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• Project Euler Question 14 (Collatz Problem)

  - by paradox

  The following iterative sequence is defined for the set of positive integers: n -n/2 (n is even) n -3n + 1 (n is odd) Using the rule above and starting with 13, we generate the following sequence: 13 40 20 10 5 16 8 4 2 1 It can be seen that this sequence (starting at 13 and finishing at 1) contains 10 terms. Although it has not been proved yet (Collatz Problem), it is thought that all starting numbers finish at 1. Which starting number, under one million, produces the longest chain? NOTE: Once the chain starts the terms are allowed to go above one million. I tried coding a solution to this in C using the bruteforce method. However, it seems that my program stalls when trying to calculate 113383. Please advise :) #include <stdio.h> #define LIMIT 1000000 int iteration(int value) { if(value%2==0) return (value/2); else return (3*value+1); } int count_iterations(int value) { int count=1; //printf("%d\n", value); while(value!=1) { value=iteration(value); //printf("%d\n", value); count++; } return count; } int main() { int iteration_count=0, max=0; int i,count; for (i=1; i<LIMIT; i++) { printf("Current iteration : %d\n", i); iteration_count=count_iterations(i); if (iteration_count>max) { max=iteration_count; count=i; } } //iteration_count=count_iterations(113383); printf("Count = %d\ni = %d\n",max,count); }

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• Bibliography behaves strange in lyx.

  - by Orjanp

  Hi! I have created a Bibliography section in my document written in lyx. It uses a book layout. For some reason it did start over again when I added some more entries. The new entries was made some time later than the first ones. I just went down to key-27 and hit enter. Then it started on key-1 again. Does anyone know why it behaves like this? The lyx code is below. \begin{thebibliography}{34} \bibitem{key-6}Lego mindstorms, http://mindstorms.lego.com/en-us/default.aspx \bibitem{key-7}C.A.R. Hoare. Communicating sequential processes. Communications of the ACM, 21(8):666-677, pages 666\textendash{}677, August 1978. \bibitem{key-8}C.A.R. Hoare. Communicating sequential processes. Prentice-Hall, 1985. \bibitem{key-9}CSPBuilder, http://code.google.com/p/cspbuilder/ \bibitem{key-10}Rune Møllegård Friborg and Brian Vinter. CSPBuilder - CSP baset Scientific Workflow Modelling, 2008. \bibitem{key-11}Labview, http://www.ni.com/labview \bibitem{key-12}Robolab, http://www.lego.com/eng/education/mindstorms/home.asp?pagename=robolab \bibitem{key-13}http://code.google.com/p/pycsp/ \bibitem{key-14}Paparazzi, http://paparazzi.enac.fr \bibitem{key-15}Debian, http://www.debian.org \bibitem{key-16}Ubuntu, http://www.ubuntu.com \bibitem{key-17}GNU, http://www.gnu.org \bibitem{key-18}IVY, http://www2.tls.cena.fr/products/ivy/ \bibitem{key-19}Tkinter, http://wiki.python.org/moin/TkInter \bibitem{key-20}pyGKT, http://www.pygtk.org/ \bibitem{key-21}pyQT4, http://wiki.python.org/moin/PyQt4 \bibitem{key-22}wxWidgets, http://www.wxwidgets.org/ \bibitem{key-23}wxPython GUI toolkit, http://www.wxPython.org \bibitem{key-24}Python programming language, http://www.python.org \bibitem{key-25}wxGlade, http://wxglade.sourceforge.net/ \bibitem{key-26}http://numpy.scipy.org/ \bibitem{key-27}http://www.w3.org/XML/ \bibitem{key-1}IVY software bus, http://www2.tls.cena.fr/products/ivy/ \bibitem{key-2}sdas \bibitem{key-3}sad \bibitem{key-4}sad \bibitem{key-5}fsa \bibitem{key-6}sad \bibitem{key-7} \end{thebibliography}

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• Locating memory leak in Apache httpd process, PHP/Doctrine-based application

  - by Sam

  I have a PHP application using these components: Apache 2.2.3-31 on Centos 5.4 PHP 5.2.10 Xdebug 2.0.5 with Remote Debugging enabled APC 3.0.19 Doctrine ORM for PHP 1.2.1 using Query Caching and Results Caching via APC MySQL 5.0.77 using Query Caching I've noticed that when I start up Apache, I eventually end up 10 child processes. As time goes on, each process will grow in memory until each one approaches 10% of available memory, which begins to slow the server to a crawl since together they grow to take up 100% of memory. Here is a snapshot of my top output: PID USER PR NI VIRT RES SHR S %CPU %MEM TIME+ COMMAND 1471 apache 16 0 626m 201m 18m S 0.0 10.2 1:11.02 httpd 1470 apache 16 0 622m 198m 18m S 0.0 10.1 1:14.49 httpd 1469 apache 16 0 619m 197m 18m S 0.0 10.0 1:11.98 httpd 1462 apache 18 0 622m 197m 18m S 0.0 10.0 1:11.27 httpd 1460 apache 15 0 622m 195m 18m S 0.0 10.0 1:12.73 httpd 1459 apache 16 0 618m 191m 18m S 0.0 9.7 1:13.00 httpd 1461 apache 18 0 616m 190m 18m S 0.0 9.7 1:14.09 httpd 1468 apache 18 0 613m 190m 18m S 0.0 9.7 1:12.67 httpd 7919 apache 18 0 116m 75m 15m S 0.0 3.8 0:19.86 httpd 9486 apache 16 0 97.7m 56m 14m S 0.0 2.9 0:13.51 httpd I have no long-running scripts (they all terminate eventually, the longest being maybe 2 minutes long), and I am working under the assumption that once each script terminates, the memory it uses gets deallocated. (Maybe someone can correct me on that). My hunch is that it could be APC, since it stores data between requests, but at the same time, it seems weird that it would store data inside the httpd process. How can I track down which part of my app is causing the memory leak? What tools can I use to see how the memory usage is growing inside the httpd process and what is contributing to it?

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• What specific features of LabView are frustrating to you?

  - by Underflow

  Please bear with me: this isn't a language debate or a flame. It's a real request for opinions. Occasionally, I have to help educate a traditional text coder in how to think in LabVIEW (LV). Often during this process, I get to hear about how LV sucks. Rarely is this insight accompanied by rational observations other than "Language X is just so much better!". While this statement is satisfying to them, it doesn't help me understand what is frustrating them. So, for those of you with LabVIEW and text language experience, what specific things about LV drive you nuts? ------ Summaries ------- Thanks for all the answers! Some of the issues are answered in the comments below, some exist on other sites, and some are just genuine problems with LV. In the spirit of the original question, I'm not going to try to answer all of these here: check LAVA or NI's website, and you'll be pleasantly surprised at how many of these things can be overcome. Unintentional concurrency No access to tradition text manipulation tools Binary-only source code control Difficult to branch and merge Too many open windows Text has cleaner/clearer/more expressive syntax Clean coding requires a lot of time and manipulation Large, difficult to access API/palette system Mouse required File namespacing: no duplicate files with the same name in memory LV objects are natively by-value only Requires dev environment to view code Lack of zoom Slow startup Memory pig "Giant" code is difficult to work with UI lockup is easy to do Trackpads and LV don't mix well String manipulation is graphically bloated Limited UI customization "Hidden" primitives (yes, these exist) Lack of official metaprogramming capability (not for much longer, though) Lack of unicode support [1]: http://www.lavag.org LAVA

