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  • How do history generation algorithms work?

    - by Bane
    I heard of the game Dwarf Fortress, but only now one of the people I follow on Youtube made a commentary on it... I was more than surprised when I noticed how Dwarf Fortress actually generates a history for the world! Now, how do these algorithms work? What do they usually take as input, except the length of the simulation? How specific can they be? And more importantly; can they be made in Javascript, or is Javascript too slow? (I guess this depends on the depth of the simulation, but take Dwarf Fortress as an example.)

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  • Hash Algorithm Randomness Visualization

    - by clstroud
    I'm curious if anyone here has any idea how the images were generated as shown in this response: Which hashing algorithm is best for uniqueness and speed? Ian posted a very well-received response but I can't seem to understand how he went about making the images. I hate to make a new question dedicated to this, but I can't find any means to ask him more directly. On the other hand, perhaps someone has an alternative perspective. The best I can personally come up with would be to have it almost like a bar graph, which would illustrate how evenly the buckets of the hash table are being generated. I have a working Cocoa program that does this, but it can't generate anything like what he showed there. So the question is two fold I suppose: A) How does one truly interpret the data he shows? Is it more than "less whitespace = better"? B) How does one generate such an image based on some set of inputs, a hash, and an index? Perhaps I'm misunderstanding entirely, but I really would like to know more about this particular visualization technique. Or maybe I'm mis-applying this to hash tables rather than just hashes in general, but in that case I don't know how it would be "bounded" for the image.

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  • Is there a (family of) monotonically non-decreasing noise function(s)?

    - by Joe Wreschnig
    I'd like a function to animate an object moving from point A to point B over time, such that it reaches B at some fixed time, but its position at any time is randomly perturbed in a continuous fashion, but never goes backwards. The objects move along straight lines, so I only need one dimension. Mathematically, that means I'm looking for some continuous f(x), x ? [0,1], such that: f(0) = 0 f(1) = 1 x < y ? f(x) = f(y) At "most" points f(x + d) - f(x) bears no obvious relation to d. (The function is not uniformly increasing or otherwise predictable; I think that's also equivalent to saying no degree of derivative is a constant.) Ideally, I would actually like some way to have a family of these functions, providing some seed state. I'd need at least 4 bits of seed (16 possible functions), for my current use, but since that's not much feel free to provide even more. To avoid various issues with accumulation errors, I'd prefer the function not require any kind of internal state. That is, I want it to be a real function, not a programming "function".

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  • How Would a Single Laptop Affect the Past? [Infographic Comic]

    - by Asian Angel
    What kind of impact could a single laptop have if it were introduced to people during key periods in Western history? This infographic comic provides some speculation on what the results could be like… View the Full-Size Version Crave asks: How would you change the past with a laptop? [CNET - Crave] The HTG Guide to Hiding Your Data in a TrueCrypt Hidden Volume Make Your Own Windows 8 Start Button with Zero Memory Usage Reader Request: How To Repair Blurry Photos

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  • The Internet – Then and Now (1996 versus 2011) [Infographic]

    - by Asian Angel
    Use the link below to view the entire infographic. Keep in mind that it may take a few moments for it to load due to its large size. True Hollywood Story: Bipeds and the World Wide Web [infographic] [via TinyHacker] How to See What Web Sites Your Computer is Secretly Connecting To HTG Explains: When Do You Need to Update Your Drivers? How to Make the Kindle Fire Silk Browser *Actually* Fast!

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  • How to divide hex grid evenly among n players?

