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  • How to auto-generate early bound properties for Entity specific (ie Local) Option Set text values?

    - by Daryl
    After spending a year working with the Microsoft.Xrm.Sdk namespace, I just discovered yesterday the Entity.FormattedValues property contains the text value for Entity specific (ie Local) Option Set texts. The reason I didn't discover it before, is there is no early bound method of getting the value. i.e. entity.new_myOptionSet is of type OptionSetValue which only contains the int value. You have to call entity.FormattedValues["new_myoptionset"] to get the string text value of the OptionSetValue. Therefore, I'd like to get the crmsrvcutil to auto-generate a text property for local option sets. i.e. Along with Entity.new_myOptionSet being generated as it currently does, Entity.new_myOptionSetText would be generated as well. I've looked into the Microsoft.Crm.Services.Utility.ICodeGenerationService, but that looks like it is mostly for specifying what CodeGenerationType something should be... Is there a way supported way using CrmServiceUtil to add these properties, or am I better off writing a custom app that I can run that can generate these properties as a partial class to the auto-generated ones? Edit - Example of the code that I would like to be generated Currently, whenever I need to access the text value of a OptionSetValue, I use this code: var textValue = OptionSetCache.GetText(service, entity, e => e.New_MyOptionSet); The option set cache will use the entity.LogicalName, and the property expression to determine the name of the option set that I'm asking for. It will then query the SDK using the RetrieveAttriubteRequest, to get a list of the option set int and text values, which it then caches so it doesn't have to hit CRM again. It then looks up the int value of the New_MyOptionSet of the entity and cross references it with the cached list, to get the text value of the OptionSet. Instead of doing all of that, I can just do this (assuming that the entity has been retrieved from the server, and not just populated client side): var textValue = entity.FormattedValues["new_myoptionset"]; but the "new_myoptionset" is no longer early bound. I would like the early bound entity classes that gets generated to also generate an extra "Text" property for OptionSetValue properties that calls the above line, so my entity would have this added to it: public string New_MyOptionSetText { return this.GetFormattedAttributeValue("new_myoptionset"); // this is a protected method on the Entity class itself... }

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  • What's the difference between an option type and a nullable type?

    - by Peter Olson
    In F# mantra there seems to be a visceral avoidance of null, Nullable<T> and its ilk. In exchange, we are supposed to instead use option types. To be honest, I don't really see the difference. My understanding of the F# option type is that it allows you to specify a type which can contain any of its normal values, or None. For example, an Option<int> allows all of the values that an int can have, in addition to None. My understanding of the C# nullable types is that it allows you to specify a type which can contain any of its normal values, or null. For example, a Nullable<int> a.k.a int? allows all of the values that an int can have, in addition to null. What's the difference? Do some vocabulary replacement with Nullable and Option, null and None, and you basically have the same thing. What's all the fuss over null about?

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  • Problem with jQuery slider - time

    - by Dawid
    Hello. I'd like to make a slider to choose time(from 1:00 to 4:00) but it doesn't work. It doesn't communicate with 'select'. Can anyone help me? <script> $(function() { var select = $( "#czastrwania" ); var slider = $( "<div id='slider'></div>" ).insertAfter( select ).slider({ min: 60, max: 240, step: 30, range: "min", value: select[ 0 ].selectedIndex + 1, slide: function( e, ui ) { var hours = Math.floor(ui.value / 60); var minutes = ui.value - (hours * 60); if(hours.length == 1) hours = '0' + hours; if(minutes.length == 1) minutes = '0' + minutes; select[ 0 ].selectedIndex = ui.value - 1; } }); $( "#czastrwania" ).change(function() { slider.slider( "value", this.selectedIndex + 1 ); }); }); </script> <select id="czastrwania" name="czastrwania"> <option value="1:00">1:00</option> <option value="1:30">1:30</option> <option value="2:00">2:00</option> <option value="2:30">2:30</option> <option value="3:00">3:00</option> <option value="3:30">3:30</option> <option value="4:00">4:00</option> </select>

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  • create jquery array to use as options

    - by SoulieBaby
    Hi all, I'm sure this is really simple, but I can't seem to get it working. I have a "time" select list, which has a number as "rel" attached to each option. If the user changes the time select, I want a new list of options to display depending on what is selected. If that makes sense? Here's my first select: <select name="time" id="time"> <option value="7:00am" rel="10">7:00am</option> <option value="12:30pm" rel="16">12:30pm</option> </select> If the user selects 7:00am, I want a new option list (using jquery) to give options from 1 - 10. Like this: <select name="quantity" id="quantity"> <option value="1">1</option> <option value="2">2</option> <option value="3">3</option> ............................ <option value="10">10</option> </select> Here's what I have so far... <script type="text/javascript" language="javascript"> jQuery("#time").change(function(){ var positions = jQuery("#time :selected").attr("rel"); //this grabs the rel from time //this is where it should create a list of options to append(??) to the select list.. jQuery("#showQuantity").show(); //this shows the hidden field for quantity }); </script> I hope it makes sense, but I'm stuck on it. Thank you in advance :)

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  • string auto splitting in each loop - jquery

    - by sluggerdog
    I have the following jquery code that is looping through the returned json data, for some reason is it splitting the suburb by a space when being assigned as the value but not as the text, I cannot work out why this is happening. MY CODE $.each(data , function( index, obj ) { $.each(obj, function( key, value ) { var suburb = $.trim(value['mcdl01']); var number = $.trim(value['mcmcu']); $("#FeedbackBranchName").append("<option value=" + suburb + ">" + suburb + " (" + number + ")</option>"); }); }); SAMPLE RETURNED RESULTS <option **value="AIRLIE" beach=""**>AIRLIE BEACH (4440)</option> <option value="ASHMORE">ASHMORE (4431)</option> <option **value="BANYO" commercial=""**>BANYO COMMERCIAL (4432)</option> <option value="BEENLEIGH">BEENLEIGH (4413)</option> <option value="BERRIMAH">BERRIMAH (4453)</option> <option **value="BOWEN" hills=""**>BOWEN HILLS (4433)</option> Notice how for AIRLEE BEACH, BANYO COMMERICAL AND BOWN HILLS the second word has been separated out from the value attribute but it's fine at the text level. Anyone have any idea why this might happen? Thanks

