Search Results

Search found 23387 results on 936 pages for 'ruby mysql'.

Page 30/936 | < Previous Page | 26 27 28 29 30 31 32 33 34 35 36 37  | Next Page >

  • Ruby Nokogiri uninitialized constant

    - by donald
    `<main>': uninitialized constant Object::Nakogiri (NameError) I get that message when trying to run a simple code (ruby test.rb): require 'rubygems' require 'nokogiri' require 'open-uri' url = "http://www.walmart.com/cp/Baby-Days/1035659?povid=cat14503-env172199-module122910-lLinksptBABY" doc = Nakogiri::HTML(open(url)) puts doc.at_css("title").text I have the gem installed: ~/Code $ gem list --local | grep nokogiri nokogiri (1.4.4, 1.4.3.1)

    Read the article

  • accessing Ruby variable(from model or controller) in SASS

    - by corroded
    Is there a way to access ruby variables in sass or do i have to make a custom function for it? What im trying to do is to generate a stylesheet for each user so in the controller, i do something like: def show respond_to do |format| format.css{render :partial => "styles"} end end then in the view name _styles.haml i do this: :sass #header :background url(user.banner.url) is this possible at all?

    Read the article

  • numerical computation locks up ruby

    - by kolosy
    i'm trying to implement an id obfuscation scheme, with a simple hash borrowed elsewhere. i've added a method on the application helper: @@M_ID = 2**31-1 @@PRIME = 1580030173 @@PRIME_INVERSE = 59260789 # (calculated from MAXID and PRIME offline) def obfuscate_id(x) if x return ((x * @@PRIME) & @@M_ID) else x end end for some reason, whenever this is called, ruby locks up, and starts eating up disk space on my mac... like - gigs of it. any ideas?

    Read the article

  • Stop duplicates from being added to an array of Ruby objects

    - by Dom
    how can I eliminate duplicate elements from an array of ruby objects using an attribute of the object to match identical objects. with an array of basic types I can use a set.. eg. array_list = [1, 3, 4 5, 6, 6] array_list.to_set => [1, 2, 3, 4, 5, 6] can I adapt this technique to work with object attributes? thanks

    Read the article

  • Login to a Remote Service (ruby based) from iPhone

    - by Chris Maness
    Ok here's my problem in a nutshell I've built a web service from ruby on rails. I'm using restful_authentication to create and run the login but I'm also building an iPhone application to access my web service but I can't quite figure it out. I was wondering if anyone could help me figure out a place to begin.

    Read the article

  • Support for IMAP IDLE in ruby

    - by Asaxena
    Ok, I have been suck on it for hours. I thought net/imap.rb with ruby 1.9 supported the idle command, but not yet. Can anyone help me in implementing that? From here, I though this would work: class Net::IMAP def idle cmd = "IDLE" synchronize do tag = generate_tag put_string(tag + " " + cmd) put_string(CRLF) end end def done cmd = "DONE" synchronize do put_string(cmd) put_string(CRLF) end end end But imap.idle with that just return nil.

    Read the article

  • Compare two times without regard to Date associated - Ruby

    - by H55nick
    I am trying to find the difference in time (without days/years/months) of two different days. Example: #ruby >1.9 time1 = Time.now - 1.day time2 = Time.now #code to make changes #test: time1 == time2 # TRUE My solution: time1 = time1.strftime("%h:%m").to_time time2 = time2.strftime("%h:%m").to_time #test time1 == time2 #True #passes I was wondering if there was a better way of doing this? Maybe we could keep the Date the same as time1/time2?

    Read the article

  • How do I print an array in Rails?

    - by Abid Hussain
    I am new to Rails and I am using Ruby version 1.9.3 and Rails version 3.0.0. I want to print an array in Rails. How do I do that? For example, we have to use print_r to print an array in PHP: <?php $a = array ('a' => 'apple', 'b' => 'banana', 'c' => array ('x', 'y', 'z')); print_r ($a); ?> Output: <pre> Array ( [a] => apple [b] => banana [c] => Array ( [0] => x [1] => y [2] => z ) ) </pre> How do I print an array in Rails?

