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  • How to intercept touch events globally?

    - by mystify
    I have an view which is sometimes covered by some other views. However, if the user slides the finger across the screen, I want to slide that underlying view across the screen, too. I could start making custom views for all those covering subviews and forward all kinds of touch events, but that's somewhat cumbersome. Maybe there's some kind of notification or another way that a UIView or UIControl subclass can be aware of touch events happening right now, no matter where they are. In short: I need an UIView subclass or UIControl subclass which knows about any touch events happening on the entire screen. Or at least if tht's not possible, knowing about any touch events happening above itself in the same underlying superview. Another description: There are 20 views, all reside inside the same superview. The first view is covered by 19 others. But if the user slides across the screen, that first view must slide too, so it must be aware of touch events. Is there any better solution that making all 19 views forward touch events? (yes, all 19 views respond to touch events in this example)

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  • python multiprocessing member variable not set

    - by Jake
    In the following script, I get the "stop message received" output but the process never ends. Why is that? Is there another way to end a process besides terminate or os.kill that is along these lines? from multiprocessing import Process from time import sleep class Test(Process): def __init__(self): Process.__init__(self) self.stop = False def run(self): while self.stop == False: print "running" sleep(1.0) def end(self): print "stop message received" self.stop = True if __name__ == "__main__": test = Test() test.start() sleep(1.0) test.end() test.join()

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  • Method in RootViewController not Storing Array

    - by Antonio
    I have an array initialized in my RootViewController and a method that addsObjects to an array. I created a RootViewController object in my SecondViewController. The method runs (outputs a message) but it doesn't add anything to the array, and the array seems empty. Code is below, any suggestions? RootViewController.h #import "RootViewController.h" #import "SecondViewController.h" @implementation RootViewController - (void)viewDidLoad { [super viewDidLoad]; myArray2 = [[NSMutableArray alloc] init]; NSLog(@"View was loaded"); } -(void)addToArray2{ NSLog(@"Array triggered from SecondViewController"); [myArray2 addObject:@"Test"]; [self showArray2]; } -(void)showArray2{ NSLog(@"Array Count: %d", [myArray2 count]); } -(IBAction)switchViews{ SecondViewController *screen = [[SecondViewController alloc] initWithNibName:nil bundle:nil]; screen.modalTransitionStyle = UIModalTransitionStyleCoverVertical; [self presentModalViewController:screen animated:YES]; [screen release]; } SecondViewController.m #import "SecondViewController.h" #import "RootViewController.h" @implementation SecondViewController -(IBAction)addToArray{ RootViewController *object = [[RootViewController alloc] init]; [object addToArray2]; } -(IBAction)switchBack{ [self dismissModalViewControllerAnimated:YES]; } EDIT***** With Matt's code I got the following error: " expected specifier-qualifier-list before 'RootViewController' "

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  • Perl replace slash in variable

    - by cc96ai
    How can I replace the slash inside the variable? $string = 'a\cc\ee'; $re = 'a\\cc'; $rep = "Work"; #doesnt work in variable $string =~ s/$re/$rep/og; print $string."\n"; #work with String $string =~ s/a\\cc/$rep/og; print $string."\n"; output: a\cc\ee Work\ee

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  • How do I lex this input?

    - by etheros
    I currently have a working, simple language implemented in Java using ANTLR. What I want to do is embed it in plain text, in a similar fashion to PHP. For example: Lorem ipsum dolor sit amet <% print('consectetur adipiscing elit'); %> Phasellus volutpat dignissim sapien. I anticipate that the resulting token stream would look something like: CDATA OPEN PRINT OPAREN APOS STRINGAPOS CPARENT SEMI CLOSE CDATA How can I achieve this, or is there a better way?

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  • Executing Multiple Lines in Python

    - by metashockwave
    When Python is first installed, the default setting executes users' code input line-by-line. But sometimes I need to write programs that executes multiple lines at once. Is there a setting in Python where I can change the code execution to one block at once? Thanks if (n/2) * 2 == n:; print 'Even'; else: print 'Odd' SyntaxError: invalid syntax When I tried to run the above code, I got an invalid syntax error on ELSE

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  • Partial PHP code refresh

    - by Tom
    Is it possible to refresh only the part of the page? How? the part: if (checkExpiry($member->expires)==true) { print timeLeft($leftts); } else { print "expired"; } I have table which is showing name, email, time until membership ends and I need to refresh 'time until membership ends' every second.

