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  • How do I sort account names alphabetically in Thunderbird?

    - by Sri
    I just upgraded to Ubuntu 12.04 and Thunderbird 13.0.1. I had 2 accounts earlier in Thunderbird: [email protected] [email protected] I also had another account on SeaMonkey: [email protected] which I imported into Thunderbird. Now the account order I want is: [email protected] [email protected] [email protected] but it shows: [email protected] [email protected] [email protected] I couldn't find any option in Thunderbird to sort them as I want. I came across a 3rd party extension but I avoid using such extensions. Is there any other way this can be done?

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  • How can I disable the guest account on OSX Lion?

    - by Wezly
    I have 'disabled' the guest account on my macbook pro running Lion via System Preferences Users & Groups. However the guest account still seems to appear as an option to login at start up and when switching users. I have never used the guest account for anything, and I have tried a system restore but the guest user has returned as before. How can I get rid of it? Thanks. edit: I also just enabled and disabled the account again - but the guest option still appears at startup offering a safari only restart for a guest user.

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  • What is the difference between a "service account" and an "installed application"?

    - by TheBeatlemaniac
    To my understanding, the main difference is that a service account doesn't require a user to log in for authorization, while an installed application does. I am making an Android app (an "installed application"?) that offers an in-app subscription, and doesn't require the user to log in to an account (a "service account"?). To get a Client ID for the Google Play Developer API, I have to declare it as either an installed application or a service account, and am unsure which to go with.

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  • an error "has no member named"

    - by helloWorld
    I have this snippet of the code account.cpp #include "account.h" #include <iostream> #include <string> using namespace std; Account::Account(string firstName, string lastName, int id) : strFirstName(firstName), strLastName(lastName), nID(id) {} void Account::printAccount(){ cout << strFirstName; } account.h #include <string> using std::string; class Account{ private: string strLastName; //Client's last name string strFirstName; //Client's first name int nID; //Client's ID number int nLines; //Number of lines related to account double lastBill; public: Account(string firstName, string lastName, int id); void printAccount(); }; company.h #ifndef CELLULAR_COMPANY_H #define CELLULAR_COMPANY_H #include <string> #include <list> #include <iostream> #include "account.h" using namespace std; class Company { private: list<Account> listOfAccounts; public: void addAccount(string firstName, string lastName, int id) { Account newAccount(firstName, lastName, id); listOfAccounts.push_back(newAccount); } void printAccounts(){ for(list<Account>::iterator i = listOfAccounts.begin(); i != listOfAccounts.end(); ++i){ i.printAccount; //here bug } } }; #endif // CELLULAR_COMPANY_H main.cpp #include "cellularcompany.h" int main(){ Company newCompany; newCompany.addAccount("Pavel", "Nedved", 11111); newCompany.printAccounts(); return 0; } can somebody please explain what does my error mean? thanks in advance (I have it in company.h see comment there) I have bug 'struct std::_List_iterator<Account>' has no member named 'printAccount'

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  • Spring security - Reach users ID without passing it through every controller

