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  • Why googling by keycaptcha gives results on reCAPTCHA? [closed]

    - by vgv8
    EDIT: I'd like to change this title to: How to STOP Google's manipulation of Google search engine presented to general public? I am frequently googling and more and more frequently bump when searching by one software product I am given instead the results on Google's own products. For ex., if I google by keyword keycaptcha for the "Past 24 hours" (after clicking on "Show search tools" -- "Past 24 hours" on the left sidebar of a browser) I am getting the Google's search results show only results on reCAPTCHA. Image uploaded later: Though, if confine keycaptcha in quotes the results are "correct" (well, kind of since they are still distorted in comparison with other search engines). I checked this during few months from different domains at different ISPs, different operating systems and from a dozen of browsers. The results are the same. Why is it and how can it be possibly corrected? My related posts: "How Gmail spam filter works?" IP adresses blacklisting Update: It is impossible for me to directly start using google.com as I am always redirected to google.ru (from google.com) by my ip-address "auto-detect location" google's "convenience". The google's help tells that it is impossible to switch off my location auto-detection because it is very helpful feature. There is a work-around to use google.com/ncr (to get google.com) (?anybody know what does it mean) to prevent redirection from google.com but even. But all results are exactly the same OK, I can search by quoted "keycaptcha", I am already accustomed to these google's quirks, but the question arises why the heck to burn time promoting someone's product if GOOGLE uses other product brands for showing its own interests/brands (reCAPTCHA) instead and what can be done with it? The general user will not understand that he was cheated and just will pick up the first (wrong) results Update2: Note that this googling behaviour: is independent on whether I am logged-in (or log-out-ed of) a google account, which account, on browser (I tried Opera, Chrome, FireFox, IE of different versions, Safari), OS or even domain; there are many such cases but I just targeted one concrete restricted example speciffically to to prevent wandering between unrelated details and peculiarities; @Michael, first it is not true and this text contains 2 links for real and significant results.. I also wrote that this is just one concrete example from many and based on many-month exp. These distortions happen upon clicking on: Past 24 hours, Past week, Past month, Past year in many other keywords, occasions/configurations of searches, etc. Second, the absence of the results is the result and there is no point to sneakingly substitute it by another unsolicited one. It is the definition of spam and scam. 3d, the question is not abt workarounds like how to write search queries or use another searching engines. The question is how to straighten the googling's results in order to stop disorienting general public about. Update: I could not understand: nobody reproduces the described by me behavior (i.e. when I click "Past 24 hours" link in google search searching for keycaptcha, the presented results are only on reCAPTCHA presented)? Update: And for the "Past week":

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  • My LAN USB NIC is not working in ubuntu 11.10?

    - by Gaurav_Java
    Today i start my system its seems that my LAN port is not working . so i buy one USB to LAN adapter and i plug in ubuntu system its doen't connect automatically .when i check result lsusb its shows me that there is one DM9601 Ethernet adapter is connected when i click on network information in panel its shows me that there is something " wired NEtwork (Broadcom NetLink BCM5784M gigabit Ethernet PCIe) I think want some driver for that .i don't have any idea how it can be used ? here output of sudo lspci -nn *00:00.0 Host bridge [0600]: Intel Corporation Mobile 4 Series Chipset Memory Controller Hub [8086:2a40] (rev 07) 00:02.0 VGA compatible controller [0300]: Intel Corporation Mobile 4 Series Chipset Integrated Graphics Controller [8086:2a42] (rev 07) 00:02.1 Display controller [0380]: Intel Corporation Mobile 4 Series Chipset Integrated Graphics Controller [8086:2a43] (rev 07) 00:1a.0 USB Controller [0c03]: Intel Corporation 82801I (ICH9 Family) USB UHCI Controller #4 [8086:2937] (rev 03) 00:1a.1 USB Controller [0c03]: Intel Corporation 82801I (ICH9 Family) USB UHCI Controller #5 [8086:2938] (rev 03) 00:1a.7 USB Controller [0c03]: Intel Corporation 82801I (ICH9 Family) USB2 EHCI Controller #2 [8086:293c] (rev 03) 00:1b.0 Audio device [0403]: Intel Corporation 82801I (ICH9 Family) HD Audio Controller [8086:293e] (rev 03) 00:1c.0 PCI bridge [0604]: Intel Corporation 82801I (ICH9 Family) PCI Express Port 1 [8086:2940] (rev 03) 00:1c.1 PCI bridge [0604]: Intel Corporation 82801I (ICH9 Family) PCI Express Port 2 [8086:2942] (rev 03) 00:1c.2 PCI bridge [0604]: Intel Corporation 82801I (ICH9 Family) PCI Express Port 3 [8086:2944] (rev 03) 00:1c.4 PCI bridge [0604]: Intel Corporation 82801I (ICH9 Family) PCI Express Port 5 [8086:2948] (rev 03) 00:1d.0 USB Controller [0c03]: Intel Corporation 82801I (ICH9 Family) USB UHCI Controller #1 [8086:2934] (rev 03) 00:1d.1 USB Controller [0c03]: Intel Corporation 82801I (ICH9 Family) USB UHCI Controller #2 [8086:2935] (rev 03) 00:1d.2 USB Controller [0c03]: Intel Corporation 82801I (ICH9 Family) USB UHCI Controller #3 [8086:2936] (rev 03) 00:1d.3 USB Controller [0c03]: Intel Corporation 82801I (ICH9 Family) USB UHCI Controller #6 [8086:2939] (rev 03) 00:1d.7 USB Controller [0c03]: Intel Corporation 82801I (ICH9 Family) USB2 EHCI Controller #1 [8086:293a] (rev 03) 00:1e.0 PCI bridge [0604]: Intel Corporation 82801 Mobile PCI Bridge [8086:2448] (rev 93) 00:1f.0 ISA bridge [0601]: Intel Corporation ICH9M LPC Interface Controller [8086:2919] (rev 03) 00:1f.2 SATA controller [0106]: Intel Corporation ICH9M/M-E SATA AHCI Controller [8086:2929] (rev 03) 00:1f.3 SMBus [0c05]: Intel Corporation 82801I (ICH9 Family) SMBus Controller [8086:2930] (rev 03) 02:00.0 Ethernet controller [0200]: Broadcom Corporation NetLink BCM5784M Gigabit Ethernet PCIe [14e4:1698] (rev 10) 04:00.0 Network controller [0280]: Intel Corporation WiFi Link 5100 [8086:4232]* sudo lshw -class network *-network description: Ethernet interface product: NetLink BCM5784M Gigabit Ethernet PCIe vendor: Broadcom Corporation physical id: 0 bus info: pci@0000:02:00.0 logical name: eth0 version: 10 serial: 00:1f:16:9a:56:98 capacity: 1Gbit/s width: 64 bits clock: 33MHz capabilities: pm vpd msi pciexpress bus_master cap_list ethernet physical tp 10bt 10bt-fd 100bt 100bt-fd 1000bt 1000bt-fd autonegotiation configuration: autonegotiation=on broadcast=yes driver=tg3 driverversion=3.119 firmware=sb v2.19 latency=0 link=no multicast=yes port=twisted pair resources: irq:47 memory:f4500000-f450ffff *-network DISABLED description: Wireless interface product: WiFi Link 5100 vendor: Intel Corporation physical id: 0 bus info: pci@0000:04:00.0 logical name: wlan0 version: 00 serial: 00:22:fa:09:02:00 width: 64 bits clock: 33MHz capabilities: pm msi pciexpress bus_master cap_list ethernet physical wireless configuration: broadcast=yes driver=iwlagn driverversion=3.0.0-17-generic firmware=8.83.5.1 build 33692 latency=0 link=no multicast=yes wireless=IEEE 802.11abgn resources: irq:46 memory:f4600000-f4601fff *-network description: Ethernet interface physical id: 4 logical name: eth1 serial: 00:60:6e:00:f1:7d size: 100Mbit/s capacity: 100Mbit/s capabilities: ethernet physical tp mii 10bt 10bt-fd 100bt 100bt-fd autonegotiation configuration: autonegotiation=on broadcast=yes driver=dm9601 driverversion=22-Aug-2005 duplex=full firmware=Davicom DM9601 USB Ethernet ip=192.168.1.34 link=yes multicast=yes port=MII speed=100Mbit/s I am using Wimax internet connection which i have to connect from browser . at that time my system is not showing that i am connected to any wired connection. but when i connect internet from other system after getting conneted to internet . when i plug again my USB LAN then its shows that you are conneted to wired connetion. here is screenshot for conneting wimax from browser after connecting to internet network connection shows