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  • Easy Python input question

    - by Josh K
    I'd like to have something similar to the following pseudo code: while input is not None and timer < 5: input = getChar() timer = time.time() - start if timer >= 5: print "took too long" else: print input Anyway to do this without threading? I would like an input method that returns whatever has been entered since the last time it was called, or None (null) if nothing was entered.

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  • How do i call a method by a string name using python?

    - by gath
    I have the following class; class myStringMethod(): def __init__(self): self.func_list= [('func1','print_func1()'),('func2','print_func2()')] def print_func1(self, name): print name def print_func2(self, name): print name def call_func_by_name(self): for func in self.func_list: getattr(self, func[1])('Func Name') if __name__=='__main__': strM = myStringMethod() strM.call_func_by_name() #Nothing prints out! No functions get called out, what am i missing? gath

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  • SQLServer - Test the result of a stored procedure

    - by Melursus
    In Microsoft SQLServer, it is possible to test the result of a stored procedure to know if the result return rows or nothing ? Example : EXEC _sp_MySp 1, 2, 3 IF @@ROWCOUNT = 0 BEGIN PRINT('Empty') END ELSE BEGIN PRINT(@@ROWCOUNT) END But @@ROWCOUNT always return 0 so maybe is there another way of doing this ?

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  • prints line number in both txtfile and list????

    - by jad
    i have this code which prints the line number in infile but also the linenumber in words what do i do to only print the line number of the txt file next to the words??? d = {} counter = 0 wrongwords = [] for line in infile: infile = line.split() wrongwords.extend(infile) counter += 1 for word in infile: if word not in d: d[word] = [counter] if word in d: d[word].append(counter) for stuff in wrongwords: print(stuff, d[stuff]) the output is : hello [1, 2, 7, 9] # this is printing the linenumber of the txt file hello [1] # this is printing the linenumber of the list words hello [1] what i want is: hello [1, 2, 7, 9]

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  • How to write a Python 2.6+ script that does gracefully fail with older pyhton?

    - by Sorin Sbarnea
    I'm using the new print from Python 3.x and I observed that the following code does not compile due to the end=' '. from __future__ import print_function import sys if sys.hexversion < 0x02060000: raise Exception("py too old") ... print("x",end=" ") # fails to compile with py24 How can I continue using the new syntax but make the script fails nicely? Is it mandatory to call another script and use only safe syntax in this one?

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  • Get active window title in X

    - by dutt
    I'm trying to get the title of the active window. The application is a background task so if the user has Eclipse open the function returns "Eclipse - blabla", so it's not getting the window title of my own window. I'm developing this in Python 2.6 using PyQt4. My current solution, borrowed and slightly modified from an old answer here at SO, looks like this: def get_active_window_title(): title = '' root_check = '' root = Popen(['xprop', '-root'], stdout=PIPE) if root.stdout != root_check: root_check = root.stdout for i in root.stdout: if '_NET_ACTIVE_WINDOW(WINDOW):' in i: id_ = i.split()[4] id_w = Popen(['xprop', '-id', id_], stdout=PIPE) for j in id_w.stdout: if 'WM_ICON_NAME(STRING)' in j: if title != j.split()[2]: return j.split("= ")[1].strip(' \n\"') It works for most windows, but not all. For example it can't find my kopete chat windows, or the name of the application i'm currently developing. My next try looks like this: def get_active_window_title(self): screen = wnck.screen_get_default() if screen == None: return "Could not get screen" window = screen.get_active_window() if window == None: return "Could not get window" title = window.get_name() return title; But for some reason window is always None. Does somebody have a better way of getting the current window title, or how to modify one of my ways, that works for all windows? Edit: In case anybody is wondering this is the way I found that seems to work for all windows. def get_active_window_title(self): root_check = '' root = Popen(['xprop', '-root'], stdout=PIPE) if root.stdout != root_check: root_check = root.stdout for i in root.stdout: if '_NET_ACTIVE_WINDOW(WINDOW):' in i: id_ = i.split()[4] id_w = Popen(['xprop', '-id', id_], stdout=PIPE) id_w.wait() buff = [] for j in id_w.stdout: buff.append(j) for line in buff: match = re.match("WM_NAME\((?P<type>.+)\) = (?P<name>.+)", line) if match != None: type = match.group("type") if type == "STRING" or type == "COMPOUND_TEXT": return match.group("name") return "Active window not found"

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  • How can c let a function declaration with any parameter type ?

