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  • BASH Script to Check if a number is Armstrong or Not

    - by atif089
    Hi, I was writing a script to check if a number is Armstrong or not. This is my Code echo "Enter Number" read num sum=0 item=$num while [ $item -ne 0 ] do rem='expr $item % 10' cube='expr $rem \* $rem \* $rem' sum='expr $sum + $cube' item='expr $item / 10' done if [ $sum -eq $num ] then echo "$num is an Amstrong Number" else echo "$num is not an Amstrong Number" fi After I run this script, $ ./arm.sh I always get this error ./arm.sh: line 5: [: too many arguments ./arm.sh: line 12: [: too many arguments I am on cygwin.

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  • Coming Up with a Good Algorithm for a Simple Idea

    - by mkoryak
    I need to come up with an algorithm that does the following: Lets say you have an array of positive numbers (e.g. [1,3,7,0,0,9]) and you know beforehand their sum is 20. You want to abstract some average amount from each number such that the new sum would be less by 7. To do so, you must follow these rules: you can only subtract integers the resulting array must not have any negative values you can not make any changes to the indices of the buckets. The more uniformly the subtraction is distributed over the array the better. Here is my attempt at an algorithm in JavaScript + underscore (which will probably make it n^2): function distributeSubtraction(array, goal){ var sum = _.reduce(arr, function(x, y) { return x + y; }, 0); if(goal < sum){ while(goal < sum && goal > 0){ var less = ~~(goal / _.filter(arr, _.identity).length); //length of array without 0s arr = _.map(arr, function(val){ if(less > 0){ return (less < val) ? val - less : val; //not ideal, im skipping some! } else { if(goal > 0){ //again not ideal. giving preference to start of array if(val > 0) { goal--; return val - 1; } } else { return val; } } }); if(goal > 0){ var newSum = _.reduce(arr, function(x, y) { return x + y; }, 0); goal -= sum - newSum; sum = newSum; } else { return arr; } } } else if(goal == sum) { return _.map(arr, function(){ return 0; }); } else { return arr; } } var goal = 7; var arr = [1,3,7,0,0,9]; var newArray = distributeSubtraction(arr, goal); //returned: [0, 1, 5, 0, 0, 7]; Well, that works but there must be a better way! I imagine the run time of this thing will be terrible with bigger arrays and bigger numbers. edit: I want to clarify that this question is purely academic. Think of it like an interview question where you whiteboard something and the interviewer asks you how your algorithm would behave on a different type of a dataset.

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  • Linqify this: Aggregate a subset of a list

    - by JMarsch
    Suppose I have a list or array of items, and I want to sum a subset of the items in the list. (in my case, it happens to always be a sequential subset). Here's the old-fashioned way: int sum = 0; for(int i = startIndex; i <= stopIndex; i++) sum += myList[i].TheValue; return sum; What's the best way to linqify that code?

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  • Can I do this in one Mysql query?

    - by bsandrabr
    Hi I have a table with two columns: column A column B 1 2 1 2 2 1 I want to return total of ones = 3 total of twos = 3 The best I can come up with is two queries like so: SELECT sum( CASE WHEN columnA =1 THEN 1 ELSE 0 END ) + sum(CASE WHEN columnB =1 THEN 1 ELSE 0 END ) SELECT sum( CASE WHEN columnA =2 THEN 1 ELSE 0 END ) + sum(CASE WHEN columnB =2 THEN 1 ELSE 0 END ) Can this be done in one query? Thanks

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  • Project Euler #9 (Pythagorean triplets) in Clojure

    - by dbyrne
    My answer to this problem feels too much like these solutions in C. Does anyone have any advice to make this more lispy? (use 'clojure.test) (:import 'java.lang.Math) (with-test (defn find-triplet-product ([target] (find-triplet-product 1 1 target)) ([a b target] (let [c (Math/sqrt (+ (* a a) (* b b)))] (let [sum (+ a b c)] (cond (> a target) "ERROR" (= sum target) (reduce * (list a b (int c))) (> sum target) (recur (inc a) 1 target) (< sum target) (recur a (inc b) target)))))) (is (= (find-triplet-product 1000) 31875000)))

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  • scheme2lisp::define function and pass it as parameter