    Read the article

  • Routing Users to single Models with Rails

    - by Eric Koslow
    I'm creating a Rails app for students and high schools and I'm having some trouble with my User.rb. I want to have a user model to be used for logging in, but having that user have many roles. The tricky part is that I want users that have a student role to have_one student page, and those that have a role of principal to have_one high_school page. The students and also nested in the high_school so the entire thing becomes a big mess. So my question(s): How do I limit a user to only creating one student / high school to represent them? Also how would I nest this student pages inside the highschool without screwing up the user system? My environment: Rails3 and Ruby 1.9.2dev Thank you!

    Read the article

  • Cannot connect to MySQL with JDBC - Connection Timeout - Ubuntu 9.04

    - by gav
    I am running Ubuntu and am ultimately trying to connect Tomcat to my MySQL database using JDBC. It has worked previously but after a reboot the instance now fails to connect. Both Tomcat 6 and MySQL 5.0.75 are on the same machine Connection string: jdbc:mysql:///localhost:3306 I can connect to MySQL on the command line using the mysql command The my.cnf file is pretty standard (Available on request) has bind address: 127.0.0.1 I cannot Telnet to the MySQL port despite netstat saying MySQL is listening I have one IpTables rule to forward 80 - 8080 and no firewall I'm aware of. I'm pretty new to this and I'm not sure what else to test. I don't know whether I should be looking in etc/interfaces and if I did what to look for. It's weird because it used to work but after a reboot it's down so I must have changed something.... :). I realise a timeout indicates the server is not responding and I assume it's because the request isn't actually getting through. I installed MySQL via apt-get and Tomcat manually. MySqld processes root@88:/var/log/mysql# ps -ef | grep mysqld root 21753 1 0 May27 ? 00:00:00 /bin/sh /usr/bin/mysqld_safe mysql 21792 21753 0 May27 ? 00:00:00 /usr/sbin/mysqld --basedir=/usr --datadir=/var/lib/mysql --user=mysql --pid-file=/var/run/mysqld/mysqld.pid --skip-external-locking --port=3306 --socket=/var/run/mysqld/mysqld.sock root 21793 21753 0 May27 ? 00:00:00 logger -p daemon.err -t mysqld_safe -i -t mysqld root 21888 13676 0 11:23 pts/1 00:00:00 grep mysqld Netstat root@88:/var/log/mysql# netstat -lnp | grep mysql tcp 0 0 0.0.0.0:3306 0.0.0.0:* LISTEN 21792/mysqld unix 2 [ ACC ] STREAM LISTENING 1926205077 21792/mysqld /var/run/mysqld/mysqld.sock Toy Connection Class root@88:~# cat TestConnect/TestConnection.java import java.sql.Connection; import java.sql.DriverManager; import java.sql.SQLException; public class TestConnection { public static void main(String args[]) throws Exception { Connection con = null; try { Class.forName("com.mysql.jdbc.Driver").newInstance(); System.out.println("Got driver"); con = DriverManager.getConnection( "jdbc:mysql:///localhost:3306", "uname", "pass"); System.out.println("Got connection"); if(!con.isClosed()) System.out.println("Successfully connected to " + "MySQL server using TCP/IP..."); } finally { if(con != null) con.close(); } } } Toy Connection Class Output Note: This is the same error I get from Tomcat. root@88:~/TestConnect# java -cp mysql-connector-java-5.1.12-bin.jar:. TestConnection Got driver Exception in thread "main" com.mysql.jdbc.exceptions.jdbc4.CommunicationsException: Communications link failure The last packet sent successfully to the server was 1 milliseconds ago. The driver has not received any packets from the server. at sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method) at sun.reflect.NativeConstructorAccessorImpl.newInstance(NativeConstructorAccessorImpl.java:39) at sun.reflect.DelegatingConstructorAccessorImpl.newInstance(DelegatingConstructorAccessorImpl.java:27) at java.lang.reflect.Constructor.newInstance(Constructor.java:513) at com.mysql.jdbc.Util.handleNewInstance(Util.java:409) at com.mysql.jdbc.SQLError.createCommunicationsException(SQLError.java:1122) at TestConnection.main(TestConnection.java:14) Caused by: com.mysql.jdbc.exceptions.jdbc4.CommunicationsException: Communications link failure The last packet sent successfully to the server was 0 milliseconds ago. The driver has not received any packets from the server. at sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method) at sun.reflect.NativeConstructorAccessorImpl.newInstance(NativeConstructorAccessorImpl.java:39) at sun.reflect.DelegatingConstructorAccessorImpl.newInstance(DelegatingConstructorAccessorImpl.java:27) at java.lang.reflect.Constructor.newInstance(Constructor.java:513) at com.mysql.jdbc.Util.handleNewInstance(Util.java:409) at com.mysql.jdbc.SQLError.createCommunicationsException(SQLError.java:1122) at com.mysql.jdbc.MysqlIO.<init>(MysqlIO.java:344) at com.mysql.jdbc.ConnectionImpl.createNewIO(ConnectionImpl.java:2181) ... 12 more Caused by: java.net.ConnectException: Connection timed out at java.net.PlainSocketImpl.socketConnect(Native Method) ... 13 more Telnet Output root@88:~/TestConnect# telnet localhost 3306 Trying 127.0.0.1... telnet: Unable to connect to remote host: Connection timed out