    - by kamil çakir
    I forgot to write void parameter but it works the i put void it gives error it lets this: print(int size,int table[size][size]){ int i,j; printf("-------TABLE-------\n"); for(i = 0;i it says"previos implicit declaration was here " (means the call in main) void print(int size,int table[size][size]){ int i,j; printf("-------TABLE-------\n"); for(i = 0;i

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  • Perl chomp backwording the string

    - by joe
    my $cmd = "grep -h $text $file2 $file1 | tail -1 | awk '{print \$NF }' "; my $port_number; $port_number =`$cmd`; print "port No : ==$port_number=="; the output is : "port No :== 2323 == and i tried chomp its not working

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  • Mobile detection - Meta tag and max-device-width vs. php user agent?

    - by nimmbl
    Which form of mobile detection should I use and why? <meta name="viewport" content="width=320,initial-scale=1,maximum-scale=1.0,user-scalable=no" /> <link media="only screen and (max-device-width: 480px) and (min-device-width: 320px)" href="css/mobile.css" type= "text/css" rel="stylesheet"> <link media="handheld, only screen and (max-device-width: 319px)" href="css/mobile_simple.css" type="text/css" rel="stylesheet" /> Or include('mobile_device_detect.php'); $mobile = mobile_device_detect(); And why on earth would this: <?php if(strpos($_SERVER['HTTP_USER_AGENT'], 'iPhone') !== false) { ?> <meta name="viewport" content="width=320,initial-scale=1,maximum-scale=1.0,user-scalable=no" /> <link media="screen" href="css/mobile.css" type= "text/css" rel="stylesheet"> <?php } else { ?> <link media="screen" href="css/mobile_simple.css" type= "text/css" rel="stylesheet"> <?php } ?> ignore this css? body { background: -webkit-gradient(linear, left top, left bottom, from(#555), to(#000)); }

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  • CSS to specify positions over a scanned document

    - by itsols
    I'm trying to write the CSS rules to position text over a scanned document. Reason: The document is a pre-printed form. I am trying to position the text on-screen so that it relates to the 'spaces' on the actual form. Issue: Although I position the values using centimeters, they don't seem to get aligned with the ones on the actual page. I can see this misalignment since my scanned image is in the background of the page. What I've tried: I used a ruler to physically measure the locations and specify them with CSS. But on-screen, it doesn't tally. I used the scanned image to position the CSS values. Then the printout is not correct. I even scaled the scanned page using Inkscape to the exact dimensions in centimeters and took into account all margins, etc... What I need: I am trying to correctly show the output values on-screen AND have them print in the correct manner as well. I know that using two CSS sheets (one for print) is an option. But I'm developing this program away from where the actual printing is to be done. So is there a convenient way of matching the exact screen locations with those on the actual/final prinout? Thanks!

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  • How to call a method from another class that's been instantiated within the current class

    - by Pavan
    my screen has a few views like such __________________ | _____ | | | | | //viewX is a video screen | | | | | viewX | vY | | //viewY is a custom uiview i created. | |____| | //it contains a method which i would like to call that toggles |_________________| //the hidden property of this view. and when it hides, a little | | //button is replaced no the top right corner on top of viewX | viewZ | //the video layer | | |_________________| //viewZ is a view containing many square views - thumbnails. my question is, i dont know how to register for touch events so that it recognises any touch event on no matter which view the user touches the screen.. atm im handling the touch events for each view inside it. so all works well... however what im trying to do is that when the user taps anywhere else on the screen but on viewY, viewY should dissapear by calling that method in the viewY class. this viewY class is instantiated and has no xib file attached to it. the uiview is created progammatically in the viewY class. this whole class for viewY behviour is instantiated in viewX - the video view. my boss says add delegates.. although i have now clue how to do that... any help? is there anyway i can just make it really simple and be able to say REMOVE VIEW no matter which class im calling from? Also ive seen other people achieve this by using these funky arrows - ... <- etc.. although im not sure if thats what i need or how to implement such a thing. ah i think ive made my question quite complicated but i really mean it to be a simple one, and know it can be done in an easy way!

