PHP function similar to this JavaScript function
- by Jude
I need a similar function in PHP for this JavaScript function
text = text.replace(/ffc/g, "Hello");
I think preg_replace will do, but i'm not sure how to write the expression..
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Help converting PHP eregi to preg_match
- by Jason
Hi all, I am wondering if someone could please help me convert a piece of PHP code that is now deprecated. Here is the single line I am trying to convert: if(eregi(trim ($request_url_handler[$x]),$this->sys_request_url) && $this->id_found == 0){ It is part of a function that return the configuration settings for a website. Below is the whole function. // GET CORRECT CONFIG FROM DATABASE function get_config($db) { global $tbl_prefix; $db->query("SELECT cid,urls FROM ".$tbl_prefix."sys_config ORDER BY cid"); while($db->next_record()){ $request_url_handler = explode("\n",$db->f("urls")); if(empty($request_url_handler[0])) { $request_url_handler[0] = "@"; $this->id_found = 2; } for($x=0; $x<count($request_url_handler); $x++) { if(empty($request_url_handler[$x])) { $request_url_handler[$x] = "@"; } if(eregi(trim($request_url_handler[$x]),$this->sys_request_url) && $this->id_found == 0) { $this->set_config($db,$db->f("cid")); $this->id_found = 1; } } if($this->id_found == 1) { return($this->sys_config_vars); } } $this->set_config($db,""); return($this->sys_config_vars); } Any help would be great ly appreciated. I only found the the eregi function was deprecated since I updated XAMPP to 1.7.3.Read the article
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PHP preg_replace - Don't match within h1 tags
- by James
Hi there. I am using preg_replace to add a link to keywords if they are found within a long HTML string. I don't want to add a link if the keyword is found within h1 tags or strong tags. The below regex nearly works and basically says (I think): If the keyword is not immediately wrapped by either a h1 tag or a strong tag then replace with the keyword that was matched, as a bolded link to google. $result = preg_replace('%(?!<h1>)(?!<strong>)\b(bobs widgets)\b(?!<\/strong>)(?!<\/h1>)%i','<a href="http://www.google.com"><strong>$1</strong></a>', $result, -1); (the reason I don't want to match if in strong tags is because I am recursing through a lot of keywords so don't want to link an already linked keyword on subsequent passes) the above works fine and won't match: <h1>bobs widgets</h1> It will however match the keyword in the following text, because the h1 tag isn't immediately either side of the keyword: <h1>Here are bobs widgets for sale</h1> I need to make the spaces either side optional and have tried adding \s* but that doesn't get me anywhere. I'd be very grateful for a push in the right direction here.Read the article
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PHP: using REGEX to get the tablename from a mysql query
- by Matt
Hi Guys, Consider these three mysql statements: select * from Users; select id, title, value from Blogs; select id, feelURL, feelTitle from Feeds where id = 1; Now im not very good at REGEX, but i want to get the table name from the mysql query. Could someone possibly create one for me with a little explanation. Thanks,Read the article
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PHP str_replace and preg_replace work on one server but not another
- by retailevolved
I have a simple function on a php page that takes a url such as: http://myurl.com/mypage.html?param1=value1 and converts it to: http://myurl.com/searchpage.html?param1=value1 All it does it swap out the page.html portion. To do this, I use the following: $currentUrl = $this-getCurrentUrl(); // Grabs the current url, i.e 'http://myurl.com/mypage.html?param1=value1' // Derive a search pattern from the current url $pattern = "/" . str_replace(array("/", ".", "-"), array("\\/", "\\.", "\\-"), $currentUrl) . "/"; // get rid of the 'mypage.html' $newUrl = preg_replace($pattern, 'http://myurl.com/', $currentUrl); // replace the question mark with the correct page $newUrl = str_replace("/?", "/searchpage.html?", $newUrl); The above code is not the exact code but is a good representation. It works beautifully on one server, but when I push to production, the preg_replace does not work. I originally attempted to use str_replace. It also works on my local development machine, but not on the production server. I have confirmed that the URL variables are coming in correctly. Any ideas?Read the article
