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  • Unix: millionth number in the serie 2 3 4 6 9 13 19 28 42 63 ... ?

    - by HH
    It takes about minute to achieve 3000 in my comp but I need to know the millionth number in the serie. The definition is recursive so I cannot see any shortcuts except to calculate everything before the millionth number. How can you fast calculate millionth number in the serie? Serie Def n_{i+1} = \floor{ 3/2 * n_{i} } and n_{0}=2. Interestingly, only one site list the serie according to Goolge: this one. Too slow Bash code #!/bin/bash function serie { n=$( echo "3/2*$n" | bc -l | tr '\n' ' ' | sed -e 's@\\@@g' -e 's@ @@g' ); # bc gives \ at very large numbers, sed-tr for it n=$( echo $n/1 | bc ) #DUMMY FLOOR func } n=2 nth=1 while [ true ]; #$nth -lt 500 ]; do serie $n # n gets new value in the function throught global value echo $nth $n nth=$( echo $nth + 1 | bc ) #n++ done

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  • Stuck with luasec LUA secure socket

    - by PeterMmm
    This example code fails: require("socket") require("ssl") -- TLS/SSL server parameters local params = { mode = "server", protocol = "sslv23", key = "server.key", certificate = "server.crt", cafile = "server.key", password = "123456", verify = {"peer", "fail_if_no_peer_cert"}, options = {"all", "no_sslv2"}, ciphers = "ALL:!ADH:@STRENGTH", } local socket = require("socket") local server = socket.bind("*", 8888) local client = server:accept() client:settimeout(10) -- TLS/SSL initialization local conn,emsg = ssl.wrap(client, params) print(emsg) conn:dohandshake() -- conn:send("one line\n") conn:close() request https://localhost:8888/ output error loading CA locations ((null)) lua: a.lua:25: attempt to index local 'conn' (a nil value) stack traceback: a.lua:25: in main chunk [C]: ? Not very much info. Any idea how to trace down to the problem ?

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  • Use one Socket to send and recieve data

    - by volody
    What makes more sense? use one socket to send and receive data to/from a embedded hardware device use one socket to send data and separate socket to read data Communication is not very intensive but the important point is to receive data as fast as possible. On application side is used Windows XP and up.

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  • unix How to compare two files and get results to third file?

    - by Martin Mocik
    I have two files 1st file is like this: www.example.com www.domain.com www.otherexample.com www.other-domain.com www.other-example.com www.exa-ample.com 2nd file is like this (numbers after ;;; are between 0-10): www.example.com;;;2 www.domain.com;;;5 www.other-domain;;;0 www.exa-ample.com;;;4 and i want compare these two files and output to third file like this: www.otherexample.com www.other-example.com Both files have large size (over 500mb)

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  • PHP Socket Server vs node.js: Web Chat

    - by Eliasdx
    I want to program a HTTP WebChat using long-held HTTP requests (Comet), ajax and websockets (depending on the browser used). Userdatabase is in mysql. Chat is written in PHP except maybe the chat stream itself which could also be written in javascript (node.js): I don't want to start a php process per user as there is no good way to send the chat messages between these php childs. So I thought about writing an own socket server in either PHP or node.js which should be able to handle more then 1000 connections (chat users). As a purely web developer (php) I'm not much familiar with sockets as I usually let web server care about connections. The chat messages won't be saved on disk nor in mysql but in RAM as an array or object for best speed. As far as I know there is no way to handle multiple connections at the same time in a single php process (socket server), however you can accept a great amount of socket connections and process them successive in a loop (read and write; incoming message - write to all socket connections). The problem is that there will most-likely be a lag with ~1000 users and mysql operations could slow the whole thing down which will then affect all users. My question is: Can node.js handle a socket server with better performance? Node.js is event-based but I'm not sure if it can process multiple events at the same time (wouldn't that need multi-threading?) or if there is just an event queue. With an event queue it would be just like php: process user after user. I could also spawn a php process per chat room (much less users) but afaik there are singlethreaded IRC servers which are also capable to handle thousands of users. (written in c++ or whatever) so maybe it's also possible in php. I would prefer PHP over Node.js because then the project would be php-only and not a mixture of programming languages. However if Node can process connections simultaneously I'd probably choose it.

