Search Results

Search found 13866 results on 555 pages for 'apache commons math'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 184/555 | < Previous Page | 180 181 182 183 184 185 186 187 188 189 190 191  | Next Page >

  • Tomcat fails on first request in combination with jsvc

    - by Roalt
    I have a web application where the first request may take a few seconds as some singletons are initialised. I've used the mod_proxy and jsvc construction mentioned in this question and described on this page to connect apache with tomcat (data is served via SSL) For the sample Tomcat application, everything works as it should. However, when using my application I get the following error in my apache log: [Wed Feb 10 09:48:29 2010] [error] [client 130.12.1.26] (70014)End of file found: proxy: error reading status line from remote server localhost [Wed Feb 10 09:48:29 2010] [error] [client 130.12.1.26] proxy: Error reading from remote server returned by /MyWebApp/MyWebApp.faces and I get the following error in my tomcat output: 10/02/2010 09:48:29 9947 jsvc.exec error: Service exit with a return value of 1 I'm not an expert on this so I would like to know what's the cause of the problem and where I should look for an answer?

    Read the article

  • Choosing circle radius to fully fill a rectangle

    - by Andy
    Hi, the pixman image library can draw radial color gradients between two circles. I'd like the radial gradient to fill a rectangular area defined by "width" and "height" completely. Now my question, how should I choose the radius of the outer circle? My current parameters are the following: A) inner circle (start of gradient) center pointer of inner circle: (width*0.5|height*0.5) radius of inner circle: 1 color: black B) outer circle (end of gradient) center pointer of outer circle: (width*0.5|height*0.5) radius of outer circle: ??? color: white How should I choose the radius of the outer circle to make sure that the outer circle will entirely fill my bounding rectangle defined by width*height. There shall be no empty areas in the corners, the area shall be completely covered by the circle. In other words, the bounding rectangle width,height must fit entirely into the outer circle. Choosing outer_radius = max(width, height) * 0.5 as the radius for the outer circle is obviously not enough. It must be bigger, but how much bigger? Thanks!

    Read the article

  • Need some help understanding this problem about maximizing graph connectivity

    - by Legend
    I was wondering if someone could help me understand this problem. I prepared a small diagram because it is much easier to explain it visually. Problem I am trying to solve: 1. Constructing the dependency graph Given the connectivity of the graph and a metric that determines how well a node depends on the other, order the dependencies. For instance, I could put in a few rules saying that node 3 depends on node 4 node 2 depends on node 3 node 3 depends on node 5 But because the final rule is not "valuable" (again based on the same metric), I will not add the rule to my system. 2. Execute the request order Once I built a dependency graph, execute the list in an order that maximizes the final connectivity. I am not sure if this is a really a problem but I somehow have a feeling that there might exist more than one order in which case, it is required to choose the best order. First and foremost, I am wondering if I constructed the problem correctly and if I should be aware of any corner cases. Secondly, is there a closely related algorithm that I can look at? Currently, I am thinking of something like Feedback Arc Set or the Secretary Problem but I am a little confused at the moment. Any suggestions? PS: I am a little confused about the problem myself so please don't flame on me for that. If any clarifications are needed, I will try to update the question.

    Read the article

  • How to pass Endpoint parameter to Endpoint defined as bean in Spring conext

    - by sempa
    I have camel Fileendpoint defined in following way: <bean id="hotfolderEndpoint" class="org.apache.camel.component.file.FileEndpoint" factory-bean="camel" factory-method="getEndpoint"> <constructor-arg ref="hotfolder" /> </bean> I want to define some File parameters such as preMove, move etc. Variable hotfolder is String taken from JNDI and I have no impact on it. When I define property as <bean id="moveExp" class="org.apache.camel.model.language.SimpleExpression"> <property name="expression" value="done/${file:name}"/> </bean> it is not correctly parsed and the file get name done/name

    Read the article

  • Interview question: f(f(n)) == -n

    - by Hrvoje Prgeša
    A question I got on my last interview: Design a function f, such that: f(f(n)) == -n Where n is a 32 bit signed integer; you can't use complex numbers arithmetic. If you can't design such a function for the whole range of numbers, design it for the largest range possible. Any ideas?

    Read the article

  • reflection paths between points in2d

    - by Chris H
    Just wondering if there was a nice (already implemented/documented) algorithm to do the following Given any shape (without crossing edges) and two points inside that shape, compute all the paths between the two points such that all reflections are perfect reflections. The path lengths should be limited to a certain length otherwise there are infinite solutions. I'm not interested in just shooting out rays to try to guess how close I can get, I'm interested in algorithms that can do it perfectly. Search based, not guess/improvement based.