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  • Cloud – the forecast is improving

    - by Rob Farley
    There is a lot of discussion about “the cloud”, and how that affects people’s data stories. Today the discussion enters the realm of T-SQL Tuesday, hosted this month by Jorge Segarra. Over the years, companies have invested a lot in making sure that their data is good, and I mean every aspect of it – the quality of it, the security of it, the performance of it, and more. Experts such as those of us at LobsterPot Solutions have helped these companies with this, and continue to work with clients to make sure that data is a strong part of their business, not an oversight. Whether business intelligence systems are being utilised or not, every business needs to be able to rely on its data, and have the confidence in it. Data should be a foundation upon which a business is built. In the past, data had been stored in paper-based systems. Filing cabinets stored vital information. Today, people have server rooms with storage of various kinds, recognising that filing cabinets don’t necessarily scale particularly well. It’s easy to ‘lose’ data in a filing cabinet, when you have people who need to make sure that the sheets of paper are in the right spot, and that you know how things are stored. Databases help solve that problem, but still the idea of a large filing cabinet continues, it just doesn’t involve paper. If something happens to the physical ‘filing cabinet’, then the problems are larger still. Then the data itself is under threat. Many clients have generators in case the power goes out, redundant cables in case the connectivity dies, and spare servers in other buildings just in case they’re required. But still they’re maintaining filing cabinets. You see, people like filing cabinets. There’s something to be said for having your data ‘close’. Even if the data is not in readable form, living as bits on a disk somewhere, the idea that its home is ‘in the building’ is comforting to many people. They simply don’t want to move their data anywhere else. The cloud offers an alternative to this, and the human element is an obstacle. By leveraging the cloud, companies can have someone else look after their filing cabinet. A lot of people really don’t like the idea of this, partly because the administrators of the data, those people who could potentially log in with escalated rights and see more than they should be allowed to, who need to be trusted to respond if there’s a problem, are now a faceless entity in the cloud. But this doesn’t mean that the cloud is bad – this is simply a concern that some people may have. In new functionality that’s on its way, we see other hybrid mechanisms that mean that people can leverage parts of the cloud with less fear. Companies can use cloud storage to hold their backup data, for example, backups that have been encrypted and are therefore not able to be read by anyone (including administrators) who don’t have the right password. Companies can have a database instance that runs locally, but which has its data files in the cloud, complete with Transparent Data Encryption if needed. There can be a higher level of control, making the change easier to accept. Hybrid options allow people who have had fears (potentially very justifiable) to take a new look at the cloud, and to start embracing some of the benefits of the cloud (such as letting someone else take care of storage, high availability, and more) without losing the feeling of the data being close. @rob_farley

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  • "The connection has timed out" - Please help!

