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  • Linq to SQL case sensitivity causing problems

    - by Roger Lipscombe
    I've seen this question, but that's asking for case-insensitive comparisons when the database is case-sensitive. I'm having a problem with the exact opposite. I'm using SQL Server 2005, my database collation is set to Latin1_General_CI_AS. I've got a table, "User", like this: CREATE TABLE [dbo].[User] ( [Id] [int] IDENTITY(1,1) NOT NULL, [Name] [nvarchar](max) NOT NULL, CONSTRAINT [PK_Example] PRIMARY KEY CLUSTERED ( [Id] ASC ) ) And I'm using the following code to populate it: string[] names = new[] { "Bob", "bob", "BoB" }; using (MyDataContext dataContext = new AppCompatDataContext()) { foreach (var name in names) { string s = name; if (dataContext.Users.SingleOrDefault(u => u.Name == s) == null) dataContext.Users.InsertOnSubmit(new User { Name = name }); } dataContext.SubmitChanges(); } When I run this the first time, I end up with "Bob", "bob" and "BoB" in the table. When I run it again, I get an InvalidOperationException: "Sequence contains more than one element", because the query against the database returns all 3 rows, and... SELECT * FROM [User] WHERE Name = 'bob' ... is case-insensitive. That is: when I'm inserting rows, Linq to SQL appears to use C# case-sensitive comparisons. When I query later, Linq to SQL uses SQL Server case-insensitive comparisons. I'd like the initial insert to use case-insensitive comparisons, but when I change the code as follows... if (dataContext.Users.SingleOrDefault(u => u.Name.Equals(s, StringComparison.InvariantCultureIgnoreCase) ) == null) ... I get a NotSupportedException: "Method 'Boolean Equals(System.String, System.StringComparison)' has no supported translation to SQL." Question: how do I get the initial insert to be case-insensitive or, more precisely, match the collation of the column in the database? Update: This doesn't appear to be my problem. My problem appears to be that SingleOrDefault doesn't actually look at the pending inserts at all.

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  • Avatar (spoiler alert!)

    - by Dave Yasko
    This past weekend we finally saw “Avatar,” or as I like to call it “Dances with Smurfs.”  It was rather light on the story, heavy on the message, and incredibly well done.  The eye for detail is what blew me away, especially the visual distortion (presumably due to density) when the two atmospheres mixed.  The only thing I thought they might have missed was why so many (presumably) mammals had 6 appendages (4 arms + 2 legs) and breathed through passages near their clavicles, but the Na’vi (sp?) didn’t have/do either.  Also, James Cameron just loves to telegraph upcoming events: Riding the big red bird thing has only happened 5 times before – Sully is on the job.  The tree is going to download dying Ripley to her avatar body – Sully is going to do that too.  I’ve seen worse foreshadowing, but not in a long time. I give it 4 Papa Smurfs out of 5.

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  • DirectX 9.0c and C++ GUI

    - by SullY
    Well, I'm trying to code a gui for my engine, but I've got some problems. I know how to make a UI overlay but buttons are still black magic for me. Anything I tried was to compilcated ( if it goes big ). To Example I tried to look if the mouse position is the same as the Pixel that is showing the button. But If I use some bigger areas it's getting to complicated. Now I'm searching for a Tutorial how to implement your own gui. I'm really confused about it. Well I hope you have/ know some good tutorials. By the way, I took a look at the DXUTSample, but it's to big to get overview.

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  • Player Movement DirectX

    - by SullY
    I'm reading on a Book that's about Gamedevelopment with C++ and DirectX 9. There is something that interrests me: It says that playermovements are increasing with the power of the CPU. Becouse a faster CPU will move the player with every frame ( better CPU = better FPS ) To bypass it, it says you have just to multiplicate time*movementfactor . I'd like to know is there an another way to bypass it ?

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  • Does Windows 8 still support DirectX 9?

    - by SullY
    Is Windows 8 supporting DirectX 9? Because I was looking through some samples written in C++ and DirectX 9 made for Windows 8. It wasn't that, like I know it ( look here http://directxtutorial.com/Lesson.aspx?lessonid=111-4-2 ). E.g. Inizialising DirectX with COM: ComPtr<ID3D11Device1> dev; ComPtr<ID3D11DeviceContext1> devcon; It's just weird because I know it with the old way: ID3D11Device *dev; ID3D11DeviceContext *devcon; ( I hope you understand what I want to tell ) I hope it hasn't change completely due the released their new OS.

