Search Results

Search found 234 results on 10 pages for 'sphere'.

Page 2/10 | < Previous Page | 1 2 3 4 5 6 7 8 9 10  | Next Page >

• Ubuntu 12.04 - compiz - make sphere to like like a planet

  - by gotqn

  I have read topics of people that what to style their compiz sphere like a planet and set a background image like space. It definitely very good idea, but I have not been able to find a tutorial of how this is done (only some clips in youtube of people who have done this and a plugin, but it is not known to work work 12.04 version of Ubuntu). I have set my settings of compiz manager, so I have a sphere now, but I need some help with the images that I need to set. Has anyone idea how these pictures should be created and who the compiz will concatenate them?

  Read the article

• 3D Sphereical Terrain with an 8 mesh sphere. The edges of the mesh are obvioulsy seen and I'm not su

  - by Justin808

  Hi :) I'm working in Unity3D, but my issue is with 3D meshes. I'm hoping someone here can help or point me in the right direction. I have 2 version of code, http://www.pasteit4me.com/695002 (old) and http://www.pasteit4me.com/690003 (new). The old code, makes a single mesh sphere and creates a terrain on it. The new code makes an 8 mesh sphere and creates a terrain on it. On the new version the edges of the meshes are obviously seen and I'm not sure why. It looks like the edges are adjusted no much, almost 2-3 times more than they should have been. GenerateB() in the old code and Generate() in the new code creates the sphere. MakeTerrain() in both create the terrain. If I dont run the MakeTerrain() function the new sphere looks like a solid mesh. I'm not sure where to start looking in the MakeTerrain() function in the new code to solve the issue :-/ Any ideas? An image of the issue is at http://img28.imageshack.us/img28/3784/screenshot20100611at850.png.

  Read the article

• Move a sphere along the swipe?

  - by gameOne

  I am trying to get a sphere curl based on the swipe. I know this has been asked many times, but still it's yearning to be answered. I have managed to add force on the direction of the swipe and it works near perfect. I also have all the swipe positions stored in a list. Now I would like to know how can the curl be achieved. I believe the the curve in the swipe can be calculated by the Vector dot product If theta is 0, then there is no need to add the swipe. If it is not, then add the curl. Maybe this condition is redundant if I managed to find how to curl the sphere along the swipe position The code that adds the force to sphere based on the swipe direction is as below: using UnityEngine; using System.Collections; using System.Collections.Generic; public class SwipeControl : MonoBehaviour { //First establish some variables private Vector3 fp; //First finger position private Vector3 lp; //Last finger position private Vector3 ip; //some intermediate finger position private float dragDistance; //Distance needed for a swipe to register public float power; private Vector3 footballPos; private bool canShoot = true; private float factor = 40f; private List<Vector3> touchPositions = new List<Vector3>(); void Start(){ dragDistance = Screen.height*20/100; Physics.gravity = new Vector3(0, -20, 0); footballPos = transform.position; } // Update is called once per frame void Update() { //Examine the touch inputs foreach (Touch touch in Input.touches) { /*if (touch.phase == TouchPhase.Began) { fp = touch.position; lp = touch.position; }*/ if (touch.phase == TouchPhase.Moved) { touchPositions.Add(touch.position); } if (touch.phase == TouchPhase.Ended) { fp = touchPositions[0]; lp = touchPositions[touchPositions.Count-1]; ip = touchPositions[touchPositions.Count/2]; //First check if it's actually a drag if (Mathf.Abs(lp.x - fp.x) > dragDistance || Mathf.Abs(lp.y - fp.y) > dragDistance) { //It's a drag //Now check what direction the drag was //First check which axis if (Mathf.Abs(lp.x - fp.x) > Mathf.Abs(lp.y - fp.y)) { //If the horizontal movement is greater than the vertical movement... if ((lp.x>fp.x) && canShoot) //If the movement was to the right) { //Right move float x = (lp.x - fp.x) / Screen.height * factor; rigidbody.AddForce((new Vector3(x,10,16))*power); Debug.Log("right "+(lp.x-fp.x));//MOVE RIGHT CODE HERE canShoot = false; //rigidbody.AddForce((new Vector3((lp.x-fp.x)/30,10,16))*power); StartCoroutine(ReturnBall()); } else { //Left move float x = (lp.x - fp.x) / Screen.height * factor; rigidbody.AddForce((new Vector3(x,10,16))*power); Debug.Log("left "+(lp.x-fp.x));//MOVE LEFT CODE HERE canShoot = false; //rigidbody.AddForce(new Vector3((lp.x-fp.x)/30,10,16)*power); StartCoroutine(ReturnBall()); } } else { //the vertical movement is greater than the horizontal movement if (lp.y>fp.y) //If the movement was up { //Up move float y = (lp.y-fp.y)/Screen.height*factor; float x = (lp.x - fp.x) / Screen.height * factor; rigidbody.AddForce((new Vector3(x,y,16))*power); Debug.Log("up "+(lp.x-fp.x));//MOVE UP CODE HERE canShoot = false; //rigidbody.AddForce(new Vector3((lp.x-fp.x)/30,10,16)*power); StartCoroutine(ReturnBall()); } else { //Down move Debug.Log("down "+lp+" "+fp);//MOVE DOWN CODE HERE } } } else { //It's a tap Debug.Log("none");//TAP CODE HERE } } } } IEnumerator ReturnBall() { yield return new WaitForSeconds(5.0f); rigidbody.velocity = Vector3.zero; rigidbody.angularVelocity = Vector3.zero; transform.position = footballPos; canShoot =true; isKicked = false; } }