    - by nilsi
    I have a design issue that I don't know how to solve. I'm using Spring 3.2.4 and Spring security 3.1.4. I have a Account table in my database that looks like this: create table Account (id identity, username varchar unique, password varchar not null, firstName varchar not null, lastName varchar not null, university varchar not null, primary key (id)); Until recently my username was just only a username but I changed it to be the email address instead since many users want to login with that instead. I have a header that I include on all my pages which got a link to the users profile like this: <a href="/project/users/<%= request.getUserPrincipal().getName()%>" class="navbar-link"><strong><%= request.getUserPrincipal().getName()%></strong></a> The problem is that <%= request.getUserPrincipal().getName()%> returns the email now, I don't want to link the user's with thier emails. Instead I want to use the id every user have to link to the profile. How do I reach the users id's from every page? I have been thinking of two solutions but I'm not sure: Change the principal to contain the id as well, don't know how to do this and having problem finding good information on the topic. Add a model attribute to all my controllers that contain the whole user but this would be really ugly, like this. Account account = entityManager.find(Account.class, email); model.addAttribute("account", account); There are more way's as well and I have no clue which one is to prefer. I hope it's clear enough and thank you for any help on this. ====== Edit according to answer ======= I edited Account to implement UserDetails, it now looks like this (will fix the auto generated stuff later): @Entity @Table(name="Account") public class Account implements UserDetails { @Id private int id; private String username; private String password; private String firstName; private String lastName; @ManyToOne private University university; public Account() { } public Account(String username, String password, String firstName, String lastName, University university) { this.username = username; this.password = password; this.firstName = firstName; this.lastName = lastName; this.university = university; } public String getUsername() { return username; } public String getPassword() { return password; } public String getFirstName() { return firstName; } public String getLastName() { return lastName; } public void setUsername(String username) { this.username = username; } public void setPassword(String password) { this.password = password; } public void setFirstName(String firstName) { this.firstName = firstName; } public void setLastName(String lastName) { this.lastName = lastName; } public University getUniversity() { return university; } public void setUniversity(University university) { this.university = university; } public int getId() { return id; } public void setId(int id) { this.id = id; } @Override public Collection<? extends GrantedAuthority> getAuthorities() { // TODO Auto-generated method stub return null; } @Override public boolean isAccountNonExpired() { // TODO Auto-generated method stub return false; } @Override public boolean isAccountNonLocked() { // TODO Auto-generated method stub return false; } @Override public boolean isCredentialsNonExpired() { // TODO Auto-generated method stub return false; } @Override public boolean isEnabled() { // TODO Auto-generated method stub return true; } } I also added <%@ taglib prefix="sec" uri="http://www.springframework.org/security/tags" %> To my jsp files and trying to reach the id by <sec:authentication property="principal.id" /> This gives me the following org.springframework.beans.NotReadablePropertyException: Invalid property 'principal.id' of bean class [org.springframework.security.authentication.UsernamePasswordAuthenticationToken]: Bean property 'principal.id' is not readable or has an invalid getter method: Does the return type of the getter match the parameter type of the setter? ====== Edit 2 according to answer ======= I based my application on spring social samples and I never had to change anything until now. This are the files I think are relevant, please tell me if theres something you need to see besides this. AccountRepository.java public interface AccountRepository { void createAccount(Account account) throws UsernameAlreadyInUseException; Account findAccountByUsername(String username); } JdbcAccountRepository.java @Repository public class JdbcAccountRepository implements AccountRepository { private final JdbcTemplate jdbcTemplate; private final PasswordEncoder passwordEncoder; @Inject public JdbcAccountRepository(JdbcTemplate jdbcTemplate, PasswordEncoder passwordEncoder) { this.jdbcTemplate = jdbcTemplate; this.passwordEncoder = passwordEncoder; } @Transactional public void createAccount(Account user) throws UsernameAlreadyInUseException { try { jdbcTemplate.update( "insert into Account (firstName, lastName, username, university, password) values (?, ?, ?, ?, ?)", user.getFirstName(), user.getLastName(), user.getUsername(), user.getUniversity(), passwordEncoder.encode(user.getPassword())); } catch (DuplicateKeyException e) { throw new UsernameAlreadyInUseException(user.getUsername()); } } public Account findAccountByUsername(String username) { return jdbcTemplate.queryForObject("select username, firstName, lastName, university from Account where username = ?", new RowMapper<Account>() { public Account mapRow(ResultSet rs, int rowNum) throws SQLException { return new Account(rs.getString("username"), null, rs.getString("firstName"), rs.getString("lastName"), new University("test")); } }, username); } } security.xml <?xml version="1.0" encoding="UTF-8"?> <beans:beans xmlns="http://www.springframework.org/schema/security" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:beans="http://www.springframework.org/schema/beans" xsi:schemaLocation="http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.1.xsd http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.1.xsd"> <http pattern="/resources/**" security="none" /> <http pattern="/project/" security="none" /> <http use-expressions="true"> <!-- Authentication policy --> <form-login login-page="/signin" login-processing-url="/signin/authenticate" authentication-failure-url="/signin?error=bad_credentials" /> <logout logout-url="/signout" delete-cookies="JSESSIONID" /> <intercept-url pattern="/addcourse" access="isAuthenticated()" /> <intercept-url pattern="/courses/**/**/edit" access="isAuthenticated()" /> <intercept-url pattern="/users/**/edit" access="isAuthenticated()" /> </http> <authentication-manager alias="authenticationManager"> <authentication-provider> <password-encoder ref="passwordEncoder" /> <jdbc-user-service data-source-ref="dataSource" users-by-username-query="select username, password, true from Account where username = ?" authorities-by-username-query="select username, 'ROLE_USER' from Account where username = ?"/> </authentication-provider> <authentication-provider> <user-service> <user name="admin" password="admin" authorities="ROLE_USER, ROLE_ADMIN" /> </user-service> </authentication-provider> </authentication-manager> </beans:beans> And this is my try of implementing a UserDetailsService public class RepositoryUserDetailsService implements UserDetailsService { private final AccountRepository accountRepository; @Autowired public RepositoryUserDetailsService(AccountRepository repository) { this.accountRepository = repository; } @Override public UserDetails loadUserByUsername(String username) throws UsernameNotFoundException { Account user = accountRepository.findAccountByUsername(username); if (user == null) { throw new UsernameNotFoundException("No user found with username: " + username); } return user; } } Still gives me the same error, do I need to add the UserDetailsService somewhere? This is starting to be something else compared to my initial question, I should maybe start another question. Sorry for my lack of experience in this. I have to read up.

