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  • What are the most important aspects to consider when choosing a SAN for a small office virtualizatio

    - by Prof. Moriarty
    I am in the process of consolidating 6 physical servers running 6 different operating system flavors (don't ask) into two identical physical servers (Dell PowerEdge 2900), using the free VMware ESXi 4.0 platform. We will install an iSCSI SAN over a 1GbE network, and store all virtual machine images on the SAN. Each physical server would run 3 VMs, and in the case of a physical server failure, we would manually switch over the other 3. These are all internal servers, while important, they can tolerate some amount of downtime (say <1h) to keep cost and complexity associated with HA down. I now need to choose the SAN to be used for the setup, on a low budget. We currently have about 2TB of data, but of course I want to able to grow, do backups of VM snapshots on other drives and remove them to a different location, etc. So what I would like to know is: Which are the must have features for this setup, without which using a SAN is not worth it? We are mostly a Dell shop, so I have been looking at the EqualLogic PS4000E High Availability model. Any opinions, anecdotes, bad experiences with this model? (This is one of the few models which could accomodate our existing disks from the physical servers.) If you can recommend something that is not Dell, but it has better value, I would most definitely consider it. Caveats, things to look out for?

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  • Is this DVD drive broken? Brand new, i need help convincing

    - by acidzombie24
    I am asking bc i know dell is going to give me a problem. How do i know if my DVD is broken on my laptop? i burnt 4 DL disc and they ALL failed, i called and dell suggested roxio. I used it and burnt 1 disc without error and the 2nd disc with an error. With both apps there were no 'problems' during the burning process only failed on the verification process. Some of these bad disc dont work on other PCs and one locks up windows when i click a specific file. Does that sound like a broken burner to you guys? when i called dell they told me since it can read disc properly 100% of the time and software doesnt fail in the burning process its not a broken drive _. They forward me to software support who demand a fee (i think $100) to help me fix my software. I am annoyed bc i dont want to be on the phone for them to watch me burn a dvd and since i burned it once correctly i dont want to happen to burn correctly again to have them say they solved my problem (doing nothing) and charge me refusing to refund. -edit- The errors i got were 1) the request could not be performed because of an I/O device error 2) Windows locking up when opening 1 specific file 3) Cannot copy : Data error (crc) NOTE: the file that causes the problems are random every disc

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  • When must arbitrary precision arithmetic functions be used in PHP?

    - by Tjorriemorrie
    My colleague uses the Binary Calculator functions in bandwidth calculations; as much as terrabytes, and with percentage splitting on allocation. His usage of these functions appears correct in order not to lose a byte; although he seems to be using them now for everything. The manual only says: For arbitrary precision mathematics PHP offers the Binary Calculator which supports numbers of any size and precision, represented as strings. How much is any size? Is it really necessary? How big is the default float in PHP? Are there any good advice regarding this or things to keep in mind?

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  • Read half precision float (float16 IEEE 754r) binary data in matlab

    - by Michael
    you have been a great help last time, i hope you can give me some advise this time, too. I read a binary file into matlab with bit16 (format = bitn) and i get a string of ones and zeros. bin = '1 00011 1111111111' (16 bits: 1. sign, 2-6. exponent, 7-16. mantissa) According to ftp://www.fox-toolkit.org/pub/fasthalffloatconversion.pdf it can be 'converted' like out = (-1)^bin(1) * 2^(bin(2:6)-15) * 1.bin(7:16) [are exponent and mantissa still binary?] Can someone help me out and tell me how to deal with the 'eeeee' and '1.mmmmmmmmmm' as mentioned in the pdf, please. Thanks a lot! Michael

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  • How to compare two times in milliseconds precision?

