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Search found 2009 results on 81 pages for 'transform'.

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  • Rotate image in Quartz? Image is upside down! (iPhone)

    - by Johannes Jensen
    I don't want to transform the ENTIRE context. I'm making a game with Quartz, and I'm drawing my player with lines, rects and ellipses. And then I have diamong.png which I rendered at 0,0 in the top left of the screen. Problem is... It renders upside down! How would I rotate it 180 degrees? Here's some of my code: CGImageRef diamondImage = CGImageRetain([UIImage imageWithContentsOfFile: [[NSBundle mainBundle] pathForResource:@"Diamond.png" ofType:nil]].CGImage); CGContextDrawImage(context, CGRectMake(0, 0, 32, 24), diamondImage); If it's of any help, I'm using Landscape mode, with home button to the right. It's defined both in my .plist, and in my ViewController's -shouldAutorotateToInterfaceOrientation:interfaceOrientation: How would I rotate/transform it?

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  • open layers LineString not working

    - by AlexS
    Sorry to bother you guys, but I'm stuck with his problem for half a day. I want to draw poly line in OpenLayers using LineString object, so I've copied the example from documentation. It runs ok but i can't see the line on the screen Code looks like this <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN"> var map; var lineLayer ; var points; var style; var polygonFeature function test() { lineLayer = new OpenLayers.Layer.Vector("Line Layer"); style = { strokeColor: '#0000ff', strokeOpacity: 1, strokeWidth: 10 }; map.addLayer(lineLayer); points = new Array(); points[0] =new OpenLayers.LonLat(-2.460181,27.333984 ).transform(new OpenLayers.Projection("EPSG:4326"), map.getProjectionObject());; points[1] = new OpenLayers.LonLat(-3.864255,-22.5 ).transform(new OpenLayers.Projection("EPSG:4326"), map.getProjectionObject());; var linear_ring = new OpenLayers.Geometry.LinearRing(points); polygonFeature = new OpenLayers.Feature.Vector( new OpenLayers.Geometry.Polygon([linear_ring]), null, style); lineLayer.addFeatures([polygonFeature]); alert("1"); } function initialize() { map = new OpenLayers.Map ("map_canvas", { controls:[ new OpenLayers.Control.Navigation(), new OpenLayers.Control.PanZoomBar(), new OpenLayers.Control.LayerSwitcher(), new OpenLayers.Control.Attribution()], maxExtent: new OpenLayers.Bounds(-20037508.34,-20037508.34,20037508.34,20037508.34), maxResolution: 156543.0399, numZoomLevels: 19, units: 'm', projection: new OpenLayers.Projection("EPSG:900913"), displayProjection: new OpenLayers.Projection("EPSG:4326") }); // Define the map layer // Here we use a predefined layer that will be kept up to date with URL changes layerMapnik = new OpenLayers.Layer.OSM.Mapnik("Mapnik"); map.addLayer(layerMapnik); var lonLat = new OpenLayers.LonLat(0, 0).transform(new OpenLayers.Projection("EPSG:4326"), map.getProjectionObject()); map.zoomTo(3); map.setCenter(lonLat, 19); test(); } </head> <body onload="initialize()" > <div id="map_canvas" style="width: 828px; height: 698px"></div> I'm sure I'm missing some parameter in creation of map or something but I really can't figure which one.

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  • VS2010 Clean Web.configs - not updating

    - by cw
    Hello, I'm messing around with MVC 2.0 on VS2010 and am having an issue getting the clean web config feature working. Basically in my Web.debug.config I have <connectionStrings xdt:Transform="Replace"> <add name="ApplicationServices" connectionString="Server=localhost;Database=SITE_DB;User ID=dbuser;Password=P@ssw0rd;Trusted_Connection=False;" /> </connectionStrings> and in my Web.config I have <connectionStrings> <add name="ApplicationServices" connectionString="data source=.\SQLEXPRESS;Integrated Security=SSPI;AttachDBFilename=|DataDirectory|aspnetdb.mdf;User Instance=true" providerName="System.Data.SqlClient" /> </connectionStrings> When I run the site in debug mode, I'd expect that xdt:Transform="Replace" would replace the entire connectionStrings section with what is in the Web.debug.config. Am I assuming wrong? Or am I doing something else incorrect. Not much info posted around this and I'd figure I'd ask you guys.

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  • Generating a scalogram of a signal

    - by Goz
    Hi there, I'm trying to build a scalogram view for my app to see whether there is relevant information we can retrieve from a wavelet transform as opposed to using a spectograms to see what can be retrieved via an FFT. So far I can take a wave form and I can perform the forward wavelet transform on it. However I am lost at the next step. How do I turn this information into power/energy information? I have a set of wave forms at different frequencies but I have, as I say, no frequency information. Can anyone tell me what the next step is for turning this transformed data into a scalogram? Any help would be much appreciated because my google skills are failing me!

