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• ms excel find and replace @ symbol results in broken formula

  - by Loopo

  I'm trying to search and replace in excel, the column is formatted as 'Text'. Find: [@ replace with: @ Whenever this finds a match at the start of a cell i.e the cell contents start with [@ and tries to replace that with @ the result is an error 'This function is not valid' I guess that since the @ operator is for references, this is causing the cell to be interpreted differently (not as text anymore) How do I make this replacement work? Copy/paste into another program is not a good option because some of the cells contain line-breaks.

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• Powerpoint: Find in Files

  - by stanigator

  I am having trouble finding such functionalities in Microsoft Powerpoint 2003. I tried googling it but no luck either. Does it exist? Is there an easy way to find keywords in a group of Powerpoint presentation files? Thanks in advance.

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• Find more than one string with Excel?

  - by ramsespiso

  How to Find more than one string with Microsoft Office Excel with the graphical interface? For example, I am looking for the cells which is contained both strings Paul and John?

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• UltraEdit find/replace history full?

  - by Stan

  It seems my UE find/replace history is full or for somehow not logging my search terms anymore. What could cause this issue? Thanks.

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• Notepad++ find string with a new-line and replace

  - by Giraldi Maggio

  [Notepad++ Question] How do I use find-and-replace to replace the attribute of a series of tags using expression? Case scenario: Let's say I have a couple of lines of something like this: <li><a title="Bla bla" href= "http://www.url.com/etc">Text</a></li> And I want to replace them with this: <li><a title="Bla bla" href="">Text</a></li> Note the new line and double tabs on the original.

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• Exclude all hidden directories in UNIX find

  - by xRickerlx

  I'm doing a word search using the following command: find . -exec grep -q [some_word] '{}' \; -print -o -name .svn -prune -o -name .ssh -prune -o -name .boneyard -o -name log -prune -prune -o -name tmp -prune Is it possible to use a regex to exclude all hidden directories? Note: The current command traverses the entire tree from the current location and exclude those being pruned. The exclusion needs to work for any hidden directory regardless off location.

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• Find files containing a string on the whole filesystem

  - by Fabio

  I need to find all the instances of a given string in the whole filesystem, because I don't remember in which configuration files, script or any other programs I put it and I need to update that string with a new one. I tried with the following command `grep -nr 'needle' / --exclude-dir=.svn | mail [email protected] -s 'References on xxx' If I run this command on a small directory it gives me the output I need in the form /path1/:nn:line containing needle /path2/:nn:line containing needle where /path1 is the full path of the file, nn is the row containing the needle and last field is the content of the line. However when I run the command on the root directory the grep process hang after a while. I run this script about 8 hours ago and even on a small filesystem (less than 5GB) it doesn't end and if I run top or ps the process seems sleeping root 24909 0.0 0.1 3772 1520 pts/1 S+ Feb10 0:15 grep -nr needle / --exclude-dir=.svn Why it doesn't end? Is there any better way to do this (it's a one time job, I don't need to execute this more than once) Thanks.

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• command line find/replace help

  - by Chrisbloom7

  I've got a set of 5000+ files that I need to do a simple search and replace in. I have been doing it in a text editor (EditPlus) by opening 500 files at a time, doing a global search/replace, saving all, closing, etc. But, that's taking literally hours to do and it's boring and tedious and I already have done it once today and need to do it again because all the files got refreshed. Is there a way to do this via the Bash command line? Here's the details: Find onchange="document.location ='/products/view.html/view/'+this.value" Replace it with onchange="alert('Not implemented')" style="display: none" All of the files have a .HTM extension, but they are nested in several sub directories.

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• Find & Replace in blogger

  - by Benjol

  (I just learnt that Yahoo are shutting down Geocities, this is a bummer as I used my account there to host two icons, in the days when Blogger didn't upload gifs. Now those two icons are referenced in every one of my 600+ posts). Blogger doesn't have a "Find & Replace in all posts" function. I'm wondering about using the API to hack something together, and wondered if anyone has already tried playing with the API, if there are any tips or things to avoid. Also if there isn't a sneaky shortcut (like switching to ftp, doing the replace locally then switching back?). Not 100% programming related, please be lenient, or at least answer my question before closing it!

