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  • Behavior tree implementation details

    - by angryInsomniac
    I have been looking around for implementation details of behavior trees, the best descriptions I found were by Alex Champarand and some of Damian Isla's talk about AI in Halo 2 (the video of which is locked up in the GDC vault sadly). However, both descriptions fall short of helping one actually create a BT, one particular question has been bugging me for a while. When is the tree in a behavior tree evaluated? Furthermore: If the tree is in the middle of executing a sequence of actions (patrolling waypoints) and a higher priority impulse comes in (distraction sound) , how to switch to that side of the tree seamlessly without resorting to a state machine like system and if it is decided that the impulse was irrelevant (the distraction is too far away to affect this guard), how to go back to the last thing that the guard was doing ? I have quite a few questions like this and I don't wish to flood the board with separate queries so if you know of any resource where questions like these can be answered I would be very grateful.

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  • How-to delete a tree node using the context menu

    - by frank.nimphius
    Hierarchical trees in Oracle ADF make use of View Accessors, which means that only the top level node needs to be exposed as a View Object instance on the ADF Business Components Data Model. This also means that only the top level node has a representation in the PageDef file as a tree binding and iterator binding reference. Detail nodes are accessed through tree rule definitions that use the accessor mentioned above (or nested collections in the case of POJO or EJB business services). The tree component is configured for single node selection, which however can be declaratively changed for users to press the ctrl key and selecting multiple nodes. In the following, I explain how to create a context menu on the tree for users to delete the selected tree nodes. For this, the context menu item will access a managed bean, which then determines the selected node(s), the internal ADF node bindings and the rows they represent. As mentioned, the ADF Business Components Data Model only needs to expose the top level node data sources, which in this example is an instance of the Locations View Object. For the tree to work, you need to have associations defined between entities, which usually is done for you by Oracle JDeveloper if the database tables have foreign keys defined Note: As a general hint of best practices and to simplify your life: Make sure your database schema is well defined and designed before starting your development project. Don't treat the database as something organic that grows and changes with the requirements as you proceed in your project. Business service refactoring in response to database changes is possible, but should be treated as an exception, not the rule. Good database design is a necessity – even for application developers – and nothing evil. To create the tree component, expand the Data Controls panel and drag the View Object collection to the view. From the context menu, select the tree component entry and continue with defining the tree rules that make up the hierarchical structure. As you see, when pressing the green plus icon  in the Edit Tree Binding  dialog, the data structure, Locations -  Departments – Employees in my sample, shows without you having created a View Object instance for each of the nodes in the ADF Business Components Data Model. After you configured the tree structure in the Edit Tree Binding dialog, you press OK and the tree is created. Select the tree in the page editor and open the Structure Window (ctrl+shift+S). In the Structure window, expand the tree node to access the conextMenu facet. Use the right mouse button to insert a Popup  into the facet. Repeat the same steps to insert a Menu and a Menu Item into the Popup you created. The Menu item text should be changed to something meaningful like "Delete". Note that the custom menu item later is added to the context menu together with the default context menu options like expand and expand all. To define the action that is executed when the menu item is clicked on, you select the Action Listener property in the Property Inspector and click the arrow icon followed by the Edit menu option. Create or select a managed bean and define a method name for the action handler. Next, select the tree component and browse to its binding property in the Property Inspector. Again, use the arrow icon | Edit option to create a component binding in the same managed bean that has the action listener defined. The tree handle is used in the action listener code, which is shown below: public void onTreeNodeDelete(ActionEvent actionEvent) {   //access the tree from the JSF component reference created   //using the af:tree "binding" property. The "binding" property   //creates a pair of set/get methods to access the RichTree instance   RichTree tree = this.getTreeHandler();   //get the list of selected row keys   RowKeySet rks = tree.getSelectedRowKeys();   //access the iterator to loop over selected nodes   Iterator rksIterator = rks.iterator();          //The CollectionModel represents the tree model and is   //accessed from the tree "value" property   CollectionModel model = (CollectionModel) tree.getValue();   //The CollectionModel is a wrapper for the ADF tree binding   //class, which is JUCtrlHierBinding   JUCtrlHierBinding treeBinding =                  (JUCtrlHierBinding) model.getWrappedData();          //loop over the selected nodes and delete the rows they   //represent   while(rksIterator.hasNext()){     List nodeKey = (List) rksIterator.next();     //find the ADF node binding using the node key     JUCtrlHierNodeBinding node =                       treeBinding.findNodeByKeyPath(nodeKey);     //delete the row.     Row rw = node.getRow();       rw.remove();   }          //only refresh the tree if tree nodes have been selected   if(rks.size() > 0){     AdfFacesContext adfFacesContext =                          AdfFacesContext.getCurrentInstance();     adfFacesContext.addPartialTarget(tree);   } } Note: To enable multi node selection for a tree, select the tree and change the row selection setting from "single" to "multiple". Note: a fully pictured version of this post will become available at the end of the month in a PDF summary on ADF Code Corner : http://www.oracle.com/technetwork/developer-tools/adf/learnmore/index-101235.html 

