Search Results

Search found 4071 results on 163 pages for 'preg split'.

Page 24/163 | < Previous Page | 20 21 22 23 24 25 26 27 28 29 30 31  | Next Page >

• Convert Plain Text Hyperlinks into HTML Hyperlinks in PHP

  - by Volomike

  I have a simple commenting system here... http://affbuzz.com/comments/7299a55137def55917a5dc6c4fe0f261af8a4217 ...and people can submit hyperlinks inside the plain text field. When I display these records back from the database and into the web page, what RegExp in PHP can I use to convert these links into HTML-type anchor links? Bonus: For the algorithm to not do this with any other kind of link, just http and https.

  Read the article

• Complex regex question, data may or may not be in brackets

  - by martinpetts

  I need to extract data from a source that presents it in one of two ways. The data could be formatted like this: Francis (Lab) 18,077 (60.05%); Waller (LD) 4,140 (13.75%); Evans (PC) 3,545 (11.78%); Rees-Mogg (C) 3,064 (10.18%); Wright (Veritas) 768 (2.55%); La Vey (Green) 510 (1.69%) Or like this: Lab 8,994 (33.00%); C 7,924 (29.07%); LD 5,197 (19.07%); PC 3,818 (14.01%); Others 517 (1.90%); Green 512 (1.88%); UKIP 296 (1.09%) The data I need to extract is the percentage and the party (these are election results), which is either in brackets (first example) or is the only non-numeric text. So far I have this: preg_match('/(.*)\(([^)]*)%\)/', $value, $match); Which is giving me the following matches (for first example): Array ( [0] => Francis (Lab) 18,077 (60.05%) [1] => Francis (Lab) 18,077 [2] => 60.05 ) So I have the percentage, but I also need the party label, which may or may not be in brackets and may or may not be the only text. Can anyone help?

  Read the article

• preg_match to match an optional string, but not match all of the string

  - by buggedcom

  Take for example the following regex match. preg_match('!^publisher/([A-Za-z0-9\-\_]+)/([0-9]+)/([0-9]{4})-(january|february|march|april|may|june|july|august|september|october|november|december):([0-9]{1,2})-([0-9]{1,2})/([A-Za-z0-9\-\_]+)/([0-9]+)(/page-[0-9]+)?$!', 'publisher/news/1/2010-march:03-23/test_title/1/page-1', $matches); print_r($matches); It produces the following: Array ( [0] => publisher/news/1/2010-march:03-23/test_title/1/page-1 [1] => news [2] => 1 [3] => 2010 [4] => march [5] => 03 [6] => 23 [7] => test_title [8] => 1 [9] => /page-1 ) However as the last match is optional it can also work with matching the following "publisher/news/1/2010-march:03-23/test_title/1". My problem is that I want to be able to match (/page-[0-9]+) if it exists, but match only the page number so "publisher/news/1/2010-march:03-23/test_title/1/page-1" would match like so: Array ( [0] => publisher/news/1/2010-march:03-23/test_title/1/page-1 [1] => news [2] => 1 [3] => 2010 [4] => march [5] => 03 [6] => 23 [7] => test_title [8] => 1 [9] => 1 ) I've tried the following regex '!^publisher/([A-Za-z0-9\-\_]+)/([0-9]+)/([0-9]{4})-(january|february|march|april|may|june|july|august|september|october|november|december):([0-9]{1,2})-([0-9]{1,2})/([A-Za-z0-9\-\_]+)/([0-9]+)/?p?a?g?e?-?([0-9]+)?$!' This works, however it will also match "publisher/news/1/2010-march:03-23/test_title/1/1". I have no idea to perform a match but not have it come back in the matches? Is it possible in a single regex?

  Read the article

• Regex to Match White Space or End of String

  - by Kirk

  I'm trying to find every instance of @username in comment text and replace it with a link. Here's my PHP so far: $comment = preg_replace('/@(.+?)\s/', '<a href="/users/${1}/">@${1}</a> ', $comment); The only problem is the regex is dependent upon there being whitespace after the @username reference. Can anyone help me tweak this so it will also match if it is at the end of the string?