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• Locating memory leak in Apache httpd process, PHP/Doctrine-based application

  - by Sam

  I have a PHP application using these components: Apache 2.2.3-31 on Centos 5.4 PHP 5.2.10 Xdebug 2.0.5 with Remote Debugging enabled APC 3.0.19 Doctrine ORM for PHP 1.2.1 using Query Caching and Results Caching via APC MySQL 5.0.77 using Query Caching I've noticed that when I start up Apache, I eventually end up 10 child processes. As time goes on, each process will grow in memory until each one approaches 10% of available memory, which begins to slow the server to a crawl since together they grow to take up 100% of memory. Here is a snapshot of my top output: PID USER PR NI VIRT RES SHR S %CPU %MEM TIME+ COMMAND 1471 apache 16 0 626m 201m 18m S 0.0 10.2 1:11.02 httpd 1470 apache 16 0 622m 198m 18m S 0.0 10.1 1:14.49 httpd 1469 apache 16 0 619m 197m 18m S 0.0 10.0 1:11.98 httpd 1462 apache 18 0 622m 197m 18m S 0.0 10.0 1:11.27 httpd 1460 apache 15 0 622m 195m 18m S 0.0 10.0 1:12.73 httpd 1459 apache 16 0 618m 191m 18m S 0.0 9.7 1:13.00 httpd 1461 apache 18 0 616m 190m 18m S 0.0 9.7 1:14.09 httpd 1468 apache 18 0 613m 190m 18m S 0.0 9.7 1:12.67 httpd 7919 apache 18 0 116m 75m 15m S 0.0 3.8 0:19.86 httpd 9486 apache 16 0 97.7m 56m 14m S 0.0 2.9 0:13.51 httpd I have no long-running scripts (they all terminate eventually, the longest being maybe 2 minutes long), and I am working under the assumption that once each script terminates, the memory it uses gets deallocated. (Maybe someone can correct me on that). My hunch is that it could be APC, since it stores data between requests, but at the same time, it seems weird that it would store data inside the httpd process. How can I track down which part of my app is causing the memory leak? What tools can I use to see how the memory usage is growing inside the httpd process and what is contributing to it?

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• Bash and regex problem : check for tokens entered into a Coke vending machine

  - by Michael Mao

  Hi all: Here is a "challenge question" I've got from Linux system programming lecture. Any of the following strings will give you a Coke if you kick: L = { aaaa, aab, aba, baa, bb, aaaa"a", aaaa"b", aab"a", … ab"b"a, ba"b"a, ab"bbbbbb"a, ... } The letters shown in wrapped double quotes indicate coins that would have fallen through (but those strings are still part of the language in this example). Exercise (a bit hard) show this is the language of a regular expression And this is what I've got so far : #!/usr/bin/bash echo "A bottle of Coke costs you 40 cents" echo -e "Please enter tokens (a = 10 cents, b = 20 cents) in a sequence like 'abba' :\c" read tokens #if [ $tokens = aaaa ]||[ $tokens = aab ]||[ $tokens = bb ] #then # echo "Good! now a coke is yours!" #else echo "Thanks for your money, byebye!" if [[ $token =~ 'aaaa|aab|bb' ]] then echo "Good! now a coke is yours!" else echo "Thanks for your money, byebye!" fi Sadly it doesn't work... always outputs "Thanks for your money, byebye!" I believe something is wrong with syntax... We didn't provided with any good reference book and the only instruction from the professor was to consult "anything you find useful online" and "research the problem yourself" :( I know how could I do it in any programming language such as Java, but get it done with bash script + regex seems not "a bit hard" but in fact "too hard" for anyone with little knowledge on something advanced as "lookahead"(is this the terminology ?) I don't know if there is a way to express the following concept in the language of regex: Valid entry would consist of exactly one of the three components : aaaa, aab and bb, regardless of order, followed by an arbitrary sequence of a or b's So this is what is should be like : (a{4}Ua{2}bUb{2})(aUb)* where the content in first braces is order irrelevant. Thanks a lot in advance for any hints and/or tips :)

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• How to shuffle pairs

  - by Jessy

  How to shuffle the elements in the pairs? The program below, generate all possible pairs and later shuffle the pairs. e.g. possible pairs before shuffle is ab,ac,ae,af..etc shuffled to ac,ae,af,ab...etc How to make it not only shuffled in pairs but within the elements in the pair itself? e.g. instead of ab, ac, how can I make ba, ac ? String[] pictureFile = {"a.jpg","b.jpg","c.jpg","d.jpg","e.jpg","f.jpg","g.jpg"}; List <String> pic1= Arrays.asList(pictureFile); ... ListGenerator pic2= new ListGenerator(pic1); ArrayList<ArrayList<Integer>> pic2= new ArrayList<ArrayList<Integer>>(); public class ListGenerator { public ListGenerator(List<String> pic1) { int size = pic1.size(); // create a list of all possible combinations for(int i = 0 ; i < size ; i++) { for(int j = (i+1) ; j < size ; j++) { ArrayList<Integer> temp = new ArrayList<Integer>(); temp.add(i); temp.add(j); pic2.add(temp); } } Collections.shuffle(pic2); } //This method return the shuffled list public ArrayList<ArrayList<Integer>> getList() { return pic2; } }

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• Good way to maintain Muliple level selection menu list in J2ME

  - by geoaxis

  Hello, I need a good way to maintain multiple form level data for menue selection. So for example If I have A and B, each might Have 1 2 3 so A A1 A2 A3 B B1 B2 B3 And this can continue for long, so that I could have A - A1 - A1.1 - A1.1.1 -.... I have the following class in place, works ok But I suspect we could have better. I just need to perform selection ni a selection tree like Widget, but each level of selection comes in another form (in J2ME) import java.util.Vector; public class Tag { private String tag; private Vector childTags; private Tag parent; Tag(String tag, Vector childtag) { this.tag = tag; this.childTags= childTags; } public void setChildTags(Vector childTags) { this.childTags = childTags; } public Vector getChildTags() { return this.childTags; } public String getTag() { return this.tag; } public String toString(int depth) { String a =""; if(depth==0) { a = a + this.getTag(); } if(this.getChildTags()!= null) { for(int k=0;k <this.getChildTags().capacity(); k++) { for (int i=0; i<depth; i++ ) { a = a + ("-"); } a = a+ ( ((Tag)this.getChildTags().elementAt(k)).toString(depth++)); } } return a; } }

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• Jquery addClass on radio box checked.

  - by Zoltan Repas

  I checked all the topics, but i simply don't know why my script does not work :( <script type="text/javascript" src="http://code.jquery.com/jquery-1.4.2.min.js"></script> <script type="text/javascript"> $('#pic').click(function() { $(this).parents("li").find(".green").removeClass("green"); if($(this).is(':checked')) { $(this).parents("ul").find("li").addClass('green'); } }); </script> etc... <ul> <li><input type="radio" name="pic" value="asd"/>asd</li> <li><input type="radio" name="pic" value="b"/>asd</li> <li><input type="radio" name="pic" value="ba"/>asd</li> <li><input type="radio" name="pic" value="bs"/>asd</li> <li><input type="radio" name="pic" value="bc"/>asd</li> </ul> Please help me!