  Read the article

• Optimized algorithm for line-sphere intersection in GLSL

  - by fernacolo

  Well, hello then! I need to find intersection between line and sphere in GLSL. Right now my solution is based on Paul Bourke's page and was ported to GLSL this way: // The line passes through p1 and p2: vec3 p1 = (...); vec3 p2 = (...); // Sphere center is p3, radius is r: vec3 p3 = (...); float r = ...; float x1 = p1.x; float y1 = p1.y; float z1 = p1.z; float x2 = p2.x; float y2 = p2.y; float z2 = p2.z; float x3 = p3.x; float y3 = p3.y; float z3 = p3.z; float dx = x2 - x1; float dy = y2 - y1; float dz = z2 - z1; float a = dx*dx + dy*dy + dz*dz; float b = 2.0 * (dx * (x1 - x3) + dy * (y1 - y3) + dz * (z1 - z3)); float c = x3*x3 + y3*y3 + z3*z3 + x1*x1 + y1*y1 + z1*z1 - 2.0 * (x3*x1 + y3*y1 + z3*z1) - r*r; float test = b*b - 4.0*a*c; if (test >= 0.0) { // Hit (according to Treebeard, "a fine hit"). float u = (-b - sqrt(test)) / (2.0 * a); vec3 hitp = p1 + u * (p2 - p1); // Now use hitp. } It works perfectly! But it seems slow... I'm new at GLSL. You can answer this questions in two ways: Tell me there is no solution, showing some proof or strong evidence. Tell me about GLSL features (vector APIs, primitive operations) that makes the above algorithm faster, showing some example. Thanks a lot!

  Read the article

• Square game map rendered as sphere with OpenGL

  - by Roflha

  Okay so I have been trying to find a good way to do this for a while now and so far I have nothing. For a hobby project of mine I have created a finite voxel world (similar to minecraft), but as I said, mine is finite. When you reach the edge of it, you are sent to the other side. That is all working fine along with rendering the far side of the map, but I want to be able to render this grid as a sphere. Looking down from above, the world is a square. I basically want to be able to represent a portion of that square as a sphere, as if you were looking at a planet. Right now I am experimenting with taking a circular section of the map, and rendering that, but it look to flat (no curvature around the edges). My question then, is what would be the best way to add some curvature to the edges of a 2d circle to make it look like a hemisphere. However, I am not overly attached to this implementation so if somebody has some other idea for representing the square as a planet, I am all ears.

  Read the article

• Function for building an isosurface (a sphere cut by planes)

  - by GameDevEnthusiast

  I want to build an octree over a quarter of a sphere (for debugging and testing). The octree generator relies on the AIsosurface interface to compute the density and normal at any given point in space. For example, for a full sphere the corresponding code is: // returns <0 if the point is inside the solid virtual float GetDensity( float _x, float _y, float _z ) const override { Float3 P = Float3_Set( _x, _y, _z ); Float3 v = Float3_Subtract( P, m_origin ); float l = Float3_LengthSquared( v ); float d = Float_Sqrt(l) - m_radius; return d; } // estimates the gradient at the given point virtual Float3 GetNormal( float _x, float _y, float _z ) const override { Float3 P = Float3_Set( _x, _y, _z ); float d = this->AIsosurface::GetDensity( P ); float Nx = this->GetDensity( _x + 0.001f, _y, _z ) - d; float Ny = this->GetDensity( _x, _y + 0.001f, _z ) - d; float Nz = this->GetDensity( _x, _y, _z + 0.001f ) - d; Float3 N = Float3_Normalized( Float3_Set( Nx, Ny, Nz ) ); return N; } What is a nice and fast way to compute those values when the shape is bounded by a low number of half-spaces?

