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  • PHP parsing XML file with and without namespaces

    - by Mike
    I need to get a XML File into a Database. Thats not the problem. Cant read it, parse it and create some Objects to map to the DB. Problem is, that sometimes the XML File can contain namespaces and sometimes not. Furtermore sometimes there is no namespace defined at all. So what i first got was something like this: <?xml version="1.0" encoding="UTF-8"?> <struct xmlns:b="http://www.w3schools.com/test/"> <objects> <object> <node_1>value1</node_1> <node_2>value2</node_2> <node_3 iso_land="AFG"/> <coords lat="12.00" long="13.00"/> </object> </objects> </struct> And the parsing: $t = $xml->xpath('/objects/object'); foreach($nodes AS $node) { if($t[0]->$node) { $obj->$node = (string) $t[0]->$node; } } Thats fine as long as there are no namespaces. Here comes the XML File with namespaces: <?xml version="1.0" encoding="UTF-8"?> <b:struct xmlns:b="http://www.w3schools.com/test/"> <b:objects> <b:object> <b:node_1>value1</b:node_1> <b:node_2>value2</b:node_2> <b:node_3 iso_land="AFG"/> <b:coords lat="12.00" long="13.00"/> </b:object> </b:objects> </b:struct> I now came up with something like this: $xml = simplexml_load_file("test.xml"); $namespaces = $xml->getNamespaces(TRUE); $ns = count($namespaces) ? 'a:' : ''; $xml->registerXPathNamespace("a", "http://www.w3schools.com/test/"); $nodes = array('node_1', 'node_2'); $obj = new stdClass(); foreach($nodes AS $node) { $t = $xml->xpath('/'.$ns.'objects/'.$ns.'object/'.$ns.$node); if($t[0]) { $obj->$node = (string) $t[0]; } } $t = $xml->xpath('/'.$ns.'objects/'.$ns.'object/'.$ns.'node_3'); if($t[0]) { $obj->iso_land = (string) $t[0]->attributes()->iso_land; } $t = $xml->xpath('/'.$ns.'objects/'.$ns.'object/'.$ns.'coords'); if($t[0]) { $obj->lat = (string) $t[0]->attributes()->lat; $obj->long = (string) $t[0]->attributes()->long; } That works with namespaces and without. But i feel that there must be a better way. Before that i could do something like this: $t = $xml->xpath('/'.$ns.'objects/'.$ns.'object'); foreach($nodes AS $node) { if($t[0]->$node) { $obj->$node = (string) $t[0]->$node; } } But that just wont work with namespaces.

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  • XSLT, JSTL e JSF

    - by Paulo S.
    I have a xml file which I want to transform in a jsf code page. To do that I've created a xsl file. xml: <?xml version='1.0' encoding='ISO-8859-1'?> <questionario xmlns:xsi='http://www.w3.org/2001/XMLSchema-instance' xsi:noNamespaceSchemaLocation='Schema2.xsd'> <componente nome='input'> <id>input1</id> </componente> <componente nome='input'> <id>input2</id> </componente> </questionario> code: <%@ taglib uri="http://java.sun.com/jstl/core_rt" prefix="c" %> <%@ taglib uri="http://java.sun.com/jsp/jstl/xml" prefix="x" %> <c:set var="xml" value="${questionarioXSLBean.xml}"/> <c:set var="xsl"> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0" xmlns:f="http://java.sun.com/jsf/core" xmlns:h="http://java.sun.com/jsf/html" exclude-result-prefixes="f h"> <xsl:template match="/"> <xsl:for-each select="questionario/componente"> <xsl:if test="attribute::nome = 'input'"> <xsl:variable name="id"> <xsl:value-of select="id" /> </xsl:variable> <h:inputText id="{$id}"/> </xsl:if> </xsl:for-each> </xsl:template> </xsl:stylesheet> </c:set> <x:transform xml="${xml}" xslt="${xsl}" /> The problem is that nothing is shown in my screen because the generated code for <h:inputText id="input1"/> is <h:inputText id="input_1" xmlns:h="http://java.sun.com/jsf/html"/> how can I replace the xmlns:h="http://java.sun.com/jsf/html" or suppress it. Thanks! Update: Let me clarify what I want to do. I want to generate a jsf page dynamically depending on the attributes of a xml file, for instance, 2 input texts, 3 check boxes, etc. To make the transformation to jsf I thought in two approaches, one using jstl and another using xslt. The problem with the former is that I couldn't integrate jstl with jsf code (to set jsf components attributes using jstl variables) and with the last approach, I'm facing the problem described above.I wouldn't like to create components in java (UIComponents). Any suggestions?

