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  • Using WPF class in a web application, problem with hosting permission

    - by tanathos
    I'm developing a DLL that uses WPF classes to make image manipulation. It works fine in my local environment, but when I try to use it in an hosted web site I retrieve this error: Request for the permission of type 'System.Security.Permissions.MediaPermission, WindowsBase, Version=3.0.0.0, Culture=neutral, PublicKeyToken=31bf3856ad364e35' failed. exactly when I try to call the EndInit() of a BitmapImage object: BitmapImage originalImage = new BitmapImage(); originalImage.BeginInit(); originalImage.CacheOption = BitmapCacheOption.OnLoad; originalImage.UriSource = new Uri(physical_imagepath); originalImage.EndInit(); Any suggestion?

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  • Error with connection in my database servlet

    - by Zerobu
    Hello, I am writing a Database servlet, all seems well except that there seems to be an error in my connection import java.io.IOException; import java.sql.Connection; import java.sql.DriverManager; import java.sql.PreparedStatement; import java.sql.ResultSet; import java.sql.SQLException; import java.sql.Statement; import java.util.ArrayList; import javax.servlet.RequestDispatcher; import javax.servlet.ServletContext; import javax.servlet.ServletException; import javax.servlet.http.HttpServlet; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; public class DBServlet3 extends HttpServlet { private static final long serialVersionUID = 1L; @Override public void init() throws ServletException { super.init(); try { String jdbcDriverClass= getServletContext().getInitParameter( "jdbcDriverClass" ); if (jdbcDriverClass == null) throw new ServletException( "Could not find jdbcDriverClass initialization parameter" ); Class.forName( jdbcDriverClass ); } catch (ClassNotFoundException e) { throw new ServletException( "Could not load JDBC driver class", e ); } } @Override protected void doGet( HttpServletRequest request, HttpServletResponse response ) throws ServletException, IOException { RequestDispatcher dispatcher= request.getRequestDispatcher( "/db.jsp" ); ServletContext application= getServletContext(); ArrayList<String> names= new ArrayList<String>(); try { Connection connection= null; Statement statement= null; ResultSet results= null; try { String jdbcUrl= application.getInitParameter( "jdbcUrl" ); String jdbcUser= application.getInitParameter( "jdbcUser" ); String jdbcPassword= application.getInitParameter( "jdbcPassword" ); connection= DriverManager.getConnection( jdbcUrl, jdbcUser, jdbcPassword ); statement= connection.createStatement(); results= statement.executeQuery( "SELECT * FROM students" ); while (results.next()) { String name= results.getString( "name" ); names.add( name ); } } finally { if (results != null) results.close(); if (statement != null) statement.close(); if (connection != null) connection.close(); } } catch (SQLException e) { throw new ServletException( e ); } request.setAttribute( "names", names ); dispatcher.forward( request, response ); } @Override protected void doPost( HttpServletRequest request, HttpServletResponse response ) throws ServletException, IOException { String sql= "INSERT INTO students VALUES (" + request.getParameter( "id" ) + ", '" + request.getParameter( "name" ) + "')"; sql= "INSERT INTO students VALUES (?, ?, ?, ?)"; PreparedStatement statement= connection.prepareStatement( sql ); //error on this line statement.setString( 1, request.getParameter( "id" ) ); statement.setString( 2, request.getParameter( "name" ) ); } }

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  • Transaction within transaction

    - by user281521
    Hello, I want to know if open a transaction inside another is safe and encouraged? I have a method: def foo(): session.begin try: stuffs except Exception, e: session.rollback() raise e session.commit() and a method that calls the first one, inside a transaction: def bar(): stuffs try: foo() #<<<< there it is :) stuffs except Exception, e: session.rollback() raise e session.commit() if I get and exception on the foo method, all the operations will be rolled back? and everything else will work just fine? thanks!!