    - by Stas
    Hi! Im need translate some code from scheme to common lisp. Now I have something like this (defun sum (term a next b) (if (> a b) 0 (+ (term a) (sum term (next a) b)))) (defun sum-int (a b) (defun (ident x) x ) (sum ident a 1+ b)) But it doesn't interprete with out errors. * - DEFUN: the name of a function must be a symbol, not (IDENT X) Help me plese. Thanks

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  • Beginner += in Ruby

    - by WANNABE
    Looking at this block, I can follow the whole program until I hit, sum += square. What is he point of this line, what does it say??? sum = 0 [1, 2, 3, 4].each do |value| square = value * value sum += square end puts sum

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  • Matrix Multiplication with C++ AMP

    - by Daniel Moth
    As part of our API tour of C++ AMP, we looked recently at parallel_for_each. I ended that post by saying we would revisit parallel_for_each after introducing array and array_view. Now is the time, so this is part 2 of parallel_for_each, and also a post that brings together everything we've seen until now. The code for serial and accelerated Consider a naïve (or brute force) serial implementation of matrix multiplication  0: void MatrixMultiplySerial(std::vector<float>& vC, const std::vector<float>& vA, const std::vector<float>& vB, int M, int N, int W) 1: { 2: for (int row = 0; row < M; row++) 3: { 4: for (int col = 0; col < N; col++) 5: { 6: float sum = 0.0f; 7: for(int i = 0; i < W; i++) 8: sum += vA[row * W + i] * vB[i * N + col]; 9: vC[row * N + col] = sum; 10: } 11: } 12: } We notice that each loop iteration is independent from each other and so can be parallelized. If in addition we have really large amounts of data, then this is a good candidate to offload to an accelerator. First, I'll just show you an example of what that code may look like with C++ AMP, and then we'll analyze it. It is assumed that you included at the top of your file #include <amp.h> 13: void MatrixMultiplySimple(std::vector<float>& vC, const std::vector<float>& vA, const std::vector<float>& vB, int M, int N, int W) 14: { 15: concurrency::array_view<const float,2> a(M, W, vA); 16: concurrency::array_view<const float,2> b(W, N, vB); 17: concurrency::array_view<concurrency::writeonly<float>,2> c(M, N, vC); 18: concurrency::parallel_for_each(c.grid, 19: [=](concurrency::index<2> idx) restrict(direct3d) { 20: int row = idx[0]; int col = idx[1]; 21: float sum = 0.0f; 22: for(int i = 0; i < W; i++) 23: sum += a(row, i) * b(i, col); 24: c[idx] = sum; 25: }); 26: } First a visual comparison, just for fun: The beginning and end is the same, i.e. lines 0,1,12 are identical to lines 13,14,26. The double nested loop (lines 2,3,4,5 and 10,11) has been transformed into a parallel_for_each call (18,19,20 and 25). The core algorithm (lines 6,7,8,9) is essentially the same (lines 21,22,23,24). We have extra lines in the C++ AMP version (15,16,17). Now let's dig in deeper. Using array_view and extent When we decided to convert this function to run on an accelerator, we knew we couldn't use the std::vector objects in the restrict(direct3d) function. So we had a choice of copying the data to the the concurrency::array<T,N> object, or wrapping the vector container (and hence its data) with a concurrency::array_view<T,N> object from amp.h – here we used the latter (lines 15,16,17). Now we can access the same data through the array_view objects (a and b) instead of the vector objects (vA and vB), and the added benefit is that we can capture the array_view objects in the lambda (lines 19-25) that we pass to the parallel_for_each call (line 18) and the data will get copied on demand for us to the accelerator. Note that line 15 (and ditto for 16 and 17) could have been written as two lines instead of one: extent<2> e(M, W); array_view<const float, 2> a(e, vA); In other words, we could have explicitly created the extent object instead of letting the array_view create it for us under the covers through the