    Read the article

  • Headless gem: webkit_server: cannot connect to X server

    - by 23tux
    I've got some problems running capybara-webkit with the Headless gem, Xvfb and our ci server. We use this setup for automatic integration testing and javascript testing of our Ruby on Rails 3.2 app. During the tests it complains that webkit_server: cannot connect to X server But when I ps aux | grep Xvfb deploy 1602 0.0 0.1 61696 1912 pts/2 S+ Jul10 0:00 /usr/bin/Xvfb :99 -screen 0 1280x1024x24 -ac I see the Xvfb running. If I run the tests with --trace it also only shows the error log above and I can't debug the error. Any ideas how I could get some more information, or even a solution?

    Read the article

  • Rails 3.0/3.2: Called id for nil, which would mistakenly be 4 -- if you really wanted the id of nil, use object_id

    - by Nick5a1
    I'm following the Kevin Skoglund tutorial Ruby on Rails 3 Essential Training, which was written for rails 3.0, though I am currently using 3.2. It uses the following method in the pages_controller with a before_filter to display only the pages which belong to the parent subject. The tutorial explicitly uses .find_by_id because if the result is nil it "will not return an error". However I get the "Called id for nil, which would mistakenly be 4 -- if you really wanted the id of nil, use object_id" error when trying to view a page where @subject has been set to nil. def find_subject if params[:subject_id] @subject = Subject.find_by_id(params[:subject_id]) end end The actual code that is causing the error is: def list @pages = Page.order("pages.position ASC").where(:subject_id => @subject.id) end Is this something that has changed since 3.0? If so, what would be the correct way to implement this functionality in 3.2?

    Read the article

  • Build custom error messages in model files (example: using the 'pluralize' method)

    - by user502052
    I am using Ruby on Rails 3.0.7 and I would like to use the pluralize method in a my model file in order to properly build custom error messages. For example, I would like to do something like the following: NAME_MIN_LENGHT = 2 # Is 2 but I plan to change that (maybe dynamically... if it is possible) in future development validates :name, :length => { :minimum => NAME_MIN_LENGHT, :too_short => "is too short (minimum is #{pluralize(NAME_MIN_LENGHT, "character")})", }, How can I do that? Is it advisable? Why?

    Read the article

  • Rendering another Action without changing URL?