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  • Pattern Matching with XSLT

    - by genesis11
    I'm trying to match a pattern into a string in XSLT/XPath using the matches function, as follows: <xsl:when test="matches('awesome','awe')"> ... </xsl:when> However, in both Firefox 3.5.9 and IE8, it doesn't show up. IE8 tells me that "'matches' is not a valid XSLT or XPath function." Is this due to XSLT 2.0 not being supported, and is there a way around this?

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  • javascript-aware html parser for Python ~

    - by znetor
    <html> <head> <script type="text/javascript"> document.write('<a href="http://www.google.com">f*** js</a>'); document.write("f*** js!"); </script> </head> <body> <script type="text/javascript"> document.write('<a href="http://www.google.com">f*** js</a>'); document.write("f*** js!"); </script> <div><a href="http://www.google.com">f*** js</a></div> </body> </html> I want use xpath to catch all lable object in the html page above... In [1]: import lxml.html as H In [2]: f = open("test.html","r") In [3]: c = f.read() In [4]: doc = H.document_fromstring(c) In [5]: doc.xpath('//a') Out[5]: [<Element a at a01d17c>] In [6]: a = doc.xpath('//a')[0] In [7]: a.getparent() Out[7]: <Element div at a01d41c> I only get one don't generate by js~ but firefox xpath checker can find all lable!? http://i.imgur.com/0hSug.png how to do that??? thx~! <html> <head> </head> <body> <script language="javascript"> function over(){ a.innerHTML="mouse me" } function out(){ a.innerHTML="<a href='http://www.google.com'>google</a>" } </script> <body><li id="a"onmouseover="over()" onmouseout="out()">mouse me</li> </body> </html>

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  • GWT + XML documents with namespaces

    - by chris_l
    I'd like to get a quick overview of available solutions (libraries, ...) that allow me to work with XML documents with namespaces on a DOM level - in GWT's client side. Additionally, I'm looking for an XPath solution that can work on that DOM (even if it requires writing my own XPath Navigator). XML parsing and serialization isn't necessary on the client - this can be done on the server.

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  • Emphasized text in docbook, fo, pdf out put.

    - by Mica
    I am trying to emphasize a character of some static text to render into the footer of my pdf, but can't figure out the right combination of tags in my xsl. How can I accomplish this? Example: <!-- Footer content --> <xsl:template name="footer.content"> <xsl:param name="pageclass" select="''"/> <xsl:param name="sequence" select="''"/> <xsl:param name="position" select="''"/> <xsl:param name="gentext-key" select="''"/> <fo:block> <xsl:choose> ... <xsl:when test="$sequence = 'odd' and $position = 'left'"> <xsl:text>&#x00A9;<emphasis>My</emphasis>Company</xsl:text> </xsl:when> ... </xsl:choose> </fo:block> </xsl:template> This example generates an error in xsltproc. Help!

