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  • php regex - can't find the error

    - by peirix
    Just one simple, specific question: I've got the string {var1}12345{var2}, and I want to get the variable names used. if (preg_match("/{([a-zA-Z0-9]*)}/g", $url, $matches)) { print_r($matches); } If I remove the global flag, it works, but I only get the first variable, as expected. Why isn't it working with a global flag? It works when I'm testing it with the Regex Tester

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  • php: remove <p>, </p>, <br> and <br /> from beginning and end of string

    - by andufo
    $chars = " \t\n\r\0\x0B"; $pattern = '('.implode('|',array_map('preg_quote',array('<p>','</p>','<br />','<br>'))).')'."\b"; $data = trim(preg_replace('~'.$pattern.'$~i','',preg_replace('~^'.$pattern.'~i','',trim($data,$chars))),$chars); That code is set to remove all <p>,</p>,<br> and <br /> from the beginning and end of a html string. But it is no working. Any ideas?

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  • count and fetch rows in php

    - by Mac Taylor
    hey guys i have a table in my mysql database named (names) now everyone can save their real names now i want to query this table and find out how many times these names used forexample the output should be : Jakob (20) Jenny (17) now this is my own code : list($usernames) =mysql_fetch_row(mysql_query('SELECT name FROM table_user GROUP BY name ORDER BY COUNT(name) DESC LIMIT 50 ')); list($c) =mysql_num_rows(mysql_query('SELECT COUNT(name) FROM table_user GROUP BY name ')); print $usernames.'('.$c.')' is this a correct approach ?!

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  • php curly braces into array

    - by David
    Hi, I would like to check a opened .txt file for braces that open and close like below: file { nextopen { //content } } no this is not my own language or anything, but I want to get say the nextopen function and all the contents inside the brackets, and all the stuff from inside the file function and add it to an array if you know what i mean. so all the content inside the braces will be in an array. if you know how to do this please reply.

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  • Bandwidth Limit Php Not working

    - by Saxtor
    Hey How are you doing guys, i am trying to limit bandwidth per users not by ipaddress for some reason my code doesnt work i need some help, what i am trying to do is to limit the download of the user that they would only have 10Gb per day to download however it seems to me that my buffer is not working when i use multiple connections it doesnt work, but when i use one connect it works 80% here is my code can you debug the error for me thanks. /** * @author saxtor if you can improve this code email me [email protected] * @copyright 2010 */ /** * CREATE TABLE IF NOT EXISTS `max_traffic` ( `id` int(255) NOT NULL AUTO_INCREMENT, `limit` int(255) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=0 ; */ //SQL Connection [this is hackable for testing] date_default_timezone_set("America/Guyana"); mysql_connect("localhost", "root", "") or die(mysql_error()); mysql_select_db("Quota") or die(mysql_error()); function quota($id) { $result = mysql_query("SELECT `limit` FROM max_traffic WHERE id='$id' ") or die(error_log(mysql_error()));; $row = mysql_fetch_array($result); return $row[0]; } function update_quota($id,$value) { $result = mysql_query("UPDATE `max_traffic` SET `limit`='$value' WHERE id='$id'") or die(mysql_error()); return $value; } if ( quota(1) != 0) $limit = quota(1); else $limit = 0; $multipart = false; //was a part of the file requested? (partial download) $range = $_SERVER["HTTP_RANGE"]; if ($range) { $cookie .= "\r\nRange: $range"; $multipart = true; header("X-UR-RANGE-Range: $range"); } $url = 'http://127.0.0.1/puppy.iso'; $filename = basename($url); //octet-stream + attachment => client always stores file header('Content-type: application/octet-stream'); header('Content-Disposition: attachment; filename="'.$filename.'"'); //always included so clients know this script supports resuming header("Accept-Ranges: bytes"); $user_agent = ini_get("user_agent"); ini_set("user_agent", $user_agent . "\r\nCookie: enc=$cookie"); $httphandle = fopen($url, "r"); $headers = stream_get_meta_data($httphandle); $size = $headers["wrapper_data"][6]; $sizer = explode(' ',$size); $size = $sizer[1]; //let's check the return header of rapidshare for range / length indicators //we'll just pass these to the client foreach ($headers["wrapper_data"] as $header) { $header = trim($header); if (substr(strtolower($header), 0, strlen("content-range")) == "content-range") { // _insert($range); header($header); header("X-RS-RANGE-" . $header); $multipart = true; //content-range indicates partial download } elseif (substr(strtolower($header), 0, strlen("Content-Length")) == "content-length") { // _insert($range); header($header); header("X-RS-CL-" . $header); } } if ($multipart) header('HTTP/1.1 206 Partial Content'); flush(); $speed = 4128; $packet = 1; //this is private dont touch. $bufsize = 128; //this is private dont touch/ $bandwidth = 0; //this is private dont touch. while (!(connection_aborted() || connection_status() == 1) && $size > 0) { while (!feof($httphandle) && $size > 0) { if ($limit <= 0 ) $size = 0; if ( $size < $bufsize && $size != 0 && $limit != 0) { echo fread($httphandle,$size); $bandwidth += $size; } else { if( $limit != 0) echo fread($httphandle,$bufsize); $bandwidth += $bufsize; } $size -= $bufsize; $limit -= $bufsize; flush(); if ($speed > 0 && ($bandwidth > $speed*$packet*103)) { usleep(100000); $packet++; //update_quota(1,$limit); } error_log(update_quota(1,$limit)); $limit = quota(1); //if( $size <= 0 ) // exit; } fclose($httphandle); } exit;

