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  • How can I get ffmpeg to convert a .mov to a .gif?

    - by user29336
    I'm trying to convert a .mov to a .gif and I'm not having success. Here's the error: ffmpeg -pix_fmt rgb24 -i yesbuddy.mov output.gif ffmpeg version 0.11.1 Copyright (c) 2000-2012 the FFmpeg developers built on Jun 12 2012 17:47:34 with clang 2.1 (tags/Apple/clang-163.7.1) configuration: --prefix=/usr/local/Cellar/ffmpeg/0.11.1 --enable-shared --enable-gpl --enable-version3 --enable-nonfree --enable-hardcoded-tables --enable-libfreetype --cc=/usr/bin/clang --enable-libx264 --enable-libfaac --enable-libmp3lame --enable-librtmp --enable-libtheora --enable-libvorbis --enable-libvpx --enable-libxvid --enable-libopencore-amrnb --enable-libopencore-amrwb --enable-libass --enable-libvo-aacenc --disable-ffplay libavutil 51. 54.100 / 51. 54.100 libavcodec 54. 23.100 / 54. 23.100 libavformat 54. 6.100 / 54. 6.100 libavdevice 54. 0.100 / 54. 0.100 libavfilter 2. 77.100 / 2. 77.100 libswscale 2. 1.100 / 2. 1.100 libswresample 0. 15.100 / 0. 15.100 libpostproc 52. 0.100 / 52. 0.100 Option pixel_format not found. If I leave out the -pix_fmt rgb24 part it complains. Thoughts on how to fix?

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  • How would I modify this ffmpeg command to include 4 videos?

    - by Michael Shnitzer
    Say I had 4 videos with the following names: Main Video.mov Top Left.mov Top Right.mov Top Mid.mov and I wanted to have "Main Video" play with a picture in picture effect with boxes of videos playing in the top left, top right and top mid. Each box would have the video that is similarly named. This command will do picture in picture for 2 videos, with one video in the lower right. ffmpeg -i 2013-07-31\ 231548.MOV -vf "movie=2013-07-31\ 231722.MOV, scale=iw/5:ih/5 [small]; [in][small] overlay=main_w*0.77:main_h*0.77 [out]" -strict -2 output.mov Can someone help me update this command to work with the 4 files I mentioned above? Thanks

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  • help understanding differences between #define, const and enum in C and C++ on assembly level.

    - by martin
    recently, i am looking into assembly codes for #define, const and enum: C codes(#define): 3 #define pi 3 4 int main(void) 5 { 6 int a,r=1; 7 a=2*pi*r; 8 return 0; 9 } assembly codes(for line 6 and 7 in c codes) generated by GCC: 6 mov $0x1, -0x4(%ebp) 7 mov -0x4(%ebp), %edx 7 mov %edx, %eax 7 add %eax, %eax 7 add %edx, %eax 7 add %eax, %eax 7 mov %eax, -0x8(%ebp) C codes(enum): 2 int main(void) 3 { 4 int a,r=1; 5 enum{pi=3}; 6 a=2*pi*r; 7 return 0; 8 } assembly codes(for line 4 and 6 in c codes) generated by GCC: 6 mov $0x1, -0x4(%ebp) 7 mov -0x4(%ebp), %edx 7 mov %edx, %eax 7 add %eax, %eax 7 add %edx, %eax 7 add %eax, %eax 7 mov %eax, -0x8(%ebp) C codes(const): 4 int main(void) 5 { 6 int a,r=1; 7 const int pi=3; 8 a=2*pi*r; 9 return 0; 10 } assembly codes(for line 7 and 8 in c codes) generated by GCC: 6 movl $0x3, -0x8(%ebp) 7 movl $0x3, -0x4(%ebp) 8 mov -0x4(%ebp), %eax 8 add %eax, %eax 8 imul -0x8(%ebp), %eax 8 mov %eax, 0xc(%ebp) i found that use #define and enum, the assembly codes are the same. The compiler use 3 add instructions to perform multiplication. However, when use const, imul instruction is used. Anyone knows the reason behind that?

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  • Output character in assembly

    - by lolopolosko
    Please help me! How i can output character that moves around the perimeter of a rectangle (10*5 or 15*7) in console with TASM? .MODEL small .STACK 100h .CODE start: mov ah,03 int 10h mov cx,10 A: push cx mov ah,03 int 10h mov ah,02h inc dl int 10h mov al,42 int 29h pop cx LOOP A mov ah,4ch int 21h end start I do not know how to solve the problem...