constructor overload we chose. The benefit of the extent object in this instance is that we can express that the data is indeed two dimensional, i.e a matrix. When we were using a vector object we could not do that, and instead we had to track via additional unrelated variables the dimensions of the matrix (i.e. with the integers M and W) – aren't you loving C++ AMP already? Note that the const before the float when creating a and b, will result in the underling data only being copied to the accelerator and not be copied back – a nice optimization. A similar thing is happening on line 17 when creating array_view c, where we have indicated that we do not need to copy the data to the accelerator, only copy it back. The kernel dispatch On line 18 we make the call to the C++ AMP entry point (parallel_for_each) to invoke our parallel loop or, as some may say, dispatch our kernel. The first argument we need to pass describes how many threads we want for this computation. For this algorithm we decided that we want exactly the same number of threads as the number of elements in the output matrix, i.e. in array_view c which will eventually update the vector vC. So each thread will compute exactly one result. Since the elements in c are organized in a 2-dimensional manner we can organize our threads in a two-dimensional manner too. We don't have to think too much about how to create the first argument (a grid) since the array_view object helpfully exposes that as a property. Note that instead of c.grid we could have written grid<2>(c.extent) or grid<2>(extent<2>(M, N)) – the result is the same in that we have specified M*N threads to execute our lambda. The second argument is a restrict(direct3d) lambda that accepts an index object. Since we elected to use a two-dimensional extent as the first argument of parallel_for_each, the index will also be two-dimensional and as covered in the previous posts it represents the thread ID, which in our case maps perfectly to the index of each element in the resulting array_view. The kernel itself The lambda body (lines 20-24), or as some may say, the kernel, is the code that will actually execute on the accelerator. It will be called by M*N threads and we can use those threads to index into the two input array_views (a,b) and write results into the output array_view ( c ). The four lines (21-24) are essentially identical to the four lines of the serial algorithm (6-9). The only difference is how we index into a,b,c versus how we index into vA,vB,vC. The code we wrote with C++ AMP is much nicer in its indexing, because the dimensionality is a first class concept, so you don't have to do funny arithmetic calculating the index of where the next row starts, which you have to do when working with vectors directly (since they store all the data in a flat manner). I skipped over describing line 20. Note that we didn't really need to read the two components of the index into temporary local variables. This mostly reflects my personal choice, in some algorithms to break down the index into local variables with names that make sense for the algorithm, i.e. in this case row and col. In other cases it may i,j,k or x,y,z, or M,N or whatever. Also note that we could have written line 24 as: c(idx[0], idx[1])=sum  or  c(row, col)=sum instead of the simpler c[idx]=sum Targeting a specific accelerator Imagine that we had more than one hardware accelerator on a system and we wanted to pick a specific one to execute this parallel loop on. So there would be some code like this anywhere before line 18: vector<accelerator> accs = MyFunctionThatChoosesSuitableAccelerators(); accelerator acc = accs[0]; …and then we would modify line 18 so we would be calling another overload of parallel_for_each that accepts an accelerator_view as the first argument, so it would become: concurrency::parallel_for_each(acc.default_view, c.grid, ...and the rest of your code remains the same… how simple is that? Comments about this post by Daniel Moth welcome at the original blog.