    - by manabreak
    I'm making a simple hex-based game, and I want the map to be divided evenly among the players. The map is created randomly, and I want the players to have about equal amount of cells, with relatively small areas. For example, if there's four players and 80 cells in the map, each of the players would have about 20 cells (it doesn't have to be spot-on accurate). Also, each player should have no more than four adjacent cells. That is to say, when the map is generated, the biggest "chunks" cannot be more than four cells each. I know this is not always possible for two or three players (as this resembles the "coloring the map" problem), and I'm OK with doing other solutions for those (like creating maps that solve the problem instead). But, for four to eight players, how could I approach this problem? As always, any and all help is appreciated. :)

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  • Camera placement sphere for an always fully visible object

    - by BengtR
    Given an object: With the bounds [x, y, z, width, height, depth] And an orthographic projection [left, right, bottom, top, near, far] I want to determine the radius of a sphere which allows me to randomly place my camera on so that: The object is fully visible from all positions on this sphere The sphere radius is the smallest possible value while still satisfying 1. Assume the object is centered around the origin. How can I find this radius? I'm currently using sqrt(width^2 + height^2 + depth^2) but I'm not sure that's the correct value, as it doesn't take the camera into account. Thanks for any advice. I'm sorry for confusing a few things here. My comments below should clarify what I'm trying to do actually.

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  • How to create reproducible probability in map generation?

    - by nickbadal
    So for my game, I'm using perlin noise to generate regions of my map (water/land, forest/grass) but I'd also like to create some probability based generation too. For instance: if(nextInt(10) > 2 && tile.adjacentTo(Type.WATER)) tile.setType(Type.SAND); This works fine, and is even reproduceable (based on a common seed) if the nextInt() calls are always in the same order. The issue is that in my game, the world is generated on demand, based on the player's location. This means, that if I explore the map differently, and the chunks of the map are generated in a different order, the randomness is no longer consistent. How can I get this sort of randomness to be consistent, independent of call order? Thanks in advance :)

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  • Randomization of biomes

    - by user24527
    You know how in Minecraft, the World is ever-expanding and all the biomes are randomized? My generalized question is: In relation to a space simulation that is also ever-expanding as the player moves about the world, how would one go about programming this randomization in Java? My real question is: Could I get a simplified example broken down into these example classes: astroids (This would include how many astroids there are, their positioning in space, their size, how often the larger astroids occur, how close they are to each other, the limitations of how many of the large asteroids can be in one field, how often astroid fields are generated, etc.) star-types (size, color, type, how often they occur, where hey occur, etc.) inhabitable-planets (size, positioning, how often they're generated, where they are generated, etc.) This would be very helpful currently since I wish to make a simplified version of such a program.

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  • How to split a string with negative numbers using ActionScript 3.0

    - by inzombiak
    I'm having trouble loading my level. I'm using Ogmo to create my level then I import it. I have no problem converting 0's and 1's into an Array, but I can't figure out how to do the same for -1's. It separates the "-" and the "1". Any help would be great. I've posted my code and the XML files below levelXML = new XML(e.target.data); playerX = int(levelXML.Entities.Player.@x); playerY = int(levelXML.Entities.Player.@y); levelGrid = levelXML.Grid; levelGrid = levelGrid.split("\n").join(""); levelTiles = levelXML.Tiles; levelTiles = levelTiles.split("\n").join(""); levelTiles = levelTiles.split(",").join(""); tileArray = levelTiles.split(""); gridArray = levelGrid.split(""); for(i = 0; i <= 34; i++) { levelArray[i] = new Array(); for(j = 0; j <= 34; j++) { if(tileArray[j*35 + i] == 0) { gridArray[j*35+i] = -1; } var currentSymbol = gridArray[j*35+i]; levelArray[i][j] = currentSymbol; if(gridArray[j*35 + i] == 1) { wall = new Wall; addChild(wall); wall.x = i*20 + 10; wall.y = j*20 + 10; } else if(gridArray[j*35 + i] == -1) { pellet = new Pellet; addChild(pellet); pellet.x = i*20 + 10; pellet.y = j*20 + 10; } } } I know the code is very dirty, but I needed a quick fix. Grid exportMode="Bitstring" 11111111111111111111111111111111111 10000000000000000011000000000000001 10000000000000000011000000000000001 10011111001111110011001111110011001 10011111001111110011001111110011001 10011111001111110011001111110011001 10000000000000000000000000000000001 10000000000000000000000000000000001 10011111001100111111100110011111001 10011111001100000100000110011111001 10000000001100000100000110000000001 10000000001111100100111110000000001 11111111001111100100111110011111111 00000001001111100100111110010000000 00000001001100000000000110010000000 11111111001100000000000110011111111 00000000000000111111100000000000000 00000000000000100000100000000000000 11111111001100100000100110011111111 00000001001100111111100110010000000 00000001001100000000000110010000000 11111111001100111111100110011111111 10000000000000000100000000000000001 10000000000000000100000000000000001 10011111001111100100111110011111001 10000011000000000000000000011000001 10000011000000000000000000011000001 11110011001100111111100110011001111 11110011001100111111100110011001111 10000000001100000100000110000000001 10000000001100000100000110000000001 10011111111111100100111111111111001 10000000000000000000000000000000001 10000000000000000000000000000000001 11111111111111111111111111111111111 Tiles tileset="Tiles" exportMode="CSV"-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,0,0,0,0,0,0,0,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,-1 -1,-1,-1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1