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  • Confusing Callbacks

    - by SullY
    I'm trying to programm now a "game", and started with the EmptyProject that's provided by the DirectX SDK. The problem is that the Callbacks are confusing me. Can please someone explain me? Edit: DXUTSetCallbackD3D9DeviceAcceptable( IsD3D9DeviceAcceptable ); // not sure but I think that's the caps? DXUTSetCallbackD3D9DeviceLost( OnD3D9LostDevice ); DXUTSetCallbackDeviceChanging( ModifyDeviceSettings ); DXUTSetCallbackFrameMove( OnFrameMove );

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  • Distribution upgrade (12.04 -> 14.04 LTS) halted while unpacking/installing packages

    - by Bob Sully
    As the title states...it just stopped unpacking/installing. "Preparing to unpack .../lirc_0.9.0-0ubuntu5_amd64.deb ..." then stopped in its tracks. Everything else is still running. The update manager process is still alive; if I hit ctrl-c, it gives me the warning message about leaving the system in a broken state. Also, if I run top, there is a process called "trusty" which is still running. I have NOT killed either process. lsb_release -a gives: LSB Version: core-2.0-amd64:core-2.0-noarch:core-3.0-amd64:core-3.0-noarch:core-3.1-amd64:core-3.1-noarch:core-3.2-amd64:core-3.2-noarch:core-4.0-amd64:core-4.0-noarch Distributor ID: Ubuntu Description: Ubuntu 14.04.1 LTS Release: 14.04 Codename: trusty I assume that if I try to restart update-manager, I won't be offered the option to upgrade again. Anyone have a way I can get the update-manager/dist-upgrade process to simply finish the upgrade? Thanks!

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  • Is it possible for double-escaping to cause harm to the DB?

    - by waiwai933
    If I accidentally double escape a string, can the DB be harmed? For the purposes of this question, let's say I'm not using parametrized queries For example, let's say I get the following input: bob's bike And I escape that: bob\'s bike But my code is horrible, and escapes it again: bob\\\'s bike Now, if I insert that into a DB, the value in the DB will be bob\'s bike Which, while is not what I want, won't harm the DB. Is it possible for any input that's double escaped to do something malicious to the DB assuming that I take all other necessary security precautions?

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  • Thin and Bundler on Windows Rails

    - by Bob
    Trying to get Thin working with Bundle on Windows, I know, major PITA but anyways, I'm new to Thin and Bundle gem, I'm on Ruby 1.8.6 and Rails 2.3.5 and trying to get someone else's app running on my laptop, the app uses Thin and Bundle gem to install gems required. I noticed that bundle created a .bundle folder under My Documents folder and put all the gems there for the app. When I tried "thin run", it reported 'thin' is not recognized as an internal or external command, operable program or batch file. I check the environment path and it doesn't point to the .bundle folder at all and I found there is a thin.bat in C:\Documents and Settings\Bob\.bundle\ruby\1.8\bin When I tried "C:\Documents and Settings\Bob.bundle\ruby\1.8\bin\thin" start, it gave me another error c:/ruby/lib/ruby/site_ruby/1.8/rubygems.rb:777:in `report_activate_error': Could not find RubyGem thin (>= 0) (Gem::LoadError) from c:/ruby/lib/ruby/site_ruby/1.8/rubygems.rb:211:in `activate' from c:/ruby/lib/ruby/site_ruby/1.8/rubygems.rb:1056:in `gem' from C:/Documents and Settings/Bob/.bundle/ruby/1.8/bin/thin:18 I get the same error if I added "C:\Documents and Settings\Bob.bundle \ruby\1.8\bin" to the env path. Anyone know I can get this working?

