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  • Inspecting the model in a Rails application

    - by Matt Sherman
    I am learning some Ruby on Rails, and am a newbie. Most of my background is in ASP.net MVC on the back end. As I play with a basic scaffold project, I wonder about this case: you jump into an established Rails project and want to get to know the model. Based on what I have seen so far (again, simple scaffold), the properties for a given class are not immediately revealed. I don't see property accessors on the model classes. I do understand that this is because of the dynamic nature of Ruby and such things are not necessary or even perhaps desirable. Convention over code, I get that. (Am familiar with dynamic concepts, mostly via JS.) But if I am somewhere off in a view, and want to quickly know whether the (eg) Person object has a MiddleName property, how would I find that out? I don't have to go into the migrations, do I?

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  • Webcast: Oracle Loans Overview - Features, Demonstration & Data Model

    - by Annemarie Provisero
    Webcast: Oracle Loans Overview - Features, Demonstration & Data ModelDate:  November 13, 2013 at 10 am ET, 9 am CT, 8 am MT, 7 am PTCome learn about Oracle Loans features & data model.  This one-hour session is recommended for technical and functional users who use or are planning to use Oracle Loans.Topics will include:     Definition and feature summary     Key business concepts for Oracle Loans     Direct Loans demonstration     Introduction to the Loans data model Bring your questions! For more details on how to register, see Doc ID 1590843.1.  Remember that you can access a full listing of all future webcasts as well as replays from Doc ID 7409661.1.

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  • Which prediction model for web page recommendation?

    - by Nilesh
    I am trying to implement a web page recommendation wherein registered users will be given a recommendation of which page to visit depending upon the previous data.So with initial study I decided to go on with clustering the data with rough sets and then will move forward to find out the sequential patters with the use of prefix span algorithm.So now I want to have a better prediction model in place which can predict the access frequency of pages.I have figured out with Markov model but still some more suggestions will be valuable.Also please help me with some references of the models too.Is it possible to directly predict the next page access with the result of PrefixSpan.If so how?

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  • Inspecting the model in a Rails application

    - by Matt Sherman
    I am learning some Ruby on Rails, and am a newbie. Most of my background is in ASP.net MVC on the back end. As I play with a basic scaffold project, I wonder about this case: you jump into an established Rails project and want to get to know the model. Based on what I have seen so far (again, simple scaffold), the properties for a given class are not immediately revealed. I don't see property accessors on the model classes. I do understand that this is because of the dynamic nature of Ruby and such things are not necessary or even perhaps desirable. Convention over code, I get that. (Am familiar with dynamic concepts, mostly via JS.) But if I am somewhere off in a view, and want to quickly know whether the (eg) Person object has a MiddleName property, how would I find that out? I don't have to go into the migrations, do I?

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  • OpenGL quake 3 shader file for objects (for trees)

    - by mlodziaszka
    I decided to add to my game few trees, I already quake 3 model loader (md3) its for characters and method for texture drawing is store in *.ini file. I found a package of trees in MD3 and I have no problem with loading model alone, but there is a *.shader file and i have no idea how to load it to draw texture properly. Tree pack: http://www.custommapmakers.org/wiki/index.php/Models:GR_Trees_set I do not have to use exactly this format, I can write another loader, but trees in *.obj or .3ds look even harder

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  • QotD: Eben Upton on Raspberry Pi Model B Shipping With 512MB of RAM

    - by $utils.escapeXML($entry.author)
    One of the most common suggestions we’ve heard since launch is that we should produce a more expensive “Model C” version of Raspberry Pi with extra RAM. This would be useful for people who want to use the Pi as a general-purpose computer, with multiple large applications running concurrently, and would enable some interesting embedded use cases (particularly using Java) which are slightly too heavyweight to fit comfortably in 256MB.The downside of this suggestion for us is that we’re very attached to $35 as our highest price point. With this in mind, we’re pleased to announce that from today all Model B Raspberry Pis will ship with 512MB of RAM as standard.Eben Upton, a founder and trustee of the Raspberry Pi foundation, in a blog post announcing the change.

