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  • Converting keys of an array/object-tree to lowercase

    - by tstenner
    Im currently optimizing a PHP application and found one function being called around 10-20k times, so I'd thought I'd start optimization there. function keysToLower($obj) { if(!is_object($obj) && !is_array($obj)) return $obj; foreach($obj as $key=>$element) { $element=keysToLower($element); if(is_object($obj)) { $obj->{strtolower($key)}=$element; if(!ctype_lower($key)) unset($obj->{$key}); } else if(is_array($obj) && ctype_upper($key)) { $obj[strtolower($key)]=$element; unset($obj[$key]); } } return $obj; } Most of the time is spent in recursive calls (which are quite slow in PHP), but I don't see any way to convert it to a loop. What would you do?

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  • How to hide some nodes in Richfaces Tree (do not render nodes by condition)?

    - by VestniK
    I have a tree of categories and courses in my SEAM application. Courses may be active and inactive. I want to be able to show only active or all courses in my tree. I've decided to always build complete tree in my PAGE scope component since building this tree is quite expensive operation. I have boolean flag courseActive in the data wrapped by TreeNode<T>. Now I can't find the way to show courses node only if this flag is true. The best result I've achieved with the following code: <h:outputLabel for="showInactiveCheckbox" value="show all courses: "/> <h:selectBooleanCheckbox id="showInactiveCheckbox" value="#{categoryTreeEditorModel.showAllCoursesInTree}"> <a4j:support event="onchange" reRender="categoryTree"/> </h:selectBooleanCheckbox> <rich:tree id="categoryTree" value="#{categoryTree}" var="item" switchType="ajax" ajaxSubmitSelection="true" reRender="categoryTree,controls" adviseNodeOpened="#{categoryTreeActions.adviseRootOpened}" nodeSelectListener="#{categoryTreeActions.processSelection}" nodeFace="#{item.typeName}"> <rich:treeNode type="Category" icon="..." iconLeaf="..."> <h:outputText value="#{item.title}"/> </rich:treeNode> <rich:treeNode type="Course" icon="..." iconLeaf="..." rendered="#{item.courseActive or categoryTreeEditorModel.showAllCoursesInTree}"> <h:outputText rendered="#{item.courseActive}" value="#{item.title}"/> <h:outputText rendered="#{not item.courseActive}" value="#{item.title}" style="color:#{a4jSkin.inactiveTextColor}"/> </rich:treeNode> </rich:tree> the only problem is if some node is not listed in any rich:treeNode it just still shown with title obtained by Object.toString() method insted of being hidden. Does anybody know how to not show some nodes in the Richfases tree according to some condition?

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  • How hide some nodes in Richfaces Tree (do not render nodes by condition)?

    - by VestniK
    I have a tree of categories and courses in my SEAM application. Courses may be active and inactive. I want to be able to show only active or all courses in my tree. I've decided to always build complete tree in my PAGE scope component since building this tree is quite expensive operation. I have boolean flag courseActive in the data wrapped by TreeNode<T>. Now I can't find the way to show courses node only if this flag is true. The best result I've achieved with the following code: <h:outputLabel for="showInactiveCheckbox" value="show all courses: "/> <h:selectBooleanCheckbox id="showInactiveCheckbox" value="#{categoryTreeEditorModel.showAllCoursesInTree}"> <a4j:support event="onchange" reRender="categoryTree"/> </h:selectBooleanCheckbox> <rich:tree id="categoryTree" value="#{categoryTree}" var="item" switchType="ajax" ajaxSubmitSelection="true" reRender="categoryTree,controls" adviseNodeOpened="#{categoryTreeActions.adviseRootOpened}" nodeSelectListener="#{categoryTreeActions.processSelection}" nodeFace="#{item.typeName}"> <rich:treeNode type="Category" icon="..." iconLeaf="..."> <h:outputText value="#{item.title}"/> </rich:treeNode> <rich:treeNode type="Course" icon="..." iconLeaf="..." rendered="#{item.courseActive or categoryTreeEditorModel.showAllCoursesInTree}"> <h:outputText rendered="#{item.courseActive}" value="#{item.title}"/> <h:outputText rendered="#{not item.courseActive}" value="#{item.title}" style="color:#{a4jSkin.inactiveTextColor}"/> </rich:treeNode> </rich:tree> the only problem is if some node is not listed in any rich:treeNode it just still shown with title obtained by Object.toString() method insted of being hidden. Does anybody know how to not show some nodes in the Richfases tree according to some condition?