    Read the article

  • htaccess handler

    - by Steve
    Hi Everyone, I have strange problem that need help. It is about rewrite using apache. Here my .htaccess content file: Options +FollowSymLinks ## This is an example .htaccess-file ## To get everything automatically parsed, the following line is needed #set link auto on ##From now on, every RewriteRule gets recognised. RewriteEngine on RewriteRule captcha(\.html){0,1}$ captcha.php [QSA,L] RewriteCond %{SCRIPT_FILENAME} !-s RewriteCond %{SCRIPT_FILENAME} !-d RewriteCond %{SCRIPT_FILENAME} !-f Rewriterule (.*) handler.php ##You can also change the text before the real link by the following line With this rule, I am hoping that all request except there is exists in file or directory will be directed to my custom handler: handler.php. Everyting just fine as expected but this case not: http://../test/form_login/query=%2Ftest%2Findex.php%3Fpage%3Dform& Root url: /test/, form_login is not file or directory index.php is exists in the root. Apache response with : 404 Page Not Found Thanks for any of your help. Regards, Steve

    Read the article

  • BOM in a PHP page auto generated by Wordpress

    - by Paolo63
    I admin two different blogs. They are both wordpress 2.8.6 (so they have exactly the same source code, plugins apart) but they are located on two different hosting platform (hostmonster.com and aruba.it). To explain my problem I've dumped with SmartSniff a session with each one of the sites. Here is the dump from hostmonster: GET /blog/paolo/ HTTP/1.1 Host: www.e-venturi.com Accept-Encoding: identity Accept-Language: en-us Accept: text/html, text/plain, text/xml, image/gif, image/x-xbitmap, image/x-icon,image/jpeg, image/pjpeg, application/vnd.ms-powerpoint, application/vnd.ms-excel, application/msword, */* User-Agent: Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.0;) HTTP/1.1 200 OK Date: Sat, 28 Nov 2009 23:47:38 GMT Server: Apache/2.2.14 (Unix) mod_ssl/2.2.14 OpenSSL/0.9.8l DAV/2 mod_auth_passthrough/2.1 FrontPage/5.0.2.2635 X-Powered-By: PHP/5.2.11 X-Pingback: http://www.e-venturi.com/blog/paolo/xmlrpc.php Vary: Accept-Encoding Transfer-Encoding: chunked Content-Type: text/html; charset=UTF-8 a6 <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> and now from aruba: GET /blog/ HTTP/1.1 Host: www.cubanite.net Accept-Encoding: identity Accept-Language: en-us Accept: text/html, text/plain, text/xml, image/gif, image/x-xbitmap, image/x-icon,image/jpeg, image/pjpeg, application/vnd.ms-powerpoint, application/vnd.ms-excel, application/msword, */* User-Agent: Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.0;) HTTP/1.1 200 OK Date: Sat, 28 Nov 2009 23:49:19 GMT Server: Apache/2.2 X-Pingback: http://www.cubanite.net/blog/xmlrpc.php Vary: Accept-Encoding Transfer-Encoding: chunked Content-Type: text/html; charset=UTF-8 100b ...<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> (note: a6 and 100b are the packet size reported by SmartSniff) Ok, the big difference are the three dots in front of the <!DOCTYPE in aruba. They are the UTF-8 BOM (0xef 0xbb 0xbf). Being the same PHP source on both the servers, why does it appears only on one server ? The content is generated so the post author can't deliberately insert a BOM and I've verified the template to be BOM free too. Naturally there are different PHP and Apache versions on the servers... what can I check or set to diagnose and resolve the problem ? By the way I don't want the BOM. Many thanks in advance.

    Read the article

  • how to subtract circle from an arbitrary polygon

    - by George
    Given an arbitary polygon with vertices stored in either clockwise/counterclockwise fashion (depicted as a black rectangle in the diagram), I need to be able to subtract an arbitrary number of circles (in red on the diagram) from that polygon. Removing a circle could possibly split the polygon into two seperate polygons (as depicted by the second line in the diagram). I'm not sure where to start. http://www.freeimagehosting.net/image.php?89a0276d9d.jpg

    Read the article

  • Drawing Directed Acyclic Graphs: Minimizing edge crossing?

    - by Robert Fraser
    Laying out the verticies in a DAG in a tree form (i.e. verticies with no in-edges on top, verticies dependent only on those on the next level, etc.) is rather simple without graph drawing algorithms such as Efficient Sugimiya. However, is there a simple algorithm to do this that minimizes edge crossing? (For some graphs, it may be impossible to completely eliminate edge crossing.) A picture says a thousand words, so is there an algorithm that would suggest: instead of: EDIT: As the picture suggests, a vertex's inputs are always on top and outputs are always below, which is another barrier to just pasting in an existing layout algorithm.