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  • XNA stopped compiling my model x files

    - by HuseyinUslu
    So I've a 3d game project I'm working on and I'm using 2 model files (SkyBlock.x and AimedBlock.x). So until now everything was all good and my models files were compiled all okay and I was able to use them within my game. With the latest changes (which I don't know what caused it really) - XNA stopped compiling my model files and instead only outputs files; AimedBlockxnb - 1kb SkyDome.xnb - 1kb SkyDomeTexture.xnb - 1389 kb SkyDomeTexture_0.xnb - 419 kb So I created a test XNA game project and moved all my asset's to new solution content project's and tried compiling them and saw that they're all good. AimedBlockxnb - 2kb SkyDome.xnb - 13kb SkyDomeTexture.xnb - 4097 kb SkyDomeTexture_0.xnb - 683 kb So I guess my main project sucks there but I couldn't came with a solution. I even tried overwriting my game's content project with new game's content project (which was all okay) but it didn't work. Anybody had similar issues?

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  • Model Based Apps and Frameworks

    Having been involved (mostly as a user or observer) with several recent applications and frameworks, Ive come to the conclusion that building your app/framework on an internal model is generally the best way to go.  In this post Ill explain what I mean by on an internal model and later describe the benefits I have seen, realized, been told about by others and still others that Ive only imagined (but are still possible).  I plan on writing a few blog posts along these lines to explore what...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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  • Model Based Apps and Frameworks

    Having been involved (mostly as a user or observer) with several recent applications and frameworks, Ive come to the conclusion that building your app/framework on an internal model is generally the best way to go.  In this post Ill explain what I mean by on an internal model and later describe the benefits I have seen, realized, been told about by others and still others that Ive only imagined (but are still possible).  I plan on writing a few blog posts along these lines to explore what...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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  • Problem with core data migration mapping model

    - by dpratt
    I have an iphone app that uses Core Data to do storage. I have successfully deployed it, and now I'm working on the second version. I've run into a problem with the data model that will require a few very simple data transformations at the time that the persistent store gets upgraded, so I can't just use the default inferred mapping model. My object model is stored in an .xcdatamodeld bundle, with versions 1.0 and 1.1 next to each other. Version 1.1 is set as the active version. Everything works fine when I use the default migration behavior and set NSInferMappingModelAutomaticallyOption to YES. My sqlite storage gets upgraded from the 1.0 version of the model, and everything is good except for, of course, the few transformations I need done. As an additional experimental step, I added a new Mapping Model to the core data model bundle, and have made no changes to what xcode generated. When I run my app (with an older version of the data store), I get the following * Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: 'Object's persistent store is not reachable from this NSManagedObjectContext's coordinator' What am I doing wrong? Here's my code for to get the managed object model and the persistent store coordinator. - (NSPersistentStoreCoordinator *)persistentStoreCoordinator { if (_persistentStoreCoordinator != nil) { return _persistentStoreCoordinator; } _persistentStoreCoordinator = [[NSPersistentStoreCoordinator alloc] initWithManagedObjectModel:[self managedObjectModel]]; NSURL *storeUrl = [NSURL fileURLWithPath: [[self applicationDocumentsDirectory] stringByAppendingPathComponent: @"gti_store.sqlite"]]; NSError *error; NSDictionary *options = [NSDictionary dictionaryWithObjectsAndKeys: [NSNumber numberWithBool:YES], NSMigratePersistentStoresAutomaticallyOption, [NSNumber numberWithBool:YES], NSInferMappingModelAutomaticallyOption, nil]; if (![_persistentStoreCoordinator addPersistentStoreWithType:NSSQLiteStoreType configuration:nil URL:storeUrl options:options error:&error]) { NSLog(@"Eror creating persistent store coodinator - %@", [error localizedDescription]); } return _persistentStoreCoordinator; } - (NSManagedObjectModel *)managedObjectModel { if(_managedObjectModel == nil) { _managedObjectModel = [[NSManagedObjectModel mergedModelFromBundles:nil] retain]; NSDictionary *entities = [_managedObjectModel entitiesByName]; //add a sort descriptor to the 'Foo' fetched property so that it can have an ordering - you can't add these from the graphical core data modeler NSEntityDescription *entity = [entities objectForKey:@"Foo"]; NSFetchedPropertyDescription *fetchedProp = [[entity propertiesByName] objectForKey:@"orderedBar"]; NSSortDescriptor* sortDescriptor = [[[NSSortDescriptor alloc] initWithKey:@"index" ascending:YES] autorelease]; NSArray* sortDescriptors = [NSArray arrayWithObjects:sortDescriptor, nil]; [[fetchedProp fetchRequest] setSortDescriptors:sortDescriptors]; } return _managedObjectModel; }

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  • what is this 'content_type' mean..