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  • Efficient representation of Hierarchies in Hibernate.

    - by Alison G
    I'm having some trouble representing an object hierarchy in Hibernate. I've searched around, and haven't managed to find any examples doing this or similar - you have my apologies if this is a common question. I have two types which I'd like to persist using Hibernate: Groups and Items. * Groups are identified uniquely by a combination of their name and their parent. * The groups are arranged in a number of trees, such that every Group has zero or one parent Group. * Each Item can be a member of zero or more Groups. Ideally, I'd like a bi-directional relationship allowing me to get: * all Groups that an Item is a member of * all Items that are a member of a particular Group or its descendants. I also need to be able to traverse the Group tree from the top in order to display it on the UI. The basic object structure would ideally look like this: class Group { ... /** @return all items in this group and its descendants */ Set<Item> getAllItems() { ... } /** @return all direct children of this group */ Set<Group> getChildren() { ... } ... } class Item { ... /** @return all groups that this Item is a direct member of */ Set<Group> getGroups() { ... } ... } Originally, I had just made a simple bi-directional many-to-many relationship between Items and Groups, such that fetching all items in a group hierarchy required recursion down the tree, and fetching groups for an Item was a simple getter, i.e.: class Group { ... private Set<Item> items; private Set<Group> children; ... /** @return all items in this group and its descendants */ Set<Item> getAllItems() { Set<Item> allItems = new HashSet<Item>(); allItems.addAll(this.items); for(Group child : this.getChildren()) { allItems.addAll(child.getAllItems()); } return allItems; } /** @return all direct children of this group */ Set<Group> getChildren() { return this.children; } ... } class Item { ... private Set<Group> groups; /** @return all groups that this Item is a direct member of */ Set<Group> getGroups() { return this.groups; } ... } However, this resulted in multiple database requests to fetch the Items in a Group with many descendants, or for retrieving the entire Group tree to display in the UI. This seems very inefficient, especially with deeper, larger group trees. Is there a better or standard way of representing this relationship in Hibernate? Am I doing anything obviously wrong or stupid? My only other thought so far was this: Replace the group's id, parent and name fields with a unique "path" String which specifies the whole ancestry of a group, e.g.: /rootGroup /rootGroup/aChild /rootGroup/aChild/aGrandChild The join table between Groups and Items would then contain group_path and item_id. This immediately solves the two issues I was suffering previously: 1. The entire group hierarchy can be fetched from the database in a single query and reconstructed in-memory. 2. To retrieve all Items in a group or its descendants, we can select from group_item where group_path='N' or group_path like 'N/%' However, this seems to defeat the point of using Hibernate. All thoughts welcome!

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  • How can I create a new branch in git from an existing file tree?

    - by pkaeding
    I am looking to add an existing file tree to a git repository as a new branch (I can't just copy the existing tree into my git tree, since the existing tree is versioned under a different VCS, and I am trying to sync them up). Is this possible? EDIT: Would setting up a new git repository, that is connected to the existing remote repository, and then moving the resulting .git folder work? That seems really hackish, but if that's the way to do it...