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  • Copying blocks (ie: copying them to instance variables) in Objective-C

    - by RyanWilcox
    I'm trying to understand blocks. I get how to use them normally, when passed directly to a method. I'm interested now in taking a block, storing it (say) in an instance variable and calling it later. The blocks programming guide makes it sound like I can do this, by using Block_copy / retain to copy the block away, but when I try to run it I crash my program. - (void) setupStoredBlock { int salt = 42; m_storedBlock = ^(int incoming){ return 2 + incoming + salt; }; [m_storedBlock retain]; } I try to call it later: - (void) runStoredBlock { int outputValue = m_storedBlock(5); NSLog(@"When we ran our stored blockwe got back: %d", outputValue); [m_storedBlock release]; } Anyone have any insights? (Or, is there something I'm not getting with blocks?) Thank you very much!

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  • Thread sleep and thread join.

    - by Dhruv Gairola
    hi guys, if i put a thread to sleep in a loop, netbeans gives me a caution saying Invoking Thread.sleep in loop can cause performance problems. However, if i were to replace the sleep with join, no such caution is given. Both versions compile and work fine tho. My code is below (check the last few lines for "Thread.sleep() vs t.join()"). public class Test{ //Display a message, preceded by the name of the current thread static void threadMessage(String message) { String threadName = Thread.currentThread().getName(); System.out.format("%s: %s%n", threadName, message); } private static class MessageLoop implements Runnable { public void run() { String importantInfo[] = { "Mares eat oats", "Does eat oats", "Little lambs eat ivy", "A kid will eat ivy too" }; try { for (int i = 0; i < importantInfo.length; i++) { //Pause for 4 seconds Thread.sleep(4000); //Print a message threadMessage(importantInfo[i]); } } catch (InterruptedException e) { threadMessage("I wasn't done!"); } } } public static void main(String args[]) throws InterruptedException { //Delay, in milliseconds before we interrupt MessageLoop //thread (default one hour). long patience = 1000 * 60 * 60; //If command line argument present, gives patience in seconds. if (args.length > 0) { try { patience = Long.parseLong(args[0]) * 1000; } catch (NumberFormatException e) { System.err.println("Argument must be an integer."); System.exit(1); } } threadMessage("Starting MessageLoop thread"); long startTime = System.currentTimeMillis(); Thread t = new Thread(new MessageLoop()); t.start(); threadMessage("Waiting for MessageLoop thread to finish"); //loop until MessageLoop thread exits while (t.isAlive()) { threadMessage("Still waiting..."); //Wait maximum of 1 second for MessageLoop thread to //finish. /*******LOOK HERE**********************/ Thread.sleep(1000);//issues caution unlike t.join(1000) /**************************************/ if (((System.currentTimeMillis() - startTime) > patience) && t.isAlive()) { threadMessage("Tired of waiting!"); t.interrupt(); //Shouldn't be long now -- wait indefinitely t.join(); } } threadMessage("Finally!"); } } As i understand it, join waits for the other thread to complete, but in this case, arent both sleep and join doing the same thing? Then why does netbeans throw the caution?

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  • [iPhone app] Detecting which key has been pressed in UITextField

    - by Dough
    Hi, I have an UITextField object in my view and want to launch a method when user press backspace button and textField is empty. First I have to do is to create a cursor storing text length, so when cursor changes from 1 to 0 there is nothing to do. The only way to launch the method is when text length is 0 - press backspace - remain to 0. How to catch the event of pressing the backspace key in my UITextField ? Thanks in advance !

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  • Losing session after Login - Java