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  • SEO - A Game of Numbers and Strategy

    Traditional marketing strategy would capitalize on the usual television commercial, banner ads, holding a social event to promote your new product, print ads and more. However, these portfolios might be missing one vital ingredient: the internet. Over one billion people have the access to internet.

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  • Finite Numbers and ExplorerCanvas

    - by PhubarBaz
    I was working on my online mathematical graphing application, CloudGraph, and trying to make it work in IE. The app uses the HTML5 canvas element to draw graphs. Since IE doesn't support canvas yet I use ExplorerCanvas to provide that support for IE. However, it seems that when using excanvas, if you try to moveTo or drawTo a point that is not finite it loses it's mind and stops drawing anything else after that. I had no such problems in Firefox or Chrome so it took me awhile to figure out what was going on. Next I discovered that I needed a way to check if a variable was NaN or Inifinity or any other non-finite value so I could avoid calling moveTo() in that case. I started writing a long if statement, then I thought there has to be a better way. Sure enough there was. There just happens to be an isFinite() function built into Javascript just for this purpose. Who knew! It works great. Another difference I discovered with excanvas is that you must specify a starting point using a moveTo() when beginning a drawing path. Again, Chrome and Firefox are a lot more forgiving in this area so it took me a while to figure out why my lines weren't drawing. But, all is happy now and I'm a little wiser to the ways of the canvas.

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  • Why is it an issue that it takes 2 digits to represent the number 10 in decimal?

    - by Crizly
    So we use hexadecimal which has the advantage of going up to 15 in single digits A-F, but why is it an issue that it takes 2 digits to represent the number 10 in decimal? I was reading up about hexadecimal and I came across these 2 lines: Base 16 suggests the digits 0 to 15, but the problem we face is that it requires 2 digits to represent 10 to 15. Hexadecimal solves this problem by using the letters A to F. My question is, why do we care how many digits it takes to represent 15? What is the importance of this number, and how does denoting it with a single character have any value?

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  • Facebook Insights numbers don't add up

    - by ChristopherJ
    I'm having trouble understanding the Facebook stats for a Fan page under reach as they don't seem to add up. Under the reach tab, if I expand the countries demographics at the top, then the countries listed add up to around 16k people. But scrolling down under reach, the graph reaches as high as 260k in a particular week. From what they say, it seems that both the graph and demographics are talking about unique users, so where are the other 244k unique users that are in the graph but seemingly not from any country on Earth?

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  • Can I randomly generate an endless road?

    - by y26jin
    So suppose we stand on a position(x0, y0) of a map. We can only move on the horizontal plane(no jump and stuff) but we can move forward, left, or right (in a discrete math way, i.e. integer movement). As soon as we move to the next position(x1, y1), everything around us is generated randomly by a program. We could be surrounded by one of mountain, lake, and road. We can only move on the road. The road is always 2D as the map itself. My question is, are we able to play this game endlessly? "End" means that we come across a dead end and the only way out is to go backward.

