Search Results

Search found 1275 results on 51 pages for 'derived'.

Page 2/51 | < Previous Page | 1 2 3 4 5 6 7 8 9 10 11 12  | Next Page >

  • Operator== in derived class never gets called.

    - by Robin Welch
    Can someone please put me out of my misery with this? I'm trying to figure out why a derived operator== never gets called in a loop. To simplify the example, here's my Base and Derived class: class Base { // ... snipped bool operator==( const Base& other ) const { return name_ == other.name_; } }; class Derived : public Base { // ... snipped bool operator==( const Derived& other ) const { return ( static_cast<const Base&>( *this ) == static_cast<const Base&>( other ) ? age_ == other.age_ : false ); }; Now when I instantiate and compare like this ... Derived p1("Sarah", 42); Derived p2("Sarah", 42); bool z = ( p1 == p2 ); ... all is fine. Here the operator== from Derived gets called, but when I loop over a list, comparing items in a list of pointers to Base objects ... list<Base*> coll; coll.push_back( new Base("fred") ); coll.push_back( new Derived("sarah", 42) ); // ... snipped // Get two items from the list. Base& obj1 = **itr; Base& obj2 = **itr2; cout << obj1.asString() << " " << ( ( obj1 == obj2 ) ? "==" : "!=" ) << " " << obj2.asString() << endl; Here asString() (which is virtual and not shown here for brevity) works fine, but obj1 == obj2 always calls the Base operator== even if the two objects are Derived. I know I'm going to kick myself when I find out what's wrong, but if someone could let me down gently it would be much appreciated.

    Read the article

  • Python metaclass to run a class method automatically on derived class

    - by Barry Steyn
    I want to automatically run a class method defined in a base class on any derived class during the creation of the class. For instance: class Base(object): @classmethod def runme(): print "I am being run" def __metclass__(cls,parents,attributes): clsObj = type(cls,parents,attributes) clsObj.runme() return clsObj class Derived(Base): pass: What happens here is that when Base is created, ''runme()'' will fire. But nothing happens when Derived is created. The question is: How can I make ''runme()'' also fire when creating Derived. This is what I have thought so far: If I explicitly set Derived's metclass to Base's, it will work. But I don't want that to happen. I basically want Derived to use the Base's metaclass without me having to explicitly set it so.

    Read the article

  • private virtual function in derived class

    - by user1706047
    class base { public: virtual void doSomething() = 0; }; class derived : public base { **private:** virtual void doSomething(){cout<<"Derived fn"<<endl;} }; now if i do the following: base *b=new child; b->doSomething(); //it calls the derived class fn even if that is private. Question: 1.its able to call the derived class fn even if that is private.How is it possible? Now if i change the inheritance access specifier from public to protected/private then i get compilation error as "'type cast' : conversion from 'Derived *' to 'base *' exists, but is inaccessible" Notes: I am aware on the concepts of the inheritance access specifiers.So in second case as its derived private/protected, its inaccessible. But here it confuses me for the first question. Any input will be highly appreciated

    Read the article

  • Calling base class constructor

    - by The Void
    In the program below, is the line Derived(double y): Base(), y_(y) correct/allowed? That is, does it follow ANSI rules? #include <iostream> class Base { public: Base(): x_(0) { std::cout << "Base default constructor called" << std::endl; } Base(int x): x_(x) { std::cout << "Base constructor called with x = " << x << std::endl; } void display() const { std::cout << x_ << std::endl; } protected: int x_; }; class Derived: public Base { public: Derived(): Base(1), y_(1.2) { std::cout << "Derived default constructor called" << std::endl; } Derived(double y): Base(), y_(y) { std::cout << "Derived constructor called with y = " << y << std::endl; } void display() const { std::cout << Base::x_ << ", " << y_ << std::endl; } private: double y_; }; int main() { Base b1; b1.display(); Derived d1; d1.display(); std::cout << std::endl; Base b2(-9); b2.display(); Derived d2(-8.7); d2.display(); return 0; }

    Read the article

  • GPL: does one line of GPLed code make program a "derived work"

    - by SigTerm
    I've recently run into some argument with a person that claims to be a lawyer (I have my suspicions about this not being completely true, though). As far as I know, copying even one line of code from GPLed program into proprietary body of code requires you to release the whole thing under GPL, if you ever decide to publish the software and make it available to the public. The person in question claims that it is "absurd" (I know it is, but AFAIK that's how GPL works), it is "redefining the copyright", "GPL has no power to do that", and claiming that "one line of GPLed code makes you release the whole thing under GPL" is absurd. That contradicts the GPL FAQ. Can somebody clarify the situation? Am I right in assumption that copying even smallest subroutine from GPL program into your code automatically makes your program a "derived work" which means you are obliged to release it under GPL license if you publish it?

