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  • How to display MySQL Select statement results in PHP

    - by Vafello
    I have the following code and it should return just one value (id) from mysql table. The following code doesnt work. How can I output it without creating arrays and all this stuff, just a simple output of one value. $query = "SELECT id FROM users_entity WHERE username = 'Admin' "; $result = map_query($query); echo $result;

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  • Safe image uploading with PHP

    - by directedition
    I want my site to have a feature for users to upload images, but I want to do it safely. Namely, I want to strip the EXIF data and any malicious code that could be in their image. I was thinking of a way to do this involving direct manipulation of the file, but it struck me, would it make more sense to just convert the image they provide to BMP and then convert that back to the original format? It would suffer a generational loss, but I believe that would meet my project's requirements. BMP doesn't contain EXIF, does it? And the reprocessing should strip any malicious content.

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  • I am unable to upload file to my local host folder in php.

    - by Nauman khan
    Hi, I have the follwing code <form enctype="multipart/form-data" action="upload.php" method="POST"> Please choose a file: <input name="uploaded" type="file" /><br /> <input type="submit" value="Upload" /> </form> <?php $target = "upload/"; $target = $target . basename( $_FILES['uploaded']['name']) ; $ok=1; if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target)) { echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded"; } else { echo "Sorry, there was a problem uploading your file."; } ?> my page is in http://localhost/nausal/upload.php now I am having the follwing error though i have created a folder in site with name upload. Notice: Undefined index: uploaded in C:\wamp\www\Nausal\upload.php on line 15 Notice: Undefined index: uploaded in C:\wamp\www\Nausal\upload.php on line 17 Sorry, there was a problem uploading your file. Please help me I am very new to php. :(

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  • PHP combobox can't save the selected value on Edit Page

    - by bEtTy Barnes
    hello I've got problem with my combobox. It's not saving the selected value in Edit page. Here what I'm working with: private function inputCAR(){ $html = ""; $selectedId = $this->CAR; //$html .= '<option value="Roadmap Accelerator - Core">Roadmap Accelerator - Core</option>'; //$html .= '<option value="Roadmap Accelerator - Optional Core">Roadmap Accelerator - Optional Core</option>'; //$html .= '<option value="Regulatory">Regulatory</option>'; //$html .= '<option value="Mission Critical">Mission Critical</option>'; //$html .= '<option value="Various CARs/Types">Various CARs/types</option>'; $selection = array( "Roadmap Accelerator - Core", "Roadmap Accelerator - Optional Core", "Regulatory", "Mission Critical", "Various CARs/types" ); $html .= '<label for="car">CAR Type</label>'; $html .= HTML::selectStart("car"); foreach($selection as $value){ $text = $value; $html .= HTML::option($value, $text, $selectedId == $value ? true : false); } $html .= HTML::selectEnd(); return $html; } My option function: public static function option($value, $text, $isSelected=false) { $html = '<option value="' . $value . '"'; if($isSelected) { $html .= ' selected="selected"'; } $html .= '>'; $html .= $text; $html .= '</option>'; return $html; } When I first created a record. The selected value from my combobox got saved into the DB then the page refreshed to display. When I went to edit page, to select another value, and clicked save button. On the display page, it's not saving. For example. on Create page I selected Regulatory. then I changed my mind and changed it to Mission Critical on Edit page. On display page it is not changed. I don't know what's wrong or what I'm missing here. Any help is welcome and truly appreciated. Thanks.

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  • PHP ingore case sensitivity when comparing array values

    - by dan.codes
    I have to modify some code in a application I am working on that is using the array_diff($array1,$array2) method. The problem I am having is it is case sensitive and I need to have it return the correct value if the array values match even if the case is different. I don't want to change the case to lowercase because I need the value returned to keep its case. I'm a little confused as the best method to do this.