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  • Change an array's value in x86 assembly (embedded in C++)

    - by VV
    I am messing around with assembly for the first time, and can't seem to change the index values of an array. Here's the method I am working on int ascending_sort( char arrayOfLetters[], int arraySize ) { char temp; __asm { //??? } } And these are what I tried mov temp, 'X' mov al, temp mov arrayOfLetters[0], al And this gave me an error C2415: improper operand type so I tried mov temp, 'X' mov al, temp mov BYTE PTR arrayOfLetters[0], al This complied, but it didn't change the array...

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  • Interrupt ?13 (ah=48) - don't working

    - by GLeBaTi
    mov dl,00h mov ah,08h int 13h this is code showing normal parameters of floppy disk. mov dl,80h mov ah,08h int 13h this is code, showing not valid parameters of hard disk(may be, my hard disk space is big (LBA)), And I've written this code: mov dl,80h mov ah,48h int 13h it is code doing cf = 1(error). How fix it? I want learn parameters of my hard disk. (http://lrs.uni-passau.de/support/doc/interrupt-57/RB-0677.HTM)

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  • Sparc Assembly Call currupts data

    - by Sigge
    I am at the moment working with some assembler code for the Sparc processor family, and i am having some truble with a piece of code.. I think the code and output explains more, but in the short.. When i do a call to the function println my varaibels that i have written to the %fp - 8 memory location is destoryed.. here is my assembler code that i am trying to run !PROCEDURE main .section ".text" .global main .align 4 main: save %sp, -96, %sp L1: set 96, %l0 mov %l0, %o0 call initObject ; nop mov %o0, %l0 mov %l0, %o0 call Test$go ; nop mov %o0, %l0 mov %l0, %o0 call println ; nop L0: ret restore !END main !PROCEDURE Test$go .section ".text" .global Test$go .align 4 Test$go: save %sp, -96, %sp L3: mov %i0, %l0 set 0, %l0 set -8, %l1 add %fp,%l1, %l1 st %l0, [%l1] set 1, %l0 mov %l0, %o0 call println ; nop set -8, %l0 add %fp,%l0, %l0 ld [%l0], %l0 mov %l0, %o0 call println ; nop set 1, %l0 mov %l0, %i0 L2: ret restore !END Test$go Here is the assembler code for the println code .global println .type println,#function println: save %sp,-96,%sp ! block 1 .L193: ! File runtime.c: ! 42 } ! 43 ! 45 /** ! 46 Prints an integer to the standard output stream. ! 47 ! 48 @param i The integer to be printed. ! 49 */ ! 50 void println(int i) { ! 51 printf("%d\n", i); sethi %hi(.L195),%o0 or %o0,%lo(.L195),%o0 call printf mov %i0,%o1 jmp %i7+8 restore This is the out put i get when i run this piece of assembler code 1 67584 1 As u can see, the data that is located at %fp - 8 has been destroyed.. please all feedback is apritiated

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  • Sparc Assembly Call corrupts data

    - by Sigge
    I am at the moment working with some assembler code for the Sparc processor family, and i am having some truble with a piece of code.. I think the code and output explains more, but in the short.. When i do a call to the function println my varaibels that i have written to the %fp - 8 memory location is destoryed.. here is my assembler code that i am trying to run !PROCEDURE main .section ".text" .global main .align 4 main: save %sp, -96, %sp L1: set 96, %l0 mov %l0, %o0 call initObject ; nop mov %o0, %l0 mov %l0, %o0 call Test$go ; nop mov %o0, %l0 mov %l0, %o0 call println ; nop L0: ret restore !END main !PROCEDURE Test$go .section ".text" .global Test$go .align 4 Test$go: save %sp, -96, %sp L3: mov %i0, %l0 set 0, %l0 set -8, %l1 add %fp,%l1, %l1 st %l0, [%l1] set 1, %l0 mov %l0, %o0 call println ; nop set -8, %l0 add %fp,%l0, %l0 ld [%l0], %l0 mov %l0, %o0 call println ; nop set 1, %l0 mov %l0, %i0 L2: ret restore !END Test$go Here is the assembler code for the println code .global println .type println,#function println: save %sp,-96,%sp ! block 1 .L193: ! File runtime.c: ! 42 } ! 43 ! 45 /** ! 46 Prints an integer to the standard output stream. ! 47 ! 48 @param i The integer to be printed. ! 49 */ ! 50 void println(int i) { ! 51 printf("%d\n", i); sethi %hi(.L195),%o0 or %o0,%lo(.L195),%o0 call printf mov %i0,%o1 jmp %i7+8 restore This is the out put i get when i run this piece of assembler code 1 67584 1 As u can see, the data that is located at %fp - 8 has been destroyed.. please all feedback is apritiated