    - by Michael Stum
    I have this code in my Rails 3 controller: def index now = Time.now.utc.strftime("%m%d") redirect_to :action => "show", :id => now end def show begin @date = Time.parse("12#{params[:id]}") dbdate = params[:id] rescue ArgumentError @date = Time.now.utc dbdate = @date.strftime("%m%d") end @date = @date.strftime("%B %d") @events = Event.events_for_date(dbdate) end So basically index is just a specialized version of show, hence I want it to execute show, render the show.html.erb view - but I do not want to change the URL like redirect_to does. I have tried this approach: def index now = Time.now.utc.strftime("%m%d") params[:id] = now show render :action => "show" end Now, this works, but it just smells badly. I'm new to Ruby and Rails, so I just wonder if there is something fundamentally wrong or if there is a better way to do this?

    Read the article

  • Rake migration aborted

    - by user2537714
    I'm running Ruby 2.0.0 and I installed it correctly. Just loaded up a gem 'devise' and as I tried to migrate my database changes, it wouldn't work: $ rake db:migrate rake aborted! attr_accessible is extracted out of Rails into a gem. Please use new recommended protection model for params(strong_parameters) or add protected_attributes to your Gemfile to use old one. Then, following another Stackoverflow post, they recommended installing Bundler. I did that successfully and got this: $ bundle exec rake db:migrate rake aborted! attr_accessible is extracted out of Rails into a gem. Please use new recommended protection model for params(strong_parameters) or add protected_attributes to your Gemfile to use old one. Is anyone up to the challenge to help?

    Read the article

  • What is a valid and reasonable alternative to a massive storage approach?

    - by Backo
    I am using Ruby on Rails 3.2.2 and MySQL. After my previous question on "how to handle massive storage of records in database for user authorization purposes", since related answers (on how to solve the issue or how to accomplish to that I am looking for) aren't sufficiently detailed or require to much resources (at least for me), I would like to know what are valid and reasonable alternatives to that approach. In few words, this question could be phrase as: how to handle "complex" (at level of SQL querying) user authorizations when you have to fetch "authorized" records? That is, for example, how to retrieve records when you would use code like the following (the following code would be used mostly in index controller actions): Article.readable_by_user(@current_user) # => Returns all articles readable by the current user.

    Read the article

  • VB.net (aspx) mysql connection

    - by StealthRT
    Hey all i am new to ASP.NET and VB.net code behind. I have a classic ASP page that connects to the mySQL server with the following code: Set oConnection = Server.CreateObject("ADODB.Connection") Set oRecordset = Server.CreateObject("ADODB.Recordset") oConnection.Open "DRIVER={MySQL ODBC 3.51 Driver}; SERVER=xxx.com; PORT=3306; DATABASE=xxx; USER=xxx; PASSWORD=xxx; OPTION=3;" sqltemp = "select * from userinfo WHERE emailAddress = '" & theUN & "'" oRecordset.Open sqltemp, oConnection,3,3 if oRecordset.EOF then ... However, i am unable to find anything to connect to mySQL in ASP.NET (VB.NET). I have only found this peice of code that does not seem to work once it gets to the "Dim conn As New OdbcConnection(MyConString)" code: Dim MyConString As String = "DRIVER={MySQL ODBC 3.51 Driver};" & _ "SERVER=xxx.com;" & _ "DATABASE=xxx;" & _ "UID=xxx;" & _ "PASSWORD=xxx;" & _ "OPTION=3;" Dim conn As New OdbcConnection(MyConString) MyConnection.Open() Dim MyCommand As New OdbcCommand MyCommand.Connection = MyConnection MyCommand.CommandText = "select * from userinfo WHERE emailAddress = '" & theUN & "'"" MyCommand.ExecuteNonQuery() MyConnection.Close() I have these import statements also: <%@ Import Namespace=System %> <%@ Import Namespace=System.IO %> <%@ Import Namespace=System.Web %> <%@ Import Namespace=System.ServiceProcess %> <%@ Import Namespace=Microsoft.Data.Odbc %> <%@ Import Namespace=MySql.Data.MySqlClient %> <%@ Import Namespace=MySql.Data %> <%@ Import Namespace=System.Data %> So any help would be great! :o) David