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  • Auto-Suggest via &lsquo;Trie&rsquo; (Pre-fix Tree)

    - by Strenium
    Auto-Suggest (Auto-Complete) “thing” has been around for a few years. Here’s my little snippet on the subject. For one of my projects, I had to deal with a non-trivial set of items to be pulled via auto-suggest used by multiple concurrent users. Simple, dumb iteration through a list in local cache or back-end access didn’t quite cut it. Enter a nifty little structure, perfectly suited for storing and matching verbal data: “Trie” (http://tinyurl.com/db56g) also known as a Pre-fix Tree: “Unlike a binary search tree, no node in the tree stores the key associated with that node; instead, its position in the tree defines the key with which it is associated. All the descendants of a node have a common prefix of the string associated with that node, and the root is associated with the empty string. Values are normally not associated with every node, only with leaves and some inner nodes that correspond to keys of interest.” This is a very scalable, performing structure. Though, as usual, something ‘fast’ comes at a cost of ‘size’; fortunately RAM is more plentiful today so I can live with that. I won’t bore you with the detailed algorithmic performance here - Google can do a better job of such. So, here’s C# implementation of all this. Let’s start with individual node: Trie Node /// <summary> /// Contains datum of a single trie node. /// </summary> public class AutoSuggestTrieNode {     public char Value { get; set; }       /// <summary>     /// Gets a value indicating whether this instance is leaf node.     /// </summary>     /// <value>     ///     <c>true</c> if this instance is leaf node; otherwise, a prefix node <c>false</c>.     /// </value>     public bool IsLeafNode { get; private set; }       public List<AutoSuggestTrieNode> DescendantNodes { get; private set; }         /// <summary>     /// Initializes a new instance of the <see cref="AutoSuggestTrieNode"/> class.     /// </summary>     /// <param name="value">The phonetic value.</param>     /// <param name="isLeafNode">if set to <c>true</c> [is leaf node].</param>     public AutoSuggestTrieNode(char value = ' ', bool isLeafNode = false)     {         Value = value;         IsLeafNode = isLeafNode;           DescendantNodes = new List<AutoSuggestTrieNode>();     }       /// <summary>     /// Gets the descendants of the pre-fix node, if any.     /// </summary>     /// <param name="descendantValue">The descendant value.</param>     /// <returns></returns>     public AutoSuggestTrieNode GetDescendant(char descendantValue)     {         return DescendantNodes.FirstOrDefault(descendant => descendant.Value == descendantValue);     } }   Quite self-explanatory, imho. A node is either a “Pre-fix” or a “Leaf” node. “Leaf” contains the full “word”, while the “Pre-fix” nodes act as indices used for matching the results.   Ok, now the Trie: Trie Structure /// <summary> /// Contains structure and functionality of an AutoSuggest Trie (Pre-fix Tree) /// </summary> public class AutoSuggestTrie {     private readonly AutoSuggestTrieNode _root = new AutoSuggestTrieNode();       /// <summary>     /// Adds the word to the trie by breaking it up to pre-fix nodes + leaf node.     /// </summary>     /// <param name="word">Phonetic value.</param>     public void AddWord(string word)     {         var currentNode = _root;         word = word.Trim().ToLower();           for (int i = 0; i < word.Length; i++)         {             var child = currentNode.GetDescendant(word[i]);               if (child == null) /* this character hasn't yet been indexed in the trie */             {                 var newNode = new AutoSuggestTrieNode(word[i], word.Count() - 1 == i);                   currentNode.DescendantNodes.Add(newNode);                 currentNode = newNode;             }             else                 currentNode = child; /* this character is already indexed, move down the trie */         }     }         /// <summary>     /// Gets the suggested matches.     /// </summary>     /// <param name="word">The phonetic search value.