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  • Interrupt ?13 (ah=48) - not working

    - by GLeBaTi
    I want fetch the parameters of my hard disk. Using the technique described here. This is code showing normal parameters of floppy disk: mov dl,00h mov ah,08h int 13h This is code, showing not valid parameters of hard disk (may be, my hard disk space is big (LBA)): mov dl,80h mov ah,08h int 13h And I've written this code: mov dl,80h mov ah,48h int 13h The code is giving cf = 1(error). How do I fix it?

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  • Getting to grips with the stack in nasm

    - by MarkPearl
    Today I spent a good part of my day getting to grips with the stack and nasm. After looking at my notes on nasm I think this is one area for the course I am doing they could focus more on… So here are some snippets I have put together that have helped me understand a little bit about the stack… Simplest example of the stack You will probably see examples like the following in circulation… these demonstrate the simplest use of the stack… org 0x100 bits 16 jmp main main: push 42h push 43h push 44h mov ah,2h ;set to display characters pop dx    ;get the first value int 21h   ;and display it pop dx    ;get 2nd value int 21h   ;and display it pop dx    ;get 3rd value int 21h   ;and display it int 20h The output from above code would be… DCB Decoupling code using “call” and “ret” This is great, but it oversimplifies what I want to use the stack for… I do not know if this goes against the grain of assembly programmers or not, but I want to write loosely coupled assembly code – and I want to use the stack as a mechanism for passing values into my decoupled code. In nasm we have the call and return instructions, which provides a mechanism for decoupling code, for example the following could be done… org 0x100 bits 16 jmp main ;---------------------------------------- displayChar: mov ah,2h mov dx,41h int 21h ret ;---------------------------------------- main: call displayChar int 20h   This would output the following to the console A So, it would seem that call and ret allow us to jump to segments of our code and then return back to the calling position – a form of segmenting the code into what we would called in higher order languages “functions” or “methods”. The only issue is, in higher order languages there is a way to pass parameters into the functions and return results. Because of the primitive nature of the call and ret instructions, this does not seem to be obvious. We could of course use the registers to pass values into the subroutine and set values coming out, but the problem with this is we… Have a limited number of registers Are threading our code with tight coupling (it would be hard to migrate methods outside of their intended use in a particular program to another one) With that in mind, I turn to the stack to provide a loosely coupled way of calling subroutines… First attempt with the Stack Initially I thought this would be simple… we could use code that looks as follows to achieve what I want… org 0x100 bits 16 jmp main ;---------------------------------------- displayChar: mov ah,2h pop dx int 21h ret ;---------------------------------------- main: push 41h call displayChar int 20h   However running this application does not give the desired result, I want an ‘A’ to be returned, and I am getting something totally different (you will to). Reading up on the call and ret instructions a discovery is made… they are pushing and popping things onto and off the stack as well… When the call instruction is executed, the current value of IP (the address of the instruction to follow) is pushed onto the stack, when ret is called, the last value on the stack is popped off into the IP register. In effect what the above code is doing is as follows with the stack… push 41h push current value of ip pop current value of ip to dx pop 41h to ip This is not what I want, I need to access the 41h that I pushed onto the stack, but the call value (which is necessary) is putting something in my way. So, what to do? Remember we have other registers we can use as well as a thing called indirect addressing… So, after some reading around, I came up with the following approach using indirect addressing… org 0x100 bits 16 jmp main ;---------------------------------------- displayChar: mov bp,sp mov ah,2h mov dx,[bp+2] int 21h ret ;---------------------------------------- main: push 41h call displayChar int 20h In essence, what I have done here is used a trick with the stack pointer… it goes as follows… Push 41 onto the stack Make the call to the function, which will push the IP register onto the stack and then jump to the displayChar label Move the value in the stack point to the bp register (sp currently points at IP register) Move the at the location of bp minus 2 bytes to dx (this is now the value 41h) display it, execute the ret instruction, which pops the ip value off the stack and goes back to the calling point This approach is still very raw, some further reading around shows that I should be pushing the value of bp onto the stack before replacing it with sp, but it is the starting thread to getting loosely coupled subroutines. Let’s see if you get what the following output would be? org 0x100 bits 16 jmp main ;---------------------------------------- displayChar: mov bp,sp mov ah,2h mov dx,[bp+4] int 21h mov dx,[bp+2] int 21h ret ;---------------------------------------- main: push 41h push 42h call displayChar int 20h The output is… AB Where to from here? If by any luck some assembly programmer comes along and see this code and notices that I have made some fundamental flaw in my logic… I would like to know, so please leave a comment… appreciate any feedback!