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  • XML cross-browser support

    - by 1anthony1
    I need help getting the file to run in Firefox: I have tried adapting scripts so that my file runs in both IE and Firefox but so far it still only works in IE. (The file can be tested at http://www.eyle.org/crosstest.html - simply type the word Mike in the text box using IE (doesn't work in Firefox).The HTML document is: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> <script type="text/javascript"> var xmlDoc; //loads xml using either IE or firefox function loadXmlDoc() { //test for IE if(window.ActiveXObject) { xmlDoc = new ActiveXObject("Microsoft.XMLDOM"); xmlDoc.async = false; xmlDoc.load("books2.xml"); } //test for Firefox else if(document.implementation && document.implementation.createDocument) { xmlDoc = document.implementation.createDocument("","",null); xmlDoc.load("books2.xml"); } //if neither else {document.write("xml file did not load");} } //window.onload = loadXmlDoc(); var subject; //getDetails adds value of txtField to var subject in outputgroup(subject) function getDetails() { //either this or window.onload = loadXmlDoc is needed loadXmlDoc(); var subject = document.getElementById("txtField1").value; function outputgroup(subject) { var xslt = new ActiveXObject("Msxml2.XSLTemplate"); var xslDoc = new ActiveXObject("Msxml2.FreeThreadedDOMDocument"); var xslProc; xslDoc.async = false; xslDoc.resolveExternals = false; xslDoc.load("contains3books.xsl"); xslt.stylesheet = xslDoc; xslProc = xslt.createProcessor(); xslProc.input = xmlDoc; xslProc.addParameter("subj", subject); xslProc.transform(); document.write(xslProc.output); } outputgroup(subject); } </script> </head> <body> <input type="text" id="txtField1"> <input type="submit" onClick="getDetails(); return false"> </body> </html> The file includes books2.xml and contains3books.xsl (I have put the code for these files at ...ww.eyle.org/books2.xml ...ww.eyle.org/contains3books.xsl) (NB: replace ...ww. with http: // www)

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  • XSLT Pagination

    - by dbomb101
    I have created a xslt document which formats an xml document, but I would like the results from the xslt sheet to be paginated. here is the orginal xlst document <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/> <xsl:template match="/"> <xsl:for-each select="musicInformation/musicdetails"> <label for="artistname{position()}" id="artistnameLabel{position()}">Artist Name:</label> <span id ="artistname{position()}"><xsl:value-of select="artistname" /></span> <br/> <label for="recordname{position()}" id="recordnameLabel{position()}">Record Name:</label> <span id ="recordname{position()}"><xsl:value-of select="recordname" /></span> <br/> <label for="recordtype{position()}" id="recordtypeLabel{position()}">Record Type:</label> <span id ="recordtype{position()}"><xsl:value-of select="recordtype" /></span> <br/> <label for="format{position()}" id="formatLabel{position()}">Format:</label> <span id ="format{position()}"><xsl:value-of select="format" /></span> <br/> <a href="xmlDetail.php?mid={@m_id}" >See Details</a> <br/><br/> </xsl:for-each> </xsl:template> </xsl:stylesheet>

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  • Actually XSLT Lookup (Store variables during loop and use in it another template)

    - by krisvandenbergh
    Is there a way to store a variable/param during a for-each loop in a sort of array, and use it in another template, namely <xsl:template match="Foundation.Core.Classifier.feature">. All the classname values that appear during the for-each should be stored. How would you implement that in XSLT? Here's my current code. <xsl:for-each select="Foundation.Core.Class"> <xsl:for-each select="Foundation.Core.ModelElement.name"> <xsl:param name="classname"> <xsl:value-of select="Foundation.Core.ModelElement.name"/> </xsl:param> </xsl:for-each> <xsl:apply-templates select="Foundation.Core.Classifier.feature" /> </xsl:for-each> Here's the template in which the classname parameters should be used. <xsl:template match="Foundation.Core.Classifier.feature"> <xsl:for-each select="Foundation.Core.Attribute"> <owl:DatatypeProperty rdf:ID="{Foundation.Core.ModelElement.name}"> <rdfs:domain rdf:resource="$classname" /> </owl:DatatypeProperty> </xsl:for-each> </xsl:template> The input file can be found at http://krisvandenbergh.be/uml_pricing.xml

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  • Access data of a XSL file from a JSF...

