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  • Game Center alternatives for non-iOS development

    - by Eat at Joes
    I have completed a game for iOS which integrates GameKit. I am happy with Game Center however my game also has an HTML5 web version and will soo have an Android version. My question is what alternatives do I have for non-iOS platforms but primarily for Android and to a lesser extent a Javascript/Web SDK. I looked at Openfeint a year ago and it seemed to be a good solution back then but am not sure if this is still the case? Note, I have no plans to replace what I already have in my iOS game and I understand the leader boards, users, and achievements won't be shared out of Game Center.

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  • How to hire a web-programmer : for non-programmer

    - by 0Complex
    I am a non-programmer that has used the services of : freelancer, odesk, etc I've tried asking for what i need but, I can't find anyone who can show me any type of example similar to what I request in the specs for the web-programming. They have front ends and back ends, but they don't fulfill true "live" website requirements. "live" as to be ready to support traffic, keys in hand, can be updated constantly by me, ... How do I figure how to evaluate a programmer ? How do I bid the appropriate price for the services ?

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  • Google relaxé par la CJUE dans l'affaire l'opposant à Louis Vuitton, la notion de non-responsabilité

    Google relaxé par la CJUE dans l'affaire l'opposant à Louis Vuitton, la notion de non-responsabilité de l'hébergeur fait débat La Cour de Justice de l'Union européenne vient de rendre son verdict dans l'affaire opposant Google à Louis Vuitton (malletier de luxe, filiale du très puissant groupe LVMI). Dans ce dossier particulièrement compliqué, la législation européenne en vigueur a du être examinée sous toutes les coutures afin de pouvoir statuer. Deux points ont demandé la plus grande attention : d'abord « l'emploi de mots clés correspondant à des marques d'autrui dans le cadre d'un service de référencement sur internet », puis « la responsabilité du prestataire du service de référencement ». En rép...

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  • Blender to Collada to Assimp - Rigid (Non-skinned) Animation

    - by gareththegeek
    I am trying to get simple animations to work, exporting from Blender and importing into my application. My first attempt was as follows: Open Blender at factory settings. Select the default cube and insert a location keyframe. Select another frame and move the cube. Insert a second location keyframe. Export to Collada. When I open the Collada file using assimp it contains zero animations, even though in Blender the cube animates correctly. On my next attempt, I inserted a bone armature with a single bone, made it the parent of the cube, and animated the bone instead. Again the animation worked correctly in Blender. Assimp now lists one animation but both key frames have the position [0, 0, 0] Does anyone have any suggestions as to how I can get animated (non-skinned) meshes from Blender into Assimp? My ultimate goal here is to export animated meshes from Blender, process them offline into my own model format, and load them into my SharpDX based graphics engine..

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  • django 1.1 beta issue

    - by ha22109
    Hello all, I m using django 1.1 beta.I m facing porblem in case of list_editable.First it was throughing exception saying need ordering in case of list_editable" then i added ordering in model but know it is giving me error.The code is working fine with django1.1 final. here is my code model.py class User(models.Model): advertiser = models.ForeignKey(WapUser,primary_key=True) status = models.CharField(max_length=20,choices=ADVERTISER_INVITE_STATUS,default='invited') tos_version = models.CharField(max_length=5) contact_email = models.EmailField(max_length=80) contact_phone = models.CharField(max_length=15) contact_mobile = models.CharField(max_length=15) contact_person = models.CharField(max_length=80) feedback=models.BooleanField(choices=boolean_choices,default=0) def __unicode__(self): return self.user.login class Meta: db_table = u'roi_advertiser_info' managed=False ordering=['feedback',] admin.py class UserAdmin(ReadOnlyAdminFields, admin.ModelAdmin): list_per_page = 15 fields = ['advertiser','contact_email','contact_phone','contact_mobile','contact_person'] list_display = ['advertiser','contact_email','contact_phone','contact_mobile','contact_person','status','feedback'] list_editable=['feedback'] readonly = ('advertiser',) search_fields = ['advertiser__login_id'] radio_fields={'approve_auto': admin.HORIZONTAL} list_filter=['status','feedback'] admin.site.register(User,UserADmin)

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  • Non-zero exit status for clean exit

    - by trinithis
    Is it acceptable to return a non-zero exit code if the program in question ran properly? For example, say I have a simple program that (only) does the following: Program takes N arguments. It returns an exit code of min(N, 255). Note that any N is valid for the program. A more realistic program might return different codes for successfully ran programs that signify different things. Should these programs instead write this information to a stream instead, such as to stdout?