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  • using document() function in .NET XSLT generates error

    - by Simon
    I'd like to use embedded resources in my XSLT file, but while invoking 'document(...)' C# complains that "Error during loading document ..." I'd like to use defined resources in XSLT file and get them by this: "document('')//my:resources/"... How can i do that?? ex xsl: <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:my="xslt-gruper-v1.2.xsl" exclude-result-prefixes="my"> <my:resources> <one>tryb</one> </my:resources> <xsl:variable name="res" select="document('')/*/my:resources/("/> </xsl:stylesheet> How can i get access to such structure without exceptions in C#? I'll add that during static transform via ex. Opera everything works fine.

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  • How to force javax xslt transformer to encode entities in utf-8?

    - by calavera.info
    I'm working on filter that should transform an output with some stylesheet. Important sections of code looks like this: PrintWriter out = response.getWriter(); ... StringReader sr = new StringReader(content); Source xmlSource = new StreamSource(sr, requestSystemId); transformer.setOutputProperty(OutputKeys.ENCODING, "UTF-8"); transformer.setParameter("encoding", "UTF-8"); //same result when using ByteArrayOutputStream xo = new java.io.ByteArrayOutputStream(); StringWriter xo = new StringWriter(); StreamResult result = new StreamResult(xo); transformer.transform(xmlSource, result); out.write(xo.toString()); The problem is that national characters are encoded as html entities and not by using UTF. Is there any way to force transformer to use UTF-8 instead of entities?

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  • Confusion testing fftw3 - poisson equation 2d test

    - by user3699736
    I am having trouble explaining/understanding the following phenomenon: To test fftw3 i am using the 2d poisson test case: laplacian(f(x,y)) = - g(x,y) with periodic boundary conditions. After applying the fourier transform to the equation we obtain : F(kx,ky) = G(kx,ky) /(kx² + ky²) (1) if i take g(x,y) = sin (x) + sin(y) , (x,y) \in [0,2 \pi] i have immediately f(x,y) = g(x,y) which is what i am trying to obtain with the fft : i compute G from g with a forward Fourier transform From this i can compute the Fourier transform of f with (1). Finally, i compute f with the backward Fourier transform (without forgetting to normalize by 1/(nx*ny)). In practice, the results are pretty bad? (For instance, the amplitude for N = 256 is twice the amplitude obtained with N = 512) Even worse, if i try g(x,y) = sin(x)*sin(y) , the curve has not even the same form of the solution. (note that i must change the equation; i divide by two the laplacian in this case : (1) becomes F(kx,ky) = 2*G(kx,ky)/(kx²+ky²) Here is the code: /* * fftw test -- double precision */ #include <iostream> #include <stdio.h> #include <stdlib.h> #include <math.h> #include <fftw3.h> using namespace std; int main() { int N = 128; int i, j ; double pi = 3.14159265359; double *X, *Y ; X = (double*) malloc(N*sizeof(double)); Y = (double*) malloc(N*sizeof(double)); fftw_complex *out1, *in2, *out2, *in1; fftw_plan p1, p2; double L = 2.*pi; double dx = L/((N - 1)*1.0); in1 = (fftw_complex*) fftw_malloc(sizeof(fftw_complex)*(N*N) ); out2 = (fftw_complex*) fftw_malloc(sizeof(fftw_complex)*(N*N) ); out1 = (fftw_complex*) fftw_malloc(sizeof(fftw_complex)*(N*N) ); in2 = (fftw_complex*) fftw_malloc(sizeof(fftw_complex)*(N*N) ); p1 = fftw_plan_dft_2d(N, N, in1, out1, FFTW_FORWARD,FFTW_MEASURE ); p2 = fftw_plan_dft_2d(N, N, in2, out2, FFTW_BACKWARD,FFTW_MEASURE); for(i = 0; i < N; i++){ X[i] = -pi + (i*1.0)*2.*pi/((N - 1)*1.0) ; for(j = 0; j < N; j++){ Y[j] = -pi + (j*1.0)*2.*pi/((N - 1)*1.0) ; in1[i*N + j][0] = sin(X[i]) + sin(Y[j]) ; // row major ordering //in1[i*N + j][0] = sin(X[i]) * sin(Y[j]) ; // 2nd test case in1[i*N + j][1] = 0 ; } } fftw_execute(p1); // FFT forward for ( i = 0; i < N; i++){ // f = g / ( kx² + ky² ) for( j = 0; j < N; j++){ in2[i*N + j][0] = out1[i*N + j][0]/ (i*i+j*j+1e-16); in2[i*N + j][1] = out1[i*N + j][1]/ (i*i+j*j+1e-16); //in2[i*N + j][0] = 2*out1[i*N + j][0]/ (i*i+j*j+1e-16); // 2nd test case //in2[i*N + j][1] = 2*out1[i*N + j][1]/ (i*i+j*j+1e-16); } } fftw_execute(p2); //FFT backward // checking the results computed double erl1 = 0.; for ( i = 0; i < N; i++) { for( j = 0; j < N; j++){ erl1 += fabs( in1[i*N + j][0] - out2[i*N + j][0]/N/N )*dx*dx; cout<< i <<" "<< j<<" "<< sin(X[i])+sin(Y[j])<<" "<< out2[i*N+j][0]/N/N <<" "<< endl; // > output } } cout<< erl1 << endl ; // L1 error fftw_destroy_plan(p1); fftw_destroy_plan(p2); fftw_free(out1); fftw_free(out2); fftw_free(in1); fftw_free(in2); return 0; } I can't find any (more) mistakes in my code (i installed the fftw3 library last week) and i don't see a problem with the maths either but i don't think it's the fft's fault. Hence my predicament. I am all out of ideas and all out of google as well. Any help solving this puzzle would be greatly appreciated. note : compiling : g++ test.cpp -lfftw3 -lm executing : ./a.out output and i use gnuplot in order to plot the curves : (in gnuplot ) splot "output" u 1:2:4 ( for the computed solution )