    - by gon
    I recently installed a fresh Ubuntu 12.04 LTS on a desktop, and the installation itself was successful (other than 'grub rescue' issue that I encountered but fixed) but this connection problem is really giving me a headache. Symptoms: 1. When I open the FireFox browser and try to connect to a website, it just hangs for a while saying "Connecting..." but eventually loads an error page "The connection has timed out". 2. It's not a browser problem (and I tried setting ipv6 thing to "true" at about:config) because running "sudo apt-get install [some-random-package]" at terminal fails ("E: Unable to locate package [package]") too. All other operations that need internet access are not working. 3. I certainly see a wired network (called "eth1") at the Network Manager, and it says "Connection Established" after disconnecting and then connecting again. I have tried almost everything that could be found from google search results still no luck. Their problems slightly differ from mine or the solutions just don't work. By the way it didn't have internet access when installing Ubuntu 12.04. (I ignored the message that I need internet to install Ubuntu) Could this be a problem? I'm sorry I don't remember if internet worked or not on the previous version of Ubuntu. :( I would really appreciate your help... I don't even know what more to do if this fails too.. Thanks!! Thanks for your comment. Here is the result of ifconfig: eth0 Link encap:Ethernet HWaddr 78:ac:c0:3d:b2:b9 inet addr:10.10.65.185 Bcast:10.10.65.255 Mask:255.255.255.0 inet6 addr: fe80::7aac:c0ff:fe3d:b2b9/64 Scope:Link UP BROADCAST RUNNING MULTICAST MTU:1500 Metric:1 RX packets:3907 errors:0 dropped:0 overruns:0 frame:0 TX packets:771 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:1000 RX bytes:393118 (393.1 KB) TX bytes:73472 (73.4 KB) Interrupt:16 eth1 Link encap:Ethernet HWaddr 78:ac:c0:3d:b2:b8 UP BROADCAST MULTICAST MTU:1500 Metric:1 RX packets:0 errors:0 dropped:0 overruns:0 frame:0 TX packets:0 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:1000 RX bytes:0 (0.0 B) TX bytes:0 (0.0 B) Interrupt:17 lo Link encap:Local Loopback inet addr:127.0.0.1 Mask:255.0.0.0 inet6 addr: ::1/128 Scope:Host UP LOOPBACK RUNNING MTU:16436 Metric:1 RX packets:4 errors:0 dropped:0 overruns:0 frame:0 TX packets:4 errors:0 dropped:0 overruns:0 carrier:0 collisions:0 txqueuelen:0 RX bytes:204 (204.0 B) TX bytes:204 (204.0 B) route -n: Kernel IP routing table Destination Gateway Genmask Flags Metric Ref Use Iface 0.0.0.0 10.10.65.1 0.0.0.0 UG 0 0 0 eth0 10.10.65.0 0.0.0.0 255.255.255.0 U 1 0 0 eth0 169.254.0.0 0.0.0.0 255.255.0.0 U 1000 0 0 eth0 /etc/resolv.conf: # Dynamic resolv.conf(5) file for glibc resolver(3) generated by resolvconf(8) # DO NOT EDIT THIS FILE BY HAND -- YOUR CHANGES WILL BE OVERWRITTEN nameserver 8.8.8.8 nameserver 8.8.4.4 nameserver 10.81.1.8 nameserver 10.1.2.10 nameserver 127.0.0.1 search yamatake.local /etc/network/interfaces: auto lo iface lo inet loopback #auto eth0 #iface eth0 inet dhcp #auto eth1 #iface eth1 inet dhcp And I'll also include the result of 'sudo lshw -C network' in case it might help: *-network description: Ethernet interface product: NetXtreme BCM5764M Gigabit Ethernet PCIe vendor: Broadcom Corporation physical id: 0 bus info: pci@0000:02:00.0 logical name: eth0 version: 10 serial: 78:ac:c0:3d:b2:b9 size: 100Mbit/s capacity: 1Gbit/s width: 64 bits clock: 33MHz capabilities: pm vpd msi pciexpress bus_master cap_list ethernet physical tp 10bt 10bt-fd 100bt 100bt-fd 1000bt 1000bt-fd autonegotiation configuration: autonegotiation=on broadcast=yes driver=tg3 driverversion=3.121 duplex=full firmware=5764m-v3.35 ip=10.10.65.185 latency=0 link=yes multicast=yes port=twisted pair speed=100Mbit/s resources: irq:93 memory:fc000000-fc00ffff *-network description: Ethernet interface product: NetXtreme BCM5764M Gigabit Ethernet PCIe vendor: Broadcom Corporation physical id: 0 bus info: pci@0000:01:00.0 logical name: eth1 version: 10 serial: 78:ac:c0:3d:b2:b8 size: 100Mbit/s capacity: 1Gbit/s width: 64 bits clock: 33MHz capabilities: pm vpd msi pciexpress bus_master cap_list ethernet physical tp 10bt 10bt-fd 100bt 100bt-fd 1000bt 1000bt-fd autonegotiation configuration: autonegotiation=on broadcast=yes driver=tg3 driverversion=3.121 duplex=full firmware=5764m-v3.35 latency=0 link=no multicast=yes port=twisted pair speed=100Mbit/s resources: irq:94 memory:fb000000-fb00ffff

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  • Caesar Cipher Program In C++ [migrated]

    - by xaliap81
    I am trying to write a caesar cipher program in c++. This is my codes template: int chooseKEY (){ //choose key shift from 1-26 } void encrypt (char * w, char *e, int key) { //Encryption function, *w is the text in the beginning, the *e is the encrypted text //Encryption in being made only in letters noy in numbers and punctuations // *e = *w + key } void decrypt (char * e, char *w, int key) { // Decryption function, *e is the text in the beginning, the *w is the decrypted text //Dencryption in being made only in letters no numbers and punctuations // *w = *e - key } void Caesar (char * inputFile, char * outputFile, int key, int mode) { // Read the inputfile which contains some data. If mode ==1 then the data is being //encrypted else if mode == 0 the data is being decrypted and is being written in //the output file } void main() { // call the Caesar function } The program has four functions, chooseKey function have to return an int as a shift key from 1-26. Encrypt function has three parameters, *w is the text in the beginning, *e is the encrypted text and the key is from the choosekey function.For encryption : Only letters have to be encrypted not numbers or punctuation and the letters are counting cyclic. Decrypt function has three parameters *e is the encrypted text, *w is the beginning text and the key. Caesar function has four parameters, inputfile which is the file that contains the beginning text, output file which contains the encrypted text, the key and the mode (if mode==1) encryption, (mode ==0) decryption. This is my sample code: #include <iostream> #include <fstream> using namespace std; int chooseKey() { int key_number; cout << "Give a number from 1-26: "; cin >> key_number; while(key_number<1 || key_number>26) { cout << "Your number have to be from 1-26.Retry: "; cin >> key_number; } return key_number; } void encryption(char *w, char *e, int key){ char *ptemp = w; while(*ptemp){ if(isalpha(*ptemp)){ if(*ptemp>='a'&&*ptemp<='z') { *ptemp-='a'; *ptemp+=key; *ptemp%=26; *ptemp+='A'; } } ptemp++; } w=e; } void decryption (char *e, char *w, int key){ char *ptemp = e; while(*ptemp){ if(isalpha(*ptemp)) { if(*ptemp>='A'&&*ptemp<='Z') { *ptemp-='A'; *ptemp+=26-key; *ptemp%=26; *ptemp+='a'; } } ptemp++; } e=w; } void Caesar (char *inputFile, char *outputFile, int key, int mode) { ifstream input; ofstream output; char buf, buf1; input.open(inputFile); output.open(outputFile); buf=input.get(); while(!input.eof()) { if(mode == 1){ encryption(&buf, &buf1, key); }else{ decryption(&buf1, &buf, key); } output << buf; buf=input.get(); } input.close(); output.close(); } int main(){ int key, mode; key = chooseKey(); cout << "1 or 0: "; cin >> mode; Caesar("test.txt","coded.txt",key,mode); system("pause"); } I am trying to run the code and it is being crashed (Debug Assertion Failed). I think the problem is somewhere inside Caesar function.How to call the encrypt and decrypt functions. But i don't know what exactly is. Any ideas?