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Regexp: Replace only in specific context
- by blinry
In a text, I would like to replace all occurrences of $word by [$word]($word) (to create a link in Markdown), but only if it is not already in a link. Example: [$word homepage](http://w00tw00t.org) should not become [[$word]($word) homepage](http://w00tw00t.org). Thus, I need to check whether $word is somewhere between [ and ] and only replace if it's not the case. Can you think of a preg_replace command for this?Read the article
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stripping a query string with php (preg_replace)
- by pg
http://www.chuckecheese.com/rotator.php?cheese=4&id=1 I want to take out the id, leaving the cheese to stand alone. I tried: $qs = preg_replace("[^&id=*]" ,'',$_SERVER[QUERY_STRING]); But that said I was using an improper modifier. I want to remove "$id=" and whatever number comes after it. Are regexp really as hard as they seem for me?Read the article
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Memory leak with preg_replace
- by Silvio Donnini
I'm using the preg_replace function to replace accents in a string, I'm working with UTF-8. I have incurred in what seems to be a memory leak, but I can't isolate the root cause, my code is rather simple: preg_replace( array_keys($aToNoAccents), array_values($aToNoAccents), $sText ); where $aToNoAccents is an associative array with entries like '~[A]~u' => 'A', '~[C]~u' => 'C',. My script prints this error for the above line: Fatal error: Allowed memory size of 1073741824 bytes exhausted (tried to allocate 3039 bytes) Obviously it's not a matter of increasing the allowed memory for PHP, (a 1Gb footprint is way off the scale of my application). Also, that line is executed thousands of times without problems but, just for some cases which are difficult to reproduce, it yields the error. Is anyone aware of memory problems with preg_replace and UTF-8 strings? Am I to use special care in passing actual parameters to such function? I'm using PHP 5.2.6-3 with Suhosin-Patch thanks SilvioRead the article
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str_replace match only first instance
- by kylex
A followup question to http://stackoverflow.com/questions/3063704/ Given the following POST data: 2010-June-3 <remove>2010-June-3</remove> 2010-June-15 2010-June-16 2010-June-17 2010-June-3 2010-June-1 I'm wanting to remove ONLY the first instance of 2010-June-3, but the following code removes all the data. $i = 1; $pattern = "/<remove>(.*?)<\/remove>/"; preg_match_all($pattern, $_POST['exclude'], $matches, PREG_SET_ORDER); if (!empty($matches)) { foreach ($matches as $match) { // replace first instance of excluded data $_POST['exclude'] = str_replace($match[1], "", $_POST['exclude'], $i); } } echo "<br /><br />".$_POST['exclude']; This echos: <remove></remove> 2010-June-15 2010-June-16 2010-June-17 2010-June-1 It should echo: <remove>2010-June-3</remove> 2010-June-15 2010-June-16 2010-June-17 2010-June-3 2010-June-1Read the article
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PHP Find and replace after in a string?
- by TheBlackBenzKid
I have some strings which contain the words LIMIT 3, 199 or LIMIT 0, 100. Basically I want to replace the word LIMIT and everything after it in my string. How do I do this in PHP? str_replace only replaces an item and the LIMIT text after is dynamic/ So it could be WHEN JOHN WAS TRYING HIS SQL QUERY, HE FOUND THAT LIMIT, 121 // RETURN WOULD BE WHEN JOHN WAS TRYING HIS SQL QUERY, HE FOUND THAT WHEN JOHN TRIED LIMIT 343, 333 HE FOUND // RETURN WOULD BE WHEN JOHN TRIEDRead the article
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preg_replace Pattern
- by codeworxx
Hey Guys, i'm not very firm with preg_replace - in other Words i do not really understand - so i hope you can help me. I have a string in a Text like this one: [demo category=1] and want to replace with the Content of Category (id=1) e.g. "This is the Content of my first Category" This is my startpoint Pattern - that's all i have: '/[demo\s*.*?]/i'; Hope you can help? Thanks, SaschaRead the article
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php preg_replace with php code
- by john
I have a function that finds a regex thingy, then replaces with php code. I want to have it replace the found regex with php code on the screen, like have it echo out ". except when it echos that in the source, it shows all theRead the article
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preg_match problem.