  Read the article

• Google veut suivre vos achats hors de la sphère internet, un projet en phase de test

  Google veut suivre vos achats hors de la sphère internet, un projet en phase de test Début octobre, Google avait annoncé son intention de mieux mesurer l'efficacité de ses publicités en ligne sur les ventes en boutique physique. Il faut dire que l'entreprise est loin d'être la seule ; de nombreuses compagnies ont déjà cherché à établir un lien entre le nombre de clics sur une publicité et un achat réellement effectué. Digiday affirme que pour y parvenir, Google a lancé un programme qui se...

  Read the article

• Calculating volume for sphere in c++

  - by Crystal

  This is probably an easy one, but is the right way to calculate volume for a sphere in c++. My getArea() seems to be right, but when I call getVolume() it doesn't output the right amount. With a sphere of radius = 1, it gives me the answer of pi, which is incorrect: double Sphere::getArea() const { return 4 * Shape::pi * pow(getZ(), 2); } double Sphere::getVolume() const { return (4 / 3) * Shape::pi * pow(getZ(), 3); }

  Read the article

• Calculating a circle or sphere along a vector

  - by Sparky

  Updated this post and the one at Math SE (http://math.stackexchange.com/questions/127866/calculating-a-circle-or-sphere-along-a-vector), hope this makes more sense. I previously posted a question (about half an hour ago) involving computations along line segments, but the question and discussion were really off track and not what I was trying to get at. I am trying to work with an FPS engine I am attempting to build in Java. The problem I am encountering is with hitboxing. I am trying to calculate whether or not a "shot" is valid. I am working with several approaches and any insight would be helpful. I am not a native speaker of English nor skilled in Math so please bear with me. Player position is at P0 = (x0,y0,z0), Enemy is at P1 = (x1,y1,z1). I can of course compute the distance between them easily. The target needs a "hitbox" object, which is basically a square/rectangle/mesh either in front of, in, or behind them. Here are the solutions I am considering: I have ruled this out...doesn't seem practical. [Place a "hitbox" a small distance in front of the target. Then I would be able to find the distance between the player and the hitbox, and the hitbox and the target. It is my understanding that you can compute a circle with this information, and I could simply consider any shot within that circle a "hit". However this seems not to be an optimal solution, because it requires you to perform a lot of calculations and is not fully accurate.] Input, please! Place the hitbox "in" the player. This seems like the better solution. In this case what I need is a way to calculate a circle along the vector, at whatever position I wish (in this case, the distance between the two objects). Then I can pick some radius that encompasses the whole player, and count anything within this area a "hit". I am open to your suggestions. I'm trying to do this on paper and have no familiarity with game engines. If any software folk out there think I'm doing this the hard way, I'm open to help! Also - Anyone with JOGL/LWJGL experience, please chime in. Is this making sense?

  Read the article

• Anyone know were i could find an algorithm or have a algorithm they could share to split a sphere (m

  - by Justin808

  I have a list a vertices and a list of triangles. I'd like to split this single mesh into, say 5, randomly shaped meshes. When the 5 randomly shaped meshes are in place the sphere should all line up and look like 1 solid mesh. I need a algorithm to do this programmatically, not a tool to do it form me. Any pointers would be great!