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  • Testing home directory scripts by setting $HOME to the location of the test directory

    - by intuited
    I have an interdependent collection of scripts in my ~/bin directory as well as a developed ~/.vim directory and some other libraries and such in other subdirectories. I've been versioning all of this using git, and have realized that it would be potentially very easy and useful to do development and testing of new and existing scripts, vim plugins, etc. using a cloned repo, and then pull the working code into my actual home directory with a merge. The easiest way to do this would seem to be to just change & export $HOME, eg cd ~/testing; git clone ~ home export HOME=~/testing/home cd ~ screen -S testing-home # start vim, write/revise plugins, edit scripts, etc. # test revisions However since I've never tried this before I'm concerned that some programs, environment variables, etc., may end up using my actual home directory instead of the exported one. Is this a viable strategy? Are there just a few outliers that I should be careful about? Is there a much better way to do this sort of thing?

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  • Event Driven Behavior Tree: deterministic traversal order with parallel

    - by Heisenbug
    I've studied several articles and listen some talks about behavior trees (mostly the resources available on AIGameDev by Alex J. Champandard). I'm particularly interested on event driven behavior trees, but I have still some doubts on how to implement them correctly using a scheduler. Just a quick recap: Standard Behavior Tree Each execution tick the tree is traversed from the root in depth-first order The execution order is implicitly expressed by the tree structure. So in the case of behaviors parented to a parallel node, even if both children are executed during the same traversing, the first leaf is always evaluated first. Event Driven BT During the first traversal the nodes (tasks) are enqueued using a scheduler which is responsible for updating only running ones every update The first traversal implicitly produce a depth-first ordered queue in the scheduler Non leaf nodes stays suspended mostly of the time. When a leaf node terminate(either with success or fail status) the parent (observer) is waked up allowing the tree traversing to continue and new tasks will be enqueued in the scheduler Without parallel nodes in the tree there will be up to 1 task running in the scheduler Without parallel nodes, the tasks in the queue(excluding dynamic priority implementation) will be always ordered in a depth-first order (is this right?) Now, from what is my understanding of a possible implementation, there are 2 requirements I think must be respected(I'm not sure though): Now, some requirements I think needs to be guaranteed by a correct implementation are: The result of the traversing should be independent from which implementation strategy is used. The traversing result must be deterministic. I'm struggling trying to guarantee both in the case of parallel nodes. Here's an example: Parallel_1 -->Sequence_1 ---->leaf_A ---->leaf_B -->leaf_C Considering a FIFO policy of the scheduler, before leaf_A node terminates the tasks in the scheduler are: P1(suspended),S1(suspended),leaf_A(running),leaf_C(running) When leaf_A terminate leaf_B will be scheduled (at the end of the queue), so the queue will become: P1(suspended),S1(suspended),leaf_C(running),leaf_B(running) In this case leaf_B will be executed after leaf_C at every update, meanwhile with a non event-driven traversing from the root node, the leaf_B will always be evaluated before leaf_A. So I have a couple of question: do I have understand correctly how event driven BT work? How can I guarantee the depth first order is respected with such an implementation? is this a common issue or am I missing something?