- by SoLoGHoST
How do I add the character - within the preg_match? preg_match('#^(\w+/){0,2}\w+\.\w+$#', $string) But it must be before the . within string. I've tried just about everything I know here. I know that the - needs to be escaped. So I tried to escape it in various places, but it's not working :( Thanks :)Read the article
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preg_match for <?php, <?, and/or ?>
- by SoLoGHoST
Hello guys, I'm not very familiar with regEx's and I'm trying to find a preg_match regex for searching for any of the following strings within a file and if found it will halt it. I already have the fopen and fgets setup I just need to use a regex inside of a preg_match for the following php tags: <?php <? ?> Thanks for your help with this :)Read the article
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Wrap link around links in tweets with php preg_replace
- by Ben Paton
Hello I'm trying to display the latest tweet using the code below. This preg_replace works great for wrapping a link round twitter @usernames but doesn't work for web addresses in tweets. How do I get this code to wrap links around urls in tweets. <?php /** Script to pull in the latest tweet */ $username='fairgroceruk'; $format = 'json'; $tweet = json_decode(file_get_contents("http://api.twitter.com/1/statuses/user_timeline/{$username}.{$format}")); $latestTweet = htmlentities($tweet[0]->text, ENT_QUOTES); $latestTweet = preg_replace('/@([a-z0-9_]+)/i', '<a href="http://twitter.com/$1" target="_blank">@$1</a>', $latestTweet); $latestTweet = preg_replace('/http://([a-z0-9_]+)/i', '<a href="http://$1" target="_blank">http://$1</a>', $latestTweet); echo $latestTweet; ?> Thanks for the help, BenRead the article
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Detecting a url using preg_match? without http:// in the string
- by Stefan
Hey there, I was wondering how I could check a string broken into an array against a preg_match to see if it started with www. I already have one that check for http://www. $stringToArray = explode(" ",$_POST['text']); foreach($stringToArray as $key=>$val){ $urlvalid = isValidURL($val); if($urlvalid){ $_SESSION["messages"][] = "NO URLS ALLOWED!"; header("Location: http://www.domain.com/post/id/".$_POST['postID']); exit(); } } Thanks! StefanRead the article
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Pulling specific entries from RSS feed [PHP]
- by n0s
So, I have an RSS feed with variations of each item. What I want to do is just get entries that contain a specific section of text. For example: <item> <title>RADIO SHOW - CF64K - 05-20-10 + WRAPUP </title> <link>http://linktoradioshow.com</link> <comments>Radio show from 05-20-10</comments> <pubDate>Thu, 20 May 2010 19:12:12 +0200</pubDate> <category domain="http://linktoradioshow.com/browse/199">Audio / Other</category> <dc:creator>n0s</dc:creator> <guid>http://otherlinktoradioshow.com/</guid> <enclosure url="http://linktoradioshow.com/" length="13005" /> </item> <item> <title>RADIO SHOW - CF128K - 05-20-10 + WRAPUP </title> <link>http://linktoradioshow.com</link> <comments>Radio show from 05-20-10</comments> <pubDate>Thu, 20 May 2010 19:12:12 +0200</pubDate> <category domain="http://linktoradioshow.com/browse/199">Audio / Other</category> <dc:creator>n0s</dc:creator> <guid>http://otherlinktoradioshow.com/</guid> <enclosure url="http://linktoradioshow.com/" length="13005" /> </item> I only want to display the results that contain the string CF64K. While it's probably really simple regex, I can't seem to wrap my head around getting it right. I always get seem to only be able to display the string 'CF64K', and not the stuff that surrounds it. Thanks in advance.Read the article
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Yet another php ereg fix
- by casben79
I have a small chunk of coding I need to take from ereg to preg_match. Here is the code. function be_file_list($d, $x) { foreach (array_diff(scandir($d), array('.', '..')) as $f) { if (is_file($d . '/' . $f) && (($x) ? ereg($x.'$',$f) : 1)) { $l[] = $f; } } return $l; } This code works as expected even if it doesn't look too pretty (source: http://www.php.net/manual/en/function.scandir.php) but as ereg is deprecated, I would really like to make it preg_match, or something like that. I have been messing with this all afternoon and the PC is about to go out the window. I would have thought that preg_match("/"$x.'$',$f"/") would have worked but no dice. Any help would be great. Cheers BenRead the article
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PHP - preg_match_all - iCalendar - REGEX
- by aSeptik
Hi All guys! ;-) i need help with creating a regex for putting all values into an array! assuming we have a huge file full of theese: Classic iCalendar style: so we know that each segment start with BEGIN:VEVENT and end with END:VEVENT ... END:VEVENT BEGIN:VEVENT UID:e3cafdf3-c5c7-427e-b8c3-653015e9321a SUMMARY:Some Text Here DESCRIPTION:Some Text Here\n555-555-555 ORGANIZER;CN=Some/Text/Here DTSTART;TZID="Some/Text/Here":20100802T190000 DTEND;TZID="Some/Text/Here":20100802T193000 STATUS:CONFIRMED CLASS:PUBLIC X-MICROSOFT-CDO-INTENDEDSTATUS:BUSY TRANSP:OPAQUE X-MICROSOFT-DISALLOW-COUNTER:TRUE DTSTAMP:20100423T021222Z SEQUENCE:1 END:VEVENT BEGIN:VEVENT ... by using preg_match_all that i think is the best choice for doing this, what's the regex that can hold all theese values into array!? PS: between segments there are no line break this is just for example! thank's to All for the time! Regards Luca FilosfiRead the article
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"string" != "string"
- by Misiur
Hi. I'm doing some kind of own templates system. I want to change <title>{site('title')}</title> Into function "site" execution with parameter "title". Here's private function replaceFunc($subject) { foreach($this->func as $t) { $args = explode(", ", preg_replace('/\{'.$t.'\(\'([a-zA-Z,]+)\'\)\}/', '$1', $subject)); $subject = preg_replace('/\{'.$t.'\([a-zA-Z,\']+\)\}/', call_user_func_array($t, $args), $subject); } return $subject; } Here's site: function site($what) { global $db; $s = $db->askSingle("SELECT * FROM ".DB_PREFIX."config"); switch($what) { case 'title': return 'Title of page'; break; case 'version': return $s->version; break; case 'themeDir': return 'lolmao'; break; default: return false; } } I've tried to compare $what (which is for this case "title") with "title". MD5 are different. strcmp gives -1, "==", and "===" return false. What is wrong? ($what type is string. You can't change call_user_func_array into call_user_func, because later I'll be using multiple arguments)Read the article
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php - regex- preg_replace - space after line-break!