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  • Using a boost::fusion::map in boost::spirit::karma

    - by user1097105
    I am using boost spirit to parse some text files into a data structure and now I am beginning to generate text from this data structure (using spirit karma). One attempt at a data structure is a boost::fusion::map (as suggested in an answer to this question). But although I can use boost::spirit::qi::parse() and get data in it easily, when I tried to generate text from it using karma, I failed. Below is my attempt (look especially at the "map_data" type). After some reading and playing around with other fusion types, I found boost::fusion::vector and BOOST_FUSION_DEFINE_ASSOC_STRUCT. I succeeded to generate output with both of them, but they don't seem ideal: in vector you cannot access a member using a name (it is like a tuple) -- and in the other solution, I don't think I need both ways (member name and key type) to access the members. #include <iostream> #include <string> #include <boost/spirit/include/karma.hpp> #include <boost/fusion/include/map.hpp> #include <boost/fusion/include/make_map.hpp> #include <boost/fusion/include/vector.hpp> #include <boost/fusion/include/as_vector.hpp> #include <boost/fusion/include/transform.hpp> struct sb_key; struct id_key; using boost::fusion::pair; typedef boost::fusion::map < pair<sb_key, int> , pair<id_key, unsigned long> > map_data; typedef boost::fusion::vector < int, unsigned long > vector_data; #include <boost/fusion/include/define_assoc_struct.hpp> BOOST_FUSION_DEFINE_ASSOC_STRUCT( (), assocstruct_data, (int, a, sb_key) (unsigned long, b, id_key)) namespace karma = boost::spirit::karma; template <typename X> std::string to_string ( const X& data ) { std::string generated; std::back_insert_iterator<std::string> sink(generated); karma::generate_delimited ( sink, karma::int_ << karma::ulong_, karma::space, data ); return generated; } int main() { map_data d1(boost::fusion::make_map<sb_key, id_key>(234, 35314988526ul)); vector_data d2(boost::fusion::make_vector(234, 35314988526ul)); assocstruct_data d3(234,35314988526ul); std::cout << "map_data as_vector: " << boost::fusion::as_vector(d1) << std::endl; //std::cout << "map_data to_string: " << to_string(d1) << std::endl; //*FAIL No 1* std::cout << "at_key (sb_key): " << boost::fusion::at_key<sb_key>(d1) << boost::fusion::at_c<0>(d1) << std::endl << std::endl; std::cout << "vector_data: " << d2 << std::endl; std::cout << "vector_data to_string: " << to_string(d2) << std::endl << std::endl; std::cout << "assoc_struct as_vector: " << boost::fusion::as_vector(d3) << std::endl; std::cout << "assoc_struct to_string: " << to_string(d3) << std::endl; std::cout << "at_key (sb_key): " << boost::fusion::at_key<sb_key>(d3) << d3.a << boost::fusion::at_c<0>(d3) << std::endl; return 0; } Including the commented line gives lots of pages of compilation errors, among which notably something like: no known conversion for argument 1 from ‘boost::fusion::pair’ to ‘double’ no known conversion for argument 1 from ‘boost::fusion::pair’ to ‘float’ Might it be that to_string needs the values of the map_data, and not the pairs? Though I am not good with templates, I tried to get a vector from a map using transform in the following way template <typename P> struct take_second { typename P::second_type operator() (P p) { return p.second; } }; // ... inside main() pair <char, int> ff(32); std::cout << "take_second (expect 32): " << take_second<pair<char,int>>()(ff) << std::endl; std::cout << "transform map_data and to_string: " << to_string(boost::fusion::transform(d1, take_second<>())); //*FAIL No 2* But I don't know what types am I supposed to give when instantiating take_second and anyway I think there must be an easier way to get (iterate over) the values of a map (is there?) If you answer this question, please also give your opinion on whether using an ASSOC_STRUCT or a map is better.

