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  • database transaction rollback processing in PHP

    - by user198729
    try { $con->beginTransaction(); $this->doSave($con); $con->commit(); } catch (Exception $e) { $con->rollBack(); throw $e; } The code above is quite standard an approach to deal with transactions, but my question is:what if $con->rollBack() also fails? It may cause db lock,right?If so,what's the perfect way to go?

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  • C# 4: how to in-line detect for nulls?

    - by Dr. Zim
    In C# 4, wasn't there a short cut for checking for null values like so: if( myobject?.myproperty?.myotherproperty?.value != null ) The value would return null and not throw an exception. Anyone have a link to how to use it or at least the syntax?

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  • In C# ,how do I terminate a thread that has had its call stack corrupted?

    - by Emil D
    I have a thread in my application that is running code that can potentially cause call stack corruption ( my application is a testing tool for dlls ). Assuming that I have a method of detecting if the child thread is misbehaving, how would I terminate it? From what I read, calling Thread.Abort() on the misbehaving thread would be equivalent to raising an exception inside it.I fear that that not be a good idea, provided the call stack of the thread might be corrupted.Any suggestions?

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  • Android: How to properly exit application when inconsistent condition is unavoidable?

    - by Bevor
    First of all I already read about all this discussion that it isn't a good idea to manually exit an Android application. But in my case it seems to be needed. I have an AsyncTask which does a lof of operations in background. That means downloading data, saving it to local storage and preparing it for usage in application. It could happen that there is no internet connection or something different happens. For all that cases I have an Exception handling which returns the result. And if there is an exception, the application is unusable so I need to exit it. My question is, do I have to do some unregistration unloading or unbinding tasks or something when I exit the application by code or is System.exit(0) ok? I do all this in an AsyncTask, see my example: public class InitializationTask extends AsyncTask<Void, Void, InitializationResult> { private ProcessController processController = new ProcessController(); private ProgressDialog progressDialog; private Activity mainActivity; public InitializationTask(Activity mainActivity) { this.mainActivity = mainActivity; } @Override protected void onPreExecute() { super.onPreExecute(); progressDialog = new ProgressDialog(mainActivity); progressDialog.setMessage("Die Daten werden aufbereitet.\nBitte warten..."); progressDialog.setIndeterminate(true); //means that the "loading amount" is not measured. progressDialog.setCancelable(false); progressDialog.show(); }; @Override protected InitializationResult doInBackground(Void... params) { return processController.initializeData(); } @Override protected void onPostExecute(InitializationResult result) { super.onPostExecute(result); progressDialog.dismiss(); if (!result.isValid()) { AlertDialog.Builder dialog = new AlertDialog.Builder(mainActivity); dialog.setTitle("Initialisierungsfehler"); dialog.setMessage(result.getReason()); dialog.setPositiveButton("Ok", new DialogInterface.OnClickListener() { @Override public void onClick(DialogInterface dialog, int which) { dialog.cancel(); //TODO cancel application System.exit(0); } }); dialog.show(); } } }

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  • embedding dll requirement in program

    - by JGC
    hi I am writing a C# Windows application program and I'm using an add-on for creating chart in it,but when I run this program on another windows which has .net framework but not that package it does not work and give me exception. I want to know how can I correct this problem even with setup file? and if the answer is setup file then how should I do that? thank you

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  • Android: Unable to access a local website over HTTPS