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  • What do you call the highlight as you hover over an OPTION in a SELECT, and how can I "un"highlight

    - by devils-avacado
    I'm working on dropdowns in IE6 (SELECT with OPTIONs as children). I'm experiencing the problem where, in IE6, dropdown menus are truncated to the width of the SELECT element. I used this jquery to fix it: var css_expanded = { 'width' : 'auto', 'position' : 'absolute', 'left' : '564px', 'top' : '393px' } var css_off = { 'width' : '190px', 'position' : 'relative', 'left' : '0', 'top' : '0' } if($.browser.msie) { $('#dropdown') .bind('mouseover', function() { $(this).css(css_expanded); }) .bind('click', function() { $(this).toggleClass('clicked'); }) .bind('mouseout', function() { if (!$(this).hasClass('clicked')) { $(this).css(css_off); } }) .bind('change blur focusout', function() { $(this).removeClass('clicked') .css(css_off) }); }; It works fine in IE7+8, but in IE6, if the user clicks on a SELECT and does not click any OPTION but instead clicks somewhere else on the page, outside the SELECT (blur), the SELECT still has a "highlight", the same as if they were hovering over an OPTION with my mouse (in my case, a blue color), and the width is not restored until the user clicks outside the SELECT a second time. In other browsers, blur causes every OPTION to not be highlighted. Using JS, how can I de-highlight an option after the dropdown has lost focus.

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  • jQuery remove SELECT options based on another SELECT selected on change and on load

    - by John Sieber
    I'm using the following jQuery code to remove options from a select and it is working well. But instead of it only executing when the theOption2 select is changed I would also like it to work when the page is loaded depending on the selected item that is selected. I tried using the a copy of the script and changing the .change to .load and also tried using (window).load without the desired results. Essentially, I need the script to execute on change of the Options1 and on the loading of the page. Any help with this would be greatly appreciated. <script type="text/javascript"> $(document).ready(function() { //copy the second select, so we can easily reset it var selectClone = $('#theOptions2').clone(); $('#theOptions1').change(function() { var val = parseInt($(this).val()); //reset the second select on each change $('#theOptions2').html(selectClone.html()) switch(val) { //if 2 is selected remove C case 2 : $('#theOptions2').find('option:contains(c)').remove();break; //if 3 is selected remove A case 3 : $('#theOptions2').find('option:contains(a)').remove();break; } }); }); </script> <select id="theOptions1"> <option value="1">1</option> <option value="2" selected="selected">2</option> <option value="3">3</option> </select> <br /> <select id="theOptions2"> <option>a</option> <option>b</option> <option>c</option> </select>

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  • Dropdown not working in some IE 6 browsers

    - by James Thomas
    We unfortunately find ourselves having to support our product in IE 6 because some of our largest users use it. One of them called today and told me that one of the dropdowns doesn't work when he clicks on it - it simply selects the first item. I checked the markup and the entire contents of the select control are being sent: <select onchange="SDateFilter_S('#ctlDateRange')" size="1" name="ctlDateRange" style="width:100px;"> <option selected="selected" value="0"> All Dates </option><option value="1"> Within </option><option value="2"> Before </option><option value="3"> After </option><option value="4"> Between </option><option value="5"> Last </option><option value="6"> Since </option> </select> This is done in ASP .NET but I am fairly certain the issue isn't with ASP .NET as when I try it in my copy of IE 6, it works correctly. Do you have any idea what would cause a dropdown list in some copies of IE 6 to effectively not work?

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  • html escape characters

    - by user1468537
    I have the following: <form name="input" method="get" action="http://site:8083/Default.aspx?DC=" target="foo" onSubmit="window.open('', 'foo', 'width=1100 height=500,status=no,resizable=yes,scrollbars=yes')"> <select name="DC"> <option value="1&Type=type1">1</option> <option value="2&Type=type2">2</option> <option value="3&Type=type3">3</option> <option value="4&Type=type4">4</option> <option value="5&Type=type5">5</option> <option value="6&Type=type6">6</option> <option value="7&Type=type7">7</option> </select> <input type="submit" value=">>"/>&nbsp;&nbsp; </form> Basically my querystring should be something like DC=1&Type=type1 the problem I have is that when I click the button above the html screws up the stirng by changing & to %26 and = to %3D How can I make the value stay as I have it in the code above?

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  • listbox select count not work dont work

    - by sadpcd
    I recently trying to make a form with multiple select box. When someone select the options the number of selected options will be display on another text. I'm a beginner in JavaScript. The function is called, but it doesn't count the number of the selected options. <select name="element_17_1[ ]" size="7" multiple="multiple" class="element select medium" id="element_17_1[ ]" onfocus="selectCount(this.form);" onClick="selectCount(this.form);" > <option value="Opt1">Opt1</option> <option value="Opt2">Opt2</option> <option value="Opt3">Opt3</option> <option value="Opt4">Opt4</option> <option value="Opt5">Opt5</option> <option value="Opt6">Opt6</option> <option value="Opt7">Opt7</option> </select> and this is the function I tried in the <head> function selectCount(f) { var selObj = myForm.elements['element_17_1[]']; var totalChecked = 0; for (i = 0; i < selObj.options.length; i++) { if (selObj.options[i].selected) { totalChecked++; } } f.element_9.value = totalChecked; }

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  • jQuery Mobile and Select menu with URLs

    - by user1907347
    Been battling with this for a while now. I'm trying to get a select menu to work as a navigation menu but I cannot get the URLs to work and have it actually change pages. In the head: <script> $(function() { $("#select-choice-1").click(function() { $.mobile.changePage($("#select-choice-1")); }); }); </script> With this Menu: <div id="MobileWrapper" data-role="fieldcontain"> <select name="select-choice-1" id="select-choice-1" data-theme="a" data-form="ui-btn-up-a" data-mini="true"> <option data-placeholder="true">Navigation</option><!-- data=placeholder makes this not show up in the pop up--> <option value="/index.php" data-ajax="false">Home</option> <option value="/services/index.php" data-ajax="false">Services</option> <option value="/trainers/index.php" data-ajax="false">Trainers</option> <option value="/locations/index.php" data-ajax="false">Locations</option> <option value="/calendar/index.php" data-ajax="false">Calendar</option> <option value="/contactus/index.php" data-ajax="false">Contact Us</option> </select> </div><!--END MobileWrapper DIV-->

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  • Submiting a Form without Refreshing the page with jQuery and Ajax Not updating MySQL database.