    - by Marcos Issler
    I have a subtitle text file that works with standart srt format 00:00:00,000 Hour, minutes, seconds, milliseconds. I want to create a timer to update the subtitle screen and check the current time to know what subtitle show on screen. Which is the best to use? NSTimeInterval, NSDate? I think the best is to convert all to times to milliseconds number and compare. But NSTimeInterval works with seconds, not milliseconds. Some clue? Marcos

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  • Multiplication algorithm for abritrary precision (bignum) integers.

    - by nn
    Hi, I'm writing a small bignum library for a homework project. I am to implement Karatsuba multiplication, but before that I would like to write a naive multiplication routine. I'm following a guide written by Paul Zimmerman titled "Modern Computer Arithmetic" which is freely available online. On page 4, there is a description of an algorithm titled BasecaseMultiply which performs gradeschool multiplication. I understand step 2, 3, where B^j is a digit shift of 1, j times. But I don't understand step 1 and 3, where we have A*b_j. How is this multiplication meant to be carried out if the bignum multiplication hasn't been defined yet? Would the operation "*" in this algorithm just be the repeated addition method? Here is the parts I have written thus far. I have unit tested them so they appear to be correct for the most part: The structure I use for my bignum is as follows: #define BIGNUM_DIGITS 2048 typedef uint32_t u_hw; // halfword typedef uint64_t u_w; // word typedef struct { unsigned int sign; // 0 or 1 unsigned int n_digits; u_hw digits[BIGNUM_DIGITS]; } bn; Currently available routines: bn *bn_add(bn *a, bn *b); // returns a+b as a newly allocated bn void bn_lshift(bn *b, int d); // shifts d digits to the left, retains sign int bn_cmp(bn *a, bn *b); // returns 1 if a>b, 0 if a=b, -1 if a<b

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  • matlab precision determint problem

    - by ldigas
    I have the following program format compact; format short g; clear; clc; L = 140; J = 77; Jm = 10540; G = 0.8*10^8; d = L/3; for i=1:500000 omegan=1.+0.0001*i; a(1,1) = ((omegan^2)*(Jm/(G*J))*d^2)-2; a(1,2) = 2; a(1,3) = 0; a(1,4) = 0; a(2,1) = 1; a(2,2) = ((omegan^2)*(Jm/(G*J))*d^2)-2; a(2,3) = 1; a(2,4) = 0; a(3,1) = 0; a(3,2) = 1; a(3,3) = ((omegan^2)*(Jm/(G*J))*d^2)-2; a(3,4) = 1; a(4,1) = 0; a(4,2) = 0; a(4,3) = 2; a(4,4) = ((omegan^2)*(Jm/(G*J))*d^2)-2; if(abs(det(a))<1E-10) sprintf('omegan= %8.3f det= %8.3f',omegan,det(a)) end end Analytical solution of the above system, and the same program written in fortran gives out values of omegan equal to 16.3818 and 32.7636 (fortran values; analytical differ a little, but they're there somewhere). So, now I'm wondering ... where am I going wrong with this ? Why is matlab not giving the expected results ? (this is probably something terribly simple, but it's giving me headaches)

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  • matlab precision determinant problem

    - by ldigas
    I have the following program format compact; format short g; clear; clc; L = 140; J = 77; Jm = 10540; G = 0.8*10^8; d = L/3; for i=1:500000 omegan=1.+0.0001*i; a(1,1) = ((omegan^2)*(Jm/(G*J))*d^2)-2; a(1,2) = 2; a(1,3) = 0; a(1,4) = 0; a(2,1) = 1; a(2,2) = ((omegan^2)*(Jm/(G*J))*d^2)-2; a(2,3) = 1; a(2,4) = 0; a(3,1) = 0; a(3,2) = 1; a(3,3) = ((omegan^2)*(Jm/(G*J))*d^2)-2; a(3,4) = 1; a(4,1) = 0; a(4,2) = 0; a(4,3) = 2; a(4,4) = ((omegan^2)*(Jm/(G*J))*d^2)-2; if(abs(det(a))<1E-10) sprintf('omegan= %8.3f det= %8.3f',omegan,det(a)) end end Analytical solution of the above system, and the same program written in fortran gives out values of omegan equal to 16.3818 and 32.7636 (fortran values; analytical differ a little, but they're there somewhere). So, now I'm wondering ... where am I going wrong with this ? Why is matlab not giving the expected results ? (this is probably something terribly simple, but it's giving me headaches)