    - by Patrick Villela
    I'm building an application that needs to login to a certain page and make a navigation. I can login, provided that the response contains a string that identifies it. But, when I navigate to the second page, I can't see the page as a logged user, only as anonymous. I'll provide my code. import java.net.*; import java.security.*; import java.security.cert.*; import javax.net.ssl.*; import java.io.*; import java.util.*; public class PostTest { static HttpsURLConnection conn = null; private static class DefaultTrustManager implements X509TrustManager { @Override public void checkClientTrusted(X509Certificate[] arg0, String arg1) throws CertificateException {} @Override public void checkServerTrusted(X509Certificate[] arg0, String arg1) throws CertificateException {} @Override public X509Certificate[] getAcceptedIssuers() { return null; } } public static void main(String[] args) { try { SSLContext ctx = SSLContext.getInstance("TLS"); ctx.init(new KeyManager[0], new TrustManager[] {new DefaultTrustManager()}, new SecureRandom()); SSLContext.setDefault(ctx); String data = URLEncoder.encode("txtUserName", "UTF-8") + "=" + URLEncoder.encode(/*username*/, "UTF-8"); data += "&" + URLEncoder.encode("txtPassword", "UTF-8") + "=" + URLEncoder.encode(/*password*/", "UTF-8"); data += "&" + URLEncoder.encode("envia", "UTF-8") + "=" + URLEncoder.encode("1", "UTF-8"); connectToSSL(/*login url*/); conn.setDoOutput(true); OutputStreamWriter wr = new OutputStreamWriter(conn.getOutputStream()); wr.write(data); wr.flush(); BufferedReader rd = new BufferedReader(new InputStreamReader(conn.getInputStream())); String line; String resposta = ""; while((line = rd.readLine()) != null) { resposta += line + "\n"; } System.out.println("valid login -> " + resposta.contains(/*string that assures me I'm looged in*/)); connectToSSL(/*first navigation page*/); rd = new BufferedReader(new InputStreamReader(conn.getInputStream())); while((line = rd.readLine()) != null) { System.out.println(line); } } catch(Exception e) { e.printStackTrace(); } } private static void connectToSSL(String address) { try { URL url = new URL(address); conn = (HttpsURLConnection) url.openConnection(); conn.setHostnameVerifier(new HostnameVerifier() { @Override public boolean verify(String arg0, SSLSession arg1) { return true; } }); } catch(Exception ex) { ex.printStackTrace(); } } } Any further information, just ask. Thanks in advance.

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  • Array index is not accessable because it is Friend

    - by user3738194
    I am getting and error when I bring my code into another project. In a blank project it works fine, I really have no idea how to get around it, here is the error Error 1 'System.Data.Index' is not accessible in this context because it is 'Friend'. Dim DataString As String = txtAdvancedCommand.Text ' Create an array containing from each letter in Textbox Dim charArray() As Char = DataString.ToCharArray For index = 0 To charArray.GetUpperBound(0) <-----ERROR on word index Try 'Now lets send the data If SerialPort.IsOpen Then SerialPort.Write(charArray(index) & vbCrLf) <-----ERROR on word index Else ConnectSerial() SerialPort.Write(charArray(index) & vbCrLf) <-----ERROR on word index End If Catch e As Exception txtLog.AppendText(e.Message & vbCrLf) End Try Next now the project I am bringing into has a DLL and I suspect it has something to do with it, I cannot get the source code to the DLL so is there another way around this?

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  • web service exception handling

    - by Jack
    I have a WebMethod that recevives following types of parameters: [WebMethod] User(long userid,int number) When Client send parameter with different types, I have to catch this error and write to database etc.. How can I solve this? Thanks.

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  • using AsyncTask class for parallel operationand displaying a progress bar

    - by Kumar
    I am displaying a progress bar using Async task class and simulatneously in parallel operation , i want to retrieve a string array from a function of another class that takes some time to return the string array. The problem is that when i place the function call in doing backgroung function of AsyncTask class , it gives an error in Doing Background and gives the message as cant change the UI in doing Background .. Therefore , i placed the function call in post Execute method of Asynctask class . It doesnot give an error but after the progress bar has reached 100% , then the screen goes black and takes some time to start the new activity. How can i display the progress bar and make the function call simultaneously.??plz help , m in distress here is the code package com.integrated.mpr; import android.app.Activity; import android.app.ProgressDialog; import android.content.Intent; import android.os.AsyncTask; import android.os.Bundle; import android.os.Handler; import android.view.View; import android.view.View.OnClickListener; import android.widget.Button; public class Progess extends Activity implements OnClickListener{ static String[] display = new String[Choose.n]; Button bprogress; @Override protected void onCreate(Bundle savedInstanceState) { // TODO Auto-generated method stub super.onCreate(savedInstanceState); setContentView(R.layout.progress); bprogress = (Button) findViewById(R.id.bProgress); bprogress.setOnClickListener(this); } @Override public void onClick(View v) { // TODO Auto-generated method stub switch(v.getId()){ case R.id.bProgress: String x ="abc"; new loadSomeStuff().execute(x); break; } } public class loadSomeStuff extends AsyncTask<String , Integer , String>{ ProgressDialog dialog; protected void onPreExecute(){ dialog = new ProgressDialog(Progess.this); dialog.setProgressStyle(ProgressDialog.STYLE_HORIZONTAL); dialog.setMax(100); dialog.show(); } @Override protected String doInBackground(String... arg0) { // TODO Auto-generated method stub for(int i = 0 ;i<40;i++){ publishProgress(5); try { Thread.sleep(1000); } catch (InterruptedException e) { // TODO Auto-generated catch block e.printStackTrace(); } } dialog.dismiss(); String y ="abc"; return y; } protected void onProgressUpdate(Integer...progress){ dialog.incrementProgressBy(progress[0]); } protected void onPostExecute(String result){ display = new Logic().finaldata(); Intent openList = new Intent("com.integrated.mpr.SENSITIVELIST"); startActivity(openList); } } }