    Read the article

  • MySQL: order by and limit gives wrong result

    - by Larry K
    MySQL ver 5.1.26 I'm getting the wrong result with a select that has where, order by and limit clauses. It's only a problem when the order by uses the id column. I saw the MySQL manual for LIMIT Optimization My guess from reading the manual is that there is some problem with the index on the primary key, id. But I don't know where I should go from here... Question: what should I do to best solve the problem? Works correctly: mysql> SELECT id, created_at FROM billing_invoices WHERE (billing_invoices.account_id = 5) ORDER BY id DESC ; +------+---------------------+ | id | created_at | +------+---------------------+ | 1336 | 2010-05-14 08:05:25 | | 1334 | 2010-05-06 08:05:25 | | 1331 | 2010-05-05 23:18:11 | +------+---------------------+ 3 rows in set (0.00 sec) WRONG result when limit added! Should be the first row, id - 1336 mysql> SELECT id, created_at FROM billing_invoices WHERE (billing_invoices.account_id = 5) ORDER BY id DESC limit 1; +------+---------------------+ | id | created_at | +------+---------------------+ | 1331 | 2010-05-05 23:18:11 | +------+---------------------+ 1 row in set (0.00 sec) Works correctly: mysql> SELECT id, created_at FROM billing_invoices WHERE (billing_invoices.account_id = 5) ORDER BY created_at DESC ; +------+---------------------+ | id | created_at | +------+---------------------+ | 1336 | 2010-05-14 08:05:25 | | 1334 | 2010-05-06 08:05:25 | | 1331 | 2010-05-05 23:18:11 | +------+---------------------+ 3 rows in set (0.01 sec) Works correctly with limit: mysql> SELECT id, created_at FROM billing_invoices WHERE (billing_invoices.account_id = 5) ORDER BY created_at DESC limit 1; +------+---------------------+ | id | created_at | +------+---------------------+ | 1336 | 2010-05-14 08:05:25 | +------+---------------------+ 1 row in set (0.01 sec) Additional info: explain SELECT id, created_at FROM billing_invoices WHERE (billing_invoices.account_id = 5) ORDER BY id DESC limit 1; +----+-------------+------------------+-------+--------------------------------------+--------------------------------------+---------+------+------+-------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +----+-------------+------------------+-------+--------------------------------------+--------------------------------------+---------+------+------+-------------+ | 1 | SIMPLE | billing_invoices | range | index_billing_invoices_on_account_id | index_billing_invoices_on_account_id | 4 | NULL | 3 | Using where | +----+-------------+------------------+-------+--------------------------------------+--------------------------------------+---------+------+------+-------------+

    Read the article

  • Getting Perl DBD::mysql working on OS X 10.7?

    - by Bart B
    I can't seem to get Perl & MySQL to talk to each other on OS X 10.7 Lion. I did all the installs by the book, I used Oracle's PKG installer for the latest MySQL Community Server, and I installed DBI and DBD::mysql via CPAN. There were not problems at all during the install, but, when I try to USE DBD::mysql to connect to my local DB server I get the following error: install_driver(mysql) failed: Can't load '/Library/Perl/5.12/darwin-thread-multi-2level/auto/DBD/mysql/mysql.bundle' for module DBD::mysql: dlopen(/Library/Perl/5.12/darwin-thread-multi-2level/auto/DBD/mysql/mysql.bundle, 1): Library not loaded: /usr/local/mysql/lib/libmysqlclient.16.dylib Referenced from: /Library/Perl/5.12/darwin-thread-multi-2level/auto/DBD/mysql/mysql.bundle Reason: image not found at /System/Library/Perl/5.12/darwin-thread-multi-2level/DynaLoader.pm line 204. at (eval 3) line 3 Compilation failed in require at (eval 3) line 3. Perhaps a required shared library or dll isn't installed where expected After a lot of googling all I could find were suggested hacks, so I gave this one a go: http://arkoftech.wordpress.com/2011/02/10/fixing-dbdmysql-for-mysql-5-5-89-under-macos-10-6-x/ I had to update some of the paths in the instructions since on Lion it's Perl 5.12 not 5.10. After doing that I got a new error: dyld: lazy symbol binding failed: Symbol not found: _mysql_init Referenced from: /Library/Perl/5.12/darwin-thread-multi-2level/auto/DBD/mysql/mysql.bundle Expected in: flat namespace dyld: Symbol not found: _mysql_init Referenced from: /Library/Perl/5.12/darwin-thread-multi-2level/auto/DBD/mysql/mysql.bundle Expected in: flat namespace Trace/BPT trap: 5 There must be a simple way to get MySQL & Perl working on OS X? - HELP!

