Cannot overload function
- by anio
So I've got a templatized class and I want to overload the behavior of a function when I have specific type, say char. For all other types, let them do their own thing. However, c++ won't let me overload the function.
Why can't I overload this function? I really really do not want to do template specialization, because then I've got duplicate the entire class.
Here is a toy example demonstrating the problem: http://codepad.org/eTgLG932
The same code posted here for your reading pleasure:
#include <iostream>
#include <cstdlib>
#include <string>
struct Bar
{
std::string blah() { return "blah"; }
};
template <typename T>
struct Foo
{
public:
std::string doX()
{
return m_getY(my_t);
}
private:
std::string m_getY(char* p_msg)
{
return std::string(p_msg);
}
std::string m_getY(T* p_msg)
{
return p_msg->blah();
}
T my_t;
};
int main(int, char**)
{
Foo<char> x;
Foo<Bar> y;
std::cout << "x " << x.doX() << std::endl;
return EXIT_SUCCESS;
}
Thank you everyone for your suggestions. Two valid solutions have been presented. I can either specialize the doX method, or specialize m_getY() method.
At the end of the day I prefer to keep my specializations private rather than public so I'm accepting Krill's answer.