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  • JsonStore.insert() causes exception in extjs

    - by kalan
    I have an EditorGridPanel with toolbar button to add new records. Everything works fine except one scenario. When I try to insert a record which already exists in database, server sends back: {"success":false,"message":"already exists","data":{}} but grid creates a new row marked with red triangle. If after that I try to insert a new record (even if it doesn't exist in database), everything works fine on the server side, but i get an 'uncaught exception' in firebug. It says: 'uncaught exception: Ext.data.DataReader: #realize was called with invalid remote-data. Please see the docs for DataReader#realize and review your DataReader configuration.' why is that?

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  • What is a good way of checking to see if a particular user may access a particular file?

    - by Rising Star
    I am working on application which runs as a special unprivileged user. I would like to be able to easily check to see if the user can read a given file. It seems like this should be easy, even when I go into the file in Windows Explorer and see that the read permission is checked, it sometimes seems that there is still something preventing the user from reading the file (such as a parent directory that the user cannot browse) when I try to read it as the user programmatically. The user has no console logon permission, so I can't just log in as the user and try to read the file. So... If I want to know, "Does UserBob have access to file c:\specialPath\specialFile, what is an easy way to find out? BTW, my environment is Windows Server 2003.

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  • How do I find where an exception was thrown in C++?

    - by Alex
    I have a program that throws an uncaught exception somewhere. All I get is a report of an exception being thrown, and no information as to where it was thrown. It seems illogical for a program compiled to contain debug symbols not to notify me of where in my code an exception was generated. Is there any way to tell where my exceptions are coming from short of setting 'catch throw' in gdb and calling a backtrace for every single thrown exception?

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  • Gridview changing text in a button column

    - by Bob Avallone
    I am working in asp.net using the gridview control. I have a button column that I create dynamically as such: ButtonField bfSelect = new ButtonField(); bfSelect.HeaderText = "View"; bfSelect.ButtonType = ButtonType.Link; bfSelect.CommandName = "View"; bfSelect.Text = "View"; grdAttachments.Columns.Add(bfSelect); The text on the button is the same for every row. I was wondering if there was any way to have the text be different for different rows depending on a condition. When I try to look at the text property of a particular row it is blank, if I try to set it, it does not change. Thanks in advance. Bob

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  • IIS5, ASP.NET (3.5) Application and Visual Studio 2008

    - by Lakeshore
    I have a solution that was developed in VS 2008 that is configured to use IIS. I configure the Virtual directory in IIS the same way I have with other working solutions using IIS. When I either build and run the solution in VS 2008 or browse the virtual directory using IIS, I get the following error message. Internet Explorer cannot display the webpage What you can try: It appears you are not connected to the Internet, but you might want to try to reconnect to the Internet Retype the address Go back to the previous page. Most likely causes: You are not connected to the Internet The website is encountering problems There might be a typing error in the address. Why might this be?

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  • Swing UI does not have native OS look

    - by Virat Kadaru
    I am building an application in java swing and I am using the following code to give the UI a native OS look try { UIManager.setLookAndFeel( UIManager.getSystemLookAndFeelClassName()); } catch (Exception e) { e.printStackTrace(); } On a OS X, the look is fine, but on windows (XP and 7) the buttons look like this. I have used this exact same code on other projects and it works fine. But in this particular project I get a completely different look. Thanks in advance!