</param>     /// <returns></returns>     public List<string> GetSuggestedMatches(string word)     {         var currentNode = _root;         word = word.Trim().ToLower();           var indexedNodesValues = new StringBuilder();         var resultBag = new ConcurrentBag<string>();           for (int i = 0; i < word.Trim().Length; i++)  /* traverse the trie collecting closest indexed parent (parent can't be leaf, obviously) */         {             var child = currentNode.GetDescendant(word[i]);               if (child == null || word.Count() - 1 == i)                 break; /* done looking, the rest of the characters aren't indexed in the trie */               indexedNodesValues.Append(word[i]);             currentNode = child;         }           Action<AutoSuggestTrieNode, string> collectAllMatches = null;         collectAllMatches = (node, aggregatedValue) => /* traverse the trie collecting matching leafNodes (i.e. "full words") */             {                 if (node.IsLeafNode) /* full word */                     resultBag.Add(aggregatedValue); /* thread-safe write */                   Parallel.ForEach(node.DescendantNodes, descendandNode => /* asynchronous recursive traversal */                 {                     collectAllMatches(descendandNode, String.Format("{0}{1}", aggregatedValue, descendandNode.Value));                 });             };           collectAllMatches(currentNode, indexedNodesValues.ToString());           return resultBag.OrderBy(o => o).ToList();     }         /// <summary>     /// Gets the total words (leafs) in the trie. Recursive traversal.     /// </summary>     public int TotalWords     {         get         {             int runningCount = 0;               Action<AutoSuggestTrieNode> traverseAllDecendants = null;             traverseAllDecendants = n => { runningCount += n.DescendantNodes.Count(o => o.IsLeafNode); n.DescendantNodes.ForEach(traverseAllDecendants); };             traverseAllDecendants(this._root);               return runningCount;         }     } }   Matching operations and Inserts involve traversing the nodes before the right “spot” is found. Inserts need be synchronous since ordering of data matters here. However, matching can be done in parallel traversal using recursion (line 64). Here’s sample usage:   [TestMethod] public void AutoSuggestTest() {     var autoSuggestCache = new AutoSuggestTrie();       var testInput = @"Lorem ipsum dolor sit amet, consectetur adipiscing elit. Integer nec odio. Praesent libero.                 Sed cursus ante dapibus diam. Sed nisi. Nulla quis sem at nibh elementum imperdiet. Duis sagittis ipsum. Praesent mauris.                 Fusce nec tellus sed augue semper porta. Mauris massa. Vestibulum lacinia arcu eget nulla. Class aptent taciti sociosqu ad                 litora torquent per conubia nostra, per inceptos himenaeos. Curabitur sodales ligula in libero. Sed dignissim lacinia nunc.                 Curabitur tortor. Pellentesque nibh. Aenean quam. In scelerisque sem at dolor. Maecenas mattis. Sed convallis tristique sem.                 Proin ut ligula vel nunc egestas porttitor. Morbi lectus risus, iaculis vel, suscipit quis, luctus non, massa. Fusce ac                 turpis quis ligula lacinia aliquet. Mauris ipsum. Nulla metus metus, ullamcorper vel, tincidunt sed, euismod in, nibh. Quisque                 volutpat condimentum velit. Class aptent taciti sociosqu ad litora torquent per conubia nostra, per inceptos himenaeos. Nam                 nec ante. Sed lacinia, urna non tincidunt mattis, tortor neque adipiscing diam, a cursus ipsum ante quis turpis. Nulla                 facilisi. Ut fringilla. Suspendisse potenti. Nunc feugiat mi a tellus consequat imperdiet. Vestibulum sapien. Proin quam. Etiam                 ultrices. Suspendisse in justo eu magna luctus suscipit. Sed lectus. Integer euismod lacus luctus magna. Quisque cursus, metus                 vitae pharetra auctor, sem massa mattis sem, at interdum magna augue eget diam. Vestibulum ante ipsum primis in faucibus orci                 luctus et ultrices posuere cubilia Curae; Morbi lacinia molestie dui. Praesent blandit dolor. Sed non quam. In vel mi sit amet                 augue congue elementum. Morbi in ipsum sit amet pede facilisis laoreet. Donec lacus nunc, viverra nec.";       testInput.Split(' ').ToList().ForEach(word => autoSuggestCache.AddWord(word));       var testMatches = autoSuggestCache.GetSuggestedMatches("le"); }   ..and the result: That’s it!