    Read the article

  • Idiomatic Scala way to deal with base vs derived class field names?

    - by Gregor Scheidt
    Consider the following base and derived classes in Scala: abstract class Base( val x : String ) final class Derived( x : String ) extends Base( "Base's " + x ) { override def toString = x } Here, the identifier 'x' of the Derived class parameter overrides the field of the Base class, so invoking toString like this: println( new Derived( "string" ).toString ) returns the Derived value and gives the result "string". So a reference to the 'x' parameter prompts the compiler to automatically generate a field on Derived, which is served up in the call to toString. This is very convenient usually, but leads to a replication of the field (I'm now storing the field on both Base and Derived), which may be undesirable. To avoid this replication, I can rename the Derived class parameter from 'x' to something else, like '_x': abstract class Base( val x : String ) final class Derived( _x : String ) extends Base( "Base's " + _x ) { override def toString = x } Now a call to toString returns "Base's string", which is what I want. Unfortunately, the code now looks somewhat ugly, and using named parameters to initialize the class also becomes less elegant: new Derived( _x = "string" ) There is also a risk of forgetting to give the derived classes' initialization parameters different names and inadvertently referring to the wrong field (undesirable since the Base class might actually hold a different value). Is there a better way? Edit: To clarify, I really only want the Base values; the Derived ones just seem necessary for initializing the Base ones. The example only references them to illustrate the ensuing issues. It might be nice to have a way to suppress automatic field generation if the derived class would otherwise end up hiding a base class field.

    Read the article

  • How to make a derived UITableVIew work

    - by justinhj
    I've made a new class in my Xcode project which is derived from UITableView I then drag a UITableView from in the interface builder onto my view and change the class of the object to my derived class. Then I drag the outlet from the table to the files owner and hook it up to an outlet variable in my main view, which is of the same type as my derived class. How do I also set up the datasource and delegate so that they belong to the derived class?

    Read the article

  • Can operator<< in derived class call another operator<< in base class in c++?

    - by ivory
    In my code, Manager is derived from Employee and each of them have an operator<< override. class Employee{ protected: int salary; int rank; public: int getSalary()const{return salary;} int getRank()const{return rank;} Employee(int s, int r):salary(s), rank(r){}; }; ostream& operator<< (ostream& out, Employee& e){ out << "Salary: " << e.getSalary() << " Rank: " << e.getRank() << endl; return out; } class Manager: public Employee{ public: Manager(int s, int r): Employee(s, r){}; }; ostream& operator<< (ostream& out, Manager& m){ out << "Manager: "; cout << (Employee)m << endl; //can not compile, how to call function of Employee? return out; } I hoped cout << (Employee)m << endl; would call ostream& operator<< (ostream& out, Employee& e), but it failed.

    Read the article

  • How does versioning work when using Boost Serialization for Derived Classes?

    - by Venkata Adusumilli
    When a Client serializes the following data: InternationalStudent student; student.id("Client ID"); student.firstName("Client First Name"); student.country("Client Country"); the Server receives the following: ID = "Client ID" Country = "Client First Name" instead of the following: ID = "Client ID" Country = "Client Country" The only difference between the Server and Client classes is the First Name of the Student. How can we make the Server ignore First Name recieved from the Client and process the Country? Server Side Classes class Student { public: Student(){} virtual ~Student(){} public: std::string id() { return idM; } void id(std::string id) { idM = id; } protected: friend class boost::serialization::access; protected: std::string idM; protected: template<class A> void serialize(A& archive, const unsigned int /*version*/) { archive & BOOST_SERIALIZATION_NVP(idM); } }; class InternationalStudent : public Student { public: InternationalStudent() {} ~InternationalStudent() {} public: std::string country() { return countryM; } void country(std::string country) { countryM = country; } protected: friend class boost::serialization::access; protected: std::string countryM; protected: template<class A> void serialize(A& archive, const unsigned int /*version*/) { archive & BOOST_SERIALIZATION_NVP(boost::serialization::base_object<Student>(*this)); archive & BOOST_SERIALIZATION_NVP(countryM); } }; Client Side Classes class Student { public: Student(){} virtual ~Student(){} public: std::string id() { return idM; } void id(std::string id) { idM = id; } std::string firstName() { return firstNameM; } void firstName(std::string name) { firstNameM = name; } protected: friend class boost::serialization::access; protected: std::string idM; std::string firstNameM; protected: template<class A> void serialize(A& archive, const unsigned int /*version*/) { archive & BOOST_SERIALIZATION_NVP(idM); if (version >=1) { archive & BOOST_SERIALIZATION_NVP(firstNameM); } } }; BOOST_CLASS_VERSION(Student, 1) class InternationalStudent : public Student { public: InternationalStudent() {} ~InternationalStudent() {} public: std::string country() { return countryM; } void country(std::string country) { countryM = country; } protected: friend class boost::serialization::access; protected: std::string countryM; protected: template<class A> void serialize(A& archive, const unsigned int /*version*/) { archive & BOOST_SERIALIZATION_NVP(boost::serialization::base_object<Student>(*this)); archive & BOOST_SERIALIZATION_NVP(countryM); } };