    Read the article

  • Compiling Ruby on Mac OS X Snow Leopard

    - by gryzzly
    Hi, I am trying to follow this tutorial, on the subject of compiling ruby and rubygems on Snow Leopard: http://hivelogic.com/articles/compiling-ruby-rubygems-and-rails-on-snow-leopard I have added this to my ~/.profile: export PATH="/usr/local/bin:/usr/local/sbin:/usr/local/mysql/bin:$PATH" But if I write: echo $PATH I get: /opt/local/bin:/opt/local/sbin:/usr/bin:/bin:/usr/sbin:/sbin:/usr/local/bin:/usr/local/git/bin:/usr/X11/bin But in tutorial it says: You should see /usr/local/bin at the beginning of the line returned by the system. I have installed macports sometime ago and plenty of other software, perhaps it has changed the path. Anyway, I have tried to proceed with the installation, so I have built ruby, I did: ./configure --enable-shared --enable-pthread CFLAGS=-D_XOPEN_SOURCE=1 make sudo make install cd .. But when I do which ruby I get: /usr/bin/ruby And according to the tutorial that's wrong. Also if I do ruby -v I get the older version of ruby that was preinstalled on Snow Leopard and not the one I've compiled. Thanks.

    Read the article

  • Is it possible for beginner to learn and develop an application in rails in 4 months?

    - by Parth
    I want to develop a web application or a website using rails. My current knowledge includes 1. HTML 2. CSS 3. C 4. Java And I am currently going through 5th chapter of the well grounded rubyist book by David A. Thomas. I came to know that learning ruby is beneficial for good knowledge of rails. So currently I am going through the basics of ruby. And learning rails in parallel. I want to know if in this scenario is it practically feasible to understand rails and develop an application/website in it within the time frame of 4 months. I need to develop an application which have atleast 3 complexity (complex functionality). Any ideas of good application for rails beginners is welcomed. But the application should be large or if it is small than it should have some complexity. Time is a constraint for me. I would have to develop application for college work but rails technology is my choice as I want to learn it.

    Read the article

  • Using MongoDB with Ruby On Rails and the Mongomapper plugin

    - by Micke
    Hello, i am currently trying to learn Ruby On Rails as i am a long-time PHP developer so i am building my own community like page. I have came pritty far and have made the user models and suchs using MySQL. But then i heard of MongoDB and looked in to it a little bit more and i find it kinda nice. So i have set it up and i am using mongomapper for the connection between rails and MongoDB. And i am now using it for the News page on the site. I also have a profile page for every User which includes their own guestbook so other users can come to their profile and write a little message to them. My thought now is to change the User models from using MySQL to start using MongoDB. I can start by showing how the models for each User is set up. The user model: class User < ActiveRecord::Base has_one :guestbook, :class_name => "User::Guestbook" The Guestbook model model: class User::Guestbook < ActiveRecord::Base belongs_to :user has_many :posts, :class_name => "User::Guestbook::Posts", :foreign_key => "user_id" And then the Guestbook posts model: class User::Guestbook::Posts < ActiveRecord::Base belongs_to :guestbook, :class_name => "User::Guestbook" I have divided it like this for my own convenience but now when i am going to try to migrate to MongoDB i dont know how to make the tables. I would like to have one table for each user and in that table a "column" for all the guestbook entries since MongoDB can have a EmbeddedDocument. I would like to do this so i just have one Table for each user and not like now when i have three tables just to be able to have a guestbook. So my thought is to have it like this: The user model: class User include MongoMapper::Document one :guestbook, :class_name => "User::Guestbook" The Guestbook model model: class User::Guestbook include MongoMapper::EmbeddedDocument belongs_to :user many :posts, :class_name => "User::Guestbook::Posts", :foreign_key => "user_id" And then the Guestbook posts model: class User::Guestbook::Posts include MongoMapper::EmbeddedDocument belongs_to :guestbook, :class_name => "User::Guestbook" But then i can think of one problem.. That when i just want to fetch the user information like a nickname and a birthdate then it will have to fetch all the users guestbook posts. And if each user has like a thousand posts in the guestbook it will get really much to fetch for the system. Or am i wrong? Do you think i should do it any other way? Thanks in advance and sorry if i am hard to understand but i am not so educated in the english language :)