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  • Problem with currency formats and big numbers [on hold]

    - by user132750
    I am working on a dollars to euros/euros to dollars converter in C#. I got the formula, $ times 0.73361 = euro, and I have checked Google with the answers. They were right, (1 dollar equals 0.73 euros). However, it stops working properly when the dollar input value is higher than $1363. This is what I get with $1364: $1364 = 1 000,64 €. I don't know what to do, will someone please help me? Thanks. decimal toEuro; Val.doy = "$" + decimal.Parse(richTextBox1.Text); //Ignore this, it's for the output form CultureInfo eu = new CultureInfo("fr-FR"); toEuro = decimal.Parse(richTextBox1.Text.Trim()); toEuro = toEuro * 0.73361m; richTextBox1.Clear(); Val.duh = toEuro.ToString("C2", eu);

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  • Random point on VideoDisplay isn't accurate enough

    - by Mike
    For a schoolassigment me and some buddies of mine are creating an application that is showing many similarities with the C-Mon & Kypski musicvideo on www.oneframeoffame.com. The application is being developed in Flex. We want to get a random point of a clip, let it pause so a user can mimic the pose and make a snapshot out of it. What i managed to do is get a random point of the movie. I did this by getting a random value between 0 and de total duration of the movie. But what i didn't managed to do is let the screen pause on every 24st of a frame. As the movie concist out of 24FPS. It looks like the the random value of the movie that is being requested is being rounded by the movie itself. As example: There appears to be no difference between the frames requested at 2.40 or 2.41. It appears it got something to do with keyframing i've read on the Adobe® Flex™ 3.5 Language Reference. The movie is a FLV file and i use the VideoDisplay object to display the movie. Does someone is familiar with this or knows a solution to my problem? Thanks in advance

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  • Javascript CS-PRNG - 64-bit random

    - by Jack
    Hi, I need to generate a cryptographically secure 64-bit unsigned random integer in Javascript. The first problem is that Javascript only allows 64-bit signed integers, so 9223372036854775808 is the biggest supported integer without going into floating point use I think? To fix this I can use a big number library, no problem. My Method: var randNum = SHA256( randBigInt(128, 0) ) % 2^64; Where SHA256() is a secure hash function and randBigInt() is defined below as a non-crypto PRNG, im giving it a 128bit seed so brute force shouldn't be a problem. randBigInt(n,s) //return an n-bit random BigInt (n>=1). If s=1, then the most significant of those n bits is set to 1. Is this a secure method to generate a cryptographically secure 64-bit random int? And importantly does taking the 2^64 mod guarantee 100% I have a 64-bit number? An abstract example, say this number is prime (it isn't i know), I will use it in the Galois Field [2^p], where p must be 64bits so that every possible 1-63bit number is a field element. In this query, my random int must be larger than any 63-bit number. And Im not sure im correct in taking the 2^64 mod of a 256bit hash output. Thanks (hope that makes sense)

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  • Copy a LinkedList that has a Random Pointer in it

    - by Bragaadeesh
    Hi, First of all this is not a homework, this is an interview question that I got from a company I attended today. You have a singly linked list with the Node structure as the following class Node{ int data; Node next; Node random; } You have a typical singly linked list of length n. The random pointer in each node in the linkedlist randomly points to some Node within the linked list. The Question is to create a copy of the linked list efficiently into a different LinkedList. I said that I will first calculate the Random pointer's position in the linked list and store it in an array. Then create a new linked list normally. Then iterate through the linked list by setting the random pointer where they belong by reading the values stored from the array. I know its a very brute force technique and the interviewer asked me to come up with a better solution but I couldnt. Please can someone answer this? I can explain if the question is not clear.

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  • Random freezes with Magix Music Maker 16

    - by NoCanDo
    Howdy, I'm experiencing random freezes in Magix Music Maker 16 on my Win7 platform. I'm running the app in admin mode btw. The freezes quite often occur after I load my compiled song and try to listen to different soundloops OR just seemingly randomly. Anyone know a solution?

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  • Best way to manually sort random text files?

    - by Jane
    I have about 1000 text files and I need to view each, and move it to a folder if it's the correct one. I can only do basic sorting by length/size, and I can't grep because the text is random. How can I do this besides manually openiing + saving each in gedit. I'm on Ubuntu Linux. Thanks

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