    Read the article

  • Proper attribution of derived work in a GPL project

    - by Anton Gogolev
    This is a continuation of me rewriting GPL project. What will be the correct way of attributing my project as being a derivative of some other GPL-licensed project? So far I came up with: HgSharp Original Copyright Matt Mackall <[email protected]> and contributors. The following code is a derivative work of the code from the Mercurial project, which is licensed GPLv2. This code therefore is also licensed under the terms of the GNU Public License, verison 2. For information on the license of this code when distributed with and used in conjunction with the other modules in the HgSharp project, please see the root-level COPYING file. Copyright 2011-2012 Anton Gogolev <[email protected]>

    Read the article

  • WPF custom control derived from ComboBox that shows a Data

    Create a custom WPF control that derives from ComboBox and create a property where its value will be used as the content of the dropdown  read moreBy Michael DetrasDid you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

    Read the article

  • c++ How to use angular velocity that derived from inertia and force(torque) in 3d

    - by user1217203
    I am relatively new to game development. May my terminology and description are not appropriate. Please excuse my poor phrasing and help me by giving advice on how to question better if this question seems less fitting. I really appreciate your efforts. Hi. I am having hard time interpreting the set of values I have. I have inertia and force(torque) in terms of x y z. FYI I used x and y coordinates as my ground, flat coordinates and z as my up/down. I am assuming that since f = ma, that angular acceleration must be a = f / m. So I divide my torque by inertia. Then I add those x y z values to my angular velocity variable's x y z. However these x y z values confuse me. Don't I need angle/sec or radian/sec sort of values in order to apply rotation? The x y z values I have seemed to not say anything about radians or angular movement. Question : If I have ( 1, 2, 3 ) or any ( x, y, z ) as my angular velocity, how do I actually apply it as angular movement? FYI Here I am pasting my code : float mass = 100; float devidedMass = 1.0/12 * mass; Vec3 innertia( devidedMass* (_box._size.z*_box._size.z + _box._size.x*_box._size.x), devidedMass* (_box._size.y*_box._size.y + _box._size.x*_box._size.x), devidedMass* (_box._size.y*_box._size.y + _box._size.z*_box._size.z )); box._angAccel += forceAng/innertia; box._angVelo += box._angAccel; box._angAccel.allZero(); source of my inertia calculation http://www.health.uottawa.ca/biomech/courses/apa4311/solids.pdf

    Read the article

  • Automatic generate code: "derived work"?

    - by Peregring-lk
    For example, I've GPL software. I'm the author of this GPL software. This GPL software has, between its code, Doxygen comments. These Doxygen comments are written to generate a CC-BY-SA html page, in order to upload this generated documentation in my project website under CC-BY-SA license. But, the Doxygen documentation output is a "derivate work"? After all, this documentation is based on my GPL source code. In this case, the documentation must be GPL. But, I want the documentation is CC-BY-SA, because it is documentation. GFDL doesn't help. GPL code can't become GFDL (the opposite yes). If this output is really a derivate work, I think, creates a strange situation, because, if I distribute my work, the recipient users can't legally distribute the generated documentation: while with my work I can do I want, the users don't, thus, they have to distribute any derivated work with the same license I offer them. What is the solution?