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  • Django shows too many warnings when deleting an object

    - by valya
    Hello! I have two models: class Account(models.Model): main_request = models.ForeignKey('JournalistRequest', related_name='main_request') key = models.CharField(_('Key'), max_length=100) class JournalistRequest(models.Model): account = models.ForeignKey(Account, blank=True, null=True) When I try to delete a JournalistRequest, It shows warning with a lot of nesting, like Are you sure you want to delete the selected ?????? ??? objects? All of the following objects and their related items will be deleted: Journalist Request: some request Account: some account Journalist Request: some request Account: some account Journalist Request: some request Account: some account Journalist Request: some request Account: some account Journalist Request: some request All accounts are the same one (ids are same), and all requests are the same one, so I think it becaues of a recursion. But I have no idea how to solve this problem in Django 1.1.1! Can you help me?

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  • Factory Girl Association

    - by David Lyod
    I have an association of a Admin - Account in factory girl I now wish to associate a second user with the same account but am unable to do so. I build my Admin-Account association like this u.account { |account| account.association(:account)} This works fine and creates the Account and Admin association. Im looking for a way to setup a second user who's account also points to the record created in the Admin factory association. I currently just build the second user as such @user = Factory.build(:seconduser) @user.account = Account.first @user.save! Which works but seems somewhat hacky .

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  • What is the functionality of "sync contacts" in Exchange account in Email application?

    - by santhosh
    Hi i am testing android E-mail application . I have configured an Exchange account where in i could find an option "Sync Contacts from this account" in Account settings. According to my understanding if i check "sync contacts from the account" option , i must be able to access contacts in the exchange account i have configured. But i don't know how to get/access these contacts in android email application. Can any one who have used this functionality or know about it can suggest to me how to make use of "Sync contacts" functionality. Or if you have any idea about, how i can test this functionality, i am very eager to here to you. Kinds & Regards Santhosh Kumar H.E

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  • Why does bash sometimes think my $HOME isn't the correct directory?