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  • Compare double till precision 2

    - by Ram
    Hi, I want to compare two double values till the second digit from decimal point. I am using following statement but I think it is not working properly. dbl1.ToString("g2", CultureInfo.InvariantCulture).Equals( dbl2.ToString("g2", CultureInfo.InvariantCulture)) Am I missing anything here?

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  • how to increase the precision in Locate Me app

    - by thndrkiss
    Hi, I just installed the locate me app and started to understand the CLLocation stuff. I need to know how to increase the number of digits after the lat and long numbers displayed. Can any one help me. currently it shows 17.5968,82.8486. I need more number of digits after decimal(6 digits after decimal.

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  • floating point precision in ruby on rails model validations

    - by Chris Allison
    Hello I am trying to validate a dollar amount using a regex: ^[0-9]+\.[0-9]{2}$ This works fine, but whenever a user submits the form and the dollar amount ends in 0(zero), ruby(or rails?) chops the 0 off. So 500.00 turns into 500.0 thus failing the regex validation. Is there any way to make ruby/rails keep the format entered by the user, regardless of trailing zeros?

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  • Qwt setAxisScale() seems to lock up application when given numbers with greater precision than 2e-07

    - by Dane Larsen
    I'm using Qwt for some scientific graphing, and I'm working with some fairly small numbers, the smallest being around 1.0e-22. I'm trying to call setAxisScale(xaxis, xmin, xmax) //xmin = 0, xmax = 2.0e-10 But when I do, the application locks up. I haven't found anything in the documentation that refers to a minimum value. Xmin and xmax are both doubles, so that shouldn't be a problem. Is this a bug in Qwt, or am I doing something wrong? Thanks in advance

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  • Sorting a vector of (double precision) reals and obtain their order

    - by Philipp
    Hello everyone, in C++ would like to sort a lengthy (2^20) vector of reals, obviously sort() does the trick. Having used R before I was used to the nice order() function which yields the permutation that leads to the sorted vector. Probably someone has done this in C++, maybe it's just my weak google-Fu that prevents me from finding it. And yeah, obivously my C++ newbness could stop me from spotting something straightforward. Example: x = {24, 55, 22, 1} then the permutation perm = {3, 2, 0, 1} maps the original x to the sorted x in ascending order. I can probably implement some bubble sort which does not only sort x but performs the same transpositions on the vector {0,1,2,...} and outputs both, but I believe someone must have thought about it and especially have done it efficiently. Thank you very much, Philipp

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  • Floating point precision and physics calculations

    - by Vee
    The gravity Vector2 in my physics world is (0; 0.1). The number 0.1 is known to be problematic, since "it cannot be represented exactly, but is approximately 1.10011001100110011001101 × 2-4". Having this value for the gravity gives me problems with collisions and creates quite nasty bugs. Changing the value to 0.11 solves these problems. Is there a more elegant solution that doesn't require changing the value at all?

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  • DateTime Comparison Precision

    - by mnh
    I'm doing DateTime comparison but I don't want to do comparison at second, millisecond and ticks level. What's the most elegant way? If I simply compare the DateTime, then they are seldom equal due to ticks differences.

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  • Extend precision of MySQL's double datatype?

    - by tim82
    I am trying to save the value "6.714285714285714" into a DOUBLE datatype field. Unfortunately it does not fit at all and is cutted by one char. Storing larger numbers becomes less precise. Already searched in the mysql manual and it seems to be that double is the most precise data type available. Anyone knows a practicable workaround? Sorry for my bad english and thx a lot!