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  • How to write a buffer-overflow exploit in windows XP,x86?

    - by Mask
    void function(int a, int b, int c) { char buffer1[5]; char buffer2[10]; int *ret; ret = buffer1 + 12; (*ret) += 8;//why is it 8?? } void main() { int x; x = 0; function(1,2,3); x = 1; printf("%d\n",x); } The above demo is from here: http://insecure.org/stf/smashstack.html But it's not working here: D:\test>gcc -Wall -Wextra hw.cpp && a.exe hw.cpp: In function `void function(int, int, int)': hw.cpp:6: warning: unused variable 'buffer2' hw.cpp: At global scope: hw.cpp:4: warning: unused parameter 'a' hw.cpp:4: warning: unused parameter 'b' hw.cpp:4: warning: unused parameter 'c' 1 And I don't understand why it's 8 though the author thinks: A little math tells us the distance is 8 bytes. My gdb dump as called: Dump of assembler code for function main: 0x004012ee <main+0>: push %ebp 0x004012ef <main+1>: mov %esp,%ebp 0x004012f1 <main+3>: sub $0x18,%esp 0x004012f4 <main+6>: and $0xfffffff0,%esp 0x004012f7 <main+9>: mov $0x0,%eax 0x004012fc <main+14>: add $0xf,%eax 0x004012ff <main+17>: add $0xf,%eax 0x00401302 <main+20>: shr $0x4,%eax 0x00401305 <main+23>: shl $0x4,%eax 0x00401308 <main+26>: mov %eax,0xfffffff8(%ebp) 0x0040130b <main+29>: mov 0xfffffff8(%ebp),%eax 0x0040130e <main+32>: call 0x401b00 <_alloca> 0x00401313 <main+37>: call 0x4017b0 <__main> 0x00401318 <main+42>: movl $0x0,0xfffffffc(%ebp) 0x0040131f <main+49>: movl $0x3,0x8(%esp) 0x00401327 <main+57>: movl $0x2,0x4(%esp) 0x0040132f <main+65>: movl $0x1,(%esp) 0x00401336 <main+72>: call 0x4012d0 <function> 0x0040133b <main+77>: movl $0x1,0xfffffffc(%ebp) 0x00401342 <main+84>: mov 0xfffffffc(%ebp),%eax 0x00401345 <main+87>: mov %eax,0x4(%esp) 0x00401349 <main+91>: movl $0x403000,(%esp) 0x00401350 <main+98>: call 0x401b60 <printf> 0x00401355 <main+103>: leave 0x00401356 <main+104>: ret 0x00401357 <main+105>: nop 0x00401358 <main+106>: add %al,(%eax) 0x0040135a <main+108>: add %al,(%eax) 0x0040135c <main+110>: add %al,(%eax) 0x0040135e <main+112>: add %al,(%eax) End of assembler dump. Dump of assembler code for function function: 0x004012d0 <function+0>: push %ebp 0x004012d1 <function+1>: mov %esp,%ebp 0x004012d3 <function+3>: sub $0x38,%esp 0x004012d6 <function+6>: lea 0xffffffe8(%ebp),%eax 0x004012d9 <function+9>: add $0xc,%eax 0x004012dc <function+12>: mov %eax,0xffffffd4(%ebp) 0x004012df <function+15>: mov 0xffffffd4(%ebp),%edx 0x004012e2 <function+18>: mov 0xffffffd4(%ebp),%eax 0x004012e5 <function+21>: movzbl (%eax),%eax 0x004012e8 <function+24>: add $0x5,%al 0x004012ea <function+26>: mov %al,(%edx) 0x004012ec <function+28>: leave 0x004012ed <function+29>: ret In my case the distance should be - = 5,right?But it seems not working..