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  • PHP versions warning on Plesk 11.0.9 upgrade on CentOS server

    - by Pixman
    I have a server turning on Plesk 10.4.4 and I want to upgrade it to 11.0.9. When I use the online upgrade tool, I have this warning: Parallels Panel pre-upgrade check... WARNING: You have a mixed set of 'php' and 'php53' packages installed. Installation or upgrade may fail or produce unexpected results. To resolve this issue run "sed -i.bak -e '/^\s*skip-bdb\s*$/d' /etc/my.cnf ; yum update 'php*' 'mysql*'". PHP Warning: Directive 'safe_mode' is deprecated in PHP 5.3 and greater in Unknown on line 0 I have run the code in ssh, but nothing changes. I have already searched all package names with "php", and I have this list: # yum list installed | grep php php-common.i386 5.3.13-5.el5.art installed php-pear.noarch 1:1.4.9-8.el5 installed php5-ioncube-loader.i386 4.0.7-11062118 installed php53.i386 5.3.3-13.el5_8 installed php53-cli.i386 5.3.3-13.el5_8 installed php53-devel.i386 5.3.3-13.el5_8 installed php53-gd.i386 5.3.3-13.el5_8 installed php53-imap.i386 5.3.3-13.el5_8 installed php53-mbstring.i386 5.3.3-13.el5_8 installed php53-mcrypt.i386 5.3.3-1.el5 installed php53-mysql.i386 5.3.3-13.el5_8 installed php53-pdo.i386 5.3.3-13.el5_8 installed php53-sqlite2.i386 5.3.2-11041315 installed php53-xml.i386 5.3.3-13.el5_8 installed psa-appvault-phpads.noarch 2.0.8-8203520080409011611 installed psa-appvault-phpbb.noarch 3.0.0-8200820080409011626 installed psa-appvault-phpbook.noarch 1.50-8203220080409011638 installed psa-appvault-phpbugtracker.noarch 1.19-8203820080416050605 installed psa-appvault-phpdig.noarch 1.85-8203120080409011645 installed psa-appvault-phpmoney.noarch 1.3-8204320080409011649 installed psa-appvault-phpmyfamily.noarch 1.4.1-8203420080409011655 installed psa-appvault-phpmyvisites.noarch 2.3-8202820080409011701 installed psa-appvault-phprojekt.noarch 5.2-8200820080409011713 installed psa-appvault-phpsurveyor.noarch 0.98-8204320080409011723 installed psa-appvault-phpwebsite.noarch 0.10.2-8203420080409011738 installed psa-appvault-phpwiki.noarch 1.3.11-8204320080409011808 installed psa-php53-configurator.i386 1.6.1-cos5.build1013111101.14 installed After verification in the Plesk file: panel_preupgrade_checker.php I think the warning is due to these lines: (from : panel_preupgrade_checker.php) foreach ($packages as $package) { $name = $package['name']; $hasPhp5 |= ($name == 'php' || strpos($name, 'php-') === 0); $hasPhp53 |= (strpos($name, 'php53') === 0); } Now, I think the problem is just due to the names of theses packages: php-common.i386 5.3.13-5.el5.art installed php-pear.noarch 1:1.4.9-8.el5 installed Can you help me to resolve this situation?

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  • How to achieve auto logoff in php ?

    - by Ramakrishnan
    I need auto-logoff system in my application. if user not using the application more than thirty minutes.they should log in again. this is what i need. lastAccessTime should be lesser than 30 minutes. if lastAccessTime exceeds than 30 minutes user should login again with their credentials. (currently i auto log off using Lastaccesstime field in My user table (database) and compare lastaccesstime with current time for every page loads, I do not think this is right way.) is their any way to achieve? Thanks in advance.