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  • codility challenge, test case OK , Evaluation report Wrong Answer

    - by Hussein Fawzy
    the aluminium 2014 gives me wrong answer [3 , 9 , -6 , 7 ,-3 , 9 , -6 , -10] got 25 expected 28 but when i repeated the challenge with the same code and make case test it gives me the correct answer Your test case [3, 9, -6, 7, -3, 9, -6, -10] : NO RUNTIME ERRORS (returned value: 28) what is the wrong with it ??? the challenge :- A non-empty zero-indexed array A consisting of N integers is given. A pair of integers (P, Q), such that 0 = P = Q < N, is called a slice of array A. The sum of a slice (P, Q) is the total of A[P] + A[P+1] + ... + A[Q]. The maximum sum is the maximum sum of any slice of A. For example, consider array A such that: A[0] = 3 A[1] = 2 A[2] = -6 A[3] = 3 A[4] = 1 For example (0, 1) is a slice of A that has sum A[0] + A[1] = 5. This is the maximum sum of A. You can perform a single swap operation in array A. This operation takes two indices I and J, such that 0 = I = J < N, and exchanges the values of A[I] and A[J]. To goal is to find the maximum sum you can achieve after performing a single swap. For example, after swapping elements 2 and 4, you will get the following array A: A[0] = 3 A[1] = 2 A[2] = 1 A[3] = 3 A[4] = -6 After that, (0, 3) is a slice of A that has the sum A[0] + A[1] + A[2] + A[3] = 9. This is the maximum sum of A after a single swap. Write a function: class Solution { public int solution(int[] A); } that, given a non-empty zero-indexed array A of N integers, returns the maximum sum of any slice of A after a single swap operation. For example, given: A[0] = 3 A[1] = 2 A[2] = -6 A[3] = 3 A[4] = 1 the function should return 9, as explained above. and my code is :- import java.math.*; class Solution { public int solution(int[] A) { if(A.length == 1) return A[0]; else if (A.length==2) return A[0]+A[1]; else{ int finalMaxSum = A[0]; for (int l=0 ; l<A.length ; l++){ for (int k = l+1 ; k<A.length ; k++ ){ int [] newA = A; int temp = newA[l]; newA [l] = newA[k]; newA[k]=temp; int maxSum = newA[0]; int current_max = newA[0]; for(int i = 1; i < newA.length; i++) { current_max = Math.max(A[i], current_max + newA[i]); maxSum = Math.max(maxSum, current_max); } finalMaxSum = Math.max(finalMaxSum , maxSum); } } return finalMaxSum; } } } i don't know what's the wrong with it ??

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  • Performance surprise with "as" and nullable types

    - by Jon Skeet
    I'm just revising chapter 4 of C# in Depth which deals with nullable types, and I'm adding a section about using the "as" operator, which allows you to write: object o = ...; int? x = o as int?; if (x.HasValue) { ... // Use x.Value in here } I thought this was really neat, and that it could improve performance over the C# 1 equivalent, using "is" followed by a cast - after all, this way we only need to ask for dynamic type checking once, and then a simple value check. This appears not to be the case, however. I've included a sample test app below, which basically sums all the integers within an object array - but the array contains a lot of null references and string references as well as boxed integers. The benchmark measures the code you'd have to use in C# 1, the code using the "as" operator, and just for kicks a LINQ solution. To my astonishment, the C# 1 code is 20 times faster in this case - and even the LINQ code (which I'd have expected to be slower, given the iterators involved) beats the "as" code. Is the .NET implementation of isinst for nullable types just really slow? Is it the additional unbox.any that causes the problem? Is there another explanation for this? At the moment it feels like I'm going to have to include a warning against using this in performance sensitive situations... Results: Cast: 10000000 : 121 As: 10000000 : 2211 LINQ: 10000000 : 2143 Code: using System; using System.Diagnostics; using System.Linq; class Test { const int Size = 30000000; static void Main() { object[] values = new object[Size]; for (int i = 0; i < Size - 2; i += 3) { values[i] = null; values[i+1] = ""; values[i+2] = 1; } FindSumWithCast(values); FindSumWithAs(values); FindSumWithLinq(values); } static void FindSumWithCast(object[] values) { Stopwatch sw = Stopwatch.StartNew(); int sum = 0; foreach (object o in values) { if (o is int) { int x = (int) o; sum += x; } } sw.Stop(); Console.WriteLine("Cast: {0} : {1}", sum, (long) sw.ElapsedMilliseconds); } static void FindSumWithAs(object[] values) { Stopwatch sw = Stopwatch.StartNew(); int sum = 0; foreach (object o in values) { int? x = o as int?; if (x.HasValue) { sum += x.Value; } } sw.Stop(); Console.WriteLine("As: {0} : {1}", sum, (long) sw.ElapsedMilliseconds); } static void FindSumWithLinq(object[] values) { Stopwatch sw = Stopwatch.StartNew(); int sum = values.OfType<int>().Sum(); sw.Stop(); Console.WriteLine("LINQ: {0} : {1}", sum, (long) sw.ElapsedMilliseconds); } }

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  • is Boost Library's weighted median broken?

