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  • ruby yaml ypath like xpath ?

    - by gurpal2000
    Hi i have a yaml file like so --- data: - date: "2004-06-11" description: First description - date: "2008-01-12" description: Another descripion How can i do a "ypath" query similar to xpath for xml ? Something like "get the description where the date is 2004-06-11" YAML.parse_file('myfile.yml').select('/data/*/date == 2004-06-11') How do you do it, and if that's possible how can i similarly edit the description by 'ypath' ? Thanks

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  • Using java provided parameters into xpath function while applying xslt transformation

    - by filmac
    I'm working at a java application that performs some xslt transformation. I would like to match nodes into the xslt document, using a parameter provided by java. Which is the right way to do something like: <xsl:template match="//m:properties/*[contains($pattern,name())]"> because when I launch my application, it claims it's not able to compile the stylesheet, since pattern is not defined but I'm setting it using the setParameter method and I was able to use another parameter defined in the same way but in a different context. Thanks in advance Fil

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  • Regular expression in Umbraco for number validation.

    - by Vizioz Limited
    This evening I was looking for a way to validate an Umbraco node that could be either text or a numeric value, in my case a salary that could be either an hourly amount, an annual figure or a comment. In the case where the node contained a value I wanted the XSLT to output a pound sign (£) and for any that contained text it would just output the text, as this could be something like "Contact Us" or "Negotiable"I thought someone else might find this useful so here is the XSLT and the regular expression.First if you are using Umbraco, don't forget to include the reference to the EXSLT Regular expression library at the top of your XSLT.<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxml="urn:schemas-microsoft-com:xslt" xmlns:umbraco.library="urn:umbraco.library" xmlns:Exslt.ExsltRegularExpressions="urn:Exslt.ExsltRegularExpressions" exclude-result-prefixes="msxml umbraco.library Exslt.ExsltRegularExpressions">Then the code I used was:<xsl:if test="Exslt.ExsltRegularExpressions:match($currentPage/data [@alias='Salary'], '^[0-9]*\,?[0-9]*\.?[0-9]+$') != ''"> <xsl:text>£</xsl:text></xsl:if>This regular expression allows any number of digits, an optional comma, more digits, an optional decimal point and finally more digits, so all the following are valid:12,00014.43334,342.03

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  • PHP and XSLTProcessor Misbehavior

    - by Aiden Bell
    Hi all, Simple question: Why is a PHP function called from an XSL Stylesheet just returning the last argument passed: foo.xsl: <xsl:template match="/"> <xsl:value-of select="php:function('date','c')" /> </xsl:template> PHP: ... $xsl = new XSLTProcessor(); $xsl->registerPHPFunctions(); $xsl->importStylesheet($fooStylesheet); echo $xsl->transformToXML($myXML); I Get the output c and if I call <xsl:value-of select="php:function('date')" /> I just get date as my output. Seems strange to me. Version info: PHP 5.3.2 libxslt Version 1.1.26 libxslt compiled against libxml Version 2.7.6 EXSLT enabled libexslt Version 1.1.26

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  • Grouping XSLT nodes via transformation

    - by scott
    I'm trying to create a page like this via XSLT transformation. Pages page1 page2 Links link1 link2 Here is the xml <siteMenu> <Pages> <title>page1</title> </Pages> <Pages> <title>page2</title> </Pages> <Links> <title>link1</title> </Links> <Links> <title>link2</title> </Links> </siteMenu> I tried using <xsl:for-each select="*"> and <xsl:for-each-group select="*" group-by="@v"> but that gives me every element, but how can i separate them out based on the parent node?

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  • Grouping XSLT nodes via transformation dynamically

    - by scott
    I'm trying to create a page like this via XSLT transformation. Pages page1 page2 Links link1 link2 Here is the xml <siteMenu> <Pages> <title>page1</title> </Pages> <Pages> <title>page2</title> </Pages> <Links> <title>link1</title> </Links> <Links> <title>link2</title> </Links> </siteMenu> I tried using <xsl:for-each select="*"> and <xsl:for-each-group select="*" group-by="@v"> but that gives me every element, but how can i separate them out based on the parent node? I also want to make it dynamic so that if I add another item in siteMenu, it would update the xslt appropriately.