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  • C# socket blocking behavior

    - by Gearoid Murphy
    My situation is this : I have a C# tcp socket through which I receive structured messages consisting of a 3 byte header and a variable size payload. The tcp data is routed through a network of tunnels and is occasionally susceptible to fragmentation. The solution to this is to perform a blocking read of 3 bytes for the header and a blocking read of N bytes for the variable size payload (the value of N is in the header). The problem I'm experiencing is that occasionally, the blocking receive operation returns a partial packet. That is, it reads a volume of bytes less than the number I explicitly set in the receive call. After some debugging, it appears that the number of bytes it returns is equal to the number of bytes in the Available property of the socket before the receive op. This behavior is contrary to my expectation. If the socket is blocking and I explicitly set the number of bytes to receive, shouldn't the socket block until it recv's those bytes?, any help, pointers, etc would be much appreciated.

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  • UNIX FIFO: How to allow only one writer/reader pair to use a FIFO?

    - by Max Krug
    Hi! I've written two programs: the first, the "writer", creates a FIFO and writes data into it. The second one, the "reader" runs in background and looks for data in the FIFO. Once data is there, the reader reads it out. If I start e.g. two writers and two readers, they all can write/read into/from the same FIFO. How can I restrict it for 3rd and 4th readers/writers to use the FIFO and allow only one writer and one reader to use the FIFO? thanks a lot. -- kind regards, Max Krug

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  • Use one Socket for send and recieve data

    - by volody
    What makes more sense? use one socket to send and receive data to/from a embedded hardware device use one socket to send data and separate socket to read data Communication is not very intensive but the important point is to receive data as fast as possible. On application side is used Windows XP and up.

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  • Strange Java Socket Behavior (Connects, but Doesn't Send)

    - by Donald Campbell
    I have a fairly complex project that boils down to a simple Client / Server communicating through object streams. Everything works flawlessly for two consecutive connections (I connect once, work, disconnect, then connect again, work, and disconnect). The client connects, does its business, and then closes. The server successfully closes both the object output stream and the socket, with no IO errors. When I try to connect a third time, the connection appears to go through (the ServerSocket.accept() method goes through and an ObjectOutputStream is successfully created). No data is passed, however. The inputStream.readUnshared() method simply blocks. I have taken the following memory precautions: When it comes time to close the sockets, all running threads are stopped, and all objects are nulled out. After every writeUnshared() method call, the ObjectOutputBuffer is flushed and reset. Has anyone encountered a similar problem, or does anyone have any suggestions? I'm afraid my project is rather large, and so copying code is problematic. The project boils down to this: SERVER MAIN ServerSocket serverSocket = new ServerSocket(port); while (true) { new WorkThread(serverSocket.accept()).start(); } WORK THREAD (SERVER) public void run() { ObjectInputBuffer inputBuffer = new ObjectInputBuffer(new BufferedInputStream(socket.getInputStream())); while (running) { try { Object myObject = inputBuffer.readUnshared(); // do work is not specified in this sample doWork(myObject); } catch (IOException e) { running = false; } } try { inputBuffer.close(); socket.close(); } catch (Exception e) { System.out.println("Could not close."); } } CLIENT public Client() { Object myObject; Socket mySocket = new Socket(address, port); try { ObjectOutputBuffer output = new ObjectOutputBuffer(new BufferedOutputStream(mySocket.getOutputStream())); output.reset(); output.flush(); } catch (Exception e) { System.out.println("Could not get an input."); mySocket.close(); return; } // get object data is not specified in this sample. it simply returns a serializable object myObject = getObjectData(); while (myObject != null) { try { output.writeUnshared(myObject); output.reset(); output.flush(); } catch (Exception e) { e.printStackTrace(); break; } // catch } // while try { output.close(); socket.close(); } catch (Exception e) { System.out.println("Could not close."); } } Thank you to everyone who may be able to help!

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  • Socket - Adress already in use

    - by Hamza Karmouda
    I'm new to socketand i try to code an Server and client on the same application just to see how it work. here's my code : public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); ((Button)this.findViewById(R.id.bouton1)).setOnClickListener(this); } public void onClick(View v) { TCPServer server = new TCPServer(); TCPClient client = new TCPClient(); server.start(); client.start(); } public class TCPServer extends Thread { @Override public void run() { try { ServerSocket s = new ServerSocket(8080,0,InetAddress.getLocalHost()); Socket cli = s.accept(); byte[] b = new byte[512]; int n; InputStream is = cli.getInputStream(); while((n=is.read(b))>0){ Log.d("TCPServer",new String(b)); if(new String(b).contains("\r\n\r\n"))break; b = new byte[512]; } OutputStream os = cli.getOutputStream(); os.write("Hello".getBytes()); } catch (Exception e) { e.printStackTrace(); } } } public class TCPClient extends Thread { @Override public void run() { try { Socket s = new Socket(InetAddress.getLocalHost().getHostAddress(),8080); //Socket s = new Socket("www.google.com",80); //Log.i("",s.getLocalAddress().getHostAddress()); byte[] b = new byte[512]; int n; if (s.isConnected()) { OutputStream os = s.getOutputStream(); os.write("Hi How are you \r\n\r\n".getBytes()); InputStream is = s.getInputStream(); while((n=is.read(b))>0){ Log.d("TCPClient",new String(b)); b = new byte[512]; } } s.close(); } catch (Exception e) { e.printStackTrace(); } } } the code work fine but just for the first time i click my button. the error is java.net.BindException: Address already in use .