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  • Demote 2003 DC from within Directory Services Restore Mode

    - by adam
    We've had a child DC fail on us, and can't get into Windows on it as Directory Services is failing. A restore of the backed-up active directory hasn't worked due to a corruption, and so we've decided to demote the child DC and - for now - run AD from the PDC only. However, dcpromo /demote doesn't work from Safe Mode or Directory Services Restore Mode. We don't want to do a complete reinstall, as we have Exchange running on the child DC. Anyone know how (if?) we can demote the DC within safe mode or otherwise get into windows? Thanks

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  • What is the kd tree intersection logic?

    - by bobobobo
    I'm trying to figure out how to implement a KD tree. On page 322 of "Real time collision detection" by Ericson The text section is included below in case Google book preview doesn't let you see it the time you click the link text section Relevant section: The basic idea behind intersecting a ray or directed line segment with a k-d tree is straightforward. The line is intersected against the node's splitting plane, and the t value of intersection is computed. If t is within the interval of the line, 0 <= t <= tmax, the line straddles the plane and both children of the tree are recursively descended. If not, only the side containing the segment origin is recursively visited. So here's what I have: (open image in new tab if you can't see the lettering) The logical tree Here the orange ray is going thru the 3d scene. The x's represent intersection with a plane. From the LEFT, the ray hits: The front face of the scene's enclosing cube, The (1) splitting plane The (2.2) splitting plane The right side of the scene's enclosing cube But here's what would happen, naively following Ericson's basic description above: Test against splitting plane (1). Ray hits splitting plane (1), so left and right children of splitting plane (1) are included in next test. Test against splitting plane (2.1). Ray actually hits that plane, (way off to the right) so both children are included in next level of tests. (This is counter-intuitive - shouldn't only the bottom node be included in subsequent tests) Can some one describe what happens when the orange ray goes through the scene correctly?

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  • Algorithm for parsing a flat tree into a non-flat tree

    - by Chad Johnson
    I have the following flat tree: id name parent_id is_directory =========================================================== 50 app 0 1 31 controllers 50 1 11 application_controller.rb 31 0 46 models 50 1 12 test_controller.rb 31 0 31 test.rb 46 0 and I am trying to figure out an algorithm for getting this into the following tree structuree: [{ id: 50, name: app, is_directory: true children: [{ id: 31, name: controllers, is_directory: true, children: [{ id: 11, name: application_controller.rb is_directory: false },{ id: 12, name: test_controller.rb, is_directory: false }], },{ id: 46, name: models, is_directory: true, children: [{ id: 31, name: test.rb, is_directory: false }] }] }] Can someone point me in the right direction? I'm looking for steps (eg. build an associative array; loop through the array looking for x; etc.).

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  • How to explore the local active directory ?

    - by Quandary
    Question: On Windows7, how can I explore the local active directory ? I mean getting all directory entries I would see when I execute this code: Dim AD As New System.DirectoryServices.DirectoryEntry("WinNT://" + Environment.MachineName & ",computer") I have found a systernals tool, called activedirectory explorer, (http://technet.microsoft.com/en-us/sysinternals/bb963907.aspx) and I run it as complete administrator (root), but it always says "server not working/running". But the server obviously works, since I can query it from .net... and it's definitely local, since I plugged the network connection

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  • Implementation of Race Game Tree

    - by Mert Toka
    I build a racing game right in OpenGL using Glut, and I'm a bit lost in all the details. First of all, any suggestions as a road map would be more than great. So far what I thought is this: Tree implementation for transformations. Simulated dynamics.(*) Octree implementation for collusion detection. Actual collusion detection.(*) Modelling in Maya and export them as .OBJs. Polishing the game with GLSL or something like that for graphics quality. (*): I am not sure the order of these two. So I started with the simulated dynamics without tree, and it turned out to be a huge chaos for me. Is there any way you can think of such that could help me to build such tree to use in racing game? I thought something like this but I have no idea how to implement it. Reds are static, yellows are dynamic nodes