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  • ArchBeat Link-o-Rama for 2012-09-27

    - by Bob Rhubart
    Understanding Oracle BI 11g Security vs Legacy Oracle BI 10g | Christian Screen "After conducting a large amount of Oracle BI 10g to Oracle BI 11g upgrades and after writing the Oracle BI 11g book," says Oracle ACE Christian Screen, "I still continually get asked one of the most basic questions regarding security in Oracle BI 11g; How does it compare to Oracle BI 10g? The trail of questions typically goes on to what are the differences? And, how do we leverage our current Oracle BI 10g security table schema in Oracle BI 11g?" Process Oracle OER Events using a simple Web Service | Bob Webster Bob Webster's post "provides an example of a simple web service that processes Oracle Enterprise Repository (OER) Events. The service receives events from OER and utilizes the OER REX API to implement simple OER automations for selected event types." Oracle Fusion Middleware Security: Attaching OWSM policies to JRF-based web services clients | Andre Correa "OWSM (Oracle Web Services Manager) is Oracle's recommended method for securing SOAP web services," says Oracle Fusion Middleware A-Team member Andre Correa. "It provides agents that encapsulate the necessary logic to interact with the underlying software stack on both service and client sides. Such agents have their behavior driven by policies. OWSM ships with a bunch of policies that are adequate to most common real world scenarios." His detailed post shows how to make it happen. WebCenter Content (WCC) Trace Sections | ECM Architect ECM Architect Kevin Smith shares a detailed technical post covering WebCenter Content (WCC) Trace sections. Thought for the Day "A complex system that works is invariably found to have evolved from a simple system that worked." — John Gall Source: SoftwareQuotes.com

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  • How to set permissions so two users can work on the same hg repository?

    - by John Mee
    Ubuntu: Jaunty Mercurial: 1.3.1 Access: ssh (users john and bob) File permission: -rw-rw---- 1 john john 129276 May 17 13:28 dirstate User: bob Command: 'hg st' Response: **abort: Permission denied: /our/respository/.hg/dirstate** Obviously mercurial can't let bob see the state because the file it needs to read belongs to me. So I change the permissions to allow bob to read the file and everything is fine, up until I next try to do something, whence the situations are reversed. Now he owns the file and I can't read it. So I set up a "committers" group and both john and bob belong to the group, but still mercurial fiddles with the ownership and permissions whenever one or other commits. How do we configure it so two different logins in the same group can commit to the same repository over ssh?

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  • How to deal with arrays of data in cookies

    - by peter
    Hi all, I want to store data in a cookie and I am not exactly sure how I will go about it. The data is the UserName, and Password values for the users that are logging into a website, e.g. sometime like this UserName = bob, Password=Passw0rd1 UserName = harry, Password=BLANK UserName = george, Password=R0jjd6s What this means is that bob and george logged into the site and chose to have their password remembered, but harry chose for his password not to be remembered. So on the login dialog a dropdown will be present with all the usernames in it 'bob', 'harry', 'george'. If they select the username bob the password will automatically be filled in, etc. So how does that information need to be stored in the cookie? Like it is above, or does it have to be, UserName1 = bob, Password1=Passw0rd1 UserName2 = harry, Password2=BLANK UserName3 = george, Password3=R0jjd6s Are the username and password values actually stored in the same cookie, or is each piece of data separate? Any information would be good.

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  • Convert Normalize table to Unormalize table

    - by M R Jafari
    I have tow tables, Table A has 3 columns as StudentID, Name, Course, ClassID and Table B has many columns as StudentID, Name, Other1, Other2, Other3 ... I want convert Table A to Table B. Please help me! Table A StudentID Name Course ClassID 85001 David Data Base 11 85001 David Data Structure 22 85002 Bob Math 33 85002 Bob Data Base 44 85002 Bob Data Structure 55 85002 Bob C# 66 85003 Sara C# 77 85003 Sara Data Base 88 85004 Mary Math 99 85005 Mary Math 100 … Table B SdentdID Name Other 1 Other 2 Other 3 Other 4 … 85001 David DBase,11 DS,22 85002 Bob Math,33 DB,44 DS,55 C#,66 85003 Sara C#,77 DBase,88 85004 Mary Math,99

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  • mysql true row merge... not just a union