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  • [java] Threading socket handler for two sided communication in tcp port

    - by raven
    I want to make a chat which will be programed in java. one computer will host the server and the other one will initiate the socket [tcp port]. now from what I read there should be a loop that will constantly read the socket which means it will make the code stuck. I have a button that is 'actionperformed' on mouse release, I want to know if it will work along with the loops that constantly reads the socket so that it will also send the infromation I wrote. If I must thread it, I want to know if the run() method must be void because if I thread it it will mean creating a new class, and the whole GUI is one big class which includes a text area, and it's private. also how can I extract the information from the socket directly to the text area? lets say the textarea variable is called "chatOutput". thx :)

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  • No IO exception reported for socket operation when the interface is removed

    - by user352536
    The wifi network is connected, the application setup a socket connection and exchange data with the remote server. But when turn off the wifi, the inteface is removed, while socket operation read/write on this socket is still like normal, no any IO exception reported. The application has to do some extra checking to avoid waiting for the data forever. Is this the normal case for Android design? Is there any plan to fix it?

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  • Strange numbers in java socket output

    - by user293163
    I have small test app: Socket socket = new Socket("jeck.ru", 80); PrintWriter pw = new PrintWriter(socket.getOutputStream(), false); pw.println("GET /ip/ HTTP/1.1"); pw.println("Host: jeck.ru"); pw.println(); pw.flush(); BufferedReader rd = new BufferedReader(new InputStreamReader(socket.getInputStream())); String str; while ((str = rd.readLine()) != null) { System.out.println(str); } It`s output: HTTP/1.1 200 OK Date: Sat, 13 Mar 2010 22:06:51 GMT Content-Type: text/html;charset=utf-8 Transfer-Encoding: chunked Connection: keep-alive Keep-Alive: timeout=5 Server HTTP/1.1 200 OK Date: Sat, 13 Mar 2010 22:06:51 GMT Content-Type: text/html;charset=utf-8 Transfer-Encoding: chunked Connection: keep-alive Keep-Alive: timeout=5 Server: Apache Cache-Control: max-age=0 Expires: Sat, 13 Mar 2010 22:06:51 GMT 123 <!DOCTYPE html> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /> <title>??? IP</title> </head> <body> <div style='text-align: center; font: 32pt Verdana;margin-top: 300px'> ??? IP &#151; 94.103.87.153 </div> </body> </html> 0 Whence these numbers (123 an 0) takes?

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  • How can I wrap an executable on UNIX (SunOS) so that it is never run more than once at the same time

    - by user332815
    I have an executable (no source) that I need to wrap, to make sure that it is not called more than once at a time. I immediately think of some sort of queue wrapper, but how do I actually make it so that my wrapper is called instead of the executable itself? Is there a better way to do this? The solution needs to be invisible because the users are other applications. Any information/recommendations are appreciated.

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  • Fragment method and socket.io