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  • Programmatically disclosing a node in af:tree and af:treeTable

    - by Frank Nimphius
    A common developer requirement when working with af:tree or af:treeTable components is to programmatically disclose (expand) a specific node in the tree. If the node to disclose is not a top level node, like a location in a LocationsView -> DepartmentsView -> EmployeesView hierarchy, you need to also disclose the node's parent node hierarchy for application users to see the fully expanded tree node structure. Working on ADF Code Corner sample #101, I wrote the following code lines that show a generic option for disclosing a tree node starting from a handle to the node to disclose. The use case in ADF Coder Corner sample #101 is a drag and drop operation from a table component to a tree to relocate employees to a new department. The tree node that receives the drop is a department node contained in a location. In theory the location could be part of a country and so on to indicate the depth the tree may have. Based on this structure, the code below provides a generic solution to parse the current node parent nodes and its child nodes. The drop event provided a rowKey for the tree node that received the drop. Like in af:table, the tree row key is not of type oracle.jbo.domain.Key but an implementation of java.util.List that contains the row keys. The JUCtrlHierBinding class in the ADF Binding layer that represents the ADF tree binding at runtime provides a method named findNodeByKeyPath that allows you to get a handle to the JUCtrlHierNodeBinding instance that represents a tree node in the binding layer. CollectionModel model = (CollectionModel) your_af_tree_reference.getValue(); JUCtrlHierBinding treeBinding = (JUCtrlHierBinding ) model.getWrappedData(); JUCtrlHierNodeBinding treeDropNode = treeBinding.findNodeByKeyPath(dropRowKey); To disclose the tree node, you need to create a RowKeySet, which you do using the RowKeySetImpl class. Because the RowKeySet replaces any existing row key set in the tree, all other nodes are automatically closed. RowKeySetImpl rksImpl = new RowKeySetImpl(); //the first key to add is the node that received the drop //operation (departments).            rksImpl.add(dropRowKey);    Similar, from the tree binding, the root node can be obtained. The root node is the end of all parent node iteration and therefore important. JUCtrlHierNodeBinding rootNode = treeBinding.getRootNodeBinding(); The following code obtains a reference to the hierarchy of parent nodes until the root node is found. JUCtrlHierNodeBinding dropNodeParent = treeDropNode.getParent(); //walk up the tree to expand all parent nodes while(dropNodeParent != null && dropNodeParent != rootNode){    //add the node's keyPath (remember its a List) to the row key set    rksImpl.add(dropNodeParent.getKeyPath());      dropNodeParent = dropNodeParent.getParent(); } Next, you disclose the drop node immediate child nodes as otherwise all you see is the department node. Its not quite exactly "dinner for one", but the procedure is very similar to the one handling the parent node keys ArrayList<JUCtrlHierNodeBinding> childList = (ArrayList<JUCtrlHierNodeBinding>) treeDropNode.getChildren();                     for(JUCtrlHierNodeBinding nb : childList){   rksImpl.add(nb.getKeyPath()); } Next, the row key set is defined as the disclosed row keys on the tree so when you refresh (PPR) the tree, the new disclosed state shows tree.setDisclosedRowKeys(rksImpl); AdfFacesContext.getCurrentInstance().addPartialTarget(tree.getParent()); The refresh in my use case is on the tree parent component (a layout container), which usually shows the best effect for refreshing the tree component. 

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  • Determine which active directory object is referred to by GUID in a Directory Synchronization Error Report

    - by Michael Shimmins
    We have active directory syncronization setup between our on-premises AD server and Microsoft hosted Exchange (business productivity online services). I've started getting a daily error report, which details an error for a specific AD user, however it references it by GUID. I can't find any info on how to translate that object guid into something meaningful so I can find and fix the problem. The error is reported as: Error 005: Unable to set the alias for this object in Microsoft Online Services because either the primary SMTP address, the e-mail nickname, or the SAM account name in the local Active Directory contains an invalid character. in reference to the Object GUID: CN={8443cbb4-5199-49f0-9529-ce965430dca6} How can I translate that object guid into a friendly object name?