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• Solving Naked Triples in Sudoku

  - by Kave

  Hello, I wished I paid more attention to the math classes back in Uni. :) How do I implement this math formula for naked triples? Naked Triples Take three cells C = {c1, c2, c3} that share a unit U. Take three numbers N = {n1, n2, n3}. If each cell in C has as its candidates ci ? N then we can remove all ni ? N from the other cells in U.** I have a method that takes a Unit (e.g. a Box, a row or a column) as parameter. The unit contains 9 cells, therefore I need to compare all combinations of 3 cells at a time that from the box, perhaps put them into a stack or collection for further calculation. Next step would be taking these 3-cell-combinations one by one and compare their candidates against 3 numbers. Again these 3 numbers can be any possible combination from 1 to 9. Thats all I need. But how would I do that? How many combinations would I get? Do I get 3 x 9 = 27 combinations for cells and then the same for numbers (N)? How would you solve this in classic C# loops? No Lambda expression please I am already confused enough :) Many Thanks for any help,

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• How do I use the sed command to remove all lines between 2 phrases (including the phrases themselves

  - by fzkl

  I am generating a log from which I want to remove X startup output which looks like this: X.Org X Server 1.7.6 Release Date: 2010-03-17 X Protocol Version 11, Revision 0 Build Operating System: Linux 2.6.31-607-imx51 armv7l Ubuntu Current Operating System: Linux nvidia 2.6.33.2 #1 SMP PREEMPT Mon May 31 21:38:29 PDT 2010 armv7l Kernel command line: mem=448M@0M nvmem=64M@448M mem=512M@512M chipuid=097c81c6425f70d7 vmalloc=320M video=tegrafb console=ttyS0,57600n8 usbcore.old_scheme_first=1 tegraboot=nand root=/dev/nfs ip=:::::usb0:on rw tegra_ehci_probe_delay=5000 smp dvfs tegrapart=recovery:1b80:a00:800,boot:2680:1000:800,environment:3780:40:800,system:38c0:2bc00:800,cache:2f5c0:4000:800,userdata:336c0:c840:800 envsector=3080 Build Date: 23 April 2010 05:19:26PM xorg-server 2:1.7.6-2ubuntu7 (Bryce Harrington <[email protected]>) Current version of pixman: 0.16.4 Before reporting problems, check http://wiki.x.org to make sure that you have the latest version. Markers: (--) probed, (**) from config file, (==) default setting, (++) from command line, (!!) notice, (II) informational, (WW) warning, (EE) error, (NI) not implemented, (??) unknown. (==) Log file: "/var/log/Xorg.0.log", Time: Wed Jun 16 19:52:00 2010 (==) Using config file: "/etc/X11/xorg.conf" (==) Using config directory: "/usr/lib/X11/xorg.conf.d" Is there any way to do this without manually checking pattern for each line?

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• OpenGL Calls Lock/Freeze

  - by Necrolis

  I am using some dell workstations(running WinXP Pro SP 2 & DeepFreeze) for development, but something was recenlty loaded onto these machines that prevents any opengl call(the call locks) from completing(and I know the code works as I have tested it on 'clean' machines, I also tested with simple opengl apps generated by dev-cpp, which will also lock on the dell machines). I have tried to debug my own apps to see where exactly the gl calls freeze, but there is some global system hook on ZwQueryInformationProcess that messes up calls to ZwQueryInformationThread(used by ExitThread), preventing me from debugging at all(it causes the debugger, OllyDBG, to go into an access violation reporting loop or the program to crash if the exception is passed along). the hook: ntdll.ZwQueryInformationProcess 7C90D7E0 B8 9A000000 MOV EAX,9A 7C90D7E5 BA 0003FE7F MOV EDX,7FFE0300 7C90D7EA FF12 CALL DWORD PTR DS:[EDX] 7C90D7EC - E9 0F28448D JMP 09D50000 7C90D7F1 9B WAIT 7C90D7F2 0000 ADD BYTE PTR DS:[EAX],AL 7C90D7F4 00BA 0003FE7F ADD BYTE PTR DS:[EDX+7FFE0300],BH 7C90D7FA FF12 CALL DWORD PTR DS:[EDX] 7C90D7FC C2 1400 RETN 14 7C90D7FF 90 NOP ntdll.ZwQueryInformationToken 7C90D800 B8 9C000000 MOV EAX,9C the messed up function + call: ntdll.ZwQueryInformationThread 7C90D7F0 8D9B 000000BA LEA EBX,DWORD PTR DS:[EBX+BA000000] 7C90D7F6 0003 ADD BYTE PTR DS:[EBX],AL 7C90D7F8 FE ??? ; Unknown command 7C90D7F9 7F FF JG SHORT ntdll.7C90D7FA 7C90D7FB 12C2 ADC AL,DL 7C90D7FD 14 00 ADC AL,0 7C90D7FF 90 NOP ntdll.ZwQueryInformationToken 7C90D800 B8 9C000000 MOV EAX,9C So firstly, anyone know what if anything would lead to OpenGL calls cause an infinite lock,and if there are any ways around it? and what would be creating such a hook in kernal memory ? Update: After some more fiddling, I have discovered a few more kernal hooks, a lot of them are used to nullify data returned by system information calls(such as the remote debugging port), I also managed to find out the what ever is doing this is using madchook.dll(by madshi) to do this, this dll is also injected into every running process(these seem to be some anti debugging code). Also, on the OpenGL side, it seems Direct X is fine/unaffected(I ran one of the DX 9 demo's without problems), so could one of these kernal hooks somehow affect OpenGL?

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• Why does iOS 5 fail to connect to a server running JDK 1.6, but not JDK 1.5