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  • Calendar event correct PHP script

    - by Marin
    Hello everybody! I need somebody(If you have time:) ) to help me find a good Calendar event script that functions:)Please help me.Thank you in advance:) Ps:I am looking for a complete web application which will run on a WAMP environment and has a GUI based installer or minimal command line installation requirements

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  • PHP CHECKBOX Array Issue

    - by Val
    I have a list of checkboxes like you would see in most email clients (You tick a box press delete then it deletes an email). <input type="checkbox" value="yes" name="box[]" /> The problem stands here ... print_r($_POST['box']);//Returns nothing at all ... var_dump($_POST['box']);// returns null... I was reading something about register globals that php5 has turned it off for security reason. Does anyone know what my options are ?

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  • Adding rows to an array in PHP

    - by ChuckO
    I have loaded an associative array of records from a MySQL database table. The array consists of 1 to 7 rows representing one week of entries, which might not have been entered for each day. How can I insert blank rows into the array for the missing days so that I can easily display the data in a table? I don't need to update the database with the blanks.

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  • PHP Looping....need some advice

    - by Homer_J
    Hi all, I have the following code: $q1 = $_POST["q1"]; $q2 = $_POST["q2"]; $q3 = $_POST["q3"]; $q4 = $_POST["q4"]; $q5 = $_POST["q5"]; $q6 = $_POST["q6"]; $q7 = $_POST["q7"]; $q8 = $_POST["q8"]; At the moment, this is hard coded and I need to manually change it each time, I'd like to use variables instead so that it's not a manual process. Is it a case of using a loop, while or foreach? If I had the the information $q and q in an array would that help? Thanks, Homer.

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  • How to loop an array with strings as indexes in PHP

    - by Axel Lambregts
    I had to make an array with as indexes A-Z (the alphabet). Each index had to have a value 0. So i made this array: $alfabet = array( 'A' => 0, 'B' => 0, 'C' => 0, 'D' => 0, 'E' => 0, 'F' => 0, 'G' => 0, 'H' => 0, 'I' => 0, 'J' => 0, 'K' => 0, 'L' => 0, 'M' => 0, 'N' => 0, 'O' => 0, 'P' => 0, 'Q' => 0, 'R' => 0, 'S' => 0, 'T' => 0, 'U' => 0, 'V' => 0, 'W' => 0, 'X' => 0, 'Y' => 0, 'Z' => 0 ); I also have got text from a file ($text = file_get_contents('tekst15.txt');) I have putted the chars in that file to an array: $textChars = str_split ($text); and sorted it from A-Z: sort($textChars); What i want is that (with a for loop) when he finds an A in the textChars array, the value of the other array with index A, goes up by one (so like: $alfabet[A]++; Can anyone help me with this loop? I have this atm: for($i = 0; $i <= count($textChars); $i++){ while($textChars[$i] == $alfabet[A]){ $alfabet[A]++; } } echo $alfabet[A]; Problem 1: i want to loop the alfabet array to, so now i only check for A but i want to check all indexes. Problem2: this now returns 7 for each alphabet index i try so its totally wrong :) I'm sorry about my english but thanks for your time.

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  • search and display string from group of string php

    - by zahir hussain
    hi i want to know how to search and display string from group of string like google display the word which we search... the following example from google search word is google books result Search and preview millions of books from libraries and publishers worldwide using Google Book Search. Discover a new favorite or unearth an old classic. i would like to do this type of one... thanks and advance

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  • Confused by this PHP Exception try..catch nesting

    - by Domenic
    Hello. I'm confused by the following code: class MyException extends Exception {} class AnotherException extends MyException {} class Foo { public function something() { print "throwing AnotherException\n"; throw new AnotherException(); } public function somethingElse() { print "throwing MyException\n"; throw new MyException(); } } $a = new Foo(); try { try { $a->something(); } catch(AnotherException $e) { print "caught AnotherException\n"; $a->somethingElse(); } catch(MyException $e) { print "caught MyException\n"; } } catch(Exception $e) { print "caught Exception\n"; } I would expect this to output: throwing AnotherException caught AnotherException throwing MyException caught MyException But instead it outputs: throwing AnotherException caught AnotherException throwing MyException caught Exception Could anyone explain why it "skips over" catch(MyException $e) ? Thanks.