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  • iphone: mechanical drawing & layers

    - by d_CFO
    I need to do a bit of mechanical drawing. I can (1) display the part’s image, [self.view addSubview:thePartAsImageView]; (2) implement two sliders (one horizontal for part’s width and one vertical for part’s height), heightSlider.transform = CGAffineTransformRotate(heightSlider.transform, 270.0/180*M_PI); (3) display the corresponding values (dimensions) as the user moves the sliders, and even (4) draw the dimensioning lines with arrowheads: CGContextAddLineToPoint What I can’t do is (5) remove those lines after I’ve drawn them. What I want is “if userTouchedTheHorizontalControl then eraseTheLinesForTheVerticalControl.” If I understand correctly – first, that Quartz composites everything to a single layer, and second, that CALayer, GeekGameBoard and so on only work on Mac -- then I have to do something different. But isn’t there something I can do other than switch to Open GL?

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  • How to Key-Value-Observe the rotation of a CALayer?

    - by HelloMoon
    I can access the value like this: NSNumber* rotationZ = [myLayer valueForKeyPath:@"transform.rotation.z"]; But for some reason, if I try to KV-observe that key path, I get a compiler error. First, this is how I try to do it: [myLayer addObserver:self forKeyPath:@"transform.rotation.z" options:0 context:nil]; The compiler tells me: *** Terminating app due to uncaught exception 'NSUnknownKeyException', reason: '[ addObserver: forKeyPath:@"rotation.z" options:0x0 context:0x528890] was sent to an object that is not KVC-compliant for the "rotation" property.' what I don't get is, why I can access that z value by KVC key path, but not add an observer to it. Does this make sense? How else could I observe the z value of that matrix? I don't care about the other values of the matrix. Only the z rotation. Any other way to access and observe it?

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  • XSLT, JSTL e JSF

    - by Paulo S.
    I have a xml file which I want to transform in a jsf code page. To do that I've created a xsl file. xml: <?xml version='1.0' encoding='ISO-8859-1'?> <questionario xmlns:xsi='http://www.w3.org/2001/XMLSchema-instance' xsi:noNamespaceSchemaLocation='Schema2.xsd'> <componente nome='input'> <id>input1</id> </componente> <componente nome='input'> <id>input2</id> </componente> </questionario> code: <%@ taglib uri="http://java.sun.com/jstl/core_rt" prefix="c" %> <%@ taglib uri="http://java.sun.com/jsp/jstl/xml" prefix="x" %> <c:set var="xml" value="${questionarioXSLBean.xml}"/> <c:set var="xsl"> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0" xmlns:f="http://java.sun.com/jsf/core" xmlns:h="http://java.sun.com/jsf/html" exclude-result-prefixes="f h"> <xsl:template match="/"> <xsl:for-each select="questionario/componente"> <xsl:if test="attribute::nome = 'input'"> <xsl:variable name="id"> <xsl:value-of select="id" /> </xsl:variable> <h:inputText id="{$id}"/> </xsl:if> </xsl:for-each> </xsl:template> </xsl:stylesheet> </c:set> <x:transform xml="${xml}" xslt="${xsl}" /> The problem is that nothing is shown in my screen because the generated code for <h:inputText id="input1"/> is <h:inputText id="input_1" xmlns:h="http://java.sun.com/jsf/html"/> how can I replace the xmlns:h="http://java.sun.com/jsf/html" or suppress it. Thanks! Update: Let me clarify what I want to do. I want to generate a jsf page dynamically depending on the attributes of a xml file, for instance, 2 input texts, 3 check boxes, etc. To make the transformation to jsf I thought in two approaches, one using jstl and another using xslt. The problem with the former is that I couldn't integrate jstl with jsf code (to set jsf components attributes using jstl variables) and with the last approach, I'm facing the problem described above.I wouldn't like to create components in java (UIComponents). Any suggestions?

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  • Using XSL-FO and HTML?

    - by buggy1985
    Hi, I'm trying to transform some XML-data to HTML with XSLT for my bachelor thesis. My professor wants me to consider XSL-FO too, or at least to write some word about it. But I'm very noob to this. So my questions are: Can I combine FO with HTML? Can I use FO istead of HTML and CSS? If yes, how will my browser render this? Are there any examples/tutorials on how to transform xml into web pages with FO? Thank you very much.