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  • How to write a buffer-overflow exploit in GCC,windows XP,x86?

    - by Mask
    void function(int a, int b, int c) { char buffer1[5]; char buffer2[10]; int *ret; ret = buffer1 + 12; (*ret) += 8;//why is it 8?? } void main() { int x; x = 0; function(1,2,3); x = 1; printf("%d\n",x); } The above demo is from here: http://insecure.org/stf/smashstack.html But it's not working here: D:\test>gcc -Wall -Wextra hw.cpp && a.exe hw.cpp: In function `void function(int, int, int)': hw.cpp:6: warning: unused variable 'buffer2' hw.cpp: At global scope: hw.cpp:4: warning: unused parameter 'a' hw.cpp:4: warning: unused parameter 'b' hw.cpp:4: warning: unused parameter 'c' 1 And I don't understand why it's 8 though the author thinks: A little math tells us the distance is 8 bytes. My gdb dump as called: Dump of assembler code for function main: 0x004012ee <main+0>: push %ebp 0x004012ef <main+1>: mov %esp,%ebp 0x004012f1 <main+3>: sub $0x18,%esp 0x004012f4 <main+6>: and $0xfffffff0,%esp 0x004012f7 <main+9>: mov $0x0,%eax 0x004012fc <main+14>: add $0xf,%eax 0x004012ff <main+17>: add $0xf,%eax 0x00401302 <main+20>: shr $0x4,%eax 0x00401305 <main+23>: shl $0x4,%eax 0x00401308 <main+26>: mov %eax,0xfffffff8(%ebp) 0x0040130b <main+29>: mov 0xfffffff8(%ebp),%eax 0x0040130e <main+32>: call 0x401b00 <_alloca> 0x00401313 <main+37>: call 0x4017b0 <__main> 0x00401318 <main+42>: movl $0x0,0xfffffffc(%ebp) 0x0040131f <main+49>: movl $0x3,0x8(%esp) 0x00401327 <main+57>: movl $0x2,0x4(%esp) 0x0040132f <main+65>: movl $0x1,(%esp) 0x00401336 <main+72>: call 0x4012d0 <function> 0x0040133b <main+77>: movl $0x1,0xfffffffc(%ebp) 0x00401342 <main+84>: mov 0xfffffffc(%ebp),%eax 0x00401345 <main+87>: mov %eax,0x4(%esp) 0x00401349 <main+91>: movl $0x403000,(%esp) 0x00401350 <main+98>: call 0x401b60 <printf> 0x00401355 <main+103>: leave 0x00401356 <main+104>: ret 0x00401357 <main+105>: nop 0x00401358 <main+106>: add %al,(%eax) 0x0040135a <main+108>: add %al,(%eax) 0x0040135c <main+110>: add %al,(%eax) 0x0040135e <main+112>: add %al,(%eax) End of assembler dump. Dump of assembler code for function function: 0x004012d0 <function+0>: push %ebp 0x004012d1 <function+1>: mov %esp,%ebp 0x004012d3 <function+3>: sub $0x38,%esp 0x004012d6 <function+6>: lea 0xffffffe8(%ebp),%eax 0x004012d9 <function+9>: add $0xc,%eax 0x004012dc <function+12>: mov %eax,0xffffffd4(%ebp) 0x004012df <function+15>: mov 0xffffffd4(%ebp),%edx 0x004012e2 <function+18>: mov 0xffffffd4(%ebp),%eax 0x004012e5 <function+21>: movzbl (%eax),%eax 0x004012e8 <function+24>: add $0x5,%al 0x004012ea <function+26>: mov %al,(%edx) 0x004012ec <function+28>: leave 0x004012ed <function+29>: ret In my case the distance should be - = 5,right?But it seems not working.. Why function needs 56 bytes for local variables?( sub $0x38,%esp )

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  • How to generate thumbnails for less common video containers (mkv, ogm, mp4, flv, rmvb and mov) in wi