    - by Adam Yanalunas
    Like the title says it seems that bash sometimes misidentifies my $HOME. This cropped up after a seemingly unique series of events that I will now replay in broad strokes. Running OS X 10.6 with normal, local account Work binds my account to Active Directory Much time passes with no issues Set up rvm to manage Ruby installs (this becomes important later) Upgraded to OS X 10.7 a few days ago After successful install, attempted to log in, was presented with "Must reset password" dialog that never allowed a password to be reset. Would simply shake the box after new password was entered. Much googling was done. Much more googling was done. Swearing was had. Logged in as root, created new account, set as admin, deleted /Users/[new account], renamed /Users/[old account] to /Users/[new account] Logged out of root, logged into new account with no issues After OS X asking for a my account password a few times to update Keychain and other system-level stuff it was back to business as usual. Opened Terminal, cd to project folder, tried "rails server" and was presented with: /usr/local/lib/ruby/1.9.1/rubygems/dependency.rb:247:in to_specs': Could not find rails (>= 0) amongst [] (Gem::LoadError) from /usr/local/lib/ruby/1.9.1/rubygems/dependency.rb:256:into_spec' from /usr/local/lib/ruby/1.9.1/rubygems.rb:1210:in gem' from /usr/local/bin/rails:18:in' Ran through a few exercises, decided to rm -rf ~/.rvm and reinstall. Running a --trace on the rvm installer shows it dies on this line: mkdir: /Users/[old account]: Permission denied Scrolling back through the --trace log I see many more mentions of /Users/[old account]. When inspect the install script the offending line is looking at "${HOME}/.rvm" as it tries to run the mkdir. To my confusion I also see mentions of /Users/[new account] in the log. I've tried exporting a new HOME in my .bash_profile to no luck. Can anyone guess why /Users/[old account] would still be kicking around?

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  • Security Issue in LinkedIn &ndash; View any 3rd profile without a premium account.

    - by Shaurya Anand
    Originally posted on: http://geekswithblogs.net/shauryaanand/archive/2013/06/25/153230.aspxI discovered this accidently when my wife forwarded a contact on LinkedIn from her tablet, using the mobile interface of the website. On opening the contact on my desktop, I was surprised to see, I need to upgrade my account to view the contact. Doing some research along with my wife, I found this simple security vulnerability from LinkedIn that can let anyone view a contact’s full profile even when you have a “not upgraded” LinkedIn account and that the contact is a “3rd + Everyone Else”. Here’s an example of what I am talking about. I just made a random search on LinkedIn for a contact whose name starts with Sacha. Do note, this is just a walkthrough and I am not publicizing any Sacha. I check the “3rd + Everyone Else” and find a “LinkedIn Member”. On clicking this person’s profile to view, I am presented with the following page, asking me to upgrade. Make a note of this page’s web address and you get the profile id from it. For example, for this contact, the page address is: http://www.linkedin.com/profile/view?id=868XXX35 The Profile Id for this contact is 868XXX35. Now, open following page where the Profile Id is the same as the one we grabbed a moment earlier. https://touch.www.linkedin.com/?#profile/868XXX35 The mobile page exposes this contact information and you even get the possibility to connect to this person without an introduction mail (InMail). I hope someone from LinkedIn sees and issues a fix for this. I am pretty sure, it’s something that they don’t want the user to do without purchasing an upgrade package.

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  • Low-level Keyboard Hooks/SendInput with Winkey+L possible? (workstation lockout is intercepted in Vi

    - by Brian Jorgensen
    I work on a project called UAWKS (Unofficial Apple Wireless Keyboard Support) that helps Windows users use Apple's bluetooth keyboard. One of the main goals of UAWKS is to swap the Cmd key (which behaves as Winkey in Windows) with Ctrl, allowing users to do Cmd+C for copy, Cmd+T for new tab, etc. It is currently developed using AutoHotkey, which worked pretty well under Windows XP. However, on Vista and Windows 7, Cmd+L causes problems: Regardless of low-level keyboard hooks, Winkey+L is always intercepted by Windows and normally locks the workstation... You can disable workstation locking with this registry hack, but pressing Winkey+L still can't be rebound in AHK Pressing Winkey+L leaves Winkey in the Keydown state until the next (additional) Winkey Up. Simulating a Keyup event doesn't seem to work either! It seems that Winkey+L is a special chord that messes everything else up. I've looked through the AHK source code, and they try to address this problem in SendKey() in keyboard_mouse.cpp (near line 883 in v1.0.48.05), but it doesn't work. I wrote up my own low-level keyboard hook application in C#, and I see the same problem. Has anyone else run into this? Is there a workaround?