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  • Alternative to Altova's MissionKit

    - by nomad311
    Anyone know of any good alternatives (other than those listed below which really are only good at specific XML development tasks)? The Why (if you're interested): I've been doing XML development on and off for years now, but someone brought XMLSpy to my attention recently, and it is awesome - the price isn't. Lately I've been using a combination of: Notepad++ (modifying XML) EditX (validating/debugging XML) Eclipse (designing schemas) and MS Visual Studio (validating schemas) ...based on which makes the task(s) easiest. But, I've just found out that we will be using XSL transformations to generate XML in the future. I've never used mission kit before, but I'm just short of positive XMLSpy replaces all the above mentioned tool for XML development. And if their XSL tools are anywhere near the caliber of XMLSpy ...simply put I need it. I don't believe that I can convince the budgeting types to buy licenses for MissionKit at $1000 each (won't stop me from trying). In the mean while some research on alternatives won't hurt, but a few Google queries has only revealed that not many people pay for Altova's (overpriced?) software as there are mostly links to P2P sites for downloading a more free-like version of MissionKit.

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  • mySQL to .XSL help

    - by kielie
    hi guys, I have to create a script that takes a mySQL table, and exports it into .XSL format, and then saves that file into a specified folder on the web host. I got it working, but now I can't seem to get it to automatically save the file to the location without prompting the user. It needs to run every day at a specified time, so it can save the previous days leads into a .XSL file on the web host. Here is the code: <?php // DB TABLE Exporter // // How to use: // // Place this file in a safe place, edit the info just below here // browse to the file, enjoy! // CHANGE THIS STUFF FOR WHAT YOU NEED TO DO $dbhost = "-"; $dbuser = "-"; $dbpass = "-"; $dbname = "-"; $dbtable = "-"; // END CHANGING STUFF $cdate = date("Y-m-d"); // get current date // first thing that we are going to do is make some functions for writing out // and excel file. These functions do some hex writing and to be honest I got // them from some where else but hey it works so I am not going to question it // just reuse // This one makes the beginning of the xls file function xlsBOF() { echo pack("ssssss", 0x809, 0x8, 0x0, 0x10, 0x0, 0x0); return; } // This one makes the end of the xls file function xlsEOF() { echo pack("ss", 0x0A, 0x00); return; } // this will write text in the cell you specify function xlsWriteLabel($Row, $Col, $Value ) { $L = strlen($Value); echo pack("ssssss", 0x204, 8 + $L, $Row, $Col, 0x0, $L); echo $Value; return; } // make the connection an DB query $dbc = mysql_connect( $dbhost , $dbuser , $dbpass ) or die( mysql_error() ); mysql_select_db( $dbname ); $q = "SELECT * FROM ".$dbtable." WHERE date ='$cdate'"; $qr = mysql_query( $q ) or die( mysql_error() ); // Ok now we are going to send some headers so that this // thing that we are going make comes out of browser // as an xls file. // header("Pragma: public"); header("Expires: 0"); header("Cache-Control: must-revalidate, post-check=0, pre-check=0"); header("Content-Type: application/force-download"); header("Content-Type: application/octet-stream"); header("Content-Type: application/download"); //this line is important its makes the file name header("Content-Disposition: attachment;filename=export_".$dbtable.".xls "); header("Content-Transfer-Encoding: binary "); // start the file xlsBOF(); // these will be used for keeping things in order. $col = 0; $row = 0; // This tells us that we are on the first row $first = true; while( $qrow = mysql_fetch_assoc( $qr ) ) { // Ok we are on the first row // lets make some headers of sorts if( $first ) { foreach( $qrow as $k => $v ) { // take the key and make label // make it uppper case and replace _ with ' ' xlsWriteLabel( $row, $col, strtoupper( ereg_replace( "_" , " " , $k ) ) ); $col++; } // prepare for the first real data row $col = 0; $row++; $first = false; } // go through the data foreach( $qrow as $k => $v ) { // write it out xlsWriteLabel( $row, $col, $v ); $col++; } // reset col and goto next row $col = 0; $row++; } xlsEOF(); exit(); ?> I tried using, fwrite to accomplish this, but it didn't seem to go very well, I removed the header information too, but nothing worked. Here is the original code, as I found it, any help would be greatly appreciated. :-) Thanx in advance. :-)