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  • Find the minimum gap between two numbers in an AVL tree

    - by user1656647
    I have a data structures homework, that in addition to the regular AVL tree functions, I have to add a function that returns the minimum gap between any two numbers in the AVL tree (the nodes in the AVL actually represent numbers.) Lets say we have the numbers (as nodes) 1 5 12 20 23 21 in the AVL tree, the function should return the minimum gap between any two numbers. In this situation it should return "1" which is |20-21| or |21-20|. It should be done in O(1). Tried to think alot about it, and I know there is a trick but just couldn't find it, I have spent hours on this. There was another task which is to find the maximum gap, which is easy, it is the difference between the minimal and maximal number.

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  • Can a binary tree or tree be always represented in a Database as 1 table and self-referencing?

    - by Jian Lin
    I didn't feel this rule before, but it seems that a binary tree or any tree (each node can have many children but children cannot point back to any parent), then this data structure can be represented as 1 table in a database, with each row having an ID for itself and a parentID that points back to the parent node. That is in fact the classical Employee - Manager diagram: one boss can have many people under him... and each person can have n people under him, etc. This is a tree structure and is represented in database books as a common example as a single table Employee.

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  • Can a binary tree or tree be always represented in a Database table as 1 table and self-referencing?

    - by Jian Lin
    I didn't feel this rule before, but it seems that a binary tree or any tree (each node can have many children but children cannot point back to any parent), then this data structure can be represented as 1 table in a database, with each row having an ID for itself and a parentID that points back to the parent node. That is in fact the classical Employee - Manager diagram: one boss can have many people under him... and each person under him can have n people under him, etc. This is a tree structure and is represented in database books as a common example as a single table Employee.

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  • Inorder tree traversal in binary tree in C

    - by srk
    In the below code, I'am creating a binary tree using insert function and trying to display the inserted elements using inorder function which follows the logic of In-order traversal.When I run it, numbers are getting inserted but when I try the inorder function( input 3), the program continues for next input without displaying anything. I guess there might be a logical error.Please help me clear it. Thanks in advance... #include<stdio.h> #include<stdlib.h> int i; typedef struct ll { int data; struct ll *left; struct ll *right; } node; node *root1=NULL; // the root node void insert(node *root,int n) { if(root==NULL) //for the first(root) node { root=(node *)malloc(sizeof(node)); root->data=n; root->right=NULL; root->left=NULL; } else { if(n<(root->data)) { root->left=(node *)malloc(sizeof(node)); insert(root->left,n); } else if(n>(root->data)) { root->right=(node *)malloc(sizeof(node)); insert(root->right,n); } else { root->data=n; } } } void inorder(node *root) { if(root!=NULL) { inorder(root->left); printf("%d ",root->data); inorder(root->right); } } main() { int n,choice=1; while(choice!=0) { printf("Enter choice--- 1 for insert, 3 for inorder and 0 for exit\n"); scanf("%d",&choice); switch(choice) { case 1: printf("Enter number to be inserted\n"); scanf("%d",&n); insert(root1,n); break; case 3: inorder(root1); break; default: break; } } }

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  • AVL tree in C language

    - by I_S_W
    Hey all; i am currently doing a project that requires the use of AVL trees , the insert function i wrote for the avl does not seem to be working , it works for 3 or 4 nodes at maximum ; i would really appreciate your help The attempt is below enter code here Tree insert(Tree t,char name[80],int num) { if(t==NULL) { t=(Tree)malloc(sizeof(struct node)); if(t!=NULL) { strcpy(t->name,name); t->num=num; t->left=NULL; t->right=NULL; t->height=0; } } else if(strcmp(name,t->name)<0) { t->left=insert(t->left,name,num); if((height(t->left)-height(t->right))==2) if(strcmp(name,t->left->name)<0) { t=s_rotate_left(t);} else{ t=d_rotate_left(t);} } else if(strcmp(name,t-name)0) { t-right=insert(t-right,name,num); if((height(t-right)-height(t-left))==2) if(strcmp(name,t-right-name)0){ t=s_rotate_right(t); } else{ t=d_rotate_right(t);} } t-height=max(height(t-left),height(t-right))+1; return t; }