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  • Would be good to include your freelancer account in your Resume / CV when applying for a job?

    - by Oscar Mederos
    I've been working as a freelancer for about two years in vWorker. Any person can visit a coder's profile, and see in how many projects the coder has worked on, (if the coders allows) see how much the coder obtained in each project, ratings, feedbacks, etc. Would be good to include a freelancer account in your Resume / CV when applying for a job? Is it something you would do if you have finished several projects there?

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  • Why are all logins disabled in the virtual terminal after enabling root account from desktop?

    - by Mitch
    Just for testing purposes, I went a head and enabled the root account, by using the commands below: sudo passwd root [sudo] password for abed: Enter new UNIX password: Retype new UNIX password: passwd: password updated successfully Once that happened, I went ahead and did Ctrl+Alt+F1, to get to the first virtual console, and at the login prompt I try logging in as abed, su, root, all comeback with login incorrect. Why is that happening, and how can I fix it.

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  • Password-protected sharing allows access to users who have no account?

    - by romkyns
    Running Win7 on two computers in my LAN. Computer A has password-protected sharing enabled, and shares a folder. It has a single user account "Bob", and the Guest account is turned off. The network is workgroup-based. According to the descriptions of the "password-protected sharing" I could find, the only people who can access the shared folder via the LAN are those who know the username+password for the "Bob" account. However a second computer on the LAN is able to view this shared folder by simply browsing to Computer A. They don't need to enter any passwords or anything. The only user account registered on that PC is called "Jim", and has a different password from "Bob". How on earth is computer B able to view this shared folder? Is the popular description of the "password-protected sharing" feature inaccurate / did I misunderstand it big time? P.S. There is a possibility that the password for "Bob" has been entered on that PC once, and possibly the "remember password" box was checked. I've looked in the "Credential Manager" on both computers and there is nothing saved anywhere.

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  • How to add a privilege to an account in Windows?

    - by mark
    Given: A VM running Windows 2008 I am logged on there using my domain account (SHUNRANET\markk) I have added the "Create global objects" privilege to my domain account: The VM is restarted (I know logout/logon is enough, but I had to restart) I logon again using the same domain account. It seems still to have the privilege: I run some process and examine its Security properties using the Process Explorer. The account does not seem to have the privilege: This is not an idle curiousity. I have a real problem, that without this privilege the named pipe WCF binding works neither on Windows 2008 nor on Windows 7! Here is an interesting discussion on this matter - http://social.msdn.microsoft.com/forums/en-US/wcf/thread/b71cfd4d-3e7f-4d76-9561-1e6070414620. Does anyone know how to make this work? Thanks. EDIT BTW, when I run the process elevated, everything is fine and the process explorer does display the privilege as expected: But I do not want to run it elevated. EDIT2 I equally welcome any solution. Be it configuration only or mixed with code. EDIT3 I have posted the same question on MSDN forums and they have redirected me to this page - http://support.microsoft.com/default.aspx?scid=kb;EN-US;132958. I am yet to determine the relevance of it, but it looks promising. Notice also that it is a completely coding solution that they propose, so whoever moved this post to the ServerFault - please reinstate it back in the StackOverflow.

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  • Update in Certification Exam Score Report Access Process!