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  • RETRIVE XPATH OF AN XML ELELEMNT BY USING ITS VALUE

    - by user299938
    My XmlFile looks like this: <?xml version="1.0"?> <document-inquiry> <publication-reference data-format="docdb" xmlns="http://www.epo.org/exchange"> <document-id> <country>EP</country> <doc-number>2160088</doc-number> <kind>A1</kind> </document-id> </publication-reference> </document-inquiry> For the above xml i need to get the xpath of a specific element say for example "country element" as My Output: "/document-inquiry/publication-reference/document-id/country" My Input : By using its value "EP" This is the code i tried doc.SelectSingleNode("/document-inquiry/publication-reference/document-id[text()='EP']"); I receivev null for the above code. I have to get it using the c# code. Can anyone pls help me on this

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  • xforms "instance namespace" issue

    - by user302254
    I am creating an Xform that reads an XML document and creates an input form for updating the document. However, apparently due to a namespace issue none of my Xpath expressions resolve.My form works fine on a simple instance when the instance file has no namespace. However, I need the namespace support. My instance file has a namespace "ai:inventory." I am referencing the instance data Where should I be declaring the prefix "ai" for my namespace so that my XPath expressions can find the appropriate elements? /ai:inventory/products ? I've tried creating the prefix in the html opening tag... that didn't help. thanks,

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  • help with xpath selecting

    - by fayer
    i've got an id attribute value for an element. i want to select only its children (not all descendants). i used $childElements = $xml-xpath('//entity[@id=212323]'); print_r($childElements); but that would select ALL descendants and print them out. i just want to select the 1 generation children. how could i do that? <entity id=212323> <this>asd</this> <this>asd</this> <this>asd</this> <this> <notThis>asd</notThis> <notThis>asd</notThis> <notThis>asd</notThis> </this> </entity>

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  • How to call an xslt transform into an xsl stylesheet

    - by Mycol
    I have written an xslt that reads some xml file names and does some operations on them. I use a for-each to work them one-by-one. I have each path inside a parameter $path. But now I would like to output the result of applying an external stylesheet to those files. I would write something like <div> <something like xsl-transform($extern-xslt,$path)> </div> to have the result tree of the transformation inside the main html output. It is possible?

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  • Using xsl:character-map on text nodes only

    - by jramos95
    I am trying to create a generic stylesheet that can convert all Latin characters in Unicode to uppercase ASCII characters. Using <xsl:character-map> works well except for one thing: namespaces. The character map converts all of my namespaces to upper case, which I do not want. Is there a way to utilize a character map to do what I want to all the other nodes while leaving the namespaces untouched? I see the disable-output-escaping attribute might be an option, but I haven't been able to make it work.

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  • Rendering XML document with multiple languages

    - by bdhar
    I have an XML page with some elements in various languages - Arabic, English, Chinese, Japanese.. Which encoding format should I have to choose for that? If I try to render the XML with an XSL (using utf-8 or ISO-8859-6 or ISO-2022-JP), I get this error: An invalid character was found in text content. How shall or solve this? Thanks.

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  • HTML encode on a XSLT

    - by Hugo Palma
    I would like to convert some value from a XML attribute into valid HTML with entities. So that for example the string "olá" from the XML would be transformed from the XSLT into "ol&#225;" I can't find any xsl function to do this. Any ideas ?

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  • How to sort by hexadecimals in xslt?

    - by fielding
    Hi, im trying to sort my transformed output by a element which contains a hex value. <xsl:sort select="Generation/Sirio/Code" data-type="number"/> Values are plain old Hex: 00 01 02 ... 0A ... FF but they are getting sorted like that: 0A FF 00 01 02, which indicates the sorting method fails as soon as there are character involved. How can i work around this? Thank you very much!

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  • XmlException - inserting attribute gives "unexpected token" exception