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  • DataContractSerializer and XSLT

    - by Russ Clark
    I've got a simple Employee class that I'm trying to serialize to an XDocument and then use XSLT to transform the document to a page that displays both the properties (Name and ID) from the Employee class, and an html form with 2 radio buttons (Approve and Reject) and a submit button. Here is the Employee class: [Serializable, DataContract(Namespace="XSLT_MVC.Controllers/")] public class Employee { [DataMember] public string Name { get; set; } [DataMember] public int ID { get; set; } public Employee() { } public Employee(string name, int id) { Name = name; ID = id; } public XDocument GetDoc() { XDocument doc = new XDocument(); var serializer = new DataContractSerializer(typeof(Employee)); using (var writer = doc.CreateWriter()) { serializer.WriteObject(writer, this); writer.Close(); } return doc; } } And here is the XSLT file: <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > <xsl:output method="html" indent="yes"/> <xsl:template match="/"> <html> <body> <xsl:value-of select="Employee/Name"/> <br /> <xsl:value-of select="Employee/ID"/> <br /> <form method="post" action="/Home/ProcessRequest?id={Employee/ID}"> <input id="Action" name="Action" type="radio" value="Approved"></input> Approved <br /> <input id="Action" name="Action" type="radio" value="Rejected"></input> Rejected <br /> <input type="submit" value="Submit"></input> </form> </body> </html> </xsl:template> </xsl:stylesheet> When I run this, all I get is the html form with the 2 radio buttons and the submit button, but not the properties from the Employee class. I saw a separate StackOverflow post that said I need to change the <xsl:template match="/"> to match on the namespace of my Employee class like this: <xsl:template match="/XSLT_MVC.Controllers">, but when I do that, now all I get are the Employee properties, and not the html form with the 2 radio buttons and the submit button. Does anyone know what needs to be done so that my transform will select and display both the Employee properties and the html form?

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  • Bullets WILL NOT dissapear in firefox

    - by DunlopBurns
    Hoping you can help me with a problem. I cannot get rid of Bullets in Firefox, i don't want any anywhere, hence my list-style-type: none!important being everywhere. It only appears in Firefox as far as i can tell. the HTML.... <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" lang="en" xml:lang="en"> <head> <title>littleprints.nl</title> <meta name="description" content="----" /> <meta name="keywords" content="----" /> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4/jquery.min.js"></script> <script type="text/javascript" src="js/slimbox2.js"></script> <link rel="stylesheet" href="css/slimbox2.css" type="text/css" media="screen" /> <link rel="stylesheet" href="layout.css"/> <link rel="stylesheet" href="style.css"/> </head> <body> <div id="container"> <div id="inline1"> <div id="mainpic"> <img src="myimages/circle.jpg" width="100%" alt="Circle bracelet"/> </div> <div id="intro"> <p>Hi and welcome to little prints NL. we make this and that all by hand with 100% silver. my name is Donna Burns and i work by commision, ive been studying for 4 years and am currently learning to become a goldsmith.</p> </div> </div> <div id="inline2"> <p>Click for more...</p> <div id="images"> <a href="myimages/photos/dogtag.jpg" rel="lightbox-gal" title="Beautiful, isn't it?" ><img src="myimages/work/chunky.gif" alt="chunky"/></a> <a href="myimages/photos/hearts.jpg" rel="lightbox-gal" title="Beautiful, isn't it?" ><img src="myimages/work/hearts.gif" alt="hearts"/></a> <a href="myimages/photos/close.jpg" rel="lightbox-gal" title="Beautiful, isn't it?" ><img src="myimages/work/close.gif" alt="close"/></a> <a href="myimages/photos/pearl.jpg" rel="lightbox-gal" title="Beautiful, isn't it?" >&nbsp;</a> <a href="myimages/photos/flower.jpg" rel="lightbox-gal" title="Beautiful, isn't it?" >&nbsp;</a> <a href="myimages/photos/frontcircle.jpg" rel="lightbox-gal" title="Beautiful, isn't it?" >&nbsp;</a> <a href="myimages/photos/dogtag.jpg" rel="lightbox-gal" title="Beautiful, isn't it?" >&nbsp;</a> </div> </div> </div><!--end container--> <div id="footer"> <div id="footalign"> <div id="social"> <ul> <li> <a href="http://www.facebook.com/littleprints" title="Little Prints"> <img src="myimages/facebook.png" width="50px" height="50px" alt="FB"/> </a> </li> <li> <a href="contact.html" title="contact"> <img src="myimages/at.gif" alt="@"/> </a> </li> </ul> </div> <div id="contact"> <p><br/>To enquire about a charm either phone:<br/> 0787463289<br/> or use one of the methods to the side.</p> </div> </div> </div> </body> </html> the CSS... * {margin: 0; padding: 0; border: 0;} html, body { background-color: #000000;image; text-align: center; font: 16px/1.8 Verdana, Arial, Helvetica, sans-serif; list-style-type: none!important; text-decoration: none;} #container { position: relative; width: 900px; top: 0; min-height: 100%; margin-left: auto; margin-right: auto; padding-top: 20px; background-image: URL(myimages/back2.gif); margin-bottom: 180px; } #footer { background-color: #555555; position: relative; clear: both; bottom: 0; width: 900px; height: auto; margin-left: auto; margin-right: auto; margin-bottom: 20px; padding-bottom: 22px; margin-top: -180px; } #inline1{ display: inline-block; margin-top: 250px; margin-bottom: 20px; } #inline2 { display: inline-block; margin-top: 30px; margin-bottom: 50px; } #mainpic { float: left; width: 68%; margin-left: 20px; } #intro { float: right; width: 20%; margin-left: auto; margin-right: 50px; margin-top: 20px; } #images { margin-bottom: 20px; margin-left: auto; margin-right: auto; } #footalign { display: inline; width:900px; list-style-type: none; } #contact { text-align: center; background-color:#555555; float: middle; list-style-type: none; } #social{ background-color:#555555; float: right; list-style: none; padding:0; padding-right: 5px; text-align:center; list-style-type: none!important; } #social img{ border: none; list-style-type: none!important; margin: 3px; } #social ul{ border: none; list-style-type: none!important; } #social a{ display:inline-block; -webkit-transition:all .5s ease-out; -moz-transition:all .5s ease-out; -ms-transition:all .5s ease-out; -o-transition:all .5s ease-out; transition:all .5s ease-out; list-style-type: none!important; } #social a:hover{ display:inline-block; -webkit-transform:translate(-10px,0px); -moz-transform:translate(0px,-10px); -ms-transform:translate(-10px,0px); -o-transform:translate(-10px,0px); transform:translate(-10px,0px); list-style-type: none!important; } #form { margin-top: 250px; margin-bottom: 50px; } .nav1 {font-family: sans-serif;font-size: 22px;text-shadow: 2px 2px 5px #000000;} a:link {text-decoration:none; color:#000000; padding:3px;} a:visited {text-decoration:none; color:#000000;} a:active {text-decoration:none; color:#555555;} a:hover {text-decoration:none; color:#555555;} .nav2 {font-family: sans-serif;font-size: 22px;text-shadow: 2px 2px 5px #ffffff;} a:link {text-decoration:none; color:#ffffff; padding:3px;} a:visited {text-decoration:none; color:#ffffff;} a:active {text-decoration:none; color:#555555;} a:hover {text-decoration:none; color:#555555;} .p1 { color: #ffffff; } div#images img { max-width: 500px; height: auto; }