    - by zjm1126
    content_type = ContentType.objects.get_for_model(Map) maps = maps.extra(select=SortedDict([ ('member_count', MEMBER_COUNT_SQL), ('topic_count', TOPIC_COUNT_SQL), ]), select_params=(content_type.id,)) and the ContentType is: class ContentType(models.Model): name = models.CharField(max_length=100) app_label = models.CharField(max_length=100) model = models.CharField(_('python model class name'), max_length=100) objects = ContentTypeManager() class Meta: verbose_name = _('content type') verbose_name_plural = _('content types') db_table = 'django_content_type' ordering = ('name',) unique_together = (('app_label', 'model'),) def __unicode__(self): return self.name def model_class(self): "Returns the Python model class for this type of content." from django.db import models return models.get_model(self.app_label, self.model) def get_object_for_this_type(self, **kwargs): """ Returns an object of this type for the keyword arguments given. Basically, this is a proxy around this object_type's get_object() model method. The ObjectNotExist exception, if thrown, will not be caught, so code that calls this method should catch it. """ return self.model_class()._default_manager.using(self._state.db).get(**kwargs) def natural_key(self): return (self.app_label, self.model) i want to know: what is the 'content_type' used for ??

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  • In MVC framworks (such as Ruby on Rails), do usually Model spell as singular and controller and view

    - by Jian Lin
    I usually see Ruby on Rails books using script/generate model Story name:string link:string which is a singular Story, while when it is controller script/generate controller Stories index then the Story now is Stories, which is plural. Is this a standard on Ruby on Rails? Is it true in other MVC frameworks too, like CakePHP, Symfony, Django, or TurboGears? I see that in the book Rails Space, the controller is also called User, which is the same as the model name, and it is the only exception I see.

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  • Doctrine 1.2: Can a model have two instances of the sluggabl behavior?

    - by prodigitalson
    I dont see any direct mention on using multiple slugs (or any behavior for that matter) for single model. Is there a way to use the sluggable behavior to generate two separate slugs for a model? For example i need to generate two slugs for every record a product_id consisting of a slugified company name and sku and a distributor_id consisting of a different slugified company name. Obviously i could write this myself fairly easily, im just wondering if this can be done quickly with Sluggable.

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  • Why the only hidden field that is being filled from GET action is not being passed in model?

    - by user1807954
    Sorry for the long title, I didn't know how to make it any shorter. My code: My model: public class CarFilter { public String carMake { get; set; } public String carModel { get; set; } public String carEdition { get; set; } . . . public String SortBy { get; set; } } public class CarSearch : CarFilter { public List<Car> Car { get; set; } } My controller: public ActionResult SearchResult(CarSearch search) { var cars = from d in db.Cars select d; if (Request.HttpMethod == "POST") { search.SortBy = "Price"; } search.Car = new List<Car>(); search.Car.AddRange(cars); var temp = new List<CarSearch>(); temp.Add(search); return View(temp); } My Index view (where user filters results): @model IEnumerable<Cars.Models.CarSearch> @using (Html.BeginForm("SearchResult", "Home", FormMethod.Post)){..forms and other stuff..} My SearchResult view (where user sees the results of filtration): @model IEnumerable<Cars.Models.CarSearch> @using (Html.BeginForm("SearchResult", "Home", FormMethod.Get)) { @Html.Hidden("carMake") @Html.Hidden("carModel") @Html.Hidden("carEdition") . . . @Html.Hidden("SortBy", temp.SortBy) <input name="SortBy" class="buttons" type="submit" value="Make"/> My goal What I'm trying to do is when user clicked on sort by Make it will have to GET back all the variables in hidden field back to the SearchResult action in order to sort the result (same filtered results). Result Is: <input id="SortBy" name="SortBy" type="hidden" value=""/>. The value is null and it's not being passed but all the other hidden fields such as carMake and etc have value. But when I use foreach it works perfect. Question Why is this like this? the SortBy is in the same model class as other fields in the view. The only difference is that SortBy is not being filled in the Index view with other fields, instead it's being filled in controller action. What is the explanation for this? Am I missing any C# definition or something such as dynamic objects or something?

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  • how to get all 'username' from my model 'MyUser' on google-app-engine ..

    - by zjm1126
    my model is : class MyUser(db.Model): user = db.UserProperty() password = db.StringProperty(default=UNUSABLE_PASSWORD) email = db.StringProperty() nickname = db.StringProperty(indexed=False) and my method which want to get all username is : s=[] a=MyUser.all().fetch(10000) for i in a: s.append(i.username) and the error is : AttributeError: 'MyUser' object has no attribute 'username' so how can i get all 'username', which is the simplest way . thanks

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  • How do I make an object a property of a model in Ruby on Rails?