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  • [PHP] preg_replace: replacing using %

    - by Juan
    Hi all, I'm using the function preg_replace but I cannot figure out how to make it work, the function just doesn't seem to work for me. What I'm trying to do is to convert a string into a link if any word contains the % (percentage) character. For instance if I have the string "go to %mysite", I'd like to convert the mysite word into a link. I tried the following... $data = "go to %mysite"; $result = preg_replace('/(^|[\s\.\,\:\;]+)%([A-Za-z0-9]{1,64})/e', '\\1%<a href=#>\\2</a>', $data); ...but it doesn't work. Any help on this would be much appreciated. Thanks Juan

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  • Math - Adding with PHP

    - by Wayne
    Basically I can't get it right. I need something like this: if($p == 1) { $start = 0; $limit = 16; } The numbers must add on depending on the value of the $p, e.g. if $p is 5 then the values of $start and $limit would be: if($p == 5) { $start = 64; $limit = 80; } The math is to add 16, depending on the value of $p. Thanks.

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  • get value from MySQL database with PHP

    - by Hristo
    $from = $_POST['from']; $to = $_POST['to']; $message = $_POST['message']; $query = "SELECT * FROM Users WHERE `user_name` = '$from' LIMIT 1"; $result = mysql_query($query); while($row = mysql_fetch_array($result, MYSQL_ASSOC)) { $fromID = $row['user_id']; } I'm trying to have $formID be the user_id for a user in my database. Each row in the Users table is like: user_id | user_name | user_type 1 | Hristo | Agent So I want $from = 1 but the above code isn't working. Any ideas why?

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  • Lightweight CMS in PHP

    - by David
    Hi, I am building a site which will require some very limited content management for a client. There are only a few areas of the site which will require the client to be able to update the content themselves. Would it be better to create a very simple custom admin page for the client to log in and say add a news story etc or would it be best using a fully fledged CMS like Drupal etc which seems overkill to me.

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  • php push 2d array into mysql

    - by john
    Hay All, I cant seem to get my head around this dispite the number to examples i read. Basically I have a 2d array and want to insert it into MySQL. The array contains a few strings. I cant get the following to work... $value = addslashes(serialize($temp3));//temp3 is my 2d array, do i need to use keys? (i am not at the moment) $query = "INSERT INTO table sip (id,keyword,data,flags) VALUES(\"$value\")"; mysql_query($query) or die("Failed Query"); Thanks Guys,

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  • Best way to stop SQL Injection in PHP

    - by Andrew G. Johnson
    So specifically in a mysql database. Take the following code and tell me what to do. // connect to the mysql database $unsafe_variable = $_POST["user-input"]; mysql_query("INSERT INTO table (column) VALUES ('" . $unsafe_variable . "')"); // disconnect from the mysql database

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  • How do you sort php and sql arrays?

    - by Jon
    How can I sort this array by city or by id in descending order? if ($num > 0 ) { $i=0; while ($i < $num) { $city = mysql_result($result,$i,"city"); $state = mysql_result($result,$i,"state"); $id = mysql_result($result,$i,"id"); echo "$city"; echo "$state"; ++$i; } } else { echo "No results."; } ?>

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  • PHP Modify Array

    - by Ozzy
    Hi all, I have the following array: array(a, a, a, b, b, c, c, c, c, d, d); When I loop through it and echo it, the result is: a a a b b c c c c d d How ever I want to echo it in such a way that it displays: a b c d a b c d a c c Here is the array in a grid to better explain what im trying to achieve Current a a a b b c c c c d d What im tryin to do a b c d a b c d a c c How would I do this?

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  • Wrong colors when merging images with PHP

    - by OfficeJet
    Hi, I want to get images ID's and creat from files a merged image according to the given ID's. This code is called by ajax and return the image file name (which is the server time to prevent browser caching). code: if (isset($_REQUEST['items'])){ $req_items = $_REQUEST['items']; } else { $req_items = 'a'; } $items = explode(',',$req_items); $bg_img = imagecreatefrompng('bg.png'); for ($i=0; $i<count($items); $i++){ $main_img = $items[$i].'-large.png'; $image = imagecreatefrompng($main_img); $image_tc = imagecreatetruecolor(300, 200); imagecopy($image_tc,$image,0,0,0,0,300,200); $black = imagecolorallocate($image_tc, 0, 0, 0); imagecolortransparent($image_tc, $black); $opacity = 100; $bg_width = 300; $bg_height = 200; $dest_x = 0;//$image_size[0] - $bg_width - $padding; $dest_y = 0;//$image_size[1] - $bg_height - $padding; imagecopymerge($bg_img, $image_tc, $dest_x, $dest_y, 0, 0, $bg_width, $bg_height, $opacity) ; } $file = $_SERVER['REQUEST_TIME'].'.jpg'; imagejpeg($bg_img, $file, 100); echo $file; imagedestroy($bg_img); imagedestroy($image); die(); The images are shown exactly as I want but with wrong colors. I lately added the part with imagecreatetruecolor and imagecolortransparent, and still got wrong results. I also saved the PNG itself on a 24 bit format and also later as 8 bit - not helping. every ideas is very welcomed ! Thanks