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  • directory services group query changing randomly

    - by yamspog
    I am receiving an unusual behaviour in my asp.net application. I have code that uses Directory Services to find the AD groups for a given, authenticated user. The code goes something like ... string username = "user"; string domain = "LDAP://DC=domain,DC=com"; DirectorySearcher search = new DirectorySearcher(domain); search.Filter = "(SAMAccountName=" + username + ")"; And then I query and get the list of groups for the given user. The problem is that the code was receiving the list of groups as a list of strings. With our latest release of the software, we are starting to receive the list of groups as a byte[]. The system will return string, suddenly return byte[] and then with a reboot it returns string again. Anyone have any ideas? code sample: DirectoryEntry dirEntry = new DirectoryEntry("LDAP://" + ldapSearchBase); DirectorySearcher userSearcher = new DirectorySearcher(dirEntry) { SearchScope = SearchScope.Subtree, CacheResults = false, Filter = ("(" + txtLdapSearchNameFilter.Text + "=" + userName + ")") }; userResult = userSearcher.FindOne(); ResultPropertyValueCollection valCol = userResult.Properties["memberOf"]; foreach (object val in valCol) { if (val is string) { distName = val.ToString(); } else { distName = enc.GetString((Byte[])val); } }

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  • Active Directory - Lightweight Directory Services and Domain Password Policy

    - by Craig Beuker
    Greetings all, We have an active directory domain which enforces a strict password policy. Hooray! Now, for the project we are working on, we are going to be storing users of our website Microsoft's AD-LDS service as well as using that for authentication of our web users. By default, it is my understanding that AD-LDS inherits its password policy from the domain of the machine it's installed on. Is there any way to break that link such that we can define a lighter password policy (or none if we so choose) for users in AD-LDS without affecting our domain? Note: AD-LDS is going to be hosted on a machine which is part of the domain. Thanks in advance.

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  • New to AVL tree implementation.

    - by nn
    I am writing a sliding window compression algorithm (LZ77) that searches for phrases in a "moving" dictionary. So far I have written a BST where each node is stored in an array and it's index in the array is also the value of the starting position in the window itself. I am now looking at transforming the BST to an AVL tree. I am a little confused at the sample implementations I have seen. Some only appear to store the balance factors whereas others store the height of each tree. Are there any performance advantage/disadvantages of storing the height and/or balance factor for each node? Apologies if this is a very simple question, but I'm still not visualizing how I want to restructure my BST to implement height balancing. Thanks.

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  • Apache2's recursive directory permission requirement

    - by Sn3akyP3t3
    The experience I've had thus far is from Ubuntu 10.04 and 12.04 64 bit OS so if there are other OS differences I'd like to know if this is an OS specific problem or not. The issue I've experienced is mostly confusion. Once the cause of the problem is identified and corrected there are no further related problems experienced. The symptom is Error 403 forbidden. Typically the cause is attempting to use a directory other than /var/www/ for content. The cause is simply permissions, but its puzzling why the required permissions must persist from at least one level deeper than root onward till the current working directory where the content is stored. For example: Alias /example/ "/home/user/permissions/can/be/confusing/with/apache/" <Directory /home/user/permissions/can/be/confusing/with/apache/> Options FollowSymLinks MultiViews AllowOverride None Order allow,deny Allow from all </Directory> With www-data being the user that spawned apache and "user" being a member of the www-data group. Thus, if ownership of /home/user/* is user:user then all that is necessary to display content with apache is permssions of read and execute. So d---r-x--- should suffice, but for practical purposes I'm using drwxr-x--- for most. However, if all directories /home/user/* are permissions of drwxr-x-- and /home/user/ itself has permissions of drwx------ then content will always fail with error 403. This is strange because it doesn't follow what I would consider traditional logic of permissions which should only be applicable to the current working directory or a particular file in that directory and not any directory further back in the chain. Is this by design or is it a bug?