    - by user1253789
    I am trying to access a locally hosted website and get its HTML source to parse. I have few questions: 1) Can I use "https://An IP ADDRESS HERE" as a valid URL to try and access. I do not want to make changes in the /etc/hosts file so I want to do it this way. 2) I cannot get the html, since it is giving me Handshake exceptions and Certificate issues. I have tried a lot of help available over the web , but am not successful. Here is the code I am using: public class MainActivity extends Activity { private TextView textView; String response = ""; String finalresponse=""; /** Called when the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_main); textView = (TextView) findViewById(R.id.TextView01); System.setProperty("javax.net.ssl.trustStore","C:\\User\\*" ); System.setProperty("javax.net.ssl.trustStorePassword", "" ); } private class DownloadWebPageTask extends AsyncTask<String, Void, String> { @Override protected String doInBackground(String... urls) { TrustManager[] trustAllCerts = new TrustManager[] { new X509TrustManager() { public java.security.cert.X509Certificate[] getAcceptedIssuers() { return null; } public void checkClientTrusted(java.security.cert.X509Certificate[] certs, String authType) { } public void checkServerTrusted(java.security.cert.X509Certificate[] certs, String authType) { } } }; try { SSLContext sc = SSLContext.getInstance("SSL"); sc.init(null, trustAllCerts, new java.security.SecureRandom()); HttpsURLConnection.setDefaultSSLSocketFactory(sc.getSocketFactory()); } catch (Exception e) { } try { URL url = new URL("https://172.27.224.133"); HttpsURLConnection con =(HttpsURLConnection)url.openConnection(); con.setHostnameVerifier(new AllowAllHostnameVerifier()); finalresponse=readStream(con.getInputStream()); } catch (Exception e) { e.printStackTrace(); } return finalresponse; } private String readStream(InputStream in) { BufferedReader reader = null; try { reader = new BufferedReader(new InputStreamReader(in)); String line = ""; while ((line = reader.readLine()) != null) { response+=line; } } catch (IOException e) { e.printStackTrace(); } finally { if (reader != null) { try { reader.close(); } catch (IOException e) { e.printStackTrace(); } } } return response; } @Override protected void onPostExecute(String result) { textView.setText(finalresponse); } } public void readWebpage(View view) { DownloadWebPageTask task = new DownloadWebPageTask(); task.execute(new String[] { "https://172.27.224.133" }); } }

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  • Can't exit an Android application

    - by saravanan
    // @Override public boolean onOptionsItemSelected(MenuItem item) { // TODO Auto-generated method stub switch(item.getItemId()) { case EXIT: try { this.finish(); } catch(Exception e) { } break; } return false; } When I exit my android application it resumes the previous screen. How can I exit the Android application properly?

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  • OutOfMemoryError loading Bitmap via DefaultHttpClient

    - by Goddchen
    i have a simple problem: Although i'm using sampleSize properly, my code doesn't even reach the BitmapFactorycode, since DefaultHttpClient is already throwing the exception. Here is my code: DefaultHttpClient client = new DefaultHttpClient(); HttpGet request = new HttpGet(mSongInfo.imageLarge); HttpResponse response = client.execute(request); int sampleSize = 1; while (response.getEntity().getContentLength() / sampleSize / sampleSize > 100 * 1024) { sampleSize *= 2; } BitmapFactory.Options options = new BitmapFactory.Options(); options.inSampleSize = sampleSize; final Bitmap bitmap = BitmapFactory.decodeStream(response .getEntity().getContent(), null, options); And here is the exception: 0 java.lang.OutOfMemoryError: (Heap Size=11463KB, Allocated=7623KB, Bitmap Size=9382KB) 1 at org.apache.http.util.ByteArrayBuffer.<init>(ByteArrayBuffer.java:53) 2 at org.apache.http.impl.io.AbstractSessionInputBuffer.init(AbstractSessionInputBuffer.java:82) 3 at org.apache.http.impl.io.SocketInputBuffer.<init>(SocketInputBuffer.java:98) 4 at org.apache.http.impl.SocketHttpClientConnection.createSessionInputBuffer(SocketHttpClientConnection.java:83) 5 at org.apache.http.impl.conn.DefaultClientConnection.createSessionInputBuffer(DefaultClientConnection.java:170) 6 at org.apache.http.impl.SocketHttpClientConnection.bind(SocketHttpClientConnection.java:106) 7 at org.apache.http.impl.conn.DefaultClientConnection.openCompleted(DefaultClientConnection.java:129) 8 at org.apache.http.impl.conn.DefaultClientConnectionOperator.openConnection(DefaultClientConnectionOperator.java:173) 9 at org.apache.http.impl.conn.AbstractPoolEntry.open(AbstractPoolEntry.java:164) 10 at org.apache.http.impl.conn.AbstractPooledConnAdapter.open(AbstractPooledConnAdapter.java:119) 11 at org.apache.http.impl.client.DefaultRequestDirector.execute(DefaultRequestDirector.java:359) 12 at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:555) 13 at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:487) 14 at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:465) 15 at de.goddchen.android.easysongfinder.fragments.SongFragment$1.run(SongFragment.java:79) 16 at java.lang.Thread.run(Thread.java:1027) As you can see, the code doesn't even reach the part where i check the size (Content-Length) of the image and calculate a proper sample size. I wasn't aware that simply calling DefaultHttpClient.execute(...) will already load the complete content into the memory. Am i doing something wrong? What is the right way to first retrieve the content length and then start reading the content from an InputStream? EDIT To avoid common answers that show how to load images from a URL: i already know how to do that, i have also posted the code above, so why do you keep referencing tutorials on that? I explicitly was very clear about the problem: Why is HttpClient.execute(...)already fetching the whole content and storing it in memory instead of providing a proper ÌnputStreamto me? Please don't post any beginner tutorials on how to load aBitmap`from a URL...

