Well, to build my menu my menu I use a db similar structure like this
To assign another submenu for existing submenu I simply assign its parent's id as its value of parent field.
parent
0 means top menu
now there is not problem while creating submenu inside another submenu
now this is way I fetch the submenu for the top menu
<ul class="topmenu">
<? $list = $obj -> childmenu($parentid);
//this list contains the array of submenu under $parendid
foreach($list as $menu) {
extract($menu);
echo '<li><a href="#">'.$name.'</a></li>';
}
?>
</ul>
What I want to do is.
I want to check if a new menu has other child menu
and I want to keep on checking until it searches every child menu that is available
and I want to display its child menu inside its particular list item like this
Home
........
