for (int a = 0; a < t.length; a++) { t[a] = new Thread(new MessageLoop()); } startTime = System.currentTimeMillis(); System.out.println(startTime); for (int a = 0; a < t.length; a++) { t[a].start(); } while ((System.currentTimeMillis() - startTime) < 1000 ) { } if ((System.currentTimeMillis() - startTime) > 1000 ) { for (int a = 0; a < t.length; a++) { t[a].interrupt(); } } long endTime = System.currentTimeMillis(); System.out.println(endTime); System.out.println("Total time: " + (endTime - startTime)); System.out.println("Total transactions: " + count); private static class MessageLoop implements Runnable { public void run() { try { //Test Number of transactions while ((System.currentTimeMillis() - startTime) < 1000 ) { // SEND TRANSACTION HERE count++; } } catch (Exception e) { } } }

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  • Ant build script executing <sql> task using java code

    - by Jay
    Any idea, why none of the debugging comments are printed once after executing the ANT build script's SQL task via java code? The java class to execute the sql in build scirpt is public class AntRunnerTest { private Project project; public void executeTask(String taskName) { try { project = new Project(); project.init(); project.setBasedir(new String(".")); ProjectHelper helper = ProjectHelper.getProjectHelper(); project.addReference("ant.projectHelper", helper); helper.parse(project, new File("build-copy.xml")); System.out.println("Before"); project.executeTarget(taskName); System.out.println("After"); } catch(Exception ex) { System.out.println(ex.getMessage()); } } public static void main(String args[]) { try { AntRunnerTest newInst = new AntRunnerTest(); newInst.executeTask("sql"); } catch(Exception e) { System.out.println(""+e); } } } I dont see the debug String "After" getting printed in the console. I noticed this issue only when i try to execute a sql task using java code. The ant script has the following simple transaction tag in it. <transaction> <![CDATA[ select now() ]]> </transaction> Any thoughts? Thanks in advance.

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