    - by HEEEEEEELP
    I'm a newbie to JQuery and have a problem, when I click submit button on the form everything says registration was successful but my MYSQL database was not updated everything worked fine until I tried to add the JQuery to the picture. Can someone help me fix this problem so my database is updated? Thanks Here is the JQuery code. $(function() { $(".save-button").click(function() { var address = $("#address").val(); var address_two = $("#address_two").val(); var city_town = $("#city_town").val(); var state_province = $("#state_province").val(); var zipcode = $("#zipcode").val(); var country = $("#country").val(); var email = $("#email").val(); var dataString = 'address='+ address + '&address_two=' + address_two + '&city_town=' + city_town + '&state_province=' + state_province + '&zipcode=' + zipcode + '&country=' + country + '$email=' + email; if(address=='' || address_two=='' || city_town=='' || state_province=='' || zipcode=='' || country=='' || email=='') { $('.success').fadeOut(200).hide(); $('.error').fadeOut(200).show(); } else { $.ajax({ type: "POST", url: "http://localhost/New%20Project/home/index.php", data: dataString, success: function(){ $('.success').fadeIn(200).show(); $('.error').fadeOut(200).hide(); } }); } return false; }); }); Here is the PHP code. if (isset($_POST['contact_info_submitted'])) { // Handle the form. // Query member data from the database and ready it for display $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT users.*, contact_info.* FROM users INNER JOIN contact_info ON contact_info.user_id = users.user_id WHERE users.user_id=3"); $user_id = mysqli_real_escape_string($mysqli, htmlentities('3')); $address = mysqli_real_escape_string($mysqli, htmlentities($_POST['address'])); $address_two = mysqli_real_escape_string($mysqli, htmlentities($_POST['address_two'])); $city_town = mysqli_real_escape_string($mysqli, htmlentities($_POST['city_town'])); $state_province = mysqli_real_escape_string($mysqli, htmlentities($_POST['state_province'])); $zipcode = mysqli_real_escape_string($mysqli, htmlentities($_POST['zipcode'])); $country = mysqli_real_escape_string($mysqli, htmlentities($_POST['country'])); $email = mysqli_real_escape_string($mysqli, strip_tags($_POST['email'])); //If the table is not found add it to the database if (mysqli_num_rows($dbc) == 0) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"INSERT INTO contact_info (user_id, address, address_two, city_town, state_province, zipcode, country, email) VALUES ('$user_id', '$address', '$address_two', '$city_town', '$state_province', '$zipcode', '$country', '$email')"); } //If the table is in the database update each field when needed if ($dbc == TRUE) { $dbc = mysqli_query($mysqli,"UPDATE contact_info SET address = '$address', address_two = '$address_two', city_town = '$city_town', state_province = '$state_province', zipcode = '$zipcode', country = '$country', email = '$email' WHERE user_id = '$user_id'"); } if (!$dbc) { // There was an error...do something about it here... print mysqli_error($mysqli); return; } } Here is the XHTML code. <form method="post" action="index.php"> <fieldset> <ul> <li><label for="address">Address 1: </label><input type="text" name="address" id="address" size="25" class="input-size" value="<?php if (isset($_POST['address'])) { echo $_POST['address']; } else if(!empty($address)) { echo $address; } ?>" /></li> <li><label for="address_two">Address 2: </label><input type="text" name="address_two" id="address_two" size="25" class="input-size" value="<?php if (isset($_POST['address_two'])) { echo $_POST['address_two']; } else if(!empty($address_two)) { echo $address_two; } ?>" /></li> <li><label for="city_town">City/Town: </label><input type="text" name="city_town" id="city_town" size="25" class="input-size" value="<?php if (isset($_POST['city_town'])) { echo $_POST['city_town']; } else if(!empty($city_town)) { echo $city_town; } ?>" /></li> <li><label for="state_province">State/Province: </label> <?php echo '<select name="state_province" id="state_province">' . "\n"; foreach($state_options as $option) { if ($option == $state_province) { echo '<option value="' . $option . '" selected="selected">' . $option . '</option>' . "\n"; } else { echo '<option value="'. $option . '">' . $option . '</option>'."\n"; } } echo '</select>'; ?> </li> <li><label for="zipcode">Zip/Post Code: </label><input type="text" name="zipcode" id="zipcode" size="5" class="input-size" value="<?php if (isset($_POST['zipcode'])) { echo $_POST['zipcode']; } else if(!empty($zipcode)) { echo $zipcode; } ?>" /></li> <li><label for="country">Country: </label> <?php echo '<select name="country" id="country">' . "\n"; foreach($countries as $option) { if ($option == $country) { echo '<option value="' . $option . '" selected="selected">' . $option . '</option>' . "\n"; } else if($option == "-------------") { echo '<option value="' . $option . '" disabled="disabled">' . $option . '</option>'; } else { echo '<option value="'. $option . '">' . $option . '</option>'."\n"; } } echo '</select>'; ?> </li> <li><label for="email">Email Address: </label><input type="text" name="email" id="email" size="25" class="input-size" value="<?php if (isset($_POST['email'])) { echo $_POST['email']; } else if(!empty($email)) { echo $email; } ?>" /><br /><span>We don't spam or share your email with third parties. We respect your privacy.</span></li> <li><input type="submit" name="submit" value="Save Changes" class="save-button" /> <input type="hidden" name="contact_info_submitted" value="true" /> <input type="submit" name="submit" value="Preview Changes" class="preview-changes-button" /></li> </ul> </fieldset> </form>

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  • Set selected using jQuery