  - by KC Baltz

  We have a Java Socket Server listening on an SSLSocket (port 443) and an iOS application that connects with it. When running on iOS 5.1, the application stopped working when we upgraded the Java version of the server from JDK 1.5 to 1.6 (or 1.7). The app connects just fine to JDK 5 and 6 when running on iOS 6. The iOS app is reporting an error: -9809 = errSSLCrypto. On the Java side, we get javax.net.ssl.SSLException: Received fatal alert: close_notify. On the Java server side, we have enabled all the available cipher suites. On the client side we have tested enabling several different suites, although we have yet to complete a test involving each one individually enabled. Right now, it is failing when we use TLS_DH_anon_WITH_AES_128_CBC_SHA although it has failed with others and we are starting to think it's not the suite. Here is the debug output. It makes it all the way to ServerHelloDone and then fails shortly thereafter: Is secure renegotiation: false [Raw read]: length = 5 0000: 16 03 03 00 41 ....A [Raw read]: length = 65 0000: 01 00 00 3D 03 03 50 83 1E 0B 56 19 25 65 C8 F2 ...=..P...V.%e.. 0010: AF 02 AD 48 FE E2 92 CF B8 D7 A6 A3 EA C5 FF 5D ...H...........] 0020: 74 0F 1B C1 99 18 00 00 08 00 FF 00 34 00 1B 00 t...........4... 0030: 18 01 00 00 0C 00 0D 00 08 00 06 05 01 04 01 02 ................ 0040: 01 . URT-, READ: Unknown-3.3 Handshake, length = 65 *** ClientHello, Unknown-3.3 RandomCookie: GMT: 1333992971 bytes = { 86, 25, 37, 101, 200, 242, 175, 2, 173, 72, 254, 226, 146, 207, 184, 215, 166, 163, 234, 197, 255, 93, 116, 15, 27, 193, 153, 24 } Session ID: {} Cipher Suites: [TLS_EMPTY_RENEGOTIATION_INFO_SCSV, TLS_DH_anon_WITH_AES_128_CBC_SHA, SSL_DH_anon_WITH_3DES_EDE_CBC_SHA, SSL_DH_anon_WITH_RC4_128_MD5] Compression Methods: { 0 } Unsupported extension signature_algorithms, data: 00:06:05:01:04:01:02:01 *** [read] MD5 and SHA1 hashes: len = 65 0000: 01 00 00 3D 03 03 50 83 1E 0B 56 19 25 65 C8 F2 ...=..P...V.%e.. 0010: AF 02 AD 48 FE E2 92 CF B8 D7 A6 A3 EA C5 FF 5D ...H...........] 0020: 74 0F 1B C1 99 18 00 00 08 00 FF 00 34 00 1B 00 t...........4... 0030: 18 01 00 00 0C 00 0D 00 08 00 06 05 01 04 01 02 ................ 0040: 01 . %% Created: [Session-1, TLS_DH_anon_WITH_AES_128_CBC_SHA] *** ServerHello, TLSv1 RandomCookie: GMT: 1333992972 bytes = { 100, 3, 56, 153, 7, 2, 251, 64, 41, 32, 66, 240, 227, 181, 55, 190, 2, 237, 146, 0, 73, 119, 70, 0, 160, 9, 28, 207 } Session ID: {80, 131, 30, 12, 241, 73, 52, 38, 46, 41, 237, 226, 199, 246, 156, 45, 3, 247, 182, 43, 223, 8, 49, 169, 188, 63, 160, 41, 102, 199, 50, 190} Cipher Suite: TLS_DH_anon_WITH_AES_128_CBC_SHA Compression Method: 0 Extension renegotiation_info, renegotiated_connection: <empty> *** Cipher suite: TLS_DH_anon_WITH_AES_128_CBC_SHA *** Diffie-Hellman ServerKeyExchange DH Modulus: { 233, 230, 66, 89, 157, 53, 95, 55, 201, 127, 253, 53, 103, 18, 11, 142, 37, 201, 205, 67, 233, 39, 179, 169, 103, 15, 190, 197, 216, 144, 20, 25, 34, 210, 195, 179, 173, 36, 128, 9, 55, 153, 134, 157, 30, 132, 106, 171, 73, 250, 176, 173, 38, 210, 206, 106, 34, 33, 157, 71, 11, 206, 125, 119, 125, 74, 33, 251, 233, 194, 112, 181, 127, 96, 112, 2, 243, 206, 248, 57, 54, 148, 207, 69, 238, 54, 136, 193, 26, 140, 86, 171, 18, 122, 61, 175 } DH Base: { 48, 71, 10, 213, 160, 5, 251, 20, 206, 45, 157, 205, 135, 227, 139, 199, 209, 177, 197, 250, 203, 174, 203, 233, 95, 25, 10, 167, 163, 29, 35, 196, 219, 188, 190, 6, 23, 69, 68, 64, 26, 91, 44, 2, 9, 101, 216, 194, 189, 33, 113, 211, 102, 132, 69, 119, 31, 116, 186, 8, 77, 32, 41, 216, 60, 28, 21, 133, 71, 243, 169, 241, 162, 113, 91, 226, 61, 81, 174, 77, 62, 90, 31, 106, 112, 100, 243, 22, 147, 58, 52, 109, 63, 82, 146, 82 } Server DH Public Key: { 8, 60, 59, 13, 224, 110, 32, 168, 116, 139, 246, 146, 15, 12, 216, 107, 82, 182, 140, 80, 193, 237, 159, 189, 87, 34, 18, 197, 181, 252, 26, 27, 94, 160, 188, 162, 30, 29, 165, 165, 68, 152, 11, 204, 251, 187, 14, 233, 239, 103, 134, 168, 181, 173, 206, 151, 197, 128, 65, 239, 233, 191, 29, 196, 93, 80, 217, 55, 81, 240, 101, 31, 119, 98, 188, 211, 52, 146, 168, 127, 127, 66, 63, 111, 198, 134, 70, 213, 31, 162, 146, 25, 178, 79, 56, 116 } Anonymous *** ServerHelloDone [write] MD5 and SHA1 hashes: len = 383 0000: 02 00 00 4D 03 01 50 83 1E 0C 64 03 38 99 07 02 ...M..P...d.8... 0010: FB 40 29 20 42 F0 E3 B5 37 BE 02 ED 92 00 49 77 .@) B...7.....Iw 0020: 46 00 A0 09 1C CF 20 50 83 1E 0C F1 49 34 26 2E F..... P....I4&. 0030: 29 ED E2 C7 F6 9C 2D 03 F7 B6 2B DF 08 31 A9 BC ).....-...+..1.. 0040: 3F A0 29 66 C7 32 BE 00 34 00 00 05 FF 01 00 01 ?.)f.2..4....... 0050: 00 0C 00 01 26 00 60 E9 E6 42 59 9D 35 5F 37 C9 ....&.`..BY.5_7. 0060: 7F FD 35 67 12 0B 8E 25 C9 CD 43 E9 27 B3 A9 67 ..5g...%..C.'..g 0070: 0F BE C5 D8 90 14 19 22 D2 C3 B3 AD 24 80 09 37 ......."....$..7 0080: 99 86 9D 1E 84 6A AB 49 FA B0 AD 26 D2 CE 6A 22 .....j.I...&..j" 0090: 21 9D 47 0B CE 7D 77 7D 4A 21 FB E9 C2 70 B5 7F !.G...w.J!...p.. 00A0: 60 70 02 F3 CE F8 39 36 94 CF 45 EE 36 88 C1 1A `p....96..E.6... 00B0: 8C 56 AB 12 7A 3D AF 00 60 30 47 0A D5 A0 05 FB .V..z=..`0G..... 00C0: 14 CE 2D 9D CD 87 E3 8B C7 D1 B1 C5 FA CB AE CB ..-............. 00D0: E9 5F 19 0A A7 A3 1D 23 C4 DB BC BE 06 17 45 44 ._.....#......ED 00E0: 40 1A 5B 2C 02 09 65 D8 C2 BD 21 71 D3 66 84 45 @.[,..e...!q.f.E 00F0: 77 1F 74 BA 08 4D 20 29 D8 3C 1C 15 85 47 F3 A9 w.t..M ).<...G.. 0100: F1 A2 71 5B E2 3D 51 AE 4D 3E 5A 1F 6A 70 64 F3 ..q[.=Q.M>Z.jpd. 0110: 16 93 3A 34 6D 3F 52 92 52 00 60 08 3C 3B 0D E0 ..:4m?R.R.`.<;.. 0120: 6E 20 A8 74 8B F6 92 0F 0C D8 6B 52 B6 8C 50 C1 n .t......kR..P. 0130: ED 9F BD 57 22 12 C5 B5 FC 1A 1B 5E A0 BC A2 1E ...W"......^.... 0140: 1D A5 A5 44 98 0B CC FB BB 0E E9 EF 67 86 A8 B5 ...D........g... 0150: AD CE 97 C5 80 41 EF E9 BF 1D C4 5D 50 D9 37 51 .....A.....]P.7Q 0160: F0 65 1F 77 62 BC D3 34 92 A8 7F 7F 42 3F 6F C6 .e.wb..4....B?o. 0170: 86 46 D5 1F A2 92 19 B2 4F 38 74 0E 00 00 00 .F......O8t.... URT-, WRITE: TLSv1 Handshake, length = 383 [Raw write]: length = 388 0000: 16 03 01 01 7F 02 00 00 4D 03 01 50 83 1E 0C 64 ........M..P...d 0010: 03 38 99 07 02 FB 40 29 20 42 F0 E3 B5 37 BE 02 .8....@) B...7.. 0020: ED 92 00 49 77 46 00 A0 09 1C CF 20 50 83 1E 0C ...IwF..... P... 0030: F1 49 34 26 2E 29 ED E2 C7 F6 9C 2D 03 F7 B6 2B .I4&.).....-...+ 0040: DF 08 31 A9 BC 3F A0 29 66 C7 32 BE 00 34 00 00 ..1..?.)f.2..4.. 0050: 05 FF 01 00 01 00 0C 00 01 26 00 60 E9 E6 42 59 .........&.`..BY 0060: 9D 35 5F 37 C9 7F FD 35 67 12 0B 8E 25 C9 CD 43 .5_7...5g...%..C 0070: E9 27 B3 A9 67 0F BE C5 D8 90 14 19 22 D2 C3 B3 .'..g......."... 0080: AD 24 80 09 37 99 86 9D 1E 84 6A AB 49 FA B0 AD .$..7.....j.I... 0090: 26 D2 CE 6A 22 21 9D 47 0B CE 7D 77 7D 4A 21 FB &..j"!.G...w.J!. 00A0: E9 C2 70 B5 7F 60 70 02 F3 CE F8 39 36 94 CF 45 ..p..`p....96..E 00B0: EE 36 88 C1 1A 8C 56 AB 12 7A 3D AF 00 60 30 47 .6....V..z=..`0G 00C0: 0A D5 A0 05 FB 14 CE 2D 9D CD 87 E3 8B C7 D1 B1 .......-........ 00D0: C5 FA CB AE CB E9 5F 19 0A A7 A3 1D 23 C4 DB BC ......_.....#... 00E0: BE 06 17 45 44 40 1A 5B 2C 02 09 65 D8 C2 BD 21 ...ED@.[,..e...! 00F0: 71 D3 66 84 45 77 1F 74 BA 08 4D 20 29 D8 3C 1C q.f.Ew.t..M ).<. 0100: 15 85 47 F3 A9 F1 A2 71 5B E2 3D 51 AE 4D 3E 5A ..G....q[.=Q.M>Z 0110: 1F 6A 70 64 F3 16 93 3A 34 6D 3F 52 92 52 00 60 .jpd...:4m?R.R.` 0120: 08 3C 3B 0D E0 6E 20 A8 74 8B F6 92 0F 0C D8 6B .<;..n .t......k 0130: 52 B6 8C 50 C1 ED 9F BD 57 22 12 C5 B5 FC 1A 1B R..P....W"...... 0140: 5E A0 BC A2 1E 1D A5 A5 44 98 0B CC FB BB 0E E9 ^.......D....... 0150: EF 67 86 A8 B5 AD CE 97 C5 80 41 EF E9 BF 1D C4 .g........A..... 0160: 5D 50 D9 37 51 F0 65 1F 77 62 BC D3 34 92 A8 7F ]P.7Q.e.wb..4... 0170: 7F 42 3F 6F C6 86 46 D5 1F A2 92 19 B2 4F 38 74 .B?o..F......O8t 0180: 0E 00 00 00 .... [Raw read]: length = 5 0000: 15 03 01 00 02 ..... [Raw read]: length = 2 0000: 02 00 .. URT-, READ: TLSv1 Alert, length = 2 URT-, RECV TLSv1 ALERT: fatal, close_notify URT-, called closeSocket() URT-, handling exception: javax.net.ssl.SSLException: Received fatal alert: close_notify FYI, this works in iOS 6.0