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  • With NHibernate, how can I create an INHibernateProxy?

    - by Eric
    After lots of reading about serialization, I've decided to try to create DTOs. After more reading, I decided to use AutoMapper. What I would like to do is transform the parent (easy enough) and transform the entity properties if they've been initialized, which I've done with ValueResolvers like below (I may try to make it generic once I get it fully working). This part works. public class OrderItemResolver : ValueResolver<Order, OrderItem> { protected override OrderItem ResolveCore(Order source) { // could also use NHibernateUtil.IsInitialized(source.OrderItem) if (source.OrderItem is NHibernate.Proxy.INHibernateProxy) return null; else return source.OrderItem; } } } When I transform the DTO back to an entity, for the entities that weren't initialized, I want to create a proxy so that if the entity wants to access it, it can. However, I can't figure out how to create a proxy. I'm using Castle if that's relevant. I've tried a bunch of things with no luck. The below code is a mess, mainly because I've been trying things at random without knowing what I should be doing. Anybody have any suggestions? public class OrderItemDTOResolver : ValueResolver<OrderDTO, OrderItem> { protected override OrderItem ResolveCore(OrderDTO source) { if (source.OrderItem == null) { //OrderItem OrderItem = new ProxyGenerator().CreateClassProxy<OrderItem>(); // Castle.Core.Interceptor. //OrderItem OrderItem = new ProxyGenerator().CreateClassProxy<OrderItem>(); //OrderItem.Id = source.OrderItemId; //OrderItem OrderItem = new OrderItem(); //var proxy = new OrderItem() as INHibernateProxy; //var proxy = OrderItem as INHibernateProxy; //return (OrderItem)proxy.HibernateLazyInitializer //ILazyInitializer proxy = new LazyInitializer("OrderItem", OrderItem, source.OrderItemId, null, null, null, null); //return (OrderItem)proxy; //return (OrderItem)proxy.HibernateLazyInitializer.GetImplementation(); //return OrderItem; IProxyTargetAccessor proxy = new Castle.Core.Interceptor. var initializer = new LazyInitializer("OrderItem", typeof(OrderItem), source.OrderItemId, null, null, null, null); //var proxyFactory = new SerializableProxyFactory{Interfaces = Interfaces, TargetSource = initializer, ProxyTargetType = IsClassProxy}; //proxyFactory.AddAdvice(initializer); //object proxyInstance = proxyFactory.GetProxy(); //return (INHibernateProxy) proxyInstance; return null; //OrderItem.Id = source.OrderItemId; //return OrderItem; } else return OrderItemDTO.Unmap(source.OrderItem); } } Thanks, Eric