  Read the article

• velocity vector

  - by wanderer

  Hi, I am trying to simulate a collision. The collision is shown here http://www.freeimagehosting.net/image.php?c5ae01b476.jpg A particle falls down on a sphere and a collision between sphere and particle takes place. The sphere always remain stationary and the collision itself is not elastic. So if the particle falls directly n top of sphere, the velocity of particle will become zero. I was trying to set the velocity of particle to be zero after the collision. But that does not give good simulation when the collision does not occur on top of sphere but along the side of sphere. So now after the collision i need to make sure that the particle has a velocity which is orthogonal to the vector of the point of collision from the center of sphere. The velocity along the vector from center of sphere to point of collision should become zero. How do i do that? I am a bit mathematically challenged but i think it has something to do with dot product of vectors. Or maybe i am wrong :) I have the initial velocity vector and 'radiusvector' say :- 1)velocity <-1.03054, -1.56563, 1.33341e-016 2) radius vector <2.04406, 2.19587, 1.0514 Pseudo code for the problem is: foreach( particle particle in particlesCollections) { //sphere.x, sphere.y sphere.z give the center of the sphere dist = particle.pos-vector(sphere.x,sphere.y,sphere.z); //detect if a collision has taken place. if (dist.mag < sphere.radius) { rVector=dist/dist.mag*sphere.radius; particle.pos=vector(sphere.x,sphere.y,sphere.z) + rVector; //particle.Velocity gives the velocity vector of the particle at the time of collision //i need to modify particle.Velocity so that the component of velocity that runs along // with the rvector becomes zero as i have a non elsatic collision. The remaining //velocity that the particle will have is the one which runs along with tangent to the //rVector. The sphere remains stationary. //example values: particle.Velocity == <-1.03054, -1.56563, .006> //and rVector = <2.04406, 2.19587, 1.0514> } } Thanks

  Read the article

• Height Map Mapping to "Chunked" Quadrilateralized Spherical Cube

  - by user3684950

  I have been working on a procedural spherical terrain generator for a few months which has a quadtree LOD system. The system splits the six faces of a quadrilateralized spherical cube into smaller "quads" or "patches" as the player approaches those faces. What I can't figure out is how to generate height maps for these patches. To generate the heights I am using a 3D ridged multi fractals algorithm. For now I can only displace the vertices of the patches directly using the output from the ridged multi fractals. I don't understand how I generate height maps that allow the vertices of a terrain patch to be mapped to pixels in the height map. The only thing I can think of is taking each vertex in a patch, plug that into the RMF and take that position and translate into u,v coordinates then determine the pixel position directly from the u,v coordinates and determine the grayscale color based on the height. I feel as if this is the right approach but there are a few other things that may further complicate my problem. First of all I intend to use "height maps" with a pixel resolution of 192x192 while the vertex "resolution" of each terrain patch is only 16x16 - meaning that I don't have any vertices to sample for the RMF for most of the pixels. The main reason the height map resolution is higher so that I can use it to generate a normal map (otherwise the height maps serve little purpose as I can just directly displace vertices as I currently am). I am pretty much following this paper very closely. This is, essentially, the part I am having trouble with. Using the cube-to-sphere mapping and the ridged multifractal algorithm previously described, a normalized height value ([0, 1]) is calculated. Using this height value, the terrain position is calculated and stored in the first three channels of the positionmap (RGB) – this will be used to calculate the normalmap. The fourth channel (A) is used to store the height value itself, to be used in the heightmap. The steps in the first sentence are my primary problem. I don't understand how the pixel positions correspond to positions on the sphere and what positions are sampled for the RMF to generate the pixels if only vertices cannot be used.

  Read the article

• Sphere entering in to the cube.unity

  - by Parthi

  I am trying Roll a Ball unity tutorial.Everything is fine,but when I roll the ball it is moving through the cube instead of picking it. my player class is using UnityEngine; using System.Collections; public class player : MonoBehaviour { public float speed; // Use this for initialization // Update is called once per frame void Update () { float h = Input.GetAxis("Horizontal"); float v = Input.GetAxis("Vertical"); Vector3 move = new Vector3(h,0,v); rigidbody.AddForce(move * speed * Time.deltaTime); } void OnTriggerEnter(Collider other) { if(other.gameObject.tag == "Pick up") { other.gameObject.SetActive(false); } } }

  Read the article

• Getting a sphere to roll down a .FBX object Unity3D/C#

  - by Timothy Williams

  I'm working on a little ramp and ball game in Unity, I modeled the ramp outside Unity and exported it to a .FBX file, then I imported the ramp in to Unity. I set up the ball and ramp, both have Rigidbodies, Ramp is set to isKinematic = true, yet when I play the game the ball just falls right through the ramp and hits the floor below it fine. So it's something wrong with the ramp. Am I doing something wrong? Are .FBX files unable to apply physics? Thanks, Tim.