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  • How to find Sub-trees in non-binary tree

    - by kenny
    I have a non-binary tree. I want to find all "sub-trees" that are connected to root. Sub-tree is a a link group of tree nodes. every group is colored in it's own color. What would be be the best approach? Run recursion down and up for every node? The data structure of every treenode is a list of children, list of parents. (the type of children and parents are treenodes) Clarification: Group defined if there is a kind of "closure" between nodes where root itself is not part of the closure. As you can see from the graph you can't travel from pink to other nodes (you CAN NOT use root). From brown node you can travel to it's child so this form another group. Finally you can travel from any cyan node to other cyan nodes so the form another group

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  • list editabale error

    - by ha22109
    Hello all, I m using django 1.1 beta.I m facing porblem in case of list_editable.First it was throughing exception saying need ordering in case of list_editable" then i added ordering in model but know it is giving me error.The code is working fine with django1.1 final. here is my code model.py class User(models.Model): advertiser = models.ForeignKey(WapUser,primary_key=True) status = models.CharField(max_length=20,choices=ADVERTISER_INVITE_STATUS,default='invited') tos_version = models.CharField(max_length=5) contact_email = models.EmailField(max_length=80) contact_phone = models.CharField(max_length=15) contact_mobile = models.CharField(max_length=15) contact_person = models.CharField(max_length=80) feedback=models.BooleanField(choices=boolean_choices,default=0) def __unicode__(self): return self.user.login class Meta: db_table = u'roi_advertiser_info' managed=False ordering=['feedback',] admin.py class UserAdmin(ReadOnlyAdminFields, admin.ModelAdmin): list_per_page = 15 fields = ['advertiser','contact_email','contact_phone','contact_mobile','contact_person'] list_display = ['advertiser','contact_email','contact_phone','contact_mobile','contact_person','status','feedback'] list_editable=['feedback'] readonly = ('advertiser',) search_fields = ['advertiser__login_id'] radio_fields={'approve_auto': admin.HORIZONTAL} list_filter=['status','feedback'] admin.site.register(User,UserADmin)

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  • Terminal will not accept password / terminale non accetta password

    - by elvizz67
    Translation, by Google Translate: I just installed lxde Lubuntu errrato and a terminal command I locked the package management and updates, after erasing software from sources I typed the wrong command sudo apt-get upgrade pero'il terminal asks me the password and the keyboard is not me accept any command. What should I do to unlock? Original text: Ho appena installato lubuntu lxde e per una errrato comando il terminale mi ha bloccato la gestione pacchetti e aggiornamenti, dopo avere cancellato dalle fonti software il comando sbagliato ho digitato sudo apt-get upgrade pero'il terminale mi chiede la password e la tastiera non mi accetta nessun comando. cosa devo fare per sbloccare ?

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  • set proxy for vpn server on ubuntu server 12.4

    - by Morteza Soltanabadiyan
    I have a vpn server with HTTPS, L2TP , OPENVPN , PPTP. i want to set proxy in the server so all connection that comes from vpn clients use the proxy that i set in my server. I made a bash script file for it , but proxy not working. gsettings set org.gnome.system.proxy mode 'manual' gsettings set org.gnome.system.proxy.http enabled true gsettings set org.gnome.system.proxy.http host 'cproxy.anadolu.edu.tr' gsettings set org.gnome.system.proxy.http port 8080 gsettings set org.gnome.system.proxy.http authentication-user 'admin' gsettings set org.gnome.system.proxy.http authentication-password 'admin' gsettings set org.gnome.system.proxy use-same-proxy true export http_proxy=http://admin:[email protected]:8080 export https_proxy=http://admin:[email protected]:8080 export HTTP_PROXY=http://admin:[email protected]:8080 export HTTPS_PROXY=http://admin:[email protected]:8080 Now , I don't know what to do to make a global proxy for server and all vpn clients use it automatically.

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  • redirect non-www to www while preserving protocol

    - by Waleed Hamra
    I am aware of the fact that there are tons of questions in this section and in server fault dealing with redirections from non-www to www URLs. But I couldn't find one dealing with this issue while preserving protocol. I am no mod-rewrite expert, and my code is just copy/pasted... here's what i have: RewriteCond %{HTTP_HOST} ^domain.tld$ [NC] RewriteRule ^(.*)$ http://www.domain.tld$1 [R=301,L] So now http://domain.tld and https://domain.tld are forwarded to http://domain.tld How do i make it so that https stays on https while http stays on http?