    - by panofish
    What is the mysql I need to achieve the result below given these 2 tables: table1: +----+-------+ | id | name | +----+-------+ | 1 | alan | | 2 | bob | | 3 | dave | +----+-------+ table2: +----+---------+ | id | state | +----+---------+ | 2 | MI | | 3 | WV | | 4 | FL | +----+---------+ I want to create a temporary view that looks like this desired result: +----+---------+---------+ | id | name | state | +----+---------+---------+ | 1 | alan | | | 2 | bob | MI | | 3 | dave | WV | | 4 | | FL | +----+---------+---------+ I tried a mysql union but the following result is not what I want. create view table3 as (select id,name,"" as state from table1) union (select id,"" as name,state from table2) table3 union result: +----+---------+---------+ | id | name | state | +----+---------+---------+ | 1 | alan | | | 2 | bob | | | 3 | dave | | | 2 | | MI | | 3 | | WV | | 4 | | FL | +----+---------+---------+ First suggestion results: SELECT * FROM table1 LEFT OUTER JOIN table2 USING (id) UNION SELECT * FROM table1 RIGHT OUTER JOIN table2 USING (id) +----+---------+---------+ | id | name | state | +----+---------+---------+ | 1 | alan | | | 2 | bob | MI | | 3 | dave | WV | | 2 | MI | bob | | 3 | WV | dave | | 4 | FL | | +----+---------+---------+

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  • Rails How to get all the grandchildren of an ojbect.

    - by adam
    I have 3 models User has_many :quetions has_many :corrections end Question has_one :correction belongs_to :user end Correction belongs_to :user belongs_to :question So if user Bob asks a question then user Terry can check it and if its wrong offer a correction. Lets stay with bob and assume he as kindly corrected 5 other users, i.e and lets assume he has been lucky to get 3 corrections from other users. I want to be able to do something like this @bob.corrections_offered = 5 correction objects @bob.corrections_received = 3 correction objects the first one is easy as its really just @bob.corrections under the hood. But i dont know how to implement the latter one. Can anyone help?

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  • Using the public ssh key from local machine to access two remote users [closed]

    - by Nick
    I have an new Ubuntu (Hardy 8.04) server; it has two users, Alice and Bob. Alice is listed in sudoers. I appended my public ssh key (my local machine's public key local/Users/nick/.ssh/id_rsa.pub) to authorized_keys in remote_server/home/Alice/.ssh/authorized_keys, changed the permissions on Alice/.ssh/ to 700 and Alice/.ssh/authorized_keys to 600, and both the file and folder are owned my Alice. Then added I Alice to sshd_config (AllowUsers Alice). This works and I can login into Alice: ssh -v [email protected] ... debug1: Offering public key: /Users/nick/.ssh/id_rsa debug1: Server accepts key: pkalg ssh-rsa blen 277 debug1: Authentication succeeded (publickey). debug1: channel 0: new [client-session] debug1: Entering interactive session. Last login: Mon Mar 15 09:51:01 2010 from 123.456.789.00 I then copied the authorized_keys file remote_server/home/Alice/.ssh/authorized_keys to remote_server/home/Bob/.shh/authorized_keys and changed the permissions and ownership and added Bob to AllowUsers in sshd_config (AllowUsers Alice Bob). Now when I try to login to Bob it will not authenticate the same public key. ssh -v [email protected] ... debug1: Offering public key: /Users/nick/.ssh/id_rsa debug1: Authentications that can continue: publickey debug1: Trying private key: /Users/nick/.ssh/identity debug1: Trying private key: /Users/nick/.ssh/id_dsa debug1: No more authentication methods to try. Permission denied (publickey). Am I missing something fundamental about the way ssh works?

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  • Objective-C classes, pointers to primitive types, etc.

    - by Toby Wilson
    I'll cut a really long story short and give an example of my problem. Given a class that has a pointer to a primitive type as a property: @interface ClassOne : NSObject { int* aNumber } @property int* aNumber; The class is instantiated, and aNumber is allocated and assigned a value, accordingly: ClassOne* bob = [[ClassOne alloc] init]; bob.aNumber = malloc(sizeof(int)); *bob.aNumber = 5; It is then passed, by reference, to assign the aNumber value of a seperate instance of this type of class, accordingly: ClassOne* fred = [[ClassOne alloc] init]; fred.aNumber = bob.aNumber; Fred's aNumber pointer is then freed, reallocated, and assigned a new value, for example 7. Now, the problem I'm having; Since Fred has been assigned the same pointer that Bob had, I would expect that Bob's aNumber will now have a value of 7. It doesn't, because for some reason it's pointer was freed, but not reassigned (it is still pointing to the same address it was first allocated which is now freed). Fred's pointer, however, has the allocated value 7 in a different memory location. Why is it behaving like this? What am I minsunderstanding? How can I make it work like C++ does?