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  • Using Private Extension Galleries in Visual Studio 2012

    - by Jakob Ehn
    Note: The installer and the complete source code is available over at CodePlex at the following location: http://inmetavsgallery.codeplex.com   Extensions and addins are everywhere in the Visual Studio ALM ecosystem! Microsoft releases new cool features in the form of extensions and the list of 3rd party extensions that plug into Visual Studio just keeps growing. One of the nice things about the VSIX extensions is how they are deployed. Microsoft hosts a public Visual Studio Gallery where you can upload extensions and make them available to the rest of the community. Visual Studio checks for updates to the installed extensions when you start Visual Studio, and installing/updating the extensions is fast since it is only a matter of extracting the files within the VSIX package to the local extension folder. But for custom, enterprise-specific extensions, you don’t want to publish them online to the whole world, but you still want an easy way to distribute them to your developers and partners. This is where Private Extension Galleries come into play. In Visual Studio 2012, it is now possible to add custom extensions galleries that can point to any URL, as long as that URL returns the expected content of course (see below).Registering a new gallery in Visual Studio is easy, but there is very little documentation on how to actually host the gallery. Visual Studio galleries uses Atom Feed XML as the protocol for delivering new and updated versions of the extensions. This MSDN page describes how to create a static XML file that returns the information about your extensions. This approach works, but require manual updates of that file every time you want to deploy an update of the extension. Wouldn’t it be nice with a web service that takes care of this for you, that just lets you drop a new version of your VSIX file and have it automatically detect the new version and produce the correct Atom Feed XML? Well search no more, this is exactly what the Inmeta Visual Studio Gallery Service does for you :-) Here you can see that in addition to the standard Online galleries there is an Inmeta Gallery that contains two extensions (our WIX templates and our custom TFS Checkin Policies). These can be installed/updated i the same way as extensions from the public Visual Studio Gallery. Installing the Service Download the installler (Inmeta.VSGalleryService.Install.msi) for the service and run it. The installation is straight forward, just select web site, application pool and (optional) a virtual directory where you want to install the service.   Note: If you want to run it in the web site root, just leave the application name blank Press Next and finish the installer. Open web.config in a text editor and locate the the <applicationSettings> element Edit the following setting values: FeedTitle This is the name that is shown if you browse to the service using a browser. Not used by Visual Studio BaseURI When Visual Studio downloads the extension, it will be given this URI + the name of the extension that you selected. This value should be on the following format: http://SERVER/[VDIR]/gallery/extension/ VSIXAbsolutePath This is the path where you will deploy your extensions. This can be a local folder or a remote share. You just need to make sure that the application pool identity account has read permissions in this folder Save web.config to finish the installation Open a browser and enter the URL to the service. It should show an empty Feed page:   Adding the Private Gallery in Visual Studio 2012 Now you need to add the gallery in Visual Studio. This is very easy and is done as follows: Go to Tools –> Options and select Environment –> Extensions and Updates Press Add to add a new gallery Enter a descriptive name, and add the URL that points to the web site/virtual directory where you installed the service in the previous step   Press OK to save the settings. Deploying an Extension This one is easy: Just drop the file in the designated folder! :-)  If it is a new version of an existing extension, the developers will be notified in the same way as for extensions from the public Visual Studio gallery: I hope that you will find this sever useful, please contact me if you have questions or suggestions for improvements!

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  • Come up with a real-world problem in which only the best solution will do (a problem from Introduction to algorithms) [closed]

    - by Mike
    EDITED (I realized that the question certainly needs a context) The problem 1.1-5 in the book of Thomas Cormen et al Introduction to algorithms is: "Come up with a real-world problem in which only the best solution will do. Then come up with one in which a solution that is “approximately” the best is good enough." I'm interested in its first statement. And (from my understanding) it is asked to name a real-world problem where only the exact solution will work as opposed to a real-world problem where good-enough solution will be ok. So what is the difference between the exact and good enough solution. Consider some physics problem for example the simulation of the fulid flow in the permeable medium. To make this simulation happen some simplyfing assumptions have to be made when deriving a mathematical model. Otherwise the model becomes at least complex and unsolvable. Virtually any particle in the universe has its influence on the fluid flow. But not all particles are equal. Those that form the permeable medium are much more influental than the ones located light years away. Then when the mathematical model needs to be solved an exact solution can rarely be found unless the mathematical model is simple enough (wich probably means the model isn't close to reality). We take an approximate numerical method and after hours of coding and days of verification come up with the program or algorithm which is a solution. And if the model and an algorithm give results close to a real problem by some degree that is good enough soultion. Its worth noting the difference between exact solution algorithm and exact computation result. When considering real-world problems and real-world computation machines I believe all physical problems solutions where any calculations are taken can not be exact because universal physical constants are represented approximately in the computer. Any numbers are represented with the limited precision, at least limited by amount of memory available to computing machine. I can imagine plenty of problems where good-enough, good to some degree solution will work, like train scheduling, automated trading, satellite orbit calculation, health care expert systems. In that cases exact solutions can't be derived due to constraints on computation time, limitations in computer memory or due to the nature of problems. I googled this question and like what this guy suggests: there're kinds of mathematical problems that need exact solutions (little note here: because the question is taken from the book "Introduction to algorithms" the term "solution" means an algorithm or a program, which in this case gives exact answer on each input). But that's probably more of theoretical interest. So I would like to narrow down the question to: What are the real-world practical problems where only the best (exact) solution algorithm or program will do (but not the good-enough solution)? There are problems like breaking of cryptographic ciphers where only exact solution matters in practice and again in practice the process of deciphering without knowing a secret should take reasonable amount of time. Returning to the original question this is the problem where good-enough (fast-enough) solution will do there's no practical need in instant crack though it's desired. So the quality of "best" can be understood in any sense: exact, fastest, requiring least memory, having minimal possible network traffic etc. And still I want this question to be theoretical if possible. In a sense that there may be example of computer X that has limited resource R of amount Y where the best solution to problem P is the one that takes not more than available Y for inputs of size N*Y. But that's the problem of finding solution for P on computer X which is... well, good enough. My final thought that we live in a world where it is required from programming solutions to practical purposes to be good enough. In rare cases really very very good but still not the best ones. Isn't it? :) If it's not can you provide an example? Or can you name any such unsolved problem of practical interest?