    - by user624188
    I confess that I am no expert in C++. I am looking for a fast way to compute weighted median, which Boost seemed to have. But it seems I am not able to make it work. #include <iostream> #include <boost/accumulators/accumulators.hpp> #include <boost/accumulators/statistics/stats.hpp> #include <boost/accumulators/statistics/median.hpp> #include <boost/accumulators/statistics/weighted_median.hpp> using namespace boost::accumulators; int main() { // Define an accumulator set accumulator_set<double, stats<tag::median > > acc1; accumulator_set<double, stats<tag::median >, float> acc2; // push in some data ... acc1(0.1); acc1(0.2); acc1(0.3); acc1(0.4); acc1(0.5); acc1(0.6); acc2(0.1, weight=0.); acc2(0.2, weight=0.); acc2(0.3, weight=0.); acc2(0.4, weight=1.); acc2(0.5, weight=1.); acc2(0.6, weight=1.); // Display the results ... std::cout << " Median: " << median(acc1) << std::endl; std::cout << "Weighted Median: " << median(acc2) << std::endl; return 0; } produces the following output, which is clearly wrong. Median: 0.3 Weighted Median: 0.3 Am I doing something wrong? Any help will be greatly appreciated. * however, the weighted sum works correctly * @glowcoder: The weighted sum works perfectly fine like this. #include <iostream> #include <boost/accumulators/accumulators.hpp> #include <boost/accumulators/statistics/stats.hpp> #include <boost/accumulators/statistics/sum.hpp> #include <boost/accumulators/statistics/weighted_sum.hpp> using namespace boost::accumulators; int main() { // Define an accumulator set accumulator_set<double, stats<tag::sum > > acc1; accumulator_set<double, stats<tag::sum >, float> acc2; // accumulator_set<double, stats<tag::median >, float> acc2; // push in some data ... acc1(0.1); acc1(0.2); acc1(0.3); acc1(0.4); acc1(0.5); acc1(0.6); acc2(0.1, weight=0.); acc2(0.2, weight=0.); acc2(0.3, weight=0.); acc2(0.4, weight=1.); acc2(0.5, weight=1.); acc2(0.6, weight=1.); // Display the results ... std::cout << " Median: " << sum(acc1) << std::endl; std::cout << "Weighted Median: " << sum(acc2) << std::endl; return 0; } and the result is Sum: 2.1 Weighted Sum: 1.5

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  • Difficulty analyzing text from a file

    - by Nikko
    I'm running into a rather amusing error with my output on this lab and I was wondering if any of you might be able to hint at where my problem lies. The goal is find the high, low, average, sum of the record, and output original record. I started with a rather basic program to solve for one record and when I achieved this I expanded the program to work with the entire text file. Initially the program would correctly output: 346 130 982 90 656 117 595 High# Low# Sum# Average# When I expanded it to work for the entire record my output stopped working how I had wanted it to. 0 0 0 0 0 0 0 High: 0 Low: 0 Sum: 0 Average: 0 0 0 0 0 0 0 0 High: 0 Low: 0 Sum: 0 Average: 0 etc... I cant quite figure out why my ifstream just completely stopped bothering to input the values from file. I'll go take a walk and take another crack at it. If that doesn't work I'll be back here to check for any responses =) Thank you! #include <iostream> #include <fstream> #include <iomanip> #include <string> using namespace std; int main() { int num; int high = 0; int low = 1000; double average = 0; double sum = 0; int numcount = 0; int lines = 1; char endoline; ifstream inData; ofstream outData; inData.open("c:\\Users\\Nikko\\Desktop\\record5ain.txt"); outData.open("c:\\Users\\Nikko\\Desktop\\record5aout.txt"); if(!inData) //Reminds me to change path names when working on different computers. { cout << "Could not open file, program will exit" << endl; exit(1); } while(inData.get(endoline)) { if(endoline == '\n') lines++; } for(int A = 0; A < lines; A++) { for(int B = 0; B < 7; B++) { while(inData >> num) inData >> num; numcount++; sum += num; if(num < low) low = num; if(num > high) high = num; average = sum / numcount; outData << num << '\t'; } outData << "High: " << high << " " << "Low: " << low << " " << "Sum: " << sum << " " << "Average: " << average << endl; } inData.close(); outData.close(); return(0); }

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  • convert a number to the shortest possible character string while retaining uniqueness

    - by alumb
    I have a list of digits, say "123456", and I need to map it to a string, any string. The only constraint on the map functions are: each list of digits must map to a unique character string (this means the string can be arbitrarily long) character string can only contain 0-9, a-z, A-Z What map function would produce the shortest strings? Solutions in JavaScript are preferred. note: Clearly the simplest solution is to use the original list of digits, so make sure you solution does better than that.