    - by Tolgay Toklar
    I have a method,this method updates an array list in fragment.I can call this method in main activity like this public void getFromUser(String message) { addMessageToFragment("ok"); } public void addMessageToFragment(String message) { Log.w("Step 1",message); frgObj.addMessageToList("asd"); } getFromUser is calling from fragment(when user presses the button) this is working as well.But I am using socket.io in my app,when I try to call this method from socket.io,app is not working. public void on(String event, IOAcknowledge ack, Object... args) { try{ addMessageToFragment("ok"); } catch (JSONException e) {} } When this callback function calls,app is giving this errors: 08-19 11:57:24.813: W/System.err(4962): io.socket.SocketIOException: Exception was thrown in on(String, JSONObject[]). 08-19 11:57:24.813: W/System.err(4962): Message was: 5:::{"name":"listele","args":[{"mesaj":"123","gonderen":"781722165-tolgay007-DKSMIcIYGahPuKXriM83","alici":"tolgay007","blck_id":"781722165-tolgay007","out_username":"Anony-781722","ars_status":1,"longinf":"3aqghef","a_status":1}]} 08-19 11:57:24.813: W/System.err(4962): at io.socket.IOConnection.transportMessage(IOConnection.java:702) 08-19 11:57:24.813: W/System.err(4962): at io.socket.WebsocketTransport.onMessage(WebsocketTransport.java:82) 08-19 11:57:24.813: W/System.err(4962): at org.java_websocket.client.WebSocketClient.onWebsocketMessage(WebSocketClient.java:361) 08-19 11:57:24.813: W/System.err(4962): at org.java_websocket.WebSocketImpl.deliverMessage(WebSocketImpl.java:565) 08-19 11:57:24.813: W/System.err(4962): at org.java_websocket.WebSocketImpl.decodeFrames(WebSocketImpl.java:331) 08-19 11:57:24.813: W/System.err(4962): at org.java_websocket.WebSocketImpl.decode(WebSocketImpl.java:152) 08-19 11:57:24.813: W/System.err(4962): at org.java_websocket.client.WebSocketClient.interruptableRun(WebSocketClient.java:247) 08-19 11:57:24.823: W/System.err(4962): at org.java_websocket.client.WebSocketClient.run(WebSocketClient.java:193) 08-19 11:57:24.823: W/System.err(4962): at java.lang.Thread.run(Thread.java:841) 08-19 11:57:24.823: W/System.err(4962): Caused by: android.view.ViewRootImpl$CalledFromWrongThreadException: Only the original thread that created a view hierarchy can touch its views. 08-19 11:57:24.823: W/System.err(4962): at android.view.ViewRootImpl.checkThread(ViewRootImpl.java:6094) 08-19 11:57:24.823: W/System.err(4962): at android.view.ViewRootImpl.focusableViewAvailable(ViewRootImpl.java:2800) 08-19 11:57:24.823: W/System.err(4962): at android.view.ViewGroup.focusableViewAvailable(ViewGroup.java:650) 08-19 11:57:24.823: W/System.err(4962): at android.view.ViewGroup.focusableViewAvailable(ViewGroup.java:650) 08-19 11:57:24.823: W/System.err(4962): at android.view.ViewGroup.focusableViewAvailable(ViewGroup.java:650) 08-19 11:57:24.823: W/System.err(4962): at android.view.ViewGroup.focusableViewAvailable(ViewGroup.java:650) 08-19 11:57:24.823: W/System.err(4962): at android.view.ViewGroup.focusableViewAvailable(ViewGroup.java:650) 08-19 11:57:24.823: W/System.err(4962): at android.view.ViewGroup.focusableViewAvailable(ViewGroup.java:650) 08-19 11:57:24.823: W/System.err(4962): at android.view.ViewGroup.focusableViewAvailable(ViewGroup.java:650) 08-19 11:57:24.823: W/System.err(4962): at android.view.View.setFlags(View.java:8878) 08-19 11:57:24.823: W/System.err(4962): at android.view.View.setFocusableInTouchMode(View.java:6114) 08-19 11:57:24.823: W/System.err(4962): at android.widget.AdapterView.checkFocus(AdapterView.java:718) 08-19 11:57:24.823: W/System.err(4962): at android.widget.AdapterView$AdapterDataSetObserver.onChanged(AdapterView.java:813) 08-19 11:57:24.823: W/System.err(4962): at android.widget.AbsListView$AdapterDataSetObserver.onChanged(AbsListView.java:6280) 08-19 11:57:24.823: W/System.err(4962): at android.database.DataSetObservable.notifyChanged(DataSetObservable.java:37) 08-19 11:57:24.823: W/System.err(4962): at android.widget.BaseAdapter.notifyDataSetChanged(BaseAdapter.java:50) 08-19 11:57:24.823: W/System.err(4962): at android.widget.ArrayAdapter.notifyDataSetChanged(ArrayAdapter.java:286) 08-19 11:57:24.823: W/System.err(4962): at com.impact.ribony.ConversationFragment.addMessageToList(ConversationFragment.java:91) 08-19 11:57:24.823: W/System.err(4962): at com.impact.ribony.MainActivity.addMessageToFragment(MainActivity.java:344) 08-19 11:57:24.823: W/System.err(4962): at com.impact.ribony.MainActivity$2.on(MainActivity.java:183) 08-19 11:57:24.823: W/System.err(4962): at io.socket.IOConnection.on(IOConnection.java:908) 08-19 11:57:24.883: W/System.err(4962): at io.socket.IOConnection.transportMessage(IOConnection.java:697) I didn't understand this error.What can be cause this error ?