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  • Is this spaghetti code already? [migrated]

    - by hephestos
    I post the following code writen all by hand. Why I have the feeling that it is a western spaghetti on its own. Second, could that be written better? <div id="form-board" class="notice" style="height: 200px; min-height: 109px; width: auto;display: none;"> <script type="text/javascript"> jQuery(document).ready(function(){ $(".form-button-slide").click(function(){ $( "#form-board" ).dialog(); return false; }); }); </script> <?php echo $this->Form->create('mysubmit'); echo $this->Form->input('inputs', array('type' => 'select', 'id' => 'inputs', 'options' => $inputs)); echo $this->Form->input('Fields', array('type' => 'select', 'id' => 'fields', 'empty' => '-- Pick a state first --')); echo $this->Form->input('inputs2', array('type' => 'select', 'id' => 'inputs2', 'options' => $inputs2)); echo $this->Form->input('Fields2', array('type' => 'select', 'id' => 'fields2', 'empty' => '-- Pick a state first --')); echo $this->Form->end("Submit"); ?> </div> <div style="width:100%"></div> <div class="form-button-slide" style="float:left;display:block;"> <?php echo $this->Html->link("Error Results", "#"); ?> </div> <script type="text/javascript"> jQuery(document).ready(function(){ $("#mysubmitIndexForm").submit(function() { // we want to store the values from the form input box, then send via ajax below jQuery.post("Staffs/view", { data1: $("#inputs").attr('value'), data2:$("#inputs2").attr('value'),data3:$("#fields").attr('value'), data4:$("#fields2").attr('value') } ); //Close the dialog $( "#form-board" ).dialog('close') return false; }); $("#inputs").change(function() { // we want to store the values from the form input box, then send via ajax below var input_id = $('#inputs').attr('value'); $.ajax({ type: "POST", //The controller who listens to our request url: "Inputs/getFieldsFromOneInput/"+input_id, data: "input_id="+ input_id, //+"&amp; lname="+ lname, success: function(data){//function on success with returned data $('form#mysubmit').hide(function(){}); data = $.parseJSON(data); var sel = $("#fields"); sel.empty(); for (var i=0; i<data.length; i++) { sel.append('<option value="' + data[i].id + '">' + data[i].name + '</option>'); } } }); return false; }); $("#inputs2").change(function() { // we want to store the values from the form input box, then send via ajax below var input_id = $('#inputs2').attr('value'); $.ajax({ type: "POST", //The controller who listens to our request url: "Inputs/getFieldsFromOneInput/"+input_id, data: "input_id="+ input_id, //+"&amp; lname="+ lname, success: function(data){//function on success with returned data $('form#mysubmit').hide(function(){}); data = $.parseJSON(data); var sel = $("#fields2"); sel.empty(); for (var i=0; i<data.length; i++) { sel.append('<option value="' + data[i].id + '">' + data[i].name + '</option>'); } } }); return false; }); }); </script>

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  • Windows service - COM class factory error 80070583

    - by jawonlee
    I have a Windows service that periodically scrapes some web pages, using mshtml and HtmlAgilityPack. For this particular C# code snippet: HTMLDocumentClass doc = new HTMLDocumentClass(); doc.write(new object[] { responseFromServer }); doc.close(); I get this error: Retrieving the COM class factory for component with CLSID {25336920-03F9-11CF-8FD0-00AA00686F13} failed due to the following error: 80070583. I tracked down the CLSID in the registry, and it turned out to be mshtml.dll. I also noticed that the version I actually have is version 7.0.6000.17023, and the registry version is listed as Version=7.0.3300.0. The error code 80070583 means "Class does not exist"; interestingly, I've also gotten an error from the same program with error code 80070582, or "Class already exists". What does it all mean? Edit: Since there are no answers, I ended up working around the problem, by ditching MSHTML and using HTML Agility Pack to parse HTML. How do I close this question?

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  • Socket.ReceiveAsync problem

    - by bartol
    Hi, I have a problem using SocketAsyncEventArgs model with .net sockets. Everything works great until the moment that the server wishes to close a client connection. I use following code for this: try { socket.Shutdown(SocketShutdown.Both); } catch { } // throws if client process has already closed finally { socket.Close(); } socket = null; Each connection is using two SocketAsyncEventArgs (one for send and one for receive) and after closing the connection they are returned to a pool from which they can be later reused. And here the problem starts, because when another connection is established and receive args are reused from the pool we get an exception: System.InvalidOperationException: "An asynchronous socket operation is already in progress using this SocketAsyncEventArgs instance."; at System.Net.Sockets.SocketAsyncEventArgs.StartOperationCommon(Socket socket) at System.Net.Sockets.Socket.ReceiveAsync(SocketAsyncEventArgs e) I've done some debugging and it appears that the connection closing code from the beginning of the question does not cancel Socket.ReceiveAsync operation that is in progress when the connection is closed. I've tried many combinations of Shutdown, Disconnect and Linger options for the socket but nothing worked. Any suggestions? Thanks

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  • Unable to determine the URL to the Xap file

    - by Matthew Glace
    I started developing a Silverlight (SL) 4 application hosted in an ASP.NET site using Visual Studio 2010. Now I want to change it so that the SL application runs out of browser as if I had not chosen to host it in a web site when I created the SL project. First, I went to the properties of the web application and removed the SL project from the “Silverlight Applications” tab. Then, I went to the properties of the SL project and made sure the “Out-of-browser Application” option was chosen on the “Debug” tab with the SL project selected in the drop list. Finally, I made sure that the SL project was set as the “StartUp” project for the solution. The solution builds successfully however when I try to run I get the following message in an error dialog: Unable to determine the URL to the Xap file from web [web project name]. I'm assuming this is happening because the SL project is trying to copy the Xap file to the ClientBin folder of the web site. Obviously, the SL and web projects are still linked in some way despite my attempt to unlink the two. I have examined each project file in notepad to find any reference between them with no luck. What’s more frustrating is that I can achieve my desired result by creating a new SL application and un-checking the “Host the Silverlight application in a new or existing Web site in the solution” option. I know I could start my project over from scratch to solve this problem however I’m really curious as to what is causing this error. A Google search yielded no results.