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  • Can I use CodeSynthesis XSD (C++/Tree mapping) together with a GPLv3-licensed library?

    - by Erik Sjölund
    Is it possible to write an open source project that uses generated code from CodeSynthesis XSD (C++/Tree) and then link it to a third-party library that is licensed under the GPL version 3? Some background information: CodeSynthesis XSD is licensed under the GPL version 2 but with an extra FLOSS exception (http://www.codesynthesis.com/projects/xsd/FLOSSE). C++ source code generated from CodeSynthesis XSD (C++/Tree) needs to be linked against Xerces (http://xerces.apache.org/xerces-c/) that is licensed under the Apache License 2.0. Update I posted a similar question on the xsd-users mailing list two years ago but I didn't fully understand the answers. In that email thread, I wrote: I think it is the GPL version 3 software that doesn't allow itself be linked to software that can't be "relicensed" to GPL version 3 ( for instance GPL version 2 software ). That would also include XSD as the FLOSS exception doesn't give permission to "relicense" XSD to GPL version 3.

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  • How to discriminate from two nodes with identical frequencies in a Huffman's tree?

    - by Omega
    Still on my quest to compress/decompress files with a Java implementation of Huffman's coding (http://en.wikipedia.org/wiki/Huffman_coding) for a school assignment. From the Wikipedia page, I quote: Create a leaf node for each symbol and add it to the priority queue. While there is more than one node in the queue: Remove the two nodes of highest priority (lowest probability) from the queue Create a new internal node with these two nodes as children and with probability equal to the sum of the two nodes' probabilities. Add the new node to the queue. The remaining node is the root node and the tree is complete. Now, emphasis: Remove the two nodes of highest priority (lowest probability) from the queue Create a new internal node with these two nodes as children and with probability equal to the sum of the two nodes' probabilities. So I have to take two nodes with the lowest frequency. What if there are multiple nodes with the same low frequency? How do I discriminate which one to use? The reason I ask this is because Wikipedia has this image: And I wanted to see if my Huffman's tree was the same. I created a file with the following content: aaaaeeee nnttmmiihhssfffouxprl And this was the result: Doesn't look so bad. But there clearly are some differences when multiple nodes have the same frequency. My questions are the following: What is Wikipedia's image doing to discriminate the nodes with the same frequency? Is my tree wrong? (Is Wikipedia's image method the one and only answer?) I guess there is one specific and strict way to do this, because for our school assignment, files that have been compressed by my program should be able to be decompressed by other classmate's programs - so there must be a "standard" or "unique" way to do it. But I'm a bit lost with that. My code is rather straightforward. It literally just follows Wikipedia's listed steps. The way my code extracts the two nodes with the lowest frequency from the queue is to iterate all nodes and if the current node has a lower frequency than any of the two "smallest" known nodes so far, then it replaces the highest one. Just like that.

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  • Is there a keyboard shortcut to toggle Tree view / Places View?

    - by zinzolin
    I find both the Tree view and the Places view useful. Changing from one view to the other is not fast because one have to go into the appearance menu. It's even slower with Oneiric because this menu can now be far away. (Before Unity, I always had the tree view on and I used my bookmarks directly from the Places menu. That was fine) Is there a keyboard shortcut to toggle from one view to the other? Or is it possible to create one oneself? Thanks a lot the help !

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  • Example usage of a custom delegate in c#

    - by Freakishly
    Hi, I found this question on SO about a tree implementation in C#. I have no idea about delegates and I was wondering how the following code could be used to implement a tree. Also, what would be the most efficient way to keep a track of parent nodes? delegate void TreeVisitor<T>(T nodeData); class NTree<T> { T data; LinkedList<NTree<T>> children; public NTree(T data) { this.data = data; children = new LinkedList<NTree<T>>(); } public void addChild(T data) { children.AddFirst(new NTree<T>(data)); } public NTree<T> getChild(int i) { foreach (NTree<T> n in children) if (--i == 0) return n; return null; } public void traverse(NTree<T> node, TreeVisitor<T> visitor) { visitor(node.data); foreach (NTree<T> kid in node.children) traverse(kid, visitor); } }

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  • Deeply nested subqueries for traversing trees in MySQL