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  • How to maintain decimal precision in calculations

    - by Blankman
    I need to sum 2 decimal values together, then divide by 2 and convert to string. My calculation currently is trimming to 2 decimal places, but I want to keep as many decimals as I can. city.Latitude = ( (lat.North + lat.South) / 2 ).ToString(); the values for lat.North and lat.Souch are like: 55.32342322

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  • Losing DateTimeOffset precision when using C#

    - by Darvis Lombardo
    I have a SQL Server table with a CreatedDate field of type DateTimeOffset(2). A sample value which is in the table is 2010-03-01 15:18:58.57 -05:00 As an example, from within C# I retrieve this value like so: var cmd = new SqlCommand("SELECT CreatedDate FROM Entities WHERE EntityID = 2", cn); var da = new SqlDataAdapter(cmd); DataTable dt =new DataTable(); da.Fill(dt); And I look at the value: MessageBox.Show(dt.Rows[0][0].ToString()); The result is 2010-03-01 15:18:58 -05:00, which is missing the .57 that is stored in the database. If I look at dt.Rows[0][0] in the Watch window, I also do not see the .57, so it appears it has been truncated. Can someone shed some light on this? I need to use the date to match up with other records in the database and the .57 is needed. Thanks! Darvis

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  • High precision event timer

    - by rahul jv
    #include "target.h" #include "xcp.h" #include "LocatedVars.h" #include "osek.h" /** * This task is activated every 10ms. */ long OSTICKDURATION; TASK( Task10ms ) { void XCP_FN_TYPE Xcp_CmdProcessor( void ); uint32 startTime = GetQueryPerformanceCounter(); /* Trigger DAQ for the 10ms XCP raster. */ if( XCPEVENT_DAQ_OVERLOAD & Xcp_DoDaqForEvent_10msRstr() ) { ++numDaqOverload10ms; } /* Update those variables which are modified every 10ms. */ counter16 += slope16; /* Trigger STIM for the 10ms XCP raster. */ if( enableBypass10ms ) { if( XCPEVENT_MISSING_DTO & Xcp_DoStimForEvent_10msRstr() ) { ++numMissingDto10ms; } } duration10ms = (uint32)( ( GetQueryPerformanceCounter() - startTime ) / STOPWATCH_TICKS_PER_US ); } What would be the easiest (and/or best) way to synchronise to some accurate clock to call a function at a specific time interval, with little jitter during normal circumstances, from C++? I am working on WINDOWS operating system now. The above code is for RTAS OSEK but I want to call a function at a specific time interval for windows operating system. Could anyone assist me in c++ language ??

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  • Formatting currency within a specific precision range

    - by Alex Prose
    I am trying to format currency that will always contain 2 decimal digits, but if there are extra digits of accuracy to display up to five. As an example: for value = 5.0 display: $5.00 for value = 5.023 display: $5.023 for value = 5.333333333333333 display: $5.33333 I have been playing with the .ToString() formatting, but I can't seem to find the right match of options. Clarification: I want to show from 2-5 decimals, truncating zeros after the second digit. for value = 5.000000000000000 display: $5.00 for value = 5.333333333333333 display: $5.33333

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  • ESX3.5 Cluster & MD3000i -- Both servers see iSCSI Targets, Only one server can use partition.