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  • Column Header for a WPF TreeView

    - by nareshbhatia
    I am using the WPF TreeView to display some hierarchical information. Each item in the TreeView consists of several attributes, so I am using a Grid within my HierarchicalDataTemplate to display these attributes: <HierarchicalDataTemplate x:Key="ArtistTemplate" ItemsSource="{Binding XPath=Title}" ItemTemplate="{StaticResource TitleTemplate}"> <Grid> <Grid.ColumnDefinitions> <ColumnDefinition SharedSizeGroup="NameColumn" /> <ColumnDefinition SharedSizeGroup="GenreColumn" /> <ColumnDefinition SharedSizeGroup="BornColumn" /> <ColumnDefinition SharedSizeGroup="DiedColumn" /> </Grid.ColumnDefinitions> <TextBlock Grid.Column="0" Text="{Binding XPath=@Name}" /> <TextBlock Grid.Column="1" Text="{Binding XPath=@Genre}" /> <TextBlock Grid.Column="2" Text="{Binding XPath=@Born}" /> <TextBlock Grid.Column="3" Text="{Binding XPath=@Died}" /> </Grid> </HierarchicalDataTemplate> This displays as a nice TreeView with 4 columns - so far so good! The only additional thing I need is a header above the TreeView that displays column names. The header column widths should be synchronized with TreeViewItems and also the header styles should be customizable. What's the easiest way to do this? P.S. I found two solutions that came close: 1) A TreeListView here, but this requires me to implement a custom interface (ITreeModel) to my model. Also the approach in this solution is to start with a ListView and to implement a RowExpander manually. In my case, the TreeView is sufficiently close to what I need, so I am hoping that putting a header on it should be very simple. 2) A TreeListView here. This one indeed starts with a TreeView, but I can't figure out how to customize the header. I suspect that I have to customize the GridViewHeaderRowPresenter in the generic.xaml, but this element does not seem to have its own ControlTemplate.

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  • Detect blocked popup in Chrome

    - by Andrew
    I am aware of javascript techniques to detect whether a popup is blocked in other browsers (as described in the answer to this question). Here's the basic test: var newWin = window.open(url); if(!newWin || newWin.closed || typeof newWin.closed=='undefined') { //POPUP BLOCKED } But this does not work in Chrome. The "POPUP BLOCKED" section is never reached when the popup is blocked. Of course, the test is working to an extent since Chrome doesn't actually block the popup, but opens it in a tiny minimized window at the lower right corner which lists "blocked" popups. What I would like to do is be able to tell if the popup was blocked by Chrome's popup blocker. I try to avoid browser sniffing in favor of feature detection. Is there a way to do this without browser sniffing? Edit: I have now tried making use of newWin.outerHeight, newWin.left, and other similar properties to accomplish this. Google Chrome returns all position and height values as 0 when the popup is blocked. Unfortunately, it also returns the same values even if the popup is actually opened for an unknown amount of time. After some magical period (a couple of seconds in my testing), the location and size information is returned as the correct values. In other words, I'm still no closer to figuring this out. Any help would be appreciated.

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  • Unrecognized Token : "#" C# to SQLITE

    - by user2788405
    Background + Problem: ( Begginer here ) I want to populate sqlite db with values from a list I have in my c# code. Here's the sqlite code taken from finisarsqlite website: I modified it a bit by creating my own column names like "seq#" etc. But I'm getting the following error : "unrecognized token #" Maybe my syntax is off? Code: // [snip] - As C# is purely object-oriented the following lines must be put into a class: // We use these three SQLite objects: SQLiteConnection sqlite_conn; SQLiteCommand sqlite_cmd; SQLiteDataReader sqlite_datareader; // create a new database connection: sqlite_conn = new SQLiteConnection("Data Source=database.db;Version=3;New=True;Compress=True;"); // open the connection: sqlite_conn.Open(); // create a new SQL command: sqlite_cmd = sqlite_conn.CreateCommand(); // Let the SQLiteCommand object know our SQL-Query: sqlite_cmd.CommandText = "CREATE TABLE table1 (Seq# integer primary key, Field integer primary key, Description integer primary key);"; // Now lets execute the SQL ;D sqlite_cmd.ExecuteNonQuery(); <<< ---- This is where Error Occurs ! // Lets insert something into our new table: sqlite_cmd.CommandText = "INSERT INTO table1 (Seq#, Field, Description) VALUES (list[0], list[1], list[2]);"; // And execute this again ;D sqlite_cmd.ExecuteNonQuery(); // We are ready, now lets cleanup and close our connection: sqlite_conn.Close(); }

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  • Java and AppStore receipt verification

    - by user1672461
    I am trying to verify a payment receipt on server side. I am getting a {"status":21002, "exception":"java.lang.IllegalArgumentException"} in return Here is the code: private final static String _sandboxUriStr = "https://sandbox.itunes.apple.com/verifyReceipt"; public static void processPayment(final String receipt) throws SystemException { final BASE64Encoder encoder = new BASE64Encoder(); final String receiptData = encoder.encode(receipt.getBytes()); final String jsonData = "{\"receipt-data\" : \"" + receiptData + "\"}"; System.out.println(receipt); System.out.println(jsonData); try { final URL url = new URL(_productionUriStr); final HttpURLConnection conn = (HttpsURLConnection) url.openConnection(); conn.setRequestMethod("POST"); conn.setDoOutput(true); final OutputStreamWriter wr = new OutputStreamWriter(conn.getOutputStream()); wr.write(jsonData); wr.flush(); // Get the response final BufferedReader rd = new BufferedReader(new InputStreamReader(conn.getInputStream())); String line; while ((line = rd.readLine()) != null) { System.out.println(line); } wr.close(); rd.close(); } catch (IOException e) { throw new SystemException("Error when trying to send request to '%s', %s", _sandboxUriStr, e.getMessage()); } } My receipt looks like this: {\n\t"signature" = "[exactly_1320_characters]";\n\t"purchase-info" = "[exactly_868_characters]";\n\t"environment" = "Sandbox";\n\t"pod" = "100";\n\t"signing-status" = "0";\n} Receipt data with a BASE64 encoded receipt looks like this: Blockquote {"receipt-data" : "[Block_of_chars_76x40+44=3084_chars_total]"} Does someone have an Idea, or sample code how can I get from receipt string to reply JSON, mentioned here: [http://developer.apple.com/library/ios/#documentation/NetworkingInternet/Conceptual/StoreKitGuide/VerifyingStoreReceipts/VerifyingStoreReceipts.html#//apple_ref/doc/uid/TP40008267-CH104-SW1]? Thank you

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  • CA2000 and disposal of WCF client

    - by Mayo
    There is plenty of information out there concerning WCF clients and the fact that you cannot simply rely on a using statement to dispose of the client. This is because the Close method can throw an exception (i.e. if the server hosting the service doesn't respond). I've done my best to implement something that adheres to the numerous suggestions out there. public void DoSomething() { MyServiceClient client = new MyServiceClient(); // from service reference try { client.DoSomething(); } finally { client.CloseProxy(); } } public static void CloseProxy(this ICommunicationObject proxy) { if (proxy == null) return; try { if (proxy.State != CommunicationState.Closed && proxy.State != CommunicationState.Faulted) { proxy.Close(); } else { proxy.Abort(); } } catch (CommunicationException) { proxy.Abort(); } catch (TimeoutException) { proxy.Abort(); } catch { proxy.Abort(); throw; } } This appears to be working as intended. However, when I run Code Analysis in Visual Studio 2010 I still get a CA2000 warning. CA2000 : Microsoft.Reliability : In method 'DoSomething()', call System.IDisposable.Dispose on object 'client' before all references to it are out of scope. Is there something I can do to my code to get rid of the warning or should I use SuppressMessage to hide this warning once I am comfortable that I am doing everything possible to be sure the client is disposed of? Related resources that I've found: http://www.theroks.com/2011/03/04/wcf-dispose-problem-with-using-statement/ http://www.codeproject.com/Articles/151755/Correct-WCF-Client-Proxy-Closing.aspx http://codeguru.earthweb.com/csharp/.net/net_general/tipstricks/article.php/c15941/