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  • Beginner python - stuck in a loop

    - by Jeremy
    I have two begininer programs, both using the 'while' function, one works correctly, and the other gets me stuck in a loop. The first program is this; num=54 bob = True print('The guess a number Game!') while bob == True: guess = int(input('What is your guess? ')) if guess==num: print('wow! You\'re awesome!') print('but don\'t worry, you still suck') bob = False elif guess>num: print('try a lower number') else: print('close, but too low') print('game over')`` and it gives the predictable output of; The guess a number Game! What is your guess? 12 close, but too low What is your guess? 56 try a lower number What is your guess? 54 wow! You're awesome! but don't worry, you still suck game over However, I also have this program, which doesn't work; #define vars a = int(input('Please insert a number: ')) b = int(input('Please insert a second number: ')) #try a function def func_tim(a,b): bob = True while bob == True: if a == b: print('nice and equal') bob = False elif b > a: print('b is picking on a!') else: print('a is picking on b!') #call a function func_tim(a,b) Which outputs; Please insert a number: 12 Please insert a second number: 14 b is picking on a! b is picking on a! b is picking on a! ...(repeat in a loop).... Can someone please let me know why these programs are different? Thank you!

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  • Altruistic network connection bandwidth estimation

    - by datenwolf
    Assume two peers Alice and Bob connected over a IP network. Alice and Bob are exchanging packets of lossy compressed data which are generated and to be consumes in real time (think a VoIP or video chat application). The service is designed to cope with as little bandwidth available, but relies on low latencies. Alice and Bob would mark their connection with an apropriate QoS profile. Alice and Bob want use a variable bitrate compression and would like to consume all of the leftover bandwidth available for the connection between them, but would voluntarily reduce the consumed bitrate depending on the state of the network. However they'd like to retain a stable link, i.e. avoid interruptions in their decoded data stream caused by congestion and the delay until the bandwidth got adjusted. However it is perfectly possible for them to loose a few packets. TL;DR: Alice and Bob want to implement a VoIP protocol from scratch, and are curious about bandwidth and congestion control. What papers and resources do you suggest for Alice and Bob to read? Mainly in the area of bandwidth estimation and congestion control.

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  • Installing ubuntuone

    - by bob
    Linux Mint 14 os I have tried to install ubuntu one onto the linux mint 14 through Synaptic package manager and software manager, both say its installed but when I go to find the programme its not there. installed as what Synaptic says........... ubuntuone client, ubuntuone client data, ubuntuone client gnome, ubuntuone control panel, what else is missing from this list please, it used to be so so easy to install but now, eeeek yours in advance Bob

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  • Ubuntu 10.10 not recognizing external hard drive

    - by sr71
    Installed Ubuntu 10.10 on a hard drive by itself (no windows). All updates are up to date. Everything`works fine except when I plug in a 320 gig Toshiba external hard drive....it is not recognized. When I plug in an 8 gig flash drive it is recognized no problem. What do I mean by "not recognized"? I mean: how do you know it was not recognized. You can check the command "cat /proc/partitions" in a terminal with and without the hdd attached. If you see some difference, it's ok. If the difference is something like "sda1" (sd+letter+number) then you have partition on it, maybe it can't be handled in Ubuntu (no filesystem on it or so). If there is only "sda" in the difference for example (sd+letter, but no number after it) then the drive itself is detected, just no partition is created on it. Also you can check out the messages of the kernel, with the "dmesg" command in the terminal. If there is no disk/partition/anything in /proc/partitions, there can be an USB level problem, you can issue command "lsusb" as it was suggested before my answer. It's really matter of what do you mean about "not recognized". @Marco Ceppi @Oli @Pitto By "not recognized" I meant that when I plug in a 8 gig flash drive an icon immediately appears on the desktop imdicating that there is a flash drive plugged in and I can click on it and view the files on the flash drive. It also shows up on the "Nautilus" default file manager. When I plug in the 320 gig Toshiba external hard drive, I get no indication on the desktop or the file manager (thus "not recogized"). When I run the command "cat/proc/partitions/" I get an error message Could not open location 'file:///home/bob/cat/proc/partitions' with or without the external hard drive installed. With the "dmeg" command I get about 10 pages of info with no mention of disk/partition/anything in /proc/partitions. When I run "lsub" command I get the following: bob@bob-desktop:~$ lsusb Bus 005 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub Bus 004 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub Bus 003 Device 003: ID 04b3:3003 IBM Corp. Rapid Access III Keyboard Bus 003 Device 002: ID 04b3:3004 IBM Corp. Media Access Pro Keyboard Bus 003 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub Bus 002 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub Bus 001 Device 001: ID 1d6b:0002 Linux Foundation 2.0 root hub bob@bob-desktop:~$