  Read the article

• Sphere Texture Mapping shows visible seams

  - by AvengerDr

  As you can see from the above picture there is a visible seam in the texture mapping. The underlying mesh is a geosphere based on octahedron subdivisions. On that particular latitude, vertices have been duplicated. However there still is a visible seam. Here is how I calculate the UV coordinates: float longitude = (float)Math.Atan2(normal.X, -normal.Z); float latitude = (float)Math.Acos(normal.Y); float u = (float)(longitude / (Math.PI * 2.0) + 0.5); float v = (float)(latitude / Math.PI); Is this a problem in the coordinates or a mipmapping issue?

  Read the article

• Unity, Unrealistic Sphere On Inclined Plane

  - by user1086516

  So I am trying to model a ball rolling down an inclined surface in Unity based on what I am observing in real life but it is still quite off. In Unity it takes the ball about 3 seconds to travel from a place to another specified place where in real life it only takes 1 second. The ball isn't as fast to react to the incline as in real life (even though I have tried giving the ball and surface low or zero friction values) The ball does not accelerate as nearly as fast as it does in real life What do I do to give the ball more realistic behavior ? I have tried messing around with mass, physics materials, drag, and angular drag on the ball and surface but it doesn't seem to be helping.

  Read the article

• How do I run the sphere-slicer.pl perl command to make a photo into a sphere?

  - by Mahdi Zenali

  I was looking for a program to slice pictures somehow to paste it on a globe(sphere). I found ip-slicer in this website. http://www.bruno.postle.net/2001/ip-slicer/ The problem I have is that I don't know where should I enter the command line. for example after running the program and entering this line "sphere-slicer.pl 16 1000 input.jpg" I get this this error Number found where operator expected at - line 72, near "pl 16" (Do you need to predeclare pl?) Number found where operator expected at - line 72, near "16 1000" (Missing operator before 1000?) Bareword found where operator expected at - line 72, near "1000 input" (Missing operator before input?) This program is written in perl language.

  Read the article

• If I project a sphere in 3D will it be a circle?

  - by yuumei

  Assuming I have infinite vertices to represent the sphere, if I project the sphere from any position/scale in 3D to 2D, will it be a circle? I know it will not be a circle on the screen, because of scaling and different resolutions. But do field of view and aspect ratio effect the results? Edit: Sorry yes, I am talking about perspective projection. Seems the answer is no then, perspective will distort the sphere. Thanks!

  Read the article

• Update on: How to model random non-overlapping spheres of non-uniform size in a cube using Matlab?

  - by user3838079

  I am trying to use MATLAB for generating random locations for non-uniform size spheres (non-overlapping) in a cube. The for loop in the code below never seems to end. I don't know what am missing in the code. I have ran the code for no. of spheres (n) = 10; dims = [ 10 10 10 ] function [ c r ] = randomSphere( dims ) % creating one sphere at random inside [0..dims(1)]x[0..dims(2)]x... % radius and center coordinates are sampled from a uniform distribution % over the relevant domain. % output: c - center of sphere (vector cx, cy,... ) % r - radius of sphere (scalar) r = rand(1); % you might want to scale this w.r.t dims or other consideration c = r + rand( size(dims) )./( dims - 2*r ); % make sure sphere does not exceed boundaries function ovlp = nonOverlapping( centers, rads ) % check if several spheres with centers and rads overlap or not ovlp = false; if numel( rads ) == 1 return; % nothing to check for a single sphere end dst = sqrt( sum( bsxfun( @minus, permute( centers, [1 3 2] ),... permute( centers, [3 1 2] ) ).^2, 3) ); ovlp = dst >= bsxfun( @plus, rads, rads.' ); %' all distances must be smaller than r1+r2 ovlp = any( ovlp(:) ); % all must not overlap function [centers rads] = sampleSpheres( dims, n ) % dims is assumed to be a row vector of size 1-by-ndim % preallocate ndim = numel(dims); centers = zeros( n, ndim ); rads = zeros( n, 1 ); ii = 1; while ii <= n [centers(ii,:), rads(ii) ] = randomSphere( dims ); if nonOverlapping( centers(1:ii,:), rads(1:ii) ) ii = ii + 1; % accept and move on end end

  Read the article

• Creating a Glowing Sphere in Java3D

  - by Jim

  Hey, I'm looking for a way to reproduce this foggy-sphere-glowing effect using Java3D. http://bzflag.org/screenshots/bzfi0021.jpg http://bzflag.org/screenshots/bzfi0019.jpg http://bzflag.org/screenshots/bzfi0022.jpg I'm creating a transform group with a point light source and an emissive-material-sphere, but I can't reproduce the foggyness. Ideas? Thanks!