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  • Multiple aggregate functions in one SQL query from the same table using different conditions

    - by Eric Ness
    I'm working on creating a SQL query that will pull records from a table based on the value of two aggregate functions. These aggregate functions are pulling data from the same table, but with different filter conditions. The problem that I run into is that the results of the SUMs are much larger than if I only include one SUM function. I know that I can create this query using temp tables, but I'm just wondering if there is an elegant solution that requires only a single query. I've created a simplified version to demonstrate the issue. Here are the table structures: EMPLOYEE TABLE EMPID 1 2 3 ABSENCE TABLE EMPID DATE HOURS_ABSENT 1 6/1/2009 3 1 9/1/2009 1 2 3/1/2010 2 And here is the query: SELECT E.EMPID ,SUM(ATOTAL.HOURS_ABSENT) AS ABSENT_TOTAL ,SUM(AYEAR.HOURS_ABSENT) AS ABSENT_YEAR FROM EMPLOYEE E INNER JOIN ABSENCE ATOTAL ON ATOTAL.EMPID = E.EMPID INNER JOIN ABSENCE AYEAR ON AYEAR.EMPID = E.EMPID WHERE AYEAR.DATE > '1/1/2010' GROUP BY E.EMPID HAVING SUM(ATOTAL.HOURS_ABSENT) > 10 OR SUM(AYEAR.HOURS_ABSENT) > 3 Any insight would be greatly appreciated.

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  • Matching a date in perl

    - by Zerobu
    Hello, I want to match a date in the format day/month/year. where day is two digits month is two digits and year is four digits. Also, I want to check see if it is a valid date, for example knows when is leap year, and know which month has 30days, 31days and 28, or 29 days for Februrary.

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  • how to increase the precision in Locate Me app

    - by thndrkiss
    Hi, I just installed the locate me app and started to understand the CLLocation stuff. I need to know how to increase the number of digits after the lat and long numbers displayed. Can any one help me. currently it shows 17.5968,82.8486. I need more number of digits after decimal(6 digits after decimal.

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  • What is the regular expression for valdating a 'price' in a jtextfield

    - by wniroshan
    I want to validate a jtextfield as user inputs a price of some item. I have a perfectly working code which beeps and discard if user inputs some character that doesnt match the regular expression.(for regular expression "[0-9]+" it accepts any number of digits and beeps if a letter is given as input) But the problem is I want to validate an input like "12500.00". Format should be any number of digits before decimal point and two digits after the decimal point. eg: ddd.dd I tried the following regular expression. But the i doesnt allow user to input "." character. It allows user to input any number of digits but when "." key is pressed input is not accepted. here is the regular expression I used. "[0-9]+ | [0-9]+. | [0-9]+.[0-9]{1} | [0-9]+{2}" important: user input is validated character by character as the user inputs them to the jtextfield.

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  • MySQL GROUP BY and JOIN

    - by christian
    Guys what's wrong with this SQL query: $sql = "SELECT res.Age, res.Gender, answer.*, $get_sum, SUM(CASE WHEN res.Gender='Male' THEN 1 else 0 END) AS males, SUM(CASE WHEN res.Gender='Female' THEN 1 else 0 END) AS females FROM Respondents AS res INNER JOIN Answers as answer ON answer.RespondentID=res.RespondentID INNER JOIN Questions as question ON answer.Answer=question.id WHERE answer.Question='Q1' GROUP BY res.Age ORDER BY res.Age ASC"; the $get_sum is an array of sql statement derived from another table: $sum[]= "SUM(CASE WHEN answer.Answer=".$db->f("id")." THEN 1 else 0 END) AS item".$db->f("id"); $get_sum = implode(', ', $sum); the query above return these values: Age: 20 item1 0 item2 1 item3 1 item4 1 item5 0 item6 0 Subtotal for Age 20 3 Age: 24 item1 2 item2 2 item3 2 item4 2 item5 1 item6 0 Subtotal for Age 24 9 It should return: Subtotal for Age 20 1 Subtotal for Age 24 2 In my sample data there are 3 respondents 2 are 24 yrs of age and the other one is 20 years old.