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  • PHP: SimpleXML and Arrays

    - by acemasta
    When I run this code: foreach($xml->movie as $movie) { if(isset($movie->photos)) { foreach ($movie->photos as $photo) { echo $photo."&nbsp;"; } echo "<hr/>"; } } I get nice output of the actual data, e.g. a row looks like 06397001.jpg 06397002.jpg 06397003.jpg 06397004.jpg 06397005.jpg But when I throw it in an array, it includes all the SimpleXML wrapper tags and the jpgs are not at the root of the array. code: foreach($xml->movie as $movie) { if(isset($movie->photos)) { $photos = array(); foreach ($movie->photos as $photo) { $photos[] = $photo; } } else $photos = ""; var_dump($photos); echo "<hr />"; } e.g. same row looks like array(5) { [0]= object(SimpleXMLElement)#11 (1) { [0]= string(12) "06397001.jpg" } [1]= object(SimpleXMLElement)#12 (1) { [0]= string(12) "06397002.jpg" } [2]= object(SimpleXMLElement)#13 (1) { [0]= string(12) "06397003.jpg" } [3]= object(SimpleXMLElement)#14 (1) { [0]= string(12) "06397004.jpg" } [4]= object(SimpleXMLElement)#15 (1) { [0]= string(12) "06397005.jpg" } } Why is this happening/how can I remove this so I just get an array of the photos at root level like when I echo it? Thanks, sorry for the single line code formatting; was messing up when I tried to paste directly with line breaks.

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  • how to convert all characters to their html entity equivalent using PHP

    - by Ashley Ward
    I want to convert this [email protected] to &#104;&#101;&#108;&#108;&#111;&#064;&#100;&#111;&#109;&#097;&#105;&#110;&#046;&#099;&#111;&#109; I have tried: url_encode($string) this provides the same string I entered, returned with the @ symbol converted to %40 also tried: htmlentities($string) this provides the same string right back. I am using a UTF8 charset. not sure if this makes a difference....

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  • PHP & CodeIgniter Error: open_basedir restriction in effect

    - by iamdadude
    open_basedir restriction in effect. File(/var/www/vhosts/domain.com) is not within the allowed path(s): (/var/www/vhosts/domain.com/httpdocs:/tmp) How do I securely fix this? This is preventing me from listing and creating directories outside of the current directory. What I mean by securely is that I don't want to remove a piece of code from a configuration file and potentially make it easier for hackers to do whatever.

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  • php curl login not work

    - by Massimo Zampieri
    Hi i have a problem with the curl. I watched an old post Remote Login not Working With Curl, but it not work. I followed baba's advice but the code enter in the if statement. Sorry for my bad english. Can anyone help me? This is the code: $url="http://hipfile.com/"; $urllog="http://hipfile.com/login.html"; $postdata = "login=bnnoor&password=########&op=login"; $ch = curl_init(); curl_setopt ($ch, CURLOPT_URL, $url); curl_setopt ($ch, CURLOPT_SSL_VERIFYPEER, FALSE); curl_setopt ($ch, CURLOPT_USERAGENT, "Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.8.1.6) Gecko/20070725 Firefox/2.0.0.6"); curl_setopt ($ch, CURLOPT_TIMEOUT, 60); curl_setopt ($ch, CURLOPT_FOLLOWLOCATION, 1); curl_setopt ($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt ($ch, CURLOPT_REFERER, $urllog); curl_setopt ($ch, CURLOPT_POSTFIELDS, $postdata); curl_setopt ($ch, CURLOPT_POST, 1); $result = curl_exec ($ch); if (!$result) { $http_code = curl_getinfo($ch, CURLINFO_HTTP_CODE); curl_close($ch); // make sure we closeany current curl sessions die($http_code.' Unable to connect to server. Please come back later.'); } echo $result; curl_close($ch);

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