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• How to scrub a document of all text between brackets with find and replace

  - by sam

  I have a log file and I need to find all instances of <password> hash here </password> and remove the hash and replace it with some dummy text like aaa-aaa-aaa-aaaa. The recurring search argument is anything that matches a bracket that starts with <password> and ends with </password>. All the hashes being replaced will be different. What's the easiest way to go a bout this? The log is on a windows machine. Probably easiest would be to use MS word for me, unless it's achievable with wordpad, notepad, or some other light weight editor like textpad. thanks

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• Find/Replace Paragraph End (^13) in Microsoft Word 2007 Merges Paragraphs

  - by Mike Blyth

  I need to replace a target at the beginning of lines with something else. Without wildcards, I can say to replace "^pTarget" with "^pReplacement". With wildcards enabled, I use replace "^13Target" with "^13Replacement". The replacement is successful except that the paragraph is now merged with the previous one in a strange way: The end-paragraph mark is still in place and the paragraph begins on a new line, but Triple clicking to select paragraph selects both the changed paragraph and the one above In a macro, starting in the paragraph above and extending the selection to the end of paragraph causes both paragraphs to be selected. Inter-paragraph spacing disappears between the changed paragraph and the one above. In essence, the paragraph boundary has been removed although the end-paragraph mark is still shown. To duplicate this problem, make a new document Line 1 Line 2 Line 3 (separate paragraphs). Find and replace (with wildcards on) "^13" with "^13". If your result is the same as mine, you will see the problems listed above. I can work around this in the usual way of replacing ^p with something else first, e.g. "^p" = "$", then "$target" = "$replacement", but I'm curious about what's going on. (This is using Word 2007 on Windows 7) I don't know Word XML, but the XML output seems to correspond with the above. Replacing ^13 with ^13 moves the paragraphs together in almost the same way as replacing end-paragraph with end-line (^p = ^l). Here is the relevant XML of the original "Line 1, Line 2, Line 3" in separate paragraphs: <w:p w:rsidR="00BB3032" w:rsidRDefault="00027252"> <w:r><w:t>Line 1</w:t></w:r> </w:p> <w:p w:rsidR="00027252" w:rsidRDefault="00027252"> <w:r><w:t>Line 2</w:t></w:r> </w:p> <w:p w:rsidR="00027252" w:rsidRDefault="00027252"> <w:r><w:t>Line 3</w:t></w:r> </w:p> Now after replacing ^13 with ^13: <w:p w:rsidR="00027252" w:rsidRDefault="00027252"> <w:r><w:t>Line 1</w:t></w:r> <w:r w:rsidR="00C57863"><w:cr/></w:r> <w:r><w:t>Line 2</w:t></w:r> <w:r w:rsidR="00C57863"><w:cr/></w:r> <w:r><w:t>Line 3</w:t></w:r> <w:r w:rsidR="00C57863"><w:cr/></w:r> </w:p> Now original after replacement of ^p with ^l (convert end-paragraph to end-line) <w:p w:rsidR="00027252" w:rsidRDefault="00027252"> <w:r><w:t>Line 1</w:t></w:r> <w:r w:rsidR="00AC7B51"><w:br/></w:r> <w:r><w:t>Line 2</w:t></w:r> <w:r w:rsidR="00AC7B51"><w:br/></w:r> <w:r><w:t>Line 3</w:t></w:r> <w:r w:rsidR="00AC7B51"><w:br/></w:r> </w:p>

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• Rails: combining multiple find requests

  - by peppermonkey

  What I want to do is something like this: searchid = 4 while searchid != -1 @a += A.find(searchid) @b = B.find(searchid) searchid = @b.parentid end The problem being the line @a += A.find(searchid) The error being something like NoMethodError: undefined method `+' for # So, how do you combine multiple 'find' requests?

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• find: missing argument to -exec in bash script

  - by Mephi_stofel

  The following works fine when I type it exactly in the command line: find /<some_path>/{epson,epson_laser,epson_inkjet} -iname "*.ppd" -exec grep "\*ModelName\:" {} \; | sed 's/.*\"\(.*\)\"/\1/' However, when I try to call the following from a bash script I get find: missing argument to -exec'. I have also tried the following (in many variants): eval find "$1" -iname "*.ppd" -exec 'bash -c grep "\*ModelName\:" "$1" | sed "s/.*\"\(.*\)\"/\1/" \; as was mentioned in find-exec-echo-missing-argument-to-exec.