    - by Charles Marsh
    Evening All, Happy new year! I'm trying to change the selected option within this list.. Its only working for some and not others? selectedVal will either be Kelly Green, Navy etc... var selectedVal = $(this).text(); $("#product-variants-option-0 option[text=" + selectedVal+"]").attr("selected","selected") ; This is the select list: <select class="single-option-selector" id="product-variants-option-0"> <option value="Gunmetal Heather">Gunmetal Heather</option> <option value="Kelly Green">Kelly Green</option> <option value="Navy">Navy</option> </select>

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  • PROBLEM: PHP strip_tags & multi-dimensional array form parameter

    - by Tunji Gbadamosi
    I'm having problems stripping the tags from the textual inputs retrieved from my form so as to do something with them in checkout.php. The input is stored in a multi-dimensional array. Here's my form: echo '<form name="choose" action="checkout.php" method="post" onsubmit="return validate_second_form(this);">'; echo '<input type="hidden" name="hidden_value" value="'.$no_guests.'" />'; if($no_guests >= 1){ echo '<div class="volunteer">'; echo '<fieldset>'; echo '<legend>Volunteer:</legend>'; echo '<label>Table:</label>'; echo '<select name="volunteer_table">'; foreach($tables as $t){ echo '<option>'.$t.'</option>'; } echo '</select><br><br>'; echo '<label>Seat number:</label>'; echo '<select name="volunteer_seat">'; foreach($seats as $seat){ echo '<option>'.$seat.'</option>'; } echo '</select><br><br>'; //echo '<br>'; echo '</fieldset>'; echo '</div>'; for($i=0;$i<$no_guests;$i++){ $guest = "guest_".$i; echo '<div class="'.$guest.'">'; echo '<fieldset>'; echo '<legend>Guest '.$i.':</legend>'; echo '<label>First Name:</label>'; echo '<input type="text" name="guest['.$i.']['.$first_name.']" id="fn'.$i.'">'; echo '<label>Surname:</label>'; echo '<input type="text" name="guest['.$i.']['.$surname.']" id="surname'.$i.'"><br><br>'; echo '<label>Date of Birth:</label> <br>'; echo '<label>Day:</label>'; echo '<select name="guest['.$i.'][dob_day]">'; for($j=1;$j<32;$j++){ echo"<option value='$j'>$j</option>"; } echo '</select>'; echo '<label>Month:</label>'; echo '<select name="guest['.$i.'][dob_month]">'; for($j=0;$j<sizeof($month);$j++){ $value = ($j + 1); echo"<option value='$value'>$month[$j]</option>"; } echo '</select>'; echo '<label>Year:</label>'; echo '<select name="guest['.$i.'][dob_year]">'; for($j=1900;$j<$year_limit;$j++){ echo"<option value='$j'>$j</option>"; } echo '</select> <br><br>'; echo '<label>Sex:</label>'; echo '<select name="guest['.$i.']['.$sex.']">'; echo '<option>Female</option>'; echo '<option>Male</option>'; echo '</select><br><br>'; echo '<label>Table:</label>'; echo '<select name="guest['.$i.']['.$table.']">'; foreach($tables as $t){ echo '<option>'.$t.'</option>'; } echo '</select><br><br>'; echo '<label>Seat number:</label>'; echo '<select name="guest['.$i.']['.$seat_no.']">'; foreach($seats as $seat){ echo '<option>'.$seat.'</option>'; } echo '</select><br><br>'; //echo '<br>'; echo '</fieldset>'; echo '</div>'; } } else{ echo '<div id="volunteer">'; echo '<fieldset>'; echo '<legend>Volunteer:</legend>'; echo '<label>Table:</label>'; echo '<select name="volunteer['.$table.']">'; foreach($tables as $t){ echo '<option>'.$t.'</option>'; } echo '</select><br><br>'; echo '<label>Seat number:</label>'; echo '<select name="volunteer['.$seat_no.']">'; foreach($seats as $seat){ echo '<option>'.$seat.'</option>'; } echo '</select><br><br>'; //echo '<br>'; echo '</fieldset>'; echo '</div>'; } echo '<input type="submit" value="Submit form">'; echo '</form>'; here's checkout.php: if(isset($_POST['guest'])){ foreach($_POST['guest'] as $guest){ $guest['first_name'] = strip_tags($guest['first_name']); $guest['surname'] = strip_tags($guest['surname']); } //$_SESSION['guest'] = $guests; }

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  • jquery: how to append elements to emtpy object

    - by John
    I want to create a set of options, that will be appended to every select in grid column <option> option 1 </option> <option> option 2 </option> ... <option> option N </option> but I don't know how to create a set of elements without parent element. appending to an empty jquery object doesn't work var options = $(''); options.append('<option></option>')

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  • printing menu in terminal and choosing an option, how to?

    - by carlos
    I'm a haskell beginner. I'm trying to make a program that shows a menu through terminal and ask user to introduce an option. Here is the code: main :: IO () main = do putStrLn "0 <- quit" putStrLn "1 <- Hello" putStr "Choose an option: " c <- getChar case c of '0' -> return () '1' -> putChar '\n' >> putStrLn "Hello World" >> main When I use this module in the ghci interpreter everything works like it's suposed to do. But if i compile this with: ghc hello.hs and run it in the terminal, it doesn't display the line "Choose an option:" before ask for a char to be introduced. I think this may be caused because of haskell lazy nature and I don't know how to fix it. Any ideas?