  Read the article

• Detecting .com / .co.uk etc etc

  - by Stefan

  Hey all! I currently have a preg_match to detect http:// and www. etc..... but I want to detect domain.com or domain.co.uk etc etc... Sorry... to clarify: i'm detecting in a string. Any ideas i need to scratch up on my regex! Thanks, Stefan

  Read the article

• Replace this Hex chars from string in PHP

  - by Guillermo

  I'm generating an XML from data that comes from database (and some JSON feeds). I'm having some problems with some texts that contains some hex chars that are breaking my XML. For example, see this screenshot of the error I get from Chrome: I identified the hex characters that are giving me problems (I believe they're called control characters). And these are: 0x03 0x05 0x16 0x0E How can I replace those characters with PHP before printing them on my XML output? Thanks!

  Read the article

• Reg exp to replace the whole word if any word contains any non alphanumeric character or space

  - by Andrew

  e.g string = "This is a re@lly long long,long! sentence"; becomes string = "This is a long sentence"; Basically so all non-alphanumeric words or removed keeping spaces in tacked Any ideas?

  Read the article

• PHP preg_replace - Don't match with h1 tags

  - by James

  Hi there. I am using preg_replace to add a link to keywords if they are found within a long HTML string. I don't want to add a link if the keyword is found within h1 tags or strong tags. The below regex nearly works and basically says (I think): If the keyword is not immediately wrapped by either a h1 tag or a strong tag then replace with the keyword that was matched, as a bolded link to google. $result = preg_replace('%(?!<h1>)(?!<strong>)\b(bobs widgets)\b(?!<\/strong>)(?!<\/h1>)%i','<a href="http://www.google.com"><strong>$1</strong></a>', $result, -1); (the reason I don't want to match if in strong tags is because I am recursing through a lot of keywords so don't want to link an already linked keyword on subsequent passes) the above works fine and won't match: <h1>bobs widgets</h1> It will however match the keyword in the following text, because the h1 tag isn't immediately either side of the keyword: <h1>Here are bobs widgets for sale</h1> I need to make the spaces either side optional and have tried adding \s* but that doesn't get me anywhere. I'd be very grateful for a push in the right direction here.

  Read the article

• preg_match , pattern, php

  - by Michael

  I'm trying to extract some specific pictures from html content . Currently I have the following array [1] = Array ( [0] = BuEZm5g!Wk~$(KGrHqQH-DgEvrb2CLuOBL-vbkHlKw~~_14.JPG#!BuEZm5g!Wk~$(KGrHqQH-DgEvrb2CLuOBL-vbkHlKw~~_12.JPG|1#http://i.ebayimg.com/08#!BuEZqMQBGk~$(KGrHqQH-DoEvrKYSoPiBL-vb)WgLw~~_14.JPG#!BuEZqMQBGk~$(KGrHqQH-DoEvrKYSoPiBL-vb)WgLw~~_12.JPG|2#http://i.ebayimg.com/13#!BuEZtkw!2k~$(KGrHqYH-EYEvsh4EjJSBL-vb-bLow~~_14.JPG#!BuEZtkw!2k~$(KGrHqYH-EYEvsh4EjJSBL-vb-bLow~~_12.JPG|3#http://i.ebayimg.com/03#!BuEZ)!wEGk~$(KGrHqYH-DwEvq8Z1JuQBL-vcMOoFQ~~_14.JPG#!BuEZ)!wEGk~$(KGrHqYH-DwEvq8Z1JuQBL-vcMOoFQ~~_12.JPG|4#http://i.ebayimg.com/09#!BuEZ1IQEGk~$(KGrHqEH-D0EvqwClvviBL-vcclJwg~~_14.JPG#!BuEZ1IQEGk~$(KGrHqEH-D0EvqwClvviBL-vcclJwg~~_12.JPG|5#http://i.ebayimg.com/17#!BuEZ4FQCWk~$(KGrHqUH-DMEvS+,FRj5BL-vco)Qgg~~_14.JPG#!BuEZ4FQCWk~$(KGrHqUH-DMEvS+,FRj5BL-vco)Qgg~~_12.JPG|6#http://i.ebayimg.com/17#!BuEZ7FQEWk~$(KGrHqYH-EYEvsh4EjJSBL-vc1v2Hg~~_14.JPG#!BuEZ7FQEWk~$(KGrHqYH-EYEvsh4EjJSBL-vc1v2Hg~~_12.JPG|7#http://i.ebayimg.com/12#!BuEZ-c!Bmk~$(KGrHqQH-CYEvr5z9)NVBL-vdC,)Mg~~_14.JPG#!BuEZ-c!Bmk~$(KGrHqQH-CYEvr5z9)NVBL-vdC,)Mg~~_12.JPG|8#http://i.ebayimg.com/20#!BuE,CNgCWk~$(KGrHqIH-CIEvqKBurmhBL-vdRBe3!~~_14.JPG#!BuE,CNgCWk~$(KGrHqIH-CIEvqKBurmhBL-vdRBe3!~~_12.JPG|9#http://i.ebayimg.com/24#!BuE,FN!EWk~$(KGrHqUH-C0EvsBdjbv0BL-vdeFkD!~~_14.JPG#!BuE,FN!EWk~$(KGrHqUH-C0EvsBdjbv0BL-vdeFkD!~~_12.JPG|10#http://i.ebayimg.com/16#!BuE,IOgBmk~$(KGrHqEH-EMEvpym7mSLBL-vdqI6nw~~_14.JPG#!BuE,IOgBmk~$(KGrHqEH-EMEvpym7mSLBL-vdqI6nw~~ ) I need to extract only the pictures that start with ! and ends in 12.JPG . An example of expected result is !BuEZm5g!Wk~$(KGrHqQH-DgEvrb2CLuOBL-vbkHlKw~~_12.JPG . I have a pattern but it doesn't work for some reasons that I don't know . It is $pattern = "/#\!(.*)_12.JPG/"; Thank you in advance for any help