    Read the article

  • Quantifying the Value Derived from Your PeopleSoft Implementation

    - by Mark Rosenberg
    As product strategists, we often receive the question, "What's the value of implementing your PeopleSoft software?" Prospective customers and existing customers alike are compelled to justify the cost of new tools, business process changes, and the business impact associated with adopting the new tools. In response to this question, we have been working with many of our customers and implementation partners during the past year to obtain metrics that demonstrate the value obtained from an investment in PeopleSoft applications. The great news is that as a result of our quest to identify value achieved, many of our customers began to monitor their businesses differently and more aggressively than in the past, and a number of them informed us that they have some great achievements to share. For this month, I'll start by pointing out that we have collaborated with one of our implementation partners, Huron Consulting Group, Inc., to articulate the levers for extracting value from implementing the PeopleSoft Grants solution. Typically, education and research institutions, healthcare organizations, and non-profit organizations are the types of enterprises that seek to facilitate and automate research administration business processes with the PeopleSoft Grants solution. If you are interested in understanding the ways in which you can look for value from an implementation, please consider registering for the webcast scheduled for Friday, December 14th at 1pm Central Time in which you'll get to see and hear from our team, Huron Consulting, and one of our leading customers. In the months ahead, we'll plan to post more information about the value customers have measured and reported to us from their implementations and upgrades. If you have a great story about return on investment and want to share it, please contact either [email protected]  or [email protected]. We'd love to hear from you.

    Read the article

  • Scope of Derived Tables in SQL Server

    - by FailBoy
    I've been looking into SQL recently and exploring a bit. in regards to Temp Tables I have discovered 3 different temp table types: 1) CREATE TABLE #TempTable 2) DECLARE TABLE @TempTable 3) SELECT * FROM (SELECT * FROM Customers) AS TempTable Now I understand the scope behind the #TempTable and the @TempTable types, but what about the derived table as in example 3? Where does this derived table get stored? and if it is declared in 1 transaction, can a 2nd transaction access it, or is the scoping of Derived Tables that same as example 1 and 2?

    Read the article

  • Friendness and derived class

    - by ereOn
    Hi, Let's say I have the following class hierarchy: class Base { protected: virtual void foo() = 0; friend class Other; }; class Derived : public Base { protected: void foo() { /* Some implementation */ }; }; class Other { public: void bar() { Derived* a = new Derived(); a->foo(); // Compiler error: foo() is protected within this context }; }; I guess I could change it too a->Base::foo() but since foo() is pure virtual in the Base class, the call will result in calling Derived::foo() anyway. However, the compiler seems to refuse a->foo(). I guess it is logical, but I can't really understand why. Am I missing something ? Can't (shouldn't) it handle this special case ? Thank you.

    Read the article

  • Convert/Cast base type to Derived type

    - by user102533
    I am extending the existing .NET framework class by deriving it. How do I convert an object of base type to derived type? public class Results { //Framework methods } public class MyResults : Results { //Nothing here } //I call the framework method public static MyResults GetResults() { Results results = new Results(); //Results results = new MyResults(); //tried this as well. results = CallFrameworkMethod(); return (MyResults)results; //Throws runtime exception } I understand that this happens as I am trying to cast a base type to a derived type and if derived type has additional properties, then the memory is not allocated. When I do add the additional properties, I don't care if they are initialized to null. How do I do this without doing a manual copy?

    Read the article

  • How to use derived class shared variables in shared methods of base class

    - by KoolKabin
    Hi guys, I am trying to add shared members in derived classes and use that values in base classes... I have base class DBLayer public shared function GetDetail(byval UIN as integer) dim StrSql = string.format("select * from {0} where uin = {1}", tablename, uin) .... end function end class my derived class class User inherits dblayer public shared tabledname as string = "users" end class class item inherits dblayer public shared tabledname as string = "item" end class class category inherits dblayer public shared tabledname as string = "category" end class currently there is error using the tablename variable of derived class in base class but i want to use it... coz i dun know other techniques... if other solutions are better then u can post it or u can say how can i make it work? confused...

    Read the article

  • WPF style problem with custom control and textbox-derived class

    - by Martin
    I had the following situation: main application has app.xaml, which sets the style for TextBox controls a custom control is implemented in a separate DLL, and uses several TextBox controls The main application's TextBox style is applied to the custom control's TextBox controls. Cool! My problem comes in because I need to use a class derived from TextBox in the custom control. Now the main app's TextBox style is no longer applied. Can the custom control DLL have something like "app.xaml" where I can set the style for all my derived TextBox controls? Or can the main application somehow set the style for all TextBox-derived classes? Thanks!