    - by Asela
    Hi all, I'm having 2 simple XML & XSL files as follows. form_1.xml <?xml version="1.0" encoding="windows-1252"?> <?xml-stylesheet type="text/xsl" href="form_1.xsl"?> <myform> </myform> form_1.xsl <?xml version="1.0" encoding="windows-1252"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="myform"> <html> <body> <form> <div align="center"> <h2>My first form in XSL</h2> <table cellspacing="1" cellpadding="1"> <tr> <td>First name : </td> <td> <input type="text"></input> </td> </tr> <tr> <td>Last name : </td> <td> <input type="text"></input> </td> </tr> <tr> <td>Address : </td> <td> <input type="text"></input> </td> </tr> </table> </div> </form> </body> </html> </xsl:template> </xsl:stylesheet> Now I have a JSF file where I have embeded the form_1.xml file inside an iFrame. Inside my JSF, I have submit & reset buttons as follows. myJsf.xhtml <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xmlns:h="http://java.sun.com/jsf/html" xmlns:f="http://java.sun.com/jsf/core" xmlns:ui="http://java.sun.com/jsf/facelets" xmlns:utils="http://java.sun.com/jsf/composite/utils"> <h:head> <title>::: The form filler application :::</title> <link href="./css/styles.css" rel="stylesheet" type="text/css" /> </h:head> <h:body> <div align="center"> <table cellspacing="2" cellpadding="2"> <tr> <th class="title">&nbsp; My form filler &nbsp;</th> </tr> </table> <br /> <fieldset><legend>Fill appropriate data in the following form</legend> <h:form> <div align="center"> <table> <tr> <td colspan="2"><iframe src="form_1.xml" frameborder="0" width="500px" height="500px"></iframe></td> </tr> <tr></tr> <tr> <td align="right"><h:commandButton value="Save data" action="#{myManagedBean.printValuesEnteredInTheForm}" /></td> <td align="left"><h:commandButton type="reset" value="Clear" /></td> </tr> </table> </div> </h:form></fieldset> </div> </h:body> </html> Now my question is that upon clicking the Submit button in my JSF, how do I access the values which I have entered in the XSL file? Any help is greatly appreciated. Thanks in advance. Reagrds, Asela.

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  • How to fetch particular element from string after splitting it, using XSLT split() ?

    - by Vijay
    Hi All, I have one query regarding XSLT functions. I am using split function to fetch values from a string. I am using separator as "*". e.g. String : {"item1*item2*item3*item4"} split function I am using is as; <xsl:template name="SplitItemsCollection"> <xsl:param name="list" select="''"/> <xsl:param name="separator" select="'*'"/> <xsl:if test="not($list = '' or $separator = '')"> <xsl:variable name="head" select="substring-before(concat($list, $separator), $separator)"/> <xsl:variable name="tail" select="substring-after($list, $separator)"/> <xsl:value-of select="$head"/> <xsl:call-template name="split"> <xsl:with-param name="list" select="$tail"/> <xsl:with-param name="separator" select="$separator"/> </xsl:call-template> </xsl:if> </xsl:template> This function returns me all the items. Is there any way to fetch particular item from these separated items ? Say I want to fetch item3. Can we do it directly ? Thanks in advance.

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  • DotNetNuke + XPath = Custom navigation menu DNNMenu HTML render