  Read the article

• Using preg_replace in mysql

  - by Roshan

  I have a CMS content in database. The content contains '<img src= .............../>' also. I want to retrieve this content using mysql query and show on frontend but with all '<img src='.........../>' removed from the content. How can it be done using query in mysql?

  Read the article

• Help with a simple switch statement

  - by revive

  I need to find the value of a variable and use it to add a class to a div, based on a switch statement. For example, my variable is $link and if $link has google.com IN IT at all, I need $class to equal 'google', if $link as yahoo.com IN IT at all, $class then needs to equal 'yahoo' So, I need something like this, but I'm not sure how/or if to use preg_match or something to check and see if the $link variable has the value we are looking for in it - see 'case' text below: switch ($link) { case 'IF link has Google.com in it': $class = 'google'; break; case 'IF link has Yahoo.com in it': $class = 'yahoo'; break; default: # code... break; } OR if there is a better way to do this, please let me know :D Thanks

  Read the article

• Encoding problem with preg_replace() and scandir()

  - by itarato

  Hi, On OS-X (PHP5.2.11) I have a file: siësta.doc (and thousand other with Unicode filenames) and I want to convert the file names to a web-consumable format (a-zA-Z0-9.). If I hardcode the file name above I can do the right conversion: <?php $file = 'siësta.doc'; echo preg_replace("/[^a-zA-Z0-9.]/u", '_', $file); // Output: si_sta.doc ?> But if I read the file names with scandir, I've got strange conversions: <?php $files = scandir(DIRNAME); foreach ($files as $file) { echo preg_replace("/[^a-zA-Z0-9.]/u", '_', $file); // Output for the file above: sie_sta.doc } ?> I tried to detect the encoding, set the encoding, convert it with iconv functions. I tried the mb_ functions also. But it was just worse. What did I do wrong? Thanks in advance

  Read the article

• php regex expression to get title

  - by 55skidoo

  I'm trying to strip content titles out of the middle of text strings. Could I use regex to strip everything out of this string except for the title (in italics) in these strings? Or is there a better way? Joe User wrote a blog post called The 10 Best Regex Expressions in the category Regex. Jane User wrote a blog post called Regex is Hard! in the category TechProblems. I've tried to come up with a regex expression to cover this, but I think it might need two. The trick is that the text in bold is always the same, so you could search for that, like this: regex: delete everything before and including wrote a blog post called regex: delete in the category and everything after it.

  Read the article

• PHP preg_replace function returns different values with the same data set

  - by patryk

  I need to use preg_match PHP function. I have a simple pattern to check the string and the thing is as follows: when I run the script at first, it gives me no match (it is supposed to match though) but when I hold F5 in my browser for a while, out of a sudden it says there's a match within the string. As I keep pushing F5, it gives either true or false. Say the pattern is /^(.*)\/[A-Za-z0-9]*$/ (I guess it's not the best way but still) and the subject is galeria/zdjecia/. I believe preg_match should return true with this set of data. Note that the data does not change when pressing F5. Why is that?