    - by iTake
    I have this in my schema: create_table "robots_matches", :force => true do |t| t.integer "robot_id" t.integer "match_id" and I think I want to be able to load a robot and match from within my robots_match model so I can do something like this: robots_match.find(:id).get_robot().Name My attempt in the robots_matches model was this: def get_robot Robot.find(this.id) end I am super new to rails, so feel free to correct my architectural decision here.

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  • How can I prevent seams from showing up on objects using lower mipmap levels?

    - by Shivan Dragon
    Disclaimer: kindly right click on the images and open them separately so that they're at full size, as there are fine details which don't show up otherwise. Thank you. I made a simple Blender model, it's a cylinder with the top cap removed: I've exported the UVs: Then imported them into Photoshop, and painted the inner area in yellow and the outer area in red. I made sure I cover well the UV lines: I then save the image and load it as texture on the model in Blender. Actually, I just reload it as the image where the UVs are exported, and change the viewport view mode to textured. When I look at the mesh up-close, there's yellow everywhere, everything seems fine: However, if I start zooming out, I start seeing red (literally and metaphorically) where the texture edges are: And the more I zoom, the more I see it: Same thing happends in Unity, though the effect seems less pronounced. Up close is fine and yellow: Zoom out and you see red at the seams: Now, obviously, for this simple example a workaround is to spread the yellow well outside the UV margins, and its fine from all distances. However this is an issue when you try making a complex texture that should tile seamlessly at the edges. In this situation I either make a few lines of pixels overlap (in which case it looks bad from upclose and ok from far away), or I leave them seamless and then I have those seams when seeing it from far away. So my question is, is there something I'm missing, or some extra thing I must do to have my texture look seamless from all distances?

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  • MVC: model of type Nullable<T>

    - by Fyodor Soikin
    I have a partial view that inherits from ViewUserControl<Guid?> - i.e. it's model is of type Nullable<Guid>. Very simple view, nothing special, but that's not the point. Somewhere else, I do Html.RenderPartial( "MyView", someGuid ), where someGuid is of type Nullable<Guid>. Everything's perfectly legal, should work OK, right? But here's the gotcha: the second argument of Html.RenderPartial is of type object, and therefore, Nullable<Guid> being a value type, it must be boxed. But nullable types are somehow special in the CLR, so that when you box one of those, you actually get either a boxed value of type T (Nullable's argument), or a null if the nullable didn't have a value to begin with. And that last case is actually interesting. Turns out, sometimes, I do have a situation when someGuid.HasValue == false. And in those cases, I effectively get a call Html.RenderPartial( "MyView", null ). And what does the HtmlHelper do when the model is null? Believe it or not, it just goes ahead and takes the parent view's model. Regardless of it's type. So, naturally, in those cases, I get an exception saying: "The model item passed into the dictionary is of type 'Parent.View.Model.Type', but this dictionary requires a model item of type 'System.Guid?'" So the question is: how do I make MVC correctly pass new Nullable<Guid> { HasValue = false } instead of trying to grab the parent's model? Note: I did consider wrapping my Guid? in an object of another type, specifically created for this occasion, but this seems completely ridiculous. Don't want to do that as long as there's another way. Note 2: now that I've wrote all this, I've realized that the question may be reduced to how to pass a null for model without ending up with parent's model?

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  • rails Creating a model instance automatically when another is created

    - by bob
    Hello I have a user model and a ratings model. Whenever a new user is created I want to create a new feedback model with it automatically. Each user model has one feedback model and each feedback model has many ratings. My Classes class User < ActiveRecord::Base end class Feedback < ActiveRecord::Base belongs_to :user has_many :ratings end class Rating < ActiveRecord::Base belongs_to :feedback end My database tables -user doesn't have anything special -feedback has user_id. This user_id should be the same as the user that has just been created. For example, user_id of 1 is created, then a feedback model should be created that belongs to user_id of 1. So the user_id column in the feedback database will also be 1. - Rating has a feedback_id and a user_id the user_id in this case is the id of the person who submitted the rating. I am having it assigned through the build command. I believe my process is correct here. The Goal The goal is to have each user have a feedback table that has many ratings from other users. So if someone goes to the feedback page, they will see all the ratings given and by who. Is there a better way to approach this? How do you create a model of feedback with the same id as the user being created right when a new user is created. The idea is that when a user is created a feedback is created associated with that user so people can then go to http://localhost:3000/users/1/feedback/ and submit new ratings. I'm trying to bypass having a user rate another user with just a ratings model because I'm not sure how to do it.

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