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  • php drop down how to control the hide and show

    - by user329394
    Hi all, i want to control the drop down box to control show or hide statement. I do like this but it seems it doesn't work, i have it working if im using radio button. can help me with the code? which part am i wrong? thank you. $dbcnx = mysql_connect('localhost', 'root', ''); mysql_select_db('dbase'); if($_POST['gred'])$gred=$_POST['gred'];else $gred=""; <script language="JavaScript"> function funcHide(elemHide1,elemHide2,elemHide3) { document.getElementById(elemHide1).style.display = 'none'; document.getElementById(elemHide2).style.display = 'none'; document.getElementById(elemHide3).style.display = 'none'; document.getElementById(elemShow).style.visibility = 'visible'; } function funcShow(elemShow1,elemShow2,elemShow3) { document.getElementById(elemShow1).style.display = 'block'; document.getElementById(elemShow2).style.display = 'block'; document.getElementById(elemShow3).style.display = 'block'; document.getElementById(elemShow1).style.visibility = 'visible'; document.getElementById(elemShow2).style.visibility = 'visible'; document.getElementById(elemShow3).style.visibility = 'visible'; } </script> <table> <tr> <td>Gred </td> <td>:</td> <td><select name="gred" id="gred"> <option value="">&nbsp;</option> <option value="A17" <?php if($gred=='A17')echo "selected";?> onClick="funcShow('box1', 'box2', 'box3');">A17</option> <option value="A22" <?php if($gred=='A22')echo "selected";?>>A22</option> <option value="A27" <?php if($gred=='A27')echo "selected";?>>A27</option> </select> </td> </tr> <tr> <td>TK</td> <td>:</td> <td> <select name="tk" id="tk"> <option value="">&nbsp;</option> <option value="01" <?php if($tk=='01')echo "selected";?>>01</option> <option value="02" <?php if($tk=='02')echo "selected";?>>02</option> <option value="03" <?php if($tk=='03')echo "selected";?>>03</option> <option value="04" <?php if($tk=='04')echo "selected";?>>04</option> <option value="05" <?php if($tk=='05')echo "selected";?>>05</option> <option value="06" <?php if($tk=='06')echo "selected";?>>06</option> </select> <?} ?> </td> </tr> <tr> <td colspan="2" valign="top">Status</td> <td valign="top">:</td> <td> <?php $qry = "SELECT * from dtable where userid='".$USER->id."'"; $sql = mysql_query($qry); $row = mysql_num_rows($sql); if($row==0) { ?> <input type=radio name="status" <?php if($status=='retake') {?>checked="checked"<?php } ?> value="retake" onClick="funcShow('box1', 'box2', 'box3');">Retake<br /></tr> <tr> <td colspan='2'> <div id="box1" style="display: none;">Last Date <br> Latest Date<br> </div></td> <td><div id="box2" style="display: none;">: <br> : <br></div></td> <td> <div id="box3" style="display: none;"> <?php $rsu[lastdate] ?> <br> <?php $rsu[latestdate] ?> </div> </td>

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  • vCenter 5.1 SSO Configuration option not available in Web Client?

    - by goober
    Problem I just finished separately installing vCenter Server 5.1. I installed the components separately but on the same machine using a local SQL 2008 R2 DB (not SQL express). Everything appears to be working correctly with the exception of SSO. It doesn't find the AD server. This is to be expected (see below) but I don't know how to fix it. Potential Leads / Steps taken During the install of SSO, I was logged on as a local administrator (waiting on central IT dept to create a service account). As a result, I received a message saying that SSO wouldn't be able to automatically locate the AD. (fair eonugh) After I read up on it a little bit, I believed I could go into the SSO Configuration option in the Web client, like so: However, what I actually see is: I also notice that the "SSO Users and Groups" entry is not there. Betting that has something to do with it as well. Question How can I get the "Configure" Option to show up for SSO? Overall goal: How can I manually enter the AD server in this scenario while logged in as a local administrator? References VMWare vCenter 5.1 Installation: Part 9 (Optional SSO Configuration) [Derek Seaman's Blog] (used the image of correct configuration menu)

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  • Why Virtual Box won't give me option to create 64 bits guests?

    - by Eduardo Born
    My host is x64 bits Windows 8.1. I downloaded the latest Virtual Box (4.3) and I'm trying to create a VM with a 64 bits Ubuntu OS (ubuntu-12.04.3-desktop-amd64). When I go to New VM wizard, it doesn't give me option to select "Ubuntu (x64)" as I have seen in other people's screenshots, only just "Ubuntu". As a result, the ISO can't boot. I tried in another PC and Virtual Box gives the x64 variants to most listed OS... Control Panel shows x64 OS, x64 processor. My host laptop is a Sony Vaio VPCZ22UGX/N, Intel® Core™ i7-2640M processor. CPUz shows Vx-t is available on my processor, of course. Here is what I tried so far: I enabled IO APIC as required in the docs. I have virtualization enabled in the BIOS. It works fine in VMware. Check that Hyper-V is not running or even installed on my Windows. Same for VMware. I also tried running the command: VBoxManage modifyvm [vmname] --longmode on for that VM, but no change.. I think the issue is really that I can't select x64 variant of the Ubuntu OS for that VM. Other people seem to indicate that's a requirement, but I don't get that option for some reason. I spent a lot of time and can't find what's wrong... Anyone knows what could be missing here? Thank you very much!! Eduardo

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  • Retreiving multiple rows from a loop-created form... Stuck.