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  • Behavior is different when debugger is attached

    - by Lys
    I'm using VS 2008 to debug C# program with source code access. The expected behavior happened as long as the debugger attached to the running program, but when the program ran without debugger attached the exception threw. What are the common reasons for this to happen, and how can I tell the code difference behind this? Thanks,

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  • twitter api post rate limit

    - by Xavier
    Does anyone know Twitter's rate limit on posting? Looking at their web page they claimed to not have one but I get an exception thrown if my program posts too fast... Any help is appreciated.

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  • issue with Cayenne Entity Manager

    - by user224270
    Hi, I'm trying to persist an object into the database using Cayenne Entity Manager. And unfortunately I get the following error: org.apache.cayenne.CayenneRuntimeException: [v.3.0 Apr 26 2010 09:59:17] Commit Exception Caused by: com.mysql.jdbc.exceptions.MySQLSyntaxErrorException: Table 'myDatabase.auto_pk_support' doesn't exist Any idea how i could solve this issue? Thanks.

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  • Java: Converting UTF 8 to String

    - by kujawk
    When I run the following program: public static void main(String args[]) throws Exception { byte str[] = {(byte)0xEC, (byte)0x96, (byte)0xB4}; String s = new String(str, "UTF-8"); } on Linux and inspect the value of s in jdb, I correctly get: s = "ì–´" on Windows, I incorrectly get: s = "?" My byte sequence is a valid UTF-8 character in Korean, why would it be producing two very different results?

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  • Sockets: I/O Error 32

    - by Genesis
    Could someone please explain what an I/O Error 32 refers to in the context of a network socket? I have a multithreaded Socks5 server written using Poco SocketReactors and am getting this error when the server load reaches a certain point. The exception is thrown within my onReadable handlers at the same time across all threads which have connections associated with them. The only other thing I am doing within those threads is std::cout but I am not sure if this is a potential cause.

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  • WTF why does this SQL work in VS but not in CODE?

    - by acidzombie24
    The line cmd.ExecuteNonQuery(); cmd.CommandText CREATE TRIGGER subscription_trig_0 ON subscription AFTER INSERT AS UPDATE user_data SET msg_count=msg_count+1 FROM user_data JOIN INSERTED ON user_data.id = INSERTED.recipient; The exception: Incorrect syntax near the keyword 'TRIGGER'. Then using VS 2010, connected to the very same file (a mdf file) i run the query above and i get a success message. WTF!