    Read the article

  • insert,update, delete derived entity in entity framework 4.0

    - by user282807
    Hi! How do i insert an entity that is derived from another entity. here is my code but it's not working:(applicationreplacement derived from application Blockquote ObjectContect _ctx public void AddReplacementApp(Application entity,ApplicationReplacement rentity) { _ctx.CreateObjectSet<Application>(rentity); _ctx.SaveChanges(); } Blockquote

    Read the article

  • Why is casting Derived** to Base*const* forbidden ?

    - by smerlin
    After reading this question, i saw the answer by Naveen containing a link to this page, which basically says, that casting from Derived** to Base** is forbidden since could change a pointer to an pointer to a Derived1 object point to a pointer to a Derived2 object (like: *derived1PtrPtr=derived2Ptr). OK, i understand this is evil ... But when casting Derived** to Base*const* this is not even possible, so whats the reason that this is not allowed anyway ?

    Read the article

  • List of Lua derived VMs and Languages

    - by Shane Holloway
    Is there a compendium of virtual machines and languages derived or inspired by Lua? By derived, I mean usage beyond embedding and extending with modules. I'm wanting to research the Lua technology tree, and am looking for our combined knowledge of what already exists. Current List: Bright - A C-like Lua Derivative http://bluedino.net/luapix/Bright.pdf Agena - An Algol68/SQL like Lua Derivative http://agena.sourceforge.net/ LuaJIT - A (very impressive) JIT for Lua http://luajit.org MetaLua - An ML-style language extension http://metalua.luaforge.net/

    Read the article

  • Binding functions of derived class with luabind

    - by Anamon
    I am currently developing a plugin-based system in C++ which provides a Lua scripting interface, for which I chose to use luabind. I'm using Lua 5 and luabind 0.9, both statically linked and compiled with MSVC++ 8. I am now having trouble binding functions with luabind when they are defined in a derived class, but not its parent class. More specifically, I have an abstract base class called 'IPlugin' from which all plugin classes inherit. When the plugin manager initialises, it registers that class and its functions like this: luabind::open(L); luabind::module(L) [ luabind::class_("IPlugin") .def("start", (void(IPlugin::*)())&IPlugin::start) ]; As it is only known at runtime what effective plugin classes are available, I had to solve loading plugins in a kind of roundabout way. The plugin manager exposes a factory function to Lua, which takes the name of a plugin class and a desired object name. The factory then creates the object, registers the plugin's class as inheriting from the 'IPlugin' base class, and immediately calls a function on the created object that registers itself as a global with the Lua state, like this: void PluginExample::registerLuaObject(lua_State *L, string a_name) { luabind::globals(L)[a_name] = (PluginExample*)this; } I initially did this because I had problems with Lua determining the most derived class of the object, as if I register it from the StreamManager it is only known as a subtype of 'IPlugin' and not the specific subtype. I'm not sure anymore if this is even necessary though, but it works and the created object is subsequently accessible from Lua under 'a_name'. The problem I have, though, is that functions defined in the derived class, which were not declared at all in the parent class, cannot be used. Virtual functions defined in the base class, such as 'start' above, work fine, and calling them from Lua on the new object runs the respective redefined code from the 'PluginExample' class. But if I add a new function to 'PluginExample', here for example a function taking no arguments and returning void, and register it like this: luabind::module(L) [ luabind::class_("PluginExample") .def(luabind::constructor()) .def("func", &PluginExample::func) ]; calling 'func' on the new object yields the following Lua runtime error: No matching overload found, candidates: void func(PluginExample&) I am correctly using the ':' syntax so the 'self' argument is not needed and it seems suddenly Lua cannot determine the derived type of the object anymore. I am sure I am doing something wrong, probably having to do with the two-step binding required by my system architecture, but I can't figure out where. I'd much appreciate some help =)

    Read the article

  • Is derived table executed once or three times?

    - by AspOnMyNet
    Every time you make use of a derived table, that query is going to be executed. When using a CTE, that result set is pulled back once and only once within a single query. Does the quote suggest that the following query will cause derived table to be executed three times ( once for each aggregate function’s call ): SELECT AVG(OrdersPlaced),MAX(OrdersPlaced),MIN(OrdersPlaced) FROM ( SELECT v.VendorID, v.[Name] AS VendorName, COUNT(*) AS OrdersPlaced FROM Purchasing.PurchaseOrderHeader AS poh INNER JOIN Purchasing.Vendor AS v ON poh.VendorID = v.VendorID GROUP BY v.VendorID, v.[Name] ) AS x thanx

    Read the article

< Previous Page | 1 2 3 4 5 6 7 8 9 10 11 12  | Next Page >