    - by fluxtendu
    So how to generate thumbnails for these containers? I know that the install of "DivX Plus Tech Preview: MKV on Windows 7" does it for MKV. But I think that only some registry changes are really necessary and I want it for other containers. If it's possible to avoiding the install of (always bloated) codecs packs it would be nice... Maybe only installing ffdshow or essential and separated codecs. (some time ago I have try reg files for vista without success...) Update: I have installed Win7codecs & tweaked a little its settings and I got almost everything I want. (I have also re-installed the relevant part of the divx plus tech preview to get something else than an all black preview for MKV) Issues that I still want to resolve: Find a cleaner & lighter method Almost all my rmvb and mov files got an all black preview (installing real media/quick time alternative doesn't help, is it the same with the officials?) With almost all containers (avi, mkv, ogm, mpg), I have (few) random files that don't get the preview. I could play them in WMP or another player and don't have found a pattern in the codecs used. All wmv, flv and mp4 have previews but I have less files in these containers. (I clear my thumbnails cache to test them) More generally I would like to understand how windows handle the containers & codecs to generate the previews. And a software that let me choose arbitrarily the pictures previewed would be convenient too

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  • GCC emits extra code for boost::shared_ptr dereference

    - by Checkers
    I have the following code: #include <boost/shared_ptr.hpp> struct Foo { int a; }; static int A; void func_shared(const boost::shared_ptr<Foo> &foo) { A = foo->a; } void func_raw(Foo * const foo) { A = foo->a; } I thought the compiler would create identical code, but for shared_ptr version an extra seemingly redundant instruction is emitted. Disassembly of section .text: 00000000 <func_raw(Foo*)>: 0: 55 push ebp 1: 89 e5 mov ebp,esp 3: 8b 45 08 mov eax,DWORD PTR [ebp+8] 6: 5d pop ebp 7: 8b 00 mov eax,DWORD PTR [eax] 9: a3 00 00 00 00 mov ds:0x0,eax e: c3 ret f: 90 nop 00000010 <func_shared(boost::shared_ptr<Foo> const&)>: 10: 55 push ebp 11: 89 e5 mov ebp,esp 13: 8b 45 08 mov eax,DWORD PTR [ebp+8] 16: 5d pop ebp 17: 8b 00 mov eax,DWORD PTR [eax] 19: 8b 00 mov eax,DWORD PTR [eax] 1b: a3 00 00 00 00 mov ds:0x0,eax 20: c3 ret I'm just curious, is this necessary, or it is just an optimizer's shortcoming? Compiling with g++ 4.1.2, -O3 -NDEBUG.

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  • x86 Assembly: Before Making a System Call on Linux Should You Save All Registers?

    - by mudge
    I have the below code that opens up a file, reads it into a buffer and then closes the file. The close file system call requires that the file descriptor number be in the ebx register. The ebx register gets the file descriptor number before the read system call is made. My question is should I save the ebx register on the stack or somewhere before I make the read system call, (could int 80h trash the ebx register?). And then restore the ebx register for the close system call? Or is the code I have below fine and safe? I have run the below code and it works, I'm just not sure if it is generally considered good assembly practice or not because I don't save the ebx register before the int 80h read call. ;; open up the input file mov eax,5 ; open file system call number mov ebx,[esp+8] ; null terminated string file name, first command line parameter mov ecx,0o ; access type: O_RDONLY int 80h ; file handle or negative error number put in eax test eax,eax js Error ; test sign flag (SF) for negative number which signals error ;; read in the full input file mov ebx,eax ; assign input file descripter mov eax,3 ; read system call number mov ecx,InputBuff ; buffer to read into mov edx,INPUT_BUFF_LEN ; total bytes to read int 80h test eax,eax js Error ; if eax is negative then error jz Error ; if no bytes were read then error add eax,InputBuff ; add size of input to the begining of InputBuff location mov [InputEnd],eax ; assign address of end of input ;; close the input file ;; file descripter is already in ebx mov eax,6 ; close file system call number int 80h

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  • Assembly keep getting seg fault when working with stack [migrated]

    - by user973917
    I'm trying to learn assembly and have found that I keep getting segfaults when trying to push/pop data off of the stack. I've read a few guides and know how the stack works and how to work with the stack; but don't know why I keep getting the error. Can someone help? segment .data myvar: db "hello world", 0xA0, 0 myvarL: equ $-myvar segment .text global _start _start: push ebp mov ebp, esp push myvarL push myvar call _hworld _hworld: mov eax, 4 mov ebx, 1 mov ecx, [ebp+4] mov edx, [ebp+8] pop ebp int 0x80 ret I'm assuming that the +4 is 32 bits, then +8 is 64 bits. It isn't really clear to me why this way is being done on some of the guides I've read. I would assume that myvar is 13 bits?