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  • How do I daemonize an arbitrary script in unix?

    - by dreeves
    I'd like a daemonizer that can turn an arbitrary, generic script or command into a daemon. There are two common cases I'd like to deal with: I have a script that should run forever. If it ever dies (or on reboot), restart it. Don't let there ever be two copies running at once (detect if a copy is already running and don't launch it in that case). I have a simple script or command line command that I'd like to keep executing repeatedly forever (with a short pause between runs). Again, don't allow two copies of the script to ever be running at once. Of course it's trivial to write a "while(true)" loop around the script in case 2 and then apply a solution for case 1, but a more general solution will just solve case 2 directly since that applies to the script in case 1 as well (you may just want a shorter or no pause if the script is not intended to ever die (of course if the script really does never die then the pause doesn't actually matter)). Note that the solution should not involve, say, adding file-locking code or PID recording to the existing scripts. More specifically, I'd like a program "daemonize" that I can run like % daemonize myscript arg1 arg2 or, for example, % daemonize 'echo `date` >> /tmp/times.txt' which would keep a growing list of dates appended to times.txt. (Note that if the argument(s) to daemonize is a script that runs forever as in case 1 above, then daemonize will still do the right thing, restarting it when necessary.) I could then put a command like above in my .login and/or cron it hourly or minutely (depending on how worried I was about it dying unexpectedly). NB: The daemonize script will need to remember the command string it is daemonizing so that if the same command string is daemonized again it does not launch a second copy. Also, the solution should ideally work on both OS X and linux but solutions for one or the other are welcome. (If I'm thinking of this all wrong or there are quick-and-dirty partial solutions, I'd love to hear that too.)

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  • Java Socket - how to catch Exception of BufferedReader.readline()

    - by Hasan Tahsin
    I have a Thread (let's say T1) which reads data from socket: public void run() { while (running) { try { BufferedReader reader = new BufferedReader( new InputStreamReader(socket.getInputStream()) ); String input = reader.readLine(); } catch (IOException e) { e.printStackTrace(); } } } Another Thread (lets say T2) try to finish the program in one of its method. Therefore T2 does the following: T1.running = false; socket.close(); Here is this scenario for which i couldn't find a solution: T1 is active and waiting for some input to read i.e. blocking. context switching T2 is active and sets running to false, closes the socket context switching because T1 was blocking and T2 closed the socket, T1 throws an Exception. What i want is to catch this SocketException. i can't put a try/catch(SocketException) in T1.run(). So how can i catch it in T1's running-method? If it's not possible to catch it in T1's running, then how can i catch it elsewhere? PS: "Another question about the Thread Debugging" Normally when i debug the code step by step, i lose the 'active running line' on a context switch. Let's say i'm in line 20 of T1, context switch happens, let's assume the program continues from the 30.line of T2, but the debugger does not go/show to the 30.line of T2, instead the 'active running line' vanishes. So i lose the control over the code. I use Eclipse for Java and Visual Studio for C#. So what is the best way to track the code while debugging on a context switch ?

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  • Testing for a closed socket

    - by Robert S. Barnes
    I'm trying to test for a closed socket that has been gracefully closed by the peer without incurring the latency hit of a double send to induce a SIGPIPE. One of the assumptions here is that the socket if closed was gracefully closed by the peer immediately after it's last write / send. Actual errors like a premature close are dealt with else where in the code. If the socket is still open, there will be 0 or more bytes data which I don't actually want to pull out of the socket buffer yet. I was thinking that I could call int ret = recv(sockfd, buf, 1, MSG_DONTWAIT | MSG_PEEK); to determine if the socket is still connected. If it's connected but there's no data in the buffer I'll get a return of -1 with errno == EAGAIN and return the sockfd for reuse. If it's been gracefully closed by the peer I'll get ret == 0 and open a new connection. I've tested this and it seems to work. However, I suspect there is a small window between when I recv the last bit of my data and when the peer FIN arrives in which I could get a false-positive EAGAIN from my test recv. Is this going to bite me, or is there a better way of doing this?

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  • Maintaining many socket connections with a single thread

    - by John
    Many tutorials on socket communication I see seem to use 1 thread per socket. But on a server used for online gaming, you might have 10k concurrent users - 10k threads isn't probably a wonderful idea. I came across a tool (SmartFox) which claims to use a single thread for monitoring all socket connections, potentially thousands of them. This app happens to be in Java, but I figure C++ or C# could do the same... how would you achieve this?

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