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  • Django: Overriding the save() method: how do I call the delete() method of a child class

    - by Patti
    The setup = I have this class, Transcript: class Transcript(models.Model): body = models.TextField('Body') doPagination = models.BooleanField('Paginate') numPages = models.PositiveIntegerField('Number of Pages') and this class, TranscriptPages(models.Model): class TranscriptPages(models.Model): transcript = models.ForeignKey(Transcript) order = models.PositiveIntegerField('Order') content = models.TextField('Page Content', null=True, blank=True) The Admin behavior I’m trying to create is to let a user populate Transcript.body with the entire contents of a long document and, if they set Transcript.doPagination = True and save the Transcript admin, I will automatically split the body into n Transcript pages. In the admin, TranscriptPages is a StackedInline of the Transcript Admin. To do this I’m overridding Transcript’s save method: def save(self): if self.doPagination: #do stuff super(Transcript, self).save() else: super(Transcript, self).save() The problem = When Transcript.doPagination is True, I want to manually delete all of the TranscriptPages that reference this Transcript so I can then create them again from scratch. So, I thought this would work: #do stuff TranscriptPages.objects.filter(transcript__id=self.id).delete() super(Transcript, self).save() but when I try I get this error: Exception Type: ValidationError Exception Value: [u'Select a valid choice. That choice is not one of the available choices.'] ... and this is the last thing in the stack trace before the exception is raised: .../django/forms/models.py in save_existing_objects pk_value = form.fields[pk_name].clean(raw_pk_value) Other attempts to fix: t = self.transcriptpages_set.all().delete() (where self = Transcript from the save() method) looping over t (above) and deleting each item individually making a post_save signal on TranscriptPages that calls the delete method Any ideas? How does the Admin do it? UPDATE: Every once in a while as I'm playing around with the code I can get a different error (below), but then it just goes away and I can't replicate it again... until the next random time. Exception Type: MultiValueDictKeyError Exception Value: "Key 'transcriptpages_set-0-id' not found in " Exception Location: .../django/utils/datastructures.py in getitem, line 203 and the last lines from the trace: .../django/forms/models.py in _construct_form form = super(BaseInlineFormSet, self)._construct_form(i, **kwargs) .../django/utils/datastructures.py in getitem pk = self.data[pk_key]

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  • What Is StreamInsight? A Primer for Non-Programmers

    - by Roman Schindlauer
    Are you trying to figure out whether StreamInsight might be something you could use, but you’re having trouble sifting through all the programming jargon that’s used to describe it? StreamInsight is, ultimately, a set of programming tools, and at some point it takes a programmer to implement a StreamInsight solution. But it really should be possible to get a handle on what StreamInsight is all about even if you’re not a programmer yourself. A new article published in the TechNet Wiki may be able to help: StreamInsight for Non-Programmers. It gives an overview of the technology, but it leaves out the C# references and relates StreamInsight to more familiar SQL databases and queries. Check it out. When you’re done there and are ready to dig a little deeper, take a look at Get Started with StreamInsight 2.1. That article should help you navigate through the StreamInsight official documentation and other resources. And, as always, you can post questions or comments here or on the TechNet Wiki. Regards, The StreamInsight Team

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  • Uploading a non-finished website

    - by Daniel
    I have a pretty basic question. I developed a neet little website wich I'm ready to upload, but still needs a bit of work. The designer needs the html to do his work so the website needs to be uploaded. Besides that, I have to correct a couple details, do the friendly-urls, etc. What's the best way to set up the webpage in the definitive hosting with the defintive domain, blocking it to any unknown users and without affecting affecting SEO and those kind of things. If I were to just upload it, the non-definitive website might be crawled by a SE-bot. Thanks!

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  • What Is StreamInsight? A Primer for Non-Programmers

    - by Roman Schindlauer
    Are you trying to figure out whether StreamInsight might be something you could use, but you’re having trouble sifting through all the programming jargon that’s used to describe it? StreamInsight is, ultimately, a set of programming tools, and at some point it takes a programmer to implement a StreamInsight solution. But it really should be possible to get a handle on what StreamInsight is all about even if you’re not a programmer yourself. A new article published in the TechNet Wiki may be able to help: StreamInsight for Non-Programmers. It gives an overview of the technology, but it leaves out the C# references and relates StreamInsight to more familiar SQL databases and queries. Check it out. When you’re done there and are ready to dig a little deeper, take a look at Get Started with StreamInsight 2.1. That article should help you navigate through the StreamInsight official documentation and other resources. And, as always, you can post questions or comments here or on the TechNet Wiki. Regards, The StreamInsight Team

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  • Carrer path as Java developer for non Btech or BCA background graduate [closed]