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• c# deleting whole row in access database

  - by user2978474

  I have question about my problem. Thru manustrip in form1 i have made new form2 when i click on a right option. This form is for deleting data in access database if you pick in combobox ID of row it deletes the whole row wher is ID 4 or somethig else... My combobox is connected on my database. my code: public partial class Form2 : Form { public string myConnectionString = @"Provider=Microsoft.ACE.OLEDB.12.0;Data Source=C:\Users\Bojan\Desktop\Programiranje\School\Novo\Novo\Ure.accdb"; // to je provider za Access 2007 in vec - ce ga ni na lokalni mašini ga je treba namestiti!!! public Form2() { InitializeComponent(); } private void Form2_Load(object sender, EventArgs e) { // TODO: This line of code loads data into the 'dataSet1.Ure' table. You can move, or remove it, as needed. this.ureTableAdapter.Fill(this.dataSet1.Ure); } private void Brisanje_Click(object sender, EventArgs e) { OleDbConnection myConnection = null; myConnection = new OleDbConnection(); // kreiranje konekcije myConnection.ConnectionString = myConnectionString; myConnection.Open(); OleDbCommand cmd = myConnection.CreateCommand(); cmd.Connection = myConnection; cmd.CommandText = "DELETE FROM Ure WHERE (ID) = '"+Izbor.SelectedValue+"'"; cmd.ExecuteNonQuery(); cmd.Prepare(); myConnection.Close(); } } Thanks for your help

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• How to get the second sub element of every element in a list in R

  - by PaulHurleyuk

  I know I've come across this problem before, but I'm having a bit of a mental block at the moment. and as I can't find it on SO, I'll post it here so I can find it next time. I have a dataframe that contains a field representing an ID label. This label has two parts, an alpha prefix and a numeric suffix. I want to split it apart and create two new fields with these values in. structure(list(lab = c("N00", "N01", "N02", "B00", "B01", "B02", "Z21", "BA01", "NA03")), .Names = "lab", row.names = c(NA, -9L ), class = "data.frame") df$pre<-strsplit(df$lab, "[0-9]+") df$suf<-strsplit(df$lab, "[A-Z]+") Which gives lab pre suf 1 N00 N , 00 2 N01 N , 01 3 N02 N , 02 4 B00 B , 00 5 B01 B , 01 6 B02 B , 02 7 Z21 Z , 21 8 BA01 BA , 01 9 NA03 NA , 03 So, the first strsplit works fine, but the second gives a list, each having two elements, an empty string and the result I want, and stuffs them both into the dataframe column. How can I select the second sub-element from each element of the list ? (or, is there a better way to do this) Thanks Paul.