    - by hangston
    Hi All, Let me start by saying that I'm new to PHP, but I'm here to learn and would really appreciate your help. I use the following code to pull in data and create a form. This creates up to 40 lines for a user to fill out. Each line consists of the same information: Description, Amount, and Frequency. The remainder of the information needed is generated by the database. (See hidden fields) <?php $row = 0; do { $optid = $row_options['option_id']; echo "<tr>\n\t<td>" . htmlentities($row_options['option']) . "</td>\n"; echo "\t<td>" . "<input name='description' type='text' size='40' maxlength='120'/>" . "</td>\n"; echo "\t<td>" . "<input name='option_id' type='hidden' value='$optid' />$<input name='amount' type='text' size='10' maxlength='7'/>" . "</td>\n"; echo "\t<td>" . "<select name='assisted_frequency'> <option value='Monthly'>Monthly</option> <option value='Weekly'>Weekly</option> <option value='Daily'>Daily</option> <option value='Hourly'>Hourly</option> <option value='One-Time'>One-Time</option> </select>" . "</td>\n</tr>\n"; $array[$row] = array( $arraydesc[$row] = $_POST['description'], $arrayamto[$row] = $_POST['amount'], $arrayoptid[$row] = $optid, $arrayfreq[$row] = $_POST['frequency'], ); $row ++; } while ($row_options = mysql_fetch_assoc($options)); $counter = $row - 1; ?> I'm having troubles retrieving the information that the user inputs. My intent is to loop through each row after the user has input their information, then upload the mix of my database information and the user's information into another database. For example, the user would see, albeit prettier: form1 Option 1: description [input box] amount [input box] frequency [option box] Option 2: description [input box] amount [input box] frequency [option box] Option 3: description [input box] amount [input box] frequency [option box] Option 4: description [input box] amount [input box] frequency [option box] submit Upon submitting the form above, I'm using a query similar to the following to input the data into the database: for($row=0; $row<=$counter; $row++){ $insertSQL2 = sprintf("INSERT INTO table (option_id, amount, description, frequency) VALUES (%s, %s, %s, %s)", GetSQLValueString($arrayoptid[$row], "int"), GetSQLValueString($arrayamto[$row], "int"), GetSQLValueString($arraydesc[$row], "text"), GetSQLValueString($arrayfreq[$row], "text")); // code to submit query } I've tried for, foreach, arrays (what feels like the everything I know) to post each row (row by row) into the database. I either get just the last row of data, or no data at all. I also worry that the [$row] technique is adding characters to my data. What is the best way to retrieve each row of the user's inputs, then upload this data (row by row) into the database? Also, I would really appreciate your suggestions for improving my coding technique and the approach I'm taking. Thank you, Hangston

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  • Retrieving multiple rows from a loop-created form... Stuck.

    - by hangston
    Let me start by saying that I'm new to PHP, but I'm here to learn and would really appreciate your help. I use the following code to pull in data and create a form. This creates up to 40 lines for a user to fill out. Each line consists of the same information: Description, Amount, and Frequency. The remainder of the information needed is generated by the database. (See hidden fields) <?php $row = 0; do { $optid = $row_options['option_id']; echo "<tr>\n\t<td>" . htmlentities($row_options['option']) . "</td>\n"; echo "\t<td>" . "<input name='description' type='text' size='40' maxlength='120'/>" . "</td>\n"; echo "\t<td>" . "<input name='option_id' type='hidden' value='$optid' />$<input name='amount' type='text' size='10' maxlength='7'/>" . "</td>\n"; echo "\t<td>" . "<select name='assisted_frequency'> <option value='Monthly'>Monthly</option> <option value='Weekly'>Weekly</option> <option value='Daily'>Daily</option> <option value='Hourly'>Hourly</option> <option value='One-Time'>One-Time</option> </select>" . "</td>\n</tr>\n"; $array[$row] = array( $arraydesc[$row] = $_POST['description'], $arrayamto[$row] = $_POST['amount'], $arrayoptid[$row] = $optid, $arrayfreq[$row] = $_POST['frequency'], ); $row ++; } while ($row_options = mysql_fetch_assoc($options)); $counter = $row - 1; ?> I'm having troubles retrieving the information that the user inputs. My intent is to loop through each row after the user has input their information, then upload the mix of my database information and the user's information into another database. For example, the user would see, albeit prettier: form1 Option 1: description [input box] amount [input box] frequency [option box] Option 2: description [input box] amount [input box] frequency [option box] Option 3: description [input box] amount [input box] frequency [option box] Option 4: description [input box] amount [input box] frequency [option box] submit Upon submitting the form above, I'm using a query similar to the following to input the data into the database: for($row=0; $row<=$counter; $row++){ $insertSQL2 = sprintf("INSERT INTO table (option_id, amount, description, frequency) VALUES (%s, %s, %s, %s)", GetSQLValueString($arrayoptid[$row], "int"), GetSQLValueString($arrayamto[$row], "int"), GetSQLValueString($arraydesc[$row], "text"), GetSQLValueString($arrayfreq[$row], "text")); // code to submit query } I've tried for, foreach, arrays (what feels like the everything I know) to post each row (row by row) into the database. I either get just the last row of data, or no data at all. I also worry that the [$row] technique is adding characters to my data. What is the best way to retrieve each row of the user's inputs, then upload this data (row by row) into the database? Also, I would really appreciate your suggestions for improving my coding technique and the approach I'm taking.

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  • Vlc And other Multi Media Problems