  Read the article

• need a regex to parse a csv file with double quotes in php

  - by Brandon G

  Trying to parse a csv file that has all the data wrapped in double quotes, because there may be commas in the double quotes. Looks like this: $songs = '"1, 2, 3, 4 (I Love You)","Plain White T's","CBE10-22",15,"CBE10-22","","","CB",984,"","10/05/10"'; $regResult = preg_match( "", $songs, $matches ); I can't figure out a regex that will return the data between the quotes as the matches. I'm sure there is some regex master that can help me with this.

  Read the article

• php regex word boundary matching in utf-8

  - by dontomaso

  Hi, I have the following php code in a utf-8 php file: var_dump(setlocale(LC_CTYPE, 'de_DE.utf8', 'German_Germany.utf-8', 'de_DE', 'german')); var_dump(mb_internal_encoding()); var_dump(mb_internal_encoding('utf-8')); var_dump(mb_internal_encoding()); var_dump(mb_regex_encoding()); var_dump(mb_regex_encoding('utf-8')); var_dump(mb_regex_encoding()); var_dump(preg_replace('/\bweiß\b/iu', 'weiss', 'weißbier')); I would like the last regex to replace only full words and not parts of words. On my windows computer, it returns: string 'German_Germany.1252' (length=19) string 'ISO-8859-1' (length=10) boolean true string 'UTF-8' (length=5) string 'EUC-JP' (length=6) boolean true string 'UTF-8' (length=5) string 'weißbier' (length=9) On the webserver (linux), I get: string(10) "de_DE.utf8" string(10) "ISO-8859-1" bool(true) string(5) "UTF-8" string(10) "ISO-8859-1" bool(true) string(5) "UTF-8" string(9) "weissbier" Thus, the regex works as I expected on windows but not on linux. So the main question is, how should I write my regex to only match at word boundaries? A secondary questions is how I can let windows know that I want to use utf-8 in my php application.

  Read the article

• regex , php, preg_match

  - by Michael

  I'm trying to extract the mileage value from different ebay pages but I'm stuck as there seem to be too many patterns because the pages are a bit different . Therefore I would like to know if you can help me with a better pattern . Some examples of items are the following : http://cgi.ebay.com/ebaymotors/1971-Chevy-C10-Shortbed-Truck-/250647101696?cmd=ViewItem&pt=US_Cars_Trucks&hash=item3a5bbb4100 http://cgi.ebay.com/ebaymotors/1987-HANDICAP-LEISURE-VAN-W-WHEEL-CHAIR-LIFT-/250647101712?cmd=ViewItem&pt=US_Cars_Trucks&hash=item3a5bbb4110 http://cgi.ebay.com/ebaymotors/ws/eBayISAPI.dll?ViewItemNext&item=250647101696 Please see the patterns at the following link (I still cannot figure it out how to escape the html here http://pastebin.com/zk4HAY3T However they are not enough many as it seems there are still new patters....

  Read the article

• PHP: BBCode with SQL selection?

  - by rayne

  I would like to code a bbcode with SQL selection. Basically I want the user to be able to input [user]Anotheruser[/user] in a text field, which then is converted in the front-end to an URL that looks like this: http://mydomain.com/user/[userid]/anotheruser. So in order to get the userid, I'd need to include an SQL selection, and additionally an if else to find out of the other user actually exists. Can I do this with a preg_replace as usually used for creating bbcode, or do I need to do something more complex?

  Read the article

• I need a regex to return true for 01.mp4

  - by Umair

  I want to sort out specific files depending on their names, i want a regex that returns true for file names like : 01.mp4, 99.avi, 05.mpg. the file extensions must match exactly to the ones that i want and the filename must start with characters which can not be longer than 2 characters. the first part is done but the file extensions aren't working. need some help the regex that I have is /^[0-9]{1,2}\.[mp4|mpg|avi]*/ but it also returns true for 01.4mp4, 01.4mp4m.