    - by Richard Lefebvre
    Please note that exam results for all Oracle Certification exams will be accessed through CertView, starting October 30th, 2012. Exam results will no longer be available at the test center, or on the Pearson VUE website. Candidates will receive an email from Oracle within 30 minutes of completing the exam to let them know that their exam results are available on CertView. Candidates must have an Oracle Web Account to access CertView. This new process applies to exam results for all Oracle Certification exams - proctored and non-proctored as well beta exams. CertView, Oracle's self-service certification portal will be the partners’ one stop source for all their certification and exam history! Other benefits of this change include: driving all candidates to have an Oracle Web Account which will lead to tighter integration with Oracle University records in the future, increased security around data privacy and a higher validity rate for candidate email addresses. Existing benefits of CertView include, self-service access to exam and certification records and logos, and access to Oracle's self service certification verification. Accessing Exam Results  Returning CertView Users ·         Click the link in the email sent by Oracle or go to certview.oracle.com ·         Select the See My New Exam Results Now link to view exam results ·         Select the Print My New Exam Results Now link to print exam results  New CertView Users - Who Have An Oracle Web Account ·         First time Users must authenticate their CertView account ·         Account Authentication requires the Oracle Testing ID and email address from your Pearson VUE profile ·         Click the link in the email sent by Oracle or go to certview.oracle.com and follow the Authenticate My CertView Account link.  New CertView Users - Who Do Not Have An Oracle Web Account ·         CertView users are required to have an Oracle Web Account ·         To create an Oracle Web Account, go to certview.oracle.com and select theCreate My Oracle Web Account Now link. Then follow the remaining instructions under I do not have an Oracle Web Account on that page.

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  • Is there a way to take credit cards on my website without needing a merchant account/payment gateway?

    - by Erik
    I've been looking for a service like this but can't find one -- it boggles my mind that such a thing doesn't exist. The ideal thing I'm looking for would be something like this: User fills out a form on my website I submit data to the service (cc #, payment amount) I get paid perhaps monthly by the service the amounts that were charged (less a fee) This is more or less how accepting paypal for payments works, except it takes my users to paypal's site and forces them to create a paypal account etc, which I'd like to avoid. Does such a service exist?

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  • Start Chrome by command line, but adding some arguments to make it login into your Google account automatically

    - by jim
    Is there a way to start Chrome calling it from the command line (using Linux), but providing it some argument to make it login into some Google account automatically? I'm looking for something like google-chrome -account foo -pass bar that I can easily put in a bash script later. A little background: I have a laptop connected to my TV, which is currently using just a mouse for user interaction. There's no google account logged in by default, and that's the way I want to keep it, so my kids can't come across videos and pictures in google and youtube that they are not supposed to see (e.g.: adult content, or anything marked as not appropriate for kids by the google's safe search filters). The bad thing about this is that there are some music videos in youtube that requires you to be logged in to see, usually those we (the adults) used to sing when playing karaoke... as the only input available is a mouse, I'm looking for a way to start with my google account without having to type the whole thing usin the on-screen keyboard. You may think "Why you can't use the keyboard, if the laptop is right there?". Well, it's in a kind of uncomfortable position - too high for me without a chair or something, as it's right above the furniture in where the TV is located. Is there a way to make this scriptable? If not, do you know any other workaround? Note: using the remember me after logging off or alike options are discarded, as the safe-search chrome version must be always the default version to run.

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  • How to create a script which opens the browser and logins to a particular Gmail account?

    - by TechGuru
    I have created a bash script login.sh. I want it to open the browser and login to my Gmail account. I tried using the following command to open the browser with www.gmail.com. xdg-open http://gmail.com It opens Gmail home page perfectly. But I don't know how to pass the username and password for login to Gmail from the bash script. Is it possible to open the browser and login to Gmail from a script?