    - by Anders Svensson
    Hi, I have an XmlDocument object in C# that I transform, using XslTransform, to html. In the stylesheet I insert an id attribute in a span tag, taking the id from an element in the XmlDocument. Here is the template for the element: <xsl:template match="word"> <span> <xsl:attribute name="id"><xsl:value-of select="@id"></xsl:value-of></xsl:attribute> <xsl:apply-templates/> </span> </xsl:template> But then I want to process the result document as an xhtml document (using the XmlDocument dom). So I'm taking a selected element in the html, creating a range out of it, and try to load the element using XmlLoad(): wordElem.LoadXml(range.htmlText); But this gives me the following exception: "'598' is an unexpected token. The expected token is '"' or '''. Line 1, position 10." And if I move the cursor over the range.htmlText, I see the tags for the element, and the "id" shows without quotes, which confuses me (i.e.SPAN id=598 instead of SPAN id="598"). To confuse the matter further, if I insert a blank space or something like that in the value of the id in the stylesheet, it works fine, i.e.: <span> <xsl:attribute name="id"><xsl:text> </xsl:text> <xsl:value-of select="@id"></xsl:value-of></xsl:attribute> <xsl:apply-templates/> </span> (Notice the whitespace in the xsl:text element). Now if I move the cursor over the range.htmlText, I see an id with quotes as usual in attributes (and as it shows if I open the html file in notepad or something). What is going on here? Why can't I insert an attribute this way and have a result that is acceptable as xhtml for XmlDocument to read? I feel I am missing something fundamental, but all this surprises me, since I do this sort of transformations using xsl:attribute to insert attributes all the time for other types of xsl transformations. Why doesn't XmlDocument accept this value? By the way, it doesn't matter if it is an id attribute. i have tried with the "class" attribute, "style" etc, and also using literal values such as "style" and setting the value to "color:red" and so on. The compiler always complains it is an unvalid token, and does not include quotes for the value unless there is a whitespace or something else in there (linebreaks etc.). I hope I have provided enough information. Any help will be greatly appreciated. Basically, what I want to accomplish is set an id in a span element in html, select a word in a webbrowser control with this document loaded, and get the id attribute out of the selected element. I've accomplished everything, and can actually do what I want, but only if I use regex e.g. to get the attribute value, and I want to be able to use XmlDocument instead to simply get the value out of the attribute directly. I'm sure I'm missing something simple, but if so please tell me. Regards, Anders

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  • How do I combine or merge grouped nodes?

    - by LOlliffe
    Using the XSL: <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" exclude-result-prefixes="xs" version="2.0"> <xsl:output method="xml"/> <xsl:template match="/"> <records> <record> <!-- Group record by bigID, for further processing --> <xsl:for-each-group select="records/record" group-by="bigID"> <xsl:sort select="bigID"/> <xsl:for-each select="current-group()"> <!-- Create new combined record --> <bigID> <!-- <xsl:value-of select="."/> --> <xsl:for-each select="."> <xsl:value-of select="bigID"/> </xsl:for-each> </bigID> <text> <xsl:value-of select="text"/> </text> </xsl:for-each> </xsl:for-each-group> </record> </records> </xsl:template> I'm trying to change: <?xml version="1.0" encoding="UTF-8"?> <records> <record> <bigID>123</bigID> <text>Contains text for 123</text> <bigID>456</bigID> <text>Some 456 text</text> <bigID>123</bigID> <text>More 123 text</text> <bigID>123</bigID> <text>Yet more 123 text</text> </record> into: <?xml version="1.0" encoding="UTF-8"?> <records> <record> <bigID>123</bigID> <text>Contains text for 123</text> <text>More 123 text</text> <text>Yet more 123 text</text> </bigID> <bigID>456 <text>Some 456 text</text> </bigID> </record> Right now, I'm just listing the grouped <bigIDs, individually. I'm missing the step after grouping, where I combine the grouped <bigID nodes. My suspicion is that I need to use the "key" function somehow, but I'm not sure. Thanks for any help.

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  • How do I combine grouped nodes?

    - by LOlliffe
    Using the XSL: <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" exclude-result-prefixes="xs" version="2.0"> <xsl:output method="xml"/> <xsl:template match="/"> <records> <record> <!-- Group record by bigID, for further processing --> <xsl:for-each-group select="records/record" group-by="bigID"> <xsl:sort select="bigID"/> <xsl:for-each select="current-group()"> <!-- Create new combined record --> <bigID> <!-- <xsl:value-of select="."/> --> <xsl:for-each select="."> <xsl:value-of select="bigID"/> </xsl:for-each> </bigID> <text> <xsl:value-of select="text"/> </text> </xsl:for-each> </xsl:for-each-group> </record> </records> </xsl:template> I'm trying to change: <?xml version="1.0" encoding="UTF-8"?> <records> <record> <bigID>123</bigID> <text>Contains text for 123</text> <bigID>456</bigID> <text>Some 456 text</text> <bigID>123</bigID> <text>More 123 text</text> <bigID>123</bigID> <text>Yet more 123 text</text> </record> into: <?xml version="1.0" encoding="UTF-8"?> <records> <record> <bigID>123</bigID> <text>Contains text for 123</text> <text>More 123 text</text> <text>Yet more 123 text</text> </bigID> <bigID>456 <text>Some 456 text</text> </bigID> </record> Right now, I'm just listing the grouped <bigIDs, individually. I'm missing the step after grouping, where I combine the grouped <bigID nodes. My suspicion is that I need to use the "key" function somehow, but I'm not sure. Thanks for any help.