    - by nickf
    I have a table in my database where I store a tree structure using the hybrid Nested Set (MPTT) model (the one which has lft and rght values) and the Adjacency List model (storing parent_id on each node). my_table (id, parent_id, lft, rght, alias) This question doesn't relate to any of the MPTT aspects of the tree but I thought I'd leave it in in case anyone had a good idea about how to leverage that. I want to convert a path of aliases to a specific node. For example: "users.admins.nickf" would find the node with alias "nickf" which is a child of one with alias "admins" which is a child of "users" which is at the root. There is a unique index on (parent_id, alias). I started out by writing the function so it would split the path to its parts, then query the database one by one: SELECT `id` FROM `my_table` WHERE `parent_id` IS NULL AND `alias` = 'users';-- 1 SELECT `id` FROM `my_table` WHERE `parent_id` = 1 AND `alias` = 'admins'; -- 8 SELECT `id` FROM `my_table` WHERE `parent_id` = 8 AND `alias` = 'nickf'; -- 37 But then I realised I could do it with a single query, using a variable amount of nesting: SELECT `id` FROM `my_table` WHERE `parent_id` = ( SELECT `id` FROM `my_table` WHERE `parent_id` = ( SELECT `id` FROM `my_table` WHERE `parent_id` IS NULL AND `alias` = 'users' ) AND `alias` = 'admins' ) AND `alias` = 'nickf'; Since the number of sub-queries is dependent on the number of steps in the path, am I going to run into issues with having too many subqueries? (If there even is such a thing) Are there any better/smarter ways to perform this query?

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  • How to get child nodes after store load

    - by Azincourt
    Version: ExtJs 4.1 To change the child items I use this function: TreeStore (Ext.data.TreeStore) storeId : 'treeStore', ... constructor: function( oConfig ) { ... this.on( 'expand', function( oObj ) { oObj.eachChild(function(oNode) { switch(oNode.data.type) { case "report": oNode.set('icon', strIconReport); break; case "view": oNode.set('icon', strIconView); break; } }); }); Reload After removing or adding items in the tree, I reload the tree somewhere else with: var oStore = Ext.getStore('treeStore'); oStore.load({ node : oNode, params : { newpath : oNode.data.path, overwrite : true } }); Although it is the same store treeStore, after loading and expanding to the correct path, the icons are not changed since the .on( 'expand') function is not called. Why? Question How can I change the icons of this newly loaded store before it expands to the node path? What I tried Before calling .load() I tried to edit the children with oNode.eachChild(function(oChild) {} but no success.

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  • SSTP BPDU with bad TLV and macflap -- info please

    - by Adeodatus
    Hi All, I'm slowly locking down the network I've inherited and mac-flapping has been a problem in the past with customers doing all kinds of crazy things. Thats changing but I am now encountering this error: Dec 30 18:31:31 10.50.1.50 1565: 001567: Dec 30 18:31:30: %SW_MATM-4-MACFLAP_NOTIF: Host xxxx.xxxx.f681 in vlan 1 is flapping between port Gi0/5 and port Gi0/48 Dec 30 18:43:28 10.50.1.50 1566: 001568: Dec 30 18:43:26: %SPANTREE-2-RECV_BAD_TLV: Received SSTP BPDU with bad TLV on GigabitEthernet0/5 VLAN1. Dec 30 18:48:18 10.50.1.50 1567: 001569: .Dec 30 18:48:17: %SPANTREE-2-RECV_BAD_TLV: Received SSTP BPDU with bad TLV on GigabitEthernet0/5 VLAN1. unfortunately, that mac address is the mac of our core router, the only link to the internet, on port gi0/48 On the other end of gi0/5, I have about 50 bridged customer machines connected through a series of managed and unmanaged L2 switches. Yes, on VLAN1 too ... like I said, working on changing this slowly. In the mean time, it has me quite baffled on how to deal with this and track down the customer or switch that is the problem. What else could be going on with these messages ... the bad TLV is a new one for me. Any ideas? Thank you and Happy New Year to you all!!

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  • Confirm that two filesystems are identical, ignoring special files

    - by endolith
    /media/A and /media/B should be identical, but I want to confirm before deleting one. Duplicate file finders don't work, because they'll find two copies of the same file within B, for instance. I only want to confirm that every file in one is identical to the other. diff -qr /media/A/ /media/B/ seems to work, but the output is cluttered with garbage like diff: /media/A//etc/alternatives/ControlPanel: No such file or directory and File /media/A//dev/tty8 is a character special file while file /media/B//dev/tty8 is a character special file I can suppress the former with 2> /dev/null, but I don't know about the latter. rsync -avn /media/A/ /media/B/ also produces a bunch of clutter, like "skipping non-regular file". How can I compare the two trees and just make sure that all the real files exist in both and are identical?