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• Invoking a method overloaded where all arguments implement the same interface

  - by double07

  Hello, My starting point is the following: - I have a method, transform, which I overloaded to behave differently depending on the type of arguments that are passed in (see transform(A a1, A a2) and transform(A a1, B b) in my example below) - All these arguments implement the same interface, X I would like to apply that transform method on various objects all implementing the X interface. What I came up with was to implement transform(X x1, X x2), which checks for the instance of each object before applying the relevant variant of my transform. Though it works, the code seems ugly and I am also concerned of the performance overhead for evaluating these various instanceof and casting. Is that transform the best I can do in Java or is there a more elegant and/or efficient way of achieving the same behavior? Below is a trivial, working example printing out BA. I am looking for examples on how to improve that code. In my real code, I have naturally more implementations of 'transform' and none are trivial like below. public class A implements X { } public class B implements X { } interface X { } public A transform(A a1, A a2) { System.out.print("A"); return a2; } public A transform(A a1, B b) { System.out.print("B"); return a1; } // Isn't there something better than the code below??? public X transform(X x1, X x2) { if ((x1 instanceof A) && (x2 instanceof A)) { return transform((A) x1, (A) x2); } else if ((x1 instanceof A) && (x2 instanceof B)) { return transform((A) x1, (B) x2); } else { throw new RuntimeException("Transform not implemented for " + x1.getClass() + "," + x2.getClass()); } } @Test public void trivial() { X x1 = new A(); X x2 = new B(); X result = transform(x1, x2); transform(x1, result); }

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• Why does Python sometimes upgrade a string to unicode and sometimes not?

  - by samtregar

  I'm confused. Consider this code working the way I expect: >>> foo = u'Émilie and Juañ are turncoats.' >>> bar = "foo is %s" % foo >>> bar u'foo is \xc3\x89milie and Jua\xc3\xb1 are turncoats.' And this code not at all working the way I expect: >>> try: ... raise Exception(foo) ... except Exception as e: ... foo2 = e ... >>> bar = "foo2 is %s" % foo2 ------------------------------------------------------------ Traceback (most recent call last): File "<ipython console>", line 1, in <module> UnicodeEncodeError: 'ascii' codec can't encode characters in position 0-1: ordinal not in range(128) Can someone explain what's going on here? Why does it matter whether the unicode data is in a plain unicode string or stored in an Exception object? And why does this fix it: >>> bar = u"foo2 is %s" % foo2 >>> bar u'foo2 is \xc3\x89milie and Jua\xc3\xb1 are turncoats.' I am quite confused! Thanks for the help! UPDATE: My coding buddy Randall has added to my confusion in an attempt to help me! Send in the reinforcements to explain how this is supposed to make sense: >>> class A: ... def __str__(self): return "string" ... def __unicode__(self): return "unicode" ... >>> "%s %s" % (u'niño', A()) u'ni\xc3\xb1o unicode' >>> "%s %s" % (A(), u'niño') u'string ni\xc3\xb1o' Note that the order of the arguments here determines which method is called!

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• Windows Phone - failing to get a string from a website with login information

  - by jumantyn

  I am new to accessing web services with Windows Phone 7/8. I'm using a WebClient to get a string from a php-website. The site returns a JSON string but at the moment I'm just trying to put it into a TextBox as a normal string just to test if the connection works. The php-page requires an authentication and I think that's where my code is failing. Here's my code: WebClient client = new WebClient(); client.Credentials = new NetworkCredential("myUsername", "myPassword"); client.DownloadStringCompleted += new DownloadStringCompletedEventHandler(client_DownloadStringCompleted); client.DownloadStringAsync(new Uri("https://www.mywebsite.com/ba/php/jsonstuff.php")); void client_DownloadStringCompleted(object sender, DownloadStringCompletedEventArgs e) { try { string data = e.Result; this.jsonText.Text = data; } catch (Exception ex) { System.Diagnostics.Debug.WriteLine(ex.Message); } } This returns first a WebException and then a TargetInvocationException. If I replace the Uri with for example "http://www.google.com/index.html" the jsonText TextBox gets filled with html text from Google (oddly enough, this also works even when the WebClient credentials are still set). So is the problem in the setting of the credentials? I couldn't find any good results when searching for guides on how to access php-pages with credentials, only without them. Then I found a short mention somewhere to use the WebClient.Credentials property. But should it work some other way? Update: here's what I can get out of the WebException (sorry for the bad formatting): System.Net.WebException: The remote server returned an error: NotFound. ---System.Net.WebException: The remote server returned an error: NotFound. at System.Net.Browser.ClientHttpWebRequest.InternalEndGetResponse(IAsyncResult asyncResult) at System.Net.Browser.ClientHttpWebRequest.<c_DisplayClasse.b_d(Object sendState) at System.Net.Browser.AsyncHelper.<c_DisplayClass1.b_0(Object sendState) --- End of inner exception stack trace --- at System.Net.Browser.AsyncHelper.BeginOnUI(SendOrPostCallback beginMethod, Object state) at System.Net.Browser.ClientHttpWebRequest.EndGetResponse(IAsyncResult asyncResult) at System.Net.WebClient.GetWebResponse(WebRequest request, IAsyncResult result) at System.Net.WebClient.DownloadBitsResponseCallback(IAsyncResult result)

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• Java - Counting how many characters show up in another string

  - by Vu Châu

  I am comparing two strings, in Java, to see how many characters from the first string show up in the second string. The following is some expectations: matchingChars("AC", "BA") ? 1 matchingChars("ABBA", "B") ? 2 matchingChars("B", "ABBA") ? 1 My approach is as follows: public int matchingChars(String str1, String str2) { int count = 0; for (int a = 0; a < str1.length(); a++) { for (int b = 0; b < str2.length(); b++) { char str1Char = str1.charAt(a); char str2Char = str2.charAt(b); if (str1Char == str2Char) { count++; str1 = str1.replace(str1Char, '0'); } } } return count; } I know my approach is not the best, but I think it should do it. However, for matchingChars("ABBA", "B") ? 2 My code yields "1" instead of "2". Does anyone have any suggestion or advice? Thank you very much.

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• Does Entity Framework saves related classes automatically?

  - by herbatnic

  Let's assume that we have such classes public class A{ string someField { get; set; } public virtual B B {get; set; } } public class B { int someIntField {get; set; } [ForeignKey("Id")] [Required] public virtual A A { get; set; } } In code I create new instances for both of them and making relation like: A a = new A () { someField = "abcd"}; B b = new B () { someIntField = 42 }; A.B = b; B.A = a; Should I using DBContext to save both classes like that: using (var db = new myDbContext()) { myDbContext.As.Add(A); myDbContext.Bs.Add(B); myDBContext.SaveChanges(); } Or saving it like that: using (var db = new myDbContext()) { myDbContext.As.Add(A); myDbContext.SaveChanges(); } is enough to store related objects into database?