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  • animate rotation

    - by Mike
    I'm trying to animate a rotation using CATransform3DMakeRotation, but the problem is once the animation is finished, the image goes back to its initial position, i.e back to zero. But I'd like to keep it where it finished rotating. How would I do that? edit What I'm trying to do is to create the same compass which comes with the new iPhone. Basically the locationmanager gives me new headings every few seconds (or several per second). Using the new heading and the timestamp, I was trying to get a smooth animation of the image but not getting anywhere. The only thing which seems to work is applying the transform directly, e.g. compassimage.layer.transform = CATransform3DMakeRotation(newHeading.trueHeading *M_PI/180,0,0,1.0): but that's not animated...

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  • C++: call original definition of operator equals

    - by Luis Daniel
    I am overloading the operator equals (==) as show bellow: #include <string> #include <algorithm> bool operator == (std::string str1, std::string str2) { std::transform(str1.begin(), str1.end(), str1.begin(), ::tolower); std::transform(str2.begin(), str2.end(), str2.begin(), ::tolower); return (str1 == str2); } but, the problem appear on line return (str1 == str2), because operator == is called recursively. So, how can I call the original definition for operator equals (not the overloaded) ? Best regards

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  • CSS - how to dry up?

    - by keruilin
    Is there a way to DRY this CSS up? Only difference is color? div.base-text-gold { position: absolute; bottom: 9px; color: #FED577; font-size: 10px; font-weight: bolder; text-align: center; width: 61px; text-transform: uppercase; } div.base-text-grey { position: absolute; bottom: 9px; color: #D1D2D4; font-size: 10px; font-weight: bolder; text-align: center; width: 61px; text-transform: uppercase; }

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  • use multiple xsl files with one xml document

    - by paracaudex
    I have a single xml document (data.xml), which I display as HTML using an XSLT document (transform.xsl) with the following line in data.xml. <?xml-stylesheet type="text/xsl" href="transform.xsl"?> Suppose, however, I want to display this information in two different ways, one at http://www.domain.com/data.xml and one at http://www.domain.com/data2.xml. Both of these displays will use the same xml document but with different xsl's. Is there a way to do this without duplicating the xml file?

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  • insane transformations of a view

    - by Mike
    I have this view and I do some rotation transformation to it using something like myView.transform = CGAffineTransformMakeRotation(degreesToRadian(90)); //The view was originally at angle 0. at some other point of my code, I would like to scale the view animating it, so I do [UIView beginAnimations:nil context:NULL]; [UIView setAnimationDuration:1.0]; myViews.transform = CGAffineTransformMakeScale(2.0f, 2.0f); [UIView commitAnimations]; but when I do that the animation is performed as the view is at 0 degrees, ignoring the previous transformation. It simply assumes as the view is yet at zero degrees, so, this animation scales the view and rotates it back to 0 degrees (!!!!?????) Is this some bug or am I missing something? thanks.

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  • Exception durin processing XSLT transformation!

    - by Artic
    I'm usin such code to generate contents file. try { StreamResult result = new StreamResult(); TransformerFactory tf = TransformerFactory.newInstance(); for (String item: groups){ item = item.replaceAll(" ", "-").toLowerCase(); result.setOutputStream(new FileOutputStream(path+item+".html")); Templates templ = tf.newTemplates(xsltSource); Transformer transf = templ.newTransformer(); transf.clearParameters(); transf.setParameter("group", item); transf.transform(xmlSource, result); } } catch (TransformerConfigurationException e) { throw new SinkException(e.getMessage()); } catch (TransformerException e) { throw new SinkException(e.getMessage()); } But on second iteration I have an exception ERROR: javax.xml.transform.TransformerException: com.sun.org.apache.xml.internal.utils.WrappedRuntimeException: Read error Cann't understand what is the reason?

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  • Maintaining last stage when rotating through CATransform3DIdentity

    - by Mikhail Naimy
    Hi. i am rotating imageview through following code.it rotates fine..but when i rotate again , Imageview goes to previous angle( which is in initial stage) and then it rotates...any one can help in this?rotationTransform has been declared as CABasicAnimation* rotationAnimation in .h file.... - (void) touchesBegan:(NSSet*)touches withEvent:(UIEvent*)event { UITouch *touch = [touches anyObject]; startTouchPosition = [touch locationInView:self.view]; } - (void) touchesMoved:(NSSet*)touches withEvent:(UIEvent*)event { UITouch *touch = [[event allTouches] anyObject]; location = [touch locationInView:self.view]; currentLocationRadians = atan2f(location.y - self.view.frame.size.height/2, location.x - self.view.frame.size.width/2); lastLocationRadians = atan2f(startTouchPosition.y - self.view.frame.size.height/2, startTouchPosition.x - self.view.frame.size.width/2); rotationTransform = CATransform3DIdentity; rotationTransform = CATransform3DRotate(rotationTransform, currentLocationRadians-lastLocationRadians + rad, 0.0, 0.0, 1.0); _imgview.layer.transform = rotationTransform; } - (void)touchesEnded:(NSSet *)touches withEvent:(UIEvent *)event { rotationTransform = _imgview.layer.transform; }

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  • .NET Extension Objects with XSLT -- how to iterate over a collection?