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  • jquery Ui Dialog box opacity / alpha filter broken in IE7/8 when using jquery.effects.fade.js

    - by Ideasman101
    Greetings! Goal: transparant ui dialog box in IE7/8 with fade in/out effect upon open/close. Opacity was set in css and works just fine (safari, chrome, ff ie7/8) using native effects blind / explode etc. But when using efects.fade.js on the dialog box the opacity does not work on ie7/8 We want fade in/out because that looks awesome. Anyway here is my code. Any help much appreciated. Maybe something to do with filter or cleartype. My css .ui-dialog { position: absolute; padding: .2em; width: 300px; overflow: hidden; opacity:0.85;filter:alpha(opacity=85);} My jQuery // Dialog1 $('#dialog1').dialog({ position: [250,120], autoOpen: false, closeOnEscape: true, modal: false, show: { effect: "fade", options: {}, speed: 1500 }, hide: { effect: "fade", options: {}, speed: 1500 }, resizable: false, width: 350, height: 200 }); // Dialog Link 1 $('#dialog_link1').click(function(){ $([1,2,3]).each(function(){ var num = this; $('#dialog'+num).dialog('close'); }); $('#dialog1').dialog('open'); $('body').css("background-image", "url(images/image1.jpg)"); $('body').css("background-repeat", "no-repeat"); $('body').css("background-position", "bottom center"); $('body').css("background-attachment", "fixed"); $('body').css("bottom", "0px"); return false; });

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  • How To Avoid a Perl script calling an Another Perl Script

    - by rockyurock
    Hello, i am calling a perl script client.pl from a main script to capture the output of client.pl in @output. is there anyway to avoid the use of these two files so i can use the output of client.pl in main.pl itself here is my code.... main.pl ======= my @output = readpipe("client.pl"); client.pl ========= #! /usr/bin/perl -w #use strict; use Socket; #initialize host and port my $host = shift || $FTP_SERVER; my $port = shift || $CLIENT_PORT; my $proto = getprotobyname('tcp'); #get the port address my $iaddr = inet_aton($host); my $paddr = sockaddr_in($port, $iaddr); #create the socket, connect to the port socket(SOCKET, PF_INET, SOCK_STREAM, $proto)or die "socket: $!\n"; connect(SOCKET, $paddr) or die "connect: $!\n"; my $line; while ($line = ) { print "$line\n"; } close SOCKET or die "close: $!"; /rocky..

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  • PayPal IPN Response

    - by Gorkem Tolan
    I am having a problem with PayPal IPN response. After payment is made by the customer, PayPal IPN returns this URL: www.mywebsite.com?orderid=32&tx=2AC67201DL3533325&st=Pending&amt=2.50&cc=USD&cm=&item_number=32 There are a couple of issues Post-back field names are undefined or missing. Thus I can get the INVALID message. I am not sure if my website does not read POST variables. When I looked at IPN history, it shows that each IPN has been sent with the complete url. Payment status keeps coming Pending. Does this issue cause the first issue? Thank you for your responses in advance. Here is the code: Dim strSandbox As String, strLive As String Dim req As HttpWebRequest strSandbox = "http://www.sandbox.paypal.com/cgi-bin/webscr/" strLive = "https://www.paypal.com/cgi-bin/webscr" req = CType(WebRequest.Create(strSandbox), HttpWebRequest) 'Set values for the request back req.Method = "POST" req.ContentType = "application/x-www-form-urlencoded" Dim param() As Byte param = Request.BinaryRead(HttpContext.Current.Request.ContentLength) Dim strRequest As String strRequest = Encoding.ASCII.GetString(param) strRequest = strRequest & "&cmd=_notify-validate" req.ContentLength = strRequest.Length 'Response.Write(strRequest) 'Send the request to PayPal and get the response Dim streamOut As StreamWriter streamOut = New StreamWriter(req.GetRequestStream(), System.Text.Encoding.ASCII) streamOut.Write(strRequest) streamOut.Close() Dim streamIn As StreamReader streamIn = New StreamReader(req.GetResponse().GetResponseStream()) Dim strResponse As String strResponse = streamIn.ReadToEnd() Response.Write(strResponse) streamIn.Close() If (strResponse = "VERIFIED") Then Response.Redirect("thankyou.aspx") ElseIf (strResponse = "INVALID") Then End If

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  • how to send image to remote server using webservices in android only save to byte array retrieve ima

    - by narasimha
    hi sir i am implemented this code public class ImageTest extends Activity { /** Called when the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); ImageView image = (ImageView) findViewById(R.id.picview); EditText value=(EditText)findViewById(R.id.EditText01); FileInputStream in; BufferedInputStream buf; try { in = new FileInputStream("/sdcard/pictures/1.jpg"); buf = new BufferedInputStream(in,1070); System.out.println("1.................."+buf); byte[] bMapArray= new byte[buf.available()]; buf.read(bMapArray); System.out.println("2................."+buf.read(bMapArray)); Bitmap bMap = BitmapFactory.decodeByteArray(bMapArray, 0, bMapArray.length); for (int i = 0; i < bMapArray.length; i++) { System.out.print(bMapArray[i]); } System.out.println("3......................"+bMap); System.out.println("4........bitmaparray"+bMap.extractAlpha()); System.out.println("5......................"+bMapArray); System.out.println("6......................"+ bMapArray.length); image.setImageBitmap(bMap); value.setText(bMapArray.length); if (in != null) { in.close(); } if (buf != null) { buf.close(); } } catch (Exception e) { Log.e("Error reading file", e.toString()); } } } 04-14 11:46:16.543: INFO/System.out(736): 2.................-1 3......................android.graphics.Bitmap@435a2d98 4........bitmaparrayandroid.graphics.Bitmap@435a3310 5......................[B@435a2758 6......................1035

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  • send sms from background thread in blackberry using j2me