    - by GruffTech
    Alright. First and foremost, Warning. This is a bigger-then-normal question. I like to be thorough and try to eliminate all possible "easymode" answers, as well as give everyone a feel of what i've tried. I've included several images of our setup and the problem it is having.. TLDR Version: So I've followed the guides located here: ESX Deployment Guide V1 this is the guide Dell has sent me to setup two ESX3.5 servers mounting a Dell MD3000i. It doesn't work. Both servers can't use the same storage partition on the MD3000. Both servers see it, but only one server can actually use it. (that server being whatever server created the partition on the target.) Both ESX servers are members of the Host Group. Full Version I have 2 ESX3.5 Servers (10.0.7.102, also called EPI2, and 10.0.7.103, also called EPI3.) connected to a iSCSI SAN Device (Dell MD3000i). Both ESX servers can "scan" the SAN and see the LUNS. Part One: MD3000i Storage On the MD3000i, Both servers are in my host group. I have two partitions, VM1 and VM2, both 1.6TB (vmware doesn't like anything past 2tb.) And you can even see that the ESX servers are targetting the MD3000 just fine. Part Two: The ESX Servers Figure 1. So as you can see above, Both ESX Servers (10.0.7.102 and 10.0.7.103) are able to see and scan the MD3000i SAN. Figure 2. Above is the storage both servers see. I created the storage partition on EPI2 (102). I then Extended the partition to include the second LUN for a grand total of 3.27 TB of storage. When i "rescan" on 103 (the server not mounting the partition), I get the below log in log/messages. Mar 11 10:41:18 epi3 kernel: scsi1: remove-single-device 0 0 0 failed, device busy(4). being the only line that grabs my attentions. (EPI3 is the server name) Mar 11 10:41:04 epi3 vmkiscsid[5436]: Connected to Discovery Address 192.168.130.101 Mar 11 10:41:04 epi3 vmkiscsid[5437]: Connected to Discovery Address 192.168.130.102 Mar 11 10:41:04 epi3 vmkiscsid[5438]: Connected to Discovery Address 192.168.131.101 Mar 11 10:41:04 epi3 vmkiscsid[5439]: Connected to Discovery Address 192.168.131.102 Mar 11 10:41:17 epi3 kernel: scsi singledevice 2 0 0 0 Mar 11 10:41:17 epi3 kernel: Vendor: DELL Model: MD3000i Rev: 0735 Mar 11 10:41:17 epi3 kernel: Type: Direct-Access ANSI SCSI revision: 05 Mar 11 10:41:17 epi3 kernel: VMWARE SCSI Id: Supported VPD pages for sdb : 0x0 0x80 0x83 0x85 0x86 0x87 0xc0 0xc1 0xc2 0xc3 0xc4 0xc8 0xc9 0xca 0xd0 Mar 11 10:41:17 epi3 kernel: VMWARE SCSI Id: Device id info for sdb: 0x1 0x3 0x0 0x10 0x60 0x1 0xe4 0xf0 0x0 0x1a 0x1a 0xa2 0x0 0x0 0x15 0xe2 0x4d 0x75 0xf6 0x99 0x53 0x98 0x0 0x54 0x69 0x71 0x6e 0x2e 0x31 0x39 0x38 0x34 0x2d 0x30 0x35 0x2e 0x63 0x6f 0x6d 0x2e 0x64 0x65 0x6c 0x6c 0x3a 0x70 0x6f 0x77 0x65 0x72 0x76 0x61 0x75 0x6c 0x74 0x2e 0x36 0x30 0x30 0x31 0x65 0x34 0x66 0x30 0x30 0x30 0x31 0x61 0x31 0x61 0x61 0x32 0x30 0x30 0x30 0x30 0x30 0x30 0x30 0x30 0x34 0x37 0x39 0x30 0x36 0x32 0x32 0x65 0x2c 0x74 0x2c 0x30 0x78 0x30 0x30 0x30 0x31 0x30 0x30 0x30 0x30 0x30 0x30 0x30 0x32 0x0 0x0 0x0 0x51 0x94 0x0 0x4 0x0 0x0 0x80 0x1 0x53 0xa8 0x0 0x44 0x69 0x71 0x6e 0x2e 0x31 0x39 0x38 0x34 0x2d 0x30 0x35 0x2e 0x63 0x6f 0x6d 0x2e 0x64 0x65 0x6c 0x6c 0x3a 0x70 0x6f 0x77 0x65 0x72 0x76 0x61 0x75 0x6c 0x74 0x2e 0x36 0x30 0x30 0x31 0x65 0x34 0x66 0x30 0x30 0x30 0x31 0x61 0x31 0x61 0x61 0x32 0x30 0x30 0x30 0x30 0x30 0x30 0x30 0x30 0x34 0x37 0x39 0x30 0x36 0x32 0x32 0x65 0x0 0x0 0x0 0x0 Mar 11 10:41:17 epi3 kernel: VMWARE SCSI Id: Id for sdb 0x60 0x01 0xe4 0xf0 0x00 0x1a 0x1a 0xa2 0x00 0x00 0x15 0xe2 0x4d 0x75 0xf6 0x99 0x4d 0x44 0x33 0x30 0x30 