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• Moving MVC2 Helpers to MVC3 razor view engine

  - by Dai Bok

  Hi, In my MVC 2 site, I have an html helper, that I use to add javascripts for my pages. In my master page I have the main javascripts I want to include, and then in the aspx pages, I include page specific javascripts. So for example, my Site.Master has something like this: .... <head> <%=html.renderScripts() %> </head> ... //core scripts for main page <%html.AddScript("/scripts/jquery.js") %> <%html.AddScript("/scripts/myLib.js") %> .... Then in the child aspx page, I may also want to include other scripts. ... //the page specific script I want to use <% html.AddScript("/scripts/register.aspx.js") %> ... So when the full page gets rendered the javascript files are all collected and rendered in the head by sitemaster placeholder function RenderScripts. This works fine. Now with MVC 3 and razor view engine, they layout pages behave differently, because now my page level javascripts are not rendered/included. Now all I see the LayoutMaster contents. How do I get the solution wo workwith MVC 3 and the razor view engine. (The helper has already been re-written to return a HTMLString ;-)) For reference: my MasterLayout looks like this: ... ... <head> @{ Html.AddJavaScript("/Scripts/jQuery.js"); Html.AddJavaScript("/Scripts/myLib.js"); } //Render scripts @html.RenderScripts() </head> .... and the child page looks like this: @{ Layout = "~/Views/Shared/MasterLayout.cshtml"; ViewBag.Title = "Child Page"; Html.AddJavaScript("/Scripts/register.aspx.js"); } .... <div>some html </div> Thanks for your help. Edit = Just to explain, if this question is not clear enough. When producing a "page" I collect all the javascript files the designers want to use, by using the html.addJavascript("filename.js") and store these in a dictionary - (1) stops people adding duplicate js files - then finally when the page is ready to render, I write out all the javascript files neatly in the header. (2) - this helper helps keep JS in one place, and prevents designers from adding javascript files all over the place. This used to work fine with Master/SiteMaster Pages in mvc 2. but how can I achieve this with razor?

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• Installing gnome on Linode with Ubuntu 9.10 x64 - remote VNC/RDP

  - by Kieran Benton

  Hi, I'm a self confessed Linux newbie, having lived and worked mostly within the Windows world for most of my life. I'm making the effort to try moving my virtual host from a Windows box to a Linode instance to try and better learn Linux, and one of the uses I occasionally have with my current Windows VPS is to RDP into it and browse the internet. I'm aware that this is probably not best practice (from either performance or security), and most of the time I will be learning from the shell, but I do occasionally need to boot into a GUI. Because of this, I'd like the ability within my Ubuntu installation on Linode to start/stop Windows X and Gnome at will after SSHing in (startx? gdm?), so I've tried: apt-get install ubuntu-desktop Reboot startx But I've got an error that no amount of googling has helped me with so far, which I'm assuming is something to do with the fact the box is headless and X needs some more configuration that is beyond me at the moment: root@local:~# startx hostname: Unknown host xauth: creating new authority file /root/.Xauthority xauth: creating new authority file /root/.Xauthority xauth: (argv):1: bad display name "local.kieranbenton.com:0" in "list" command xauth: (stdin):1: bad display name "local.kieranbenton.com:0" in "add" command X.Org X Server 1.6.4 Release Date: 2009-9-27 X Protocol Version 11, Revision 0 Build Operating System: Linux 2.6.24-23-server x86_64 Ubuntu Current Operating System: Linux local.kieranbenton.com 2.6.31.5-x86_64-linode9 #1 SMP Mon Oct 26 19:35:25 UTC 2009 x86_64 Kernel command line: root=/dev/xvda xencons=tty console=tty1 console=hvc0 nosep nodevfs ramdisk_size=32768 ro Build Date: 26 October 2009 05:19:56PM xorg-server 2:1.6.4-2ubuntu4 (buildd@) Before reporting problems, check http://wiki.x.org to make sure that you have the latest version. Markers: (--) probed, (**) from config file, (==) default setting, (++) from command line, (!!) notice, (II) informational, (WW) warning, (EE) error, (NI) not implemented, (??) unknown. (==) Log file: "/var/log/Xorg.0.log", Time: Wed Dec 2 15:50:23 2009 Primary device is not PCI (==) Using default built-in configuration (21 lines) (EE) open /dev/fb0: No such file or directory (EE) No devices detected. Fatal server error: no screens found Please consult the The X.Org Foundation support at http://wiki.x.org for help. Please also check the log file at "/var/log/Xorg.0.log" for additional information. ddxSigGiveUp: Closing log Can anyone give me any pointers as to how to go from here and get VNC/RDP setup? (RDP would be preferred?). Thanks.

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• Installing gnome on Linode with Ubuntu 9.10 x64 - remote VNC/RDP

  - by Kieran Benton

  Hi, I'm a self confessed Linux newbie, having lived and worked mostly within the Windows world for most of my life. I'm making the effort to try moving my virtual host from a Windows box to a Linode instance to try and better learn Linux, and one of the uses I occasionally have with my current Windows VPS is to RDP into it and browse the internet. I'm aware that this is probably not best practice (from either performance or security), and most of the time I will be learning from the shell, but I do occasionally need to boot into a GUI. Because of this, I'd like the ability within my Ubuntu installation on Linode to start/stop Windows X and Gnome at will after SSHing in (startx? gdm?), so I've tried: apt-get install ubuntu-desktop Reboot startx But I've got an error that no amount of googling has helped me with so far, which I'm assuming is something to do with the fact the box is headless and X needs some more configuration that is beyond me at the moment: root@local:~# startx hostname: Unknown host xauth: creating new authority file /root/.Xauthority xauth: creating new authority file /root/.Xauthority xauth: (argv):1: bad display name "local.kieranbenton.com:0" in "list" command xauth: (stdin):1: bad display name "local.kieranbenton.com:0" in "add" command X.Org X Server 1.6.4 Release Date: 2009-9-27 X Protocol Version 11, Revision 0 Build Operating System: Linux 2.6.24-23-server x86_64 Ubuntu Current Operating System: Linux local.kieranbenton.com 2.6.31.5-x86_64-linode9 #1 SMP Mon Oct 26 19:35:25 UTC 2009 x86_64 Kernel command line: root=/dev/xvda xencons=tty console=tty1 console=hvc0 nosep nodevfs ramdisk_size=32768 ro Build Date: 26 October 2009 05:19:56PM xorg-server 2:1.6.4-2ubuntu4 (buildd@) Before reporting problems, check http://wiki.x.org to make sure that you have the latest version. Markers: (--) probed, (**) from config file, (==) default setting, (++) from command line, (!!) notice, (II) informational, (WW) warning, (EE) error, (NI) not implemented, (??) unknown. (==) Log file: "/var/log/Xorg.0.log", Time: Wed Dec 2 15:50:23 2009 Primary device is not PCI (==) Using default built-in configuration (21 lines) (EE) open /dev/fb0: No such file or directory (EE) No devices detected. Fatal server error: no screens found Please consult the The X.Org Foundation support at http://wiki.x.org for help. Please also check the log file at "/var/log/Xorg.0.log" for additional information. ddxSigGiveUp: Closing log Can anyone give me any pointers as to how to go from here and get VNC/RDP setup? (RDP would be preferred?). Thanks.