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  • ASP.net MVC - Update Model on complex models

    - by ludicco
    Hi there, I'm struggling myself trying to get the contents of a form which is a complex model and then update the model with that complex model. My account model has many individuals [AcceptVerbs(HttpVerbs.Post)] public ActionResult OpenAnAccount(string area,[Bind(Exclude = "Id")]Account account, [Bind(Prefix="Account.Individuals")] EntitySet<Individual> individuals){ var db = new DB(); account.individuals = invdividuals; db.Accounts.InsertOnSubmit(account); db.SubmitChanges(); } So it works nicely for adding new Records, but not for update them like: [AcceptVerbs(HttpVerbs.Post)] public ActionResult OpenAnAccount(string area,[Bind(Exclude = "Id")]Account account, [Bind(Prefix="Account.Individuals")] EntitySet<Individual> individuals){ var db = new DB(); var record = db.Accounts.Single(a => a.Reference == area); account.individuals = invdividuals; try{ UpdateModel(record, account); // I can't convert account ToValueProvider() db.SubmitChanges(); } catch{ return ... //Error Message } } My problem is being how to use UpdateModel with the account model since it's not a FormCollection. How can I convert it? How can I use ToValueProvider with a complex model? I hope I was clear enough Thanks a lot :)

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  • "The Operation Failed." accepting METHOD: PUBLISH iCalendar files in .pst account

    - by Jamie Kitson
    if I create a new Mail Profile using the Internet E-mail wizard, ie, creating a new local .pst account, and then try to add a .ics iCalendar file with a METHOD of PUBLISH to the calendar of that account, I get the error "The Operation Failed." If I change any of the above it works ok, eg, if I use an Exchange account or METHOD: REQUEST in the iCalendar file. I'm using Outlook 2010 on Windows 7 but I think the user that originally reported this was using Outlook 2007. Does anyone have any idea of why this might be? Thanks, Jamie Kitson

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  • How can I tell what user account is being used by a service to access a network share on a Windows 2008 server?

    - by Mike B
    I've got a third-party app/service running on a Windows 2003 SP2 server that is trying to fetch something from a network share on Windows 2008 box. Both boxes are members of an AD domain. For some reason, the app is complaining about having insufficient permissions to read/write to the store. The app itself doesn't have any special options for acting on the authority of another user account. It just asks for a UNC path. The service is running with a "log on as" setting of Local System account. I'd like to confirm what account it's using when trying to communicate with the network share. Conversely, I'd also like more details on if/why it's being rejected by the Windows 2008 network share. Are there server-side logs on 2008 that could tell me exactly why a connection attempt to a share was rejected?

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  • Does Outlook continue to auto-discover account settings for already configured accounts? Can it be prevented?

    - by Oliver Salzburg
    fail2ban just locked me out of our website because something from my desktop was hammering port 443 on the server (which is not in use). I saw my IP also requesting "GET /autodiscover/autodiscover.xml HTTP/1.1", so I assume that's what's going on on port 443 as well. But I only have 1 email account configured in Outlook and it's working just fine. The account is for the address [email protected] and said server will answer for example.com, but that server is not our MX and it is also not configured as an Exchange server in my mail account. So, why is Outlook still trying to retrieve those auto-configuration settings?

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  • How to update Sharepoint 2010 user profile for user whose account name has changed in AD?

    - by Daniel Root
    We have an issue with User Profile Sync in SharePoint 2010 when the following happens: A new user is added to AD (ie DOMAIN\jdoh) The user is synched successfully to SharePoint Time passes The user's account name is changed in AD (ie because it was originally misspelled: DOMAIN\jdoe) The user is re-synced to SharePoint The behavior appears to be that the account name is not changed. In the above example, accountname will continue to be DOMAIN\jdoh in SharePoint, though other properties are synced correctly- I would assume by SID. This means that the users' my profile and mysite links still refer to the 'old' name (ie Person.aspx?accountname=Domain\jdoh). What steps should be taken to fix this in SharePoint when an account name is changed in AD?

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  • How to add an account to Entourage that's only a mail forward?

    - by Robot
    I have two email accounts, one is my main account, and the other just forwards to the main. I'd like to select either address from the From: dropdown list, but I think the forward would need to be formal Entourage account for that to work. If I add the forward acct, it insists on trying to login, even though there is no real mailbox for it... it's just a forward. This happens even if I don't check the "Include this account in my Send & Receive All Schedule" checkbox. Is there any way to prevent login attempts, or to add From: addresses without adding them as real mailbox accounts? -Robot

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