0x30 Mar 11 10:41:17 epi3 kernel: VMWARE: Unique Device attached as scsi disk sdb at scsi2, channel 0, id 0, lun 0 Mar 11 10:41:17 epi3 kernel: Attached scsi disk sdb at scsi2, channel 0, id 0, lun 0 Mar 11 10:41:17 epi3 kernel: scan_scsis starting finish Mar 11 10:41:17 epi3 kernel: SCSI device sdb: 3509329920 512-byte hdwr sectors (1797751 MB) Mar 11 10:41:17 epi3 kernel: sdb: sdb1 Mar 11 10:41:17 epi3 kernel: scan_scsis done with finish Mar 11 10:41:17 epi3 kernel: scsi singledevice 2 0 0 1 Mar 11 10:41:17 epi3 kernel: Vendor: DELL Model: MD3000i Rev: 0735 Mar 11 10:41:17 epi3 kernel: Type: Direct-Access ANSI SCSI revision: 05 Mar 11 10:41:18 epi3 kernel: VMWARE SCSI Id: Supported VPD pages for sdc : 0x0 0x80 0x83 0x85 0x86 0x87 0xc0 0xc1 0xc2 0xc3 0xc4 0xc8 0xc9 0xca 0xd0 Mar 11 10:41:18 epi3 kernel: VMWARE SCSI Id: Device id info for sdc: 0x1 0x3 0x0 0x10 0x60 0x1 0xe4 0xf0 0x0 0x1a 0x1a 0x86 0x0 0x0 0xd 0xb7 0x4d 0x75 0xf2 0x77 0x53 0x98 0x0 0x54 0x69 0x71 0x6e 0x2e 0x31 0x39 0x38 0x34 0x2d 0x30 0x35 0x2e 0x63 0x6f 0x6d 0x2e 0x64 0x65 0x6c 0x6c 0x3a 0x70 0x6f 0x77 0x65 0x72 0x76 0x61 0x75 0x6c 0x74 0x2e 0x36 0x30 0x30 0x31 0x65 0x34 0x66 0x30 0x30 0x30 0x31 0x61 0x31 0x61 0x61 0x32 0x30 0x30 0x30 0x30 0x30 0x30 0x30 0x30 0x34 0x37 0x39 0x30 0x36 0x32 0x32 0x65 0x2c 0x74 0x2c 0x30 0x78 0x30 0x30 0x30 0x31 0x30 0x30 0x30 0x30 0x30 0x30 0x30 0x32 0x0 0x0 0x0 0x51 0x94 0x0 0x4 0x0 0x0 0x80 0x1 0x53 0xa8 0x0 0x44 0x69 0x71 0x6e 0x2e 0x31 0x39 0x38 0x34 0x2d 0x30 0x35 0x2e 0x63 0x6f 0x6d 0x2e 0x64 0x65 0x6c 0x6c 0x3a 0x70 0x6f 0x77 0x65 0x72 0x76 0x61 0x75 0x6c 0x74 0x2e 0x36 0x30 0x30 0x31 0x65 0x34 0x66 0x30 0x30 0x30 0x31 0x61 0x31 0x61 0x61 0x32 0x30 0x30 0x30 0x30 0x30 0x30 0x30 0x30 0x34 0x37 0x39 0x30 0x36 0x32 0x32 0x65 0x0 0x0 0x0 0x0 Mar 11 10:41:18 epi3 kernel: VMWARE SCSI Id: Id for sdc 0x60 0x01 0xe4 0xf0 0x00 0x1a 0x1a 0x86 0x00 0x00 0x0d 0xb7 0x4d 0x75 0xf2 0x77 0x4d 0x44 0x33 0x30 0x30 0x30 Mar 11 10:41:18 epi3 kernel: VMWARE: Unique Device attached as scsi disk sdc at scsi2, channel 0, id 0, lun 1 Mar 11 10:41:18 epi3 kernel: Attached scsi disk sdc at scsi2, channel 0, id 0, lun 1 Mar 11 10:41:18 epi3 kernel: scan_scsis starting finish Mar 11 10:41:18 epi3 kernel: SCSI device sdc: 3509329920 512-byte hdwr sectors (1797751 MB) Mar 11 10:41:18 epi3 kernel: sdc: sdc1 Mar 11 10:41:18 epi3 kernel: scan_scsis done with finish Mar 11 10:41:18 epi3 kernel: scsi1: remove-single-device 0 0 0 failed, device busy(4). Mar 11 10:41:18 epi3 kernel: scsi singledevice 1 0 0 0 Things I've Tried: Removing iSCSI targets from only 103, disabling iSCSI, rebooting, enabled iSCSI, re-adding targets, rescan. Same result. Removing partition on 102, Formatted partition on 103 instead. Same result, except flipped. 103 can use storage, 102 can not. Starting Over. Removing all iSCSI Targets on both ESX Boxes, disabling iSCSI, turning off the firewall for iSCSI, rebooting ESX. Then on the MD3000, Removed the Host Group, Removed the Host-to-Virtual Mappings, Restarted the SAN. Followed the Documentation again, same result. Both servers see the storage, but only one server can use it. Disabling and Re-enabling VMware DRS and HA. Same result. Flat-out turning off VMware DRS and HA, and doing the "start over" step to see if maybe that borked it. Same Result. I'm kinda loosing my mind here, Everything i read online says "just partition it and if the ESX boxes can see the targets, it just works".... well crap. Any ideas, any other things to try? Can anyone atleast point me in the right direction? I'm really tired of working from 1am til 4am (our maintenance hours)