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  • avconv and ffmpeg - drawtext filter text_w evaluates as 0 in Ubuntu Precise

    - by Chris White
    I'm attempting to draw text onto a video using either the avconv or ffmpeg commands. When specifying x= for where on the final video to place the text, the 'text_w' value is evaluating to 0, rather than the width of the rendered text as it should. I'm using Ubuntu 12.04 I've got avconv version 0.8.3-4:0.8.3-0ubuntu0.12.04.1 and ffmpeg version 0.8.3-4:0.8.3-0ubuntu0.12.04.1 Example command: avconv -i test.mov -vf "drawtext=fontfile='/usr/share/fonts/truetype/ttf-dejavu/DejaVuSans.ttf':text='test text':x=text_w:y=50:fontsize=24:fontcolor=black" texted.mov This command causes the text to be printed as if x were set to 0. What I'd really like to be able to do is center the text horizontally using something like this: avconv -i test.mov -vf "drawtext=fontfile='/usr/share/fonts/truetype/ttf-dejavu/DejaVuSans.ttf':text='test text':x=(main_w-text_w)/2:y=50:fontsize=24:fontcolor=black" texted.mov Using ffmpeg for to attempt the same ends with the same result ffmpeg -i test.mov -vf "drawtext=fontfile='/usr/share/fonts/truetype/ttf-dejavu/DejaVuSans.ttf':text='test text':x=(main_w-text_w)/2:y=50:fontsize=24:fontcolor=black" texted.mov

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  • Need some help deciphering a line of assembler code, from .NET JITted code

    - by Lasse V. Karlsen
    In a C# constructor, that ends up with a call to this(...), the actual call gets translated to this: 0000003d call dword ptr ds:[199B88E8h] What is the DS register contents here? I know it's the data-segment, but is this call through a VMT-table or similar? I doubt it though, since this(...) wouldn't be a call to a virtual method, just another constructor. I ask because the value at that location seems to be bad in some way, if I hit F11, trace into (Visual Studio 2008), on that call-instruction, the program crashes with an access violation. The code is deep inside a 3rd party control library, where, though I have the source code, I don't have the assemblies compiled with enough debug information that I can trace it through C# code, only through the disassembler, and then I have to match that back to the actual code. The C# code in question is this: public AxisRangeData(AxisRange range) : this(range, range.Axis) { } Reflector shows me this IL code: .maxstack 8 L_0000: ldarg.0 L_0001: ldarg.1 L_0002: ldarg.1 L_0003: callvirt instance class DevExpress.XtraCharts.AxisBase DevExpress.XtraCharts.AxisRange::get_Axis() L_0008: call instance void DevExpress.XtraCharts.Native.AxisRangeData::.ctor(class DevExpress.XtraCharts.ChartElement, class DevExpress.XtraCharts.AxisBase) L_000d: ret It's that last call there, to the other constructor of the same class, that fails. The debugger never surfaces inside the other method, it just crashes. The disassembly for the method after JITting is this: 00000000 push ebp 00000001 mov ebp,esp 00000003 sub esp,14h 00000006 mov dword ptr [ebp-4],ecx 00000009 mov dword ptr [ebp-8],edx 0000000c cmp dword ptr ds:[18890E24h],0 00000013 je 0000001A 00000015 call 61843511 0000001a mov eax,dword ptr [ebp-4] 0000001d mov dword ptr [ebp-0Ch],eax 00000020 mov eax,dword ptr [ebp-8] 00000023 mov dword ptr [ebp-10h],eax 00000026 mov ecx,dword ptr [ebp-8] 00000029 cmp dword ptr [ecx],ecx 0000002b call dword ptr ds:[1889D0DCh] // range.Axis 00000031 mov dword ptr [ebp-14h],eax 00000034 push dword ptr [ebp-14h] 00000037 mov edx,dword ptr [ebp-10h] 0000003a mov ecx,dword ptr [ebp-0Ch] 0000003d call dword ptr ds:[199B88E8h] // this(range, range.Axis)? 00000043 nop 00000044 mov esp,ebp 00000046 pop ebp 00000047 ret Basically what I'm asking is this: What the purpose of the ds:[ADDR] indirection here? VMT-table is only for virtual isn't it? and this is constructor Could the constructor have yet to be JITted, which could mean that the call would actually call through a JIT shim? I'm afraid I'm in deep water here, so anything might and could help. Edit: Well, the problem just got worse, or better, or whatever. We are developing the .NET feature in a C# project in a Visual Studio 2008 solution, and debugging and developing through Visual Studio. However, in the end, this code will be loaded into a .NET runtime hosted by a Win32 Delphi application. In order to facilitate easy experimentation of such features, we can also configure the Visual Studio project/solution/debugger to copy the produced dll's to the Delphi app's directory, and then execute the Delphi app, through the Visual Studio debugger. Turns out, the problem goes away if I run the program outside of the debugger, but during debugging, it crops up, every time. Not sure that helps, but since the code isn't slated for production release for another 6 months or so, then it takes some of the pressure off of it for the test release that we have soon. I'll dive into the memory parts later, but probably not until over the weekend, and post a followup.