    - by Rui Santos
    I'm developing a skin for DotNetNuke 5 using the Component DNN Done Right menu by Mark Alan which uses XSL-T to convert the XML sitemap into an HTML navigation. The XML sitemap outputs the following structure: <Root > <root > <node id="40" text="Home" url="http://localhost/dnn/Home.aspx" enabled="1" selected="0" breadcrumb="0" first="1" last="0" only="0" depth="0" > <node id="58" text="Child1" url="http://localhost/dnn/Home/Child1.aspx" enabled="1" selected="0" breadcrumb="0" first="1" last="0" only="0" depth="1" > <keywords >Child1</keywords> <description >Child1</description> <node id="59" text="Child1 SubItem1" url="http://localhost/dnn/Home/Child1/Child1SubItem1.aspx" enabled="1" selected="0" breadcrumb="0" first="1" last="0" only="0" depth="2" > <keywords >Child1 SubItem1</keywords> <description >Child1 SubItem1</description> </node> <node id="60" text="Child1 SubItem2" url="http://localhost/dnn/Home/Child1/Child1SubItem2.aspx" enabled="1" selected="0" breadcrumb="0" first="0" last="0" only="0" depth="2" > <keywords >Child1 SubItem2</keywords> <description >Child1 SubItem2</description> </node> <node id="61" text="Child1 SubItem3" url="http://localhost/dnn/Home/Child1/Child1SubItem3.aspx" enabled="1" selected="0" breadcrumb="0" first="0" last="1" only="0" depth="2" > <keywords >Child1 SubItem3</keywords> <description >Child1 SubItem3</description> </node> </node> <node id="65" text="Child2" url="http://localhost/dnn/Home/Child2.aspx" enabled="1" selected="0" breadcrumb="0" first="0" last="1" only="0" depth="1" > <keywords >Child2</keywords> <description >Child2</description> <node id="66" text="Child2 SubItem1" url="http://localhost/dnn/Home/Child2/Child2SubItem1.aspx" enabled="1" selected="0" breadcrumb="0" first="1" last="0" only="0" depth="2" > <keywords >Child2 SubItem1</keywords> <description >Child2 SubItem1</description> </node> <node id="67" text="Child2 SubItem2" url="http://localhost/dnn/Home/Child2/Child2SubItem2.aspx" enabled="1" selected="0" breadcrumb="0" first="0" last="1" only="0" depth="2" > <keywords >Child2 SubItem2</keywords> <description >Child2 SubItem2</description> </node> </node> </node> </root> </Root> My Goal is to render this XML block into this HTML Navigation structure only using UL's LI's, etc.. <ul id="topnav"> <li> <a href="#" class="home">Home</a> <!-- Parent Node - Depth0 --> <div class="sub"> <ul> <li><h2><a href="#">Child1</a></h2></li> <!-- Parent Node 1 - Depth1 --> <li><a href="#">Child1 SubItem1</a></li> <!-- ChildNode - Depth2 --> <li><a href="#">Child1 SubItem2</a></li> <!-- ChildNode - Depth2 --> <li><a href="#">Child1 SubItem3</a></li ><!-- ChildNode - Depth2 --> </ul> <ul> <li><h2><a href="#">Child2</a></h2></li> <!-- Parent Node 2 - Depth1 --> <li><a href="#">Child2 SubItem1</a></li> <!-- ChildNode - Depth2 --> <li><a href="#">Child2 SubItem2</a></li> <!-- ChildNode - Depth2 --> </ul> </div> </li> </ul> Can anyone help with the XSL coding? I'm just starting now with XSL..

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  • Calling a .NET C# class from XSLT

    - by HanSolo
    If you've ever worked with XSLT, you'd know that it's pretty limited when it comes to its programming capabilities. Try writing a for loop in XSLT and you'd know what I mean. XSLT is not designed to be a programming language so you should never put too much programming logic in your XSLT. That code can be a pain to write and maintain and so it should be avoided at all costs. Keep your xslt simple and put any complex logic that your xslt transformation requires in a class. Here is how you can create a helper class and call that from your xslt. For example, this is my helper class:  public class XsltHelper     {         public string GetStringHash(string originalString)         {             return originalString.GetHashCode().ToString();         }     }   And this is my xslt file(notice the namespace declaration that references the helper class): <?xml version="1.0" encoding="UTF-8" ?> <xsl:stylesheet  xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0" xmlns:ext="http://MyNamespace">     <xsl:output method="text" indent="yes" omit-xml-declaration="yes"/>     <xsl:template  match="/">The hash code of "<xsl:value-of select="stringList/string1" />" is "<xsl:value-of select="ext:GetStringHash(stringList/string1)" />".     </xsl:template> </xsl:stylesheet>   Here is how you can include the helper class as part of the transformation: string xml = "<stringList><string1>test</string1></stringList>";             XmlDocument xmlDocument = new XmlDocument();             xmlDocument.LoadXml(xml);               XslCompiledTransform xslCompiledTransform = new XslCompiledTransform();             xslCompiledTransform.Load("XSLTFile1.xslt");               XsltArgumentList xsltArgs = new XsltArgumentList();                        xsltArgs.AddExtensionObject("http://MyNamespace", Activator.CreateInstance(typeof(XsltHelper)));               using (FileStream fileStream = new FileStream("TransformResults.txt", FileMode.OpenOrCreate, FileAccess.ReadWrite, FileShare.ReadWrite))             {                 // transform the xml and output to the output file ...                 xslCompiledTransform.Transform(xmlDocument, xsltArgs, fileStream);                            }