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  • Get return values from a stored procedure in c# (login process)

    - by Jin
    Hi all, I am trying to use a Stored Procedure which takes two parameters (login, pw) and returns the user info. If I execute the SP manually, I get Session_UID User_Group_Name Sys_User_Name ------------------------------------ -------------------------------------------------- - NULL Administrators NTMSAdmin No rows affected. (1 row(s) returned) @RETURN_VALUE = 0 Finished running [dbo].[p_SYS_Login]. But with the code below, I only get the return value. do you know how to get the other values shown above like Session_UID, User_Group_Name, and Sys_User_Name ? if you see the commented part below code. I tried to add some output parameters but it doesn't work with incorrect number of parameters error. string strConnection = Settings.Default.ConnectionString; using (SqlConnection conn = new SqlConnection(strConnection)) { using (SqlCommand cmd = new SqlCommand()) { SqlDataReader rdr = null; cmd.Connection = conn; cmd.CommandText = "p_SYS_Login"; //cmd.CommandText = "p_sys_Select_User_Group"; cmd.CommandType = CommandType.StoredProcedure; SqlParameter paramReturnValue = new SqlParameter(); paramReturnValue.ParameterName = "@RETURN_VALUE"; paramReturnValue.SqlDbType = SqlDbType.Int; paramReturnValue.SourceColumn = null; paramReturnValue.Direction = ParameterDirection.ReturnValue; //SqlParameter paramGroupName = new SqlParameter("@User_Group_Name", SqlDbType.VarChar, 50); //paramGroupName.Direction = ParameterDirection.Output; //SqlParameter paramUserName = new SqlParameter("@Sys_User_Name", SqlDbType.VarChar, 50); //paramUserName.Direction = ParameterDirection.Output; cmd.Parameters.Add(paramReturnValue); //cmd.Parameters.Add(paramGroupName); //cmd.Parameters.Add(paramUserName); cmd.Parameters.AddWithValue("@Sys_Login", textUserID.Text); cmd.Parameters.AddWithValue("@Sys_Password", textPassword.Text); try { conn.Open(); object result = cmd.ExecuteNonQuery(); int returnValue = (int)cmd.Parameters["@RETURN_VALUE"].Value; if (returnValue == 0) { Hide(); Program.MapForm.Show(); } else if (returnValue == 1) { MessageBox.Show("The username or password you entered is incorrect", "NTMS Login", MessageBoxButtons.OK, MessageBoxIcon.Warning); } else if (returnValue == 2) { MessageBox.Show("This account is disabled", "NTMS Login", MessageBoxButtons.OK, MessageBoxIcon.Warning); } else { MessageBox.Show("Database error. Please contact administrator", "NTMS Login", MessageBoxButtons.OK, MessageBoxIcon.Warning); } } catch (Exception ex) { string message = ex.Message; string caption = "MAVIS Exception"; MessageBoxButtons buttons = MessageBoxButtons.OK; MessageBox.Show( message, caption, buttons, MessageBoxIcon.Warning, MessageBoxDefaultButton.Button1); } } } Thanks for your help.

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  • java oracle cusor is closed where cursor is not return to jdbc

    - by optimus
    I am executing a stored procedure which has 2 cusors within the stored procedure. The 1st cursor which is not return to the jdbc as a resultset is closed within the stored procedure. The 2nd cursor which returns the resultset to the jdbc is not closed within the stored procedure. Upon executing I encounter cursor is closed exception which is puzzling. Since the ResultSet will close all underlying cursor upon invoking the close() method

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  • NetBeanse J2ME DataBinding

    - by Wasim
    Hi all , I build an application based on the new Netbeanse data binding feature . I have a problem using this fature on Motorola IDEN mobile (i680) , I get a java exception while trying to install the application on the mobile . What can be the problem . Thanks in advance ...

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  • Why the generated key size is not constant?

    - by Tom Brito
    The following code prints randomly 634, 635, 636, each time I run it. Why its not constant? public static void main(String[] args) throws Exception { KeyPairGenerator keyPairGen = KeyPairGenerator.getInstance("RSA", "BC"); keyPairGen.initialize(1024); RsaKeyPair keyPair = new RsaKeyPair(keyPairGen.generateKeyPair()); System.out.println(keyPair.getPrivate().getEncoded().length); }

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