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  • Problem with bootstrap loader and kernel

    - by dboarman-FissureStudios
    We are working on a project to learn how to write a kernel and learn the ins and outs. We have a bootstrap loader written and it appears to work. However we are having a problem with the kernel loading. I'll start with the first part: bootloader.asm: [BITS 16] [ORG 0x0000] ; ; all the stuff in between ; ; the bottom of the bootstrap loader datasector dw 0x0000 cluster dw 0x0000 ImageName db "KERNEL SYS" msgLoading db 0x0D, 0x0A, "Loading Kernel Shell", 0x0D, 0x0A, 0x00 msgCRLF db 0x0D, 0x0A, 0x00 msgProgress db ".", 0x00 msgFailure db 0x0D, 0x0A, "ERROR : Press key to reboot", 0x00 TIMES 510-($-$$) DB 0 DW 0xAA55 ;************************************************************************* The bootloader.asm is too long for the editor without causing it to chug and choke. In addition, the bootloader and kernel do work within bochs as we do get the message "Welcome to our OS". Anyway, the following is what we have for a kernel at this point. kernel.asm: [BITS 16] [ORG 0x0000] [SEGMENT .text] ; code segment mov ax, 0x0100 ; location where kernel is loaded mov ds, ax mov es, ax cli mov ss, ax ; stack segment mov sp, 0xFFFF ; stack pointer at 64k limit sti mov si, strWelcomeMsg ; load message call _disp_str mov ah, 0x00 int 0x16 ; interrupt: await keypress int 0x19 ; interrupt: reboot _disp_str: lodsb ; load next character or al, al ; test for NUL character jz .DONE mov ah, 0x0E ; BIOS teletype mov bh, 0x00 ; display page 0 mov bl, 0x07 ; text attribute int 0x10 ; interrupt: invoke BIOS jmp _disp_str .DONE: ret [SEGMENT .data] ; initialized data segment strWelcomeMsg db "Welcome to our OS", 0x00 [SEGMENT .bss] ; uninitialized data segment Using nasm 2.06rc2 I compile as such: nasm bootloader.asm -o bootloader.bin -f bin nasm kernel.asm -o kernel.sys -f bin We write bootloader.bin to the floppy as such: dd if=bootloader.bin bs=512 count=1 of/dev/fd0 We write kernel.sys to the floppy as such: cp kernel.sys /dev/fd0 As I stated, this works in bochs. But booting from the floppy we get output like so: Loading Kernel Shell ........... ERROR : Press key to reboot Other specifics: OpenSUSE 11.2, GNOME desktop, AMD x64 Any other information I may have missed, feel free to ask. I tried to get everything in here that would be needed. If I need to, I can find a way to get the entire bootloader.asm posted somewhere. We are not really interested in using GRUB either for several reasons. This could change, but we want to see this boot successful before we really consider GRUB.

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  • Could this code damage my processor??!!

    - by Osama Gamal
    A friend sent me that code and alleges that it could damage the processor. Is that true? void damage_processor() { while (true) { // Assembly code that sets the five control registers bits to ones which causes a bunch of exceptions in the system and then damages the processor Asm( "mov cr0, 0xffffffff \n\t" "mov cr1, 0xffffffff \n\t" "mov cr2, 0xffffffff \n\t" "mov cr3, 0xffffffff \n\t" "mov cr4, 0xffffffff \n\t" ) } } Is that true?

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