  Read the article

• Colored sphere in OpenGL

  - by Michael

  Ok so here's link to code in c++ http://pastebin.com/nfPmd0um (with polish comments ;) I would like to make a sphere divided by four planes. Each part of sphere should have a different color. At the moment it displays only 2 colored parts. I know that something's wrong with that part of code in Display() function: glEnable (GL_CLIP_PLANE0 +i); glDisable (GL_CLIP_PLANE1 -i); glEnable (GL_CLIP_PLANE2 +i); glDisable (GL_CLIP_PLANE3 -i); Anyone know what should i change? Thanks in advance :)

  Read the article

• ray collision with rectangle and floating point accuracy

  - by phq

  I'm trying to solve a problem with a ray bouncing on a box. Actually it is a sphere but for simplicity the box dimensions are expanded by the sphere radius when doing the collision test making the sphere a single ray. It is done by projecting the ray onto all faces of the box and pick the one that is closest. However because I'm using floating point variables I fear that the projected point onto the surface might be interpreted as being below in the next iteration, also I will later allow the sphere to move which might make that scenario more likely. Also the bounce coefficient might be as low as zero, making the sphere continue along the surface. So my naive solution is to project not only forwards but backwards to catch those cases. That is where I got into problems shown in the figure: In the first iteration the first black arrow is calculated and we end up at a point on the surface of the box. In the second iteration the "back projection" hits the other surface making the second black arrow bounce on the wrong surface. If there are several boxes close to each other this has further consequences making the sphere fall through them all. So my main question is how to handle possible floating point accuracy when placing the sphere on the box surface so it does not fall through. In writing this question I got the idea to have a threshold to only accept back projections a certain amount much smaller than the box but larger than the possible accuracy limitation, this would only cause the "false" back projection when the sphere hit the box on an edge which would appear naturally. To clarify my original approach, the arrows shown in the image is not only the path the sphere travels but is also representing a single time step in the simulation. In reality the time step is much smaller about 0.05 of the box size. The path traveled is projected onto possible sides to avoid traveling past a thinner object at higher speeds. In normal situations the floating point accuracy is not an issue but there are two situations where I have the concern. When the new position at the end of the time step is located very close to the surface, very unlikely though. When using a bounce factor of 0, here it happens every time the sphere hit a box. To add some loss of accuracy, the motivation for my concern, is that the sphere and box are in different coordinate systems and thus the sphere location is transformed for every test. This last one is why I'm not willing to stand on luck that one floating point value lying on top of the box always will be interpreted the same. I did not know voronoi regions by name, but looking at it I'm not sure how it would be used in a projection scenario that I'm using here.

  Read the article

• Vmware sphere setting up external network

  - by Tom Beech

  I've just setup vmware vsphere 5 on a remote server (rented dedicated server). I've added my first VPS (centos 5.8) barebones. It's not finding any IP (internal or external) on boot. I've had an extra external IP assigned to my server that I wanted to use on the VPS. I tried editing the eth0 config and adding the IP in there and turning off the DHCP, but it can't find any IP or ping google or do any networking type things. How do I route the IP to my VPS so I can access it remotely?

  Read the article

• How to center viewport at center of the sphere

  - by satyam

  Hi I want to create panorama view with opengl in android. Is it possible using spherical view and centering viewpoint at the sphere center to show bounded image on screen. will this be good aproch , i havent used opengl but want to achive this effect in android Am i going in right direction , any pointers for this will be great help . thanx in advance.

  Read the article

• Generating a random displacement on the unit sphere

  - by becko

  Given a unit vector n, I need to generate, as fast as possible, another random unit vector m. The deviation of m from n should be on the order of a positive parameter sigma, and the distribution of m on the unit sphere should be symmetrical around n. I have no specific requirements on the representation of unit vectors, so you can use spherical angles, Cartesian coordinates, or whatever turns out to be convenient. Also, there are no precise requirements on the probability distributions used, as long as it decays when m deviates more than sigma from n. I am working with gsl and C. I have come up with a somewhat convoluted method using Cartesian coordinates. I will post it later if it is useful, but I would like to see people's ideas.

  Read the article

< Previous Page | 1 2 3 4 5 6 7 8 9 10  | Next Page >