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  • Solving the context menu problem with drag and drop in trees

    - by Frank Nimphius
    Normal 0 false false false EN-US X-NONE X-NONE /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin:0in; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} The following drag-and-drop problem has been reported on OTN: An ADF Faces tree component is configured with a af:collectionDropTarget tag to handle drop events. The same tree component also has a context menu defined that is shown when users select the tree with the right mouse button. The problem now was - and I could reproduce this - that the context menu stopped working after the first time the tree handled a drop event. The drag and drop use case is to associate employees from a table to a department in the tree using drag and drop. The drop handler code in the managed bean looked up the tree node that received the drop event to determine the department ID to assign to the employee. For this code similar to the one shown below was used List dropRowKey = (List) dropEvent.getDropSite(); //if no dropsite then drop area was not a data area if(dropRowKey == null){    return DnDAction.NONE; }                tree.setRowKey(dropRowKey); JUCtrlHierNodeBinding dropNode = (JUCtrlHierNodeBinding) tree.getRowData(); Normal 0 false false false EN-US X-NONE X-NONE /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin:0in; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} Normal 0 false false false EN-US X-NONE X-NONE /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin:0in; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} So what happens in this code? The drop event contains the dropSite reference, which is the row key of the tree node that received the drop event. The code then sets the key to the tree in a call to getRowDate() returns the node information for the drop target (the department). This however causes the tree state to go out of synch with its model (ADF tree binding), which is known to cause issues. In this use case the issue caused by this is that the context menu no longer shows up. To fix the problem, the code needs to be changes to read the current row key from the key, then perform the drop operation and at the end set the origin (or model) row key back //memorize current row key Object currentRowKey = tree.getRowKey();        List dropRowKey = (List) dropEvent.getDropSite(); //if no dropsite then drop area was not a data area if(dropRowKey == null){   return DnDAction.NONE;   }              tree.setRowKey(dropRowKey); JUCtrlHierNodeBinding dropNode = (JUCtrlHierNodeBinding) tree.getRowData(); ... do your stuff here .... //set current row key back tree.setRowKey(currentRowKey); AdfFacesContext.getCurrentInstance().addPartialTarget(tree); Node the code line that sets the row key back to its original value.

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  • Using antlr and the DLR together -- AST conversion

    - by RCIX
    I have an AST generated via ANTLR, and I need to convert it to a DLR-compatible one (Expression Trees). However, it would seem that i can't use tree pattern matchers for this as expression trees need their subtrees at instantiation (which i can't get). What solution would be best for me to use?

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  • How do I replace XmlTreeLoader in Ext JS?

    - by stinkycheeseman
    Ext.ux.xmltreeloader is now deprecated and I'm trying to update it but I'm not sure exactly how to do so. Here's my code: rmg.sscp.search.xmlLoader = Ext.extend(Ext.ux.tree.XmlTreeLoader, { processAttributes : function(attr){ var text = attr.tagName; attr.text = text + ' ' + attr.textContent; attr.loaded = true; attr.expanded = true; } });

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  • Alpha-Beta cutoff

    - by Becky
    I understand the basics of this search, however the beta cut-off part is confusing me, when beta <= value of alphabeta I can either return beta, break, or continue the loop. return beta doesn't seem to work properly at all, it returns the wrong players move for a different state of the board (further into the search tree) break seems to work correctly, it is very fast but it seems a bit TOO fast continue is a lot slower than break but it seems more correct...I'm guessing this is the right way but pseudocode on google all use 'break' but because this is pseudocode I'm not sure what they mean by 'break'

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  • Recursive N-way merge/diff algorithm for directory trees?