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• How to find files older than N days from a given timestamp

  - by JGeZau

  I want to find files older than N days from a given timestamp in format YYYYMMDDHH I can find file older than 2 days with the below command, but this finds files with present time find /path/to/dir -mtime -2 -type f -ls Lets say I give the input timeSamp=2011093009 so I want to find files older than 2 days from 2011093009 Been doing my research, but can't seem to figure it out. ========================================== Found the solution...see below for my Answer.. Thanks

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• Find directories not containing a specific directory

  - by Morgan ARR Allen

  Been searching around for a bit and cannot find a solution for this one. I guess I'm looking for a leaf-directory by name. In this example I'd like to get a list of directories call 'modules' that do NOT have a subdirectory called module. modules/package1/modules/spackage1 modules/package1/modules/spackage2 modules/package1/modules/spackage3/modules modules/package1/modules/spackage3/modules/spackage1 modules/package2/modules/ The list I desire would contain modules/package1/modules/spackage3/modules/ modules/package2/modules/ All the directories named module that do not have a subdirectory called module I started with trying something this with no luck find . -name modules \! -exec sh -c 'find -name modules' \; -exec works on exit code, okay lets pass the count as exit code find . -name modules -exec sh -c 'exit $(find {} -name modules|grep -n ""|tail -n1|cut -d: -f1)' \; This should take the count of each subdirectory called modules and exit with it. No such love.

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• bash find xargs grep only single occurence

  - by keftebub

  hi. maybe it's a bit strange - and maybe there are other tools to do this but, well.. i am using the following classic bash command to find all files which contain some string: find . -type f | xargs grep "something" i have a great number of files, on multiple depths. first occurence of "something" is enough for me, but find continues searching, and takes a long time to complete the rest of the files. what i would like to do is something like a "feedback" from grep back to find so that find could stop searching for more files. is such a thing possible? thank you

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• Using find and tar with files with special characters in the name

  - by Costi

  I want to archive all .ctl files in a folder, recursively. tar -cf ctlfiles.tar `find /home/db -name "*.ctl" -print` The error message : tar: Removing leading `/' from member names tar: /home/db/dunn/j: Cannot stat: No such file or directory tar: 74.ctl: Cannot stat: No such file or directory I have these files: /home/db/dunn/j 74.ctl and j 75. Notice the extra space. What if the files have other special characters? How do I archive these files recursively?

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• grep + sed for find & replace fun!

  - by Jim Greenleaf

  I have a dev copy of a website set up that has quite a few hardcoded references to its live counterpart. I would like to replace all occurrences of "www." with "dev." in all files. I think I can use a combination of grep + sed, but I'm not sure how.

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• find files their name is smaller or greater than a given parameter

  - by Tzury Bar Yochay

  Say that in a given directory I got tzury@x200:~/Desktop/sandbox$ ls -l total 20 drwxr-xr-x 2 tzury tzury 4096 2011-03-09 10:19 N00.P000 drwxr-xr-x 2 tzury tzury 4096 2011-03-09 10:19 N00.P001 drwxr-xr-x 2 tzury tzury 4096 2011-03-09 10:19 N00.P002 drwxr-xr-x 2 tzury tzury 4096 2011-03-09 10:19 N00.P003 drwxr-xr-x 2 tzury tzury 4096 2011-03-09 10:19 N00.P004 drwxr-xr-x 2 tzury tzury 4096 2011-03-09 10:19 N01.P000 drwxr-xr-x 2 tzury tzury 4096 2011-03-09 10:19 N01.P001 drwxr-xr-x 2 tzury tzury 4096 2011-03-09 10:19 N01.P002 I seek for a bash way to grab the list of files which their name is either grater or smaller than a given parameter, for instance: $ my_finder lt N00.P003 shall return N00.P000, N00.P001 and N00.P002 $ my_finder gt N00.P003 shall return N00.P004, N01.P000, N01.P001 and N01.P002 I was thinking of iterating over for name in $(ls) and while $name != $2 but believe there are more elegant way of doing so

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• Problem using the find function in MATLAB

  - by Peter Etchells

  I have two arrays of data that I'm trying to amalgamate. One contains actual latencies from an experiment in the first column (e.g. 0.345, 0.455... never more than 3 decimal places), along with other data from that experiment. The other contains what is effectively a 'look up' list of latencies ranging from 0.001 to 0.500 in 0.001 increments, along with other pieces of data. Both data sets are X-by-Y doubles. What I'm trying to do is something like... for i = 1:length(actual_latency) row = find(predicted_data(:,1) == actual_latency(i)) full_set(i,1:4) = [actual_latency(i) other_info(i) predicted_info(row,2) ... predicted_info(row,3)]; end ...in order to find the relevant row in predicted_data where the look up latency corresponds to the actual latency. I then use this to created an amalgamated data set, full_set. I figured this would be really simple, but the find function keeps failing by throwing up an empty matrix when looking for an actual latency that I know is in predicted_data(:,1) (as I've double-checked during debugging). Moreover, if I replace find with a for loop to do the same job, I get a similar error. It doesn't appear to be systematic - using different participant data sets throws it up in different places. Furthermore, during debugging mode, if I use find to try and find a hard-coded value of actual_latency, it doesn't always work. Sometimes yes, sometimes no. I'm really scratching my head over this, so if anyone has any ideas about what might be going on, I'd be really grateful.