    - by MrMagu
    ive tried numerous Free Multimedia Programs on ubuntu and i get the same result when i go to watch one of my movies off my other hardrive it allways ends up full screening with a stuck image in the middle and vlc ends up looking pitch black. ive look all over the web for this issue im wondering if anyone is experinceing the same problems I Dont know if it has to do with the duel monitors ive tried adding and re adding the repositorys but it seems to be doing the same repetive thing for over a month now do i need to reinstall the whole system or what idk anyhelp please would be much appreciated Ty MrMagu Xorg Conf File nvidia-settings: X configuration file generated by nvidia-settings nvidia-settings: version 304.37 (buildd@allspice) Sun Sep 9 05:59:26 UTC 2012 Section "ServerLayout" Identifier "Layout0" Screen 0 "Screen0" 0 0 InputDevice "Keyboard0" "CoreKeyboard" InputDevice "Mouse0" "CorePointer" Option "Xinerama" "0" EndSection Section "Files" EndSection Section "InputDevice" # generated from default Identifier "Mouse0" Driver "mouse" Option "Protocol" "auto" Option "Device" "/dev/psaux" Option "Emulate3Buttons" "no" Option "ZAxisMapping" "4 5" EndSection Section "InputDevice" # generated from default Identifier "Keyboard0" Driver "kbd" EndSection Section "Monitor" # HorizSync source: edid, VertRefresh source: edid Identifier "Monitor0" VendorName "Unknown" ModelName "Ancor Communications Inc VE247" HorizSync 30.0 - 83.0 VertRefresh 50.0 - 76.0 Option "DPMS" EndSection Section "Monitor" Identifier "Monitor1" VendorName "Unknown" ModelName "Ancor Communications Inc VE247" HorizSync 30.0 - 83.0 VertRefresh 50.0 - 76.0 EndSection Section "Device" Identifier "Device0" Driver "nvidia" VendorName "NVIDIA Corporation" BoardName "Quadro FX 1500" EndSection Section "Device" Identifier "Device1" Driver "nvidia" VendorName "NVIDIA Corporation" BoardName "Quadro FX 1500" BusID "PCI:1:0:0" Screen 1 EndSection Section "Screen" Removed Option "metamodes" "DFP-0: nvidia-auto-select +0+0, DFP-1: nvidia-auto-select +1920+0; DFP-0: 1920x1080 +0+0, DFP-1: 1920x1080 +1920+0" Removed Option "metamodes" "DFP-0: nvidia-auto-select +0+0; DFP-0: 1920x1080 +0+0; DFP-0: 1920x1080_60 +0+0; DFP-0: 1680x1050 +0+0; DFP-0: 1680x1050_60 +0+0; DFP-0: 1440x900 +0+0; DFP-0: 1440x900_60 +0+0; DFP-0: 1280x1024 +0+0; DFP-0: 1280x1024_75 +0+0; DFP-0: 1280x1024_60 +0+0; DFP-0: 1280x960 +0+0; DFP-0: 1280x960_60 +0+0; DFP-0: 1152x864 +0+0; DFP-0: 1152x864_75 +0+0; DFP-0: 1024x768 +0+0; DFP-0: 1024x768_75 +0+0; DFP-0: 1024x768_70 +0+0; DFP-0: 1024x768_60 +0+0; DFP-0: 800x600 +0+0; DFP-0: 800x600_75 +0+0; DFP-0: 800x600_72 +0+0; DFP-0: 800x600_60 +0+0; DFP-0: 800x600_56 +0+0; DFP-0: 640x480 +0+0; DFP-0: 640x480_75 +0+0; DFP-0: 640x480_72 +0+0; DFP-0: 640x480_60 +0+0; DFP-0: nvidia-auto-select @1920x720 +0+0" Removed Option "metamodes" "DFP-0: nvidia-auto-select +0+0; DFP-0: 1920x1080 +0+0; DFP-0: 1920x1080_60 +0+0; DFP-0: 1680x1050 +0+0; DFP-0: 1680x1050_60 +0+0; DFP-0: 1440x900 +0+0; DFP-0: 1440x900_60 +0+0; DFP-0: 1280x1024 +0+0; DFP-0: 1280x1024_75 +0+0; DFP-0: 1280x1024_60 +0+0; DFP-0: 1280x960 +0+0; DFP-0: 1280x960_60 +0+0; DFP-0: 1152x864 +0+0; DFP-0: 1152x864_75 +0+0; DFP-0: 1024x768 +0+0; DFP-0: 1024x768_75 +0+0; DFP-0: 1024x768_70 +0+0; DFP-0: 1024x768_60 +0+0; DFP-0: 800x600 +0+0; DFP-0: 800x600_75 +0+0; DFP-0: 800x600_72 +0+0; DFP-0: 800x600_60 +0+0; DFP-0: 800x600_56 +0+0; DFP-0: 640x480 +0+0; DFP-0: 640x480_75 +0+0; DFP-0: 640x480_72 +0+0; DFP-0: 640x480_60 +0+0" Identifier "Screen0" Device "Device0" Monitor "Monitor0" DefaultDepth 24 Option "TwinView" "1" Option "TwinViewXineramaInfoOrder" "DFP-0" Option "Stereo" "0" Option "nvidiaXineramaInfoOrder" "DFP-0" Option "metamodes" "DFP-0: nvidia-auto-select +0+0, DFP-1: 1920x1080 +1920+0; DFP-0: 1920x1080 +0+0, DFP-1: nvidia-auto-select +1920+0; DFP-0: 1920x1080_60 +0+0; DFP-0: 1680x1050 +0+0; DFP-0: 1680x1050_60 +0+0; DFP-0: 1440x900 +0+0; DFP-0: 1440x900_60 +0+0; DFP-0: 1280x1024 +0+0; DFP-0: 1280x1024_75 +0+0; DFP-0: 1280x1024_60 +0+0; DFP-0: 1280x960 +0+0; DFP-0: 1280x960_60 +0+0; DFP-0: 1152x864 +0+0; DFP-0: 1152x864_75 +0+0; DFP-0: 1024x768 +0+0; DFP-0: 1024x768_75 +0+0; DFP-0: 1024x768_70 +0+0; DFP-0: 1024x768_60 +0+0; DFP-0: 800x600 +0+0; DFP-0: 800x600_75 +0+0; DFP-0: 800x600_72 +0+0; DFP-0: 800x600_60 +0+0; DFP-0: 800x600_56 +0+0; DFP-0: 640x480 +0+0; DFP-0: 640x480_75 +0+0; DFP-0: 640x480_72 +0+0; DFP-0: 640x480_60 +0+0" SubSection "Display" Depth 24 EndSubSection EndSection Section "Screen" Identifier "Screen1" Device "Device1" Monitor "Monitor1" DefaultDepth 24 Option "Stereo" "0" Option "metamodes" "DFP-1: 1920x1080 +0+0" SubSection "Display" Depth 24 EndSubSection EndSection Section "InputClass" Identifier "Mouse Remap" MatchProduct "Saitek Cyborg R.A.T.7 Mouse" MatchDevicePath "/dev/input/event*" Option "ButtonMapping" "1 2 3 4 5 6 7 8 9 0 0 0 0 0 0" EndSection Pictures http://tinypic.com/r/34o7j1h/6 http://tinypic.com/r/3rn20/6 Ty so Much Mr Magu

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  • Multi Monitor Setup Problems