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  • Why does Ubuntu reset brightness settings at the loading screen?

    - by leugim
    Since I first installed Ubuntu 11.10, I noticed that volume and screen brightness get reset every time Ubuntu starts. Why is this so? And what ways are there to keep brightness and volume levels after rebooting? I have found some scripts that change the screen-brightness at login. But this is not a good solution since login is slower because it seems to wait until the screen brightness is at the level specified by the script. After entering the password I see the screen brightness go down gradually. Only after this is complete (~1 or 2 seconds) does the background disappear and Unity come up. The screenbrightness is not remembered but instead redefined at login. So it gets remembered for the first part of the boot, then set to MAX and then again re-set to normal value by the script. My boot process is as follows: desired brightness: 2 (13,33%) / Max brightness: 15 (100%) Bios / brightness: OK GRUB (violet background color, white text) / brightness: OK Ubuntu loading screen with the dots / brightness: MAX (win7 loads with OK-brightness) User Login / brightness: MAX Unity starts / brightness: OK It seems to be more like a temporary patch than a actual solution. I'm looking for solutions that set the desired brightness permanently and consistently throughout the whole boot-process After updating to 12.04 the behavior is the same. I tried setpci -s 02:00.0 F4.B=XX The value of F4.B is always '0' regardless of what value I try to set it to (tried 0, ff, f, 5, etc) The solution in this answer does not have any noticeable effect: Desktop doesn't remember brightness settings after a reboot The variables at /sys/class/backlight/acpi_video0/ get changed if I use Fn+UP and Fn+DOWN Any help is appreciated. Thanks!

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