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• Problem using find function in Matlab

  - by Peter Etchells

  Hi all, I have two arrays of data that I'm trying to amalgamate. One contains actual latencies from an experiment in the first column (e.g. 0.345, 0.455... never more than 3 decimal places), along with other data from that experiment. The other contains what is effectively a 'look up' list of latencies ranging from 0.001 to 0.500 in 0.001 increments, along with other pieces of data. Both data sets are X-by-Y doubles. What I'm trying to do is something like... for i = 1:length(actual_latency) row = find(predicted_data(:,1) == actual_latency(i) full_set(i,1:4) = [actual_latency(i) other_info(i) predicted_info(row,2)... predicted_info(row,3)]; end ...in order to find the relevant row in predicted_data where the look up latency corresponds to the actual latency. I then use this to created an amalgamated data set, full_set. I figured this would be really simple, but the find function keeps failing by throwing up an empty matrix when looking for an actual latency that I know is in predicted_data(:,1) (as I've double-checked during debugging). Moreover, if I replace find with a for loop to do the same job, I get a similar error. It doesn't appear to be systematic - using different participant data sets throws it up in different places. Furthermore, during debugging mode, if I use find to try and find a hard-coded value of actual_latency, it doesn't always work. Sometimes yes, sometimes no. I'm really scratching my head over this, so if anyone has any ideas about what might be going on, I'd be really grateful.

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• Visual Studio 2010 Solution Find all References Not Working

  - by Jeremiah

  I have a Visual Studio 2010 Solution that was imported from a Visual Studio 2008 solution that the Find all References does not work on. I've tried doing some searches on Google to try and figure this out but have come up empty handed. The find all references in VS2008 worked like a charm, we upgraded to 2010 and now no matter what file I'm in the Find All References doesn't return anything. Anyone have any idea how to possibly fix this or some good ways to "debug" the issue.

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• Linux/OpenSSL:Send find output to openssl

  - by Starsky

  I am trying to send the output from the find command to OpenSSL in order to find out when certificates expire. This finds the files find . -name \*.pem -type f This generates the cert info I want openssl x509 -in certname.pem -noout -enddate Can I merge these two? Thanks for your help.

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• Outlook VBA - Find & Replace Incoming Emails

  - by user1912198

  Good morning everyone at Stackoverflow, I am trying to find a VBA script that finds and replaces a certain text in incoming e-mails. So far i've been unable to find such a script that is working. I found several scripts to find and replace stuff in the e-mail but these don't work as a rule on incoming e-mails, they only work on outgoing / creating e-mails. Does anyone have such a script that they can share with me? I would like to find & replace a certain text on every incoming e-mail. I would really apreciate it! Regards, Kris ps: I don't know how to program a whole VBA script, that's why I am asking here :) Current Code: Sub testing(MyMail As MailItem) Dim mail As MailItem Dim Inbox As Outlook.Folder Set Inbox = Session.GetDefaultFolder(olFolderInbox) For Each mail In Inbox.Items 'change subject mail.Subject = "TESTING" 'replace body text If mail.BodyFormat = olFormatHTML Then mail.HTMLBody = Replace(mail.HTMLBody, "Test 123", "TESTING") Else mail.Body = Replace(mail.Body, "Test 123", "TESTING") End If Next mail End Sub

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• Word VBA - Find text between delimiters and convert to lower case

  - by jJack

  I would like to find text which is between the < and characters, and then turn any found text into "normal" case, where first letter of word is capitalized. Here is what I have thus far: Function findTextBetweenCarots() As String Dim strText As String With Selection .Find.Text = "<" ' what about <[^0-9]+> ? .Find.Forward = True .Find.Wrap = wdFindContinue End With Selection.Find.Execute ' Application.Selection. ' how do I get the text between the other ">"? findCarotSymb = Application.Selection.Text End Function Or, is there a better way of doing this? I also approached the problem using the VBScript Regex 5.5 library, which worked on simple documents, but not on certain documents with complex tables. For example, trying to just bold the text (for simplicity): Sub BoldUpperCaseWords() Dim regEx, Match, Matches Dim rngRange As Range Set regEx = New RegExp regEx.Pattern = "<[^0-9]+>" regEx.IgnoreCase = False regEx.Global = True Set Matches = regEx.Execute(ActiveDocument.Range.Text) For Each Match In Matches ActiveDocument.Range(Match.FirstIndex, Match.FirstIndex + Len(Match.Value)).Bold = True Next End Sub would not work in a document with tables. In fact, it would not even bold the correct text (the text between the <. This leads me to believe I have a broader issue here that I am missing. Here is what a sample doc looks like. Notice the wrong text is bold:

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