    - by SWATI
    hey i made a lot of search and found some similar types of code. I tried for gsm method 1 gives IllegalArgumentException try { MessageConnection _mc = (MessageConnection)Connector.open("sms://"); TextMessage tm = (TextMessage) _mc.newMessage(MessageConnection.TEXT_MESSAGE); tm.setPayloadText(smsText); tm.setAddress("965xxxxxxx"); _mc.send(tm); _mc.close(); }catch(exception e){} method 2: gives java.lang.error exception try { MessageConnection _mc = (MessageConnection)Connector.open("sms://"); TextMessage tm = (TextMessage) _mc.newMessage(MessageConnection.TEXT_MESSAGE, "//9790XXXXXX"); tm.setPayloadText(text); _mc.send(tm); _mc.close(); }catch(Exception e){} I think the problem is with address i also tried : but no success +91965xxxxxxx , 0091965xxxxxxx , 0965xxxxxxx How my application works---- i have created 2 applications-- 1) Application 1 is a background app that is a System module as well as startup application. 2) Another is a uiapplication the background app runs in background.If there comes an incoming call then a flag value is set in persistent object and after checking that value as true the sms is send to that no from whom call is made.

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  • Why is XmlSerializer throwing an InvalidOperationException?

    - by qster
    public void Save() { XmlSerializer Serializer = new XmlSerializer(typeof(DatabaseInformation)); /* A first chance exception of type 'System.IO.FileNotFoundException' occurred in mscorlib.dll A first chance exception of type 'System.IO.FileNotFoundException' occurred in mscorlib.dll A first chance exception of type 'System.InvalidOperationException' occurred in System.Xml.dll */ // .... } This is the whole class if you need it: public class DatabaseInformation { /* Create new database */ public DatabaseInformation(string name) { mName = name; NeedsSaving = true; mFieldsInfo = new List<DatabaseField>(); } /* Read from file */ public static DatabaseInformation DeserializeFromFile(string xml_file_path) { XmlSerializer Serializer = new XmlSerializer(typeof(DatabaseInformation)); TextReader r = new StreamReader(xml_file_path); DatabaseInformation ret = (DatabaseInformation)Serializer.Deserialize(r); r.Close(); ret.NeedsSaving = false; return ret; } /* Save */ public void Save() { XmlSerializer Serializer = new XmlSerializer(typeof(DatabaseInformation)); if (!mNeedsSaving) return; TextWriter w = new StreamWriter(Path.Combine(Program.MainView.CommonDirectory.Get(), Name + ".xml"), false); Serializer.Serialize(w, this); w.Close(); NeedsSaving = false; } private string mName; public string Name { get { return mName; } } private bool mNeedsSaving; public bool NeedsSaving { get { return mNeedsSaving; } set { mNeedsSaving = value; Program.MainView.UpdateTitle(value); } } private bool mHasId; public bool HasId { get { return mHasId; } } List<DatabaseField> mFieldsInfo; }

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  • Cannot debug views in MVC2 project, getting "The resource cannot be found" error

    - by schefdev
    I'm running Visual Studio 2008 sp1 on Win7, with MVC2 RTM installed. I created a new MVC2 project using the wizard and am unable to debug specific pages. With webforms and even MVC1, I was able to sit on a View page, hit F5, and then have the integrated web server in VS2008 start on the page I was working on. Very handy for building up app logic. When I try this now I get a "The resource cannot be found" error page. I retried this just now with a stock new MVC2 Web Application project. Here are the steps I took after creating the new project to reproduce: Open up project settings. Under the Web subtab, set the Start Action to "Current Page". Leave all the other settings as is. Open one of the views up (e.g. Account/Register.aspx) Hit F5 to debug the project Note that the browser window which displays shows the error message "The resource cannot be found". The link I saw in my browser for this run was: http://localhost:49471/Views/Account/Register.aspx I did some googling and found suggestions related to ensuring all HTTP server pieces were installed. I double checked and made sure that "HTTP Errors" and "HTTP Redirection" were both installed. If I leave the project setting as it was originally, set to "Specific Page" with nothing in the text box, then routing works and I always get the default home page. I'm hoping this isn't the only option. Thanks!

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  • Create non-persistent cookie with FormsAuthenticationTicket

    - by Marcus
    Hello! I'm having trouble creating a non-persistent cookie using the FormsAuthenticationTicket. I want to store userdata in the ticket, so i can't use FormsAuthentication.SetAuthCookie() or FormsAuthentication.GetAuthCookie() methods. Because of this I need to create the FormsAuthenticationTicket and store it in a HttpCookie. My code looks like this: DateTime expiration = DateTime.Now.AddDays(7); // Create ticket FormsAuthenticationTicket ticket = new FormsAuthenticationTicket(2, user.Email, DateTime.Now, expiration, isPersistent, userData, FormsAuthentication.FormsCookiePath); // Create cookie HttpCookie cookie = new HttpCookie(FormsAuthentication.FormsCookieName, FormsAuthentication.Encrypt(ticket)); cookie.Path = FormsAuthentication.FormsCookiePath; if (isPersistent) cookie.Expires = expiration; // Add cookie to response HttpContext.Current.Response.Cookies.Add(cookie); When the variable isPersistent is true everything works fine and the cookie is persisted. But when isPersistent is false the cookie seems to be persisted anyway. I sign on in a browser window, closes it and opens the browser again and I am still logged in. How do i set the cookie to be non-persistent? Is a non-persistent cookie the same as a session cookie? Is the cookie information stored in the sessiondata on the server or are the cookie transferred in every request/response to the server? Thanks in advance! /Marcus

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  • jQuery UI Dialog pass on variables

    - by Dante
    Hi, I'm creating a Web interface for a table in Mysql and want to use jQuery dialog for input and edit. I have the following code to start from: $("#content_new").dialog({ autoOpen: false, height: 350, width: 300, modal: true, buttons: { 'Create an account': function() { alert('add this product'); }, Cancel: function() { $(this).dialog('close'); $.validationEngine.closePrompt(".formError",true); } }, closeText: "Sluiten", title: "Voeg een nieuw product toe", open: function(ev, ui) { /* get the id and fill in the boxes */ }, close: function(ev, ui) { $.validationEngine.closePrompt(".formError",true); } }); $("#newproduct").click(function(){ $("#content_new").dialog('open'); }); $(".editproduct").click(function(){ var test = this.id; alert("id = " + test); }); So when a link with the class 'editproduct' is clicked it gets the id from that product and I want it to get to the open function of my dialog. Am I on the right track and can someone help me getting that variable there. Thanks in advance.

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