    - by Piyush Jolly
    My name is Piyush and I'm a graduate in Bsc. multimedia. Now I'm planing to learn JAVA and take it as my carrier and there are few things I'm really worried about:- 1)Does the industry accepts graduates from Non-it background. 2)Because my course was all about 3D Animation nothing like software programing was taught to us and I have been doing programing in c from long time just because i liked it so now i want to purse my carrier as programmer. 3)From where should I learn, which Institute should I refer to who teaches the Java from the basic. 4)What kind of jobs I can expect after the completion of the course. I'm from Delhi. Any help will be much appreciated. Regards Piyush Jolly

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  • Algorithm for perfect non-binary graph layout

    - by mariki
    I have a complex non-binary graph model. Each tree node can have multiple children&parents (a node can also have a connection to it's "brother"). A node is represented as square on screen with lines to the connected nodes. For that I want to use Draw2D and GEF libraries. The problem I am facing is the graph layout. I need a nice algorithm that can reposition the square nodes and the connections with minimum intersections and also make it symmetric as possible.

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  • Non-unique display names?

    - by Davy8
    I know of at least big title game (Starcraft II) that doesn't require unique display names, so it would seem like it can work in at least some circumstance. Under what situations does allowing non-unique display names work well? When does it not work well? Does it come down to whether or not impersonation of someone else is a problem? The reasons I believe it works for Starcraft II is that there isn't any kind of in-game trading of virtual goods and other than "for kicks" there isn't much incentive to impersonate someone else in the game. There's also ladder rankings so even trying to impersonate a pro is easily detectable unless you're on a similar skill level. What are some other cases where it makes sense to specifically allow or disallow duplicate display names? (I have no idea what to tag this as. I went with game-design because I needed at least 1 tag and I don't have rep to create new ones yet.)

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  • Django 1.5 custom User model error. "Manager isn't available; User has been swapped"

    - by bpetit
    I extend the django user model as described in the dev doc. I wan't to keep most of the original User model features so I extend the AbstractUser class. I've defined in settings.py: AUTH_USER_MODEL = 'myapp.CustomUser' My user class: class CustomUser(AbstractUser): custom_field = models.ForeignKey('OtherModel') objects = UserManager() Everything seems to work fine but when I try to make it managed by the admin site: admin.site.register(CustomUser, UserAdmin) I get this error on the admin CustomUser creation page (after validation of the password confirmation form): AttributeError: Manager isn't available; User has been swapped for 'myapp.CustomUser' The point is that I need this model managed by the admin site in order to have the same creation process as with the original User model (two step process with password validation). Thanks for any reply

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  • Need a non-X terminal for the nvidia driver installation

    - by broiyan
    When I try to install the nvidia driver for my video card, I receive an error message. ERROR: You appear to be running an X server; please exit X before installing. For further details, please see the section INSTALLING THE NVIDIA DRIVER in the README available on the Linux driver download page at www.nvidia.com. I wasn't able to find the README on the website but how do I create a terminal that is non-X? I am on 12.04.

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  • Non-trivial functions that operate on any monad

    - by Strilanc
    I'm looking for examples of interesting methods that take an arbitrary monad and do something useful with it. Monads are extremely general, so methods that operate on monads are widely applicable. On the other hand, methods I know of that can apply to any monad tend to be... really, really trivial. Barely worth extracting into a function. Here's a really boring example: joinTwice. It just flattens an m m m t into an m t: join n = n >>= id joinTwice n = (join . join) n main = print (joinTwice [[[1],[2, 3]], [[4]]]) -- prints [1,2,3,4] The only non-trivial method for monads that I know of is bindFold (see my answer below). Are there more?

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  • La beta du SDK de Kinect pour Windows est disponible gratuitement pour un usage non commercial

    La beta du SDK de Kinect pour Windows est disponible gratuitement Pour un usage non commercial Mise à jour du 17/06/11, par Hinault Romaric Comme l'avait annoncé Microsoft lors de la conférence MiX 11 de la Las Vegas en avril (lire ci-avant), le SDK de Kinect pour Windows est disponible aujourd'hui en version Beta. Ce SDK permettra aux développeurs de créer des applications pour PC exploitant son capteur de mouvements, de porter les jeux initialement conçus pour la Xbox 360 vers le PC ou appliquer la technologie à d'autres usages. Pour Microsoft, Kinect est en effet « plus qu'une simple plateforme pour les jeux et le ...

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  • Django: Proper place to unregister ModelAdmins

    - by lazerscience
    Sometimes I need to UNREGISTER some ModelAdmins from the admin site, because I don't want them to be there as they are, eg. if I'm using the Sites framework, and I dont want it to appear in the admin. It's no big deal to e.g. call admin.site.unregister(Site) to do so. In most cases I put it in admin.py of some related app that I have made, but sometimes I end up putting it in a place that hasn't much to do with the original app; another possibility would be making a "dummy app" and put it there... Does anybody know a more descent place where these calls can live?

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