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  • Problem with posting the message using php

    - by Darshana
    Hello, I have successfully come up to the access_token step along with final oauth_token and oauth_token_secret values. Now I'm trying to access the Post method given by Yammer API with following request : https://www.yammer.com/api/v1/messages/? body=MyMessage& oauth_consumer_key=Myconsumerkey& oauth_nonce=1825bbc0f0a2875eb94bdb4d51c0638b& oauth_signature=JzG4DCWxuP%2B7xT7u3tFZ2zCC8%2BI%3D& oauth_signature_method=HMAC-SHA1& oauth_timestamp=1257761059& oauth_token=Myfinaloauthtoken& oauth_version=1.0 But I'm getting "Invalid OAuth signature" error. Can somebody help me in this.

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  • php cookies block access to directories

    - by user342391
    I have a mysql database of users that can login to my site and view content. I would like to block a couple of directories from certain users. What is the best way to do this. Currently when a user logs in a cookie is created with their customer id and the customer is is used to display their content. How would I block entire directories from my users???

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  • PHP PDO fetch null

    - by Jacob
    How do you check if a columns value is null? Example code: $db = DBCxn::getCxn(); $sql = "SELECT exercise_id, author_id, submission, result, submission_time, total_rating_votes, total_rating_values FROM submissions LEFT OUTER JOIN submission_ratings ON submissions.exercise_id=submission_ratings.exercise_id WHERE id=:id"; $st = $db->prepare($sql); $st->bindParam(":id", $this->id, PDO::PARAM_INT); $st->execute(); $row = $st->fetch(); if($this->total_rating_votes == null) // this doesn't seem to work even though there is no record in submission_ratings???? { ... }

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  • PHP String Encoding Error

    - by Brian
    I'm trying to get the following code to output an IMG tag with the URL for Google Static Maps API http://code.google.com/apis/maps/documentation/staticmaps/#Imagesizes embedded in there... the result is that everything except the $address is being output successfully... what am I doing wrong? function event_map_img($echo = true){ global $post; $address = get_post_meta($post->ID, 'date_address', true); if($echo): echo '<img src="'.'http://maps.google.com/maps/api/staticmap?center='.$address.'&zoom=14&size=700x512&maptype=roadmap&markers=color:blue|label:X|'.$address.'&sensor=false" />'; else: return '<img src="'.'http://maps.google.com/maps/api/staticmap?center='.$address.'&zoom=14&size=700x512&maptype=roadmap&markers=color:blue|label:X|'.$address.'&sensor=false" />'; endif; }

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  • [PHP] Sending Email Notification in Facebook JavaScript API

    - by Veera
    I'm trying to send a email notification to the user from my Facebook application. I'm trying to use the FaceBook JavaScript API function notifications_sendEmail(Array recipients, String subject, String text, String fbml, Object onRequestCompleted) I can understand the first four parameters. But what's the usage of the last parameter 'onRequestCompleted'. The Doc says it's the call back function. But, what if I do not want to execute a call back function? In this case, what will be a valid values to the parameter onRequestCompleted?

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  • PHP is not returning me a number type

    - by Tristan
    Hello, i tryed to follow that great tutorial (STAR rating with css : http://stackoverflow.com/questions/1987524/turn-a-number-into-star-rating-display-using-jquery-and-css) but i've just a big problem : When i do <span class="stars">1.75</span> or $foo='1.75'; echo '<span class="stars">'.$foo.'</span> the stars is correctly shown, but as soon as i do : while($val = mysql_fetch_array($result)) { $average = ($val['services'] + $val['serviceCli'] + $val['interface'] + $val['qualite'] + $val['rapport'] ) / 5 ; <span class="stars">.$average.</span> } the stars stops working i double checked the data type in mysql : they're all TINYINT(2) and i tryed that : $average = intval($average); but it's still not working, Thank you

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