    - by BobMcGee
    What algorithms or Java libraries are available to do N-way, recursive diff/merge of directories? I need to be able to generate a list of folder trees that have many identical files, and have subdirectories with many similar files. I want to be able to use 2-way merge operations to quickly remove as much redundancy as possible. Goals: Find pairs of directories that have many similar files between them. Generate short list of directory pairs that can be synchronized with 2-way merge to eliminate duplicates Should operate recursively (there may be nested duplicates of higher-level directories) Run time and storage should be O(n log n) in numbers of directories and files Should be able to use an embedded DB or page to disk for processing more files than fit in memory (100,000+). Optional: generate an ancestry and change-set between folders Optional: sort the merge operations by how many duplicates they can elliminate I know how to use hashes to find duplicate files in roughly O(n) space, but I'm at a loss for how to go from this to finding partially overlapping sets between folders and their children. EDIT: some clarification The tricky part is the difference between "exact same" contents (otherwise hashing file hashes would work) and "similar" (which will not). Basically, I want to feed this algorithm at a set of directories and have it return a set of 2-way merge operations I can perform in order to reduce duplicates as much as possible with as few conflicts possible. It's effectively constructing an ancestry tree showing which folders are derived from each other. The end goal is to let me incorporate a bunch of different folders into one common tree. For example, I may have a folder holding programming projects, and then copy some of its contents to another computer to work on it. Then I might back up and intermediate version to flash drive. Except I may have 8 or 10 different versions, with slightly different organizational structures or folder names. I need to be able to merge them one step at a time, so I can chose how to incorporate changes at each step of the way. This is actually more or less what I intend to do with my utility (bring together a bunch of scattered backups from different points in time). I figure if I can do it right I may as well release it as a small open source util. I think the same tricks might be useful for comparing XML trees though.

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  • BST insert operation. don't insert a node if a duplicate exists already

    - by jeev
    the following code reads an input array, and constructs a BST from it. if the current arr[i] is a duplicate, of a node in the tree, then arr[i] is discarded. count in the struct node refers to the number of times a number appears in the array. fi refers to the first index of the element found in the array. after the insertion, i am doing a post-order traversal of the tree and printing the data, count and index (in this order). the output i am getting when i run this code is: 0 0 7 0 0 6 thank you for your help. Jeev struct node{ int data; struct node *left; struct node *right; int fi; int count; }; struct node* binSearchTree(int arr[], int size); int setdata(struct node**node, int data, int index); void insert(int data, struct node **root, int index); void sortOnCount(struct node* root); void main(){ int arr[] = {2,5,2,8,5,6,8,8}; int size = sizeof(arr)/sizeof(arr[0]); struct node* temp = binSearchTree(arr, size); sortOnCount(temp); } struct node* binSearchTree(int arr[], int size){ struct node* root = (struct node*)malloc(sizeof(struct node)); if(!setdata(&root, arr[0], 0)) fprintf(stderr, "root couldn't be initialized"); int i = 1; for(;i<size;i++){ insert(arr[i], &root, i); } return root; } int setdata(struct node** nod, int data, int index){ if(*nod!=NULL){ (*nod)->fi = index; (*nod)->left = NULL; (*nod)->right = NULL; return 1; } return 0; } void insert(int data, struct node **root, int index){ struct node* new = (struct node*)malloc(sizeof(struct node)); setdata(&new, data, index); struct node** temp = root; while(1){ if(data<=(*temp)->data){ if((*temp)->left!=NULL) *temp=(*temp)->left; else{ (*temp)->left = new; break; } } else if(data>(*temp)->data){ if((*temp)->right!=NULL) *temp=(*temp)->right; else{ (*temp)->right = new; break; } } else{ (*temp)->count++; free(new); break; } } } void sortOnCount(struct node* root){ if(root!=NULL){ sortOnCount(root->left); sortOnCount(root->right); printf("%d %d %d\n", (root)->data, (root)->count, (root)->fi); } }

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  • Translate C# code into AST?

    - by Erik Forbes
    Is it currently possible to translate C# code into an Abstract Syntax Tree? Edit: some clarification; I don't necessarily expect the compiler to generate the AST for me - a parser would be fine, although I'd like to use something "official." Lambda expressions are unfortunately not going to be sufficient given they don't allow me to use statement bodies, which is what I'm looking for.

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