  Read the article

• replace string in preg_replace

  - by zahir hussain

  <?php $a="php.net s earch for in the all php.net sites this mirror only function list online documentation bug database Site News Archive All Changelogs just pear.php.net just pecl.php.net just talks.php.net general mailing list developer mailing list documentation mailing list What is PHP? PHP is a widely-used..."; ?> I want to highlight specific words. For example php, net and func: php.net s earch for in the all **php**.**net** sites this mirror only **func**tion list online documentation bug database Site News Archive All Changelogs just pear.**php**.**net** just pecl.**php**.**net** just talks.php.net general mailing list developer mailing list documentation mailing list What is **PHP**? **PHP** is a widely-used... Thanks advance.

  Read the article

• Selectively replacing words outside of tags using regular expressions in PHP?

  - by Gary Willoughby

  I have a paragraph of text and i want to replace some words using PHP (preg_replace). Here's a sample piece of text: This lesson addresses rhyming [one]words and ways[/one] that students may learn to identify these words. Topics include learning that rhyming words sound alike and these sounds all come from the [two]ending of the words[/two]. This can be accomplished by having students repeat sets of rhyming words so that they can say them and hear them. The students will also participate in a variety of rhyming word activities. In order to demonstrate mastery the students will listen to [three]sets of words[/three] and tell the teacher if the words rhyme or not. If you notice there are many occurances of the word 'words'. I want to replace all the occurances that don't occur inside any of the tags with the word 'birds'. So it looks like this: This lesson addresses rhyming [one]words and ways[/one] that students may learn to identify these birds. Topics include learning that rhyming birds sound alike and these sounds all come from the [two]ending of the words[/two]. This can be accomplished by having students repeat sets of rhyming birds so that they can say them and hear them. The students will also participate in a variety of rhyming word activities. In order to demonstrate mastery the students will listen to [three]sets of words[/three] and tell the teacher if the birds rhyme or not. Would you use regular expressions to accomplish this? Can a regular expression accomplish this?

  Read the article

• Extracting Text from between parentheses in PHP using preg_replace

  - by Christopher

  I am trying to take a string of text like so: $string = "This (1) is (2) my (3) example (4) text"; In every instance where there is a positive integer inside of parentheses, I'd like to replace that with simply the integer itself. The code I'm using now is: $result = preg_replace("((\d+))", "$0", $string); But I keep getting a "Delimiter must not be alphanumeric or backslash" error. Any thoughts? I know there are other questions on here that sort of answer the question, but my knowledge of regex is not enough to switch it over to this example.

  Read the article

• Having problems getting a PHP regex to match.

  - by dqhendricks

  Here is my problem. It's probably a simple fix. I have a regex that I am using to replace a url BBCode. What I have right now that is not working looks like this. <?php $input_string = '[url=www.test.com]Test[url]'; $regex = '/\[url=(.+?)](.+?)\[\/url]/is'; $replacement_string = '<a href="$1">$2</a>'; echo preg_replace($regex, $replacement_string, $input_string); ?> This currently outputs the original $input_string, while I would like it to output the following. <a href="www.test.com">Test</a> What am I missing?

  Read the article

• A solid nickname regexp

  - by iBram

  I want a regular expression to validate a nickname: 6 to 36 characters, it should contain at least one letter. Other allowed characters: 0-9 and underscores. This is what I have now: if(!preg_match('/^.*(?=\d{0,})(?=[a-zA-Z]{1,})(?=[a-zA-Z0-9_]{6,36}).*$/i', $value)){ echo 'bad'; } else{ echo 'good'; } This seems to work, but when a validate this strings for example: 11111111111a is not valid, but it should aaaaaaa!aaaa is valid, but it shouldn't Any ideas to make this regexp better?

  Read the article

• preg_replace only part of match

  - by Tony Vipros

  Hi, I'm using preg_replace to create urls for modrewrite based paging links. I use: $nextURL = preg_replace('%/([\d]+)/%','/'.($pageNumber+1).'/',$currentURL); which works fine, however I was wondering if there is a better way without having to include the '/' in the replacement parameter. I need to match the number as being between two / as the URLs can sometimes contain numbers other than the page part. These numbers are never only numbers however, so have /[\d]+/ stops them from getting replaced.

  Read the article

< Previous Page | 20 21 22 23 24 25 26 27 28 29 30 31  | Next Page >