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  • OpenSUSE Yast permissions for user

    - by pajton
    I have an OpenSUSE 11.4 box with Kde 4.6. I am currently working to create a sandbox environment for the user, let's call hime bob. Bob isn't allowed to do much in the system, but I'd like to let him configure certain things in yast. I have dektop shortcuts for particular yast modules, e.g. the shortcut executes xdg-su -c "/sbin/yast2 lan" to launch yast lan configuration. Now, I do not want Bob to have to enter password to launch this configuration (just please don't tell me it's insecure - I know this, in this particular setting it is going to be OK). I wanted to do this with setuid, but obiously setting it on *.desktop shortcut doesn't work. There is sudo approach, but I would have to allow Bob to use all yast modules. So, is there anything more fine-grained to set the permissions for exact yast modules? Thanks in advance!

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  • Which server software and configuration to retrieve from multiple POP servers, routing by address to correct user

    - by rolinger
    I am setting up a small email server on a Debian machine, which needs to pick up mail from a variety of POP servers and figure out who to send it to from the address, but I'm not clear what software will do what I need, although it seems like a very simple question! For example, I have 2 users, Alice and Bob. Any email to [email protected] ([email protected] etc) should go to Alice, all other mail to domain.example.com should go to Bob. Any email to [email protected] should go to Bob, and [email protected] should go to Alice Anything to *@bobs.place.com should go to Bob And so on... The idea is to pull together a load of mail addresses that have built up over the years and present them all as a single mailbox for Bob and another one for Alice. I'm expecting something like Postfix + Dovecot + Amavis + Spamassassin + Squirrelmail to fit the bill, but I'm not sure where the above comes in, can Postfix deal with it as a set of defined regular expressions, or is it a job for Amavis, or something else entirely? Do I need fetchmail in this mix, or is its role now included in one of the other components above. I think of it as content-filtering, but everything I read about content-filtering is focussed on detecting spam rather than routing email.

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  • Sendmail - preventing aliased users from receiving multiple copies of the same email

    - by MikeQ
    Is there any way to prevent a user from receiving multiple copies of the same email if an email is sent to both an alias for the user as well as the user themselves? For example, suppose bob.smith is a included in the alias list for developers (@company.com) If I send the email to both the user and an alias for the user: To: bob[email protected], [email protected] ... is there any way to prevent user Bob from receiving the same email two times? EDIT: I've observed that if Bob is a member of two different alias groups, and I send an email just to those two groups (not the user directly), sendmail correctly expands the groups and removes the duplicate. The behavior I want to fix occurs when you send directly to the user AND a group they belong to.

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  • Windows 7, network shares, and authentication via local group instead of local user

    - by Donovan
    I have been doing some troubleshooting of my home network lately and have come to an odd conclusion that I was hoping to get some clarification on. I'm used to managing share permissions in a domain environment via groups instead of individual user accounts. I have a box at home running windows 7 ultimate and I decided to share some directories on that machine. I set it up to disallow guest access and require specifically granted permissions. (password moe?). Anyway, after a whole bunch of time i figured out that even though the shares I created were allowed via a local group i could not access them until i gave specific allowance to the intended user. I just didn't think i would have to do that. So here is the breakdown. Network is windows workgroup, not homegroup or nt domain PC_1 - win 7 ultimate - sharing in classic mode - user BOB - groups Admins PC_2 - win 7 starter - client - user BOB - groups admins PC_3 - win xp pro - client - user BOB - groups admins the share on PC_1 granted permission to only the local group administrators. local user BOB on PC_1 was a member of administrators. Both PC_2 and PC_3 could not browse the intended share on PC_1 because they were denied access. Also, no challenge was presented. They were simply denied. After adding BOB specifically to the intended share everything works just fine. Remember, its not an nt domain just a workgroup. But still, shouldn't i be able to manage share permissions via groups instead of individual user accounts? D.

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