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  • How is schoolbook long division an O(n^2) algorithm?

    - by eSKay
    Premise: This Wikipedia page suggests that the computational complexity of Schoolbook long division is O(n^2). Deduction: Instead of taking "Two n-digit numbers", if I take one n-digit number and one m-digit number, then the complexity would be O(n*m). Contradiction: Suppose you divide 100000000 (n digits) by 1000 (m digits), you get 100000, which takes six steps to arrive at. Now, if you divide 100000000 (n digits) by 10000 (m digits), you get 10000 . Now this takes only five steps. Conclusion: So, it seems that the order of computation should be something like O(n/m). Question: Who is wrong, me or Wikipedia, and where?

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  • Define a regex, which matches one digit twice and all others once

    - by Amin
    As part of a larger regex I would like to match the following restrictions: The string has 11 digits All digits are numbers Within the first 10 digits one number [0-9] (and one only!) must be listed twice This means the following should match: 12345678914 12235879600 Whereas these should not: 12345678903 -> none of the numbers at digits 1 to 10 appears twice 14427823482 -> one number appears more than twice 72349121762 -> two numbers appear twice I have tried to use a lookahead, but all I'm managing is that the regex counts a certain digit, i.e.: (?!.*0\1{2}) That does not do what I need. Is my query even possible with regex?

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  • How to solve such system with given parts of it? (maple)

    - by Kabumbus
    So I had a system #for given koefs k:=3; n:=3; #let us solve system: koefSolution:= solve({ sum(a[i], i = 0 .. k) = 0, sum(a[i], i = 0 .. k)-(sum(b[i], i = 0 .. k)) = 0, sum(i^n*a[i], i = 0 .. k)-(sum(i^(n-1)*b[i], i = 0 .. k)) = 0 }); So I have a vector like koefSolution := { a[0] = 7*a[2]+26*a[3]-b[1]-4*b[2]-9*b[3], a[1] = -8*a[2]-27*a[3]+b[1]+4*b[2]+9*b[3], a[2] = a[2], a[3] = a[3], b[0] = -b[1]-b[2]-b[3], b[1] = b[1], b[2] = b[2], b[3] = b[3]} I have a[0] so I try solve({koefSolution, a[0] = 1}); why it does not solve my system for given a[0]? ( main point here is to fill koefSolution with given a[] and b[] and optimize.)

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  • Extending Java Enums

    - by CaseyB
    Here's what I am looking to accomplish, I have a class that has an enum of some values and I want to subclass that and add more values to the enum. This is a bad example, but: public class Digits { public enum Digit { 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 } } public class HexDigits extends Digits { public enum Digit { A, B, C, D, E, F } } so that HexDigits.Digit contains all Hex Digits. Is that possible?

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  • Writing a JavaScript zip code validation function

    - by mkoryak
    I would like to write a JavaScript function that validates a zip code, by checking if the zip code actually exists. Here is a list of all zip codes: http://www.census.gov/tiger/tms/gazetteer/zips.txt (I only care about the 2nd column) This is really a compression problem. I would like to do this for fun. OK, now that's out of the way, here is a list of optimizations over a straight hashtable that I can think of, feel free to add anything I have not thought of: Break zipcode into 2 parts, first 2 digits and last 3 digits. Make a giant if-else statement first checking the first 2 digits, then checking ranges within the last 3 digits. Or, covert the zips into hex, and see if I can do the same thing using smaller groups. Find out if within the range of all valid zip codes there are more valid zip codes vs invalid zip codes. Write the above code targeting the smaller group. Break up the hash into separate files, and load them via Ajax as user types in the zipcode. So perhaps break into 2 parts, first for first 2 digits, second for last 3. Lastly, I plan to generate the JavaScript files using another program, not by hand. Edit: performance matters here. I do want to use this, if it doesn't suck. Performance of the JavaScript code execution + download time. Edit 2: JavaScript only solutions please. I don't have access to the application server, plus, that would make this into a whole other problem =)

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