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  • Minidlna Directory Issues

    - by Somnambulist
    I've done my searching and can't find an answer to THIS specific issue. I have my minidlna set up and running - but it's not really done properly. First off, when I open the server on my bluray player, all of my movies are listed twice - when they are certainly not saved on my external twice. Second, when I open the server - rather than reading "Movies" "TV" "Music", etc - It just mashes all of my movies, tv, and some other folders all together with no real organization. I never had this problem when I had my Windows set up, so I know it's something configured improperly more-so than my external drive giving me gruff. Here's my minidlna.conf file: # This is the configuration file for the MiniDLNA daemon, a DLNA/UPnP-AV media # server. # # Unless otherwise noted, the commented out options show their default value. # # On Debian, you can also refer to the minidlna.conf(5) man page for # documentation about this file. media_dir=/media/somnambulist/Ghost In You # This option can be specified more than once if you want multiple directories # scanned. # # If you want to restrict a media_dir to a specific content type, you can # prepend the directory name with a letter representing the type (A, P or V), # followed by a comma, as so: # * "A" for audio (eg. media_dir=A,/var/lib/minidlna/music) # * "P" for pictures (eg. media_dir=P,/var/lib/minidlna/pictures) # * "V" for video (eg. media_dir=V,/var/lib/minidlna/videos) # # WARNING: After changing this option, you need to rebuild the database. Either # run minidlna with the '-R' option, or delete the 'files.db' file # from the db_dir directory (see below). # On Debian, you can run, as root, 'service minidlna force-reload' instead. #media_dir=/var/lib/minidlna media_dir=V,/media/somnambulist/Ghost In You/Movies media_dir=V,/media/somnambulist/Ghost In You/TV media_dir=P,/home/somnambulist/Pictures # Path to the directory that should hold the database and album art cache. db_dir=/home/somnambulist/serverart # Path to the directory that should hold the log file. log_dir=/home/somnambulist/serverlog # Minimum level of importance of messages to be logged. # Must be one of "off", "fatal", "error", "warn", "info" or "debug". # "off" turns of logging entirely, "fatal" is the highest level of importance # and "debug" the lowest. #log_level=warn # Use a different container as the root of the directory tree presented to # clients. The possible values are: # * "." - standard container # * "B" - "Browse Directory" # * "M" - "Music" # * "P" - "Pictures" # * "V" - "Video" # if you specify "B" and client device is audio-only then "Music/Folders" will be used as root root_container=B # Network interface(s) to bind to (e.g. eth0), comma delimited. #network_interface= # IPv4 address to listen on (e.g. 192.0.2.1). #listening_ip= # Port number for HTTP traffic (descriptions, SOAP, media transfer). port=8200 # URL presented to clients. # The default is the IP address of the server on port 80. #presentation_url=http://example.com:80 # Name that the DLNA server presents to clients. friendly_name=Somnambulist Media Server # Serial number the server reports to clients. serial=12345678 # Model name the server reports to clients. #model_name=Windows Media Connect compatible (MiniDLNA) # Model number the server reports to clients. model_number=1 # Automatic discovery of new files in the media_dir directory. #inotify=yes # List of file names to look for when searching for album art. Names should be # delimited with a forward slash ("/"). album_art_names=Cover.jpg/cover.jpg/AlbumArtSmall.jpg/albumartsmall.jpg/AlbumArt.jpg/albumart.jpg/Album.jpg/album.jpg/Folder.jpg/folder.jpg/Thumb.jpg/thumb.jpg # Strictly adhere to DLNA standards. # This allows server-side downscaling of very large JPEG images, which may # decrease JPEG serving performance on (at least) Sony DLNA products. #strict_dlna=no # Support for streaming .jpg and .mp3 files to a TiVo supporting HMO. #enable_tivo=no # Notify interval, in seconds. #notify_interval=895 # Path to the MiniSSDPd socket, for MiniSSDPd support. #minissdpdsocket=/run/minissdpd.sock` And here's the error I get in terminal when I run: sudo service minidlna restart sudo service minidlna force-reload Force restart error: Restarting DLNA/UPnP-AV media server minidlna [2013/08/12 21:19:27] minidlna.c:474: error: Media directory "/media/somnambulist/Ghost In You/Movies" not accessible! [Permission denied] [2013/08/12 21:19:27] minidlna.c:474: error: Media directory "/media/somnambulist/Ghost In You/TV" not accessible! [Permission denied] Force-reload error: Restarting DLNA/UPnP-AV media server minidlna [2013/08/12 21:19:46] minidlna.c:474: error: Media directory "/media/somnambulist/Ghost In You/Movies" not accessible! [Permission denied] [2013/08/12 21:19:46] minidlna.c:474: error: Media directory "/media/somnambulist/Ghost In You/TV" not accessible! [Permission denied] rm: cannot remove ‘/home/somnambulist/serverart/files.db’: Permission denied rm: cannot remove ‘/home/somnambulist/serverart/art_cache/media/somnambulist/Ghost In You/Movies/Slumdog Millionaire/Slumdog.Millionaire.Cover.jpg’: Permission denied rm: cannot remove ‘/home/somnambulist/serverart/art_cache/media/somnambulist/Ghost In You/Movies/Zack and Miri Make a Porno/ZackAndMiriMakeAPornoCover.jpg’: Permission denied [2013/08/12 21:19:46] minidlna.c:744: warn: Failed to clean old file cache. [ OK ] I've spent hours on this at this point, read through various files - and even had a friend who is relatively Ubuntu-savvy try to help me via chat - no such luck. Thanks in advance for any help.