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  • How to create a HTML5 + SVG document using the PHP XSLTProcessor

    - by Kau-Boy
    For a little project about XML I try to use HTML5 as it has SVG and WAI-ARIA Support. I also want to use a XSL stylesheet for my document. But I can't get a valid HTML5 document with a nested SVG. Here are some version I tested so far: <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output indent="yes" method="xml"/> <xsl:template match="/"> <html xmlns="http://www.w3.org/1999/xhtml"> // content with the svg tag in the body </html> </xsl:template> </xsl:stylesheet> In combination with header('Content-Type: application/xml'); it works and produces this HTML output: <?xml version="1.0"?> <html xmlns="http://www.w3.org/1999/xhtml"> // content with the svg tag in the body </html> But it is not HTML5 and without a DOCTYPE I get a lot of errors on the W3 validator. So trying to get a HTML5 document I used the following XSL: <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output indent="yes" method="html"/> <xsl:template match="/"> <xsl:text disable-output-escaping='yes'>&lt;!DOCTYPE HTML></xsl:text> <html> // content with the svg tag in the body </html> </xsl:template> </xsl:stylesheet> But unfortunately that will produce thze following HTML output: <!DOCTYPE HTML> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> .... </head> // content with the svg tag in the body </html> As you can see it's regular HTML5 but using it in combination with header('Content-Type: application/xml'); it fails because of the missing slash at the end of the meta tag (which was automatically created). Using header('Content-Type: image/xhtml+svg'); or header('Content-Type: text/html'); there is no XML parsing error, but the page will not show the SVG as a graph but as text (without the tags). Can anyone tell me how to avoid the meta tag to be inserted or how to set a propper Content-Type that will make the browser rendern the SVG. Or even any other hint to get this working. I would really like to keep HTML5 to be able to keep the WAI-ARIA Landmark Roles an the HTML5 tags like NAV and FOOTER.

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  • nested for-each loops in xml