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• Trouble connecting a Ubuntu system to IPv6 tunnel over NAT

  - by John Millikin

  I'm trying to set up an IPv6 tunnel, via Hurricane Electric's tunnel-broker service. I've configured my system using their example commands: # $ipv4a = tunnel server's IPv4 IP # $ipv4b = user's IPv4 IP # $ipv6a = tunnel server's side of point-to-point /64 allocation # $ipv6b = user's side of point-to-point /64 allocation ip tunnel add he-ipv6 mode sit remote $ipv4a local $ipv4b ttl 255 ip link set he-ipv6 up ip addr add $ipv6b dev he-ipv6 ip route add ::/0 dev he-ipv6 And have configured my desktop to be in my NAT router's DMZ. The router is running Tomato firmware. But I can't ping any IPv6 services: $ ping6 -I he-ipv6 '2001:470:1f04:454::1' PING 2001:470:1f04:454::1(2001:470:1f04:454::1) from 2001:470:1f04:454::2 he-ipv6: 56 data bytes From 2001:470:1f04:454::2 icmp_seq=1 Destination unreachable: Address unreachable From 2001:470:1f04:454::2 icmp_seq=2 Destination unreachable: Address unreachable I can ping my local address: $ ping6 -I he-ipv6 '2001:470:1f04:454::2' PING 2001:470:1f04:454::2(2001:470:1f04:454::2) from 2001:470:1f04:454::2 he-ipv6: 56 data bytes 64 bytes from 2001:470:1f04:454::2: icmp_seq=1 ttl=64 time=0.037 ms 64 bytes from 2001:470:1f04:454::2: icmp_seq=2 ttl=64 time=0.039 ms I don't know much about routing, but results I found online suggested the output of ip -6 route and ip addr could be useful: $ ip -6 route 2001:470:1f04:454::/64 via :: dev he-ipv6 proto kernel metric 256 mtu 1480 advmss 1420 hoplimit 4294967295 fe80::/64 dev virbr0 proto kernel metric 256 mtu 1500 advmss 1440 hoplimit 4294967295 fe80::/64 dev eth1 proto kernel metric 256 mtu 1500 advmss 1440 hoplimit 4294967295 fe80::/64 via :: dev he-ipv6 proto kernel metric 256 mtu 1480 advmss 1420 hoplimit 4294967295 default dev he-ipv6 metric 1024 mtu 1480 advmss 1420 hoplimit 4294967295 $ ip addr 1: lo: <LOOPBACK,UP,LOWER_UP> mtu 16436 qdisc noqueue state UNKNOWN link/loopback 00:00:00:00:00:00 brd 00:00:00:00:00:00 inet 127.0.0.1/8 scope host lo inet6 ::1/128 scope host valid_lft forever preferred_lft forever 2: eth1: <BROADCAST,MULTICAST,UP,LOWER_UP> mtu 1500 qdisc pfifo_fast state UP qlen 100 link/ether 00:1c:c0:a1:98:b2 brd ff:ff:ff:ff:ff:ff inet 192.168.1.10/24 brd 192.168.1.255 scope global eth1 inet6 fe80::21c:c0ff:fea1:98b2/64 scope link valid_lft forever preferred_lft forever 3: virbr0: <BROADCAST,MULTICAST,UP,LOWER_UP> mtu 1500 qdisc noqueue state UNKNOWN link/ether 36:4c:33:ab:0d:c6 brd ff:ff:ff:ff:ff:ff inet 192.168.122.1/24 brd 192.168.122.255 scope global virbr0 inet6 fe80::344c:33ff:feab:dc6/64 scope link valid_lft forever preferred_lft forever 4: vboxnet0: <BROADCAST,MULTICAST> mtu 1500 qdisc noop state DOWN qlen 1000 link/ether 00:76:62:6e:65:74 brd ff:ff:ff:ff:ff:ff 5: pan0: <BROADCAST,MULTICAST> mtu 1500 qdisc noop state DOWN link/ether 7e:29:5e:7c:ba:93 brd ff:ff:ff:ff:ff:ff 6: sit0: <NOARP> mtu 1480 qdisc noop state DOWN link/sit 0.0.0.0 brd 0.0.0.0 7: he-ipv6@NONE: <POINTOPOINT,NOARP,UP,LOWER_UP> mtu 1480 qdisc noqueue state UNKNOWN link/sit 24.130.225.239 peer 72.52.104.74 inet6 2001:470:1f04:454::2/64 scope global valid_lft forever preferred_lft forever inet6 fe80::1882:e1ef/128 scope link valid_lft forever preferred_lft forever

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• Installing drivers for switchable graphics

  - by Anonymous

  I recently bought a laptop that came with Windows 7 64-bit installed. I have some older (16-bit and 32-bit) software that doesn't work with 64-bit Windows, but works just fine with 32-bit. Since I also wanted to get rid of all of the pre-installed spam, I decided to wipe the hard drive and install a fresh copy of Windows 7 32-bit. I can't get the graphics cards working. This laptop uses switchable graphics, an Intel card and a Radeon card. I first tried installing this driver from Intel, which works for the Intel card. Of course, the Radeon card doesn't work with this driver and I need it for some of the newer games I have. I also tried this driver. Windows's device manager will recognize the Radeon card, but it will still use the Intel card. Also, even though that package says it contains the Intel driver, the Intel card still isn't properly recognized by Windows (leaving me with a nasty 800x600 resolution). On top of that, the Catalyst Control Center won't open (saying "The Catalyst Control Center is not supported by the driver version of your enabled graphics adapter") I tried installing HP's driver then installing Intel's driver on top of it. Device manager will then recognize both graphics cards properly. However, the laptop still uses the Intel card. The CCC still won't start (saying the same thing as before) and I can't find any of 'switching' graphics cards. Before formatting, I could right-click the desktop and click "Configure Switchable Graphics" This option hasn't been in the context menu regardless of what driver(s) I've installed. After some research, I found out that this menu entry runs the command "cli.exe Start PowerXpressHybrid" I've tried manually running this command, but I get the same unsupported message from CCC. So, does anyone know how I can get this working? I would like to be able to switch between the Intel and Radeon. But, if there's some way to disable the Intel and use only the Radeon, that would be fine I dual-boot with Linux (framebuffer uses the Intel, haven't even tried getting X set up yet) Here's the output of lspci # lspci -v | grep VGA 00:02.0 VGA compatible controller: Intel Corporation 2nd Generation Core Processor Family Integrated Graphics Controller (rev 09) (prog-if 00 [VGA controller]) 01:00.0 VGA compatible controller: ATI Technologies Inc NI Seymour [AMD Radeon HD 6470M] (prog-if 00 [VGA controller]) The laptop is a HP Pavilion g6t-1d00. HP doesn't support installing anything but Windows 7 64-bit, so calling tech support isn't an option. Thanks for any help UPDATE: I finally got it working. After a fresh install of Windows 7, I installed the HP driver (the one linked above). Then, there's an optional Windows update I installed (don't remember the exact name, but it'll stick out). After that, graphics switching works just like it's supposed to. Moab, thanks anyways for your help

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