    Read the article

  • mysql cmd promt import data.sql

    - by udhaya
    i wanna import sql using cmd prompt. first open windows cmd prompt, navigate to xampp/mysql/bin folder & run mysql this error occurs D:\Program Files\xampp\mysql\bin>mysql ERROR 1045 (28000): Access denied for user 'ODBC'@'localhost' (using password: N O) D:\Program Files\xampp\mysql\bin>mysql -u root -p -h localhost dev1base < dev1b ase.sql Enter password: D:\Program Files\xampp\mysql\bin> D:\Program Files\xampp\mysql\bin>mysql -u root Welcome to the MySQL monitor. Commands end with ; or \g. Your MySQL connection id is 104 Server version: 5.0.51a Source distribution Type 'help;' or '\h' for help. Type '\c' to clear the buffer. mysql> mysql> -h localhost dev1base < dev1base.sql -> -> -> ->

    Read the article

  • MySQL not releasing temp file descriptors

    - by Wakaru44
    Since a few days ago, we’ve been experiencing some serious problems with our MySQL installation: MySQL keeps opening temporal files (normal behaviour) but these files are never released. The consequence is that, eventually, the disk space is exhausted and we have to restart the service and clean up /tmp manually. Using lsof, we see something like this: mysqld 16866 mysql 5u REG 8,3 0 692 /tmp/ibyWJylQ (deleted) mysqld 16866 mysql 6u REG 8,3 0 707 /tmp/ibf5adsT (deleted) mysqld 16866 mysql 7u REG 8,3 0 728 /tmp/ibGjPRyW (deleted) mysqld 16866 mysql 8u REG 8,3 0 5678 /tmp/ibMQDLMZ (deleted) mysqld 16866 mysql 13u REG 8,3 0 5679 /tmp/ibQAnM42 (deleted) Maybe it's not related, but when we shutdown the server, the files are finally freed, and we can see the following warnings in the MySQL log: 121029 7:44:27 [Warning] /usr/local/mysql/bin/mysqld: Forcing close of thread 1333 user: 'xxx' 121029 7:44:27 [Warning] /usr/local/mysql/bin/mysqld: Forcing close of thread 1156 user: 'yyy' 121029 7:44:27 [Warning] /usr/local/mysql/bin/mysqld: Forcing close of thread 1151 user: 'zzz' where 'xxx', 'yyy' and 'zzz' are distinct mysql users (and the only 3 users with active connections to the database). We have a few theories: There is a problem in the OS, that keeps file handlers open. Could it be possible that the OS "delete" operation blocks the threads until shutdown? This may explain the warning at shutdown and the fact that files are finally deleted when the process dies. Until now, data sets were so small that temp files were relatively small and there was enough time to release the file handles without exhausting disk space. We are using Mysql 5.5 on a RHEL 6.2 with the default kernel.

    Read the article

< Previous Page | 26 27 28 29 30 31 32 33 34 35 36 37  | Next Page >