    Read the article

  • Sparse quadratic program solver

    - by Jacob
    This great SO answer points to a good sparse solver, but I've got constraints on x (for Ax = b) such that each element in x is >=0 an <=N. The first thing which comes to mind is an QP solver for large sparse matrices. Also, A is huge (around 2e6x2e6) but very sparse with <=4 elements per row. Any ideas/recommendations?

    Read the article

  • What is likely cause of Android runtime exception "No suitable Log implementation" related to loggin

    - by M.Bearden
    I am creating an Android app that includes a third party jar. That third party jar utilizes internal logging that is failing to initialize when I run the app, with this error: "org.apache.commons.logging.LogConfigurationException: No suitable Log implementation". The 3rd party jar appears to be using org.apache.commons.logging and to depend on log4j, specifically log4j-1.2.14.jar. I have packaged the log4j jar into the Android app. The third party jar was packaged with a log4j.xml configuration file, which I have tried packaging into the app as an XML resource (and also as a raw resource). The "No suitable Log implementation" error message is not very descriptive, and I have no immediate familiarity with Java logging. So I am looking for likely causes of the problem (what class or configuration resources might I be missing?) or for some debugging technique that will result in a different error message that is more explicit about the problem. I do not have access to source code for the 3rd party jar. Here is the exception stack trace. When I run the app, I get the following exception as soon as one of the third party jar classes attempts to initialize its internal logging. DEBUG/AndroidRuntime(15694): Shutting down VM WARN/dalvikvm(15694): threadid=3: thread exiting with uncaught exception (group=0x4001b180) ERROR/AndroidRuntime(15694): Uncaught handler: thread main exiting due to uncaught exception ERROR/AndroidRuntime(15694): java.lang.ExceptionInInitializerError ERROR/AndroidRuntime(15694): Caused by: org.apache.commons.logging.LogConfigurationException: No suitable Log implementation ERROR/AndroidRuntime(15694): at org.apache.commons.logging.impl.LogFactoryImpl.discoverLogImplementation(LogFactoryImpl.java:842) ERROR/AndroidRuntime(15694): at org.apache.commons.logging.impl.LogFactoryImpl.newInstance(LogFactoryImpl.java:601) ERROR/AndroidRuntime(15694): at org.apache.commons.logging.impl.LogFactoryImpl.getInstance(LogFactoryImpl.java:333) ERROR/AndroidRuntime(15694): at org.apache.commons.logging.impl.LogFactoryImpl.getInstance(LogFactoryImpl.java:307) ERROR/AndroidRuntime(15694): at org.apache.commons.logging.LogFactory.getLog(LogFactory.java:645) ERROR/AndroidRuntime(15694): at org.apache.commons.configuration.ConfigurationFactory.<clinit>(ConfigurationFactory.java:77)

    Read the article

  • Merge overlapping triangles into a polygon

    - by nornagon
    I've got a bunch of overlapping triangles from a 3D model projected into a 2D plane. I need to merge each island of touching triangles into a closed, non-convex polygon. The resultant polygons shouldn't have any holes in them (since the source data doesn't). Many of the source triangles share (floating point identical) edges with other triangles in the source data. What's the easiest way to do this? Performance isn't particularly important, since this will be done at design time.

    Read the article

  • Need a formula for calculating the tax portion of a total amount.

    - by pawz
    In Australia we have to advertise products with tax already added, so rather than say a product is $10 + $1 GST = $11, we normally work backwards and say "ok, total is $10, how much of that is GST ?" For example, for a $10 total, you do 10 * (1 /11) = 0.91, which is the tax component of the $10 total. My problem is I need calculate a formula for working out the taxable component when the tax rate is a variable. So far I've made this calculation although I'm not sure how correct an assertion it is: 10 * (1 / x) = 0.09 * (1 / y) where y = 10, x = 11 Basically i want to work out x on the left hand side when I know that the tax rate is 0.05 for example, which will give me a formula that I can use to calculate the taxable component of an total figure. I want a function into which I can plug in the total price and the tax rate, and get back the taxable component of the total price. I'd really appreciate the help with this as it really makes my head hurt ! :")

    Read the article

  • Apache Lucene or another Search in iPhone app

    - by lostInTransit
    Hi I would like to implement a search functionality within my iPhone app which can search for terms within all the documents in the application. I believe I cannot use Apache Lucene directly since it is in Java. Can I use Lucy which is a C port of Lucene (not sure if Perl and Ruby would work on it)? Or is there any other open-source search engine which I can use in my iPhone app for search within the app? Thanks

    Read the article

  • Finding the intersection of two vector equations.