    - by Shamballa
    I have Ubuntu 10.04 LTS - the Lucid Lynx. I have until recently been using a nVida Graphics card (NVIDIA GeForce 9800 GT) with two monitors attached, this all worked fine and dandy. A couple of days ago I bought two new identical LCD monitors for a multi monitor setup and two ATI graphics cards (ATI Sapphire Radeon HD5450). NOTE *All monitors work fine in Windows XP, 2k, Vista and 7 After I had booted into Ubuntu only one display came on, that I kind of expected anyway, then I removed the driver for the nVidia card and downloaded the ATI version which gave me the ATI Catalyst Control Center - in that only two of the displays were showing the third was disabled and showing unknown driver. I enabled the third monitor that stated "Unkown Driver" and had to reboot, upon reboot none of the displays work. I restarted and booted up into recovery mode and from now that is only what I can get into using a failsafe driver. It seems according to the log that a server is already active for Display 0 and I have to remove /tmp/.X0-lock and start again. This is what the log file is saying: Fatal Server Error Server is already active for display 0 if this server is no longer running, remove /tmp/.X0-lock and start again. (WW) xf86 closeconsole: KDSETMODE failed: Bad file descriptor (WW) xf86 closeconsole: VT_GETMODE failed: Bad file descriptor (WW) xf86 closeconsole: VT_GETSTATE failed: Bad file descriptor ddxSigGiveUp: closing log I have tried looking at my xorg.config file but unfortunately I have not really got a clue as to how it "should" be - I have tried regenerating it using this command from a terminal: sudo dpkg-reconfigure -phigh xserver-xorg but that had no effect so I am currently stuck in failsafe driver mode but two monitors are active but are mirroring each other. I hope that this is not to long - looking back I have been going on a bit! but I am just trying to explain as much as I can... I have asked this on Linuxquestions but nobody seems to know either or at least I have not had any responses. Could some kind soul please help explain what I can do from here? I would be eternally grateful. Chris * Update * Removing xorg.conf does nothing other than allowing me to use only two monitors - using the command: sudo aticonfig --initial generates the xorg.conf file below: but does not work either - I just get two monitors... Section "ServerLayout" Identifier "aticonfig Layout" Screen 0 "aticonfig-Screen[0]-0" 0 0 EndSection Section "Files" EndSection Section "Module" EndSection Section "Monitor" Identifier "aticonfig-Monitor[0]-0" Option "VendorName" "ATI Proprietary Driver" Option "ModelName" "Generic Autodetecting Monitor" Option "DPMS" "true" EndSection Section "Device" Identifier "aticonfig-Device[0]-0" Driver "fglrx" BusID "PCI:1:0:0" EndSection Section "Screen" Identifier "aticonfig-Screen[0]-0" Device "aticonfig-Device[0]-0" Monitor "aticonfig-Monitor[0]-0" DefaultDepth 24 SubSection "Display" Viewport 0 0 Depth 24 EndSubSection EndSection I have tried using this command from a thread on the Ubuntu Forums with a question similar to mine: sudo aticonfig --initial=dual-head --adapter=all Generated xorg.conf file Section "ServerLayout" Identifier "aticonfig Layout" Screen 0 "aticonfig-Screen[0]-0" 0 0 Screen "aticonfig-Screen[0]-1" RightOf "aticonfig-Screen[0]-0" Screen "aticonfig-Screen[1]-0" RightOf "aticonfig-Screen[0]-1" Screen "aticonfig-Screen[1]-1" RightOf "aticonfig-Screen[1]-0" EndSection Section "Files" EndSection Section "Module" EndSection Section "Monitor" Identifier "aticonfig-Monitor[0]-0" Option "VendorName" "ATI Proprietary Driver" Option "ModelName" "Generic Autodetecting Monitor" Option "DPMS" "true" EndSection Section "Monitor" Identifier "aticonfig-Monitor[0]-1" Option "VendorName" "ATI Proprietary Driver" Option "ModelName" "Generic Autodetecting Monitor" Option "DPMS" "true" EndSection Section "Monitor" Identifier "aticonfig-Monitor[1]-0" Option "VendorName" "ATI Proprietary Driver" Option "ModelName" "Generic Autodetecting Monitor" Option "DPMS" "true" EndSection Section "Monitor" Identifier "aticonfig-Monitor[1]-1" Option "VendorName" "ATI Proprietary Driver" Option "ModelName" "Generic Autodetecting Monitor" Option "DPMS" "true" EndSection Section "Device" Identifier "aticonfig-Device[0]-0" Driver "fglrx" BusID "PCI:1:0:0" EndSection Section "Device" Identifier "aticonfig-Device[0]-1" Driver "fglrx" BusID "PCI:1:0:0" Screen 1 EndSection Section "Device" Identifier "aticonfig-Device[1]-0" Driver "fglrx" BusID "PCI:2:0:0" EndSection Section "Device" Identifier "aticonfig-Device[1]-1" Driver "fglrx" BusID "PCI:2:0:0" Screen 1 EndSection Section "Screen" Identifier "aticonfig-Screen[0]-0" Device "aticonfig-Device[0]-0" Monitor "aticonfig-Monitor[0]-0" DefaultDepth 24 SubSection "Display" Viewport 0 0 Depth 24 EndSubSection EndSection Section "Screen" Identifier "aticonfig-Screen[0]-1" Device "aticonfig-Device[0]-1" Monitor "aticonfig-Monitor[0]-1" DefaultDepth 24 SubSection "Display" Viewport 0 0 Depth 24 EndSubSection EndSection Section "Screen" Identifier "aticonfig-Screen[1]-0" Device "aticonfig-Device[1]-0" Monitor "aticonfig-Monitor[1]-0" DefaultDepth 24 SubSection "Display" Viewport 0 0 Depth 24 EndSubSection EndSection Section "Screen" Identifier "aticonfig-Screen[1]-1" Device "aticonfig-Device[1]-1" Monitor "aticonfig-Monitor[1]-1" DefaultDepth 24 SubSection "Display" Viewport 0 0 Depth 24 EndSubSection EndSection This upon reboot renders ALL monitors blank and I have to go into recovery mode and use a failsafe driver. This is so much harder than I thought it would be, I don't think Ubuntu likes ATI for multi (3) monitors or maybe the other way around. Can anyone help still?

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  • How to create filter option in RDLC report column ?

    - by prasanna
    I wanted to have filter option (like the one available in Excel sheet) in rdlc report column. is it possible and how ? http://img62.imageshack.us/img62/2223/sample1n.png i am trying in Visual studio 2005 and Microsoft report viewer. kindly let me know the option for this or a work around for it. Thanks

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