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  • HTML Agility Pack Screen Scraping XPATH isn't returning data

    - by Matthias Welsh
    I'm attempting to write a screen scraper for Digikey that will allow our company to keep accurate track of pricing, part availability and product replacements when a part is discontinued. There seems to be a discrepancy between the XPATH that I'm seeing in Chrome Devtools as well as Firebug on Firefox and what my C# program is seeing. The code I'm currently using is pretty quick and dirty... //This function retrieves data from the digikey private static List<string> ExtractProductInfo(HtmlDocument doc) { List<HtmlNode> m_unparsedProductInfoNodes = new List<HtmlNode>(); List<string> m_unparsedProductInfo = new List<string>(); //Base Node for part info string m_baseNode = @"//html[1]/body[1]/div[2]"; //Write part info to list m_unparsedProductInfoNodes.Add(doc.DocumentNode.SelectSingleNode(m_baseNode + @"/table[1]/tr[1]/td[1]/table[1]/tr[1]/td[1]")); //More lines of similar form will go here for more info //this retrieves digikey PN foreach(HtmlNode node in m_unparsedProductInfoNodes) { m_unparsedProductInfo.Add(node.InnerText); } return m_unparsedProductInfo; } Although the path I'm using appears to be "correct" I keep getting NULL when I look at the list "m_unparsedProductInfoNodes" Any idea what's going on here? I'll also add that if I do a "SelectNodes" on the baseNode it only returns a div... not sure what that indicates but it doesn't seem right.

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  • Problem merging similar XML files with XSL