    - by Matthew Mitchell
    I've been trying to solve this and I found an equation that gives the possibility of zero division errors. Not the best thing: v1 = (a,b) v2 = (c,d) d1 = (e,f) d2 = (h,i) l1: v1 + ?d1 l2: v2 + µd2 Equation to find vector intersection of l1 and l2 programatically by re-arranging for lambda. (a,b) + ?(e,f) = (c,d) + µ(h,i) a + ?e = c + µh b +?f = d + µi µh = a + ?e - c µi = b +?f - d µ = (a + ?e - c)/h µ = (b +?f - d)/i (a + ?e - c)/h = (b +?f - d)/i a/h + ?e/h - c/h = b/i +?f/i - d/i ?e/h - ?f/i = (b/i - d/i) - (a/h - c/h) ?(e/h - f/i) = (b - d)/i - (a - c)/h ? = ((b - d)/i - (a - c)/h)/(e/h - f/i) Intersection vector = (a + ?e,b + ?f) Not sure if it would even work in some cases. I haven't tested it. I need to know how to do this for values as in that example a-i. Thank you.

    Read the article

  • how to determine base of a number?

    - by evil.coder
    Given a integer number and its reresentation in some arbitrary number system. The purpose is to find the base of the number system. For example, number is 10 and representation is 000010, then the base should be 10. Another example: number 21 representation is 0010101 then base is 2. One more example is: number is 6 and representation os 10100 then base is sqrt(2). Does anyone have any idea how to solve such problem?

    Read the article

  • Installing Bugzilla on Ubuntu 9.04 and Plesk

    - by makeflo
    Hey guys. I'm trying to install the latest Bugzilla version on my ubuntu server. (Want to use a subdomain like bugs.domain.com) I already installed all necessary perl modules and check_modules.pl doesn't show any errors. But when I'm running the testserver.pl script I get the following: TEST-OK Webserver is running under group id in $webservergroup TEST-FAILED Fetch of images/padlock.png failed I'm also not able to visit ANY file within the bugzilla folder from the browser. I'm always getting a 404 error. The bugzilla folder and all containing files are set to apache as the owner. I tried to enter the apache configuration form the installation guide in the http.include file of the domain and in the vhosts.conf file of the subdomain as well. I don't know what to do... Playing with plesks' suexecgroup doesn't bring any solution... I hope you can help me! Thanks in advance!

    Read the article

  • Check if BigInteger is not a perfect square

    - by Ender
    I have a BigInteger value, let's say it is 282 and is inside the variable x. I now want to write a while loop that states: while b2 isn't a perfect square: a ? a + 1 b2 ? a*a - N endwhile How would I do such a thing using BigInteger? EDIT: The purpose for this is so I can write this method. As the article states one must check if b2 is not square.

    Read the article

  • Using bitwise operators on > 32 bit integers

    - by dqhendricks
    I am using bitwise operations in order to represent many access control flags within one integer. ADMIN_ACCESS = 1; EDIT_ACCOUNT_ACCESS = 2; EDIT_ORDER_ACCESS = 4; var myAccess = 3; // ie: ( ADMIN_ACCESS | EDIT_ACCOUNT_ACCESS ) if ( myAccess & EDIT_ACCOUNT_ACCESS ) { // check for correct access // allow for editing of account } Most of this is occurring on the PHP side of my project. There is one piece however where Javascript is used to join several access flags using | when saving someone's access level. This works fine to a point. I have found that once an integer (flag) gets too large ( 32bit), it no longer works correctly with bitwise operators in Javascript. For instance: alert( 4294967296 | 1 ); // equals 1, but should equal 4294967297 I am trying to find a workaround for this so that I do not have to limit my number of access control flags to 32. Each access control flag is two times the previous control flag so that each control flag will not interfere with other control flags. dec(4) = bin(100) dec(8) = bin(1000) dec(16) = bin(10000) I have noticed that when adding two of these flags together with a simple +, it seems to come out with the same answer as a bitwise or operation, but am having trouble wrapping my head around whether this is a simple substitution, or if there might be problems with doing this. Can anyone comment on the validity of this workaround? Example: (4294967296 | 262144 | 524288) == (4294967296 + 262144 + 524288)

    Read the article

  • Diagonal of polygon is inside or outside?

    - by Himadri
    I have three consecutive points of polygon, say p1,p2,p3. Now I wanted to know whether the orthogonal between p1 and p3 is inside the polygon or outside the polygon. I am doing it by taking three vectors v1,v2 and v3. And the point before the point p1 in polygon say p0. v1 = (p0 - p1) v2 = (p2 - p1) v3 = (p3 - p1) With reference to this question, I am using the method shown in the accepted answer of that question. It is only for counterclockwise. What if my points are clockwise. I am also knowing my whole polygon is clockwise or counterclockwise. And accordingly I select the vectors v1 and v2. But still I am getting some problem. I am showing one case where I am getting problem. This polygon is counterclockwise. and It is starting from the origin of v1 and v2.

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 180 181 182 183 184 185 186 187 188 189 190 191  | Next Page >