    - by Pandincus
    Help me, Stackoverflow! I have a simple .NET 3.5 console app that reads some data and sends emails. I'm representing the email format in an XSLT stylesheet so that we can easily change the wording of the email without needing to recompile the app. We're using Extension Objects to pass data to the XSLT when we apply the transformation: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl" xmlns:EmailNotification="ext:EmailNotification"> -- this way, we can have statements like: <p> Dear <xsl:value-of select="EmailNotification:get_FullName()" />: </p> The above works fine. I pass the object via code like this (some irrelevant code omitted for brevity): // purely an example structure public struct EmailNotification { public string FullName { get; set; } } // Somewhere in some method ... var notification = new Notification("John Smith"); // ... XsltArgumentList xslArgs = new XsltArgumentList(); xslArgs.AddExtensionObject("ext:EmailNotification", notification); // ... // The part where it breaks! (This is where we do the transformation) xslt.Transform(fakeXMLDocument.CreateNavigator(), xslArgs, XmlWriter.Create(transformedXMLString)); So, all of the above code works. However, I wanted to get a little fancy (always my downfall) and pass a collection, so that I could do something like this: <p>The following accounts need to be verified:</p> <xsl:for-each select="EmailNotification:get_SomeCollection()"> <ul> <li> <xsl:value-of select="@SomeAttribute" /> </li> </ul> <xsl:for-each> When I pass the collection in the extension object and attempt to transform, I get the following error: "Extension function parameters or return values which have Clr type 'String[]' are not supported." or List, or IEnumerable, or whatever I try to pass in. So, my questions are: How can I pass in a collection to my XSLT? What do I put for the xsl:value-of select="" inside the xsl:for-each ? Is what I am trying to do impossible?

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  • Bandpass filter of FFT applied image. (Like ImageJ bandpass filter algorithm)

    - by maximus
    There is a good function that I need, which is implemented in Java program: ImageJ I need to understand the algorithm used there. The function has several parameters: link text And before using FFT it converts image to a special one: The Bandpass Filter uses a special algorithm to reduce edge artifacts (before the Fourier transform, the image is extended in size by attaching mirrored copies of image parts outside the original image, thus no jumps occur at the edges) Can you tell me more about this special transform? Actually tiling mirrored image. I am writing on C++ and wish to rewrite that part of the program on C++.

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  • SVG via dynamic XML+XSL

    - by Daniel
    This is a bit of a vague notion which I have been running over in my head, and which I am very curious if there is an elegant method of solving. Perhaps it should be taken as a thought experiment. Imagine you have an XML schema with a corresponding XSL transform, which renders the XML as SVG in the browser. The XSL generates SVG with appropriate Javascript handlers that, ultimately, implement editing-like functionality such that properties of the objects or their locations on the SVG canvas can be edited by the user. For instance, an element can be dragged from one location to another. Now, this isn't particularly difficult - the drag/drop example is simply a matter of changing the (x,y) coordinates of the SVG object, or a resize operation would be a simple matter of changing its width or height. But is there an elegant way to have Javascript work on the DOM of the source XML document instead of the rendered SVG? Why, you ask? Well, imagine you have very complex XSL transforms, where the modification of one property results in complex changes to the SVG. You want to maintain simplicity in your Javascript code, but also a simple way to persist the modified XML back to the server. Some possibilities of how this may function: After modification of the source DOM, simply re-run the XSL transform and replace the original. Downside: brute force, potentially expensive operation. Create id/class naming conventions in the source and target XML/SVG so elements can be related back to each other, and do an XSL transform on only a subset of the new DOM. In other words, modify temporary DOM, apply XSL to it, remove changed elements from SVG, and insert the new one. Downside: May not be possible to apply XSL to temporary in-browser DOMs(?). Also, perhaps a bit convoluted or ugly to maintain. I think that it may be possible to come up with a framework that handles the second scenario, but the challenge would be making it lightweight and not heavily tied to the actual XML schema. Any ideas or other possibilities? Or is there maybe an existing method of doing this which I'm not aware of? UPDATE: To clarify, as I mentioned in a comment below, this aids in separating the draw code from the edit code. For a more concrete example of how this is useful, imagine an element which determines how it is drawn dependent on the value of a property of an adjacent element. It's better to condense that logic directly in the draw code instead of also duplicating it in the edit code.

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