    - by LOlliffe
    I have two documents that I need to merge, that happen in a way that I don't seem to be able to find covered in other examples. Namely, that it needs to match not only on a node's attribute at one level, but also on the value of an attribute a node level below that, to get that node's value. I'm trying to take this sample: <?xml version="1.0" encoding="UTF-8" ?> <marc:collection xmlns:marc="http://www.loc.gov/MARC21/slim" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> <marc:record> <marc:datafield tag="035" ind1=" " ind2=" "> <marc:subfield code="a">12345</marc:subfield> </marc:datafield> <marc:datafield tag="041" ind1=" " ind2=" "> <marc:subfield code="a">eng</marc:subfield> </marc:datafield> <marc:datafield tag="650" ind1=" " ind2="4"> <marc:subfield code="a">Art</marc:subfield> </marc:datafield> <marc:datafield tag="949" ind1=" " ind2=" "> <marc:subfield code="i">Review of conference proceedings</marc:subfield> </marc:datafield> </marc:record> <marc:record> <marc:datafield tag="035" ind1=" " ind2=" "> <marc:subfield code="a">54321</marc:subfield> </marc:datafield> <marc:datafield tag="041" ind1=" " ind2=" "> <marc:subfield code="a">eng</marc:subfield> </marc:datafield> <marc:datafield tag="650" ind1=" " ind2="4"> <marc:subfield code="a">Byzantine</marc:subfield> </marc:datafield> </marc:record> </marc:collection> And when the value of "datafield" '035', "subfield" 'a' matches e.g. "12345" <marc:collection xmlns:marc="http://www.loc.gov/MARC21/slim" xmlns:fn="http://www.w3.org/2005/xpath-functions" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:fo="http://www.w3.org/1999/XSL/Format"> <marc:record> <marc:datafield ind2=" " ind1=" " tag="035"> <marc:subfield code="a">12345</marc:subfield> </marc:datafield> <marc:datafield ind2="4" ind1=" " tag="650"> <marc:subfield code="a">General works</marc:subfield> <marc:subfield code="x">Historians and critics</marc:subfield> <marc:subfield code="x">Smith, John, 1834-1917</marc:subfield> </marc:datafield> <marc:datafield ind2="4" ind1=" " tag="650"> <marc:subfield code="a">Généralités</marc:subfield> <marc:subfield code="x">Historiens et critiques d'art</marc:subfield> <marc:subfield code="x">Dietrichson, Lorentz, 1834-1917</marc:subfield> </marc:datafield> <marc:datafield ind2=" " ind1=" " tag="654"> <marc:subfield code="a">General works</marc:subfield> </marc:datafield> <marc:datafield ind2=" " ind1=" " tag="654"> <marc:subfield code="a">Généralités</marc:subfield> <marc:subfield code="b">Historiens et critiques d'art</marc:subfield> <marc:subfield code="b">Smith, John, 1834-1917</marc:subfield> </marc:datafield> </marc:record> <marc:record> <marc:datafield ind2=" " ind1=" " tag="035"> <marc:subfield code="a">54321</marc:subfield> </marc:datafield> <marc:datafield ind2="4" ind1=" " tag="650"> <marc:subfield code="a">General works</marc:subfield> <marc:subfield code="x">Historians and critics</marc:subfield> <marc:subfield code="x">Lange, Julius Henrik, 1838-1896</marc:subfield> </marc:datafield> </marc:record> </marc:collection> The result should be: <?xml version="1.0" encoding="UTF-8" ?> <marc:collection xmlns:marc="http://www.loc.gov/MARC21/slim" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> <marc:record> <marc:datafield tag="035" ind1=" " ind2=" "> <marc:subfield code="a">12345</marc:subfield> </marc:datafield> <marc:datafield tag="041" ind1=" " ind2=" "> <marc:subfield code="a">eng</marc:subfield> </marc:datafield> <marc:datafield tag="650" ind1=" " ind2="4"> <marc:subfield code="a">Art</marc:subfield> </marc:datafield> <marc:datafield ind2="4" ind1=" " tag="650"> <marc:subfield code="a">General works</marc:subfield> <marc:subfield code="x">Historians and critics</marc:subfield> <marc:subfield code="x">Smith, John, 1834-1917</marc:subfield> </marc:datafield> <marc:datafield ind2="4" ind1=" " tag="650"> <marc:subfield code="a">Généralités</marc:subfield> <marc:subfield code="x">Historiens et critiques d'art</marc:subfield> <marc:subfield code="x">Dietrichson, Lorentz, 1834-1917</marc:subfield> </marc:datafield> <marc:datafield ind2=" " ind1=" " tag="654"> <marc:subfield code="a">General works</marc:subfield> </marc:datafield> <marc:datafield ind2=" " ind1=" " tag="654"> <marc:subfield code="a">Généralités</marc:subfield> <marc:subfield code="b">Historiens et critiques d'art</marc:subfield> <marc:subfield code="b">Smith, John, 1834-1917</marc:subfield> </marc:datafield> <marc:datafield tag="949" ind1=" " ind2=" "> <marc:subfield code="i">Review of conference proceedings</marc:subfield> </marc:datafield> </marc:record> <marc:record> <marc:datafield tag="035" ind1=" " ind2=" "> <marc:subfield code="a">54321</marc:subfield> </marc:datafield> <marc:datafield tag="041" ind1=" " ind2=" "> <marc:subfield code="a">eng</marc:subfield> </marc:datafield> <marc:datafield tag="650" ind1=" " ind2="4"> <marc:subfield code="a">Byzantine</marc:subfield> </marc:datafield> <marc:datafield ind2="4" ind1=" " tag="650"> <marc:subfield code="a">General works</marc:subfield> <marc:subfield code="x">Historians and critics</marc:subfield> <marc:subfield code="x">Lange, Julius Henrik, 1838-1896</marc:subfield> </marc:datafield> </marc:record> </marc:collection> I've tried using examples that I've found that did lookups, but none of them seemed to work. I didn't include any of my XSL, because all of my results were disasterous. I keep looking at it, like it must be simple, but I'm just not getting any decent results. Any help or pointers would be greatly appreciated. Thanks!

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  • Preserving order when copying elements using Deliverance / XPath

    - by Jon Hadley
    How would I, using Deliverance & XPath (or CSS) selectors, select and copy list items .one and .three from each list below, but display them in the order of their parent list? <ul id="a-wrapper"> <li class="one"></li> <li class="two"></li> <li class="three"></li> <li class="four"></li> </li> <ul id="b-wrapper"> <li class="one"></li> <li class="two"></li> <li class="three"></li> <li class="four"></li> </ul> c,d,e,f,g etc.... The catch is it needs to use a href rule, eg: <prepend href="/blah/deblah" content="#x" theme="#y" /> Using the following just lists all the .one elements, then all the .three elements. <prepend href="/blah/deblah" content=".one" theme="#y" /> <prepend href="/blah/deblah" content=".three" theme="#y" />

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