- by aSeptik
Hi all guys! still on regex! i want learn it but i'm still crashing the head into my keybord! ;-) ok very trivial for you, i'm sure! Assuming i have this sting, the \s is where the space actualy is... \n where linebreak is.. DESCRIPTION: The quick brown fox jum`\s\n` `\s`ps over the lazy dog now, what i need to do is remove All the space after the A-Z: that i have achieved by this regex: /\s+(?![A-Z:])/m that produce this result DESCRIPTION: The quick brown fox jum ps over the lazy dog as you can see it leave the space between jum and ps how to have a result like this? DESCRIPTION: The quick brown fox jumps over the lazy dog thank's for the time!Read the article
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Multiple calls to preg_replace alters result
- by Hurpe
I have a bunch of files that were named in a somewhat standard format. The standard form is basically this: [integer]_word1_word2_word3_ ... _wordn where a word could really be anything, but all words are separated by an underscore. There is really only 3 things I want to do to the text: 1.) I want to modify the integer, which is always at the beginning, so that something like "200" would become $ 200.00. 2.) replace any "words" of the form "with", "With", "w/", or "W/" with "with". 3.) Replace all underscores with a space. I wrote three different preg_replace calls to do the trick. They are as follows: 1.) $filename = preg_replace("/(^[0-9]+)/","$ $1.00",$filename) 2.) $filename = preg_replace("/_([wW]|[wW]ith)_/"," with ",$filename) 3.) $filename = preg_replace("/_/"," ",$filename); Each replacement works as expected when run individually, but when all three are run, the 2nd replacement is ignored. Why would something like that occur? Thanks for the help!Read the article
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PHP - REGEX - use string for pattern but exclude it from being removed!
- by aSeptik
Hi All guys! i'm pretty new on regex, i have learned something by the way, but is still pour knowledge! so i want ask you for clarification on how it work! assuming i have the following strings, as you can see they can be formatted little different way one from another but they are very similar! DTSTART;TZID="America/Chicago":20030819T000000 DTEND;TZID="America/Chicago":20030819T010000 DTSTART;TZID=US/Pacific DTSTART;VALUE=DATE now i want replace everything between the first A-Z block and the colon so for example i would keep DTSTART:20030819T000000 DTEND:20030819T010000 DTSTART DTSTART so on my very noobs knowledge i have worked out this shitty regex! :-( preg_replace( '/^[A-Z](?!;[A-Z]=[\w\W]+):$/m' , '' , $data ); but why i'm sure this regex will not work!? :-) Pls help me! PS: the title of question is pretty explaned, i want also know how for example use a well know string block for match another... preg_replace( '/^[DTSTART](?!;[A-Z]=[\w\W]+):$/m' , '' , $data ); ..without delete DTSTART Thanks for the time! Regards Luca FilosofiRead the article
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[PHP] preg_replace: replacing using %
- by Juan
Hi all, I'm using the function preg_replace but I cannot figure out how to make it work, the function just doesn't seem to work for me. What I'm trying to do is to convert a string into a link if any word contains the % (percentage) character. For instance if I have the string "go to %mysite", I'd like to convert the mysite word into a link. I tried the following... $data = "go to %mysite"; $result = preg_replace('/(^|[\s\.\,\:\;]+)%([A-Za-z0-9]{1,64})/e', '\\1%<a href=#>\\2</a>', $data); ...but it doesn't work. Any help on this would be much appreciated. Thanks JuanRead the article
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regular expression search and replace
- by Thoman
Hello This is some code <br /> <br /> <br /> <br /> <br /> <br /> but I want replace <br /> of 4 with <hr /> And this output <br /> <br /> <br /> <hr /> <br /> <br /> Please help meRead the article