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  • Is there some way to make variables like $a and $b in regard to strict?

    - by Axeman
    In light of Michael Carman's comment, I have decided to rewrite the question. Note that 11 comments appear before this edit, and give credence to Michael's observation that I did not write the question in a way that made it clear what I was asking. Question: What is the standard--or cleanest way--to fake the special status that $a and $b have in regard to strict by simply importing a module? First of all some setup. The following works: #!/bin/perl use strict; print "\$a=$a\n"; print "\$b=$b\n"; If I add one more line: print "\$c=$c\n"; I get an error at compile time, which means that none of my dazzling print code gets to run. If I comment out use strict; it runs fine. Outside of strictures, $a and $b are mainly special in that sort passes the two values to be compared with those names. my @reverse_order = sort { $b <=> $a } @unsorted; Thus the main functional difference about $a and $b--even though Perl "knows their names"--is that you'd better know this when you sort, or use some of the functions in List::Util. It's only when you use strict, that $a and $b become special variables in a whole new way. They are the only variables that strict will pass over without complaining that they are not declared. : Now, I like strict, but it strikes me that if TIMTOWTDI (There is more than one way to do it) is Rule #1 in Perl, this is not very TIMTOWDI. It says that $a and $b are special and that's it. If you want to use variables you don't have to declare $a and $b are your guys. If you want to have three variables by adding $c, suddenly there's a whole other way to do it. Nevermind that in manipulating hashes $k and $v might make more sense: my %starts_upper_1_to_25 = skim { $k =~ m/^\p{IsUpper}/ && ( 1 <= $v && $v <= 25 ) } %my_hash ;` Now, I use and I like strict. But I just want $k and $v to be visible to skim for the most compact syntax. And I'd like it to be visible simply by use Hash::Helper qw<skim>; I'm not asking this question to know how to black-magic it. My "answer" below, should let you know that I know enough Perl to be dangerous. I'm asking if there is a way to make strict accept other variables, or what is the cleanest solution. The answer could well be no. If that's the case, it simply does not seem very TIMTOWTDI.

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  • python-McNuggets

    - by challarao
    I have created some program for this.But printed a,b,c values are not correct.Please check this weather it is correct or not? n=input("Enter the no.of McNuggets:") a,b,c=0,0,0 count=0 for a in range(n): if 6*a+9*b+20*c==n: count=count+1 break else: for b in range(n): if 6*a+9*b+20*c==n: count=count+1 break else: for c in range(n): if 6*a+9*b+20*c==n: count=count+1 break if count>0: print "It is possible to buy exactly",n,"packs of McNuggetss",a,b,c else: print "It is not possible to buy"

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  • Why are my two date fields not identical when I copy them?

    - by Hobhouse
    I use django, and have two models with a models.DateTimeField(). Sometimes I need a copy of a date - but look at this: >>>myobject.date = datetime.datetime.now() >>>print myobject.date >>>2010-04-27 12:10:43.526277 >>>other_object.date_copy = myobject.date >>>print other_object.date_copy >>>2010-04-27 12:10:43 Why are these two dates not identical, and how do I make an excact copy of myobject.date?

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  • What happens when I instantiate class in Python?

    - by Konstantin
    Could you clarify some ideas behind Python classes and class instances? Consider this: class A(): name = 'A' a = A() a.name = 'B' # point 1 (instance of class A is used here) print a.name print A.name prints: B A if instead in point 1 I use class name, output is different: A.name = 'B' # point 1 (updated, class A itself is used here) prints: B B Even if classes in Python were some kind of prototype for class instances, I'd expect already created instances to remain intact, i.e. output like this: A B Can you explain what is actually going on?

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  • php extending but with a new constructor...possible?

    - by Patrick
    I have a class: class test { function __construct() { print 'hello'; } function func_one() { print 'world'; } } what I would like to do is a have a class that sort of extends the test class. I say 'sort of', because the class needs to be able to run whatever function the test class is able to run, but NOT run the construct unless I ask it to. I do not want to override the construct. Anyone has any idea how to achieve this?

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