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  • How can give group in active directory folder access by group policy

    - by AAA-Super
    I have windows server 2003 64bit and my clients running on windows xp 32bit. My clients have user rights so they can't install any program. I have some programs needs admin rights for example I have French dictionary without admin right the program will not work properly. I don't want go to each PC and login with admin account then go to program folder located in programs files to give full permission to the group. Is there a way to add them folder in group policy so I can force all the PCs to have full access on the folder? Thanks you in advance.

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  • Unexpected deletion of directory

    - by Anubhav Chaturvedi
    I find that somehow the Downloads directory in /home/user/ is deleted. on using $locate Downloads, it shows the existence of directory without any existence of files within. now when i manually create directory named Downloads, $ locate Downloads shows the directory as well as the files the original folder had. also there is no hidden Downloads folder nor can i access the folder or its files this behavior is quite unexpected .... please help.

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  • Convert a binary tree to linked list, breadth first, constant storage/destructive

    - by Merlyn Morgan-Graham
    This is not homework, and I don't need to answer it, but now I have become obsessed :) The problem is: Design an algorithm to destructively flatten a binary tree to a linked list, breadth-first. Okay, easy enough. Just build a queue, and do what you have to. That was the warm-up. Now, implement it with constant storage (recursion, if you can figure out an answer using it, is logarithmic storage, not constant). I found a solution to this problem on the Internet about a year back, but now I've forgotten it, and I want to know :) The trick, as far as I remember, involved using the tree to implement the queue, taking advantage of the destructive nature of the algorithm. When you are linking the list, you are also pushing an item into the queue. Each time I try to solve this, I lose nodes (such as each time I link the next node/add to the queue), I require extra storage, or I can't figure out the convoluted method I need to get back to a node that has the pointer I need. Even the link to that original article/post would be useful to me :) Google is giving me no joy. Edit: Jérémie pointed out that there is a fairly simple (and well known answer) if you have a parent pointer. While I now think he is correct about the original solution containing a parent pointer, I really wanted to solve the problem without it :) The refined requirements use this definition for the node: struct tree_node { int value; tree_node* left; tree_node* right; };

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