    - by user1748443
    I'm new to XML. I'm trying to create table containing item details and another table to contain customer details for each order on a picklist. It seems like it should be straightforward but I just get a list of all items on all orders repeated by the number of orders. What am I doing wrong? (XSL code below...) <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0" xmlns:xsl = "http://www.w3.org/1999/XSL/Transform"> <xsl:output method="html" doctype-system="about:legacy-compat"/> <xsl:template match="/"> <html xmlns = "http://www.w3.org/1999/xhtml"> <head> <meta charset="utf-8"/> <link rel="stylesheet" type="css/text" href="style.css"/> <title>Orders</title> </head> <body> <xsl:for-each select="//order"> <table> <caption><h3>Order Information</h3></caption> <thead> <th align="left">Item Id</th> <th align="left">Item Description</th> <th align="left">Quantity</th> <th align="left">Price</th> </thead> <xsl:for-each select="//item"> <tr> <td align="left"><xsl:value-of select="itemId"/></td> <td align="left"><xsl:value-of select="itemName"/></td> <td align="left"><xsl:value-of select="quantity"/></td> <td align="left"><xsl:value-of select="price"/></td> </tr> </xsl:for-each> </table> <table> <caption><h3>Customer Information</h3></caption> <thead> <th align="left">Customer Name</th> <th align="left">Street</th> <th align="left">City</th> </thead> <xsl:for-each select="//item"> <tr> <td align="left"><xsl:value-of select="customerName"/></td> <td align="left"><xsl:value-of select="street"/></td> <td align="left"><xsl:value-of select="city"/></td> </tr> </xsl:for-each> </table> </xsl:for-each> </body> </html> </xsl:template> </xsl:stylesheet> This is the XML: <?xml version="1.0" encoding="utf-8"?> <?xml-stylesheet type="text/xsl" href="Orders.xsl"?> <orders xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation="Orders.xsd"> <order> <orderId>123</orderId> <items> <item> <itemId>001</itemId> <itemName>Nylon Rope</itemName> <quantity>1</quantity> <price>3.50</price> </item> <item> <itemId>002</itemId> <itemName>Shovel</itemName> <quantity>1</quantity> <price>24.95</price> </item> </items> <customerAddress> <customerName>Larry Murphy</customerName> <street>Shallowgrave Lane</street> <city>Ballymore Eustace, Co. Kildare</city> </customerAddress> </order> <order> <orderId>124</orderId> <items> <item> <itemId>001</itemId> <itemName>Whiskey</itemName> <quantity>1</quantity> <price>18.50</price> </item> <item> <itemId>002</itemId> <itemName>Shotgun</itemName> <quantity>1</quantity> <price>225</price> </item> <item> <itemId>003</itemId> <itemName>Cartridge</itemName> <quantity>1</quantity> <price>1.85</price> </item> </items> <customerAddress> <customerName>Enda Kenny</customerName> <street>A Avenue</street> <city>Castlebar, Co. Mayo</city> </customerAddress> </order> </orders>

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  • Namespace Traversal

    - by RikSaunderson
    I am trying to parse the following sample piece of XML: <?xml version="1.0" encoding="UTF-8"?> <soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <soapenv:Body> <d2LogicalModel modelBaseVersion="1.0" xmlns="http://datex2.eu/schema/1_0/1_0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://datex2.eu/schema/1_0/1_0 http://datex2.eu/schema/1_0/1_0/DATEXIISchema_1_0_1_0.xsd"> <payloadPublication xsi:type="PredefinedLocationsPublication" lang="en"> <predefinedLocationSet id="GUID-NTCC-VariableMessageSignLocations"> <predefinedLocation id="VMS30082775"> <predefinedLocationName> <value lang="en">VMS M60/9084B</value> </predefinedLocationName> </predefinedLocation> </predefinedLocationSet> </payloadPublication> </d2LogicalModel> </soapenv:Body> </soapenv:Envelope> I specifically need to get at the contents of the top-level predefinedLocation tag. By my calculations, the correct XPath should be /soapenv:Envelope/soapenv:Body/d2LogicalModel/payloadPublication/predefinedLocationSet/predefinedLocation I am using the following C# code to parse the XML: string filename = "content-sample.xml"; XmlDocument xmlDoc = new XmlDocument(); xmlDoc.Load(filename); XmlNamespaceManager nsmanager = new XmlNamespaceManager(xmlDoc.NameTable); nsmanager.AddNamespace("soapenv", "http://schemas.xmlsoap.org/soap/Envelope"); string xpath ="/soapenv:Envelope/soapenv:Body/d2LogicalModel/payloadPublication/predefinedLocationSet/predefinedLocation"; XmlNodeList itemNodes = xmlDoc.SelectNodes(xpath, nsmanager); However, this keeps coming up with no results. Can anyone shed any light on this, because I feel like I'm banging my head on a brick wall.