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  • warning: (Internal error: pc 0x804a6b0 in read in psymtab, but not in symtab.) g++

    - by Sriram
    Hi, I am trying to debug a program using ddd. When I try to enter any function, or within main() itself, I get the following warning: warning: (Internal error: pc 0x804a6b0 in read in psymtab, but not in symtab.) This warning flashes whenever I try to move to another instruction using 'n' or enter or leave a function. I have tried to look this up in other forums, but with no conclusive answer. The code I am trying to debug runs into several files and I am not sure if I can post the entire code here. I am using g++ version: g++ (GCC) 4.4.1 20090725 (Red Hat 4.4.1-2) Any help on this is most welcome. Thanks, Sriram.

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  • Android: Issue with acceptable file types via bluetooth

    - by poeschlorn
    Hi guys, i've got a problem with pushing files to my nexus one: It seems to me that there is only a small selection of file types that are accepted by my phone (such like jpg, gif and so on). I recently tried to push other files to my phone (in my case gpx) and my phone has rejected it automatically... is there a way to bypass or extent this filter? Is there also a way to catch those files by a service? greets, poeschlorn

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  • which version of the code below is right?

    - by TheVillageIdiot
    Hi I found this function in a utilities code file: Version 1: public static bool IsValidLong(string strLong) { bool result = true; try { long tmp = long.Parse(strLong); } catch (Exception ex) { result = false; } return result; } I want to replace this (and validators for other types) with following: Version 2: public static bool IsValidLong(string strLong) { long l; return long.TryParse(strLong, out l); } which version is better and why?

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  • How is the Viewflipper handling the back button in Android?

    - by Janusz
    I'm thinking about using a ViewFlipper for an Wizard like Activity. But I see one problem with this approach. The back button. Will the back button go back to the last shown activity or will the the Viewflipper somehow catch the back button event and only change to the last shown activity? I suspect the ViewFlipper to be treated as one Activity on the BackStack so is seems that is the wrong aproach for a wizard. Is this correct?

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  • How to use sound and images in a Java applet?

    - by Click Upvote
    Question 1: How should I structure my project so the sound and images files can be loaded most easily? Right now, I have the folder: C:\java\pacman with the sub-directory C:\java\pacman\src containing all the code, and C:\java\pacman\assets containing the images and .wav files. Is this the best structure or should I put the assets somewhere else? Question 2: What's the best way to refer to the images/sounds without using the full path e.g C:\java\pacman\assets\something.png to them? If I use the getCodeBase() function it seems to refer to the C:\java\pacman\bin instead of C:\java\pacman\. I want to use such a function/class which would work automatically when i compile the applet in a jar as well as right now when I test the applet through eclipse. Question 3: How should I load the images/sounds? This is what I'm using now: 1) For general images: import java.awt.Image; public Image getImg(String file) { //imgDir in this case is a hardcoded string containing //"C:\\java\\pacman\\assets\\" file=imgDir + file; return new ImageIcon(file).getImage(); } The images returned from this function are used in the drawImage method of the Graphics class in the paint method of the applet. 2) For a buffered image, which is used to get subImages and load sprites from a sprite sheet: public BufferedImage getSheet() throws IOException { return ImageIO.read(new File(img.getPath("pacman-sprites.png"))); } Later: public void loadSprites() { BufferedImage sheet; try { sheet=getSheet(); redGhost.setNormalImg(sheet.getSubimage(0, 60, 20, 20)); redGhost.setUpImg(sheet.getSubimage(0, 60, 20, 20)); redGhost.setDownImg(sheet.getSubimage(30, 60, 20, 20)); redGhost.setLeftImg(sheet.getSubimage(30, 60, 20, 20)); redGhost.setRightImg(sheet.getSubimage(60, 60, 20, 20)); } catch (IOException e) { System.out.println("Couldnt open file!"); System.out.println(e.getLocalizedMessage()); } } 3) For sound files: import sun.audio.*; import java.io.*; public synchronized void play() { try { InputStream in = new FileInputStream(filename); AudioStream as = new AudioStream(in); AudioPlayer.player.start(as); } catch (IOException e) { e.printStackTrace(); } }

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