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  • XML parsing problem

    - by Albinoswordfish
    I'm having this strange XML parsing problem. I have this XML string I'm trying to parse <?xml version="1.0"?> <response status="success"> <lot>32342</lot> </response> I'm using XPath with Java in order to do this. I'm using the Xpath expression "/response/@status" to find the text "success". However whenever I evaluate this expression I get an empty string. However I am able to successfully parse this string using "/response/@type" <?xml version="1.0"?> <response type="success"> <lot>32342</lot> </response> So why would simply changing the name of the attribute change the return string to nothing? is = new InputSource(testWOcreateStrGood); xPathexpressionSuccess = xPath.compile("/response/@status"); responseStr = xPathexpressionSuccess.evaluate(is); reponseStr is the string I posted earlier with the "status" attribute

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  • Unable to get node using xpath in soapUI

    - by R.S
    How can i access "AccountId" node from following response file using Xpath in soapUI 4.0.0? Thanks in advance. Response file is as follow, <s:Envelope xmlns:s="http://schemas.xmlsoap.org/soap/envelope/"> <s:Body> <GetResponse xmlns="http://www.tieto.com/cmw/tcm/account"> <GetResult xmlns:i="http://www.w3.org/2001/XMLSchema-instance"> <Account> <AccountId>14338049839</AccountId> <AccountLabel>Spara Femman</AccountLabel> <AccountRoleDTOList> <AccountRole> <AddressTypeId>REC</AddressTypeId> <EndDay i:nil="true"/> <ExtPosReference i:nil="true"/> <HolderId>10533</HolderId> <HolderName>TÄRNHOLMS HOTELL AB</HolderName> <HolderTypeId>COR</HolderTypeId> <IdentificationId>005164006917</IdentificationId> <ReportProfileId>3</ReportProfileId> <ReportProfileName>Standard</ReportProfileName> <RoleDocumentPath i:nil="true"/> <RoleId>HOL</RoleId> <RoleName>Holder</RoleName> <ShareOfAccount>100.00000</ShareOfAccount> </AccountRole> </AccountRoleDTOList> <AccountTypeId>AGG</AccountTypeId> <CloseDay i:nil="true"/> <CurrencyId>SEK</CurrencyId> <CustodianAccountId i:nil="true"/> I have tried it by using following code... but it's not working declare namespace i='http://www.w3.org/2001/XMLSchema-instance'; //i:GetResult[1]/Account[1] But i am getting error like, Missing content for xpath declare namespace i='http://www.w3.org/2001/XMLSchema-instance'; //i:GetResult[1]/Account[1] in response

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  • C# XPath id() not working?

    - by Iggyhopper
    I'm using C# and I'm stumped. Does it just not support id()? I have a large XML file, about 4-5 of them at ~400kb, so I need some speed and performance wherever I can get it. I use XmlDocument.SelectSingleNode("id('blahblahblah')") and it doesn't get the node by id. Am I going crazy or is it that C# XPath just doesn't support id()?

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  • label in xsl - change the text

    - by naz
    hi, if i want that some value from the xml insert into the text area in the label in the xsl. how can i do that? for example if i want that the ID attribute inser into the label foreach ID.

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  • How to assign XML attribute values to drop down list using XSL

    - by Vijay
    Hi, I have a sample xml as; <?xml version="1.0" encoding="iso-8859-9"?> <DropDownControl id="dd1" name="ShowValues" choices="choice1,choice2,choice3,choice4"> </DropDownControl > I need to create a UI representation of this XML using XSL. I want to fill the drop down list with values specified in choices attribute. Does anyone have any idea about this ? Thanks in advance :)

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  • Forming Xpath Query for total Google results

    - by user619879
    I've used this formula in Google Spreadsheets in the past to input the number of search results into a cell. The formula's not working anymore and I know I need to fix the xpath query. any ideas? Current formula: =importXML("http://www.google.com/search?num=100&q="&A2,"//p[@id='resultStats']/b[3]") Spreadsheet for public testing: https://spreadsheets8.google.com/ccc?key=tJzmFllp7Sk1lt23cXSVXFw&authkey=CM625OUO#gid=0

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